A toy car rolls down a straight inclined track and its speed increases steadily. At the moment when the car reaches the flat surface at the base of the track, its speed remains constant. Which statement best explains why the speed of the car remains the same when it reaches the flat surface

Answers

Answer 1

Answer:

Due to same gravity.

Explanation:

The speed of the car remains the same when it reaches on the flat surface because the gravity is same at every step of flat surface while on the other hand, the speed of car speed increases steadily on the inclined plane due to gravity of the earth. So we can say that speed of the car remains the same on the flat surface due to same gravitational force.


Related Questions

Without using the Gizmo, use your equation to calculate the acceleration of a puck that is in uniform circular motion with a radius of 3.0 m and a velocity of 9.0 m/s:___________.

Answers

Answer:

the centripetal acceleration of the puck is 27 m/s²

Explanation:

Given;

radius of the circular path, r = 3.0 m

velocity of the puck in the circular motion, v = 9.0 m/s

The centripetal acceleration of the puck is calculated as;

[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{(9)^2}{3} \\\\a_c = 27 \ m/s^2[/tex]

Therefore, the centripetal acceleration of the puck is 27 m/s²

If you exert a force of 10.N to lift a box over 1 m how much work do you do?

5
20
10

Answers

Answer:

The work done is 10 Joules

Explanation:

Mechanical Work

It is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being  the force vector and  the displacement vector, the work is calculated as:

[tex]W=\vec F\cdot \vec s[/tex]

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

If a force of F=10 N is used to lift a box over a distance of s=1 m, the work done is:

W = 10 N * 1 m

W = 10 J

The work done is 10 Joules

A 4.5-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ.

Answers

Answer:

The electrical energy is 13.5 kWh or 48600 kJ

Explanation:

Given that,

The power of the resistance heater, P = 4.5 kW

The water heater runs for 3 hours to raise the water temperature to the desired level.

We need to find the amount of electric energy used in both kWh and kJ.

Energy = Power × time

E = 4.5 kW × 3 h

= 13.5 kWh

Since,

1 kWh = 3600 kJ

13.5 kWh = 48600 kJ

Hence, the required electrical energy is 13.5 kWh or 48600 kJ

Popeye, of mass 75.0 kg, has just downed a can of spinach. He accelerates quickly and stops Bluto, of mass 720 kg (Bluto is very dense), who is charging in at 15.0 m/s. What was Popeye's speed

Answers

Answer:

Popeye's speed is 144 m/s.

Explanation:

Given;

mass of Popeye, m₁ = 75 kg

mass of Bluto, m₂ = 720 kg

velocity of Bluto, v₂ = 15 m/a

velocity of Popeye, v₁ = ?

Apply the principle of conservation of linear momentum;

m₁v₁ = m₂v₂

v₁ = (m₂v₂) / m₁

[tex]v_1 = \frac{720\ \times \ 15}{75} \\\\v_1 = 144 \ m/s[/tex]

Therefore, Popeye's speed is 144 m/s.

A dragster going at 15 m/s increases its velocity to 25 m/s in in 2 seconds. What is its acceleration?

Answers

Answer:

5m/s²

Explanation:

Given parameters:

Initial velocity  = 15m/s

Final velocity  = 25m/s

Time taken  = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time taken. It is mathematically expressed as;

      Acceleration  = [tex]\frac{Final velocity - Initial velocity }{Time taken }[/tex]  

    Acceleration  = [tex]\frac{25 - 15}{2}[/tex]   = 5m/s²

1. A 20.0 kg weight is hanging from a rope. What is the force of tension on the rope?

Answers

Explanation:

The tension on an object is equal to the mass of the object x gravitational force plus/minus the mass x acceleration. Tension Formula Questions: 1) There is a 5 kg mass hanging from a rope.

A tank is is half full of oil that has a density of 900kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 for g and 3.14 for . Round your answer to three significant digits.)

Answers

Image of the tank has been attached.

From online sources, we will use radius r = 9 meters with a spout of height h = 3 meters.

Answer:

W = 75800 KJ

Explanation:

Let's assume that we inscribe a cylinder which is x units from the center of the sphere and also has a height denoted by ∆x.

Now, At the center of the sphere with radius r, the equation of the sphere is given as:

x² + y² + z² = r².

Now, at the point location where the cylinder is x units from the center point, the width(y) of the sphere will be gotten as:

0² + y² + x² = 9²

y² + x² = 81

y² = 81 - x²

Thus;

y = √(81 - x²)

So y = r is the radius of the cylinder.

Thus; volume of the cylinder is given as:

V = πr²h

∆V = π(81 - x²)∆x

Integrating, we have;

V = π(81 - x²)

The weight of the water is given as:

F = mg

We know that density is;

ρ = m/V

So, m = ρV

Thus;

F = ρVg

F = (900)[π(81 - x²)](9.8)

F = 8820π(81 - x²)

Work needed to move this water up is;

W = Fd

The water will move up x to units to the center which is 9 units up to the top of the sphere, and 3 units to get to the top of the spout. Thus, d = 9 + 3 + x = 12 + x

Thus;

W = 8820π(81 - x²)(12 + x).

Due to the fact that x varies from -9 to 0 at the bottom half of the sphere, the required work will be;:

W = ∫8820π(81 - x²)(9 + x)dx (from x = -9 to 0)

Using online integral calculator, we have;

W = 8820π × 2733.75

W = 75749.061 KJ

To 3 significant figures = 75800 KJ

which terms correctly represent a vector quantity and its respective unit

Answers

Answer:

Explanation:

The best terms that represent vector quantity are magnitude and direction. Magnitude and direction are both qualities in vector quantity. The basic measurement of vector quantity is the meter all others would best be described as scalars. So to best describe vector quantity use the meter uni

A 3.50-g bullet has a muzzle velocity of 250 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed of the rifle. m/s (b) If a marksman with a weight of 650 N holds the rifle firmly against his shoulder, determine the recoil speed of the shooter and rifle.

Answers

Answer:

(a) 0.343 m/s

(b) 0.012 m/s

Explanation:

(a) From the question above,

MV = mv............................... Equation 1

Where M = mass of the rifle, V = recoiling speed of the rifle, m = mass of the bullet, v = velocity of the bullet.

make V the subject of the equation

V = mv/M........................... Equation 2

Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg.

Substitute into equation 2

V = (0.0035×250)/2.55

V = 0.343 m/s.

(b) Similarly,

(M'+M)V' = mv....................... Equation 3

Where M' = mass of the marksman, V' = recoiling speed of the shooter and rifle

make V' the subject of the equation

V' = mv/(M'+M)................... Equation 4

Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg, M' = 650 N = 650/9.8 = 66.33 N

Substitute into equation 4

V' = (0.0035×250)/(66.33+2.55)

V' = 0.8125/68.88

V' = 0.012 m/s

The recoil velocity can be obtained using the principle of conservation of linear momentum.

Using the principle of conservation of linear momentum;

momentum before collision = momentum after collision

Mass of the bullet = 3.50-g or 0.0035 Kg

Mass of the rifle = 2.5 Kg

Where;

M1 = mass of rifle

M2 = mass of bullet

u1 =initial velocity of rife

u2 = initial velocity of the bullet

(2.5 × 0) + (0.0035 × 250) = (0.0035 × 0) + (2.5 × v)

0.875 = 2.5 v

v = 0.35 m/s

For the shooter and the rifle;

(67.5 × 0) + (0.0035 × 250) =  (0.0035 × 0) + (67.5 × v)

0.875 = 67.5 × v

v = 0.013 m/s

Learn more about momentum: https://brainly.com/question/904448

can i eat air? im hungry

Answers

Answer:

Yes

Explanation:

A sprinter accelerates at 7.5 m/s from rest in 2.0 s, what distance did she go? (15 m)
Proof please

Answers

Answer:

The sprinter traveled a distance of 7.5 m

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the rate of change of the velocity of an object is constant.

The equation that rules the change of velocities is:

[tex]v_f=v_o+at\qquad\qquad [1][/tex]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]

Using the equation [1] we can solve for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:

[tex]\displaystyle a=\frac{7.5-0}{2}[/tex]

[tex]a=3.75\ m/s^2[/tex]

Now calculate the distance:

[tex]\displaystyle x=0*2+\frac{3.75*2^2}{2}[/tex]

[tex]\displaystyle x=7.5\ m[/tex]

The sprinter traveled a distance of 7.5 m

What is buoyancy? How is it related to the force of gravity?

Answers

Answer:

buoyancy is the ability to float on water or other liquids. this relates to the force of gravity because the stronger that force, the more likely it is to sink.

Explanation:

Tim’s cow is anemic. The cow is lacking which type of nutrient?

Answers

Answer:

Iron deficiency

Explanation:

or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.

The answer is Iron deficiency

6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged

Answers

Answer:

The percentage of the submerged wood is 13%.

Explanation:

Given;

density of the Balsa wood, [tex]\rho _{wood}[/tex]  = 130 kg/m³

density of pure water, [tex]\rho_{water}[/tex] = 1000 kg/m³

The percentage of the submerged wood is calculated as;

[tex]Percentage \ of \ submerged \ wood = \frac{130 \ kg/m^3}{1000 \ kg/m^3} \ \times \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%[/tex]

Therefore, the percentage of the submerged wood is 13%.

A problem says a car is initially driving 19.4 m/s due north. Which one of these tables includes that information correctly? ​

Answers

Answer: B

Explanation: because x is 19.4 and then the y is m/s north

Kate must do 39 days of training each year as a naval reservist. How will she serve that time?
A.
one month plus one week
B.
three weeks in the summer plus two in the winter
C.
one weekend per month plus two weeks
D.
two weeks in the spring plus three in the fall

Answers

Answer:

c

Explanation:

i did the test


13. The
are beautiful lights in the sky caused from solar energy entering the
atmosphere after moving along the magnetic field of the Earth.

Answers

Answer:

Are you talking about aurora borealis?

Explanation:

Which of the following is NOT true about essential body fat? A. The human body would not function normally without essential body fat. B. Essential body fat accounts for about 3% of men's total weight. C. The percentage of essential body fat is the same for both males and females. D. Essential body fat is found in one's organs, bones, and muscles. Please select the best answer from the choices provided. A B C D Mark this and return

Answers

Answer:

I believe it is A. The human body would not function normally without essential body fat.

Explanation:

Answer:

Cccccccccccc

Explanation:

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

The first person with the right answer gets to be a brainlest

In the attachment there is a density column where there is colour

Question: tell me why is the red at the bottom of the density column if it is the least dense

Answers

Explanation: That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.


What was the main cause of the shift to a postindustrial society?

A. Citizens started to prefer manual labor to jobs that required providing a service.

B. The economic situation allowed people to work from home instead of going to work.

C. The focus became the control of information instead of traditional manufacturing.

D. People started to purchase computers and cell phones in mass quantities.

Answers

Answer: i thnk its B

Explanation:

You are sitting on the beach and notice that a seagull floating on the water moves up and down 5 times in I minute. What is the frequency of the water waves

Answers

Answer:

f = 0.0833 Hz

Explanation:

Frequency is defined as the no. of cycles per unit time. The frequency of water waves can be given by the following formula:

[tex]Frequency\ of\ waves = f = \frac{No.\ of\ Waves}{time}\\[/tex]

here,

No. of Waves = No. of times seagull moves up and down = 5

Time = 1 minute = 60 sec

Therefore, using these values in the formula, we get:

[tex]f = \frac{5}{60\ sec}[/tex]

f = 0.0833 Hz

A 2.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0300 m . The spring has force constant 815 N/m . The coefficient of kinetic friction between the floor and the block is μk=0.40. The block and spring are released from rest and the block slides along the floor.

Required:
What is the speed of the block when it has moved a distance of 0.0200 m from its initial position? (At this point the spring is compressed 0.0100 m.)

Answers

Answer:

v = 0.41 m/s

Explanation:

In this case, the change in the mechanical energy, is equal to the work done by the fricition force on the block.At any point, the total mechanical energy is the sum of the kinetic energy plus the elastic potential energy.So, we can write the following general equation, taking the initial and final values of the energies:

       [tex]\Delta K + \Delta U = W_{ffr} (1)[/tex]

Since the block and spring start at rest, the change in the kinetic energy is just the final kinetic energy value, Kf.⇒ Kf = 1/2*m*vf²  (2)The change in the potential energy, can be written as follows:

       [tex]\Delta U = U_{f} - U_{o} = \frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (3)[/tex]

       where k = force constant = 815 N/m

       xf = final displacement of the block = 0.01 m (taking as x=0 the position

      for the spring at equilibrium)

      x₀ = initial displacement of  the block = 0.03 m

Regarding the work done by the force of friction, it can be written as follows:

       [tex]W_{ffr} = - \mu_{k}* F_{n} * \Delta x (4)[/tex]

       where μk = coefficient of kinettic friction, Fn = normal force, and Δx =

       horizontal displacement.

Since the surface is horizontal, and no acceleration is present in the vertical direction, the normal force must be equal and opposite to the force due to gravity, Fg:Fn = Fg= m*g (5)Replacing (5) in (4), and (3) and (4) in (1), and rearranging, we get:

        [tex]\frac{1}{2} * m* v^{2} = W_{ffr} - \Delta U = W_{ffr} - (U_{f} -U_{o}) (6)[/tex]

        [tex]\frac{1}{2} * m* v^{2} = (- \mu_{k}* m*g* \Delta x) -\frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (7)[/tex]

Replacing by the values of m, k, g, xf and x₀, in (7) and solving for v, we finally get:

    [tex]\frac{1}{2} * 2.00 kg* v^{2} = (-0.4*2.00 kg*9.8m/s2*0.02m) +( (\frac{1}{2} *815 N/m)* (0.03m)^{2} - (0.01m)^{2}) = -0.1568 J + 0.326 J (8)[/tex]

[tex]v =\sqrt{(0.326-0.1568} = 0.41 m/s (9)[/tex]

The micrometer (1 μm) is often called the micron. (a) How many microns make up 3.0 km? (b) How many centimeters equal 3.0 μm? (c) How many microns are in 3.0 yd?

Answers

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   [tex]\frac{3000}{1 x 10^{-6} }[/tex]   = [tex]\frac{3 x 10^{3} }{ 1 x 10^{-6} }[/tex]   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give [tex]\frac{2.73}{1 x 10^{-6} }[/tex]   = 2.73 x 10⁶μm

           

Why are Newton’s 3 laws important?

Answers

They are the physics of the world??

Answer:

Newton's law are very important because they tie into almost everything we see in everyday life. ... Newton's laws speak very generally all forces, but to use them for any specific problem, you have to actually know all the forces involved, like gravity, friction, and tension.

1. What is the frame of reference for a plane moving at 500 km/h?
O A the clouds
O B the other planes in the sky
O C the ground
O d the passengers

Answers

Answer:

A: the clouds

Explanation: none

The answer is C, The ground

Explanation: Gradpoint

A small steel ball falls from rest through a distance of 3m. When calculating the time of fall, air resistance can be ignored because

Answers

Answer:

First, let's write the movement equations for this ball.

The only force acting on the ball will be the gravitational acceleration (because we ignore the air resistance) then the acceleration equation is:

a(t) = -9.8m/s^2

Where the minus sign is because the ball is falling down.

To get the velocity of the ball, we need to integrate over time to get:

v(t) = -(9.8m/s^2)*t + v0

Where v0 is the initial velocity of the ball. Because it falls from rest, we can conclude that the initial velocity is 0 m/s, then the velocity equation is:

v(t) = -(9.8m/s^2)*t

For the position equation we need to integrate again, here we get:

p(t) = -(1/2)*(9.8m/s^2)*t^2 + p0

Where p0 is the initial position. In this cse we know that the ball falls from a height of 3m, then po = 3m

The position equation is:

p(t) = -(1/2)*(9.8m/s^2)*t^2 + 3m

The ball will hit the ground when p(t) = 0m, then we need to solve the equation:

p(t) = -(1/2)*(9.8m/s^2)*t^2 + 3m = 0m

for t.

-(1/2)*(9.8m/s^2)*t^2 + 3m = 0m

3m = (1/2)*(9.8m/s^2)*t^2

3m*2 = (9.8m/s^2)*t^2

6m/(9.8m/s^2) = t^2

√(6m/(9.8m/s^2)) = t = 0.78s

The ball needs 0.78 seconds to hit the ground.

The correct answer is (d) the weight of steel ball is much larger than air resistance.

since the density of steel ball is quite higher than that of air. The weight of even a small steel ball will be much larger than the air resistance acting opposite to the motion of the steel ball. Hence in the case of a freely falling steel ball the air resistance can be neglected.

Learn more about air resistance:

https://brainly.com/question/2575108

Which heat related illness requires immediate medical attention

Answers

Answer:

Heat stroke

Explanation:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention.

Answer:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.

Explanation:

I HOPE THIS HELPS * pls mark me brainliest }

What is my name?:

I am a god

I am a guardian of the sun

I am used to measure heat.

Answers

Answer:

Apllo?

Explanation:

Helios??? Apollo??? I really don’t know? Hi

A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead

Answers

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .

Find the distance between (-6, 1) and (2, 2). Round to the
nesest hundredth.

Answers

Answer:

d = 8.06 (units)

Explanation:

In this problem, we are given two points with X & y coordinates. therefore we must use the Pythagorean theorem with the respective coordinates of each point to determine the required distance.

[tex]A = (-6, 1)\\B = (2, 2)[/tex]

Now using the Pythagorean theorem.

[tex]d=\sqrt{(x_{1}-x_{0})^{2} +(y_{1}-y_{o})^{2} }\\d=\sqrt{(2-(-6))^{2} +(2-1)^{2} }\\d=\sqrt{64+1} \\d=8.06[/tex]

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