Answer: 9.53 *2= 19.06
Explanation:
The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.
in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.
But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.
CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.
Methane (CH4) and the perchlorate ion (ClO4â) are both described as tetrahedral. Methane and the perchlorate ion are both described as tetrahedral. What does this indicate about their bond angles?
a. Bond angles in the methane molecule are greater than those in the perchlorate ion.
b. Bond angles in the perchlorate ion are greater than those in the methane molecule.
c. Bond angles in the methane molecule and in the perchlorate ion are approximately equal
Answer:
c
Explanation:
The correct answer would be that the bond angles in the methane molecule and in the perchlorate ion are approximately equal.
A tetrahedral shape or geometry means both molecules are sp3 hybridized with the hydrogen atoms and the oxygen ions surrounding the central carbon and chlorine atoms respectively being as far away from one another as possible. This results in an approximate angle of 109.5 degrees in both molecules.
The correct option is c.
an auto of an element has 17 protons in its nucleus.a) write the electronic configuration of the atom.b)to what period and group does the element belong
Answer:
i hope it will help you
Explanation:
electronic configuration 1s²,2s,²2p^6,3s²3p^6,4s^1
as it has one electron in its valence shell so it is the member of group 1A(ALKALI METALS) and the number of shells is 4 so it is in period 4
What is the law of conservation and what happens when two substances at different temperatures come into contact.
Answer:
- Both energy and matter cannot be neither created nor destroyed.
- An equilibrium temperature will be reached.
Explanation:
Hello,
In this case, the law of conservation is applied to both matter and energy, and it states that both energy and matter cannot be neither created nor destroyed. Specifically, in chemical reactions, it states that in closed systems, the mass of the reactants equals the mass of the products even when the number of moles change. Moreover, for energy, if two substances at different temperatures come into contact, the hot one will cool down and the cold one will heat up until an equilibrium temperature so the energy lost by the hot one is gained by the cold one, which accounts for the transformation of energy.
Best regards.
1. Write the molecular balanced equation for the dissolution of copper. 2. Write the complete ionic balanced equation for the dissolution of copper. 3. Write the net ionic balanced equation for the dissolution of copper. 4. What type of reaction is this
Answer:
Cu + HNO3 -----> Cu (NO3) 2 + NO2 + H2O
Explanation:
This equation is the equation for dissolving copper in nitric acid, this reaction is a REDOX reaction, that is, an oxide-reduction reaction.
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H2S(g) 2.10 g were obtained. What is the percent yield of the reaction?
Answer:
[tex]Y=58.15\%[/tex]
Explanation:
Hello,
For the given chemical reaction:
[tex]Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)[/tex]
We first must identify the limiting reactant by computing the reacting moles of Al2S3:
[tex]n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3[/tex]
Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:
[tex]n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3[/tex]
Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:
[tex]m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3[/tex]
Finally, we compute the percent yield with the obtained 2.10 g:
[tex]Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%[/tex]
Best regards.
What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium when 18.8 g of Cu(NO3)2 is added to 1.0 L of a 0.800 M solution of aqueous ammonia? Assume that there is no volume change upon the addition of the solid, and that the reaction goes to completion and forms Cu(NH3)42+.
Answer:
Explanation:
Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺ + 2 NO₃⁻
187.5 gm 4M 1 M
187.5 gm reacts with 4 M ammonia
18.8 g reacts with .4 M ammonia
ammonia remaining left after reaction
= .8 M - .4 M = .4 M .
187.5 gm reacts with 4 M ammonia to form 1 M Cu(NH₃)₄²⁺
18.8 g reacts with .4 M ammonia to form 0.1 M Cu(NH₃)₄²⁺
At equilibrium , the concentration of Cu²⁺ will be zero .
concentration of ammonia will be .4 M
concentration of Cu(NH₃)₄²⁺ formed will be 0.1 M
408 J of energy is transferred to a system consisting of 2.0 moles of an ideal gas. If the volume of this gas stays at a constant 4.4 L, calculate the change in internal energy of the gas.
Answer: The change in internal energy of the gas is +408 J
Explanation:
According to first law of thermodynamics:
[tex]\Delta E=q+w[/tex]
[tex]\Delta E[/tex] =Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done on the system= [tex]-P\Delta V[/tex]
As volume is constant , [tex]\Delta V[/tex] = 0 and w = 0.
q = +408J {Heat absorbed by the system is positive}
[tex]\Delta E=+408J+(0J)=+408J[/tex]
Thus the change in internal energy of the gas is +408 J
A student was given a sample containing a mixture of stereoisomers of 3-bromo-4-fluorohexane that was contaminated and was asked to identify all of the possible stereoisomers of 3-bromo-4-fluorohexane that could be present so they could isolate the contaminant.
Draw the four possible stereoisomers of 3-bromo-4-fluorohexane.
Answer:
Explanation:
From the given information;
The objective is to draw the four possible stereoisomers of 3-bromo-4-fluorohexane.
Stereoisomerism is the difference of the spatial arrangement of atoms in a molecule or a compound with the same molecular formula.
For 3-bromo-4-fluorohexane, We have the stereoisomers as follows:
(3S, 4S)-3-bromo-4-fluorohexane
(3S,4R)-3-bromo-4-fluorohexane
(3R, 4R)-3-bromo-4-fluorohexane
(3R, 4S)-3-bromo-4-fluorohexane
The above four possible stereoisomers are drawn and can be seen in the file attached below in a respective order.
Which of the following elements has the highest ionization energy?
A) Ba
B) Al
C) Ne
D) Cl
E) Ca
Answer:
C
It is Neon
:DDDDDDDDDDDDDDDD
Explanation:
MY BRAIN :D
A 13.0-L helium tank is pressurized to 26.0 atm. When connected to this tank, a balloon will inflate because the pressure inside the tank is greater than the atmospheric pressure pushing on the outside of the balloon. Assuming the balloon could expand indefinitely and never burst, the pressure would eventually equalize causing the balloon to stop inflating. What would the volume of the balloon be when this happens? Assume atmospheric pressure is 1.00 atm. Also assume ideal behavior and constant temperature. i got 338L for he whole thing but that is the volume of the entire sample of helium. But you need to consider that 13.0 liters of that is still in the 13.0-L tank. A helium tank is able to inflate balloons if the inside pressure is greater than the atmospheric pressure. can you explain how to do this
Answer:
The volume of the ballon is 325L.
Explanation:
Boyle's law express that the pressure of a gas is inversely proportional to its volume. That means if the pressure increases, the volume decreases. The formula is:
P₁V₁ = P₂V₂
Where P represents pressure and V volume of 1, initial state and 2, final state of the gas.
In the problem, the volume of the tank is 13.0L and the final pressure of the ballon is 1atm -The atmospheric pressure-. As 1atm of gas is in the ballon, the pressure of the tank is 26.0atm - 1.0atm = 25.0atm.
Replacing in Boyle's law expression:
25.0atm*13.0L = 1atmV₂
325L = V₂
The volume of the ballon is 325L.
Calculate the energy (in J/atom) for vacancy formation in silver, given that the equilibrium number of vacancies at 800 C is 3.6 x 1017/cm3. The atomic weight and density for silver are 107.9 g/mol and 9.5 g/cm3, respectively
Answer:
the energy vacancies for formation in silver is [tex]\mathbf{Q_v = 3.069*10^{-4} \ J/atom}[/tex]
Explanation:
Given that:
the equilibrium number of vacancies at 800 °C
i.e T = 800°C is 3.6 x 10¹⁷ cm3
Atomic weight of sliver = 107.9 g/mol
Density of silver = 9.5 g/cm³
Let's first determine the number of atoms in silver
Let silver be represented by N
SO;
[tex]N = \dfrac{N_A* \rho _{Ag}}{A_{Ag}}[/tex]
where ;
[tex]N_A =[/tex] avogadro's number = [tex]6.023*10^{23} \ atoms/mol[/tex]
[tex]\rho _{Ag}[/tex] = Density of silver = 9.5 g/cm³
[tex]A_{Ag}[/tex] = Atomic weight of sliver = 107.9 g/mol
[tex]N = \dfrac{(6.023*10^{23} \ atoms/mol)*( 9.5 \ g/cm^3)}{(107.9 \ g/mol)}[/tex]
N = 5.30 × 10²⁸ atoms/m³
However;
The equation for equilibrium number of vacancies can be represented by the equation:
[tex]N_v = N \ e^{^{-\dfrac{Q_v}{KT}}[/tex]
From above; Considering the natural logarithm on both sides; we have:
[tex]In \ N_v =In N - \dfrac{Q_v}{KT}[/tex]
Making [tex]Q_v[/tex] the subject of the formula; we have:
[tex]{Q_v = - {KT} In( \dfrac{ \ N_v }{ N})[/tex]
where;
K = Boltzmann constant = 8.62 × 10⁻⁵ eV/atom .K
Temperature T = 800 °C = (800+ 273) K = 1073 K
[tex]Q _v =-( 8.62*10^{-5} \ eV/atom.K * 1073 \ K) \ In( \dfrac{3.6*10^{17}}{5.3 0*10^{28}})[/tex]
[tex]\mathbf{Q_v = 2.38 \ eV/atom}[/tex]
Where;
1 eV = 1.602176565 × 10⁻¹⁹ J
Then
[tex]Q_v = (2.38 \ * 1.602176565 * 10^{-19} ) J/atom }[/tex]
[tex]\mathbf{Q_v = 3.069*10^{-4} \ J/atom}[/tex]
Thus, the energy vacancies for formation in silver is [tex]\mathbf{Q_v = 3.069*10^{-4} \ J/atom}[/tex]
Perform the conversions between energy units.
861 kJ=
J
3495 kcal=
kJ
7.84×106
Answer:
861 kJ = 861000 J,
3495 kcal = 14623.08 kJ
Explanation:
As I mentioned before, the last bit " 7.84 × 106 " just threw me off track, so I am simply going to assume that that does not appear in your question.
_______________________________________________________
Now we have 861 kilojoules, and have to convert it into joules for this first bit. Kilo being equal to 1000, to convert to joules you would have to multiply 861 by 1000, = 861000 Joules.
This second bit here asks us to convert 3495 kilocalorie to kilojoules. The difference between the two is that one is about 4.18 times greater than the other, so 3495 kilocalorie = 3495 * 4.18 = 14623.08 kilojoules.
Hope that helps!
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the rate of the hydrolysis reaction by a factor of 1 million, how much lower does the activation barrier have to be when sucrose is in the active site of the enzyme
Answer:
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Explanation:
From the given information:
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.
In this same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;
Rate factor in the absence of catalyst:
[tex]k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}[/tex]
Rate factor in the presence of catalyst:
[tex]k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}[/tex]
Assuming the catalyzed reaction and the uncatalyzed reaction are taking place at the same temperature :
Then;
the ratio of the rate factors can be expressed as:
[tex]\dfrac{k_2}{k_1}={ \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}[/tex]
[tex]\dfrac{k_2}{k_1}={ \dfrac {e^{[ Ea_1 - Ea_2 ] }}{RT} }}[/tex]
Thus;
[tex]Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}[/tex]
Let say the assumed temperature = 25° C
= (25+ 273)K
= 298 K
Then ;
[tex]Ea_1-Ea_2 = 8.314 \ J/mol/K * 298 \ K * In (10^6)[/tex]
[tex]Ea_1-Ea_2 = 34228.92 \ J/mol[/tex]
[tex]\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}[/tex]
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Suppose you were told that the above reaction was a substitution reaction but you were not told the mechanism. Evaluate the following categories to determine the reaction mechanism and then draw the structure of the major organic product.Type of alkyl halide: _________ (methyl, primary, primary benzyl, primary allyl, secondary, secondary benzyl, secondary allyl, tertiary, tertiary benzyl, tertiary allyl.)Type of nucleophile: _________ (good, moderate, poor.)Solvent: _________ (protic, aprotic.)Is the product racemic? _____ (yes, no.)
Answer:
The alkyl halide is secondary
The nucleophile is a poor nucleophile
The solvent is a protic solvent
The product is racemic
Explanation:
The reaction is shown in the image attached.
Alkyl halides undergo nucleophilic substitution by two mechanisms; SN1 and SN2. The particular mechanism that applies depends on;
I) structure of the alkyl halide
ii) nature of the nucleophile
iii) nature of the solvent
Looking at the reaction under review, we can see from the structure that the alkyl halide is a secondary alkyl halide. A secondary alkyl halide may undergo substitution via SN1 or SN2 mechanism depending on the conditions of the reaction.
If the nucleophile is poor, and the solvent is protic, SN1 mechanism is favoured over SN2 mechanism. Since CH3CH2OH is a poor nucleophile and ethanol is a protic solvent, we expect the reaction to proceed via SN1 mechanism leading to the formation of a racemic product.
The organic product is also shown in the second image attached.
Enter an abbreviated electron configuration for magnesium: Express your answer in complete form, in order of increasing energy. For example, [He]2s22p2 would be entered as [He]2s^22p^2.
Answer:
[Ne]3s²
Explanation:
Mg
1s2 2s2 2p6 3s2 or [Ne]3s²
Abbreviated electronic configuration of magnesium is [Ne]3 s² and in complete form it is 1 s² 2 s² 2 p⁶ 3 s².
What is electronic configuration?Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.
Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.
Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.
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Boron trifluoride gas is collected at in an evacuated flask with a measured volume of . When all the gas has been collected, the pressure in the flask is measured to be . Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to significant digits.
Answer:
0.683 mol
46.3 g
Explanation:
There is some info missing. I think this is the original question.
Boron trifluoride gas is collected at 21.0 °C in an evacuated flask with a measured volume of 50.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.330 atm. Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to 3 significant digits.
Step 1: Convert the temperature to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 21.0°C + 273.15
K = 294.2 K
Step 2: Calculate the moles of boron trifluoride gas
We will use the ideal gas equation.
[tex]P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{0.330atm \times 50.0L}{\frac{0.0821atm.L}{mol.K} \times 294.2K} = 0.683 mol[/tex]
Step 3: Calculate the mass of boron trifluoride gas
The molar mass of BF₃ is 67.81 g/mol.
[tex]0.683 mol \times \frac{67.81g}{mol} = 46.3 g[/tex]
Which of the following elements is the most nonreactive? H,fe, Au, O, Ne
Answer:
Ne (Neon)
Explanation:
H = Hydrogen
Fe = Iron
Au = Gold
O = Oxygen
Ne = Neon
Non-reactive elements do not easily combine with the other elements. Neon is an example of a very non-reactive element.
what volume at stp of (a)o2 (b)H2 (c)Cl2 gas will be liberated during electrolysis by the passage of 48250c of electricity,molar volume=22.4
The volume of o₂ 2.8 liters or 2.8 dm³.
The volume of H₂ 2.8 liters or 5.6dm³.
The volume of H₂ 2.8 liters or 5.6 dm³.
What s electrolysis?
Electrolysis is the process by which electric current is passed through an electrolyte to effect a chemical change.
Through this chemical change in which the substance loses gets oxidized or gains an electron reduced.
calculations:-for a divalent molecule O2 4*96500, C = 1 mole of gas evolved.
∴48250c =48250/(4*96500)=0.125mole
volvme = 0.125*22.4= 2.8 litre.
for monovalent cl and H2 molecules, 2*96500c = 1 mole of gas is evolved.
∴48250c =48250/(2*96500)=0.25mole
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Spell out the full name of the compound.
Answer:
2–methylpropene.
Explanation:
To successfully name the compound given in the question, we must observe the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, let us determine the name of the compound. This is illustrated below:
1. The functional group of the compound is the double bond i.e the compound is an alkene.
2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.
3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.
4. Therefore, the name of the compound is:
2–methylpropene
The name of the compound in the attached image is; 2-methyl propene
Naming Organic compoundsAmong the rules for Naming organic compounds is to identify the longest carbon chain containing the dominant function group (in this case alkene).
Hence, the base compound is propene.
However, the structure is branched on the 2nd carbon atom and attached is a methyl group.
Ultimately, the name of the compound is; 2-methyl propene
Read more on organic compounds;
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A certain lightbulb containing argon at 1.20 atm and 18°C is
heated to 85°C at constant volume. Calculate its final pressure
(in atm).
Answer:
certain lightbulb containing argon at 1.20 atm and 18 0 C is heated to 85 0 C at constant volume. What is the final pressure of argon in the lightbulb (in atm)? P 1 T 1 P 2 T 2 ... Ideal Gas Equation 5.4 Charles' law: V T (at constant n and P ) ... Consider a case in which two gases, A and B , are in a container of volume V.
Explanation:
A sample of 0.35 L of argon gas (at a temperature of 13 oC and a pressure of 568 torr) is heated to 156 oC and a new pressure of 897 torr. Calculate the new volume of the gas.
Answer:
The new volume of the gas is 0.332 liters.
Explanation:
Let suppose that argon behaves ideally, the equation of state of the ideal gas is:
[tex]P\cdot V = n \cdot R_{u}\cdot T[/tex]
Where:
[tex]P[/tex] - Pressure, measured in torr.
[tex]V[/tex] - Volume, measured in liters.
[tex]n[/tex] - Molar quantity, measured in moles.
[tex]T[/tex] - Temperature, measured in kelvins.
[tex]R_{u}[/tex] - Ideal gas constant, measured in [tex]\frac{torr\cdot L}{mol \cdot K}[/tex].
Since gas sample is a closed system experimenting a heating process, that is, molar quantity remains constant, the following relationship is derived from the equation of state described above:
[tex]\frac{P_{o}\cdot V_{o}}{T_{o}} = \frac{P_{f}\cdot V_{f}}{T_{f}}[/tex]
Where:
[tex]P_{o}[/tex], [tex]P_{f}[/tex] - Initial and final pressures, measured in torr.
[tex]V_{o}[/tex], [tex]V_{f}[/tex] - Initial and final volumes, measured in liters.
[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures, measured in kelvins.
Now, the final volume of the gas is found:
[tex]V_{f} = \left(\frac{T_{f}}{T_{o}}\right)\cdot \left(\frac{P_{o}}{P_{f}} \right)\cdot V_{o}[/tex]
If [tex]T_{o} = 286.15\,K[/tex], [tex]T_{f} = 429.15\,K[/tex], [tex]P_{o} = 568\,torr[/tex], [tex]P_{f} = 897\,torr[/tex] and [tex]V_{o} = 0.35\,L[/tex], the new volume of the gas is:
[tex]V_{f} = \left(\frac{429.15\,K}{286.15\,K} \right)\cdot \left(\frac{568\,torr}{897\,torr} \right)\cdot 0.35\,L[/tex]
[tex]V_{f} = 0.332\,L[/tex]
The new volume of the gas is 0.332 liters.
How many grams of Boron can be obtained from 234 grams of B2O3?
Answer:
72.67g of B
Explanation:
The reaction of B₂O₃ to produce boron (B), is:
B₂O₃ → 3/2O₂ + 2B
That means B₂O₃ produce 2 moles of boron
Molar mass of B₂O₃ is 69.62g/mol. 234g of B₂O₃ contains:
234g B₂O₃ ₓ (1mol / 69.62g) = 3.361 moles of B₂O₃.
As 1 mole of B₂O₃ produce 2 moles of B, Moles of B that can be produced from B₂O₃ is:
3.361mol B₂O₃ ₓ 2 = 6.722 moles of B.
As molar mass of B is 10.811g/mol. Thus mass of B that can be produced is:
6.722mol B ₓ (10.811g / mol) = 72.67g of B
Design your own experiment: Factors that affect the rate of a reaction
Did anybody do the lab?
Answer:
Reactant concentration, the physical states of the reactants, surface area, temperature and the presence of catalyst.
What is a double bond?
Predict the products that will be formed by the reaction below. Al(s)+Na2SO4(s)—>
Answer:
Al₂(SO₄)₃ and Na
Explanation:
Al has a charge of +3, Na has a charge of +1 and SO₄ has a charge of -2. Since cations and anions will bond we know that Al will bond with SO₄ leaving Na by itself (since this is a single replacement reaction). When Al bonds with SO₄ it makes aluminum sulfate which is Al₂(SO₄)₃ and Na will be left by itself.
How many moles are in 17.2g k2s
Answer: 0.156 mol
Explanation:
To find the moles of 17.2 g K₂S, we need to know the molar mass to convert.
[tex]17.2g*\frac{mol}{110.256 g} =0.156 mol[/tex]
Use the link Standard Reduction Potentials. Write net equations for the spontaneous redox reactions that occur during the following or none (all lower case) if there is no extensive reaction. Use the lowest possible coefficients. A) Iron metal is dipped into a Ni2+ solution.B) Copper metal is added to hydrochloric acid.C) A silver wire is added to nitric acid (HNO3).D) Magnesium metal is added to waterE) Chromium metal is added to a solution of Mg2+
Answer:
a) Fe(s) + Ni^2+(aq) ----> Fe^2+(aq) + Ni(s)
b) no reaction
c) no reaction
d) 2Mg(s) + 2H2O(l)-----> 2Mg^2+(aq) + O2(g) +4H^+(aq)
e) no reaction
Explanation:
It is important to say here that the ability of a particular chemical specie to displace another chemical specie is dependent on the relative standard reduction potentials of the species involved.
All the reactions stated above are redox reactions. Let us take reaction E as an example. Mg^2+ has a reduction potential of -2.37 V while Cr^3+ has a reduction potential of -0.74V. Since the reduction potential of magnesium is more negative than that of chromium, there is no reaction when a piece of chromium metal is dipped into a solution of Mg^2+.
Similarly, though metals displace hydrogen gas from dilute acids, metals that are less than hydrogen in the reactivity series cannot do that. This explains why there is no reaction when copper and silver are dipped into dilute acid solutions.
Reaction occurs when iron is dipped into a nickel solution because the reduction potential of Fe^2+ is far more negative than that of Ni^2+.
e.) MO(NO2)3
What’s the name
Answer:
Molybdenum Nitrite
Explanation:
Mo => Molybdenum
NO2 => Nitrite
In a zero order reaction, it takes 342 seconds for 75% of a hypothetical reactant to decompose. Determine the half-life t_{1/2} in units of seconds. Do not enter units with your numerical answer. Numeric Answer:
Answer:
228 s
Explanation:
In a zero order reaction, the formula for the half life is given as;
t1/2 = [A]o / 2k
To obtain the rate constant k, we have to use;
[A] = [A]o - kt
kt = [A]o - [A]
From the question;
it takes 342 seconds for 75% of a hypothetical reactant to decompose.
We have;
t = 324
[A] = 25
[A]o = 100
Upon solving for k we have;
kt = [A]o - [A]
k = ( [A]o - [A] ) / t
k = (100 - 25 ) / 342
k = 75 / 342 = 0.2193
Solving for t1/2;
t1/2 = [A]o / 2k
t1/2 = 100 / 2(0.2193)
t1/2 = 100 / 0.4386 = 228 s
How many grams of POCl3 are produced when 225.0 grams of P4O10 and 675.0 grams of PCl5 react? This is the balance equation P4O10 + 6PCl5 → 10POCl3
Answer:
900g of POCl₃
Explanation:
Hello,
To solve this question, we'll require the equation of reaction.
P₄O₁₀ + 6PCl₅ → 10POCl₃
Molar mass of P₄O₁₀ = 283.886 g/mol
Molar mass of PCl₅ = 208.24 g/mol
Molar mass of POCl₃ = 153.33 g/mol
But Number of moles = mass / molar mass
Mass = molar mass × number of moles
Mass of POCl₃ = 153.33 × 10 = 1533.3g
Mass of PCl₅ = 208.24 × 6 = 1249.44g
Mass of P₄O₁₀ = 283.886 × 1 = 283.886g
From the equation of reaction,
283.886g of P₄O₁₀ + 1249.44g of PCl₅ produces 1533.33g of POCl₃
I.e 1533.33g of reactants produces 1533.33g of product (law of conservation of mass)
Therefore, (225g of P₄O₁₀ + 675g of PCl₅) = 900g will give x g of POCl₃.
1533.33g of reactants = 1533.33g of products
900g of reactants = x g of products
x = (900 × 1533.33) / 1533.33
x = 900g of POCl₃
