Answer:
a,c,e
Step-by-step explanation:
on edge-
Answer:
The answer is A, C, E
Find a probability. A bag contains 10 red M&Ms, 15 blue M&Ms, and 20 yellow M&Ms. a) What is the probability of drawing a yellow M&M? b) What is the probability of drawing something besides a blue M&M?
Answer:
a) 4/9
b) 2/3
hope it helps!
Step-by-step explanation:
a) number is yellow m&ms = 20
total number of m&ms = 10+15+20
= 45
Probability of getting a yellow m&m = 20/45
= 4/9
b) Number of blue m&ms = 15
Number of m&ms that aren't blue = 45-15 = 30
Total number of m&ms = 45
Probability of getting something besides blue m&m = 30/45
= 2/3
The probability that a house in an urban area will be burglarized is 6%. If 10 houses are randomly selected, what is the probability that none of the houses will be burglarized?
Answer:
[tex](\dfrac{94}{100})^{10} \ or\ \approx 0.54[/tex]
Step-by-step explanation:
Given :
Probability that a house in an urban area will be burglarized,
[tex]p =6\%=\dfrac{6}{100}[/tex]
To find:
Probability that none of the houses randomly selected from 10 houses will be burglarized = ?
[tex]P(r=0) =?[/tex]
Solution:
This question is related to binomial distribution where:
[tex]p =\dfrac{6}{100}[/tex]
[tex]\Rightarrow[/tex] Probability that a house in an urban area will not be burglarized,
[tex]q =1-6\%=94\%=\dfrac{94}{100}[/tex]
Formula is:
[tex]P(r=x)=_nC_xp^xq^{n-x}[/tex]
Where n is the total number of elements in sample space and
x is the number selected from the sample space.
Here, x = 10 and
x = 0
[tex]\therefore P(r=0)=_nC_0p^0q^{10-0}\\\Rightarrow 1 \times (\dfrac{6}{100})^0\times (\dfrac{94}{100})^{10}\\\Rightarrow 1\times (\dfrac{94}{100})^{10}\\\Rightarrow (\dfrac{94}{100})^{10}\\\\\Rightarrow (0.94)^{10}\\\Rightarrow \approx 0.54[/tex]
An industrial expert claims that the average useful lifetime of a typical car transimssion which comes with ten years warranty is significantly more than 10 years. In order to test this claim, 9 car transmissions are randomly selected and their useful lifetimes are recorded. The sample mean lifetime is 13.5 years and the sample standard deviation is 3.2 years. Assuming that the useful lifetime of a typical car transmission has a normal distribution, based on these sample result, the correct conclusion at 1% significance level for this testing hypotheses problem is: Group of answer choices
Answer:
Step-by-step explanation:
The question is incomplete. The missing information is the group of answer choices. The group of answer choices are
a) none of the above
b) Data provides sufficient evidence, at 1% significance level, to reject the expert's claim. In addition the p-value (or the observed significance level) is equal to P( T < -3.281).
c) Data provides insufficient evidence, at 1% significance level, to support the expert's claim. In addition the p-value (or the observed significance level) is equal to P( Z > 2.896).
d) Data provides sufficient evidence, at 1% significance level, to support the expert's claim. In addition the p-value (or the observed significance level) is equal to P( T >3.355).
e) Data provides insufficient evidence, at 1% significance level, to support the researcher's claim. In addition the p-value (or the observed significance level) is equal to P(Z > 2.896).
Solution:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ ≥ 10
For the alternative hypothesis,
µ < 10
This is a left tailed test.
Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.
Since n = 9,
Degrees of freedom, df = n - 1 = 9 - 1 = 8
t = (x - µ)/(s/√n)
Where
x = sample mean = 13.5
µ = population mean = 10
s = samples standard deviation = 3.2
t = (13.5 - 10)/(3.2/√9) = 3.28
Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a left tailed test. Therefore, we would find the critical value corresponding to 1 - α and reject the null hypothesis if the test statistic is less than the negative of the table value.
1 - α = 1 - 0.01 = 0.99
The negative critical value is - 2.896
Since - 3.28 is lesser than - 2.896, then we would reject the null hypothesis.
By using probability value,
We would determine the p value using the t test calculator. It becomes
p = 0.0056
Level of significance = 1%
Since alpha, 0.01 > than the p value, 0.0056, then we would reject the null hypothesis. Therefore, At a 1% level of significance, the sample data showed significant evidence that the average useful lifetime of a typical car transimssion which comes with ten years warranty is significantly less than 10 years
The correct option is
a) none of the above
Please answer this correctly
Answer:
11 2/3 tablespoons.
Step-by-step explanation:
[tex]1+1+1\frac{1}{3} +1\frac{1}{3} +1\frac{2}{3} +1\frac{2}{3} +1\frac{2}{3} +2=\\\\2+2\frac{2}{3} +3\frac{6}{3} +2=\\\\9\frac{8}{3} =\\\\11\frac{2}{3}[/tex]
11 2/3 tbsp chocolate mix
In a packet of stickers there are small stars, big stars, small rockets, and big rockets. Kevin is going to choose one of these stickers from the packet at random to put on his artwork. What is the probability that the sticker Kevin chooses is big or is a rocket
Answer:
3/4 or 0.75
Step-by-step explanation:
You have four options available
Lets say P(A) is pick a rocket
P(A) = 2/4 because there are two rockets in the four choices
simplify it to 1/2
P(B) pick a big = 2/4 because there are two bigs and two smalls.
simplify it to 1/2
P(A ∩ B) = Pick a big rocket = 1/4
P(AUB) = P(A)+P(B)- P(A ∩ B)
P(AUB) = 1/2+1/2- 1/4 = 3/4 or 0.75
for a sample size of 115 and a population parameter of 0.1,what is the standard deviation of the normal curve that can be used to approximate the binomial probability histogram. Round your answer to three decimal places
A.0.028
B.0.054
C.0.043
D.0.035
Answer:
A) 0.028
Step-by-step explanation:
Given:
Sample size, n = 115
Population parameter, p = 0.1
The X-Bin(n=155, p=0.1)
Required:
Find the standard deviation of the normal curve that can be used to approximate the binomial probability histogram.
To find the standard deviation, use the formula below:
[tex]\sigma = \sqrt{\frac{p(1-p)}{n}}[/tex]
Substitute figures in the equation:
[tex]\sigma = \sqrt{\frac{0.1(1 - 0.1)}{115}}[/tex]
[tex]\sigma = \sqrt{\frac{0.1 * 0.9}{115}}[/tex]
[tex]\sigma = \sqrt{\frac{0.09}{115}}[/tex]
[tex] \sigma = \sqrt{7.826*10^-^4}[/tex]
[tex] \sigma = 0.028 [/tex]
The Standard deviation of the normal curve that can be used to approximate the binomial probability histogram is 0.028
Stephen and Laura want to split a bag of fun-sized candy, and decide to use the divider-chooser method. The bag contains 100 Snickers, 100 Milky Ways, and 100 Reese's, which Stephen values at $1, $3, and $4 respectively. (This means Stephen values the 100 Snickers together at $1, or $0.01 for 1 Snickers)
If Kendra is the divider, and in one half puts: 30 Snickers , 40 Milky Ways , and 66 Reese's
a. What is the value of this half in Dustin's eyes?
b. Does D ustin consider this a fair share?
c. If Dustin was a divider, find a possible division that is consistent with his value system
Answer:
a) $4.14
b) No
c) 28 Snickers, 40 Milky Ways, 63 Reese's
72 Snickers, 60 Milky Ways, 37 Reese's
Step-by-step explanation:
a)
Since 1 Snickers is $0.01, 1 Milky Ways is $0.03, and 1 Reese's is $0.04:
30 Snickers: 30(0.01) = 0.3
40 Milky Ways: 40(0.03) = 1.2
66 Reese's: 66(0.04) = 2.64
The value is: 0.3 + 1.2 + 2.64 = 4.14
b)
The total value is: 1 + 3 + 4 = 8
A fair share must have the same value, 8/2 = 4. Since one half is 4.14 which is more than 4, it is not a fair share.
c)
First half:
28 Snickers: 28(0.01) = 0.28
40 Milky Ways: 40(0.03) = 1.2
63 Reese's: 63(0.04) = 2.52
Second half:
72 Snickers: 72(0.01) = 0.72
60 Milky Ways: 60(0.03) = 1.8
37 Reese's: 37(0.04) = 1.48
Find the volume of the cone.
4 cm
3 cm
V = [?] cm3
Round to the nearest tenth.
Answer:
Volume of a cone = 1/3πr²h
h = height
r = radius
r = 3cm h = 4cm
Volume = 1/3π(3)²(4)
= 36 × 1/3π
= 12π
= 36.69cm³
= 37cm³ to the nearest tenth
Hope this helps
Answer:
37.7
_______
NOT 37
Step-by-step explanation:
v = [tex]\frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]r^{2}[/tex] · [tex]h[/tex]
v = [tex]\frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]3^{2}[/tex] · [tex]4 = 12\pi = 37.69911 =[/tex] 37.7
A basketball coach is looking over the possessions per game during last season. Assume that the possessions per game follows an unknown distribution with a mean of 56 points and a standard deviation of 12 points. The basketball coach believes it is unusual to score less than 50 points per game. To test this, she randomly selects 36 games. Use a calculator to find the probability that the sample mean is less than 50 points. Round your answer to three decimal places if necessary.
Answer:
The probability that the sample mean is less than 50 points = 0.002
Step-by-step explanation:
Step(i):-
Given mean of the normal distribution = 56 points
Given standard deviation of the normal distribution = 12 points
Random sample size 'n' = 36 games
Step(ii):-
Let x⁻ be the random variable of normal distribution
Let x⁻ = 50
[tex]Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]
[tex]Z = \frac{50-56 }{\frac{12}{\sqrt{36} } }= -3[/tex]
The probability that the sample mean is less than 50 points
P( x⁻≤ 50) = P( Z≤-3)
= 0.5 - P(-3 <z<0)
= 0.5 -P(0<z<3)
= 0.5 - 0.498
= 0.002
Final answer:-
The probability that the sample mean is less than 50 points = 0.002
Answer:
56
2
.001
Step-by-step explanation:
The Central Limit Theorem for Means states that the mean of any sampling distribution of the means is equal to the mean of the population distribution. The standard deviation is equal to the standard deviation of the population divided by the square root of the sample size. So, the mean of this sampling distribution of the means with sample size 36 is 56 points and the standard deviation is 1236√=2 points. The z-score for 50 using the formula z=x¯¯¯−μσ is −3.
z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
-3.0 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001
-2.9 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.001 0.001 0.001
-2.8 0.003 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002
-2.7 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003
-2.6 0.005 0.005 0.004 0.004 0.004 0.004 0.004 0.004 0.004 0.004
-2.5 0.006 0.006 0.006 0.006 0.006 0.005 0.005 0.005 0.005 0.005
Using the Standard Normal Table, the area to the left of −3 is approximately 0.001. Therefore, the probability that the sample mean will be less than 50 points is approximately 0.001.
you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours this semester. what gpa must you get in order to raise your gpa to the correct level? set up an equation and use algebra to solve.
Answer:
[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]
And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:
[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]
And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:
[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]
And from the previous result we got:
[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]
And solving we got:
[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]
And then we can find the mean with this formula:
[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]
So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:
[tex] \bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8[/tex]
Where [tex] w_i[/tex] represent the number of credits and [tex]X_i[/tex] the grade for each subject. From this case we can find the following sum:
[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]
And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:
[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]
And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:
[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]
And from the previous result we got:
[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]
And solving we got:
[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]
And then we can find the mean with this formula:
[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]
So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Please help me with this problem I cant figure it out
Answer:
14w -29x
Step-by-step explanation:
-4w -6(4x -3w) -5x
= -4w -6(4x) -6(-3w) -5x (expand)
= -4w -24x +18w -5x
(grouping like terms together,)
= 18w -4w -24x -5x
= 14w -29x
Translate and solve: 30 times m is greater than −330. (Write your solution in interval notation.)
Answer:
(-11, infinity)
Step-by-step explanation:
30m>-330
m>-11
(-11, infinity)
The range of values of m solved by obtain the value of m in the equation given is (-11, infinity)
Expressing the problem Mathematically :
30m > - 330We can solve for m thus ;
30m> - 330
Divide both sides by 30
m > - 11
Hence, the value of m is greater than -11 up till infinity
Therefore, result expressed in interval notation (-11, infinity)
Learn more : https://brainly.com/question/18109354
What type of number can be written as an a fraction a/b where a and b are Integres and b is not equal to zero?
Answer:
Integers, Terminating Decimals, Recurring Decimals, Proper and Improper Fractions.
Step-by-step explanation:
The following subset of the real number system can be written in the form [tex]\dfrac{a}{b}[/tex], b≠0.
Integers(ℤ): These are positive and negative whole numbers. For example, 5 can be written as [tex]\dfrac{5}{1}[/tex]
Terminating Decimals: These are fractions that when converted to decimal numbers have an end.
e.g. [tex]\dfrac{5}{2}=2.5[/tex]
Recurring Decimals: These are fractions that when converted to decimal numbers do not have an end.
e.g. [tex]\dfrac{8}{11}=0.727272...=0.\overline{72}[/tex]
Proper Fractions: These are fractions of the form [tex]\dfrac{a}{b}[/tex] where a<b. An examples is [tex]\dfrac{4}{5}[/tex]
Improper Fractions: These are fractions of the form [tex]\dfrac{a}{b}[/tex] where a>b. An examples is [tex]\dfrac{5}{4}[/tex]
Which line is parallel to the line y = 1/2 x + 5 and passes through the point (-2, 1)?
Answer:
[tex]y = \frac{1}{2} x+2[/tex]
Step-by-step explanation:
Parallel => So, Its slope would be the same as this one
Slope = m = 1/2
Now,
Point = (x,y) = (-2,1)
So, x = -2, y = 1
Putting this in the slope - intercept equation to get b
[tex]y = mx+b[/tex]
1 = (1/2)(-2)+b
1 = -1+b
Adding 1 to both sides
b = 1+1
b = 2
Now Putting m and b in the slope - intercept equation to get the equation of this line
[tex]y = \frac{1}{2} x+2[/tex]
Please answer this correctly
Answer:
3/8
Step-by-step explanation:
Since the wheel is numbered 2 through 9, only 3 of the 8 are less than 5 (2, 3, and 4)
Answer:
37.5%
Step-by-step explanation:
It’s 3/8 but to make a percent you divide 3 by 8 which is .375 and you move the decimal place 2 places to the right do it is 37.5%
Assume that when adults with smartphones are randomly selected, 47% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that fewer than 4 of them use their smartphones in meetings or classes.
Answer:
22.51% probability that fewer than 4 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smartphones in meetings or classes, or they do not. The probability of an adult using their phone is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening
47% use them in meetings or classes.
This means that [tex]p = 0.47[/tex]
10 adult smartphone users are randomly selected
This means that [tex]n = 10[/tex]
Find the probability that fewer than 4 of them use their smartphones in meetings or classes.
[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{10,0}.(0.47)^{0}.(0.53)^{10} = 0.0017[/tex]
[tex]P(X = 1) = C_{10,1}.(0.47)^{1}.(0.53)^{9} = 0.0151[/tex]
[tex]P(X = 2) = C_{10,2}.(0.47)^{2}.(0.53)^{8} = 0.0619[/tex]
[tex]P(X = 3) = C_{10,3}.(0.47)^{3}.(0.53)^{7} = 0.1464[/tex]
[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0017 + 0.0151 + 0.0619 + 0.1464 = 0.2251[/tex]
22.51% probability that fewer than 4 of them use their smartphones in meetings or classes.
Need help ASAP thank you!!!!
Answer:
65.97
Step-by-step explanation:
volume of a cone is pi(r)^2(h)/3
hope this helps
What is the area of the following circle? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal.
Answer:
A = 16 pi units^2
Step-by-step explanation:
The area of a circle is given by
A = pi r^2
A = pi ( 4)^2
A = 16 pi units^2
Which of the following is NOT a collinear point in the image below?
Consider the next 1000 98% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on which the intervals are based are selected independently of one another. How many of these 1000 intervals do you expect to capture the corresponding value of μ?
Answer:
980 intervals.
Step-by-step explanation:
For each interval, there are only two possible outcomes. Either it captures the population mean, or it does not. One interval is independent of other intervals. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
98% confidence interval
Has a 98% probability of capturing the population mean, so [tex]p = 0.98[/tex]
1000 intervals
This means that [tex]n = 1000[/tex]
How many of these 1000 intervals do you expect to capture the corresponding value of μ?
[tex]E(X) = np = 1000*0.98 = 980[/tex]
980 intervals.
Let S(x, y) denote the statement "x has seen y" and D denote the set of all students in our class and M be the set of all movies.
a. Express the following English sentence as a quantified proposition using the definitions above:
"For every movie there is a pair of students in our class who have both seen it." Hint: Use three quantifiers - one for the movie and two for a pair of students.
b. Negate the quantified proposition you wrote for part (a) (i.e., place a "¬" in front of it). Use de Morganâs law for quantifiers to move the negation inside the quantifiers.
c. Translate you answer for part (b) back to plain English.
Answer:
Step-by-step explanation:
a) Recall the quantifiers [tex]\forall, \exists[/tex].
Then, we can translate the proposition as follows
[tex]\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m)[/tex]
b) Recall that an expression of the form [tex]\exists x P(x)[/tex] its negation is of the form [tex]\forall x \neg P(x)[/tex] which means that it is not true that for all elements the proposition P holds. Equivalently, we have that the negation of an expression of the form [tex]\forall x P(x)[/tex] is [tex]\exists x \neg P(x)[/tex] which means that there is at least one x such that P doesn't hold. Using this, we get the following
[tex]\neg(\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \neg (\exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \neg (\exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \forall y \in D \neg(S(x,m)\land S(y,m))[/tex]
By De Morgan's law, we have that [tex]\neg (A \land B) = \neg A \lor \neg B[/tex]
So, the final statement is
[tex]\exists m \in M \forall x \in D \forall y \in D \neg S(x,m) \lor \neg S(y,m)[/tex]
c)
This statement means: There is a movie that for every pair of students, at least one of the students hasn't seen the movie yet.
People who are good at maths help
Answer:
F-6
E-12
V-8
Step-by-step explanation:
In the case of a cuboid this gives 6 + 8 = 12 + 2; that is, like a cube, a cuboid has 6 faces, 8 vertices, and 12 edges.
hope this helps :))
This applet illustrates 95% confidence intervals for samples from a normal distribution with known variance.
When taking 100 samples of size 30 or greater from a population, exactly 95 of them will create a confidence interval that contains the true population mean.
a. True
b. False
Which statement is the correct interpretation of the confidence interval in this illustration
a. The probability the true mean is between 76.08 and 83.92 is 0.95 or 95%.
b. We are 95% confident that the true mean is between 76.08 and 83.92.
Answer:
1- b. False
2 b. We are 95% confident that the true mean is between 76.08 and 83.92.
Step-by-step explanation:
Confidence Interval is the estimated value that is computed from the statistic of data which is observed. The range value is plausible for unknown parameters. To find the critical value the confidence interval value is observed through the t-value table.
It is a square pyramid with a base edge of 706 feet and an original height of 470 feet.
Answer: That would be the Khafre Pyramid
Step-by-step explanation:
What value of X makes this equation true negative 2X +3 equals -15
Answer:
The answer is -9
Answer:
1x=-15
Step-by-step explanation:
-2 plus 3 =1 therefore 1x which = -15
$425, but everything is on sale for 20% off. What is the amount of the discount? What is the cost of the table after the discount?
Answer:
$85 discount and $340 after Discount
Step-by-step explanation:
425x0.20=85
425-85=340
Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer: time = 20 seconds
Step-by-step explanation:
h(t) = -16t² + 316t + 80
The shape of this graph is an upside parabola ∩.
It lands on the ground when height (h) = 0
Set the equation equal to zero, factor, and solve for t.
0 = -16t² + 316t + 80
0 = 4t² - 79t - 20 divided both sides by -4
0 = (4t + 1)(t - 20) factored the equation
t = -1/4 t = 20 Applied Zero Product Property and solved for t
Since we know time cannot be negative, disregard t = -1/4
The only valid solution is: t = 20
I need help on this problem step by step:) It would help me a lot
Answer:
8x+7
Step-by-step explanation:
follow through the step by step, I will post a proof if you want.
what is the solution to the division problem below? (you can use long division or synthetic division.) PLEASE ANSWER
Answer: C
Step-by-step explanation: A P E X
Evaluate cosθ if sinθ = sqrt5/3
Answer:
2/3
Step-by-step explanation:
sinθ is opposite/hypotenuse (soh cah toa)
If given what sinθ is, you have the opposite leg to θ and the hypotenuse. It helps to draw a triangle. You can figure out the adjacent leg using the pythagorean theorem. [tex]3^{2}[/tex]-[tex](\sqrt{5} )^{2}[/tex] = 4
Square root 4 to find the adjacent leg, 2.
To find cosθ, which is adjacent over hypotenuse, substitute in the respective numbers, which gives you 2/3.
