Answer:
816
Explanation:
We must remember that torque is defined as the product of a force by a distance.
This distance is measured from the pivot point of the Bolt to the point where the force is applied. in this way, we have the following equation to be able to determine the torque.
[tex]T=F*d[/tex]
Now if we double the turning distance we have the torque should also be double.
[tex]T =F*2*d[/tex]
what is the initial position of the object?
a. 2m b. 4m c. 6m d. 8m e. 10 m
what is the velocity of the object?
a. -10 m/s b. -5 m/s c. 0 m/s d. 5 m/s e. 10 m/s
which of the following is true?
a. the object increase its velocity.
b. the object decrease its velocity.
c. the objects velocity stays unchanged.
d. the object stays at rest.
e. more information is required.
Answer:
(e)10m (b)-5m/s (b)the object decreases its velocity
Explanation:
-5m/s you get this ans since the gradient of the graph is equal to the bodies velocity
Answer:(e)10m (b)-5m/s (b)the object decreases its velocity
Explanation:
The most cost effective solution to energy shortages is energy
conservation.
What are Newton’s 3 laws of motion?
Answer: It states that for every action, there is an equal and opposite reaction.
I hope this helps, and Happy Holidays! :)
A horizontal spring has a spring constant of 2.00 N/m. One end of the spring is attached to a fixed wall. A mass of 0.200 kilograms is attached to the free end of the spring and the spring is compressed by 0.500 meters from its natural length. The mass is released. What is the speed of the mass when the spring returns to its natural length?
a. 2.24 m/s
b. 2.50 m/s
c. 5.00 m/s
d. 1.58 m/s
Answer:
(D) the speed of the mass when the spring returns to its natural length is 1.58 m/s.
Explanation:
Given;
spring constant of the spring, k = 2 N/m
mass attached to the spring, m = 0.2 kg
compression of the spring, x = 0.5 m
Apply the principle of conservation of mechanical energy;
K.E = P.E
¹/₂m(v² - u²) = ¹/₂kx²
where;
u is the initial speed of the mass = 0
¹/₂mv² = ¹/₂kx²
mv² = kx²
[tex]v^2= \frac{kx^2}{m} \\\\v= \sqrt{\frac{kx^2}{m}} \\\\v = \sqrt{\frac{(2)(0.5)^2}{0.2}} \\\\v = 1.58 \ m/s[/tex]
Therefore, the speed of the mass when the spring returns to its natural length is 1.58 m/s.
An observer sitting on shore sees a canoe traveling 5.0 m/s east, and a sailboat traveling 15.0 m/s west. What is the velocity of the sailboat as observed on the canoe (relative to the canoe)?
Answer:
Vs/c = 20 [m/s]
Explanation:
This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.
We are asked for the velocity of the sailboat with respect to an observer located in the canoe.
[tex]V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s][/tex]
Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.
The substance that is formed in a chemical reaction is called the
Answer:
The substance formed is the product. A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.
Answer:
product
Explanation:
educere
If your heart is beating at 76.0 beats per minute, what is the frequency of your heart's oscillations in hertz?A) 3.98 HzB) 4560 HzC) 2.54 HzD) 1450 HzE) 1.27 Hz
Answer:
E) 1.27 Hz
Explanation:
If the heart beats 76 times in a minute, this means that the time needed for a single beat (the period of the oscillation), is just 1/76 of a minute, as follows:[tex]T = \frac{1}{76} min = 0.013 min = 0.79 sec. (1)[/tex]
The frequency of the oscillation, by definition, is just the inverse of the period T, as follows:[tex]f = \frac{1}{T} = \frac{1}{.79sec} = 1.27 Hz (2)[/tex]
The right answer is the E).What is the relationship between kinetic and potential energy of a falling object
Answer:
See the explanation below.
Explanation:
According to the law of energy conservation. This can be transformed from potential energy to kinetic or vice versa.
For example, when you have a body at rest at a height with respect to the ground level, this body possesses potential energy with respect to the ground, but the moment that the body falls the potential energy decreases as it loses height with respect to the ground, but as the potential energy decreases, the kinetic energy increases, that is to say, the potential energy is transformed into kinetic energy as the body is falling.
As the energy relationship is maintained we can say that the potential and kinetic energies are equal.
[tex]E_{pot}=m*g*h\\E_{kin}=\frac{1}{2} *m*v^{2} \\E_{pot}=E_{kin}[/tex]
If you take a trip from Earth (g = -9.8 m/s2) to Pluto (g = -0.6 m/s2) what would happen to your mass and weight?
A. your mass would stay the same and your weight would stay the same
B. your mass would decrease and your weight would decrease
C. your mass would decrease and your weight would stay the same
D. your mass would stay the same and your weight would decrease
A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km. What is the frequency of the waves in such a tsunami?A. 6.8 HzB. 0.93 HzC. 0.00026 HzD. 1.1 HzE. 0.15 Hz
Answer:
C) 0.00026 Hz
Explanation:
In any wave, there exists a fixed relationship between the speed v, the frequency f and the wavelength λ, as follows:[tex]v = \lambda * f (1)[/tex]
Replacing by the givens in (1), and solving for f, we get:[tex]f = \frac{v}{\lambda} = \frac{700km/hr}{750 km} = 0.93 1/hr (2)[/tex]
Converting the units to Hz (1/sec), we get:[tex]f = 0.93 \frac{1}{hr} *\frac{1 hr}{3600sec} = 2.6e-4 = 0.00026 Hz (2)[/tex]
The answer C. is the right one.A 3-kg toy cart is moving at 4 m/s. Calculate the kinetic energy of this cart if it were moving TWICE as fast.
Answer:
96 J
Explanation:
KE = (1/2) mv^2
m= 3kg
v= 4 m/s
(We have to calculate the KE of the cart when it is moving twice as fast, so 4x2=8, v=8m/s.)
KE = (1/2)(3kg)(8^2) = 96J
The kinetic energy of the cart moving with twice speed is 96 Joules.
Kinetic EnergyThe kinetic energy of an object of mass m and velocity v is given below.
[tex]KE = \dfrac {1}{2}mv^2[/tex]
Given that the mass of the toy is 3 kg and velocity is 4 m/s. The kinetic energy of the cart which is moving twice its original speed is given below.
[tex]KE = \dfrac {1}{2}m\times (2v)^2[/tex]
[tex]KE = \dfrac {1}{2}\times 3\times (2\times 4)^2[/tex]
[tex]KE = 96 \;\rm J.[/tex]
Hence we can conclude that the kinetic energy of the cart moving with twice speed is 96 Joules.
To know more about kinetic energy, follow the link given below.
https://brainly.com/question/999862.
On an alien planet, a simple pendulum of length 0.400 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Express your answer with the appropriate units.
Answer:
1.269 s
Explanation:
The period of oscillation of a simple pendulum is given or expressed with the following relationship
T = 2π√(L/g), where
T is the period of the said pendulum, ?
L is the length of string of the pendulum, 0.4 m
g is the acceleration due to gravity, 9.81 m/s²
On applying the values into the formula, we have
T = 2 * 3.142 * √(0.4/9.81)
T = 6.284 * √0.04077
T = 6.284 * 0.202
T = 1.269 s
Therefore, the period of the pendulum is 1.269 s
The size, shape, and color of an object would be an example of a
O physical change
O physical property
O chemical change
chemical property
Answer:
physical change
Explanation:
its only changing things you see.
According to Steinberg, which of the following statements is true about creative people
They appreciate art and music.
They always take popular stands.
They accept ideas at fàce value.
They accept their limitations,
A 1 200-kg automobile moving at 25 m/s has the brakes applied with a deceleration of 8.0 m/s2. How far does the car travel before it stops?
Answer:
Δx = 39.1 m
Explanation:
Assuming that deceleration keeps constant during the braking process, we can use one of the kinematics equations, as follows:[tex]v_{f} ^{2} - v_{o} ^{2} = 2* a * \Delta x (1)[/tex]
where vf is the final velocity (0 in our case), v₀ is the initial velocity
(25 m/s), a is the acceleration (-8.0 m/s²), and Δx is the distance
traveled since the brakes are applied.
Solving (1) for Δx, we have:[tex]\Delta x = \frac{-v_{o} ^{2} }{2*a} = \frac{-(25m/s)^{2}}{2*(-8.0m/s2} = 39.1 m (2)[/tex]
The car will travel a distance of 39.1 m before its stops.
To solve the problem above, use the equations of motion below.
Equation:
v² = u²+2as................... Equation 1Where:
v = final velocity of the automobileu = initial velocity of the automobilea = accelerations = distance coveredFrom the question,
Given:
v = 0 m/s (before its stops)u = 25 m/sa = -8 m/s² (decelerating)Substitute these values into equation 1
⇒ 0² = 25²+2(-8)(s)Solve for s
⇒ 0²-25² = -16s⇒ -16s = -625⇒ s = -625/16⇒ s = 39.1 mHence, The car will travel a distance of 39.1 m before its stops.
Learn more about acceleration here: https://brainly.com/question/605631
A tennis ball moving at a speed of 4 m/s, collides with a bowling ball at rest. The tennis ball bounces back in the direction opposite to the initial velocity, and the bowling ball moves very slowly too. Which object experiences the greater magnitude impulse during the collision? The bowling ball Neither, both experienced the same magnitude impulse It's impossible to tell none of these The tennis ball
Answer:
Both experienced the same magnitude impulse
Explanation:
This is because, the impulse force is internal to the system of both the tennis ball and the bowling ball. It is an action-reaction pair. So, the force exerted on the tennis ball by the bowling ball equals in magnitude to the force exerted by the tennis ball on the bowling ball although, they are in opposite directions. This, both experienced the same magnitude impulse.
At an amusemlec 27 collisions and powerent park, a 96.0 kg car moving with a speed v bounces elastically off a 135-kg bumper car at rest. If the final speed of the 135-kg car is 1.03 m/s, what is the initial speed of the 96.0-kg car?
By conservation of momentum :
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2\\\\96v + 0 = 96v_1 + 135\times 1.03\\\\96v = 96v_1 +139.05 \ \ \ \ \ \ .....1[/tex]
By conservation of energy :
[tex]\dfrac{m_1u_1^2}{2}+\dfrac{m_1u_2^2}{2} =\dfrac{m_2v_1^2}{2} +\dfrac{m_2v_2^2}{2}\\\\96v^2 + 0 = 96v_1^2 + 135(1.03)^2\\\\96v^2 = 96v_1^2 +143.22 \ \ \ \ \ ....2)[/tex]
Solving equation 1 and 2, we get :
v = 1.23 m/s
Therefore, the initial speed of 96 kg car is 1.23 m/s .
Given f(x)=-2x+7, which of the following is the value of x when f(x)=13?
3
-19
-10
-3
Answer:
-19 is the answer because put the value of x=13 then make equation
During an experiment, Ellie records a measurement of 25,000 m. How would she write her
measurement in scientific notation?
O 2.5 x 10^2 m
O 2.5 x 10^3 m
0 2.5 x 10^5 m
O 2.5 x 10^4.m
Answer:
D. 2.5 x 10^4
Explanation:
10 to the power of 4 is 10,000.
10,000 x 2.5 = 25,000
D. 2.5 x 10⁴ is the scientific notation of Ellie records.
What is scientific notation?Scientific Notation is the expression of a number n in the form a∗10ᵇ. where a is an integer such that 1≤|a|<10. and b is an integer too. It is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.
According to the question,
The given number is 25,000 m
i.e.
25 x 10³
Since we have to put the decimal between 2 and 5
It becomes,
2.5 x 10⁴
or
10 to the power of 4 is 10,000.
10,000 x 2.5 = 25,000
Therefore,
The answer is 2.25 x 10⁻⁶ M
Learn more about Scientific notation here:
https://brainly.com/question/18073768
#SPJ2
A ball rolls of buildings that is 100m high calculate the time that it takes for ball to hit the ground
Answer:
2as=v2-u2
2000=v2
V=44
V=u+at
44/10=t
T=4.4seconds
When a coil is carrying a current of 25.0 A that is increasing at 145 A/s the induced emf in the coil has magnitude 3.70 mV.
A. Find the self-inductance of the coil.
B. Find the magnitude of the induced emf at t = 2.00 s if the current is i(t) = (225 A/s)t2.
Answer:
a) 25.5 µH
b) 22.95 mV
Explanation:
Induced emf in a inductor is given by
E = L * di/dt, where
E is the voltage of the circuit
L is the inductance of the circuit
di/dt if the rate of inductance
A
So we have
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
B
i(t) = 225t²
Recall that
E = L * di/dt, so that
E = 25.5 µH * |225t²|
Differentiating with respect to t, we have
E = 25.5 * 2 * 225t
E = 25.5 * 450t
Solving for t = 2,we get
E = 25.5 * 450(2)
E = 25.5 * 900
E = 22950 µV or
E = 22.95 mV
Bonnie and Clyde are trying to steal the world's largest diamond from a 10 story
building. Bonnie needs to make a landing spot for when Clyde jumps with the
diamond. She knows they will be jumping from 58 feet. Neglecting air resistance,
what is the speed Clyde will be falling at right before hitting the ground?
Answer:
The speed Clyde will be falling at is 33.72.
What causes a compass needle to point to geographic north?
a. The force of Earth's rotation causes the needle of the compass to seek the north pole.
b. The pole of the compass is attracted to Earth's Geographic North Pole.
Selected:c. The compass needle aligns with Earth's magnetic field.
d. all of the answer choices are correct
1+1=?
FIRST ONE TO ANSWER GETS BRAINLIEST!
Answer:
Thx for points merry Christmas answer 2
Explanation:
Answer:2
Explanation:
A rock is at the top of a 20 meter tall hill. The rock has a mass of 10 kg. How much potential energy does it have?
Answer:
1960 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
PE = 10 × 9.8 × 20
We have the final answer as
1960 JHope this helps you
Help me please..
Velocity is defined as a
and a?
A) speed, direction
B) change, direction
C) speed, acceleration
D) change, acceleration
Answer:
Speed and direction.....
32. Which type of electromagnetic wave is used for nuclear power and medical treatment?
A. UV wave
B.Radio wave
C.Visible light wave
D. Gamma ray
Which of the following is a way that microwaves and x-rays are similar?
A. They both have technological uses.
B. They are both high energy waves,
C. They are both safe to be exposed to at high doses
D. They are both used to transmit information.
Answer:
Answers at the bottom!!
Explanation:
For the first answer: Gamma ray
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
For the second answer: They both have technological uses.
In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.
Hope this helps!!
Happy Holidays and Season Greeting!!
ii Feliz Navidad a todos !!
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
What are gamma rays ?"A gamma ray (g) is a packet of electromagnetic energy (photon) emitted by the nucleus of some radionuclides following radioactive decay." Gamma photons are the most energetic photons in the electromagnetic spectrum.
What are x-rays ?"An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation." Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 145 eV to 124 keV.
Know more about gamma rays here
https://brainly.com/question/23281551
# SPJ2
They both have technological uses.
Microwaves and x-rays have in common is all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other.
What is technological usage?
"The application of practical sciences to industry or commerce." The methods, theory, and practices governing such application. a highly developed technology. The total knowledge and skills available to any human society for industry, art, science, etc.
What are technological uses of microwave and x-ray ?Microwaves are used in spacecraft communication, and much of the world's data, TV, and telephone communications are transmitted long distances by microwaves between ground stations and communications satellites. Microwaves are also employed in microwave ovens and in radar technology.
They are used on such products as aircraft and rocket parts and structures, canned and packaged foods, electronics, semiconductors and microchips, thermal insulations, and automobile tires. Material processing technologies use X-ray systems to automatically control the density or thickness of layers of substances.
Know more about microwaves and x-rays here https://brainly.com/question/15708046
#SPJ2
If I can travel 20m in 18 seconds how far can I go in 10 minutes?
Answer:
36 s
Explanation:
20 m = 18 s
10 m = ?
20 × 18 = 360÷ 10
= 36 sec
A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg
An airplane wing is designed so that the speed of the air across the top of the wing is 297 m/s when the speed of the air below the wing is 209 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 26.0 m2?
Answer:
The value is [tex]F_L = 759200 \ N[/tex]
Explanation:
From the question we are told that
The speed of air across the top of its wings is [tex]v = 297 \ m/s[/tex]
The speed of air below its wings is [tex]u = 209 \ m/s[/tex]
The density of air is [tex]\rho = 1.29 \ kg/m^3[/tex]
The area of the wing is [tex]A = 26.0 \ m^2[/tex]
Generally the lifting force is mathematically represented as
[tex]F_L = \Delta P * A[/tex]
Here [tex]\Delta P[/tex] is the difference in kinetic energy density between the top and the bottom
[tex]\Delta P = \frac{1}{2} * \rho * [v^2 - u^2 ][/tex]
=> [tex]\Delta P = \frac{1}{2} * 1.29 * [297^2 - 209^2 ][/tex]
=> [tex]\Delta P = 2.92 *10^{4} \ Pa[/tex]
So
[tex]F_L = 2.92 *10^{4} * 26.0[/tex]
=> [tex]F_L = 759200 \ N[/tex]
