9. A mouse has a mass of 0. 4kg. What is its weight? (acceleration due to gravity on Earth is 9.8m/s2 = g)


Answers

Answer 1

Answer:

Weight = 3.92 N

Explanation:

Given:

Mass m = 0.4 kg

Acceleration due to gravity g = 9.8 m/s²

Find:

Weight

Computation:

Weight = Mass x Acceleration due to gravity

Weight = 0.4 x 9.8

Weight = 3.92 N


Related Questions

a cyclist accelerates at a rate of 7.0 m/s2. how long will it take the cyclist to go from a velocity of 4 m/s to a velocity of 18 m/s?​

Answers

Answer:

2.57 seconds  (rounded to 2.6 Seconds)

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,

Where:

Vf is the final Velocity

Vi is the initial velocity

A is the acceleration

t is the time in seconds

Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).

Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

how large amount of energy is produced during the fission of uranium ​

Answers

Answer:

answer is a very large amount of energy is produced from a very small mass

Explanation:

nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)

Suppose you had the same laser and diffraction grating from the previous question but now you had a flat detection screen. You want to use this set up to measure the displacement due to small vibrations of the detection screen. (The vibrations cause the screen to move closer and farther from the grating.) A. Describe how you would do measurements for this experiment to determine the displacement of the detection screen.

Answers

Answer:

measuring the zero intensity point, we can deduce the movement of the screen.

The distance from the center of the pattern to the first zero is proportional to the distance to the screen,

Explanation:

The expression for the diffraction phenomenon is

           a sin θ = m λ

for the case of destructive interference. In general the detection screen is quite far from the grid, let's use trigonometry to find the angles

           tan θ = y / L

     

in these experiments the angles are small

          tan θ = sin θ / cos θ = sin θ

          sunt θ = y / L

we substitute

          a [tex]\frac{y}{L}[/tex]= m  λ

           y = m L λ / a

therefore, by carefully measuring the zero intensity point, we can deduce the movement of the screen.

 

The distance from the center of the pattern to the first zero is proportional to the distance to the screen, so you can know where the displacement occurs, it should be clarified that these displacements are very small so the measurement system must be capable To measure quantities on the order of hundredths of a millimeter, a micrometer screw could be used.

Help me please,

A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?

A) v 0m/s, = 0m/s/s

B) v = 0m/s, a 10m/s/s

C) v = 10m/s, a 10m/s/s

D) v = 10m/s, a = 0m/s/s

E) None of the above

Answers

Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

10 Select the correct answer. What property of a wave remains unchanged when a wave enters a different medium? O A amplitude OB. frequency OC. wavelength OD. velocity O E. density Reset​

Answers

a and b ik thats the awser becuse imjust did it

Answer:

B frequency

Explanation:

if the frequency changes so does the energy and that doesn't happen to EM waves entering a medium by the conservation of energy

Correct me if im wrong but im 100% its B

suppose you drop an object and it strikes the ground. you can calculate the velocity of the object as it strikes the ground using the law of conservation of energy. in order to do this, you need to know the original height of the object. do you also need to know the mass of the object? why or why not?

a. you do not need to know the mass because you can compute it based on the provided information.
b. you do not need to know the mass because it cancels out.
c. you need to know the mass of the object in order to compute the kinetic and gravitational potential energies.
d. you need to know the mass of the object in order to compute the elastic potential energy.

Answers

Answer:

b)

Explanation:

Assuming no friction forces present, the total mechanical energy must be conserved, so at any moment, the sum of  the gravitational potential energy and the kinetic energy must be the same.When the object is dropped, all the energy is gravitational, as follows:E = m*g*h (1)When the object strikes the ground, if we choose the ground as the zero reference level for the gravitational potential energy, all the energy is kinetic:E = 1/2*m*v² (2)Since E is constant, left sides in (1) and (2) are equal each other, so the right sides must be equal each other too.Since the mass is present in the right side of (1) and (2) it cancels out, so b) is the right answer.

Answer: B you do not need to know the mass because it cancels out

Explanation:

A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?

Answers

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

[tex]m = \frac{p}{v} [/tex]

[tex]m = \frac{36}{4} [/tex]

[tex]m = 9kg[/tex]

Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster

Answers

Answer:

52.095 m/s

Motorcycle a was moving faster

Explanation:

We start by using one of the equations of motion

V = u + at

If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as

V(a) = u(a) + a(a).t

If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as

V(b) = u(b) + a(b).t

Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have

0 = u(a) - u(b) + a(a).t - a(b).t

-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have

u(b) - u(a) = [a(a) - a(b)]t

Since we have the values for acceleration and the time, we substitute so that

u(b) - u(a) = (4.55 - 18.9)3.63

u(b) - u(a) = -14.35 * 3.63

u(b) - u(a) = -52.095, or we rearrange to get

u(a) - u(b) = 52.095 m/s

A 2-kg body of mass is moving on a horizontal frictionless surface with a
velocity of 4 m/s. What is the net force required to keep the body moving with
the same velocity and direction for 5 s?

Answers

Answer:

Force=m×a. a(which is acceleration)=V/t

what is the name of this element?​

Answers

Answer:

fluorine is the right answer of this question

The circular plates of a parallel-plate capacitor have a radius of 30 mm. A steady 0.43-mA current is charging the initially uncharged capacitor, and the surface charge on the plates is distributed uniformly. The flat circular surface between the capacitor plates is coaxial and parallel to the plates, and has a radius of 13 mm. Calculate the magnetic field at any point on the circumference of the circular region (in Tesla).

Answers

Solution :

The electric field between two plates is given by

[tex]$E = \frac{q}{\varepsilon_0 A}$[/tex]

where

[tex]$\varepsilon_0 = $[/tex] permitivity of free space

 q = charge

 A = surface area

It is given that  :

the radius of the circular plates , r = 30 mm

the current, I = 0.43 mA

Therefore, Magnetic field can be found by

[tex]$B \times 2 \pi r = \mu_0 I_{(enclosed)}$[/tex]

[tex]$\Rightarrow B = \frac{\mu_0}{2 \pi r} \times (0.43 \ mA) \times \left(\frac{13 \ mm}{30 \ mm}\right)^2$[/tex]

[tex]$\Rightarrow B = \frac{2 \times 10^{-7}}{13 \times 10^{-3}} \times 0.43 \times 10^{-3} \times \left(\frac{13 }{30 }\right)^2$[/tex]

[tex]$\Rightarrow B = 1.2 \times 10^{-9} \ T$[/tex]

An inductor of 247 mH with a resistance of 37 Ω is connected to a power supply with a maximum voltage of 336 V and a frequency of 71 Hz. Find the current in the circuit. Answer in units of A. 022 (part 2 of 3) 10.0 points Find the phase angle between the current and applied voltage. Answer in units of ◦ . 023 (part 3 of 3) 10.0 points Find the power loss in the inductor. Answer in units of W.

Answers

Answer:

(i) The current in the circuit is 2.044 A

(ii) the phase angle is 71.441⁰

(iii) The power loss in the inductor is 154.58 W

Explanation:

Given;

inductance, L = 247 mH

resistance, R = 37 Ω

maximum voltage, V₀ = 336 V

frequency, f = 71 Hz

The rms voltage is given as;

[tex]V_{rms} = 0.7071V_o\\\\V_{rms} = 0.7071 \ \times \ 336\\\\V_{rms} = 237.586 \ V\\[/tex]

The inductive reactance is given as;

[tex]X_l = \omega \ L\\\\X_l = 2\pi f L\\\\X_l = 2\pi (71)(247 \times 10^{-3})\\\\X_l = 110.202 \ ohms[/tex]

The impedance of the A.C circuit is given as;

[tex]Z = \sqrt{X_l^2 + R^2} \\\\Z = \sqrt{(110.202)^2 + (37)^2}\\\\Z = 116.248 \ ohms[/tex]

(i) The current in the circuit is given as;

[tex]I_{rms} = \frac{V_{rms}}{Z}\\\\ I_{rms} =\frac{237.586}{116.248} \\\\I_{rms} =2.044 \ A[/tex]

(ii) the phase angle is given as;

[tex]tan \phi = \frac{X_l}{R}\\\\tan \phi =\frac{110.202}{37} \\\\ tan \phi =2.9784\\\\\phi = tan^{-1} (2.9784)\\\\\phi = 71.441 ^0 \\\\[/tex]

(iii) The power loss in the inductor is given as;

P = IVcosΦ

P = (2.044)(237.586)Cos(71.441⁰)

P = 154.58 W

An aluminum baking sheet with a mass of 225 g absorbs 2.4 x 104 J from an oven. If its temperature was initially 25 C, what will its new temperature be?

Answers

Answer:

The value is [tex]T_2 =416.9 \ K[/tex]

Explanation:

From the question we are told that

     The mass of the aluminum baking sheet is  [tex]m = 225 \ g = 0.225 \ kg[/tex]

      The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]

       The initial  temperature is  [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]

   

Generally the heat absorbed is mathematically represented as

         [tex]Q = m * c_a * [T_2 - T_1][/tex]

Here  [tex]c_a[/tex] is the specific heat capacity of  aluminum with value  [tex]c_a = 897 \ J / kg \cdot K[/tex]

So

           [tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]

=>         [tex]T_2 - 298 = 118.915[/tex]

=>          [tex]T_2 =416.9 \ K[/tex]

A train moving with a speed of 20.9 m/s sounds a 103 Hz horn. What frequency is heard by an observer standing near the tracks as the train approaches

Answers

Answer:

observed frequency =  109.68 Hz

Explanation:

given data

speed u = 20.9 m/s

frequency f = 103 Hz

solution

we consider here speed of sound (v)  is 343 m/s

so observed frequency is express as

observed frequency = f × [tex]\frac{v}{v-u}[/tex]     ...............1

put here value and we get

observed frequency =  103 × \frac{343}{343-20.9}

observed frequency =  109.68 Hz

A 5 kg block rests on an inclined plane with a coefficient of static friction equal to 0.30. What is the minimum angle at which the block will begin to slide

Answers

Answer:

[tex]\theta = 16.70 ^{\circ}[/tex]

Explanation:

The coefficient of static friction is equal to the tangent of the minimum angle at which an object will begin to start sliding down a ramp.  

[tex]\displaystyle u_s=\frac{F_f}{F_N} = \frac{F_g\ \text{sin}\theta}{F_g\ \text{cos} \theta} = \text{tan} \theta[/tex]

Since we are given the coefficient of static friction we can solve for the minimum angle that the block will begin to slide.

Let's solve for the force of gravity that is acting on the block. The force of gravity is also known as the weight force, which can be calculated by using w = mg.

[tex]w=mg[/tex]

We are given the mass of the block (kg) and we know that g = 9.8 m/s².

[tex]w=(5)(9.8) = 49 \ \text{N}[/tex]

Now we can use this force in the equation:

[tex]\displaystyle u_s = \frac{F_g \ \text{sin} \theta }{F_g \ \text{cos} \theta}[/tex]

Plug [tex]\displaystyle u_s = 0.30[/tex] and 49 N into the equation.

[tex]\displaystyle 0.30 = \frac{(49) \ \text{sin} \theta }{(49) \ \text{cos} \theta}[/tex]  [tex]0.30=\text{tan} \theta[/tex]

Notice that the gravitational force cancels out in the end, so we can actually start with [tex]0.30=\text{tan} \theta[/tex].

Evaluate this equation by taking the inverse tangent of both sides of the equation.

[tex]\text{tan}^-^1 (0.30) = \text{tan}^-^1 (\text{tan}\theta)[/tex] [tex]\text{tan}^-^1 (0.30) =\theta[/tex] [tex]\theta = 16.69924423[/tex]

The minimum angle at which the block will begin to slide is about 16.70 degrees.

True or False: As water evaporates, it removes a lot of heat with it.

Answers

Answer:

True, when it evaporates heat goes down, because it’s up the the sky.

Facts: In order for water to evaporate, hydrogen bonds must be broken. Water's heat of vaporization is 540 cal/g.

Because of the need for so much energy to evaporate, as water leaves the surface from which it is evaporating and removes a lot of heat with it.

Help me please..

Suppose a car is moving in a straight line and steadily increases its
speed. It goes from 0 miles/hour to 15 miles/hour the first second and 15
miles/hour to 30 miles/hour the next second. What is the acceleration?

A)10 miles/hour/second

B) 15 miles/hour/second

C) 20 miles/hour/second

D)30 miles/hour/second

Answers

it’s B, 15 miles per hour

An ideal gas, at initial temperature T1 and initial volume 3.1 m3, is expanded adiabatically to a volume of 7.1 m3, then expanded isothermally to a volume of 23 m3, and then compressed adiabatically back to T1. What is its final volume?

Answers

Answer:

10.0 m³

Explanation:

The gas initially starts expanding adiabatically from state 1 until it reaches state 2, with V2 being 7.1 m³ then it goes on to continue on to state 3 isothermally, with V3 being 23 m³ and finally gets compressed adiabatically to reach state 4.

For the adiabatic process in stage 1 to 2, we have that

P1V'1 = P2V'2

For the isothermal process in stage 2 to 3, we have that

P2V2 = P3V3

For the adiabatic process in stage 3 to 4, we have that

P3V'3 = P4V'4

Starting from the ending, we see that

P4 = P3 * (V3/V4)',

Going backwards we see that

P4 = P2 * (V2/V3) * (V3/V4)'

Going further backwards, we see that

P4 = P1 * (V1/V2)' * (V2/V3) * (V3/V4)'

We substitute expression for P4 into the equation P1V1 = P4V4 with T being constant, and then get V1V3 = V2V4

Trying to solve for V4, we get

V4 = V1V3/V2

V4 = (3.1 * 23) / 7.1

V4 = 71.3 / 7.1

V4 = 10.0 m³

a wandering dog walks 1 km due east, 1 km due south, then runs 2 km due west. the magnitude of the dogs displacement is closest to
a. 0 km
b. 1.4 km
c. 3.4 km
d. 4.0 km​

Answers

Answer:

b) 1.4km

Explanation:

A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force

Answers

Answer:

F = 6[N].

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 10 [kg]

v = velocity [m/s]

F = force [N]

t = time = 5 [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 10 [kg]

v₁ = velocity of the object before the impulse = 1 [m/s]

v₂ = velocity of the object after the impulse = 4 [m/s]

[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]

A car accelerates from rest at a constant rate 5m/s^2. Which of the following statements is true

Answers

Answer:

jjhbkvjuhigjgyihbgtimnvyuoibc

Need ASAP
which is one characteristic shared by electromagnetic and mechanical waves?
A: both have a crest and a trough
B: both move due to particles
C: both are formed by charged particles
D: both occur as a result of a disturbance

Answers

Answer:

Both are formed by charged particles.

Explanation:

Answer:

A: both have a crest and a trough

Explanation:

vote edge 2020

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4.0 m/s^2. Find the final velocity of the roller coaster ?​

Answers

[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ (u) = 13 \ m/s }[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Distance \ (s) = 400 \ m }[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{ Acceleration = 4 \ m/s^2}[/tex]

[tex]\\[/tex]

[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{The \:Final \:velocity \:of \:the\: body }[/tex]

[tex]\\[/tex]

[tex]{\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\[/tex]

Using 3rd equation of motion

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} +2as }[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {13}^{2} + 2 \times 4 \times 400 }[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{{v}^{2} = 169 + 3200 }[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{ {v}^{2} = 3369 }[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{ v = \sqrt{3369} }[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \underline{\boxed{\sf{ v = 58.04 \: m/s }}}[/tex]

[tex]\\[/tex]

[tex]{\mathfrak{\underline{\purple{\:\:\:Additional \:Information:-\:\:\:}}}} \\ \\ [/tex]

Equations Of Motion

[tex]\\[/tex]

[tex]\boxed{

\begin{minipage}{3 cm}$\\

\sf{\:\:\star\:\:v = u +at} \\ \\

\sf{\:\:\star\:\:s = ut + \dfrac{1}{2}\:at^{2} }\\ \\

\sf{\:\:\star\:\:v^{2} = u^{2} + 2as}\\ \\

\sf{\:\:\star\:\:s = \dfrac{1}{2} (u + v)t}\\$

\end{minipage}

} [/tex]

[tex]\\[/tex]

[tex]\sf{Where,}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\textsf{s = Distance}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}[/tex]

A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?

Answers

Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h

What is the average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s

Answers

Answer:

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 [tex]\frac{m}{s}[/tex].

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

[tex]velocity=\frac{displacement}{time}[/tex]

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.

In this case, the displacement is 192 m and the time period is 8 s. Replacing:

[tex]velocity=\frac{192 m}{8 s}[/tex]

Solving:

velocity= 24 [tex]\frac{m}{s}[/tex]

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 [tex]\frac{m}{s}[/tex].

If the acceleration of the negative charge is to the right. And the magnetic field is pointed downwards. What direction was the negative charge moving originally?

Answers

probably down because it’s negative

Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.

Answers

Answer:

The magnetic field strength needed is 1.5 T.

Explanation:

Given;

number of turns, N = 200 turn

length of the each side of the square loop, L = 20 cm = 0.2 m

maximum torque created, τ = 300 N-m

current through the loop, I = 25 A

The maximum torque created in the is the loop is given by;

τ = NIBA

Where;

B is the magnetic field strength, which is calculated as;

[tex]B = \frac{\tau}{NIA}\\\\B = \frac{300}{200 \times \ \ 25 \ \times\ \ (0.2)^2}\\\\B = 1.5 \ T \\[/tex]

Therefore, the magnetic field strength needed is 1.5 T.

Induced magnetic field strength is defined as the number of magnetic flux lines per unit area.The magnetic field strength will be 1.5 T.

What is magnetic field strength?

Induced magnetic field strength is defined as the number of magnetic flux lines per unit area that pass perpendicular to a particular line direction. B stands for it.

The given data in the problem is

(I) is the current=25.0A

B is the induced magnetic field=?

τ is the Torque= 300 N-M

n is the number of loop=200

L is length of the each side of the square loop = 20 cm = 0.2 m

The maximum torque created in the loop will be

[tex]\rm \tau =NIBA\\\\ \rm B=\frac{\tau}{IBA} \\\\\rm B=\frac{600}{200\times25\times(0.2)^2}\\\\\rm B=1.5T\\[/tex]

Hence the magnetic field strength will be 1.5 T.

To learn more about the strength of induced magnetic field ;

https://brainly.com/question/2248956

What is the average speed of the toy car in the investigation?
0.25 m/s
4.0 m/s
5.0 m/s
20 m/s

Answers

Answer:

I would got with A or B because they seem more reasonable. Hope this helps and good luck :)

4. A little boy pushes a wagon with his dog in it. The mass of the dog and
wagon together is 70 kg. The wagon accelerates at 0.85 m/s². What force is
the boy pulling with? F=mxa

Answers

Answer:

59.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 70 × 0.85

We have the final answer as

59.5 N

Hope this helps you

A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to slow down to 12.6 m/s. How long was this force applies?

Answers

Answer:

t = 1.4[s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 50 [kg]

v = velocity [m/s]

F = force = 200[N]

t = time = [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})-F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 50 [kg]

v₁ = velocity of the object before the impulse = 18.2 [m/s]

v₂ = velocity of the object after the impulse = 12.6 [m/s]

[tex](50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s][/tex]

Other Questions
Help! Due soon! :) help me out and get some points How is the law of conservation of matter best represented in a chemical reaction The main goal of Junior Achievement is to F involve students in their local city government G help students earn money while attending school H allow students to improve businesses in their community J prepare students for adult responsibilities PLEASE HELP! FINALS! - Shawn bought a 10-pound turkey to serve for Thanksgiving. He plans to serve each adult 2/5 of a pound.Complete each of the 2 activities for this task.Activity 1 of 2 : Part A: Write an equation to represent the number of adult servings, x, Shawn can get from the 10 - pound turkey. Use your equation, x, Shawn can get from the 10 - pound turkey. Use your equation to determine the number of adult servings.Activity 2 of 2 : Part B: The price of a turkey is $1.36 per pound. Write an equation that can be used to determine the total cost, c, for a turkey that weighs *p* pounds. Then, find the cost of Shawn's turkey. What of the following happens first?A) Introns are edited out of premature RNAB) RNA polymerase reaches a terminator regionC) Nucleotides are covalently linked togetherD) RNA polymerase binds to a promoter region of DNA Help Please I Will mark Brainlest if you respond Which of the following bonds are most polar? Can you write a short story in at least ten sentences that includes a violin, a rainforest, some sort of fae, a fight scene, and an elder that is aggressively positive? Brainliest to whoever writes one first! Be creative and have fun writing!!! Based on the information in the table, which of the following arranges the bonds in order of decreasingpolarity?Choose 1 answer:H-S > Sn-Te > Si-FSn-Te > H-S > Si-FSi-F>H-S > Sn-TeSi-F > Sn-Te > H-S A microwave originally costs $96, but is marked up to a price of $115.20. What isthe percent increase? pls help pls ASAPWILL MARK BRAINLIIEST what's the slope for (-1,-6) and (5,-4) Dan drove 737 miles in 11 hours. At the same rate, how many miles would he drive in 13 hours? In 150 words or less explain the pacing of Hard Times and how it is achieved. Sara says, "If you subtract 17 from my number and multiply the difference by - 6, the result is- 36." What is Sara's number?Sara's number is Please Help Answer My Question(Worth 40 points.)Please read this except before answering my question, thanks!The Oregon Trailby Francis Parkman, Jr.1 The path soon after led inland and as we crossed an open meadow we saw a cluster of buildings on a rising ground before us, with a crowd of people surrounding them. They were the storehouse, cottage, and stables of the Kickapoo traders establishment. Just at that moment, as it chanced, he was beset with half the Indians of the settlement. They had tied their wretched, neglected little ponies by dozens along the fences and outhouses, and were either lounging about the place, or crowding into the trading house. Here were faces of various colors red, green, white, and black, curiously intermingled and disposed over the visage in a variety of patterns. Calico shirts, red and blue blankets, brass ear-rings, wampum necklaces, appeared in profusion. The trader was a blue-eyed openfaced man who neither in his manners nor his appearance betrayed any of the roughness of the frontier though just at present he was obliged to keep a lynx eye on his suspicious customers, who, men and women, were climbing on his counter and seating themselves among his boxes and bales.2 The village itself was not far off, and sufficiently illustrated the condition of its unfortunate and self-abandoned occupants. Fancy to yourself a little swift stream, working its devious way down a woody valley sometimes wholly hidden under logs and fallen trees, sometimes issuing forth and spreading into a broad, clear pool and on its banks in little nooks cleared away among the trees, miniature log-houses in utter ruin and neglect. A labyrinth of narrow, obstructed paths connected these habitations one with another. Sometimes we met a stray calf, a pig or a pony, belonging to some of the villagers, who usually lay in the sun in front of their dwellings, and looked on us with cold, suspicious eyes as we approached. Farther on, in place of the log-huts of the Kickapoos, we found the pukwi lodges of their neighbors, the Pottawattamies, whose condition seemed no better than theirs.3 Growing tired at last, and exhausted by the excessive heat and sultriness of the day, we returned to our friend, the trader. By this time the crowd around him had dispersed, and left him at leisure. He invited us to his cottage, a little white-and-green building, in the style of the old French settlements and ushered us into a neat, well-furnished room. The blinds were closed, and the heat and glare of the sun excluded the room was as cool as a cavern. It was neatly carpeted too and furnished in a manner that we hardly expected on the frontier. The sofas, chairs, tables, and a well-filled bookcase would not have disgraced an Eastern city though there were one or two little tokens that indicated the rather questionable civilization of the region. A pistol, loaded and capped, lay on the mantelpiece and through the glass of the bookcase, peeping above the works of John Milton glittered the handle of a very mischievous-looking knife.4 Our host went out, and returned with iced water, glasses, and a bottle of excellent claret a refreshment most welcome in the extreme heat of the day and soon after appeared a merry, laughing woman, who must have been, a year of two before, a very rich and luxuriant specimen of Creole beauty. She came to say that lunch was ready in the next room. Our hostess evidently lived on the sunny side of life, and troubled herself with none of its cares. She sat down and entertained us while we were at table with anecdotes of fishing parties, frolics, and the officers at the fort. Taking leave at length of the hospitable trader and his friend, we rode back to the garrison.How is paragraph 3 of the passage organized?A. cause and effectB. compare and contrastC. problem and solutionD. sequence of eventsPart BWhich word from the paragraph provides evidence to support the answer to Part A?A. frontierB. disgracedC. thoughD. questionable The sophmore class at south high school raised $800 from ticket sales for the dance. Tickets sold for $1.50 pre - sale, and $2.00 at the door. If a total of 475 tickets were sold how many tickets were sold at the door? how many times does 12 go into 60? Answer this question please!! Write an inequality to represent all combinations of numbers whose sum is greater than 10.