a roller coaster climbs up a hill at 4 m/s and then zips down the hill at 30 m/s. the momentum of the roller coasteris greater up the hill than down the hillis greater down the hill than up the hillremains the same throughout the rideis zero throughout the ride

Answers

Answer 1

The momentum of the roller coaster remains the same throughout the ride. Option c is correct.

Momentum is defined as the product of an object's mass and velocity. In this case, the roller coaster has a certain mass and is moving at different velocities as it goes up and down the hill. However, momentum is a conserved quantity, meaning that the total momentum of the system (the roller coaster and the Earth) remains constant as long as no external forces act on it.

Therefore, even though the roller coaster is moving at different velocities up and down the hill, its momentum remains the same throughout the ride. This is because the increase in velocity down the hill is balanced by the decrease in velocity up the hill, and the roller coaster's mass remains constant. So, the correct answer is option (c): the momentum of the roller coaster remains the same throughout the ride.

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--The complete question is, A roller coaster climbs up a hill at 4 m/s and then zips down the hill at 30 m/s. The momentum of the roller coaster

a. is greater up the hill than down the hill

b. is greater down the hill than up the hill

c. remains the same throughout the ride

d. is zero throughout the ride--


Related Questions

A tuna saw a marlin swimming toward it at 1 meter per second. To avoid the marlin, the tuna swam southwest for 6.8seconds at a constant velocity. In that time, the tuna swam 17meters. What was the tuna's velocity?

Answers

The velocity of the tuna is 4.1 meters per second and During the 6.8 seconds that the tuna swims southwest, it covers a horizontal distance of 17 meters.

We can use the Pythagorean theorem to determine the velocity of the tuna. Let's say that the velocity of the tuna has two components: a horizontal component (vx) and a vertical component (vy).

Therefore, we can say that:

vx = 17 meters / 6.8 seconds

vx = 2.5 meters per second

Now, we need to find the vertical component of the velocity (vy). We know that the marlin is swimming directly toward the tuna, which means that its velocity is entirely in the north direction. Therefore, the tuna needs to swim directly south to avoid the marlin.

The angle between the direction of the tuna's velocity and the direction of the marlin's velocity is 45 degrees (since the tuna is swimming southwest). Using trigonometry, we can find the vertical component of the tuna's velocity:

sin(45) = vy / v

vy = v * sin(45)

where v is the magnitude of the tuna's velocity.

Now, we can use the Pythagorean theorem to find the magnitude of the tuna's velocity:

v^2 = vx^2 + vy^2

v^2 = (2.5 m/s)^2 + (v * sin(45))^2

Solving for v, we get:

v = 4.1 meters per second

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how many grams is a ml

Answers

Answer:

1 gram

Explanation:

hope this helps

How to make 41 f to c?

Answers

41 Fahrenheit to Celsius is 5 °C where Fahrenheit and Celsius are related in that they are both units of temperature measurement.

To convert from Fahrenheit (F) to Celsius (C), use the formula:

[tex]C = (F - 32) * 5/9[/tex]

Therefore, to convert 41 F to C, substitute F with 41 and solve for C:

[tex]C = (41 - 32) * 5/9[/tex]

C = 9 * 5/9

C = 5 °C

The calculation to convert from Fahrenheit to Celsius takes the Fahrenheit temperature, subtracts 32 from it, and then multiplies the result by 5/9. This conversion formula takes into account the difference between the two temperature scales, with farenheit being the higher temperature scale and Celsius being the lower temperature scale.

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Five balls move through the air. All five have the same size and shape. Air resistance is not negligible. Rank in order, from largest to smallest, the magnitudes of the accelerations a1 to a5. Some may be equal. Give your answer in the form 1>2=3>4>5 and explain your ranking. where Vy= velocity in the y-direction A1: 50 g, just released, Vy=0 A2: 100 g, just released, Vy=0 A3: 50 g, Vy= -20 m/s A4: 100 g, Vy= -20 m/s A5: 50 g, Vy= 20 m/s

Answers

The first two balls (A1 and A2), are just released, which means that their initial velocity is zero. The next two balls (A3 and A4), have the same mass but opposite velocities in the y-direction. The last ball (A5), has the same mass as A1 and A3, but its velocity is in the opposite direction to A3.

Resistance is a fundamental property of any material that determines its ability to oppose the flow of electric current. It is measured in units called ohms and denoted by the symbol "Ω". When a voltage is applied to a conductor, such as a wire or a circuit component, the current that flows through it is proportional to the voltage and inversely proportional to the resistance. This relationship is described by Ohm's Law, which states that the current through a conductor is equal to the voltage across it divided by its resistance.

Resistance is determined by the material properties of the conductor, including its dimensions, temperature, and the nature of the material itself. Conductors with high resistance, such as insulators, restrict the flow of electric current, while conductors with low resistance, such as metals, allow current to flow more freely. Resistance can also be affected by external factors such as light, pressure, and magnetic fields.

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QuestionWhat is the excess charge on a conducting sphere of radius R=0.15m if the potential of the sphere is 1500V and V=0 at infinity?A2.5μCB2.5nCC2.5mCD25nCMedium

Answers

The excess charge on a conducting sphere is 25nC.

What is a charge?

When matter is placed in an electromagnetic field, it creates a force due to its physical property known as electric charge. They can have a positive or negative charge (usually, by convention, carried by protons and electrons, respectively). Dissimilar charges attract and like charges repel. Neutral refers to objects that have no net electrical charge. Classical electrodynamics, the name given to our early understanding of charged particle interactions, can also be applied to problems that do not require consideration of quantum phenomena. Charge is a conserved property. That is, the net charge (the sum of the positive and negative charges of the isolated system) does not change. 

The excess charge of a conducting sphere can be determined using the sphere capacitance formula.

C = 4πε₀R

where C is the capacitance, ε₀ is the electrical constant, and R is the radius of the sphere.

The potential difference between a conducting sphere and infinity is given by the formula:

ΔV = V - V∞ = V

where V∞ is the potential at infinity, which in this case is zero.

The charge of a sphere can be calculated using the formula:

Q = CΔV 

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A rock thrown with speed 11.5m/s and launch angle 30.0?(above the horizontal) travels a horizontal distance of d = 20.0m before hitting the ground. From what height was the rock thrown? Use the value g = 9.810m/s2 for the free-fall acceleration.Find the height yi from which the rock was launched.

Answers

Answer:

The rock was launched from approximately [tex]8.23\; {\rm m}[/tex] above the ground. Assume that the air resistance on the rock is negligible.

Explanation:

It is given that the initial velocity [tex]u = 11.5\; {\rm m\cdot s^{-1}}[/tex] is at [tex]30^{\circ}[/tex] above the ground. Therefore:

Initial horizontal velocity would be:[tex]u_{x} = u\, \cos(30^{\circ}) = ((\sqrt{3}) / 2) \, (11.5)\; {\rm m \cdot s^{-1}} \approx 9.9593\; {\rm m\cdot s^{-1}}[/tex].Initial vertical velocity would be:[tex]u_{y} = u\, \sin(30^{\circ}) = (1 / 2) \, (11.5)\; {\rm m \cdot s^{-1}} = 5.75\; {\rm m\cdot s^{-1}}[/tex].

Under the assumptions, horizontal velocity would stay the same during the entire flight: [tex]v_{x} = u_{x} \approx 9.9593\; {\rm m\cdot s^{-1}}[/tex].

Since the rock travelled a horizontal distance of [tex]x_{x} = 20.0\; {\rm m}[/tex], the duration of the flight would be:

[tex]\begin{aligned}t &= \frac{x_{x}}{v_{x}} \approx \frac{20.0\; {\rm m}}{9.9593\; {\rm m\cdot s^{-1}}} \approx 2.0082\; {\rm s}\end{aligned}[/tex].

Also under the assumptions, vertical acceleration of the rock would be [tex]a_{y} = (-g) = (-9.810)\; {\rm m\cdot s^{-2}}[/tex] during the entire flight. (Negative since gravitational pull points towards the ground.)

Apply the SUVAT equation to find the vertical displacement [tex]x_{y}[/tex] of the rock (distance between where the rock was launched and where the rock landed):

[tex]\begin{aligned}x_{y} &= \frac{1}{2}\, a_{y}\, t^{2} + u_{y}\, t \\ &\approx \left(\frac{1}{2}\, (-9.810)\, (2.0082)^{2} + (5.75)\, (2.0082)\right)\; {\rm m} \\ &\approx (-8.23)\; {\rm m}\end{aligned}[/tex].

(Negative since the rock landed below where it was launched.)

In other words, the rock was launched from a height of approximately [tex]8.23\; {\rm m}[/tex].

Wind, water, and gravity, temperature changes, and pressure changes are all a cause of what process?
chemical weathering
physical weathering
biological weathering
acid weathering

Answers

When rock is eroded mechanically by forces like wind, water, gravity, freeze-thaw cycles, or root growth in the rock, this is known as physical weathering.

Why does gravity have a force?

However, as gravity defines the ensuing interaction between two masses, it is a force in the broadest sense. The deformation of spacetime and indeed the motion of things through the stretched spacetime are the primary causes of gravitational effects. It appears as though a force was exerted towards the end, though.

9.8 gravity is what unit?

Gravity's acceleration can be quantified as 9.8 m/s/s, which is the most precise figure. This number (to the second decimal place) has a few tiny changes, most of which are related to altitude.

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what is microliter to ml?

Answers

One microliter (µL) is equal to 0.001 milliliters (mL).

Both microliter and milliliter are units of volume used in the metric system. Microliter is a smaller unit and is equal to one millionth (10^-6) of a liter, while milliliter is a larger unit and is equal to one thousandth (0.001) of a liter.

Therefore, to convert the unit of measurements from microliters to milliliters, we divide the value in microliters by 1000 (or multiply the number by 0.001). For example, 500 microliters is equal to 0.5 milliliters (500/1000 = 0.5).

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A substance melts when it changes from a __________ to a __________. What are the missing words in this sentence?

Answers

A substance melts when it changes from a solid state to a liquid state.

The temperature at which a substance transforms from a solid to a liquid is known as the melting point. The temperature at which a substance changes from a liquid to a solid is known as the freezing point, which is the exact opposite of the melting point.

An impure solid often melts over a range of temperatures below the melting point of the primary component, whereas this process occurs in pure crystalline solids at a set temperature known as the melting point.

A solid's particles generate enough energy during heating to overcome the strong bonding forces holding them tightly together.

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a monatomic gas is adiabatically compressed to 0.125 of its initial volume. how do each of the following quantities change?

Answers

Since, A monotonic gas is adiabatically compressed to 0.125 of its initial volume. Therefore, the rms speed of the system is 0.25 while Mean free path is 0.5 times the first mean free path.

a. The following temperature and volume relationship holds for the adiabatic process:

[tex]TV^{\alpha -1}[/tex] = constant

Therefore,

[tex]T_1V_1^{\alpha -1} = T_2V_2^{\alpha -1}[/tex]

This yields

[tex]\frac{T_2}{T_1} = (\frac{V_1}{V_2} )^{2}[/tex]

In the equation , it is given that V₁/V₂ = 0.125

So, V₁/V₂ = 1/0.125

The adiabatic exponent for monoatomic gases is 0.66. So,

   T₂/T₁ = (0.125)⁰⁶⁶⁻¹

⇒ T₂/T₁ = (0.125)⁰°⁶⁵

⇒ T₂/T₁ = 0.25

As a result, the temperature rises by a factor of ten in this procedure 0.25 .We know that V(rms) is proportional to √T. so we have

[tex]\frac{V_rms_1}{V_rms_2}[/tex] = [tex]\sqrt{\frac{T_2}{T_1} }[/tex] = √0.25 = 0.5

i.e. The rms speed increases by a factor of 0.5.

b. The mean free path is given by in the book

λ = [tex]\frac{V}{4\sqrt{2}\pi Nr^{2} }[/tex]

where

r is The effective radius of the molecule,

V is the volume of the gas and

N is the number of molecules.

All quantities in the λ formula except volume are constant in this process.

Since, λ ∞ ∨ decreases by a factor of 0.5, also decreases by a factor of 0.5.

C. A monoatomic gas's thermal energy is given by

[tex]E_th[/tex] = [tex]_nC_vT[/tex]

Both the number of moles  n , and ,

the molar specific heat at constant volume [tex]C_v[/tex] are constant in this process so the only thing that changes is the temperature.

Since [tex]E_th[/tex] ∞ T since we have found that the temperature increases by a factor of 0.25 then [tex]E_th[/tex] also increases by a factor of 0.25 .

d. The molar specific heat of a monoatomic gas is just a constant equal to [tex]C_v =[/tex] 0.5R.

So, it doesn't change in this process.

Therefore,

The rms speed of the system is 0.25 while Mean free path is 0.5 times the first mean free path.

Complete Question:

A monatomic gas is adiabatically compressed to 0.125 of its initial volume. Do each of the following quantities change?

A) What is rms speed?

B) What is the mean free path?

C) What is the thermal energy of gas?

D) What is the molar specific at a constant volume?

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what produces keratin that starts the death of skin cells

Answers

Answer:

Keratinocytes are the predominant cell type of epidermis and originate in the basal layer, produce keratin, and are responsible for the formation of the epidermal water barrier by making and secreting lipids.

Answer:

Keratinocytes, which are cells in the epidermis, produce keratin, which helps create a protective barrier on the skin's outer layer [1]. As the keratinocytes produce keratin, they start to die, leading to the death of the skin cells.

What are the 5 main interactions of light with matter?

Answers

In the actual world, there are five primary types of interactions between light and matter. These are emission, scattering, reflection, absorption, and transmission.

What is the interaction of light with solid?

Maxwell's equations, which regard the solid as a continuum and result in its optical characteristics as a measure of the frequency of the electromagnetic energy: the complex dielectric constant, are used to explain the interaction of light with solids.

What happens as light and matter interact?

As light enters a material, transmission happens. As light moves across a medium, it may do so without being distorted or dispersed by the medium. When light transmits its energy to matter instead of being reflected nor transmitted by it, this is known as absorption of light.

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Alpha Centauri A lies at a distance of 4.4 light-years and has an apparent brightness in our night sky of 2.7 x 10^−8 Watts/m^2Recall that 1 light-year = 9.46 x 10^15 m.a) Use the inverse square law for light to calculate the luminosity of Alpha Centauri A, in Watts.b) Suppose you have a light bulb that emits 100 Watts of visible light (not true for a standard 100 W bulb, which emits most of its light in the infrared). How far away would you have to put the light bulb for it to have the same apparent brightness as Alpha Centauri A in our sky? (Hint: Use 100 Watts as luminosity L in the inverse square law for light, and use the apparent brightness given above for Alpha Centauri A. Then solve for the distance.)

Answers

The light bulb would have to be placed approximately 0.0613 light-years away from us to have the same apparent brightness as Alpha Centauri A in our sky.

a) The inverse square law for light states that the apparent brightness of a light source decreases with the square of the distance from the source. Therefore, we can use the following formula to calculate the luminosity of Alpha Centauri A:

Luminosity = 4π(distance)² × apparent brightness

where distance is the distance from Alpha Centauri A to Earth, which is 4.4 light-years or 4.4 × 9.46 × 10¹⁵ meters.

Substituting the values, we get:

Luminosity = 4π(4.4 × 9.46 × 10¹⁵)² × 2.7 × 10⁻⁸

= 3.85 × 10²⁶ Watts

Therefore, the luminosity of Alpha Centauri A is approximately 3.85 × 10²⁶ Watts.

b) We can use the inverse square law for light to calculate the distance at which a 100 Watt light bulb would have the same apparent brightness as Alpha Centauri A:

100 = Luminosity/4π(distance)² × apparent brightness

Substituting the values, we get:

distance = √(Luminosity/4π × apparent brightness × 100)

Using the value of luminosity and apparent brightness from part (a), we get:

distance = √(3.85 × 10²⁶/4π × 2.7 × 10⁻⁸ × 100)

= 5.80 × 10¹⁴ meters

Converting to light-years, we get:

distance = 5.80 × 10¹⁴/9.46 × 10¹⁵

= 0.0613 light-years

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What is the relationship between the potential difference across the generator and across the resistor?

Answers

Both the potential difference across a generator and that across a resistor obeys Ohms law. Greater the potential difference between two points, greater will be the current passing across the devices.

What is potential difference ?

The potential difference of across an object is the energy required to bring a point charge from infinity to a point. The unit of potential energy is volt and it also calling voltage of a device.

According to Ohm's law, the potential difference across a device is the product of the resistance and current passing through it.

V = IR.

In a generator the current is generated through electromagnetic induction. Here the resistance is developed across the armature of the generator. Hence, the overall potential difference like across a resistor depends on the resistance and current.

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You ride a roller coaster with a loop-the-loop.A) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the bottom of the loop. Express your answer in terms of R (radius of the loop), vb (speed at the bottom of the loop), and constant g.B) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the top of the loop. Express your answer in terms of R (radius of the loop), vt (speed at the top of the loop), and constant g.You ride a roller coaster with a loop-the-loop.A) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the bottom of the loop. Express your answer in terms of R (radius of the loop), vb (speed at the bottom of the loop), and constant g.Nbottommg =

Answers

A) At bottom Normal force is minimum, so: [tex]Nbottom = mvb^2/R - mg[/tex] B) At top Normal force is maximum, so: [tex]Ntop = mvt^2/R + mg[/tex]

A) When you are passing the bottom of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the bottom of the loop, the net force on you is equal to the force of gravity, and it acts towards the center of the loop, providing the centripetal force required to keep you moving in a circular path.

The normal force, N, is the force exerted by the seat on you, perpendicular to the surface of the seat. The force of gravity, mg, acts vertically downwards. Therefore, we can write:

[tex]Nbottom + mg = Fnet = mvb^2/R[/tex]

where R : radius of the loop and vb : speed at the bottom of the loop.

At the bottom of the loop, the normal force is at a minimum, and it is equal to:

[tex]Nbottom = mvb^2/R - mg[/tex]

B) When you are passing the top of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the top of the loop, the net force on you is again equal to the force of gravity, but it acts downwards, providing the centripetal force required to keep you moving in a circular path.

The normal force, N, is still perpendicular to the surface of the seat. The force of gravity, mg, acts vertically downwards. Therefore, we can write:

[tex]Ntop + mg = Fnet = mvt^2/R[/tex]

where vt : speed at the top of the loop.

At the top of the loop, the normal force is at a maximum, and it is equal to:

[tex]Ntop = mvt^2/R + mg[/tex]

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What is the direction of the electric field of a positive point charge?

Answers

Answer:

Explanation:

north

a physical property that describes the ability of a substance to be rolled or pounded into thin sheets​ is?

Answers

The physical property that describes the ability of a substance to be rolled or pounded into thin sheets is called Ductility.

Ductility is the ability of a material to deform under tensile stress, such that it can be drawn out into a thin wire or flattened into a thin sheet without breaking. This property is particularly important for metals, as it allows them to be easily shaped into useful forms like wires or foils, and also contributes to their overall strength and toughness. Materials with high ductility can withstand significant strain without fracturing, making them useful in many engineering applications. Conversely, materials with low ductility are more brittle and prone to fracture, which can limit their usefulness in certain applications.

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what quantity relates to the stiffness of a spring

Answers

The proportional constant k is called the spring constant. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.

What is Hookes Law?

The force a spring applies to items fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium. Consider a spring that has one end attached to a wall or ceiling and the other end being pulled or pushed by an object. The spring is pulled by the object, and the object is pulled by the spring. The spring applies a force F to the object that is in the opposite direction as the free end's displacement. The equilibrium point of the spring's free end is at x = 0, and if the x-axis of a coordinate system is selected to be parallel to the spring, then F = -kx.

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One mole of an ideal diatomic gas goes from a to c along the diagonal path in Fig. The scale of the vertical axis is set by pab​=5. 0 kPa and pc​=2. 0 kPa, and the scale of the horizontal axis is set by Vbc​=4. 0 m3 and Va​=2. 0 m3. During the transition,What is the change in internal energy of the gas

Answers

In internal energy of the gas −5.0×10 3J if  scale of the vertical axis is set by pab​=5. 0 kPa and pc​=2. 0 kPa. set by Vbc​=4. 0 m3 and Va​=2. 0 m3.

What is a energy in science?

Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.” Despite this confusing definition, its meaning is very simple: energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic.

What is energy in Example?

Energy exists in many different forms. Examples of these are: light energy, heat energy, mechanical energy, gravitational energy, electrical energy, sound energy, chemical energy, nuclear or atomic energy and so on.

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which particles in an atom are ‘light’ particles? ____________________________

Answers

The particles in an atom that are considered "light" are the electrons.

The three types of particles found in atoms are protons, neutrons, and electrons. Protons and neutrons are found in the nucleus of the atom, while electrons orbit around the nucleus in electron shells. Electrons are considered "light" particles because they have a much smaller mass than protons and neutrons.

Specifically, electrons have a mass of approximately 9.1 x 10^-31 kilograms, which is about 1/1836th the mass of a proton or neutron. This small mass makes electrons highly mobile and allows them to be involved in chemical reactions and electrical conductivity.

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54. 7 of HCl gas is dissolved to make 1L of solution what is the molarity of the solution

Answers

The molarity of the solution is 1.496 M.

To find the molarity of a solution, you need to use the formula Molarity = moles of solute / liters of solution.

First, you need to find the moles of solute (HCl gas) in the solution. You can do this by using the formula moles = mass / molar mass.

The molar mass of HCl gas is 36.5 g/mol.

So, the moles of HCl gas in the solution is:

moles = 54.7 g / 36.5 g/mol = 1.496 mol

Next, you need to find the liters of solution. The question states that there is 1L of solution, so this is already given to you.

Finally, you can plug in the values you found for moles of solute and liters of solution into the formula for molarity:

Molarity = 1.496 mol / 1 L = 1.496 M

So, the molarity of the solution is 1.496 M.

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if a satellite is in orbit around jupiter and an identical satellite is in orbit around the earth, which satellite would experience a greater attractive force?

Answers

Answer:

This is a somewhat difficult question:

the acceleration at the surface of Jupiter is about 26 m/s^2 while the acceleration at the surface of earth is 9.8 m/s^2 - however Jupiter has a density of only 1/4 that of earth while its diameter is about 11 times that of earth - one needs to consider the distance of the satellite from the center of rotation

Near the surface of each planet the acceleration of Jupiter would be greater, but Jupiter has most of its mass outside of this radius (of Earth)

M is proportional to R^3 so one can see that even tho density of Jupiter is less than that of Earth almost all of Jupiter's volume occurs at a radius greater that of Earth

F = K M m / R^2         describes the force of attraction on a mass m, but one needs to consider R and at the surface R is 11X greater for Jupiter  

What effect will a change in wind direction have upon maintaining a 3° glide slope at a constant true airspeed?

Answers

A change in wind direction will not have a significant effect on maintaining a 3° glide slope at a constant true airspeed, but it may require some minor adjustments in heading or pitch to compensate for any deviations caused by the wind.

A change in wind direction will have an effect on maintaining a 3° glide slope at a constant true airspeed. The glide slope is determined by the vertical and horizontal components of the aircraft's velocity. If there is a crosswind, it will cause the aircraft to drift off course, which could lead to a deviation from the desired glide slope. The pilot will have to adjust the aircraft's heading to compensate for the crosswind and maintain the desired glide slope.

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What does 35.5 Celsius mean in Fahrenheit?

Answers

In Fahrenheit, 35.5 degrees Celsius is equivalent to 127.9 degrees.

Use the formula below for the convert 35.5 degrees Celsius to Fahrenheit:

°F = (°C x 1.8) + 32

The process of translating a temperature from one scale to another is referred to as temperature conversion. Temperature conversions between the several regularly used temperature scales, including Celsius, Fahrenheit, and Kelvin, are frequently required.

where the temperature is expressed in degrees Fahrenheit (°F) and degrees Celsius (°C).

Plugging in 35.5 degrees Celsius yields the following results:

°F = (35.5 x 1.8) + 32 °F

=> 95.9 + 32 °F

=> 127.9

As a result, 35.5 Celsius is equivalent to 127.9 Fahrenheit.

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Disturbance that transfers energy from one place to another
wave
energy
vacuums

Answers

An interruption known as a wave is one that shifts matter-free energy from one location to another.

How does Wave operate?

Wave also lets you create and maintain client profiles, issue receipts, follow-up emails, and payment reminders. In order to issue invoices and monitor payments, it also provides a mobile app just for invoicing.

How does Wave payment work?

Businesses may collect payments online, send invoices to clients via email, and keep track of revenue with the help of Wave Payments, a digital payment processing & invoicing tool. Small businesses can afford it since it's free and just levies processing costs.

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Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round your answer to the nearest whole number.

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It requires 9600 joules of work to get the wheelbarrow across the yard in 12 seconds. Rounded to the nearest whole number, the answer is 9600 J.

How is power related to work and time?

Power is the rate at which work is done or energy is transferred, and it is measured in watts (W). Work is the amount of energy required to move an object, and it is measured in joules (J). Time is the duration over which work is done, and it is measured in seconds (s). Power is calculated by dividing the amount of work done by the time taken to do it, or by multiplying force by velocity. Mathematically, we can represent the relationship between power, work, and time as: Power = Work / Time

We can use the formula: Work = Power x Time

To find the work required, we can plug in the given values:

Work = 800 W x 12 s

Work = 9600 J

Therefore, it requires 9600 joules of work to get the wheelbarrow across the yard in 12 seconds. Rounded to the nearest whole number, the answer is 9600 J.

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which is not used to determine the relative age of a rock? A. radioactive decay. B. law of superposition. C. core rock samples.

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Answer is C) Core rock samples while radioactive decay and the law of superposition are commonly used methods for this purpose.

Determining the relative age of a rock is the process of placing rocks in a sequential order based on their ages, without assigning numerical ages to them. There are various methods used to determine the relative age of a rock, including radioactive decay and the law of superposition.

Radioactive decay is the process by which unstable isotopes decay and transform into a stable isotope, releasing energy and particles in the process. By measuring the ratio of unstable isotopes to stable isotopes in a rock, scientists can estimate the age of the rock.

The law of superposition is the principle that in a sequence of sedimentary rock layers, the oldest layer is at the bottom, and the youngest layer is at the top. By analyzing the sequence of rock layers, scientists can determine the relative age of a rock.

In contrast, core rock samples are used to extract and study the composition of rocks. Core samples can provide detailed information about the mineralogy, texture, and structure of rocks, but they do not directly provide information about the relative age of a rock. However, core samples can be used in conjunction with other methods, such as radioactive dating, to obtain a more accurate estimate of the age of a rock.

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Rank the forms of light from left to right in order of increasing frequency. To rank items as equivalent, overlap them.

Options: gamma rays, X-rays, ultraviolet, visible light, infrared, radio waves.

Lowest frequency.

(1. ) radio waves.

(2. ) infrared.

(3. ) visible light.

(4. ) ultraviolet.

(5. ) X-rays.

(6. ) gamma rays.

Highest frequency

Answers

The correct ranking of the forms of light from left to right in order of increasing frequency is:

Lowest frequency:

(1) Radio waves

(2) Infrared

(3) Visible light

(4) Ultraviolet

(5) X-rays

(6) Gamma rays

What is frequency?

It is usually measured in hertz (Hz), which represents one cycle per second. The higher the frequency of a wave, the more cycles it completes per unit of time, and the shorter its wavelength. Frequency is an important concept in many branches of physics, including electromagnetism, quantum mechanics, and wave mechanics. It is used to describe a wide range of phenomena, such as the vibrations of musical instruments, the electromagnetic radiation emitted by light sources, and the behavior of subatomic particles.

Frequency is a fundamental concept in wave mechanics, which is the study of the behavior of waves. Waves are defined as disturbances that propagate through space and time, carrying energy and momentum with them. Examples of waves include electromagnetic waves (such as light and radio waves), sound waves, and water waves. In all cases, the frequency of a wave determines many of its properties, including its energy, wavelength, and period.

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A block of mass 0.2 kg is launched by a spring k1 = 2.0 N/m as shown below. The block moves along a frictionless horizontal table and pushes another spring, k2 = 1.1 N/m , to the maximum deflection x . If the initial deflection of the spring k1 is 0.050 m , what is the maximum deflection of spring k2 ?

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Please mark brainliest if the answer is true

We can use conservation of mechanical energy to solve this problem. At the point where the block is launched from the spring, all the energy is in the form of potential energy stored in the spring. When the block reaches the maximum deflection x of spring k2, all the energy is in the form of potential energy stored in spring k2.

The potential energy stored in a spring is given by U = (1/2) k x^2, where k is the spring constant and x is the deflection from the equilibrium position.

At the initial point, the potential energy stored in spring k1 is:

U1 = (1/2) k1 x1^2
= (1/2) (2.0 N/m) (0.050 m)^2
= 0.000125 J

At the point where the block reaches the maximum deflection x of spring k2, the potential energy stored in spring k2 is:

U2 = (1/2) k2 x^2

Conservation of energy tells us that the potential energy at the two points must be equal:

U1 = U2

Substituting in the values for U1 and k2, we get:

0.000125 J = (1/2) (1.1 N/m) x^2

Solving for x, we get:

x^2 = (0.000125 J) / (0.55 N/m)
x^2 = 0.0002273
x = 0.0151 m

Therefore, the maximum deflection of spring k2 is 0.0151 m.

The maximum deflection of the spring k2 is approximately 0.31 m.

What is spring constant?

The spring constant, k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.

To solve this problem, we can use conservation of energy and Hooke's law.

1/2 k1 x[tex]1^2[/tex] = 1/2 m [tex]v^2[/tex]

v = [tex](2 k1 x1 / m)^{0.5[/tex] = [tex](2 x 2.0 N/m x 0.050 m / 0.2 kg)^{0.5[/tex] ≈ 0.5 m/s

1/2 m [tex]v^2[/tex] = 1/2 k2 [tex]x^2[/tex]

x = [tex](m v^2/ k2)^{0.5[/tex] =[tex](0.2 kg x (0.5 m/s)^2 / 1.1 N/m)^{0.5[/tex] ≈ 0.31 m

Therefore, the maximum deflection of the spring k2 is approximately 0.31 m.

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Occasionally when walking across carpet in socks your socks seem to collect
"static.
This static build up really occurs when charges from the carpet are transterred to your socks by friction). What would the approximate order of magnitude be of the amount of charge collected by your socks in such a
situation?
A. 103 c
B. 1.0 C
C 10-3 c
D 10-8 с
E 10-12 ~

Answers

The approximate order of magnitude of the amount of charge collected by socks when walking across carpet in socks would be in the range of 10^-8 C (Option D) to 10^-12 C (Option E).

The amount of charge generated by friction between socks and carpet is typically very small, on the order of microcoulombs or even picocoulombs. This is because the charge generated by friction is proportional to the amount of surface area in contact and the strength of the electric field in the region.

Therefore, option D (10^-8 C) and option E (10^-12 C) are the most likely orders of magnitude for the amount of charge collected by socks in such a situation. Option A (10^3 C) and option B (1.0 C) are far too high, while option C (10^-3 C) is too low.

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--The complete answer is, Occasionally when walking across carpet in socks your socks seem to collect "static". This static build up really occurs when charges from the carpet are transferred to your socks by friction). What would the approximate order of magnitude be of the amount of charge collected by your socks in such a situation?

A. 10^3 C

B. 1.0 C

C 10^-3 C

D 10^-8 C

E 10^-12 C--

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