The volume of air at 73.9 °C would be approximately 70.91 ml.
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure and amount of gas are kept constant.
Let's assume that the pressure and amount of air remain constant.
Given:
Initial volume (V1) = 59.6 ml
Initial temperature (T1) = 20.5 °C = 20.5 + 273.15 K = 293.65 K
Final temperature (T2) = 73.9 °C = 73.9 + 273.15 K = 347.05 K
Using Charles's Law, we can set up the following proportion:
V1 / T1 = V2 / T2
Plugging in the values, we have:
59.6 ml / 293.65 K = V2 / 347.05 K
To solve for V2 (the final volume), we can rearrange the equation:
V2 = (59.6 ml * 347.05 K) / 293.65 K
V2 = 70.91 ml
Therefore, the volume of air at 73.9 °C would be approximately 70.91 ml.
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Which of the following set of quantum numbers (ordered n, ℓ, mℓ ) are possible for an electron in an atom? Check all that apply
a. 2, 1, 3
b. 5, 3, -3
c. 4, 3, -2
d. -4, 3, 1
e. 2, 1, -2
f. 3, 2, 2
g. 3, 3, 1
the possible quantum numbers (ordered n, ℓ, mℓ ) are:Option B.5, 3, -3 and Option C. 4, 3, -2
The quantum numbers n, ℓ, mℓ represent respectively the principal quantum number, the orbital angular momentum quantum number and the magnetic quantum number.
These are the three most important quantum numbers. T
here is another quantum number called the spin quantum number, denoted by ms.
Let's see which of the given quantum number sets is possible.2, 1, 3 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. 5, 3, -3 is possible.4, 3, -2 is possible. -4, 3, 1 is not possible.
For any value of ℓ, mℓ must be between -ℓ and +ℓ. e. 2, 1, -2 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. f. 3, 2, 2 is not possible because for ℓ = 2, mℓ can only be -2, -1, 0, +1, or +2. g. 3, 3, 1 is not possible because for any value of ℓ, mℓ must be between -ℓ and +ℓ.
Therefore, the possible quantum numbers (ordered n, ℓ, mℓ ) are:5, 3, -34, 3, -2
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-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:
6.02 x [tex]10^{20[/tex] formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.
Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.
Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:
(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))
The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:
(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol
Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.
Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.
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