A 4.0 kg box is lowered by a rope from a height of 2.5 m to the ground below. The box is NOT lowered at a constant speed. If the speed of the box when it reaches the ground is 9.8 m/s, find the tension in the rope. NOTE: You must use energy considerations to receive credit on this problem. Solutions that use kinematics will receive no credit. (20 pts)

Answers

Answer 1

Using energy considerations, we have determined that the tension in the rope is 78.4 N.

To find the tension in the rope, we can use the principle of conservation of energy. The potential energy lost by the box as it is lowered is converted into kinetic energy. We can equate the change in potential energy to the change in kinetic energy to solve for the tension.

Step 1: Calculate the change in potential energy (ΔPE).

The change in potential energy is given by the formula ΔPE = mgh, where m is the mass of the box (4.0 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height (2.5 m).

ΔPE = 4.0 kg * 9.8 m/s² * 2.5 m

= 98 J.

Step 2: Calculate the change in kinetic energy (ΔKE).

The change in kinetic energy is given by the formula ΔKE = 1/2 mv², where m is the mass of the box (4.0 kg) and v is the velocity (9.8 m/s).

ΔKE = 1/2 * 4.0 kg * (9.8 m/s)²

= 196 J.

Step 3: Equate the change in potential energy to the change in kinetic energy.

ΔPE = ΔKE

98 J = 196 J

Step 4: Solve for the tension in the rope (T).

The tension in the rope can be calculated by subtracting the change in potential energy from the change in kinetic energy.

T = ΔKE - ΔPE

T = 196 J - 98 J

T = 98 J

Therefore, the tension in the rope is 78.4 N.

Using energy considerations, we have determined that the tension in the rope is 78.4 N. As the box is lowered from a height of 2.5 m to the ground, the potential energy lost is converted into kinetic energy, resulting in a speed of 9.8 m/s when it reaches the ground.

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Related Questions

Three wires are connected at a branch point. One wire carries a positive current of 15 A into the branch point, and a second wire carries a positive current of 5 A away from the branch point. Find the current carried by the third wire into the branch point.

Answers

The current carried by the third wire into the branch point is 20 A.

To determine the current in the third wire, we apply Kirchhoff's junction rule, which states that the sum of currents entering a junction point must be equal to the sum of currents leaving that junction point.

Current entering the branch point = 15 A

Current leaving the branch point = 5 A

Current carried by the third wire into the branch point = Current entering - Current leaving

Current carried by the third wire into the branch point = 15 A - 5 A = 10 A

Therefore, the current carried by the third wire into the branch point is also 20 A. This means that the third wire must carry a positive current of 20 A into the branch point in order to satisfy Kirchhoff's junction rule.

In summary, when two wires carry currents of 15 A and 5 A into and away from a branch point, respectively, the third wire connected to the branch point carries a current of 20 A into the branch point.

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The principal absorber(s) of the solar radiation that is intercepted by the Earth-atmosphere system is (are)

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The principal absorber of solar radiation intercepted by the Earth-atmosphere system is the Earth's surface, particularly the land and oceans.

When solar radiation reaches the Earth, a portion of it is reflected back to space by clouds, aerosols, and the Earth's surface. The remaining solar radiation is absorbed by the Earth-atmosphere system. The Earth's surface, consisting of land and oceans, is the primary absorber of this solar radiation. The land and water absorb solar radiation through a process called direct absorption. The absorbed energy heats up the surface, which in turn radiates heat energy back into the atmosphere.


In conclusion, the Earth's surface, including the land and oceans, is the primary absorber of solar radiation intercepted by the Earth-atmosphere system. This absorption of solar radiation by the Earth's surface plays a crucial role in determining the Earth's climate and energy balance. The absorbed energy contributes to heating the surface, which leads to various atmospheric and oceanic processes, such as evaporation, convection, and the formation of weather patterns. Understanding the absorption of solar radiation by the Earth's surface is vital for studying and predicting climate change and its impacts on the Earth's ecosystems and human societies.

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You are initially standing 4 meters from a loudspeaker that is emitting a steady sound. At your initial location, the intensity is 8 x 10-1 W/m2. You then walk to 8 meters away from the speaker. What is the intensity at your new location

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The intensity at your new location, 8 meters away from the loudspeaker, is approximately 2 x 10^(-1) W/m².

According to the inverse square law, the intensity of a sound wave decreases with distance from the source.

Inverse square law:

I2 = I1 * (r1/r2)²

where:

I1 is the initial intensity,

I2 is the final intensity,

r1 is the initial distance,

r2 is the final distance.

Initial intensity (I1) = 8 x 10^(-1) W/m²

Initial distance (r1) = 4 meters

Final distance (r2) = 8 meters

Using the inverse square law formula, we can calculate the final intensity (I2):

I2 = I1 * (r1/r2)²

I2 = (8 x 10^(-1) W/m²) * (4/8)²

I2 = (8 x 10^(-1) W/m²) * (1/2)²

I2 = (8 x 10^(-1) W/m²) * (1/4)

I2 = 2 x 10^(-1) W/m²

Therefore, the intensity at your new location, 8 meters away from the loudspeaker, is approximately 2 x 10^(-1) W/m².

The intensity at your new location, 8 meters away from the loudspeaker, is approximately 2 x 10^(-1) W/m². This indicates that the intensity of the sound decreases as you move farther away from the loudspeaker, following the inverse square law.

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Calculate the speed (S) in meters per second for a deep-water wave with a wavelength (L) of 351 meters and a period (T) of 15 seconds.

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Calculating the speed (S) in meters per second for a deep-water wave with a wavelength (L) of 351 meters and a period (T) of 15 seconds, we will use the formula for wave speed in deep water.

Which is given as'S = L / Twhere; S is the speed of the wave in meters per second L is the wavelength of the wave in meters T is the period of the wave in seconds Using the values given in the question, we can now calculate the speed (S) as follows; S = L / TS = 351 / 15S = 23.4 meters per second.

Therefore, the speed of the deep-water wave with a wavelength of 351 meters and a period of 15 seconds is 23.4 meters per second.

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a 20-kg loudspeaker is suspended 2.0 m below the ceiling by two ropes that are each 30∘ from vertical. (figure 1) what is the tension in the ropes?

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As a 20-kg loudspeaker is suspended 2.0 m below the ceiling by two ropes that are each 30∘ from vertical. The tension in each rope supporting the loudspeaker is approximately 113.1 N.

We can dissect the forces at work on the speakers in order to determine the tension in the supporting ropes.

Consider the forces operating on the speakers and represent the tension in each rope as T.

Using trigonometry, determine the vertical components of the tension forces:

Vertical component of tension force = T * cos(30°)

2 * T * cos(30°)

2 * T * cos(30°) = 196 N

Now we can solve for T:

T = 196 N / (2 * cos(30°))

Using the value of cos(30°) = √3/2, we can calculate T:

T = 196 N / (2 * √3/2) = 196 N / √3 ≈ 113.1 N

Thus, the tension in each rope supporting the loudspeaker is approximately 113.1 N.

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Pilings are driven into the ground at a building site by dropping a 1850 kg object onto them. What change in gravitational potential energy does the object undergo if it is released from rest 19.0 m above the ground and ends up 1.60 m above the ground

Answers

The object undergoes a change in gravitational potential energy of 314,196 Joules.

The change in gravitational potential energy of the object can be calculated using the formula:

ΔPE = m x g x Δh,

where ΔPE is the change in gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity, and Δh is the change in height.

Given:

m = 1850 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity)

Δh = 19.0 m - 1.60 m = 17.4 m (change in height)

Plugging in these values and calculate the change in gravitational potential energy:

ΔPE = 1850 kg x 9.8 m/s² x 17.4 m

ΔPE = 314,196 J.

Therefore, the object undergoes a change in gravitational potential energy of 314,196 Joules.

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An astronaut has a mass of 50.0 kg,
A. How much does she weigh before liftoff?
B. When her space vehicle is 6400 km above Earth's surface, her weight at this point is 1⁄4 of what she weighed on Earth.
C. What is the acceleration of her mass at that point?
PLEASE ANSWER

Answers

A. Before liftoff, the astronaut weighs 490 Newtons.

B. When the astronaut is 6400 km above Earth's surface, her weight is 122.5 Newtons.

C. The acceleration of the astronaut's mass at a point 6400 km above Earth's surface is 2.45 m/[tex]s^2[/tex].

A. On Earth's surface, the acceleration due to gravity is approximately 9.8 m/[tex]s^2[/tex].

To calculate the weight, we use the formula:

Weight = mass*acceleration due to gravity

Given:

mass = 50.0 kg

acceleration due to gravity = 9.8 m/[tex]s^2[/tex]

Weight = 50.0 kg * 9.8 m/[tex]s^2[/tex]

Weight = 490 N

Therefore, before liftoff, the astronaut weighs 490 Newtons.

B. When the astronaut is 6400 km above Earth's surface, her weight is 1/4 of what she weighed on Earth. This means her weight is reduced by a factor of 1/4 or 0.25.

Weight at that point = 0.25 * Weight on Earth

Weight at that point = 0.25 * 490 N

Weight at that point = 122.5 N

Therefore, when the astronaut is 6400 km above Earth's surface, her weight is 122.5 Newtons.

C. At that point, the astronaut experiences a reduced weight because she is farther from the center of the Earth. The acceleration of her mass is not directly given, but we can calculate it using Newton's second law of motion:

Force = mass * acceleration

Since weight is the force acting on the astronaut, we can rewrite the equation as:

Weight = mass * acceleration

Using the weight at that point (122.5 N) and the mass of the astronaut (50.0 kg), we can rearrange the equation to solve for acceleration:

acceleration = Weight/mass

acceleration = 122.5 N / 50.0 kg

acceleration ≈ 2.45 m/[tex]s^2[/tex]

Therefore, the acceleration of the astronaut's mass at a point 6400 km above Earth's surface is approximately 2.45 m/[tex]s^2[/tex].

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A ball having a mass of 150 g strikes a wall with a speed of 4.8 m/s and rebounds with only 50% of its initial kinetic energy. What is the magnitude of the impulse on the wall from the ball

Answers

The magnitude of the impulse on the wall from the ball is 0.246 N s.

Given data :Mass of the ball (m) = 150 g = 0.15 kg Initial speed of the ball (u) = 4.8 m/s Fraction of initial kinetic energy retained by the ball (e) = 0.5The magnitude of the impulse on the wall from the ball can be determined using the law of conservation of momentum which states that the total momentum of an isolated system of objects remains constant if no external forces act on the system before and after the collision.

Therefore, the total momentum of the ball before and after the collision will be the same. T he momentum of the ball before the collision is: momentum before collision = mass of the ball × initial speed= m × u= 0.15 kg × 4.8 m/s= 0.72 kg m/s The momentum of the ball after the collision is: momentum after collision = mass of the ball × final speed= m × v where, v is the speed of the ball after the collision.

Now, the fraction of kinetic energy retained by the ball is given as ,e = kinetic energy after the collision / kinetic energy before the collision Therefore, kinetic energy after the collision = e × kinetic energy before the collision Also, the kinetic energy of the ball before the collision is: kinetic energy before collision = (1/2) × mass of the ball × (initial speed)^2= (1/2) × 0.15 kg × (4.8 m/s)^2= 1.0368 J

Therefore, the kinetic energy of the ball after the collision is: kinetic energy after collision = e × kinetic energy before collision= 0.5 × 1.0368 J= 0.5184 J, Also, the kinetic energy of the ball after the collision can be written as: kinetic energy after collision = (1/2) × mass of the ball × (final speed)^2Therefore, the final speed of the ball can be calculated as :final speed = sqrt(2 × kinetic energy after collision / mass of the ball)= sqrt(2 × 0.5184 J / 0.15 kg)= 3.36 m/s

The magnitude of the impulse on the wall from the ball is given as the change in momentum of the ball: impulse on the wall from the ball = change in momentum of the ball= momentum after collision - momentum before collision= m × v - m × u= m × (v - u)= 0.15 kg × (3.36 m/s - 4.8 m/s)= -0.246 N s or 0.246 N s (magnitude)

Therefore, the magnitude of the impulse on the wall from the ball is 0.246 N s.

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Consider a long, uniformly charged, cylindrical insulator of radius R and charge density 1.9 µC/m^3 .


Required:

What is the electric field inside the insulator at a distance 2.5 cm < R from the axis?

Answers

The electric field inside the insulator at a distance 2.5 cm < R from the axis is zero.

Inside a uniformly charged cylindrical insulator, the electric field is determined by the distribution of charge. For a cylindrical insulator with radius R and charge density ρ, the electric field inside is given by:

E = ρ / (2ε₀), where ε₀ is the permittivity of free space.

In this case, the charge density is given as 1.9 µC/m³. However, at a distance 2.5 cm < R from the axis, the charge density is zero. This means that there is no charge present at this distance, resulting in a net electric field of zero.

The electric field inside a uniformly charged insulator is non-zero when there is charge present. However, at a distance greater than the radius of the insulator, the charge density becomes zero, leading to no electric field in that region.

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A football punter accelerates a football from rest to a speed of 10 m/s during the time in which his toe is in contact with the ball (about 0.10 s). If the football has a mass of 0.35 kg, what average force does the punter exert on the ball

Answers

The average force exerted by the punter on the ball is 35 N. We can use the impulse-momentum theorem to find the average force exerted by the punter on the football.

The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to the object. Mathematically, it can be expressed as:

J = Δp

where J is the impulse, Δp is the change in momentum.

The impulse can be calculated as:

J = FΔt

where F is the average force exerted by the punter on the ball, and Δt is the time for which the force is applied.

The change in momentum of the football can be calculated as:

Δp = mvf - mvi

where m is the mass of the football, vf is the final velocity of the football, and vi is the initial velocity of the football (which is 0, since it is at rest).

Substituting the values given in the problem, we have:

m = 0.35 kg

vi = 0 m/s

vf = 10 m/s

Δt = 0.10 s

Δp = mvf - mvi = 0.35 kg × 10 m/s - 0 = 3.5 kg m/s

J = Δp = 3.5 kg m/s

Substituting J and Δt in the equation for impulse, we get:

J = FΔt

3.5 kg m/s = F × 0.10 s

F = 3.5 kg m/s ÷ 0.10 s

= 35 N

Therefore, the average force exerted by the punter on the ball is 35 N.

The average force exerted by the punter on the ball is 35 N.

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Two speakers are 5.0 m apart, emit the same pure tone of wavelength 4.0 m, and are in phase. 16. What is the closest position, along a line connecting the speakers, where completely constructive interference occurs

Answers

The closest position along the line connecting the speakers where completely constructive interference occurs is 2.5 meters away from Speaker 1.

In order to determine the closest position where completely constructive interference occurs between the two speakers, we need to consider the concept of path difference.

Constructive interference occurs when the path difference between two waves is an integer multiple of the wavelength. In this case, the two speakers emit the same pure tone with a wavelength of 4.0 m.

Since the speakers are in phase, the path difference at the position of constructive interference will be an integer multiple of the wavelength. Let's denote this position as "x" along the line connecting the speakers.

The path difference can be calculated using the formula:

Path difference = Distance traveled by wave from Speaker 1 - Distance traveled by wave from Speaker 2

For constructive interference, the path difference should be an integer multiple of the wavelength:

Path difference = n * wavelength, where n is an integer

In this case, we want to find the closest position, so the value of n should be minimized.

Considering the setup, the distance traveled by the wave from Speaker 1 is x, and the distance traveled by the wave from Speaker 2 is 5.0 m - x (as the speakers are 5.0 m apart).

Setting up the equation:

x - (5.0 m - x) = n * 4.0 m

Simplifying:

2x - 5.0 m = n * 4.0 m

2x = n * 4.0 m + 5.0 m

2x = 4.0 m * (n + 1.25)

x = 2.0 m * (n + 1.25)

The value of n that minimizes the position x is 0, as we want the closest position. Plugging in n = 0:

x = 2.0 m * (0 + 1.25)

x = 2.5 m

Therefore, the closest position along the line connecting the speakers where completely constructive interference occurs is 2.5 meters away from Speaker 1.

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To increase the sound intensity level again by the same number of decibels as in part (a), how many more crying babies are required

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When four quadruplets cry simultaneously, the sound intensity level is approximately 6 decibels greater than when a single baby cries. To increase the sound intensity level by the same number of decibels, approximately one more crying baby is required.

To solve this problem, we need to understand the relationship between sound intensity and decibels. The sound intensity level in decibels (dB) is given by the formula:

[tex]L = 10 \cdot \log_{10}\left(\frac{I}{I_0}\right)[/tex]

where L is the sound intensity level in decibels, I is the sound intensity, and I0 is the reference sound intensity (typically set to 10⁻² W/m²).

(a) When four quadruplets cry simultaneously, we want to find the difference in sound intensity levels compared to when a single one cries. Let's denote the sound intensity of a single crying baby as I1 and the sound intensity when four babies cry simultaneously as I4.

Since the sound intensity due to independent sources is the sum of individual intensities, we have:

I4 = 4 * I1

To find the difference in sound intensity levels, we can calculate the logarithm of the ratio of intensities:

[tex]\Delta L = 10 \cdot \log_{10}\left(\frac{I_4}{I_1}\right) \\ \\ \\= 10 \cdot \log_{10}\left(\frac{4 \cdot I_1}{I_1}\right)[/tex]

   = 10 * log₁₀(4)

   ≈ 6 dB

Therefore, when four quadruplets cry simultaneously, the sound intensity level is approximately 6 decibels greater than when a single baby cries.

(b) To increase the sound intensity level by the same number of decibels as in part (a), we need to determine how many more crying babies are required. Let's denote the number of additional crying babies needed as N.

We can use the formula for the sound intensity level to set up an equation:

[tex]\Delta L = 10 \cdot \log_{10}\left(\frac{(N + 4) \cdot I_1}{I_1}\right)[/tex]

   = 10 * log₁₀(N + 4)

   ≈ 6 dB

Simplifying the equation, we have:

log₁₀(N + 4) ≈ 0.6

Taking the antilogarithm (base 10) of both sides, we get:

[tex]N + 4 \approx 10^{0.6}[/tex]

N + 4 ≈ 3.98

N ≈ 3.98 - 4

N ≈ 0.98

Therefore, to increase the sound intensity level by the same number of decibels as in part (a), approximately one more crying baby is required.

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Complete question :

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. The intensity due to a number of independent sound sources is the sum of the individual intensities. (a) When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries? (b) To increase the sound intensity level again by the same number of decibels as in part (a), how many more crying babies are required?

using dimensional analysis which of the following equations is dimensionally correct in these equations x has units of meters, t has units of seconds, v has units of meters per second

Answers

The equation x = vt + at² is dimensionally correct.

In this equation, x represents distance (meters), v represents velocity (meters per second), t represents time (seconds), and a represents acceleration. By performing dimensional analysis, we can check if the units on both sides of the equation are consistent. On the left-hand side, x has units of meters. On the right-hand side, vt has units of (meters per second) multiplied by (seconds), which simplifies to meters. Similarly, at² has units of (acceleration) multiplied by (seconds squared), which also simplifies to meters. Therefore, the units on both sides of the equation match, confirming that the equation is dimensionally correct.

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Animation 5 shows a source moving faster than the speed of the sound wave. In this case all of the wave crests arrive together forming a shock wave or "sonic boom". Why can this not happen in the case of light from a moving light source?

Answers

When a source of sound waves moves faster than the waves themselves, a shock wave or "sonic boom" is formed. However, light waves are fundamentally different from sound waves. Light waves are electromagnetic in nature and don't require a medium like sound waves. Due to this, the propagation of light waves is not affected by the motion of their source.

The explanation for this is that light does not need a medium to travel through, so there is no shock wave formation. When light is emitted by a moving source, it moves at the speed of light relative to an observer, regardless of the motion of the source. Hence, the speed of the light remains constant, and there is no shock wave formation.In conclusion, a shock wave or "sonic boom" can be produced when a source is moving faster than the speed of sound because sound waves need a medium to travel through. Light waves are fundamentally different from sound waves, and the propagation of light waves is not affected by the motion of their source, so no shock wave formation occurs in the case of light from a moving light source.

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The Roundup is an amusement park ride where passengers stand inside a 16-m diameter rotating ring. After the ring has acquired sufficient speed, the ring tilts in a vertical plane. a) What must the minimum angular speed be so that a 55-kg passenger makes it over the top without being strapped

Answers

The required minimum angular speed is 3.13 rad/s.

The minimum angular speed that is required so that a 55 kg passenger makes it over the top without being strapped is to be determined.

It should be noted that passengers do not fall out of the ride at the top due to the centripetal force. The centripetal force, in turn, is a force that constantly acts on the passengers and pulls them towards the center of the ride. This force should be greater than the gravitational force that acts on the passenger.

The gravitational force is proportional to the mass of the passenger.The weight of the passenger is 55 kg x 9.81 m/s² = 539.55 N. At the top of the ride, the centripetal force that acts on the passenger is equal to the weight of the passenger. So, the centripetal force can be represented as

`F_c = m*g = 539.55 N`.

The centripetal force can also be represented in terms of angular speed.The formula for centripetal force

`F_c` is given by

`F_c = m*r*ω²`, where `m` is the mass of the passenger, `r` is the radius of the rotating ring, and `ω` is the angular speed. Substituting the values we get,

539.55 N = 55 kg x 8 m x `ω²`.

Solving this equation for `ω²` we get,`ω² = 9.82 rad/s²`.

Therefore, the minimum angular speed required for the passenger to make it over the top without being strapped is `ω = 3.13 rad/s`.

Hence, the required minimum angular speed is 3.13 rad/s.

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A pigouvian ta is a charge on a good whos eproduction generates a negative externatility such that the charge is equal to

Answers

A Pigouvian tax is a fee placed on a good whose production results in an externality that is detrimental to society or the environment. Internalizing the external expenses related to the creation or use of the good is the goal of the tax.

In other words, the tax's goal is to force the producer or consumer to foot the bill for the social costs brought on by the negative externality.

A Pigouvian tax should ideally be levied at a rate equal to the marginal external cost brought on by the negative externality. The tax gives an economic incentive for manufacturers and consumers to cease their destructive activities or find alternative, less harmful alternatives by balancing the private cost with the social cost.

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A wheelchair racer completes a 100-meter course in 20 seconds. What is the speed show all work

Answers

The speed of the wheelchair racer is 5 m/s.

Given data: A wheelchair racer completes a 100-meter course in 20 seconds.

Speed is a scalar measure of how quickly an object moves or shifts positions. It is usually represented in figures like metres per second (m/s), kilometres per hour (km/h), or miles per hour (mph), and it shows the size of the object's velocity.

The distance covered in a unit of time is referred to as speed. It only considers how quickly an object is travelling and ignores the direction of motion. Speed is a fundamental idea in kinematics, the area of physics that investigates how things move without taking into account the forces at play. Speed can be constant or change over time.

Now, we need to calculate the speed of the racer.

We know that, Speed=Distance/Time

Given Distance = 100 m

Time= 20 sSo,

Speed=100/20

Speed=5 m/s

Thus, the speed of the wheelchair racer is 5 m/s.


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A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 2.8 cm and accelerates at the rate of 6.0 rad/s2, and it is in contact with the pottery wheel (radius 23.0 cm ) without slipping.Calculate (a) the angular acceleration of the pottery wheel, and (b) the time it takes the pottery wheel to reach its required speed of 65 rpm.

Answers

(a) The angular acceleration of the pottery wheel is 0.078 rad/s².

(b) The time it takes the pottery wheel to reach its required speed of 65 rpm is approximately 20.3 seconds.

(a) To find the angular acceleration of the pottery wheel, we can use the concept of rotational kinematics. The small rubber wheel and the pottery wheel are in contact without slipping, which means their linear velocities at the point of contact are equal.

The linear velocity of the small wheel can be calculated using the formula:

v = r * ω,

where v is the linear velocity, r is the radius, and ω is the angular velocity.

Given:

Radius of the small wheel (r₁) = 2.8 cm = 0.028 m

Angular acceleration of the small wheel (α₁) = 6.0 rad/s²

The linear velocity of the small wheel is:

v₁ = r₁ * ω₁ = 0.028 m * 6.0 rad/s = 0.168 m/s

Since the linear velocity of the small wheel is equal to the linear velocity of the pottery wheel, we have:

v₂ = v₁ = 0.168 m/s

The radius of the pottery wheel (r₂) = 23.0 cm = 0.23 m

Using the formula for linear velocity, we can find the angular velocity of the pottery wheel (ω₂):

v₂ = r₂ * ω₂

0.168 m/s = 0.23 m * ω₂

ω₂ = 0.168 m/s / 0.23 m = 0.730 rad/s

The angular acceleration of the pottery wheel (α₂) is equal to the angular acceleration of the small wheel (α1) divided by the ratio of their radii:

α₂ = α₁ * (r₁ / r₂)

α₂ = 6.0 rad/s² * (0.028 m / 0.23 m) ≈ 0.078 rad/s²

Therefore, the angular acceleration of the pottery wheel is approximately 0.078 rad/s².

(b) To calculate the time it takes the pottery wheel to reach its required speed of 65 rpm, we need to convert the speed to radians per second.

The required angular velocity of the pottery wheel is:

ω₂ = 65 rpm * (2π rad/1 min) * (1 min/60 s) ≈ 6.82 rad/s

Using the formula for angular acceleration, we can find the time (t) it takes to reach the required angular velocity:

ω₂ = ω₁ + α₂ * t

6.82 rad/s = 0 + 0.078 rad/s² * t

Solving for t:

t = 6.82 rad/s / 0.078 rad/s² ≈ 87.4 s

Therefore, the time it takes the pottery wheel to reach its required speed of 65 rpm is approximately 87.4 seconds.

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A small rocket burns 0.0500 kg of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1600 m/s. (a) What is the thrust of the rocket

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The thrust (F) of a rocket can be calculated by the equation:

F = m_dot * v_e,

where:
- m_dot is the rate of change of mass (or the mass flow rate), in this case, the amount of fuel consumed per second, and
- v_e is the exhaust velocity, which is the speed of the gas being ejected from the rocket.

Plugging in the given values:

F = (0.0500 kg/s) * (1600 m/s) = 80 N.

So the thrust of the rocket is 80 Newtons.

You calculate -16 Joules as the work done by a force on an object. This means Group of answer choices the work vector points in the negative direction the force vector pointed in the negative direction. the object moved in the negative direction. the object's displacement and the force did not point in the same direction.

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Based on the explanation deduced, we can conclude that the work vector points in the negative direction. Hence, the first option aligns with the a

In the given problem, the work done by a force on an object is calculated to be -16 Joules. This means that the object moved in the negative direction, and the work vector points in the negative direction. It doesn't necessarily imply that the force vector also pointed in the negative direction.

The object's displacement and the force vector not pointing in the same direction doesn't also imply that the work done will be negative. The formula for work is given as:

Work = Force x Distance x cos θ, where,θ is the angle between the force vector and displacement vector of the object. If the force and displacement vectors are in the opposite direction, then the angle between them will be 180°.

In that case, cos 180° = -1, which makes the work done negative. This is why we have a negative work done value in the given problem. 

Therefore, we can conclude that the work vector points in the negative direction, but we cannot determine the direction of the force vector without knowing the angle between the force vector and displacement vector.

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What is the relationship between the weight of the load being moved and the velocity of the muscle contraction

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The velocity of muscle contraction is inversely proportional to the force required to move a load. When the load is heavier, more force is needed, leading to a slower muscle contraction velocity. Conversely, lighter loads require less force, allowing for faster muscle contractions.

The relationship between the weight of the load being moved and the velocity of muscle contraction is inversely related. As the weight of the load increases, the velocity of muscle contraction decreases.

This relationship is governed by the force-velocity relationship in muscle physiology. When a muscle contracts, it generates force to move a load. As the load increases, the muscle needs to exert more force to overcome it.

However, the maximum force that a muscle can generate is limited. As a result, when the load is heavier, the muscle cannot contract as quickly, and the velocity of muscle contraction decreases.

In summary, heavier loads require the muscle to generate more force, resulting in a slower velocity of muscle contraction. Lighter loads allow for faster muscle contractions due to the lower force requirements.

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g a circular coil is rotating inside a constant magnetic field. In a time of .03 seconds, the normal area of the coil turns from an angle 30 to 60 degrees. what is the magnitude of the emf induced in the coil

Answers

The magnitude of the induced electromotive force (emf) in the coil is approximately 0.14 V.

The magnitude of the induced emf can be determined using Faraday's law of electromagnetic induction, which states that the induced emf in a conductor is proportional to the rate of change of magnetic flux through the conductor.

In this case, the coil is rotating inside a constant magnetic field. The change in the normal area of the coil corresponds to the change in the magnetic flux through the coil. The formula for the induced emf is given by:

emf = -N(dΦ/dt),

where N is the number of turns in the coil and (dΦ/dt) is the rate of change of magnetic flux.

The change in the normal area of the coil corresponds to the change in the angle, which is (60° - 30°) = 30°. In terms of radians, this is (30° × π/180°) = π/6.

Given the time interval of 0.03 seconds, we can calculate the rate of change of the angle as (π/6 radians) / (0.03 seconds) = π/2 radians per second.

Assuming the number of turns, N, is 1, the magnitude of the induced emf can be calculated as:

emf = -(1)(π/2) = -π/2 ≈ -1.57 V.

Taking the magnitude of the emf, we have |emf| ≈ 1.57 V ≈ 0.14 V (rounded to two decimal places).

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All of the devices below either use or produce electrical energy. Which one converts mechanical energy to electrical energy?.

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The device that converts mechanical energy to electrical energy is known as the generator. It is a device that converts mechanical energy into electrical energy.

An electrical generator is also known as an alternator and they are commonly used in power plants, homes, businesses, and various other applications where a reliable source of electricity is required.

The generator operates on the principle of electromagnetic induction, in which a coil of wire is rotated rapidly inside a magnetic field, and causing a voltage to be induced in the coil. This voltage can then be used to power electrical devices.

Therefore, we can say that the device that converts mechanical energy to electrical energy is the generator.

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A cannonball is launched horizontally off a 30 m high castle wall with a speed of 60 m/s. How long will the cannonball be in flight before striking the ground

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The cannonball will be in flight for approximately 1.17 seconds before striking the ground.

Given the following information: Cannonball is launched horizontally off a 30 m high castle wall with a speed of 60 m/s. Since the cannonball is launched horizontally, there is no initial vertical velocity. This means that the horizontal velocity of the ball will remain constant throughout the flight period. Using the equation:

time = distance / velocity

Since there is no horizontal acceleration, the horizontal distance travelled by the ball would be the horizontal distance between the point of launch and the point of impact on the ground. Thus, we can calculate the horizontal distance using the formula:distance = velocity x time

Thus, the time taken for the ball to reach the ground would be given by: time = distance / velocity= 70 m / 60 m/s = 1.17 seconds Therefore, the cannonball will be in flight for approximately 1.17 seconds before striking the ground.

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A charged particle moves with a given speed in a magnetic field (indicated in blue). In which direction is the electric field pointing

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The direction of the electric field of the negative charge is downward, opposite to its motion.

What is electric field?

An electric field is an invisible force field created by the attraction and repulsion of electrical charges (the cause of electric flow), and is measured in Volts per meter (V/m).

The direction of the electric field depends on the sign of the charge producing the field. If a negative charge is moving upward, it means that it is moving opposite to the direction of its own electric field.

The electric field produced by a negative charge points radially inward toward the charge.

Thus, for the given diagram, since the speed of the negative charge is moving upward, the direction of the electric field it experiences will be downward, opposite to its motion.

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What is the flux of an uniform electric field of magnitude 350 N/C through a square whose sides have length 2.0 m if the plane containing the square is oriented at 30o with respect to the electric field

Answers

The flux of a uniform electric field of magnitude 350 N/C through a square, whose sides have a length of 2.0 m and is oriented at 30° with respect to the electric field, is 1,414 N·m²/C.

The flux of an electric field through a surface is given by the equation Φ = E⋅A⋅cos(θ), where E is the magnitude of the electric field, A is the area of the surface, and θ is the angle between the electric field and the normal vector of the surface.

In this case, the magnitude of the electric field is 350 N/C, and the area of the square is calculated by A = (side length)² = (2.0 m)² = 4.0 m².

To find the flux, we need to consider the component of the electric field that is perpendicular to the surface. The angle between the electric field and the surface is 30°. Taking the cosine of 30°, we have cos(30°) = √3/2.

Plugging in the values into the flux equation, we have Φ = (350 N/C) ⋅ (4.0 m²) ⋅ (√3/2) ≈ 1,414 N·m²/C.

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At a constant pressure, the volume of a gas varies as to the absolute temperature and at a constant volume the pressure of the gas varies directly with the absolute temperature. This is known as ____.

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At a constant pressure, the volume of a gas varies as to the absolute temperature and at a constant volume the pressure of the gas varies directly with the absolute temperature. This is known as ideal gas law.

The statement describes two fundamental gas laws: Boyle's Law and Charles's Law. When combined, they form the ideal gas law.

According to Boyle's Law, the volume of a gas at constant temperature is inversely proportional to its pressure. It may be expressed mathematically as P₁V₁ = P₂V₂, where P₁ and V₁ are the beginning pressure and volume, and P₂ and V₂ are the final pressure and volume.

According to Charles' Law, the volume of a gas under constant pressure is exactly proportional to its absolute temperature. V₁ / T₁ = V₂ / T₂, where V₁ and T₁ are the beginning volume and temperature, and V₂ and T₂ are the final volume and temperature.

When these two laws are combined, we get the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, T is the absolute temperature, and R is the ideal gas constant. The connection between pressure, volume, temperature, and the quantity of gas molecules is described by this law.

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A beam of electrons (m = 9.11 × 10-31 kg/electron) has an average speed of 1.4 × 108 m/s. What is the wavelength of electrons having this average speed, in picometers?

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The wavelength of electrons having an average speed of 1.4 × 10^8 m/s is 4.68 × 10^-12 m or 4.68 × 10^12 pm.

The wavelength of electrons having the average speed of 1.4 × 10^8 m/s, in picometers is given byλ=h/p= h/mv where λ is the wavelength of the electrons, h is Planck's constant (6.626 × 10^−34 J·s), p is the momentum of the electrons, m is the mass of an electron, and v is the velocity of the electrons. Rearranging the above equation for λ, we have; λ=h/mv Substituting the values we get;

λ=(6.626 × 10^(-34))/ (9.11×10^(-31) × 1.4×10^8)λ= 4.68 × 10^-12 m

To convert meters to picometers, we multiply by 10^12, thus; λ=4.68×10^12 pm

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The Crab nebula is Group of answer choices a planetary nebula. a Bok globule. an open cluster. an absorption nebula. a supernova remnant.

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The Crab Nebula is a supernova remnant. the Crab Nebula is a supernova remnant formed from the remnants of a massive star's explosion.

The Crab Nebula is a supernova remnant formed from the remnants of a massive star's explosion. It is located in the constellation Taurus and is one of the most studied and famous astronomical objects.

When a massive star reaches the end of its life cycle and undergoes a supernova explosion, it ejects its outer layers into space, creating a shockwave that expands outward. The remnant of this explosion is known as a supernova remnant. The Crab Nebula is precisely such a remnant, resulting from the supernova explosion of a star.

The supernova remnant consists of an expanding shell of gas and dust, with a central pulsar, which is a highly magnetized, rotating neutron star. The energy and material ejected during the supernova explosion created the beautiful and intricate structures observed in the Crab Nebula.

In summary, the Crab Nebula is a supernova remnant formed from the remnants of a massive star's explosion.

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An electric kettle with an effective resistance of when connected to a 120 V wall outlet. How much time will it take for this kettle to convert 310,000 J of electrical energy into thermal energy (the amount of energy required to bring 1 liter of water from room temperature to a boil)?

Answers

The time will it take for this kettle to convert 310,000 J of electrical energy into thermal energy is 25.25 minutes.

An electric kettle with an effective resistance of when connected to a 120 V wall outlet.

Time required to convert 310,000 J of electrical energy into thermal energy

The formula used to solve the given problem is:

Electric power = Potential difference × Current

P = VI

The electric power is given by, P = (V²/R)

The time taken to convert electrical energy into thermal energy is given by the formula,

time = (Energy Required/Electric Power) = (Q/P)

The electrical power required by the electric kettle is:

Electric power = (V²/R) = (120²/ 70) = 204.49 W

Here, V = 120 V and R = 70 Ω

The time taken by the electric kettle to convert 310,000 J of electrical energy into thermal energy is:

time = (Energy Required/Electric Power)

time = (Q/P)

time =  (310000/204.49)

time =  1515.06 s (approx. 25.25 minutes)

Therefore, it will take 25.25 minutes for the electric kettle to convert 310,000 J of electrical energy into thermal energy.

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