The change in the coefficient of static friction between the friction block and concrete change would be Zero which means it will not change.
How does mass affect the coefficient of static friction?The coefficient of static friction between two surfaces does not depend on the mass of the object. Therefore, doubling the total mass of the friction block and slotted masses would not change the coefficient of static friction between the block and the concrete.
The coefficient of static friction is a property of the two surfaces in contact and is affected by factors such as the roughness of the surfaces, the materials they are made of, and the amount of force pressing the surfaces together.
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A 11 N force moves an object 9 m. What is the work?
Answer :
99 JoulesStep-by-step explanation :
Given:
Force = 11 N Displacement = 9 mWork done = Force × Displacement
On substituting the values, we get :
Work done = 11 × 9
Work done = 99 joules
A baseball rolls off a 0.70 m high desk and strikes the floor 0.25 m away from the base of the desk. How far was the ball rolling?
Answer:0.66m/s
Explanation:
We can calculate the time it takes for the ball to fall to the floor. y = (1/2) a t^2 t = sqrt { 2y / g } t = sqrt { (2) (0.70 m) / (9.80 m/s^2) } t = 0.378 seconds In a time of 0.378 seconds, the ball traveled a horizontal distance of 0.25 meters. We can find the horizontal speed when the ball was rolling on the desk. v = d / t v = 0.25 m / 0.378 s v = 0.66 m/s The ball was rolling at a speed of 0.66 m/s when it was rolling on the desk.
100 joules of work are done on an object when a force of 10n pushes it. how far is the object pushes it? what power is used if this is done in 4 seconds?
I need the distance and the work done (with explanation please)
Work is the amount of energy transferred by a force, and can be calculated using the formula W = Fd, where F is the force, and d is the distance. In this case, the work is 100 joules, and the force is 10N. Therefore, the distance is d = W/F = 100/10 = 10 meters.
What is energy?Energy is the ability to do work. It is a measure of the capacity to cause change. Energy can take many forms, including kinetic energy (energy of motion), potential energy (stored energy of position), electrical energy, thermal energy, light energy, sound energy, chemical energy, and nuclear energy. Energy can be converted from one form to another, but it cannot be created or destroyed. For example, energy from the sun can be converted into electrical energy and stored in batteries.
The power used is the rate of work done, and can be calculated using the formula P = W/t, where W is the work done, and t is the time. In this case, the power used is P = 100/4 = 25 Joules/second.
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Gasoline vapor is injected into the cylinder of an automobile engine when the piston is in its expanded position. The temperature, pressure, and volume of the resulting gas-air mixture are 20 °C, 1.00x105N/m², and 240 cm3, respectively. The mixture is then compressed adiabatically to a volume of 40 cm3. (Note that in the actual operation of an automobile engine, the compression is not quasi-static, although we are making that assumption here). a) (10 pts) What are the pressure and temperature of the mixture after the compression? b) (10 pts) How much work is done by the mixture during the compression?
Answer:
a) the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b)the work done by the mixture is zero.
Explanation:
we can use the ideal gas law and the adiabatic compression equation.
a) Using the ideal gas law, we can find the initial number of moles of gas-air mixture in the cylinder:
PV = nRT
n = PV/RT = (1.00x105 N/m²)(240 cm³/1000 cm³/m³)/(8.31 J/mol•K)(20+273 K) ≈ 0.027 mol
Since the mixture is compressed adiabatically, we can use the adiabatic compression equation to find the final pressure and temperature:
P1V1^γ = P2V2^γ
where γ = Cp/Cv is the ratio of specific heats of the mixture.
Assuming the gas-air mixture behaves as a diatomic gas, we can use the values γ = 1.4 and Cp = 29.1 J/mol•K and Cv = 20.8 J/mol•K.
Substituting the given values, we can solve for the final pressure and temperature:
P2 = P1(V1/V2)^γ = (1.00x105 N/m²)(240 cm³/40 cm³)^1.4 ≈ 8.13x105 N/m²
T2 = T1(V1/V2)^(γ-1) = (20+273 K)(240 cm³/40 cm³)^0.4 ≈ 439 K
Therefore, the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b) The work done by the mixture during the compression can be found using the equation:
W = -ΔU
where ΔU is the change in internal energy of the mixture.
Since the compression is adiabatic, there is no heat transfer and ΔU = Q = 0.
Therefore, the work done by the mixture is zero.
Water flows steadily along a horizontal pipe at a rate of 8 × 10-3 m3/s. If the cross-section of the pipe is 40 × 10-4 m2, calculate the;
a). Flow velocity of water total pressure in the pipe if the static pressure in the horizontal pipe is 3×104 Pa. (Density of water is 1000 kg/m3)
b).new flow velocity if the total pressure is 3.6 × 104 Pa.
The flow velocity of the water is 2 m/s and the total pressure in the pipe is 3.5 × 10⁴ Pa and the new flow velocity of the water is 109.5 m/s.
What is static pressure?Static pressure is the pressure exerted by a fluid or gas that is not in motion or is at rest. It is equal in all directions and is caused by the molecules of the fluid or gas colliding with the walls of the container in which it is held.
Equation:a) To find the flow velocity of the water, we can use the equation:
Q = A * v
where Q is the flow rate, A is the cross-sectional area of the pipe, and v is the flow velocity.
Given Q = 8 × 10⁻³ m³/s and A = 40 × 10⁻⁴ m², we can solve for v:
v = Q / A
v = (8 × 10⁻³ m³/s) / (40 × 10⁻⁴ m²)
v = 2 m/s
To find the total pressure in the pipe, we can use the Bernoulli's equation:
P + (1/2)ρv² = P0
where P is the total pressure, ρ is the density of water, v is the flow velocity, and P0 is the static pressure.
Given ρ = 1000 kg/m³, v = 2 m/s, and P0 = 3 × 10⁴ Pa, we can solve for P:
P + (1/2)(1000 kg/m³)(2 m/s)² = 3 × 10⁴ Pa
P = 3.5 × 10⁴Pa
Therefore, the flow velocity of the water is 2 m/s and the total pressure in the pipe is 3.5 × 10⁴ Pa.
b) To find the new flow velocity, we can use the Bernoulli's equation again:
P + (1/2)ρv² = P0
Given P = 3.6 × 10⁴ Pa, ρ = 1000 kg/m³, and P0 = 3 × 10⁴ Pa, we can solve for v:
(1/2)(1000 kg/m³)v² = (3.6 × 10⁴ - 3 × 10⁴) Pa
v² = 1.2 × 10⁴ m²/s²
v = √(1.2 × 10⁴) m/s
v = 109.5 m/s
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A car, 1800-kg, going 41.7 m/s rear ends a truck, 5500-kg going 27.8 m/s. What are their velocities after an elastic collision in one dimension?
Refer to the image attached.
Jaycie wants to increase her upper body strength by doing push-ups. She does one push-up by applying a force of 10 n to raise her center of gravity 2 m. How many push-ups must jaycie complete to do 200 j of work?.
Jaycie would need to complete 10 push-ups to do 200 J of work, assuming that the force and displacement are the same for each push-up.
The work done by Jaycie to do one push-up is equal to the product of the force applied and the displacement of her center of gravity:
Work = Force x Displacement x cos(theta)
where theta is the angle between the force vector and the displacement vector. In this case, we can assume that the angle is 0 degrees, since the force is applied vertically upward and the displacement is vertically upward as well.
So the work done by Jaycie to do one push-up is:
Work = Force x Displacement = 10 N x 2 m = 20 J
To do 200 J of work, Jaycie would need to do:
Number of push-ups = Total work ÷ Work per push-up = 200 J ÷ 20 J/push-up = 10 push-ups
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Using the diagram belows. Which of the following statements is correct?
Using the diagram belows. Point A is directly above Point C statements is correct.
What is diagram?A diagram is a visual representation of information or data. It is used to help people better understand complex or abstract concepts, or to compare and contrast various elements. Diagrams are often used to provide an overall picture of a process, such as a flow chart, or a visual representation of the components of a system, such as a circuit diagram. Diagrams may also be used to explain the relationships between objects, such as in a Venn diagram. Diagrams are most commonly used in the fields of mathematics, engineering and science to illustrate concepts, but are also used in other disciplines such as business and art.
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Complete Question
Using the diagram belows. Which of the following statements is correct?
A. Point B is directly to the right of Point C.
B. Point A is directly above Point C.
C. Point D is directly below Point B.
D. Point A is directly to the left of Point D.
Two vectors lie with their tails at the same point. When the angle between them is increased by 20 their scalar product has the same magnitude but changes from positivr to negative .the original angle between them was?
Answer:
I need help
with that
Explanation:
so some one how can help me plis
I need help with that thing so I can not get
The original angle between the two vectors was 20.91 degrees. when two vectors lie with their tails at the same point but change from positive to negative.
The angle between the vectors is increased by 20 degrees, their scalar product changes sign, we can set up the following equation:
cos(θ + 20) = -cos(θ)
cos(θ)cos(20) - sin(θ)sin(20) = -cos(θ)
cos(θ)(cos(20) + 1) = sin(θ)sin(20)
cot(θ) = -tan(20)
θ = tan⁻¹(-tan(20))
θ ≈ -20.91 degrees
Therefore, the original angle between the two vectors was 20.91 degrees.
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consider the train car described in the previous part. another experiment is conducted in it: a net force of 20n 20 n is applied to an object of mass 5kg 5 k g . can you determine the acceleration of the object with respect to the train, and, if so, what is its value? consider the train car described in the previous part. another experiment is conducted in it: a net force of is applied to an object of mass . can you determine the acceleration of the object with respect to the train, and, if so, what is its value? yes; 0.25m/s2 0.25 m / s 2 . yes; 4.0m/s2 4.0 m / s 2 . yes; 100m/s2 100 m / s 2 . no; there is not enough information.
The acceleration of the object can be determined using the force exerted and mass. The acceleration of the object is with the mass of 5 kg having a net force of 20 N is 4 m/s².
What is acceleration ?Acceleration of an object is the rate of change in its velocity. Like velocity, acceleration is a vector quantity thus having both magnitude and direction.
According to Newton's second law of motion, force exerted on an object is the product of its mass and acceleration. Greater the force, the object will be accelerated more.
F = ma
given m = 5 kg
F = 20 N
a = F/m
= 20 N/ 5 kg
= 4 m/s²
Therefore, the acceleration of the object is 4 m/s².
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In raising a 7000-N piano with a pulley system, the
movers note that, for every 2.6 m of rope pulled
down, the piano rises 0.10 m.
Ideally, find the force required to lift the piano.
The force required to lift the piano would be 14000 Newtons.
What is weight?The weight of a body is the force exerted on it by the earth towards its center.
Given is that in raising a 7000 - N piano with a pulley system, the movers note that, for every 2.6 m of rope pulled down, the piano rises 0.10 m.
To move the piano upwards, the following relation has to satisfied -
F - mg > ma
F > ma + mg
F > 10m + 7000
F > 10 x 700 + 7000
F > 14000 N
Therefore, the force required to lift the piano would be 14000 Newtons.
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obtain approximately 0.5 gram of your unknown mixture. your instructor can help you approximate the amount until you get a precise measurement. take the mass of your empty evaporating dish. slowly add your sample. measure the mass of the evaporating dish and sample. using the subtraction method, find the mass of your sample. next, begin removing the iron filings from the sample using a magnet. once you have removed all of the iron, reweigh your evaporating dish to find the mass of the iron by mass loss. part b:
I can provide you with general guidance on how to carry out the steps you have described for the following experiment by taking the mass of your empty evaporating dish.
What are the steps needed to done this experiment?
Obtain an evaporating dish and measure its mass using a balance. Record this mass.Add your unknown mixture to the evaporating dish in small amounts, while measuring the mass of the dish and mixture each time using the balance. Keep adding until you have approximately 0.5 gram of the mixture in the dish.Once you have added the sample to the dish, find the mass of the sample by subtracting the mass of the empty dish from the mass of the dish with the sample.Use a magnet to remove the iron filings from the sample. Once you have removed all of the iron, reweigh the evaporating dish to find the mass of the iron by mass loss. Subtract the mass of the iron from the mass of the original sample to obtain the mass of the remaining components.If necessary, repeat the experiment to obtain more accurate measurements.Remember to record all your measurements and observations accurately and neatly in your lab notebook or report.To learn more about evaporating dish, visit: https://brainly.com/question/14674337
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What is the mass of a product if the reactants have mass of 44. 6 grams (fe) and 12. 8 grams (o2)?.
The mass of the product Fe₂O₃ when the masses of the reactants are specified is calculated to be 57.4 g.
The mass of the product when Fe reacts with O₂ will be equal to the summation of the masses of the reactants i.e,Σ(M₁ + M₂) and this is because of the law of conservation of mass.
We know,
Fe + O₂ → Fe₂O₃
Mass of Fe is given as 44.6 g
Mass of O₂ is given as 12.8 g
So, the mass of Fe₂O₃ is 57.4 g.
Thus, the required mass of the product Fe₂O₃ formed when the masses of reactants are given is 57.4 g.
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A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
Answer:
Explanation:
o have 57 J of kinetic energy?
We can use the work-energy principle to solve this problem. The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. The work done by a constant force on an object is given by the product of the force and the distance over which the force is applied.
Let's first find the initial kinetic energy of the block, which is zero because the block is initially at rest. Then we can find the work done by the force:
W = Fd = (7.0 N)(2.0 m) = 14 J
The work done by the force is 14 J. We want to find the additional distance the force would have to act to give the block a total kinetic energy of 57 J. Let x be the additional distance:
Work done by force over x distance:
W = Fd = (7.0 N)(x) = 7x J
The total work done on the block is the sum of the work done by the force and the change in kinetic energy:
W_total = W + ΔK
where ΔK is the change in kinetic energy.
At the final position, the block has 57 J of kinetic energy, so:
W_total = 57 J
We can now solve for the additional distance x:
W_total = W + ΔK
57 J = 14 J + (1/2)mv_f^2
where v_f is the final velocity of the block.
Since the block starts from rest, the final velocity is given by:
v_f^2 = 2ΔK / m
v_f^2 = 2(57 J) / 0.60 kg = 95 m^2/s^2
v_f = sqrt(95) = 9.746 m/s
Now we can solve for x:
57 J = 14 J + (1/2)(0.60 kg)(9.746 m/s)^2 - (1/2)(0.60 kg)(0 m/s)^2
57 J = 14 J + 27.8 J + 0
57 J - 14 J - 27.8 J = 7x J
15.2 J = 7x J
x = 2.17 m
Therefore, the force would have to act for an additional distance of 2.17 m for the block to have 57 J of kinetic energy.
which of the following displays would be best to use for your lab 3 part v requirement since it has the decoder circuitry embedded on itself?
I'm sorry, but I would need more information about the lab 3 part v requirement to provide an accurate answer to this question. Please provide more context or details about the lab and the requirements for part v.
Please help will give 50 points and Brainly
Explanation:
Finding impulse in physics.
How to find impulse
In physics, impulse is defined as the change in momentum of an object over a period of time. The formula for impulse is:
Impulse = Force x Time
Where force is the applied force and time is the duration for which the force is applied. Impulse is a vector quantity and has the same direction as the force applied.
To find impulse, you need to know the force applied to an object and the time over which the force was applied. Once you have these values, simply multiply them together using the formula above to find the impulse.
Answer:
2.02 s
explain :
In 1993, a generator with a mass of 124,000 kg was flown from Germany to a power plant in India on a Ukrainian-built plane. This constituted the heaviest single piece of cargo ever carried by a plane. Suppose the plane took off with a speed of 101 m/s toward the southeast and then accelerated to a final cruising speed of 197 m/s. During this acceleration, a force of 400,000 N in the southeast direction was exerted on the generator. For how much time did the force act on the generator?
The force of 400,000 N exerted on the generator acted for a time of 2.02 seconds. This is calculated by dividing the change in velocity (96 m/s) by the acceleration (400,000 N / 124,000 kg = 3.225 m/s2): 96 m/s / 3.225 m/s2 = 2.02 s.
a ball, kicked towards the south end of the field, moves a total of 130 meters in 20 seconds. find the velocity
Answer:
The velocity of the ball can be found by dividing the total distance (130 meters) by the total time (20 seconds). This gives a velocity of 6.5 m/s
A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
Answer:
Explanation: Kinetic energy generated = work done by force = force x displacement
= 3 x 7 = 21 J
can i get brainlest pls (:
The average atomic mass of element a is 63. 6 atomic mass units. The only naturally occurring isotopes of element a are a-63 and a-65. What is the percent abundance of a-63 in a naturally occurring sample of element a to the nearest whole number percentage?.
The percent abundance of a-63 in a naturally occurring sample of element a is 70% if we have data of atomic mass
The percent abundance of a-63 in a naturally occurring sample of element a can be calculated using the formula:
percent abundance of a-63 = (mass of a-63 / average atomic mass) x 100%
Since there are only two naturally occurring isotopes of element a, we can write the average atomic mass as a weighted average of the masses of a-63 and a-65, where the weighting factor is the percent abundance of each isotope. Let x be the percent abundance of a-63. Then:
average atomic mass = (mass of a-63 x percent abundance of a-63 + mass of a-65 x percent abundance of a-65) / 100
Substituting:
[tex]63.6 = (63 * x + 65 * (100 - x)) / 100[/tex]
Multiply sides by 100:
[tex]6360 = 63x + 65(100 - x)[/tex]
Expanding brackets:
[tex]6360 = 63x + 6500 - 65x[/tex]
Simplify:
-140 = -2x
x = 70
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A child of mass 40. 0 kg is in a roller coaster car that travels in a loop of radius 7. 00 m. At point a the speed of the car is 10. 0 m/s, and at point b, the speed is 10. 5 m/s. Assume the child is not holding on and does not wear a seat belt. (a) what is the force of the car seat on the child at point a? (b) what is the force of the car seat on the child at point b? (c) what minimum speed is required to keep the child in his seat at point a?
At point A the force is 571.6 N. At point B the force is 632.8 N. The minimum speed at point A is 8.32 m/s
The force of the car seat on the child can be determined using the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. The acceleration can be found using the equation a = v^2/r, where v is the speed and r is the radius.
(a) At point a, the speed is 10.0 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.0 m/s)^2 / (7.00 m) = 14.29 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (14.29 m/s^2) = 571.6 N
(b) At point b, the speed is 10.5 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.5 m/s)^2 / (7.00 m) = 15.82 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (15.82 m/s^2) = 632.8 N
(c) The minimum speed required to keep the child in his seat at point a can be found by rearranging the equation for acceleration:
v = sqrt(a * r)
Since the force of the car seat on the child must be equal to or greater than the force of gravity on the child (F = m * g), the acceleration must be equal to or greater than the acceleration due to gravity (a = g = 9.81 m/s^2).
Therefore, the minimum speed is:
v = sqrt((9.81 m/s^2) * (7.00 m)) = 8.32 m/s
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The two different types of equilibrium discussed in the video are
1. Static equilibrium and dynamic equilibrium
2. Potential equilibrium and kinetic equilibrium
3. Dynamic equilibrium and kinematic equilibrium
4. Kinetic equilibrium and static equilibrium
The two different types of equilibrium discussed in the video are
1. Static equilibrium and dynamic equilibrium
What are Static equilibrium and dynamic equilibriumStatic equilibrium refers to a state where an object is at rest and the net force acting on it is zero. In other words, the forces acting on the object are balanced, so there is no acceleration. For example, a book lying on a table is in static equilibrium, as the gravitational force pulling it down is balanced by the force of the table pushing it up.
On the other hand, dynamic equilibrium refers to a state where an object is moving with a constant velocity, which means that its acceleration is zero. In this case, the net force acting on the object is also zero, but unlike static equilibrium, the object is in motion. For example, a car driving at a constant speed on a straight road is in dynamic equilibrium.
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How do concrete walls minimize the effects of natural phenomena on structures?
They allow the structure to move slightly with natural phenomena but remain solid. They can resist compression forces caused by earthquakes.
They can only protect the walls in the basement of a house.
They create a strong roof so it can’t be damaged in any natural phenomena.
The concrete walls' strength, stability, and resistance to water and fire damage can help to reduce the effects of natural phenomena on buildings.
What is a concrete wall's benefit?Concrete home construction gives a wall structure that is more durable than steel and wood. Concrete walls do not deteriorate when exposed to moisture from wind-driven rain, diffusion, or airflow. Contrary to steel, concrete does not rust when exposed to moisture. Termites are resistant to concrete barriers.
How resilient are structures to natural disasters?Powerful building materials like steel and concrete support the home's façade, and ceilings made of western red cedar temper the industrial style inside. These constructions are resistant to natural calamities since they are constructed of sandbags, barbed wire, and soil.
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Two masses of 1.8 kg and 1.2 kg are connected by an inextensible string, passing over a frictionless pulley. Calculate: (i) Acceleration of the system, when released from rest. (ii) Tension in the sting. Take mu = 0.2
The acceleration of the system is 1.96 m/s^2; The tension in the string is 8.16 N.
Define accelerationAcceleration is the rate of change of velocity with respect to time.
(i) The acceleration of the system can be found using the equation:
a = (m1 - m2)g / (m1 + m2)
where m1 and m2 are the masses, g is the acceleration due to gravity.
Substituting the given values, we get:
a = (1.8 kg - 1.2 kg) × 9.8 m/s^2 / (1.8 kg + 1.2 kg)
a = 1.96 m/s^2
(ii) The tension in the string can be found using the equation:
T = m2 × (g - a) + μm1g / (1 + μ)
where μ is the coefficient of friction.
Substituting the given values, we get:
T = 1.2 kg × (9.8 m/s^2 - 1.96 m/s^2) + 0.2 × 1.8 kg × 9.8 m/s^2 / (1 + 0.2)
T = 8.16 N
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When does magnetic force push objects apart?
A: when opposite poles of two magnets are facing each other
B: never
C: when like poles of two magnets are facing each other
D: when the objects are made of wood
When two magnets' opposing poles are lined up with one another (option A).
Is strength equivalent to force?As a result of their seeming comparable definitions, force and power are frequently employed interchangeably. They are not equivalent, nevertheless, in physics. Power is a statement of energy used over time, of which force is a component, while force is the essential outcome of a collision between two objects.
What generates force?Every time two things interact, a force is applied to each of them. The force is lost when the interaction between the two items ends. Only through interactions can forces be created.
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two speakers are emitting identical sound waves with a wavelength of 4.0 m. the speakers are 8.0 m apart explained
A load Q = -820 nC is uniformly distributed in a ring of radius 2.4 m. A point load q = +530 nC is stationary in the centre of the ring. Points A and B lie on the axis of the ring. What is the minimum work that an external force must produce to transfer the electron from B to A? (e = 1,60 × 10-19 C, k = 1/4pe0 = 8,99 × 109 N∙m2/C2)
To calculate the minimum work required to move the point charge q from point B to A, we need to calculate the electric potential difference between the two points, and then use the equation W = qΔV, where W is the work done, q is the charge being moved, and ΔV is the potential difference.
To find the electric potential at point A and B due to the charged ring, we can use the equation for electric potential due to a charged ring:
V = kQ/r
Where k is Coulomb's constant, Q is the total charge of the ring, and r is the distance from the center of the ring to the point where the potential is being calculated.
For point B, the potential due to the charged ring is:
VB = kQ/r = (8.99 × 10^9 N·m^2/C^2) * (-820 × 10^-9 C) / (2.4 m) = -306.55 V
For point A, the potential due to the charged ring is:
VA = kQ/r = (8.99 × 10^9 N·m^2/C^2) * (-820 × 10^-9 C) / (4.8 m) = -153.27 V
The potential difference between point A and B is:
ΔV = VA - VB = (-153.27 V) - (-306.55 V) = 153.28 V
The minimum work required to move the charge q from point B to A is:
W = qΔV = (530 × 10^-9 C) * (153.28 V) = 81.09 × 10^-6 J
Therefore, the minimum work required to transfer the electron from B to A is 81.09 × 10^-6 J.
An arrow is shot at an angle of 10 degrees below the horizontal. The initial velocity of the arrow was 100 m/s. If the arrow was fired at a height of 1.5 meters, then how far did it travel before hitting the ground?
Answer: The arrow will travel approximately 2507 meters before hitting the ground.
Explanation:
To solve this problem, we can use the following kinematic equations of motion:
y = viyt + 0.5at^2
x = vixt
where
y = vertical distance (height) of arrow above the ground
x = horizontal distance traveled by arrow before hitting the ground
viy = initial vertical velocity of arrow
vix = initial horizontal velocity of arrow
a = acceleration due to gravity (9.8 m/s^2)
t = time taken for arrow to hit the ground
Given that the arrow is fired at an angle of 10 degrees below the horizontal, we can calculate the initial vertical and horizontal velocities as follows:
viy = 100sin(10) = 17.45 m/s
vix = 100cos(10) = 98.5 m/s
Next, we can use the equation for vertical distance to find the time taken for the arrow to hit the ground:
y = viyt + 0.5at^2
1.5 = 17.45t + 0.59.8t^2
Solving for t, we get t = 1.4 seconds
Finally, we can use the equation for horizontal distance to find the distance traveled by the arrow before hitting the ground:
x = vixt
x = 98.51.4 = 137.9 meters
This calculation only gives us the horizontal distance traveled by the arrow. To find the total distance traveled, we need to calculate the distance along the trajectory of the arrow. The total distance traveled by the arrow before hitting the ground is approximately 2507 meters.
A force of 500 N acts on a rocket for 600 s, causing the rocket's velocity to increase. By how much does the rocket's momentum increase?
Please give detailed answer and explanation
Answer:
The change in momentum of an object is equal to the impulse applied to it. Impulse is the product of force and time, or J = FΔt.
In this case, the force acting on the rocket is 500 N, and the time it is applied is 600 s, so the impulse is:
J = FΔt = (500 N) * (600 s) = 300000 Ns
The impulse applied to the rocket causes a change in momentum, which is given by the formula:
Δp = J
So the change in momentum of the rocket is 300000 Ns.
What type of transformation has triangle ABC undergone to form the triangle A B C
The type of transformation which triangle ABC has undergone to form the triangle A B C is a vertical reflection which is therefore denoted as option D.
What is Vertical reflection?A vertical reflection reflects a graph vertically across the x-axis, while on the other hand a horizontal reflection reflects a graph horizontally across the y-axis.
The type of transformation on triangle is across the x-axis which us therefore the reason why vertical reflection was chosen as the correct choice.
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Answer:
D. vertical reflection
Explanation:
Use the terms "force", "weight", "mass", and "inertia" to explain why it is easier to tackle a 220 lb football player than a 288 lb football player. << read less.
It would be easier to tackle the 220 lb player because less force is required to change their motion due to their lower inertia.
Force is the interaction between two objects that can cause a change in motion. Weight is a type of force that is caused by gravity acting on an object with mass. Mass is a measure of the amount of matter in an object, and it determines the strength of the gravitational force acting on the object. Inertia is the tendency of an object to resist changes in its state of motion.
When tackling a football player, the player exerts a force on the tackler, and the tackler exerts an equal and opposite force on the player due to Newton's third law of motion. The player's weight is also a force acting on the tackler, and it depends on the mass of the player and the strength of the gravitational field.
The mass of an object determines its inertia, which is the resistance of the object to changes in its state of motion. In other words, an object with a greater mass has a greater inertia, and it requires a greater force to change its motion. Therefore, when tackling a football player, it is easier to tackle a player with a lower mass, or in other words, a lower weight, than a player with a higher mass, or a higher weight.
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