A kite is flying 85 ft off the ground, and its string is pulled taut. The angle of elevation of the kite is 52degrees. Find the length of the string. Round your answer to the nearest tenth.

Answer:

reflex angle

Step-by-step explanation:

Acute is less than 90

Right = 90

Obtuse is greater than 90 and less than 180

Straight is 180

Reflex is greater than 180 and less than 360

This is greater than 90 and less than 180 so it is a reflex angle

Step-by-step explanation:

2) 63

3) 7000

4) 10

These are some answers

Answer:

196x^2y

Step-by-step explanation: The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

Answer:

r = -10*cos(t)

Step-by-step explanation:

To write the rectangular equation in polar form we need to replace x and y by:

[tex]x=r*cos(t)\\y=r*sin(t)[/tex]

Replacing on the original equation, we get:

[tex](x+5)^2+y^2=25\\x^2+10x+25+y^2=25\\(r*cos(t))^2+10*(r*cos(t))+25+(r*sin(t))^2=25[/tex]

Using the identity [tex]sin^2(t)+cos^2(t)=1[/tex] and solving for r, we get that the polar form of the equation is:

[tex](r*cos(t))^2+10*(r*cos(t))+25+(r*sin(t))^2=25\\r^2cos^2(t)+10rcos(t)+r^2sin^2(t)=0\\r^2cos^2(t)+r^2sin^2(t)=-10rcos(t)\\r^2(cos^2(t)+sin^2(t))=-10rcos(t)\\r^2=-10rcos(t)\\\\r=-10cos(t)[/tex]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?

Answer:

P( X' ∩ Y' ) = 0.205

Step-by-step explanation:

Let X is the event that the customer insures more than one car.

Let X' is the event that the customer insures exactly one car.

Let Y is the event that customer insures a sport car.

Let Y' is the event that customer insures not a sport car.

From the given information we have

70% of customers insure more than one car.

P(X) = 0.70

20% of customers insure a sports car.

P(Y) = 0.20

Of those customers who insure more than one car, 15% insure a sports car.

P(Y | X) = 0.15

We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

P( X' ∩ Y' ) = ?

Which can be found by

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

From the rules of probability we know that,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )    (Additive Law)

First, we have to find out P( X ∩ Y )

From the rules of probability we know that,

P( X ∩ Y ) = P(Y | X) × P(X)       (Multiplicative law)

P( X ∩ Y ) = 0.15 × 0.70

P( X ∩ Y ) = 0.105

So,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )

P( X ∪ Y ) = 0.70 + 0.20 - 0.105

P( X ∪ Y ) = 0.795

Finally,

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

P( X' ∩ Y' ) = 1 - 0.795

P( X' ∩ Y' ) = 0.205

Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

Answer:

[tex]1/\sqrt{2}[/tex]

Answer:

B

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

every sequence goes down by -3

Answer:

take away 3. the common difference is 3

Step-by-step explanation:

take away 3

Answer:

6

Step-by-step explanation:

If D is the midpoint of AC, that means that AC = AD * 2 = 3 * 2 = 6. And if C is the midpoint of AB, that means BC = AC = 6.

Answer:

84.13% of homes will have a monthly utility bill of more than $135

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 143, \sigma = 8[/tex]

What percentage of homes will have a monthly utility bill of more than $135?

We have to find 1 subtracted by the pvalue of Z when X = 135.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{135 - 143}{8}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a pvalue of 0.1587

1 - 0.1587 = 0.8413

84.13% of homes will have a monthly utility bill of more than $135

[tex]solution \\ {2x}^{2} - x + ( - x - {2x}^{2} - 2) \\ = {2x}^{2} - x - x - {2x}^{2} - 2 \\ = {2x}^{2} - {2x}^{2} - x - x - 2 \\ = - 2x - 2[/tex]

Hope it helps

Good luck on your assignment

Answer:

[tex] - 2x - 2[/tex]

Step-by-step explanation:

[tex]2 {x}^{2} - x + ( - x - 2 {x}^{2} - 2) \\ 2 {x}^{2} - x - x - 2 {x}^{2} - 2 \\ 2 {x}^{2} - 2 {x}^{2} - x - x - 2 \\ - 2x - 2[/tex]

hope this helps you.

brainliest appreciated

good luck!

have a nice day!

what that guy said                            ddddddddddddddddd

Answer:

Check Explanation

Step-by-step explanation:

Complete Question

Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the difference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.

Solution

The information required to run an hypothesis test to compare the annual bonuses of employees at company A and employees at company B.

- First of, we require a sample of bonuses from each of the two firms, to calculate the mean bonus at each of the companies and the standard deviation.

- We also need the data to satisfy the conditions necessary for an hypothesis test.

the major conditions for an hypothesis test is that

1) The sample must be a random sample extracted from the population, with each variable in the sample independent from one another.

2) The sample should be exrracted from a normal distribution population or approximate a normal distribution, so as to ensure almost normal behaviour from the samples

Then, to do the test,

Step 1

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

For this test, we want to investigate if the difference in annual bonuses for employees of company A and employees of company B is greater than $100.

Hence, the null hypothesis is that there is no sufficient evidence to suggest that the difference in annual bonuses for employees from company A and employees from company B is greater than $100.

And the alternative hypothesis is that there is sufficient evidence to suggest that the difference in annual bonuses for employees from company A and employees from company B is greater than $100.

Mathematically, if the difference in mean annual bonuses for employees from company A and employees from company B is μ

The null hypothesis is represented as

H₀: μ ≤ 100

The alternative hypothesis is represented as

Hₐ: μ > 100

Step 2

The testing procedure for this is a two-sample hypothesis test, Hence, we compute the test statistic in the next step.

Note that we must have had the mean of each of the samples (μ₁ and μ₂) and their standard deviations from the sample of annual bonuses of employees from both firms (s₁ and s₂)

Such that μ = μ₁ - μ₂

Test statistic = (μ - 100)/σₓ

σₓ = √[(s₁²/n₁) + (s₂²/n₂)]

Test statistic =

[(μ₁ - μ₂) - 100] ÷ √[(s₁²/n₁) + (s₂²/n₂)]

Step 3

Using the test statistic calculated, the significance level, the degree of freedom and the p-value table, we obtain the p-value.

Degree of freedom = n₁ + n₂ - 2

Step 4

The interpretation of p-values

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

Hope this Helps!!!

Answer:

length of segment YZ is 8 cm

Step-by-step explanation:

given data

AB = 16 cm

DA = 3[tex]\sqrt{2}[/tex] cm

AB and DA form interior angle  =  45-degre

WX ≠ YZ

WX = 16 cm

to find out

length of segment YZ

solution

area of △ABD is  the same as the area of △BCD

and

area of △ABD is express as

area of △ABD = AB × AD × sin(45) ÷ 2    ............1

put here value

area of △ABD = 16 × 3√2 × sin(45) ÷ 2

area of △ABD = 24

and

area of the parallelogram is

area of the parallelogram = 24 × 2

area of the parallelogram = 48

so

now we will consider here YZ = x

and Since ZY XW is isosceles trapezoid

so here we can say that

WM = ZM = (16 - x)  ÷ 2   .......................2

so area of  trapezoid will be

area of  trapezoid = [tex]\frac{ZY + WX }{2} \times ZM[/tex]         .......................3

area of  trapezoid = [tex]\frac{x+16}{2} \times \frac{16 - x}{2}[/tex]    

48 = [tex]\frac{x+16}{2} \times \frac{16 - x}{2}[/tex]  

solve it we get

x = 8

so length of segment YZ is 8 cm

Answer:

8

Step-by-step explanation:

YZ = 8

Answer:26 2/3 feet

Step-by-step explanation:40/30 = 4/3

(26 2/3) / 20= 4/3

Answer:

3.5

Step-by-step explanation:

To find the mean, add up all the numbers

(8+0+3+3+1+7+4+1+4+4) = 35

Then divide by how many numbers there are

35/10 = 3.5

The mean is 3.5

Answer:

Step-by-step explanation:

- Mean- The AVERAGE OF ALL NUMBERS: You add up all the numbers then you divide it by the TOTAL NUMBER of NUMBERS!

8+0+3+3+1+7+4+1+4+4=35

35/10=3.5

35

Answer:  c) BG ≡ GC

Step-by-step explanation:

Since A F, BD, and CE are medians, their intersected point is the centroid of the triangle.

Thus, the distance from the centroid to the vertices is the same.

⇒ GA = GB = GC

Answer:

Option A is correct.

A uniform distribution.

Step-by-step explanation:

Complete Question

T-Mobile sells 6 different models of cell phones and have found that they sell an equal number of each model. The probability distribution that would describe this random variable is called:

A) Uniform Distribution

B) Continuous Distribution

C) Poisson Distribution

D) Relative Frequency Distribution

Solution

A uniform distribution is one in which all the variables have the same probability of occurring.

It is also known as a rectangular distribution, as every portion of the sample space has an equal chance of occurring, with equal length on the probability curve, leading to a rectangular probability curve.

And for this question, 6 different models of phones sell an equal number, hence, the probability of selling each model is equal to one another, hence, this is evidently a uniform distribution.

Hope this Helps!!!

Answer:

The lateral area is equal to

LA=64\sqrt{3}\ m^{2}

Step-by-step explanation:

Answer:

3 wooden plank he can saw

Answer:

he can saw 3 wooden planks

Step-by-step explanation:

Answer:

Anle at B

b = 56.25°

Step-by-step explanation:

Triangle ABC is a right angle triangle. we are required to look for the angle at B

To do that we have one side of the triangle missing and we'd look for it first.

Let's side AC = c

AB = a

BC = b

c²=a² - b²

C² = 9² -5²

C² = 81 - 25

C² = 56

C = √56

For angle at B

√56/sinb = 9/sin90

Sin 90 = 1

Sinb = √56/9

b = sin^-1 (√56/9)

b = 56.251°

To the nearest hundredth

b = 56.25°

Problem 1

y = tan(3x+4)

f(x) = tan(3x+4)

f ' (x) = 3sec^2(3x+4) .... apply derivative chain rule

dy/dx = f ' (x)

dy = f ' (x) * dx

dy = ( 3sec^2(3x+4) ) * dx

Now plug in x = 5 and dx = 0.3

dy = ( 3sec^2(3*5+4) ) * 0.3

dy = 0.920681 which is approximate

Make sure your calculator is in radian mode.  Calculus textbooks will be in radian mode for the special sine limit definition [tex]\lim_{x\to0}\frac{\sin x}{x} = 1[/tex] to be true.

===========================================================

Problem 2

We'll have the same derivative function and same x value. The only difference is that dx = 0.6 this time.

dy = f ' (x) * dx

dy = ( 3sec^2(3*5+4) ) * 0.6

dy = 1.84136 approximately

Answer:

The relative change from Ohio to Indiana is 49.04

Step-by-step explanation:

Answer:

Step-by-step explanation:

Baltimore orioles : 1,000,000 + 1,000,000 + 500,000

Click 2 full bag and 1 half bag

Kansas city royals : 1,000,000 +500,000

Click 1 full bag and 1 half bag

Newyork Yankees  : 1,000,000 + 1,000,000 + 1,000,000 +1,000,000 +1,000,000 + 500,000

Click 5 full bag + 1 half bag

Answer:

D) Kaia saved $165.45 on a new guitar because it was 75 percent off. The price of the guitar before the discount was $220.60.

Step-by-step explanation:

Given in the attached diagram shows a model of a discount given on a purchase of guitar showing 75% of the price of guitar ($55.15 + $55.15 + $55.15) that was given.

It also tells that the price pays is 25% of the price of the guitar before the discount. I.e. 25% of %220.60 = 0.25 × 220.60 = $55.15.

From the diagram given, we can infer that Kaia bought the guitar at $55.15 while saving $165.45. That is 25% of the original price. And the amount saved, $165.45, is %75 of the original price ($55.15+$55.15+$55.15).

The answer is D.

Answer:

Kaia saved $165.45 on a new guitar because it was 75 percent off. The price of the guitar before the discount was $220.60.      

or D

Step-by-step explanation:

i got it right on my test

if you can please mark as branliest

Answer:

67,365,043,200

Step-by-step explanation:

A coin toss has 2 possible outcomes.  A coin tossed 3 times has 2³ = 8 possible permutations.

A standard die has 6 possible outcomes.  A die rolled 4 times has 6⁴ = 1296 possible permutations.

The number of ways 4 cards can be chosen from a deck of 52 without replacements is 52×51×50×49 = 6,497,400.

The total number of possible outcomes is:

8 × 1296 × 6,497,400 = 67,365,043,200

Answer:

It would decrease by 9.

Step-by-step explanation:

52 is the original mean or the initial mean.

43 is the final mean.

52-43 = 9

So 9 is the difference.

Hope this helped!

Answer:

$632.66 is the amount of money in the savings account after graduation

Step-by-step explanation:

There are 12 grades in high school. So the number of years before graduation here is 6 years.

Now to know the amount of money, the equation to use is;

A(t) = a(1+r)^t

Here;

A(t) = ?

a = 500

r = 4% = 4/100 = 0.04

t = 6 years

Substituting these values into the equation, we have;

A(t) = 500(1 + 0.04)^6

A(t) = 500(1.04)^6

A(t) = $632.66

Answer:

3^4

Step-by-step explanation:

3^2*3^2

3*3*3*3

3^4

a² + b² = c²

5² + 12² = c²

25 + 144 = c²

169 = c²

c = √169

c = 13

Answer:

the answer is 13

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that,

[tex]n_1=9,x=520,s^2_x=38\\\\n_2=8,y=540,s^2_y=20[/tex]

a) Under null hypothesis H₀ : there is no difference between the variability of night shift and day shift workers

i.e [tex]H_0:\sigma^2_x=\sigma^2_y=\sigma^2[/tex]

Alternative hypothesis [tex]H_1:\sigma_x^2>\sigma_y^2[/tex]

Level of significance = 5% = 0.05

b) The test statistic

[tex]F=\frac{S^2_x}{S_y^2} \sim F(n_1-1,n_2-1)\\\\=\frac{38}{20}\\\\=1.9[/tex]

Table value of [tex]F_{0.05}(n_1-1,n_2-1)[/tex]

[tex]=F_{0.05}(9-1,8-1))\\\\=F_{0.05}(8,7)\\\\=3.726[/tex]

[tex]\therefore F_{calculated}=1.9<Tab F_{0.05}(8,7)=3.726[/tex]

[tex]H_0[/tex] is accepted at 5% level of significance

Therefore ,there is no difference between the variability of night shift and day shift worker

c) The P-value is 0.206356

The result is not significant at P < 0.05

d) At 95% confidence interval

[tex]\frac{\frac{S^2_x}{S^2_y} }{F_{t-\alpha/2(8,7)} } <\frac{\sigma^2_x}{\sigma^2_y}\frac{\frac{S^2_x}{S^2_y} }{F_{\alpha/2(8,7)} } \\\\\Rightarrow\frac{1.9}{F_{t-(0.05/2)}} <\frac{\sigma^2_x}{\sigma^2_y} <\frac{1.9}{F_{(0.05/2)}} \\\\\Rightarrow\frac{1.9}{F_{0.975}} <\frac{\sigma^2_x}{\sigma^2_y} <\frac{1.9}{F_{(0.025)}} \\\\\Rightarrow\frac{1.9}{F_{3.726}} <\frac{\sigma^2_x}{\sigma^2_y} <\frac{1.9}{F_{(0.286)}}[/tex]

Variance -ratio lies betwee (0.51,6.643)

Conclusion: There is not sufficient evidence to support the claim  that the night shift worker show more variability in their output levels, than the day workers at α =0.05

Answer:

Step-by-step explanation:

Hello!

The claim is that the variability of the output levels of the night-shift is greater than the variability in the output levels of the day workers.

Be

X₁: output level of night shift workers.

n₁= 9

X[bar]₁= 520

S₁= 38

X₂: output level of day shift workers.

n₂= 8

X[bar]₂= 540

S₂= 20

Considering both variables have a normal distribution, the parameters of interest are the population variances.

a)

H₀: σ₁² ≤ σ₂²

H₁: σ₁² > σ₂²

b)

To compare both variances you have to conduct a variance ratio test with statistic:

[tex]F= (\frac{S^2_1}{S^2_2} )*(\frac{Sigma^2_1}{Sigma^2_2} )~~F_{n_1-1;n_2-1}[/tex]

[tex]F_{H_0}= (\frac{1444}{400} )*1=3.61[/tex]

c)

The test is one tailed  to the right, the p-value will have the same direction, i.e. it will be in the right tail of the distribution. The F distribution has degrees of freedom:

n₁ - 1= 9 - 1= 8

n₂ - 1= 8 - 1= 7

P(F₈,₇ ≥ 3.61) = 1 - P(F₈,₇ < 3.61) = 1 - 0.9461= 0.0539

The p-value of this test is 0.0539

d)

The CI for the variance ratio is:

[tex][\frac{S^2_1/S_2^2}{F_{n_1-1;n_2-1;1-\alpha /2}}; \frac{S^2_1/S_2^2}{F_{n_1-1;n_2-1;\alpha /2}}][/tex]

[tex]F_{n_1-1;n_2-1;1-\alpha /2}= F_{8;7;0.975}= 4.90[/tex]

[tex]F_{n_1-1;n_2-1;\alpha /2}= F_{8;7;0.025}= 0.22[/tex]

[tex][\frac{1444/400}{4.90}}; \frac{1444/400}{0.22}}][/tex]

[0.736; 16.409]

Using the level of significance complementary to the confidence level of the interval, you can compare it to the p-value calculated in item c.

p-value: 0.0539

α: 0.05

The p-value is less than the significance level, the decision is to reject the null hypothesis. Using a 5% significance level you can conclude that the variance in the output levels of the night shift workers is greater than the variance in the output levels of the day shift workers.