Answer:
Weight = 3.92 N
Explanation:
Given:
Mass m = 0.4 kg
Acceleration due to gravity g = 9.8 m/s²
Find:
Weight
Computation:
Weight = Mass x Acceleration due to gravity
Weight = 0.4 x 9.8
Weight = 3.92 N
An ideal gas, at initial temperature T1 and initial volume 3.1 m3, is expanded adiabatically to a volume of 7.1 m3, then expanded isothermally to a volume of 23 m3, and then compressed adiabatically back to T1. What is its final volume?
Answer:
10.0 m³
Explanation:
The gas initially starts expanding adiabatically from state 1 until it reaches state 2, with V2 being 7.1 m³ then it goes on to continue on to state 3 isothermally, with V3 being 23 m³ and finally gets compressed adiabatically to reach state 4.
For the adiabatic process in stage 1 to 2, we have that
P1V'1 = P2V'2
For the isothermal process in stage 2 to 3, we have that
P2V2 = P3V3
For the adiabatic process in stage 3 to 4, we have that
P3V'3 = P4V'4
Starting from the ending, we see that
P4 = P3 * (V3/V4)',
Going backwards we see that
P4 = P2 * (V2/V3) * (V3/V4)'
Going further backwards, we see that
P4 = P1 * (V1/V2)' * (V2/V3) * (V3/V4)'
We substitute expression for P4 into the equation P1V1 = P4V4 with T being constant, and then get V1V3 = V2V4
Trying to solve for V4, we get
V4 = V1V3/V2
V4 = (3.1 * 23) / 7.1
V4 = 71.3 / 7.1
V4 = 10.0 m³
Suppose you had the same laser and diffraction grating from the previous question but now you had a flat detection screen. You want to use this set up to measure the displacement due to small vibrations of the detection screen. (The vibrations cause the screen to move closer and farther from the grating.) A. Describe how you would do measurements for this experiment to determine the displacement of the detection screen.
Answer:
measuring the zero intensity point, we can deduce the movement of the screen.
The distance from the center of the pattern to the first zero is proportional to the distance to the screen,
Explanation:
The expression for the diffraction phenomenon is
a sin θ = m λ
for the case of destructive interference. In general the detection screen is quite far from the grid, let's use trigonometry to find the angles
tan θ = y / L
in these experiments the angles are small
tan θ = sin θ / cos θ = sin θ
sunt θ = y / L
we substitute
a [tex]\frac{y}{L}[/tex]= m λ
y = m L λ / a
therefore, by carefully measuring the zero intensity point, we can deduce the movement of the screen.
The distance from the center of the pattern to the first zero is proportional to the distance to the screen, so you can know where the displacement occurs, it should be clarified that these displacements are very small so the measurement system must be capable To measure quantities on the order of hundredths of a millimeter, a micrometer screw could be used.
A train moving with a speed of 20.9 m/s sounds a 103 Hz horn. What frequency is heard by an observer standing near the tracks as the train approaches
Answer:
observed frequency = 109.68 Hz
Explanation:
given data
speed u = 20.9 m/s
frequency f = 103 Hz
solution
we consider here speed of sound (v) is 343 m/s
so observed frequency is express as
observed frequency = f × [tex]\frac{v}{v-u}[/tex] ...............1
put here value and we get
observed frequency = 103 × \frac{343}{343-20.9}
observed frequency = 109.68 Hz
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
True or False: As water evaporates, it removes a lot of heat with it.
Answer:
True, when it evaporates heat goes down, because it’s up the the sky.
Facts: In order for water to evaporate, hydrogen bonds must be broken. Water's heat of vaporization is 540 cal/g.
Because of the need for so much energy to evaporate, as water leaves the surface from which it is evaporating and removes a lot of heat with it.
A 2-kg body of mass is moving on a horizontal frictionless surface with a
velocity of 4 m/s. What is the net force required to keep the body moving with
the same velocity and direction for 5 s?
Answer:
Force=m×a. a(which is acceleration)=V/t
A 5 kg block rests on an inclined plane with a coefficient of static friction equal to 0.30. What is the minimum angle at which the block will begin to slide
Answer:
[tex]\theta = 16.70 ^{\circ}[/tex]
Explanation:
The coefficient of static friction is equal to the tangent of the minimum angle at which an object will begin to start sliding down a ramp.
[tex]\displaystyle u_s=\frac{F_f}{F_N} = \frac{F_g\ \text{sin}\theta}{F_g\ \text{cos} \theta} = \text{tan} \theta[/tex]Since we are given the coefficient of static friction we can solve for the minimum angle that the block will begin to slide.
Let's solve for the force of gravity that is acting on the block. The force of gravity is also known as the weight force, which can be calculated by using w = mg.
[tex]w=mg[/tex]We are given the mass of the block (kg) and we know that g = 9.8 m/s².
[tex]w=(5)(9.8) = 49 \ \text{N}[/tex]Now we can use this force in the equation:
[tex]\displaystyle u_s = \frac{F_g \ \text{sin} \theta }{F_g \ \text{cos} \theta}[/tex]Plug [tex]\displaystyle u_s = 0.30[/tex] and 49 N into the equation.
[tex]\displaystyle 0.30 = \frac{(49) \ \text{sin} \theta }{(49) \ \text{cos} \theta}[/tex] [tex]0.30=\text{tan} \theta[/tex]Notice that the gravitational force cancels out in the end, so we can actually start with [tex]0.30=\text{tan} \theta[/tex].
Evaluate this equation by taking the inverse tangent of both sides of the equation.
[tex]\text{tan}^-^1 (0.30) = \text{tan}^-^1 (\text{tan}\theta)[/tex] [tex]\text{tan}^-^1 (0.30) =\theta[/tex] [tex]\theta = 16.69924423[/tex]The minimum angle at which the block will begin to slide is about 16.70 degrees.
What is the average speed of the toy car in the investigation?
0.25 m/s
4.0 m/s
5.0 m/s
20 m/s
Answer:
I would got with A or B because they seem more reasonable. Hope this helps and good luck :)
Need ASAP
which is one characteristic shared by electromagnetic and mechanical waves?
A: both have a crest and a trough
B: both move due to particles
C: both are formed by charged particles
D: both occur as a result of a disturbance
Answer:
Both are formed by charged particles.
Explanation:
Answer:
A: both have a crest and a trough
Explanation:
vote edge 2020
Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.
Answer:
The magnetic field strength needed is 1.5 T.
Explanation:
Given;
number of turns, N = 200 turn
length of the each side of the square loop, L = 20 cm = 0.2 m
maximum torque created, τ = 300 N-m
current through the loop, I = 25 A
The maximum torque created in the is the loop is given by;
τ = NIBA
Where;
B is the magnetic field strength, which is calculated as;
[tex]B = \frac{\tau}{NIA}\\\\B = \frac{300}{200 \times \ \ 25 \ \times\ \ (0.2)^2}\\\\B = 1.5 \ T \\[/tex]
Therefore, the magnetic field strength needed is 1.5 T.
Induced magnetic field strength is defined as the number of magnetic flux lines per unit area.The magnetic field strength will be 1.5 T.
What is magnetic field strength?Induced magnetic field strength is defined as the number of magnetic flux lines per unit area that pass perpendicular to a particular line direction. B stands for it.
The given data in the problem is
(I) is the current=25.0A
B is the induced magnetic field=?
τ is the Torque= 300 N-M
n is the number of loop=200
L is length of the each side of the square loop = 20 cm = 0.2 m
The maximum torque created in the loop will be
[tex]\rm \tau =NIBA\\\\ \rm B=\frac{\tau}{IBA} \\\\\rm B=\frac{600}{200\times25\times(0.2)^2}\\\\\rm B=1.5T\\[/tex]
Hence the magnetic field strength will be 1.5 T.
To learn more about the strength of induced magnetic field ;
https://brainly.com/question/2248956
An aluminum baking sheet with a mass of 225 g absorbs 2.4 x 104 J from an oven. If its temperature was initially 25 C, what will its new temperature be?
Answer:
The value is [tex]T_2 =416.9 \ K[/tex]
Explanation:
From the question we are told that
The mass of the aluminum baking sheet is [tex]m = 225 \ g = 0.225 \ kg[/tex]
The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]
The initial temperature is [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]
Generally the heat absorbed is mathematically represented as
[tex]Q = m * c_a * [T_2 - T_1][/tex]
Here [tex]c_a[/tex] is the specific heat capacity of aluminum with value [tex]c_a = 897 \ J / kg \cdot K[/tex]
So
[tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]
=> [tex]T_2 - 298 = 118.915[/tex]
=> [tex]T_2 =416.9 \ K[/tex]
what is the name of this element?
Answer:
fluorine is the right answer of this question
10 Select the correct answer. What property of a wave remains unchanged when a wave enters a different medium? O A amplitude OB. frequency OC. wavelength OD. velocity O E. density Reset
a and b ik thats the awser becuse imjust did it
Answer:
B frequencyExplanation:
if the frequency changes so does the energy and that doesn't happen to EM waves entering a medium by the conservation of energy
Correct me if im wrong but im 100% its B
A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?
Answer:
50 km/h
Explanation:
200 km = 4 hours
200/4=50
50km/h
The circular plates of a parallel-plate capacitor have a radius of 30 mm. A steady 0.43-mA current is charging the initially uncharged capacitor, and the surface charge on the plates is distributed uniformly. The flat circular surface between the capacitor plates is coaxial and parallel to the plates, and has a radius of 13 mm. Calculate the magnetic field at any point on the circumference of the circular region (in Tesla).
Solution :
The electric field between two plates is given by
[tex]$E = \frac{q}{\varepsilon_0 A}$[/tex]
where
[tex]$\varepsilon_0 = $[/tex] permitivity of free space
q = charge
A = surface area
It is given that :
the radius of the circular plates , r = 30 mm
the current, I = 0.43 mA
Therefore, Magnetic field can be found by
[tex]$B \times 2 \pi r = \mu_0 I_{(enclosed)}$[/tex]
[tex]$\Rightarrow B = \frac{\mu_0}{2 \pi r} \times (0.43 \ mA) \times \left(\frac{13 \ mm}{30 \ mm}\right)^2$[/tex]
[tex]$\Rightarrow B = \frac{2 \times 10^{-7}}{13 \times 10^{-3}} \times 0.43 \times 10^{-3} \times \left(\frac{13 }{30 }\right)^2$[/tex]
[tex]$\Rightarrow B = 1.2 \times 10^{-9} \ T$[/tex]
An inductor of 247 mH with a resistance of 37 Ω is connected to a power supply with a maximum voltage of 336 V and a frequency of 71 Hz. Find the current in the circuit. Answer in units of A. 022 (part 2 of 3) 10.0 points Find the phase angle between the current and applied voltage. Answer in units of ◦ . 023 (part 3 of 3) 10.0 points Find the power loss in the inductor. Answer in units of W.
Answer:
(i) The current in the circuit is 2.044 A
(ii) the phase angle is 71.441⁰
(iii) The power loss in the inductor is 154.58 W
Explanation:
Given;
inductance, L = 247 mH
resistance, R = 37 Ω
maximum voltage, V₀ = 336 V
frequency, f = 71 Hz
The rms voltage is given as;
[tex]V_{rms} = 0.7071V_o\\\\V_{rms} = 0.7071 \ \times \ 336\\\\V_{rms} = 237.586 \ V\\[/tex]
The inductive reactance is given as;
[tex]X_l = \omega \ L\\\\X_l = 2\pi f L\\\\X_l = 2\pi (71)(247 \times 10^{-3})\\\\X_l = 110.202 \ ohms[/tex]
The impedance of the A.C circuit is given as;
[tex]Z = \sqrt{X_l^2 + R^2} \\\\Z = \sqrt{(110.202)^2 + (37)^2}\\\\Z = 116.248 \ ohms[/tex]
(i) The current in the circuit is given as;
[tex]I_{rms} = \frac{V_{rms}}{Z}\\\\ I_{rms} =\frac{237.586}{116.248} \\\\I_{rms} =2.044 \ A[/tex]
(ii) the phase angle is given as;
[tex]tan \phi = \frac{X_l}{R}\\\\tan \phi =\frac{110.202}{37} \\\\ tan \phi =2.9784\\\\\phi = tan^{-1} (2.9784)\\\\\phi = 71.441 ^0 \\\\[/tex]
(iii) The power loss in the inductor is given as;
P = IVcosΦ
P = (2.044)(237.586)Cos(71.441⁰)
P = 154.58 W
What is the average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s
Answer:
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 [tex]\frac{m}{s}[/tex].
Explanation:
Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.
[tex]velocity=\frac{displacement}{time}[/tex]
Velocity considers the direction in which an object moves, so it is considered a vector magnitude.
In this case, the displacement is 192 m and the time period is 8 s. Replacing:
[tex]velocity=\frac{192 m}{8 s}[/tex]
Solving:
velocity= 24 [tex]\frac{m}{s}[/tex]
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 [tex]\frac{m}{s}[/tex].
a wandering dog walks 1 km due east, 1 km due south, then runs 2 km due west. the magnitude of the dogs displacement is closest to
a. 0 km
b. 1.4 km
c. 3.4 km
d. 4.0 km
Answer:
b) 1.4km
Explanation:
a cyclist accelerates at a rate of 7.0 m/s2. how long will it take the cyclist to go from a velocity of 4 m/s to a velocity of 18 m/s?
Answer:
2.57 seconds (rounded to 2.6 Seconds)
Step-by-step explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,
Where:
Vf is the final Velocity
Vi is the initial velocity
A is the acceleration
t is the time in seconds
Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).
Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Help me please..
Suppose a car is moving in a straight line and steadily increases its
speed. It goes from 0 miles/hour to 15 miles/hour the first second and 15
miles/hour to 30 miles/hour the next second. What is the acceleration?
A)10 miles/hour/second
B) 15 miles/hour/second
C) 20 miles/hour/second
D)30 miles/hour/second
A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4.0 m/s^2. Find the final velocity of the roller coaster ?
[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ (u) = 13 \ m/s }[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Distance \ (s) = 400 \ m }[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{ Acceleration = 4 \ m/s^2}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{The \:Final \:velocity \:of \:the\: body }[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\[/tex]
☯ Using 3rd equation of motion
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} +2as }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {13}^{2} + 2 \times 4 \times 400 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{{v}^{2} = 169 + 3200 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = 3369 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ v = \sqrt{3369} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \underline{\boxed{\sf{ v = 58.04 \: m/s }}}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\:Additional \:Information:-\:\:\:}}}} \\ \\ [/tex]
☢ Equations Of Motion
[tex]\\[/tex]
[tex]\boxed{
\begin{minipage}{3 cm}$\\
\sf{\:\:\star\:\:v = u +at} \\ \\
\sf{\:\:\star\:\:s = ut + \dfrac{1}{2}\:at^{2} }\\ \\
\sf{\:\:\star\:\:v^{2} = u^{2} + 2as}\\ \\
\sf{\:\:\star\:\:s = \dfrac{1}{2} (u + v)t}\\$
\end{minipage}
} [/tex]
[tex]\\[/tex]
[tex]\sf{Where,}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\textsf{s = Distance}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}[/tex]
A car accelerates from rest at a constant rate 5m/s^2. Which of the following statements is true
Answer:
jjhbkvjuhigjgyihbgtimnvyuoibc
suppose you drop an object and it strikes the ground. you can calculate the velocity of the object as it strikes the ground using the law of conservation of energy. in order to do this, you need to know the original height of the object. do you also need to know the mass of the object? why or why not?
a. you do not need to know the mass because you can compute it based on the provided information.
b. you do not need to know the mass because it cancels out.
c. you need to know the mass of the object in order to compute the kinetic and gravitational potential energies.
d. you need to know the mass of the object in order to compute the elastic potential energy.
Answer:
b)
Explanation:
Assuming no friction forces present, the total mechanical energy must be conserved, so at any moment, the sum of the gravitational potential energy and the kinetic energy must be the same.When the object is dropped, all the energy is gravitational, as follows:E = m*g*h (1)When the object strikes the ground, if we choose the ground as the zero reference level for the gravitational potential energy, all the energy is kinetic:E = 1/2*m*v² (2)Since E is constant, left sides in (1) and (2) are equal each other, so the right sides must be equal each other too.Since the mass is present in the right side of (1) and (2) it cancels out, so b) is the right answer.
Answer: B you do not need to know the mass because it cancels out
Explanation:
how large amount of energy is produced during the fission of uranium
Answer:
answer is a very large amount of energy is produced from a very small mass
Explanation:
nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)
Help me please,
A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?
A) v 0m/s, = 0m/s/s
B) v = 0m/s, a 10m/s/s
C) v = 10m/s, a 10m/s/s
D) v = 10m/s, a = 0m/s/s
E) None of the above
Option B
Explanation:
no distance was given only the acceleration due to the fact that it went up (10m/s/s)
s0 it is
0 m/s and 10m/s/s (option B)
A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?
p = 36 kgm/s
v = 4m/s
we know that,
p = mv
so,
[tex]m = \frac{p}{v} [/tex]
[tex]m = \frac{36}{4} [/tex]
[tex]m = 9kg[/tex]
A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to slow down to 12.6 m/s. How long was this force applies?
Answer:
t = 1.4[s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 50 [kg]
v = velocity [m/s]
F = force = 200[N]
t = time = [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})-F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 50 [kg]
v₁ = velocity of the object before the impulse = 18.2 [m/s]
v₂ = velocity of the object after the impulse = 12.6 [m/s]
[tex](50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s][/tex]
4. A little boy pushes a wagon with his dog in it. The mass of the dog and
wagon together is 70 kg. The wagon accelerates at 0.85 m/s². What force is
the boy pulling with? F=mxa
Answer:
59.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 70 × 0.85
We have the final answer as
59.5 NHope this helps you
If the acceleration of the negative charge is to the right. And the magnetic field is pointed downwards. What direction was the negative charge moving originally?
A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force
Answer:
F = 6[N].
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 10 [kg]
v = velocity [m/s]
F = force [N]
t = time = 5 [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 10 [kg]
v₁ = velocity of the object before the impulse = 1 [m/s]
v₂ = velocity of the object after the impulse = 4 [m/s]
[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]
