3
2
1
-1
-2
-3
Determine the period.
V
MAN
6 8 10 12 14
2 4

Answer:

F

Step-by-step explanation:

i could be incorrect but SSA isn't a valid congruency statement and if you were trying to prove them congruent that wouldn't work

The applied overhead cost for job 201 is $36,000 and total cost for job 201 under direct materials cost as allocation base is $86,000.

Allocation base is a technique utilized in accounting to designate the cost of something to its use or product to recognize the price of the finished product.

Example provides the total overhead cost at $120,000 for the period, the base data of $100,000 direct material cost and 500 direct labor hours. The base data are used to calculate the predetermined factory overhead rate, which is used to apply overhead costs to work in progress.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the base data. The predetermined factory overhead rate is multiplied by the actual activity in the allocation base to obtain the applied overhead cost.

Direct materials cost as allocation base $30,000 is the actual direct material cost used in job 201. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct material cost, which is $120,000/$100,000=120%.

The applied overhead cost for job 201 is $30,000*120% = $36,000.

Total cost for job 201 under direct materials cost as allocation base is $30,000+$20,000+$36,000 = $86,000.

-Direct labor cost as allocation base:

The actual direct labor cost used in job 201 is $20,000. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor cost, which is $120,000/$100,000=120%.

The applied overhead cost for job 201 is $20,000*120% = $24,000.

Total cost for job 201 under direct labor cost as allocation base is $30,000+$20,000+$24,000 = $74,000.

-Direct labor hours as allocation base:

The actual direct labor hours used in job 201 is 400 hours.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor hours, which is $120,000/500 hours = $240 per hour.The applied overhead cost for job 201 is $240*400 hours = $96,000.

Total cost for job 201 under direct labor hours as allocation base is $30,000+$20,000+$96,000 = $146,000.

-Physical output as allocation base: The actual output in units completed for job 201 is 2,000 shirts.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the output in units, which is $120,000/10,000 units = $12 per unit.

The applied overhead cost for job 201 is $12*2,000 units = $24,000.Total cost for job 201 under physical output as allocation base is $30,000+$20,000+$24,000 = $74,000.

-Machine hours as allocation base: The actual machine hours used in job 201 is 240 hours.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the machine hours, which is $120,000/5,000 hours = $24 per hour.

The applied overhead cost for job 201 is $24*240 hours = $5,760.

Total cost for job 201 under machine hours as allocation base is $30,000+$20,000+$5,760 = $55,760.

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Calculating 384 yd^2 and 1057 yd^2. expression, we find that the volume of the smaller solid is approximately 493.6 yd^3 when rounded to the nearest unit.

The surface areas of two similar solids are given as 384 yd^2 and 1057 yd^2. Let's denote the surface area of the smaller solid as SA_small and the surface area of the larger solid as SA_large.

We know that the surface area of a solid is proportional to the square of its linear dimension (length, width, or height) in similar solids. Therefore, the ratio of the surface areas is equal to the square of the ratio of their corresponding linear dimensions.

Using this concept, we can set up the following proportion:

(SA_small / SA_large) = (V_small / V_large)^2

Plugging in the given values, we have:

384 / 1057 = (V_small / 1795)^2

Simplifying further:

0.363 = (V_small / 1795)^2

Taking the square root of both sides:

√0.363 = V_small / 1795

V_small = √0.363 * 1795

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Given statement solution is :-You should mix 20 milligrams of Medication A this week when using 26 milligrams of Medication B.

To determine how many milligrams of Medication A should be mixed this week, we need to maintain the same proportion as last week.

Last week's proportion:

Medication A : Medication B = 100 mg : 130 mg

To find out the amount of Medication A for this week's prescription, we can set up a proportion using the known ratio:

Medication A / Medication B = Last week's Medication A / Last week's Medication B

Let's plug in the values:

Medication A / 26 mg = 100 mg / 130 mg

To solve for Medication A, we can cross-multiply and then divide:

Medication A * 130 mg = 100 mg * 26 mg

Medication A * 130 mg = 2600 mg*mg

Medication A = 2600 mg*mg / 130 mg

Medication A = 20 mg

Therefore, you should mix 20 milligrams of Medication A this week when using 26 milligrams of Medication B.

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Answer:

Let's assume the woman invested x dollars in the account that pays 11% per year.

Since she invested a total of $8000, the amount invested in the account that pays 12% per year would be (8000 - x) dollars.

Now, let's calculate the interest earned from each investment:

Interest from the 11% account: 0.11x

Interest from the 12% account: 0.12(8000 - x)

According to the given information, the total interest earned in the first year is $910. Therefore, we can set up the following equation:

0.11x + 0.12(8000 - x) = 910

Let's solve this equation to find the value of x:

0.11x + 0.12 * 8000 - 0.12x = 910

0.11x - 0.12x = 910 - 0.12 * 8000

-0.01x = 910 - 960

-0.01x = -50

Dividing both sides by -0.01:

x = (-50) / (-0.01)

x = 5000

Therefore, the woman invested $5000 in the account that pays 11% per year.

The amount invested in the account that pays 12% per year would be 8000 - 5000 = $3000.

So, she invested $5000 in the 11% account and $3000 in the 12% account.

Answer:

(A) - [tex]f(g(x))=-18x^2+27x-19[/tex]

(B) - Quadratic

(C) - x=3/4

Step-by-step explanation:

Given:

[tex]f(x)=-2x^2+x-9\\\\g(x)=3x-2[/tex]

Find:

(A) -[tex]f(g(x))= \ ??[/tex]

(B) - Determine if f(g(x)) is linear or quadratic

(C) - Identify the slope or axis of symmetry

[tex]\hrulefill[/tex]

Part (A) -

Simply plug the function g(x) into f(x) to find f(g(x)):

[tex]f(g(x))=-2(3x-2)^2+(3x-2)-9[/tex]

Simplifying:

[tex]\therefore \boxed{f(g(x))=-18x^2+27x-19}[/tex]

Thus, part (A) is solved.

Part (B) -

To determine if a function is linear or quadratic, you need to examine its form and characteristics. Here are some key differences between linear and quadratic functions:

Linear Function:

Quadratic Function:

Using the information above we can determine f(g(x)) is quadratic.

Part (C) -

The axis of symmetry of a quadratic function can be found by using the formula x = -b / (2a), where a and b are the coefficients of the quadratic function in standard form. The resulting x-coordinate represents the vertical line that divides the parabola into two equal halves.

[tex]\text{In our case}: \ a=-18 \ \text{and} \ b=27\\\\\\\Longrightarrow x=\dfrac{-27}{2(-18)} \\\\\\\therefore \boxed{x=\frac{3}{4} }[/tex]

Thus, part (C) is solved.

The given statement presents a contradiction in the assumption by assuming the existence of a well-ordered set and an increasing function, and shows that the function's value is always less than the input element in the set.

The given statement is a part of a proof demonstrating a property of an increasing function on a well-ordered set. Here's an explanation in 150 words:

The statement assumes that we have a well-ordered set W, equipped with a strict total order "<." Additionally, we have a function f defined on the set of all elements of W to W itself. The function f is said to be increasing, meaning that for any x and y in W, if x < y, then f(x) < f(y).

The proof aims to show that for every element x in W, f(x) is always less than x. To do this, it considers the set X, which contains all elements x in W such that f(x) < x. The assumption is made that X is nonempty and let z be the least element of X.

Then, the proof considers the element w = f(z), and it aims to reach a contradiction. It assumes that w is greater than f(z), i.e., f(w) < w. This leads to a contradiction because it contradicts the definition of X, where x should be in X if f(x) < x.

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The robot's locations for each time t are P(14, 27) when t = 14, and P(0.7, 0.4) when t = 0.7.

To find the robot's location, P, for each time t, we can use the equation of a straight line.

Given points A(0, -1) and B(1, 1), we can calculate the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

m = (1 - (-1)) / (1 - 0) = 2/1 = 2

Now that we have the slope, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

For point A(0, -1):

y - (-1) = 2(x - 0)

y + 1 = 2x

Simplifying the equation, we get:

y = 2x - 1

Now we can substitute the values of t into the equation to find the corresponding locations of the robot, P.

For t = 14:

y = 2(14) - 1

y = 28 - 1

y = 27

So, when t = 14, the robot's location is P(14, 27).

For t = 0.7:

y = 2(0.7) - 1

y = 1.4 - 1

y = 0.4

So, when t = 0.7, the robot's location is P(0.7, 0.4).

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Answer:

The Answer Will Be D

Step-by-step explanation:
The fuel economy of a car is modeled by the function f(s) = -0.009s² +0.699s +12 where s represents the speed of the car, measured in miles per hour.We need to find the fuel economy of the car when it travels at an average of 20 miles an hour.f(20) = -0.009(20)² +0.699(20) +12f(20) = -0.009(400) +13.98f(20) = 9.6The fuel economy of the car when it travels at an average of 20 miles an hour is 9.6 miles per gallon.Therefore, the answer is option D. 22.38 miles per gallon.

The mean for the given frequency tables is:

(a) Grade Frequency: 48.7

(b) Daily Low Temperature Frequency: 54.5

(c) Points per Game Frequency: 54.5

To find the mean for the given frequency tables, we need to calculate the weighted average. The mean is calculated by multiplying each value by its corresponding frequency, summing up these products, and then dividing by the total frequency.

(a) Grade Frequency:

To find the mean for the grade frequency table, we need to multiply the midpoints of each class interval by their respective frequencies and then divide by the total frequency.

The midpoints are:

54.5, 64.5, 74.5, 84.5, 94.5

The frequencies are:

2, 3, 6, 11, 5

Calculating the weighted sum: (54.52) + (64.53) + (74.56) + (84.511) + (94.5*5) = 1315

Calculating the total frequency: 2 + 3 + 6 + 11 + 5 = 27

Mean = 1315 / 27 ≈ 48.7

(b) Daily Low Temperature Frequency:

Since the frequency for the 49.5–59.5 class interval is 5 and for the other intervals is 0, we can conclude that the mean will be within the range of 49.5–59.5. The mean will be the midpoint of this class interval.

Mean = (49.5 + 59.5) / 2 = 54.5

(c) Points per Game Frequency:

Similarly to part (b), since the frequency for the 49.5–59.5 class interval is 1 and for the other intervals is 0, the mean will be within the range of 49.5–59.5.

Mean = (49.5 + 59.5) / 2 = 54.5

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The amount of net income on the income statement for the year is $26,200.

To determine the net income, we need to calculate the total revenue and subtract the total expenses.

Total Revenue = Service Revenue = $50,400

Total Expenses = Wages Expense + Advertising Expense + Rent Expense = $8,400 + $5,400 + $10,400 = $24,200

Net Income = Total Revenue - Total Expenses = $50,400 - $24,200 = $26,200

Therefore, the amount of net income on the income statement for the year is $26,200.

To calculate the net income, we consider the revenue and expenses recorded in the company's financial records.

Revenue represents the inflow of money from the company's primary operations. In this case, the revenue is listed as "Service Revenue" with a value of $50,400.

Expenses represent the outflow of money incurred by the company in conducting its operations. The expenses mentioned in the records are "Wages Expense" ($8,400), "Advertising Expense" ($5,400), and "Rent Expense" ($10,400).

To calculate the net income, we subtract the total expenses from the total revenue:

Net Income = Total Revenue - Total Expenses

Total Revenue = $50,400

Total Expenses = $8,400 + $5,400 + $10,400 = $24,200

Net Income = $50,400 - $24,200 = $26,200

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To estimate the minimum sample size required to estimate the population mean with a 95% confidence level and a desired margin of error, we can use the formula:

n = (Z * σ / E)²

Where:

n = sample size

Z = Z-score corresponding to the desired confidence level

σ = population standard deviation

E = desired margin of error

In this case, the desired confidence level is 95%, so the corresponding Z-score is the critical value associated with a 95% confidence level. From standard normal distribution tables, the Z-score for a 95% confidence level is approximately 1.96.

Given that the population standard deviation is 1.6 hours and the desired margin of error is 25 hours, we can plug in these values into the formula:

n = (1.96 * 1.6 / 25)²

Simplifying the equation:

n = (0.3136 / 25)²

n = 0.0125²

n ≈ 0.00015625

To find the minimum sample size, we need to round up to the nearest whole number since the sample size must be a whole number:

n ≈ 1

Therefore, the minimum sample size required to estimate the population mean with 95% confidence and a margin of error of 25 hours is approximately 1.

It is important to note that a sample size of 1 is not practically feasible or reliable for making statistical inferences. This result suggests that there may be other factors or considerations that need to be taken into account to determine a suitable sample size for this particular study.

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Answer:

f(-3) = -29

f(-5) = -45

f(-6) = -53

Step-by-step explanation:

8x-5 , x [tex]\leq[/tex] -5

f(-5)

= 8(-5) - 5

= -40-5

=-45 ( less than -5 , so we can use)

-[tex]x^{2}[/tex] , x > -5

= -[tex](-5)^{2}[/tex]

= -(25)

= -25 (greater than -5, we can't use)

if u have any question let me know.

Answer:

Step-by-step explanation:

The measure of the interior angle of a triangle is 180 degrees

therefore 3x + 2x + 90 = 180

5x + 90 = 180

5x = 90

x = 18

3x = 3(18)  = 54 degrees

2x = 2(18) = 36 degrees

To check:

54 + 36 + 90 = 180

We have proven trigonometric  equation a² + b² = p² + q², using the given equations a sin θ + b cos θ = p --- (1) and a cos θ - b sin θ = q --- (2).

To prove that a² + b² = p² + q², we need to manipulate the given equations and show their equivalence.

Given equations:

a sin θ + b cos θ = p --- (1)

a cos θ - b sin θ = q --- (2)

Square equation (1):

(a sin θ + b cos θ)² = p²

Expanding and simplifying:

a² sin² θ + 2ab sin θ cos θ + b² cos² θ = p² --- (3)

Square equation (2):

(a cos θ - b sin θ)² = q²

Expanding and simplifying:

a² cos² θ - 2ab sin θ cos θ + b² sin² θ = q² --- (4)

Now, adding equations (3) and (4):

a² sin² θ + a² cos² θ + b² sin² θ + b² cos² θ + 2ab sin θ cos θ - 2ab sin θ cos θ = p² + q²

Using the trigonometric identity: sin² θ + cos² θ = 1, we simplify:

a² + b² = p² + q²

We have proven that a² + b² = p² + q², using the given equations (1) and (2).

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Answer:

Step-by-step explanation:

[tex]\frac{sin(x)}{1-cos(x)} -cot(x)=csc(x)\\[/tex]

[tex]\frac{sin(x)}{1-cos(x)} -\frac{cos(x)}{sin(x)} =csc(x)[/tex]

[tex]\frac{sin^{2}(x)-cos(x)+cos^{2}(x) }{(1-cos(x))sin(x)} =csc(x)\\\\\frac{1-cos(x)}{(1-cos(x))sin(x)} =csc(x)\\[/tex]

[tex]\frac{1}{sin(x)} =csc(x)\\csc(x)=csc(x)[/tex]

QED

Answer:

See below for proof.

Step-by-step explanation:

Use the cotangent identity to rewrite cot(x) as cos(x) / sin(x):

[tex]\dfrac{\sin(x)}{1-\cos(x)}-\cot(x)=\dfrac{\sin(x)}{1-\cos(x)}-\dfrac{\cos (x)}{\sin(x)}[/tex]

Make the denominators of both fractions the same:

                              [tex]=\dfrac{\sin(x)}{1-\cos(x)}\cdot{\dfrac{\sin(x)}{\sin(x)}-\dfrac{\cos (x)}{\sin(x)}\cdot{\dfrac{1-\cos(x)}{1-\cos(x)}[/tex]

                              [tex]=\dfrac{\sin^2(x)}{\sin(x)(1-\cos(x))}-\dfrac{\cos (x)(1-\cos(x))}{\sin(x)(1-\cos(x))}[/tex]

Expand the numerator of the second fraction:

                              [tex]=\dfrac{\sin^2(x)}{\sin(x)(1-\cos(x))}-\dfrac{\cos (x)-\cos^2(x)}{\sin(x)(1-\cos(x))}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}-\dfrac{b}{c}=\dfrac{a-b}{c}:[/tex]

                              [tex]=\dfrac{\sin^2(x)-(\cos (x)-\cos^2(x))}{\sin(x)(1-\cos(x))}[/tex]

                              [tex]=\dfrac{\sin^2(x)-\cos (x)+\cos^2(x)}{\sin(x)(1-\cos(x))}[/tex]

                              [tex]=\dfrac{\sin^2(x)+\cos^2(x)-\cos (x)}{\sin(x)(1-\cos(x))}[/tex]

Apply the trigonometric identity, sin²θ + cos²θ = 1, to the numerator:

                              [tex]=\dfrac{1-\cos (x)}{\sin(x)(1-\cos(x))}[/tex]

Factor out the common term (1 - cos(x)) from the numerator and denominator:

                              [tex]=\dfrac{1}{\sin(x)}[/tex]

Finally, use the cosecant identity, csc(x) = 1 / sin(x):

                              [tex]=\csc(x)[/tex]

Hence we have verified that the left side of the equation equals the right side.

Answer:

W.T.H is this

Step-by-step explanation:

This ain't the way to past <s<h>t>

>>>>>>>>>(X₁V₂) O A. A=(₁-₂)(53-51) B. A=(3-₁)(3-1) CO. A=(₁-₁)(2-51) O D. A=(√₂-₁)(²3-11) O E. A=(√₂-₁)(52-51) (Xg. Ya)​?????????????????

XD u a noobie of life kid get better lol

Answer:

C

Step-by-step explanation:

the common ratio r of a geometric sequence is

r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{-\frac{4}{15} }{\frac{2}{5} }[/tex] = - [tex]\frac{4}{15}[/tex] × [tex]\frac{5}{2}[/tex] = - [tex]\frac{2}{3}[/tex]

Answer:

(x - 9)^2 + (y + 5)^2 = 50.

Step-by-step explanation:

To determine the equation of the circle with a center at (9, -5) and containing the point (10, 2), we need to find the radius of the circle first. The radius is the distance between the center and any point on the circle, such as (10, 2).

We can use the distance formula to find the radius:

r = √((x2 - x1)^2 + (y2 - y1)^2)

Substituting the given values:

r = √((10 - 9)^2 + (2 - (-5))^2)

Simplifying:

r = √(1^2 + 7^2)

r = √(1 + 49)

r = √50

Simplifying further:

r = √(25 * 2)

r = 5√2

Now that we have the radius, we can write the equation of the circle in standard form:

(x - h)^2 + (y - k)^2 = r^2

Substituting the values:

(x - 9)^2 + (y - (-5))^2 = (5√2)^2

Simplifying:

(x - 9)^2 + (y + 5)^2 = 50

Therefore, the equation of the circle with a center at (9, -5) and containing the point (10, 2) is:

(x - 9)^2 + (y + 5)^2 = 50.

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:Two lines with slopes  and  are parallel when  and are perpendicular when

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

The weight of the new player is 9 kg.

Given -

Mean weight of the team before including the new player = 86.5 kg

Mean weight of the team after including the new player = 86 kg

Number of players in the team before including the new player = 18

To find -

The weight of the new player

Solution -

Let's denote the weight of the new player as 'x' kg.

To solve the problem, we'll use the formula for the mean:

Mean = (Sum of all values) / (Number of values)

The sum of weights of the original 18 players = 86.5 kg * 18

The sum of weights of all 19 players = (86 kg * 18) + x kg

According to the problem, the mean weight before including the new player is 86.5 kg, and the mean weight after including the new player is 86 kg. So, we can set up the following equation:

(86.5 kg * 18) = (86 kg * 18) + x kg

Now, let's solve the equation to find the weight of the new player:

(86.5 kg * 18) = (86 kg * 18) + x kg

1557 kg = 1548 kg + x kg

9 kg = x kg

Therefore, the weight of the new player is 9 kg.

The mean is the most sensitive to extreme scores, followed by the median, while the mode is the least affected. The mean is greatly influenced by outliers, the median is moderately influenced, and the mode is generally unaffected by extreme scores.

The mean, median, and mode are measures of central tendency used to describe the average or typical value in a dataset. They differ in their sensitivity to extreme scores, also known as outliers or extreme values.

Mean:

The mean is calculated by summing all the values in a dataset and dividing by the total number of values. It is highly sensitive to extreme scores because it takes into account the magnitude of each value. Even a single extreme score can significantly affect the mean. This sensitivity arises from the fact that the mean incorporates all values in the dataset. Therefore, outliers can distort the mean and pull it towards their direction

Median:

The median represents the middle value when the dataset is arranged in ascending or descending order. It is less sensitive to extreme scores compared to the mean. The median only considers the position of the values, not their actual values. Therefore, extreme scores have less impact on the median since it focuses on the relative position of values rather than their magnitude. As a result, outliers have minimal influence on the median.

Mode:

The mode represents the value(s) that appear most frequently in the dataset. Like the median, the mode is not significantly affected by extreme scores. Outliers can occur in a dataset without affecting the mode because the mode is determined by the most frequently occurring value(s), regardless of their magnitude. In datasets with multiple modes or no mode, extreme scores may not significantly impact the mode.

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Path A-B-C-E represents the distance traveled, which is 18 meters.

Path A-G-C-E represents the displacement, which is 17 meters.

From the given figure, we can identify the paths and calculate the distance and displacement.

Path A-B-C-E represents the distance traveled, and path A-G-C-E represents the displacement.

Let's calculate the lengths of both paths:

Distance traveled (Path A-B-C-E):

Length of AB = 9m

Length of BC = 3m

Length of CE = 6m

Total distance traveled = Length of AB + Length of BC + Length of CE

= 9m + 3m + 6m

= 18m

Therefore, the distance traveled along path A-B-C-E is 18 meters.

Displacement (Path A-G-C-E):

Length of AG = 5m

Length of GC = 6m

Length of CE = 6m

Total displacement = Length of AG + Length of GC + Length of CE

= 5m + 6m + 6m

= 17m

Therefore, the displacement along path A-G-C-E is 17 meters.

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The graph of the function y = -2x + 3 is added as an attachment

From the question, we have the following parameters that can be used in our computation:

So, the equation is

y = -2x + 3

The above function is a linear function that has been transformed as follows

Vertically stretched by a factor of -2

Shifted up by 3 units

Next, we plot the graph using a graphing tool by taking note of the above transformations rules

The graph of the function is added as an attachment

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Answer:

28,45,53 is a Pythagorean Triple

Step-by-step explanation:

To determine whether 28, 45, and 53 form a Pythagorean triple, we need to check whether they satisfy the Pythagorean theorem, which states that for any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

So, we need to check whether:

28^2 + 45^2 = 53^2

Evaluating the left-hand side of the equation, we get:

784 + 2025 = 2809

And evaluating the right-hand side of the equation, we get:

2809 = 2809

Since both sides are equal, we can conclude that 28, 45, and 53 form a Pythagorean triple, because they satisfy the Pythagorean theorem. Therefore, 28^2 + 45^2 = 53^2 is a true statement, and we can say that the lengths 28, 45, and 53 can form the sides of a right triangle.

A. The relation R is reflexive. B. This relation is not symmetric. C. The relation R is neither an equivalence relation nor a partial ordering relation on the set N = {1, 2, 3, 4, ...}.

Di. R is not a partial ordering relation, a Hasse diagram cannot be drawn. ii. There are no equivalence classes to find.

To determine whether the relation R is an equivalence relation or a partial ordering relation on the set N = {1, 2, 3, 4, ...}, examine its properties.

a. Reflexivity:

For a relation to be reflexive, every element in the set should be related to itself. In the given definition of R, we have x = y¹, where y¹ represents the first power of y. Since any number raised to the power of 1 is equal to itself, the relation R is reflexive.

b. Symmetry:

For a relation to be symmetric, if x is related to y, then y should also be related to x. In the given definition of R, we have x = y¹. This relation is not symmetric because if x = 2 and y = 3, then x = y¹ is not satisfied.

c. Transitivity:

For a relation to be transitive, if x is related to y and y is related to z, then x should be related to z. In the given definition of R, we have x = y¹. This relation is not transitive because if x = 2, y = 3, and z = 4, then x = y¹ and y = z¹ are satisfied, but x = z¹ is not satisfied.

Based on the above analysis, we can conclude that the relation R is neither an equivalence relation nor a partial ordering relation on the set N = {1, 2, 3, 4, ...}.

d. Since the relation R is neither an equivalence relation nor a partial ordering relation on the set N = {1, 2, 3, 4, ...}, the Hasse diagram cannot be drawn, as it is applicable only for partial ordering relations.

i. Given that R is not a partial ordering relation, a Hasse diagram cannot be drawn.

ii. Since R is not an equivalence relation, there are no equivalence classes to find. Equivalence classes are relevant only for equivalence relations, where elements are grouped together based on their equivalence under the relation.

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Answer:

number (a) = 4

Step-by-step explanation:

f(g(x)) = x + 11 + 2√x and g(f(x)) = √(x² + 5) + 6. These are the simplified expressions for f(g(x)) and g(f(x)) using the given pair of functions.

To find f(g(x)), we substitute g(x) into the function f(x) and simplify:

f(g(x)) = f(√x + 6)

Since f(x) = x² + 5, we have:

f(g(x)) = (√x + 6)² + 5

= (x + 6 + 2√x) + 5

= x + 6 + 2√x + 5

= x + 11 + 2√x

Therefore, f(g(x)) simplifies to x + 11 + 2√x.

To find g(f(x)), we substitute f(x) into the function g(x) and simplify:

g(f(x)) = g(x² + 5)

Since g(x) = √x + 6, we have:

g(f(x)) = √(x² + 5) + 6

There is no further simplification possible for g(f(x)).

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Answer:

Area of a Segment of a Circle = θ/360° × πr2 – ½ r2sinC

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Answer:

[tex]AB=2r\sin\left(\dfrac{m\overset\frown{AB}}{2}\right)[/tex]

Step-by-step explanation:

Label the center of the circle O.

If two line segments are drawn from the center of the circle to points A and B on the circumference, an isosceles triangle will be formed, where the legs OA and OB are the radius, r, and the base is chord AB.

If an angle bisector is drawn from the center of the circle to the midpoint of AB, the isosceles triangle is divided into two right triangles.

An equation can now be formed for the base of the right triangle (half the length of chord AB), by using the sine trigonometric ratio.

The angle is half the central angle AOB, the side opposite the angle is half the chord AB, and the hypotenuse is the radius, r. Therefore:

                [tex]\sin (\theta)=\dfrac{\sf opposite\;side}{\sf hypotenuse}[/tex]

[tex]\sin\left(\dfrac{m\angle AOB}{2}\right)=\dfrac{\frac{1}{2}AB}{r}[/tex]

Rearrange the equation to isolate AB:

[tex]\dfrac{1}{2}AB=r\sin\left(\dfrac{m\angle AOB}{2}\right)[/tex]

[tex]AB=2r\sin\left(\dfrac{m\angle AOB}{2}\right)[/tex]

Since the measure of an arc is equal to the measure of its corresponding central angle, this means that [tex]m\overset\frown{AB}=m \angle AOB[/tex]. Therefore, the equation to find the length of chord AB given the measure of arc AB is:

[tex]\boxed{AB=2r\sin\left(\dfrac{m\overset\frown{AB}}{2}\right)}[/tex]

Note: We would also need to know the length of the radius, r.