A car is moving along a straight horizontal road. The car has 1.6MJ of kinetic energy. The car accelerates for 20s until the kinetic energy of the car increases to 2.5MJ. What is the minimum average power developed by the car engine for this acceleration?

Answers

Answer 1

Answer:

P = 45 [kW]

Explanation:

We must find the difference in kinetic energy during the 20 seconds.

[tex]D_{kE}=2.5-1.6\\D_{kE}=0.9[MJ][/tex]

Power is defined as the relationship between energy over time.

[tex]P=D_{kE}/t\\P=0.9/20\\P=0.045[MW] or 45 [kW][/tex]


Related Questions

Instantaneous speed is measured _____.

Answers

Answer:

Instantaneous speed is measured in metres per second.

Answer:

I believe this speed is measured in knots...like a jet, or lightspeed/Lightyear...like in space

If constants aren't given in an experiment, what can be constant in the experiment?

Answers

Answer:

Anything in an experiment that remains unchanged.

Explanation:

An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.

Pick the correct word: inertia, whiplash, resistance, friction , force to fill up the blank in below question.
When hit from behind in a car crash, a passenger can suffer a neck injury from the forward and backward motion called _______.

Answers

Answer:

It is whiplash I hope this is right

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s, what is he acceleration down the hill? What is the force needed for that kind of acceleration

Answers

Given :

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s.

To Find :

The acceleration down the hill.

The force needed for that kind of acceleration.

Solution :

By equation of motion :

[tex]v^2 -u^2 = 2as\\\\a = \dfrac{v^2-u^2}{2s}\\\\a = \dfrac{15^2 -0^2}{2\times 100}\\\\a = 1.125\ m/s^2[/tex]

Force required is, F = ma

F = 80×1.125 N

F = 90 N

Hence, this is the required solution.

Help!!

Which is the most common source of ocean oil pollution?
A.oil spills
B.street runoff
C.offshore drilling
D.ship repairs

Answers

Answer:

Oil Spills.

Explanation:

Answer:

C

Explanation:

What do the most abundant elements in Earth’s atmosphere have in common?

Answers

Answer: Since the oceans are mostly water, the elements hydrogen and oxygen are the most common. Sodium and chlorine are found in the salt in ocean water. Earth's atmosphere is made up of a combination of gases, including nitrogen, oxygen, and carbon dioxide. Nitrogen and oxygen are the most common elements in the atmosphere..

An object has an acceleration of 6.0 m/s/s. If the net force acting upon this object were tripled , then its new acceleration would be _____ m/s/s.

Answers

Answer:

18m/s/s

Explanation:

6 times 3= 18

1. Which of the following is true about sound waves?
They move faster than light.
They make wind.
They vibrate the air.
They move slower in water than in air.

Answers

Answer:

They vibrate the air.

Explanation:

The sound waves in air are longitudinal while the light waves are transverse Sound wave is longitudinal because the medium particles move parallel to the direction of wave propagation, whereas a light wave is transverse because the medium particles move perpendicular to direction of wave propagation. Hence, option C is correct.

A gun recoils back when the bullet is fired ,why? ​

Answers

A gun recoils back when the bullet is fired due to conservation of momentum. Conservation of momentum suggest that - the net change of momentum in a closed system must be zero.

Therefore in equation form -

[tex]mv - mu = 0[/tex]

Question:

Why does a gun recoil when a bullet is fired?

Explanation:

When a bullet is fired, the gun exerts a force on the bullet through the trigger (this is action) in a particular direction. According to Newton's Third Law, we know to every action there is an equal and opposite reaction; action and reaction act on different bodies. So, the bullet will also exert an equal and opposite reaction on the gun in the opposite direction. That is why a gun recoils when a bullet is fired from it.

Hope it helps.ray4918 here to help

What is the velocity of a wave with a frequency of 930 Hz and a wavelength of 0.50 m?

Answers

Answer:

Hi, thank you for posting your question here at Brainly.

To find the velocity of light or any electromagnetic wave, we use the equation: v = wavelength * frequency. Substituting,

v = 0.5 m * 930 1/s

v = 465 m/s

Brainiest please

Explanation:

A star's brightness as if it were a standard distance from Earth (10 parsecs) is known as what? radiation apparent brightness lighting absolute brightness​

Answers

Answer:

In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).

Explanation:

A student presses her palm by her thumb with a force of 75 N . What would be the pressure under her thumb having contact area is 1.5 cm2

Answers

Step 1: Identify the knowns.

[tex] F=75 N [/tex]

[tex] A= 1.5 cm^2[/tex]

Step 2: Determine.

[tex] P= \frac {F} {A}\ [/tex]

[tex] P = \frac {75 N} {1.5 cm^2}\ = 50 Pa [/tex]

Answer:

50 Pascal

Explanation:

Pressure= Force/Area

P=75/1.5

=50 Pascal

MARK ME AS BRAINIEST IF MY ANSWER HELPED YOU :):)

A ray of light incident in water strikes the surface separating water from air making an angle of 10 ° with the normal to the surface. (refractive index of water = 1.3) a) What is the angle of refraction? b) What should be the angle of incidence if we want an angle of refraction not greater than 45 ° ? c) What is the critical angle?

Answers

Answer:

a

 [tex]\theta _2 = 13^o[/tex]

b

 [tex]\theta _1 =32.94^o[/tex]

c

 [tex]\theta_c = 53.05^o[/tex]    

Explanation:

From the question we are told that

    The angle of incidence is  [tex]\theta_1 = 10^o[/tex]

    The refractive index of water is  [tex]n_1 = 1.3[/tex]

  Generally Snell's law is mathematically represented as

          [tex]n_1 sin(\theta_1) = n_2 sin(\theta_ 2)[/tex]

Here [tex]n_2[/tex] is the refractive index of air with value  [tex]n_2 = 1[/tex]

         [tex]\theta_2[/tex]  is the angle of refraction

So  

        [tex]\theta _2 = sin^{-1}[\frac{n_1 * sin(\theta _1)}{n_2} ][/tex]

=>     [tex]\theta _2 = sin^{-1}[\frac{1.3 * sin(10)}{1} ][/tex]

=>     [tex]\theta _2 = 13^o[/tex]

Given that the angle should not be greater than [tex]\theta _2 =45^o[/tex]  then the angle of incidence will be

       [tex]\theta _1 = sin^{-1}[\frac{n_2 * sin(\theta _2)}{n_1} ][/tex]

=>     [tex]\theta _1 = sin^{-1}[\frac{1 * sin(45)}{1.3} ][/tex]

=>     [tex]\theta _1 =32.94^o[/tex]

Generally for critical angle is mathematically represented as

        [tex]\theta_c = sin^{-1}[\frac{n_2}{n_1} ][/tex]

=>     [tex]\theta_c = sin^{-1}[\frac{1}{1.3} ][/tex]  

=>     [tex]\theta_c = 53.05^o[/tex]            

An object has three forces acting upon it, the first force is 58.2 N to the right and the second force is 14.0 N to the left. What is the magnitude of the third force, such that the object travels at a constant velocity? Answer in units of N and be sure to include all necessary work, as well as a free body diagram.

Help Please!

Answers

Answer:

44.2 N towards left

or

-44.2 N towards right

Explanation:

pls refer attachment for detailed solution

On an air track, a 4-kg cart moving at 3 m/s collides with a 2-kg cart that is
initially at rest. If the two carts stick together, what will be their velocity
after the collision? Show all calculations, including any equation(s) used,
and include correct measurement units. *
Your answer

Answers

Answer:

v₃ = 2 [m/s]

Explanation:

To solve such problems we must use the principle of conservation of momentum. That is, the linear momentum is conserved before and after the collision.

P = m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

The momentum is conserved before and after the collision, in this way we can obtain the following equation.

[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]

where:

m₁ = mass of the cart moving = 4 [kg]

v₁ =  velocity of the cart moving before the collision = 3 [m/s]

m₂ = mass of the cart initially at rest = 2 [kg]

v₂ = velocity of the cart at rest = 0

v₃ = velocity of the two carts combined (carts stick together) after the collision [m/s]

[tex](4*3)+(2*0)=(4+2)*v_{3}\\v_{3}=12/6\\v_{3}=2[m/s][/tex]

Which of the following would have the least amount of inertia? Assume all the bags are the same size.

bag of rocks
bag of feathers
bag of bricks
bag of sand

Answers

bag of bricks would be the correct answer

If a net force of 375N is acting on a crate and there is 65N of friction
created, what is the magnitude net force the crate experiences?
375N
65N
310N
440N

Answers

Answer:

310 N

Explanation:

The net force, I assume, is an applied force that is causing motion of the crate. However, frictional force opposes this motion, so the frictional force is in the opposite direction. Overall, we can create a net force equation of this crate as

Fnet= Force applied + Force of friction

Thus,

Fnet= 375N -65N (because friction is in the opposite direction)

Then solve to get that the net force while the crate is in motion is 310N.


I have like 3 min !!!

Answers

Answer:

to talk??? i will talk with you

A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog

Answers

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = [tex]\frac{1}{2}[/tex] m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  [tex]\frac{1}{2}[/tex]  x 10 x 5  = 25J

HELP ASAPP!! WILL TRY TO GIVE BRAINLIEST

What is produced in the nucleolus?

Answers

Answer: Image result for What is produced in the nucleolus?

The nucleolus is a region found within the cell nucleus that is concerned with producing and assembling the cell's ribosomes. Following assembly, ribosomes are transported to the cell cytoplasm where they serve as the sites for protein synthesis.

Explanation: hope this helps! PLs mark me as brainliest! Thank you and have a wonderful day/night!

WHICH ONE IS IT????

RINGS

POINT

GRAPH

READS

TALKS

Answers

Answer:  c or b

Explanation:

graph or points would be the answer

b. The coefficient of friction between the tires and the road is 0.850 and the mass of the car is
1.35x10' kg. Draw the free body diagram of this situation and determine the applied force
that caused the acceleration from part a. (2 law: Fnet-ma)
Given:
u
בנו
Samt
g=9.8 m/s^2
am
(from part a)
Unknown:
Fapp = ?
Equation:
Fnet=ma
Fapp- umg=ma
Solution:

Answers

Answer:

156.26N

Explanation:

The data needed are incomplete. Let the acceleration of the body be 3.5m/s²

Other given parameters

Mass = 1.35×10^1 = 13.5kg

coefficient of friction between the tires and the road = 0.850

Acceleration due to gravity = 9.8m/s²

According to Newton's second law:

Fnet = ma

Fnet = Fapp - Ff

Fapp is the applied force

Ff is the frictional force = umg

The equation becomes:

Fapp - Ff = ma

Fapp-umg = ma

Fapp - 0.85(13.5)(9.8) = 13.5(3.5)

Fapp - 109.0125 = 47.25

Fapp = 47.25+109.0125

Fapp = 156.2625N

Hence the applied force that caused the acceleration is 156.26N

Note that the acceleration of the car was assumed. Any value of acceleration can be used for the calculation.

Uncle Harry weighs 750 N. What is his mass in kg?

Answers

Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

Answer:

76.479 Kilograms Force (kgf)

Explanation:

An astronaut and his space suit have a combined mass of 157 kg. The
astronaut is using a 5 kg tqol kit to repair a solar panel on the International
Space Station. When the têther connecting the astronaut to the space
station becomes unattached, the astronaut, still holding the tool kit, starts
to float away at 0.2 m/s. Calculate the velocity with which the astronaut
must throw the tool kit in order to float back toward the space station at
0.1 m/s. Show your calculations and include units in your answer.
*

Answers

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

[tex]-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})[/tex]

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

[tex]-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s][/tex]

The velocity with which the astronaut must throw the tool kit is 9.62 m/s.

The given parameters:

Mass of the astronaut and space suit, m₁ = 157 kgMass of the tool kit, m₂ = 5 kgVelocity of the astronaut and tool kit, v = 0.2 m/sVelocity of the astronaut and space station, u₁ = -0.1 m/s

Apply the principle of conservation of linear momentum to determine the velocity of the tool kit;

[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\-0.1(157) \ + 5u_2 = 0.2(157 + 5) \\\\-15.7 + 5u_2 = 32.4\\\\5u_2 = 32.4 + 15.7\\\\5u_2 = 48.1\\\\u_2 = \frac{48.1}{5} \\\\u_2 = 9.62 \ m/s[/tex]

Thus, the velocity with which the astronaut must throw the tool kit is 9.62 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

Two equal forces act at the same time on the same motionless object, but in opposite directions. Which statement best describes the object’s resulting motion?


A. The object will accelerate.

B. The object will move at a constant speed.

C. The object will remain motionless.

D. The object will change direction.

Answers

I think the answer is C

Which of the following BEST describes Jupiter's seasons?
O A.
There are no significant seasonal changes.
B.
The seasons are much like Earth's.
OC.
The seasons are much shorter than Earth's.
OD. The seasons are much longer than Earth's.


Answers

Answer:

Jupiter does not have changing seasons like the Earth, but instead is believed to have a constantly stormy atmosphere. This is partly due to its tilt, which is only 3 degrees. The planet has a very turbulent atmosphere and is believed to have a lot of long-term storms.

So the answer is  A : There are no significant seasonal changes.

Explanation:

1. The coin remains at rest in the figure shown. This is due to
(a) inertia of rest
(b) two forces act on the coin which balance each other
(c) no unbalanced force acts on it
(d) all of these​

Answers

D would be correct.

Have a merry Christmas!
D I hope it helps have a good day

Jimmy runs a chain of souvenir shops in South Florida. He imports T-shirts and other apparel from Guatemala to sell in his stores. One day, student protesters damage several of his stores, demanding that he pay his workers in Guatemala a fair wage. Jimmy estimates the damage at $5,500. He sues the protestors for the damage they cause. Where is the original jurisdiction of this case?

Answers

Answer  he would go to court veto bill

Explanation

that how it works

what other factor affected the gravitational force between the two objects in this simulation?

Answers

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases

Density of water is 1000kg/m3. Find out the amount of mass of 5m3 water​

Answers

Answer:

5000 m³

Explanation:

density = mass / volume

mass = density × volume

mass = 1000 × 5

mass = 5000 ( kg )

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