Answer:
f = 0 N
Explanation:
It is given that,
A horse pulls a wagon with 2000N of at constant velocity.
We need to find the friction acting on the wagon.
As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.
Hence, the correct option is (a).
What determines the type of air mass that forms in an area?
Question 11 options:
The amount of oxygen present
The amount of air present
The direction of air flow
The location where it forms
Answer: no because you have left the number
Explanation:
If your parasympathetic nervous system was activated what might you be doing?
A. Relaxing under a tree
B. Running a marathon
C. Skiing
D. Driving home in traffic
Question 2: Start-Up
Now you will use another Tracker experiment to examine the displacement, velocity, and acceleration of a car in the x (horizontal) direction. To
begin your investigation, open the Tracker Car Start-up experiment.
Part A
Play () the video. At the end, rewind (H) and step forward (►) one frame ata time to observe the step-by-step changes in position. Based on
your observations, describe the car's displacement (distance and direction from the starting place) over time.
Answer:
The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.
Explanation:
Answer: The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.
Explanation: edmentum sample answer
Use of lubricants increase efficency of machine
Answer:
Lubrication reduces friction and allows moving machine parts to slide smoothly past each other. Selecting the appropriate lubrication solution can help reduce premature bearing failures and increase machine uptime, productivity and energy efficiency.
Explanation:
which statement about force is incorrect
Answer:
What are the options?
Explanation:
calculate the number of molecules of hydrogen and carbon present in 4 g of methane
Answer:
Answer = 6.022×10²³ molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.
During an isothermal process one mole of a monoatomic gas did 3000 J of work on its surrounding. The final volume and pressure of the gas are 25 L and 1 atm, respectively. What was the initial volume of the gas
Answer: The initial volume of the gas is 7.72 L
Explanation:
For an isothermal process the temperature is constant.
[tex]PV=nRT[/tex]
as P = pressure = 1 atm ,
V = Volume = 25 L
n = moles
R= gas constant
T = temperature
[tex]PV=1atm\times 25L[/tex]
[tex]nRT=25Latm=25\times 101.3J=2532.5J[/tex] (1Latm=101.3 J)
For isothermal reaction :
[tex]w=-2.303nRT\log\frac{V_2}{V_1}[/tex]
where , w = work done by system = -ve
n = moles = 1
[tex]V_2[/tex] = final volume = 25 L
[tex]V_1[/tex] = initial volume = ?
[tex]-3000J=-2.303\times 2532.5\log \frac{25}{V_1}[/tex]
[tex]V_1=7.72L[/tex]
Thus initial volume of the gas is 7.72 L
A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one second, what is the spring constant required if the mass is 1.3 kg
Answer:
The value is [tex]k = 51.34 \ N/ m[/tex]
Explanation:
From the question we are told that
The mass is [tex]m = 1.3 \ kg[/tex]
The needed oscillation time is [tex]T = 1 \ s[/tex]
Generally the spring constant is mathematically represented as
[tex]k = \frac{4 \pi^2 * m }{ T^2}[/tex]
=> [tex]k = \frac{4* 3.142^2 * 1.3 }{ 1^2}[/tex]
=> [tex]k = 51.34 \ N/ m[/tex]
help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 39 points and will give branlist asap!
Examine the diagram below and answer the following questions for 2 points each: Identify which graph shows an object that is not moving. Explain why. Identify which graph shows an object that is speeding up over time. Explain why. Identify which graph shows an object that is moving at a constant speed. Explain why. Question 15 options:
Answer:
Graph for object that is not moving: B
Graph for object that is speeding up: D
Explanation:
A.) In order to represent that an object is not moving, you must either show that there is no velocity (0 m/s) or show a position over time graph that is a horizontal line.
Because the position is the same as time increases, the graph shows that there the object must be at rest, as there is no change in position due to velocity. (Velocity must be 0m/s)
B.) In order to represent an object is speeding up, the position time graph must either be a positive exponential function, the velocity time graph must be a positive, linear line, or the acceleration over time graph must be a positive, horizontal line.
Why is D the correct answer? Because if an object is speeding up, you know that the value of its speed (velocity) is increasing at some rate. And since speeding up refers to positive change, the function of velocity over time graph must be a positive function.
what is force?answer in one line.
in great detail, explain why big chungus is the most powerful being of all? any counter arguments?
Answer:
well for me
Explanation:
I think
Big Chungus is the greatest game know to man currently it is only available on ps4, dispite the fact I am loyal to Xbox I couldn’t help but buy a ps4 for it I have found a review from a Redditor
And also he's presence scared everyi
Answer:
big chungus is not funny, its just a big rabbit.
Explanation:
During the pitching motion, a baseball pitcher exerted an average horizontal force of 90 N against the 0.1 kg baseball while moving it through a horizontal displacement of 2.0 m before release. (1) what was the amount of work performed by the pitcher on the baseball (2) If the velocity at the start of the pitching motion was zero, at release the ball was traveling horizontally at which velocity
Answer:
(1) 180 J
(2) 60 m/s
Explanation:
(1) From the question,
Amount of work performed by the pitcher on the baseball = Force × distance.
W = F×d............... Equation 1
Given: F = 90 N, and d = 2.0 m.
Substitute into equation 1
W = 90×2
W = 180 Joules.
(2)
F = ma........... Equation 2
Where a = acceleration of the ball.
a = F/m
Given: F = 90 N, m = 0.1 kg.
therefore,
a = 90/0.1
a = 900 m/s².
Using,
v² = u² + 2as ............ Equation 3
Where u = 0 m/s, a = 900 m/s², s = 2 m.
substitute into equation 3
v² = 0² + 2×900×2
v² = 3600
v = √3600
v = 60 m/s
Question 1 of 25
Two asteroids with masses 3.71 x 10 kg and 1.88 x 104 kg are separated by
a distance of 1,300 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity
Gm, 2 The gravitational
constant Gis 6.67 x 10-11 Nm²/kg?
A. 275 x 10"N
B. 4.13 x 10°N
C. 2.04 x 10°N
O D. 3.58 x 10-N
SUBMIT
Answer:
2.753*10^-11N
Explanation:
According to Newton's law of gravitation, the force between the masses is expressed as;
F = GMm/d²
M and m are the distances
d is the distance between the masses
Given
M = 3.71 x 10 kg
m = 1.88 x 10^4 kg
d = 1300m
G = 6.67 x 10-11 Nm²/kg
Substitute into the formula
F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²
F = 46.52*10^(-6)/1.69 * 10^6
F = 27.53 * 10^{-6-6}
F = 27.53*10^{-12}
F = 2.753*10^-11
Hence the gravitational force between the asteroid is 2.753*10^-11N
Coherent light from a laser shines through two slits 0.002 cm apart, producing an interference pattern on a screen. A bright central fringe is seen on the screen in line with a point directly between the slits. The next bright fringe is seen at an angle of 2 degrees above the central fringe (with a dark fringe between). What is the wavelength of the laser’s light? (1 nm = 10-9 m)
Answer:
λ = 698 nm (Approx)
Explanation:
Given:
Width d = 0.002 cm = 0.002 x 10⁻² nm
θ = 2°
Computation:
d sinθ = mλ
(0.002 x 10⁻²) sin2° = mλ
λ = 698 nm (Approx)
Through which material would you expect sound waves to move fastest? O A. Iron O B. Water O c. Air O D. Milk
Answer:
Solids
Is this what your looking for, It might tell you the answer?
the capacity of computer of performing more than one task at the same time is called ............of computer.
Answer:
We conclude that the capacity of the computer of performing more than one task at the same time is called the versatility of the computer.
Explanation:
We know that when a PC or laptop is capable of doing multiple tasks at the same time, this particular characteristic of a computer is termed as the versatility of the computer.
In other words, the versatility of the computer makes sure the computer or PC can do multitasking at the same time.
The versatility of a computer makes sure the machine can perform different types of works completed at the same time.
For example, using a computer, we can listen to music while playing games at the same time.
Therefore, we conclude that the capacity of the computer of performing more than one task at the same time is called the versatility of the computer.
An apple (mass = 0.25 kg) on a string 1 m in length is whirled above a student's head in a circle. The apple has a tangential speed of 12 m/s. What is the magnitude of the centripetal force on the apple?
Answer:
36N
Explanation:
Given parameters:
Mass of apple = 0.25kg
length of string = 1m
tangential speed = 12m/s
Unknown:
magnitude of centripetal force = ?
Solution:
The centripetal force keeps a body moving along a circular path.
It is mathematically derived using the expression below;
F = [tex]\frac{mv^{2} }{r}[/tex]
F is the centripetal force
m is the mass
v is the tangential speed
r is the radius
Now insert the parameters and solve;
F = [tex]\frac{0.25 x 12^{2} }{1}[/tex] = 36N
which button allow you to move the text enter to a higher heading level
Answer:
The entry level is the basic part of any text or power point which needs to be pushed to the higher levels for reading the entire content
Can a physical guantity have unit but is dimensionless ?
You and your buddy are scuba diving and notice that air bubbles triple in volume as they rise to the surface from where you are in the ocean. Ignoring any temperature changes, how far below the surface of the water (in m) are you when these bubbles are released
Answer:
You and your buddy are scuba diving and notice that air bubbles triple in volume as they rise to the surface from where you are in the ocean. Ignoring any temperature changes, how far below the surface of the water (in m) are you when these bubbles are released? The ocean has a density of 1034 kg/m3
The arrow strikes a deer in the woods with the speed of 55 m/sec at an angle of 315 degrees. Calculate the Horizontal and vertical components of the arrow’s velocity.
Answer:
100 m
Explanation:
Determine e when I = 0.50 A and R = 12 W.
Answer:
The correct answer is "24 V".
Explanation:
The given values are:
Current,
I = 0.50 A
Resistance,
R = 12 W
As we know,
⇒ [tex]I = 0.5\times (\frac{E}{2R})[/tex]
On substituting the given values, we get
⇒ [tex]0.5= (\frac{E}{4\times 12} )[/tex]
⇒ [tex]0.5= (\frac{E}{48} )[/tex]
⇒ [tex]E=24 \ V[/tex]
A school bus's velocity decreases from 15 m/s to 5 m/s forwards over a period of 10 s. What is the bus's average acceleration? [Vf=v,+at]
Answer:-1 m/s/s
Explanation:
The acceleration of the bus when its velocity changes from 15 m/s to 5 m/s will be a=1 m/s^2
What is acceleration?Acceleration is defined as the change of the velocity with the time. Acceleration is a vector quantity and is defined by both the magnitude and the direction.
Now from the first equation of motion we have,
[tex]a= \dfrac{v-u}{t}[/tex]
we have V=15 m/s, u=5 m/s , t=10 seconds
[tex]a=\dfrac{15-5}{10}=1\ \frac{m}{s^2}[/tex]
Hence the acceleration of the bus will be a=1 m\s^2
To know more about acceleration follow
https://brainly.com/question/25749514
difference between incident ray and refracted ray
Answer:
** incident ray.
Incident ray - the ray of light falling on the surface AB is called the incident ray
reflected ray.
** Reflected ray - the incident ray bouncing back in the same medium after striking the reflecting surface is called reflected ray.
a 0.8 ,^3 insulated rigid tank contains 1.54 kg of carbon dioxide at 100 kPa. Now paddle wheel work is done on the system until pressure in the tank rises to 135 kpa assuming the ideal gas model and negligible kinetic and potential energy effects determine the paddle wheel work dine during the process and the energychange during this process
Answer:
The answer is "[tex]W= 100.44 \ KJ\ \ \ \W_{win}=7.23 \ KJ[/tex]"
Explanation:
Please find the complete question in the attached file.
From of the ideal gas relation that initial and the last temperatures were determined:
[tex]T_1 = \frac{P_1 V}{m R}[/tex]
[tex]= \frac{100 \times 0.8}{1.54 \times 0.1889} \\\\ = 275 \ K[/tex]
[tex]T_2 = \frac{P_2 V}{m R}[/tex]
[tex]= \frac{135 \times 0.8}{1.54 \times 0.1889} \\\\ = 317 \ K[/tex]
In the initial and final states, the internal energies for given temperatures are described from A-20 by means of intelmpolation and divided by the carlxon molar mass.
[tex]u_1 = 141.56 \frac{KJ}{kg}\\\\u_2 = 206.78 \frac{KJ}{kg}[/tex]
The real job is just the difference between internal energies:
[tex]W = m(u_2 - u_1) \\\\[/tex]
[tex]= 1.54(206.78 -141.56) \ kJ \\\\ =100.44 \ kJ[/tex]
In the initial and final states, the zero entries are as determined as internal energies:
[tex]S_1^{\circ} =4.788 \frac{KJ}{kg K}\\\\S_2^{\circ} =5.0478 \frac{KJ}{kg K}[/tex]
From its energy increase, the minimum work required is determined:
[tex]W_{min} = m(u_2-u_1 - T_0(s_2 -S_1))\\\\=W-mT_0(S_2^{\circ}- S_1^{\circ} -R \In \frac{P_2}{P_1})\\\\= 100.44kJ -1.54 \times 298( 5.0478-4.788-0.1889 \In \frac{135}{100})\\\\=7.23\ KJ\\[/tex]
why did the following change occur? the snow that covered the ground all winter began to melt, temperatures rose, and flowers started to bloom
A.) Days became shorter.
B.) The Earth tilted away from the sun
C.) The sun's rats became for concentrated.
D.) Earth completed one revolution
Answer:C
Explanation:
Answer:
B
Explanation:
Because the earth shifts axes points so it would make it cllser hotter etc
charge of one of electron is 1.6022×10*-19 coulomb. what is the total charge on 1 mole of electrons
There are
[tex]6.023 \times {10}^{23} [/tex]
electrons in a mole. So charge of 1 mole electron is
[tex]6 \times {10}^{23} \times ( - 1.6022) \times {10 }^{ - 19} [/tex]
a rock falls for 4 seconds. How far did it fall
Answer:
d = 80 m
Explanation:
It is given that,
A rock falls for 4 seconds.
We need to find how far did it fall.
let it cover d distance.
Using equation of motion to find it :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 (at rest initially)
a = g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 10\times 4^2\\\\d=80\ m[/tex]
It will fall at a distance of 80 m.
Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalpost and experiences a backward force of 17600 N for 55 ms.
Answer:
0.8 m/s
Explanation:
F(avg) * Δt = I, where
F(avg) = Average force
Δt = change in time
I = impulse
From the question, we know that the
average force is given as -17600 N
time change is given as 55 milliseconds
speed of the player, v = 8 m/s
Mass of the player is given as 110 kg
Impulse, I = F(avg) * Δt
I = -17600 * 0.055
I = -968
Now, using the Impulse-Momentum theory, we have that
Δp = I and thus,
Δp = m [v(f) - v(i)], where
Δp = change in the momentum
v(f) = final speed of the player
v(i) = initial speed of the player
Substituting the values, we have
I = m [v(f) - v(i)]
-968 = m.v(f) - m.v(i)
m.v(f) = m.v(i) - 968
110v(f) = 110 * 8 - 968
110v(f) = 880 - 968
110v(f) = -88
v(f) = -88 / 110
v(f) = -0.8 m/s
A 0.0600-kilogram ball traveling at 60.0 meters per second hits a concrete wall. What speed must a 0.0100-kilogram bullet have in order to hit the wall with the same magnitude of momentum as the ball?
Answer:
the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
Explanation:
The computation of the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is as follows:
The ball momentum is
[tex]\Delta Q = mv\\\\\Delta Q = 6 \times 1^-2 \times 60\\\\\Delta Q = 3.6 kg \times m/s[/tex]
As there is a similar momentum
So,
[tex]\Delta Q = MV\\\\3.6 = 10^-2V\\\\V = 360 m/s[/tex]
Hence, the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
