If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.
Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.
Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.
Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.
Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.
It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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PLEASE HELP ON QUESTION ASAP !
hi ! I really need help understanding paragraph and I've also added a question about paragraph by me down below . Would like explanation in simple words.
If answers correct I'll rate you five stars a thanks and maybe even brainliest
Paragraph I needed help understanding:
If two or more cells are connected together side by side, the voltage across them is sum of the voltage of each cell. This is because both cells are pushing same way.
My Question about paragraph:
If the sum lets say was 4.5v would every individual cell be worth 4.5 as it says in question ' voltage across them is the sum of voltage of each cell ' or are they each a different value? And how would we be able to find value?.
The voltage across a group of cells connected in series is the sum of the voltages of each individual cell.
In the given paragraph, it states that when two or more cells are connected together side by side, the voltage across them is the sum of the voltage of each cell. This means that if you have two cells connected together, the total voltage across them would be the sum of the voltage of each individual cell.
Let's consider an example where you have two cells connected in series and the total voltage across them is 4.5 volts. In this case, it means that the voltage of each individual cell is not necessarily 4.5 volts. The total voltage is the combination of the voltages of both cells.
To find the voltage of each individual cell, you need to know the total voltage and the number of cells connected. In this example, if you have two cells and the total voltage is 4.5 volts, it would mean that each cell has a voltage of 2.25 volts. This is because the total voltage is divided equally among the cells when they are connected in series.
To summarize, the voltage across a group of cells connected in series is the sum of the voltages of each individual cell. The individual voltage of each cell can be found by dividing the total voltage by the number of cells connected.
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A 900 pF capacitor is charged by 100 V battery. (a) How much electrostatic energy is stored by the capacitor? The capacitor is disconnected from the battery and connected to another 900 pF capacitor. How much is the electrostatic energy stored in the system?
Answer:
The electrostatic energy stored in the system after connecting the two capacitors is 0.09 Joules
Explanation:
The formula to calculate the electrostatic energy stored in a capacitor is given by:
E = (1/2) * C * V^2
where:
E is the electrostatic energy,
C is the capacitance, and
V is the voltage across the capacitor.
(a) For the first scenario, where a 900 pF capacitor is charged by a 100 V battery:
C = 900 pF = 900 * 10^(-12) F
V = 100 V
Using the formula, we can calculate the electrostatic energy stored in the capacitor:
E = (1/2) * C * V^2
E = (1/2) * (900 * 10^(-12)) * (100^2)
E = 0.045 J
Therefore, the electrostatic energy stored by the capacitor in the first scenario is 0.045 Joules.
(b) In the second scenario, when the first capacitor is disconnected from the battery and connected to another 900 pF capacitor, the total capacitance in the system becomes:
C_total = C1 + C2
C_total = 900 pF + 900 pF
C_total = 1800 pF = 1800 * 10^(-12) F
The voltage across the capacitors remains the same, as they are connected in parallel.
Using the formula for electrostatic energy, we can calculate the new energy stored in the system:
E_total = (1/2) * C_total * V^2
E_total = (1/2) * (1800 * 10^(-12)) * (100^2)
E_total = 0.09 J
Therefore, the electrostatic energy stored in the system after connecting the two capacitors is 0.09 Joules.
The saturated vapour pressure at 20°C and 8°C is 17.54mmHg and 8.05mmHg respectively. Find,
(i) Relative humidity at the room temperature.
(ii) How much mass of water should evapourate such that it saturate at 20°C (1mmHg = 133.3Pa)
1.) The relative humidity is 100 percent. 2.)To saturate the air at 20°C, 0.018g of water should evaporate.
(i) To calculate the relative humidity at room temperature, compare the amount of water vapour in the air to the maximum amount of water vapour that the air can hold at that temperature.
The saturated vapour pressure at that temperature determines the maximum amount. The relative humidity is stated as a percentage and can be calculated using the formula:
(Actual vapour pressure / Saturated vapour pressure) times 100% = Relative humidity
The saturation vapour pressure at room temperature (20°C) is 17.54mmHg. The relative humidity is 100% if the actual vapour pressure in the air equals the saturation vapour pressure.This signifies that the air has held the most water vapour it can at that temperature.
(ii) Using the ideal gas law, we can calculate the amount of water that should evaporate to saturate the air at 20°C. PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin, according to the ideal gas equation.
This equation can be rearranged to calculate the amount of moles of water:
n = (PV) / (RT)
We know that the required pressure is 17.54mmHg, which is equal to 2.338 kPa. We also know that the temperature is 20° C, which is 293.15 K.The volume is not specified, but we can assume it is constant and hence ignore it. The gas constant is 8.31 joules per mol-K.
n = ((2.338 kPa) / (8.31 J/mol-K * 293.15K))
To calculate the mass of water, multiply the number of moles by the molar mass of water, which is about 18.015 g/mol.
0.01796 g = 0.000997 mol * 18.015 g/mol mass of water
To saturate the air at 20°C, around 0.018g of water should evaporate.
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(a) Define the following terms(1) internal energy (ii) an isovolumic process (b) state first law of thermodynamics (c
The definitions of Internal energy, Isovolumic process and the law of thermodynamics are:
(a) (i) Internal energy: Internal energy refers to the total energy stored within a system, including the kinetic and potential energies of its particles. It is a state function and depends only on the current state of the system, such as its temperature, pressure, and volume.
(ii) Isovolumic process: An isovolumic or isochoric process is a thermodynamic process where the volume of the system remains constant. During an isovolumic process, no work is done by or on the system through expansion or compression.
(b) The first law of thermodynamics, also known as the law of conservation of energy, states that energy cannot be created or destroyed; it can only be transferred or converted from one form to another. The first law of thermodynamics is expressed mathematically as ΔU = Q - W, where ΔU is the change in internal energy of the system, Q is the heat transferred into or out of the system, and W is the work done on or by the system.
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A 40kg child is on a swing. At the bottom of a swing, the child attains a speed
of 4.0 meters per second. If the chain holding the swing is 4.0m long, what is
the Force of Contact by the chain on the child at the bottom of the swing
(assume the chain has no mass)?
The force of contact by the chain on the child at the bottom of the swing is 160 N. This is the minimum force required to keep the child moving in a circular path with a constant speed of 4.0 m/s. Any lesser force and the child will move away from the circular path and slow down.
At the bottom of the swing, the child has a velocity of 4.0 m/s and is being pulled downwards by the force of gravity. The tension in the chain holding the swing provides the necessary centripetal force to keep the child moving in a circular path. The centripetal force required is given by the formula F = (mv^2)/r, where F is the force, m is the mass of the child, v is the velocity, and r is the radius of the circular path. In this case, the radius is equal to the length of the chain, which is 4.0 m.
Substituting the given values, we get:
F = (40 kg x (4.0 m/s)^2)/4.0 m
F = 160 N
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When 119 J of work is done in pushing a box horizontally 17 m, how much force is applied?
The surface of the exit road is horizontal, not banked. (See figure.) If the static
friction between the tires and the surface of the road is us = 0.688 and the
maximum speed with which the car can exit the highway safely without sliding is
25.2 m/s, what is the radius of curvature of a highway exit, r?
The radius of curvature of the highway exit is approximately 220 km.
To find the radius of curvature of the highway exit, we can use the centripetal force equation:
F = mv^2 / r
where F is the maximum static friction force, m is the mass of the car, v is the maximum safe speed, and r is the radius of curvature.
We can solve for r by rearranging the equation:
r = mv^2 / F
Substituting the given values, we have:
r = (1000 kg)(25.2 m/s)^2 / (0.688)
r = 2.20 x 10^5 m
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calculate the electric potential energy in a capacitor that stores 9.40 x 10 to the negative 10 C of charge at 50.0 V
The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
The electric potential energy stored in a capacitor is given by the formula:
U = (1/2) * C * V^2
where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.
In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.
To find the capacitance value, we can use the formula:
C = Q / V
where Q is the charge stored in the capacitor and V is the voltage across the capacitor.
Substituting the given values, we get:
C = 9.40 x 10^-10 / 50.0
= 1.88 x 10^-11 F
Now we can use the formula for electric potential energy to find the energy stored in the capacitor:
U = (1/2) * 1.88 x 10^-11 * (50.0)^2
= 4.70 x 10^-8 J
Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
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A small bar magnet is placed in the magnetic field of a larger bar magnet, at
the position marked Yin the diagram below. Assuming the small bar magnet
is free to rotate, how would it be positioned?
X
The orientation of the magnet that is free to rotate is the wil be oriented as shown as the magnet in the option D.
The correct option is therefore, option D.
What is a bar magnet?A magnet produces magnetic field and it also attracts magnetic materials.
The directions of the lines of flux from a magnetic field is from the north to the south, such that the lines of flux emerges from the north of the magnet and enters into the magnet from the south pole of the magnet.
The point Y on the diagram shows the lines of flux entering the magnet, which indicates that the point Y is located in the south pole of the magnet, and therefore, will attract the north pole of another magnet, aligning it with the north and south pole of the large magnet in the figure.
The magnet free to rotate will therefore, be oriented with the north pole on the right (closer due to the attraction to the point Y) and the south pole on the left, which corresponds to the magnet D.
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Draw conclusions: As a wave moves into a medium with a higher index of refraction, it slows down. What causes the wave to slow: a change in the wave's wavelength or a change in its frequency?
The wave slows down as its wavelength gets smaller because its speed also slows down. During this process, the wave's frequency doesn't change.
Wavelength is a fundamental property of a wave, and is defined as the distance between two adjacent points in a wave that are in phase, or that have the same degree of oscillation.
In other words, wavelength is the distance between two identical points in a wave pattern, such as two crests or two troughs, and is typically represented by the symbol lambda (λ). It is measured in units of length, such as meters (m), centimeters (cm), or nanometers (nm), depending on the type of wave.
Wavelength is an important characteristic of waves, as it determines many of their properties, such as their speed, frequency, and energy. For example, shorter wavelengths correspond to higher frequencies and higher energy waves, while longer wavelengths correspond to lower frequencies and lower energy waves.
When a wave moves from one medium to another with a higher index of refraction, the speed of the wave decreases due to the change in the wave's wavelength. This is because the speed of a wave is directly proportional to its wavelength and inversely proportional to its frequency.
Therefore, as the wavelength decreases, the speed of the wave decreases as well, causing it to slow down. The frequency of the wave remains constant during this process.
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. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth
A. The weight of the mass on the earth is 117.6 N
A. The weight of the mass on the moon is 19.56 N
How do i determine the weight of the mass?Weight is defined as follow:
Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Now we shall determine the weight. Details below:
A. Weight on earth
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Weight on earth (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 9.8
Weight on earth = 117.6 N
B. Weight on moon
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Acceleration due to gravity on moon (g) = (1/6) × 9.8 = 1.63 m/s² Weight on moon (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 1.63
Weight on moon = 19.56 N
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Complete question:
The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon
Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:
The density of water at STP, which is [tex]997 kg/m^3[/tex], we can see that Saturn is less dense than water.
To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is [tex]997 kg/m^3[/tex].
Saturn's density can be computed using the following formula:
density equals mass divided by volume
Saturn's mass and volume may be computed given its mass and radius.
The volume of Saturn can be determined using the sphere volume formula:
volume =[tex](4/3) \pi (r^3)[/tex]
where r is Saturn's radius.
Filling in the blanks:
volume = [tex](4/3) \pi (5.6 \times 107) m^3[/tex]
8.27 x 1023 [tex]m^3[/tex]volume
Saturn's mass is given as [tex]5.68 \times 10^{26} kg.[/tex]
We can now compute Saturn's density:
density equals mass divided by volume
density= [tex](5.68 x 10^{26 }kg[/tex]) /[tex](8.27 \times 10^{23 }[/tex]m³) a density of[tex]687 kg/m^3[/tex]
This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.
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