A wave connected armature winding has V1 slots with 54 conductors per slot. If the flux per pole is 0.025 Wb and number of poles is 8, Find the speed at which generator should be run to give 513 V. Also find the speed If the armature is lap connected.
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The speed of the block at x = 0 is 1.84 m/s.

Kinetic energy is a type of energy that an object possesses due to its motion. It is defined as the energy that an object has by virtue of its motion, and is given by the equation:

K = (1/2)mv²

where K is the kinetic energy of the object, m is its mass, and v is its velocity.

We use the conservation of energy principle. Initially, the block has potential energy stored in the spring, which is converted into kinetic energy as the block moves towards its equilibrium position, where x=0.

The potential energy stored in the spring when it is compressed to x = -6.5 cm is given by:

U = (1/2)kx²

where k is the force constant of the spring and x is the displacement from its equilibrium position.

Substituting the given values, we get:

U = (1/2) (2.90 X 10³ N/m) (0.065 m)²

U = 6.73 J

Therefore, the work done by compressing the spring is 6.73 J.

At the equilibrium position, all the potential energy stored in the spring is converted into kinetic energy. So, kinetic energy of the block at x = 0 is equal to potential energy stored in spring at x = -6.5 cm.

Therefore, the kinetic energy of the block at x = 0 is also 6.73 J.

Speed of the block at x = 0:

The kinetic energy of the block at x = 0 is given by:

K = (1/2)mv²

where m is the mass of the block and v is its speed.

Substituting the given values, we get:

6.73 J = (1/2) (2.0 kg) v²

Solving for v, we get:

v = √((2 x 6.73 J) / 2.0 kg)

v = 1.84 m/s

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As the settling distance is less than the chamber depth (1.0 m), the grit chamber can be expected to be effective in removing the particles with the given diameter.Using the Stoke's Law, the settling velocity is calculated as:

Stoke's Law is a scientific principle that states that the terminal settling velocity of a small sphere in a viscous fluid is inversely proportional to the fluid's viscosity. It is named after Sir George Gabriel Stokes, who first derived this law in 1851. Stoke's Law is important in many different fields, such as particle sedimentation, particle separation, and fluid mechanics. The law is also used to predict the settling velocity of particles in a fluid, which is important for applications such as filtration.

V = (2 x 9.81 x (1.71 x 10-4)2 x (1.83 - 1)) / (18 x 10-6 x (1 - 0.01))

= 1.39 x 10-4 m/s

The settling distance is calculated as:

S = V x T

= 1.39 x 10-4 x 60

= 0.00834 m

As the settling distance is less than the chamber depth (1.0 m), the grit chamber can be expected to be effective in removing the particles with the given diameter.

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The work done by friction as the rock moves from point a to point b is equal in magnitude to the potential energy of the rock at point a, and it is negative because it acts in the opposite direction to the displacement of the rock

To determine how much work friction did on the rock as it moved from point a to point b, we need to first consider the forces acting on the rock and the work done by each force.

At point a, the rock has only potential energy due to its position above the ground. As it slides down the slope towards point b, the potential energy is converted to kinetic energy, and the rock gains speed.

The forces acting on the rock as it slides down the slope are:

The force of gravity acting downward, with a magnitude equal to the weight of the rock (mg).

The normal force acting perpendicular to the slope, which is equal in magnitude but opposite in direction to the force of gravity (2mg at point b).

The force of friction acting parallel to the slope, in the opposite direction to the motion of the rock.

Since the rock is sliding down the slope, the force of friction must be acting in the direction opposite to the motion, which means that the work done by friction is negative.

The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. In this case, we can assume that the initial velocity of the rock at point a is zero, so its initial kinetic energy is also zero.

At point b, the rock has reached its maximum speed and all of its potential energy has been converted to kinetic energy. Therefore, the work done by gravity is equal to the change in potential energy:

[tex]mgh = (1/2)mv^2[/tex]

where m is the mass of the rock, g is the acceleration due to gravity, h is the vertical distance between points a and b, v is the speed of the rock at point b.

Solving for v, we get:

[tex]v = \sqrt{(2gh)}[/tex]

The work done by the normal force is zero, since it acts perpendicular to the displacement of the rock.

The work done by friction is given by:

[tex]W_{friction} = -f * d[/tex]

where f is the force of friction and d is the horizontal distance between points a and b.

To determine the force of friction, we can use the fact that it is equal in magnitude to the normal force multiplied by the coefficient of friction (μ):

f = μ * N

At point b, the normal force is twice the weight of the rock, so N = 2mg. The coefficient of friction is not given, so we cannot calculate the exact value of the work done by friction.

However, we can make some general observations about the work done by friction based on the information given. Since the normal force at point b is twice the weight of the rock, this implies that the slope is steeper at point b than it is at point a. This in turn implies that the force of friction at point b is greater than it is at point a. Therefore, we can conclude that the work done by friction is negative and that its magnitude is greater than zero.

Finally, we can use the work-energy principle to calculate the work done by friction:

[tex]W_{friction} = -mgh = -[(1/2)mv^2][/tex]

Substituting the expression we derived for v, we get:

[tex]W_{friction} = -mgh = -[(1/2)m(2gh)] = -mgh[/tex]

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The resolving power of the microscope is approximately 0.196 μm when using the oil immersion lens.

What is Aperture?

In optics, the aperture refers to the opening or hole in an optical system through which light passes. It is typically a circular or rectangular opening that can be adjusted to control the amount of light that enters the system. The aperture size affects various properties of the optical system, such as the depth of field, the amount of light that reaches the sensor or film, and the resolving power or sharpness of the resulting image. The numerical aperture (N.A.) is a related term that describes the ability of an optical system to gather light, and it is determined by the size of the aperture and the refractive index of the medium through which light passes.

To calculate the resolving power (R.P.) of the microscope, we can use the formula:

R.P. = wavelength / (2 * N.A.)

where wavelength is the average wavelength of visible light, and N.A. is the numerical aperture of the objective lens.

Given that the average wavelength of visible light is 0.55 μm (micrometers), and assuming we are using an oil immersion lens, which typically has a numerical aperture of around 1.4, we can plug in these values and solve for R.P.:

R.P. = (0.55 μm) / (2 * 1.4)

R.P. = 0.196 μm

Therefore, the resolving power of the microscope is approximately 0.196 μm when using the oil immersion lens.

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The net electric potential at the origin due to the circular arc of charge Q1, and the two particles of charges Q2 and Q3 can be calculated by using the formula for electric potential due to a point charge:

V = (kQ)/r

Where V is the electric potential, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the point of charge to the point where we want to calculate the electric potential.

For the circular arc of charge Q1, the electric potential at the origin is:

V1 = (kQ1)/R = (8.99 x 10^9 Nm^2/C^2)(7.21 x 10^-12 C)/(2.00 m) = 1.62 x 10^-2 V

For the particle of charge Q2, the electric potential at the origin is:

V2 = (kQ2)/R = (8.99 x 10^9 Nm^2/C^2)(4.00Q1)/(2.00 m) = 4.00V1 = 6.48 x 10^-2 V

For the particle of charge Q3, the electric potential at the origin is:

V3 = (kQ3)/R = (8.99 x 10^9 Nm^2/C^2)(-2.00Q1)/(2.00 m) = -2.00V1 = -3.24 x 10^-2 V

The net electric potential at the origin is the sum of the electric potentials due to each charge:

Vnet = V1 + V2 + V3 = 1.62 x 10^-2  V  + 6.48 x 10^-2  V  - 3.24 x 10^-2  V

Vnet = 4.86 x 10^-2 V

Therefore, the net electric potential at the origin due to the circular arc of charge Q1 and the two particles of charges Q2 and Q3 is 4.86 x 10^-2 V.

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The basal metabolic rate for the girl of 14 years weighing 125 pounds and height of 5ft.6 inch is 1573 Kcal/day.

The basal metabolic rate of a person is the number of calories that is burned inside the body through basic life -sustaining metabolic functions. It can be calculated using the below equations for men and women.

BMR for men = 88.362 + (13.397 x weight in kg) + (4.799 x height in cm) – (5.677 x age in years)

BMR for women  = 447.593 + (9.247 x weight in kg) + (3.098 x height in cm) – (4.330 x age in years).

Given, the age = 14 years

weight = 125 pounds = 56.7 kg

1 feet =  30.48 cm

1 inch = 2.54 cm.

then 5ft.6inch = 167.64 cm.

Now BMR =  447.593 + (9.247 x 56.7) + (3.098 x 167.64 ) – (4.330 x 14)

=  1573 Kcal/day.

Therefore, the basal metabolic rate of the girl is 1573 Kcal/day.

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The components of the corresponding force and moment reactions at the built-in support at O are:

Horizontal reaction force = 0 lb

Vertical reaction force = 138.6 lb

Moment reaction = -5370.6 lb-in.

What is Moment Reaction?

In mechanics, a moment reaction refers to the force that acts on an object in response to a moment or torque applied to it. The moment reaction can be thought of as the force that resists the rotation of an object around a given axis. In engineering and physics, moment reactions are important in the analysis of structures and systems that involve rotational motion, such as beams, gears, and engines. They are typically represented as vectors, and can be calculated using mathematical formulas and equations based on the principles of mechanics and Newton's laws of motion.

We can apply the equations of equilibrium to point O to determine the components of the corresponding force and moment reactions. The equations of equilibrium are:

ΣFx = 0 (the sum of forces in the x-direction is zero)

ΣFy = 0 (the sum of forces in the y-direction is zero)

ΣM = 0 (the sum of moments about any point is zero)

Taking the x- and y-axes to be along the horizontal and vertical members, respectively, we have:

ΣFx = -T1 cos(45) - T2 cos(45) = 0

ΣFy = T1 sin(45) + T2 sin(45) = R

ΣM = -T1 cos(45) (24/2) - T2 cos(45) (24 + 36) + R (32) = 0

where R is the reaction force at point O.

Solving these equations, we get:

T1 = 180 lb

T2 = 120 lb

R = 138.6 lb

To find the moment reaction at point O, we can take moments about point O:

ΣM = -T1 cos(45) (24/2) - T2 cos(45) (24 + 36) + R (32) = M

where M is the moment reaction at point O.

Solving this equation, we get:

M = -5370.6 lb-in

Therefore, the components of the corresponding force and moment reactions at the built-in support at O are:

Horizontal reaction force = 0 lb

Vertical reaction force = 138.6 lb

Moment reaction = -5370.6 lb-in.

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The force reaction at the built-in support at O is the sum of the forces from turnbuckles T1 and T2, which can be calculated as follows:

Force is a push or pull on an object that results from an interaction between two objects. Forces can cause objects to accelerate, decelerate, start moving, stop moving, or change direction. Every interaction in the universe is a result of forces between two objects. Force can be a result of gravity, electromagnetism, or even nuclear forces. Forces are measured in Newtons and can be calculated using the equation F=ma, where F is the force, m is the mass of the object, and a is the object’s acceleration. Force is an integral part of many physical phenomena, and understanding how forces interact is essential to understanding our universe.

Force reaction from T1 = 180 lb
Force reaction from T2 = 120 lb
Total force reaction at O = 180 lb + 120 lb = 300 lb
The moment reaction at the built-in support at O is the sum of the
moments from turnbuckles T1 and T2, which can be calculated as follows:
Moment reaction from T1 = 180 lb x 24 in = 4320 lb-in
Moment reaction from T2 = 120 lb x 18 in = 2160 lb-in
Total moment reaction at O = 4320 lb-in + 2160 lb-in = 6480 lb-in

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Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

In physics, a wave is a disturbance that travels through space and time, usually accompanied by the transfer of energy. Waves can be characterized by their amplitude, wavelength, frequency, and speed.

Here,

Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

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The torque acts on a distance of 0.2 m from one end of the beam is 88.96 Nm and the torque acting upon a the distance of 0.3 m from the other end of the beam is 133.4 Nm. Then, the net torque of the mass is 44.48 Nm.

Torque is the rotational analogue of force on an object. It is the measure of force that acts on the object to rotate the object about an axis.

It is the cross product of force and distance from the end of axis. Torques generates the angular momentum in the object.

Given the mass  m= 100 pounds.

1 pound = 4.448 N

then Force by the weight F = 100 × 4.448 = 444.8 N.

Then, the torque acts over 0.2 m from one end = F .r = 444.8 × 0.2 = 88.96 Nm.

Then, the torque acts over 0.3 m from one end = F .r = 444.8 × 0.3 = 133.4 Nm.

Therefore, the net torque acting on the mass is 133.4 -88.96 = 44.48 Nm.

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The total initial momentum of the rocket is 150.28 kg m/s. The total final momentum of the mass fractions is equal to the initial value. From this, the mass of the second piece is 1.3 kg with a velocity of 80 m/s.

Momentum of an object is the product of its mass and velocity. During a collision, the total momentum will be conserved. Thus, total initial momentum of the system is equal to its total final momentum.

Here, mass of the rocket = 3.4 kg

velocity = 44.2 m/s

then momentum =  3.4 kg × 44.2 m/s = 150.28 kg m/s

The mass of one piece = 2.1 kg.

then mass of second piece of the rocket = 3.4 - 2.1 = 1.3 kg.

velocity of first piece = 22 m/s

then, momentum = 2.1 kg × 22 m/s = 46.2 kg m/s.

Now, momentum of first piece + momentum of second piece = 150.28 kg m/s.

then momentum of  second piece = 150.28 - 46.2 = 104 kg m/s.

Therefore, velocity = momentum/mass

v = 104 kg m/s /1.3 kg = 80 m/s.

Therefore, the velocity of the second piece of the rocket after explosion is 80 m/s.

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Answer:

8.65 m/s.

Explanation:

Let's use conservation of momentum and conservation of kinetic energy to solve this problem.

Since the two balls have equal masses, we can simplify the problem by assuming they are identical. Let's call the initial speed of the incoming ball v and the final speed of the outgoing ball v'.

Conservation of momentum tells us that the total momentum before the collision is equal to the total momentum after the collision:

mv = mv'cos(29°) + mv'sin(29°)

where m is the mass of each ball.

Conservation of kinetic energy tells us that the total kinetic energy before the collision is equal to the total kinetic energy after the collision:

(1/2)mv^2 = (1/2)mv'^2

We can solve the first equation for v' and substitute it into the second equation:

v' = v(1 - sin(29°)) / cos(29°)

(1/2)mv^2 = (1/2)m[v(1 - sin(29°)) / cos(29°)]^2

Solving for v', we get:

v' = v[1 - sin(29°)] / cos(29°)

v' = 8.65 m/s (to two decimal places)

Therefore, the speed of the first ball after the collision is 8.65 m/s.

The correct statements for the children's linear accelerations are:

Since the children are moving in a circle with a constant speed, their tangential acceleration is constant and equal for all of them. However, their radial acceleration depends on their distance from the center of the circle, and it decreases as the distance increases.

Therefore: The last child in the line has the greatest radial acceleration, since they are closest to the center of the circle. All the children have the same tangential acceleration.

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0Nm, 147.5 Nm and  -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.

A moment is indeed a mathematical term used in physics that involves the combination of a physical quantity and a distance. Seconds relate to physical quantities that are dispersed from either the reference point and are often described with regard to something like a fixed reference point.

The instant therefore explains the position or arrangement of the amount. For instance, the moment of force, also known as torque, is the result of the force acting on an object and the item's distance first from reference point.

Moment = force ×distance

M = f × d

Moment about the x axis:

M = 5.9  ×0

M = 0Nm

Moment about the y axis:

M =5.9  ×25  = 147.5 Nm

Moment about the z axis:

M = 5.9  × (-25)

M = -147.5Nm

Therefore, 0Nm, 147.5 Nm and  -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.

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The distance over which the force is applied when using a lever is called the effort distance.

Force is defined as the rate of change of momentum.

Here,
The distance over which the force is applied when using a lever is called the effort distance. It refers to the distance between the point where the effort is applied and the fulcrum of the lever. In the case we described, where a force is applied when using a lever over 2 meters to move an object 1 meter, the effort distance would be 2 meters. The load distance, on the other hand, refers to the distance between the fulcrum and the point where the load is applied. Understanding the relationship between the effort and load distances is crucial to determining the mechanical advantage of a lever system.

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The maximum width of the gorge that the secret agent can clear is 33.2 m.

Gorge is a steep-sided valley that is typically formed when a river or stream cuts through a landscape. Gorges can occur in a variety of landscapes and can range greatly in size. They are often found in areas of limestone or sandstone, and are often filled with spectacular scenery, including waterfalls, rapids, and cliffs. Gorges can also be formed by ice, erosion, and glacial activity.

The maximum width of the gorge that the secret agent can clear is given by the equation:

W = 2v0^2 * sin(2θ) / g

Where W is the maximum width of the gorge, v0 is the initial speed of the agent, θ is the angle of the slope, and g is the acceleration due to gravity.

Substituting the given values into the equation, we get:

W = 2 * (12.9 m/s)^2 * sin(2 * 28°) / 9.81 m/s^2

W = 33.2 m

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Answer:

Explanation:

The type of motion executed will be the simple harmonic motion. The time do you have to move out of the way will be 1.74 sec.

What is simple harmonic motion?

When an object executes a to and fro motion in the definite plane when it is tied with the string. The type of motion will be the simple harmonic motion.

Simple harmonic motion is a form of periodic motion in mechanics and physics in which the restoring force on the moving item is directly proportional to the size of the object.

The time period is given by the formula;

Hence the time do you have to move out of the way will be 1.74 sec.

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Answer:

muscle fiber, acetylcholine, ACh receptor-channels, motor neuron, motor end plate

Explanation:

Those are the ones that are necessary to initiate the muscle action.

Answer:

according to the variations that they have been within years.

Explanation:

Answer:

your answer is

Explanation:

Living things provide evidence for evolution through various ways such as the existence of homologous structures (similar structures in different organisms indicating a common ancestor), vestigial structures (organs that have lost their original function over time), the distribution of species across different regions, genetic similarities and differences between organisms, and the observation of natural selection in action.

The missing part of the question have been filled below on Continental drift

In the early part of the 20th century, a German scientist named Alfred Wegener, proposed the theory of continental drift which suggested the continents move and started out in different positions from what they are currently. In the 1960s, scientists discovered the spreading apart of areas of the sea floor. This in turn led to the theory of plate tectonics. The lithosphere is made of plates which float on a "plastic-like" undersurface called the mantle. Where these plates come together at boundaries, changes take place in the crust and its feature.

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The hiker will hear her echo 1.65 seconds after she shouts.

To determine how long it takes for the hiker to hear her echo, we need to calculate the time it takes for the sound to travel from the hiker to the canyon wall, reflect off the wall, and travel back to the hiker.

Let's start by calculating the time it takes for the sound to travel from the hiker to the canyon wall. We can use the formula:

Time = distance / speed

where distance is the distance between the hiker and the canyon wall, and speed is the speed of sound.

Plugging in the given values, we get:

Time = 280.5 m / 340.0 m/s = 0.825 s

So it takes 0.825 s for the sound to travel from the hiker to the canyon wall.

Now we need to calculate the time it takes for the sound to travel from the canyon wall back to the hiker. This time will be the same as the time it took for the sound to travel from the hiker to the canyon wall, since the distance is the same and the speed of sound is constant.

Therefore, the total time it takes for the hiker to hear her echo is:

total time = 2 x time = 2 x 0.825 s = 1.65 s

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"The expression that shows number of remote control cars on the display self is 16s."

In order to create a mathematical expression, you need at least two numbers, variables, one arithmetic procedure, and a statement. In order to determine the total number of items in all of the self, we must multiply the number of self (n) by the number of self (x).

On a display stand, 16 remote-control vehicles are present. There are s display racks in total.

Therefore, there will be 16 times as many vehicles overall as s.

16 vehicles are displayed.

As a result, the expression '16s' indicates that there are 16 cars on exhibit.

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Answer: The force exerted on the wall by He is twice than by H2.

Explanation: I believe this is the answer because:

Pressure is defined as the force per unit area.

It means that pressure is directly proportional to the force. If the pressure is increased, more force will be exerted on the walls of the container.

According to Henry’s law, the partial pressure of gas in the gas mixture is directly proportional to the mole fraction of the gas.

Among the given gas mixture, the mole fraction of He is twice more than that of H2. So, the pressure exerted by the He gas is two times greater than H2.

Hence, the force exerted on the wall will be greater by He than by H2.

The ratio of the impact of the gases is:

H2 over He = 1/3 over 2/3 - 1 : 2

Therefore, the force exerted on the wall by He is twice than by H2.

I hope this helps!

Answer:

N = hailstones / sec = 580 / 41 = 14.1 stones / sec

mass = .007 kg

v = 6.7 m/s * sin 31 = 3.45   speed of stones perpendicular to surface

Δp = 2 m Δv        change in momentum dur to striking window

F = N Δp        force required to repel hailstones

F = 2 N m Δv = .68 N       force on window pane

Pressure = force / area       (don't need window area for force)

Answer:

This raboratory activity is broken up into four distinct parts so that the goals and variables of each part can be observed separately. In Part I, students manipulate the observe a magnetic field. In Part II, students manipulate the objects to observe an electric field. In Part III, students intentionally change the generated. In Part IV, students intentionally change the magnetic field. •and document the attraction with a magnet to ~ and document the attraction between the and measure the electric current •and observe the generation of a

In Part I of this lab activity, students manipulate objects to observe a magnetic field. In Part II, they manipulate objects to observe an electric field. In Part III, they intentionally change the generated electric field. In Part IV, they intentionally change the magnetic field and document the attraction with a magnet to and document the attraction between the objects and measure the electric current and observe the generation of a magnetic field.

The laboratory activity contains four distinct parts related to magnetic fields and electric fields. It is designed to help high school students understand the fundamental principles of electricity and electromagnetism in physics. Students manipulate, observe, document, and measure in all parts of the activity to gain comprehensive exposure.

The laboratory activity you're referring to is subdivided into four distinct parts, each focusing on different aspects of Physics related to magnetic fields and electric fields.

In Part I of the lab, students experiment with a magnet to understand the mechanics of a magnetic field. Part II shifts the focus onto electric fields where students manipulate various objects and document interactions.

For Part III and Part IV, students are required to measure the electrical current generated and observe the change in generation when different variables are intentionally altered in the magnetic field.

Overall, this activity offers comprehensive exposure to the fundamental principles of electromagnetism and electricity in physics.

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Therefore, of the three options given, the electromagnet with more coils around the metal rod is the most powerful if all other factors such as current and core material are kept constant.

What is the very short response to an electromagnet?

An electromagnet is a temporary magnet made by winding a wire around an iron core. When current flows through the coil, iron becomes a magnet, and when the current is cut off, it loses its magnetic properties.

What is Electromagnetism?

Electromagnetism is the branch of physics that deals with the electromagnetic forces that occur between charged particles. Electromagnetic force is one of the four basic forces and describes the electromagnetic field.

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Answer: The answer is B

Explanation:

The frequency of the oscillation. In this case, the amplitude is 0.218 m. and B. the maximum speed of the oscillation is 0.636 m/s.

Frequency is a measure of the number of occurrences of a repeating event per unit of time. It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency.

a) The amplitude of the oscillation is the maximum displacement of the car from its equilibrium position. It is equal to the maximum acceleration divided by the frequency of the oscillation. In this case, the amplitude is 0.24 m/s² / 1.1 hz = 0.218 m.

b) The maximum speed of the oscillation is related to the amplitude and frequency of the oscillation. It can be calculated using the formula v = √(2*a*f), where a is the maximum acceleration and f is the frequency of the oscillation. In this case, the maximum speed of the oscillation is v = √(2*0.24 m/s² * 1.1 hz) = 0.636 m/s.

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The kinetic energy of the object is: KE = 0.5 x 1 kg x (5 m/s)2

 = 12.5 J

Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be defined as the energy an object has due to its mass and its velocity. Kinetic energy is measured in Joules (J). Kinetic energy increases with increasing mass and velocity of an object. When an object is at rest, it has zero kinetic energy. When an object is in motion, it has kinetic energy. Kinetic energy is a form of energy that is associated with the motion of an object. It is the energy that is stored in the movement of an object. Kinetic energy is one of the fundamental forms of energy, along with potential energy.

Kinetic energy is the energy possessed by an object due to its motion. It is a form of energy that can be calculated using the equation:

Kinetic energy (KE) = 0.5 x Mass (m) x Velocity (v)2

In this case, the mass of the object is 1 kg and its velocity is 5 m/s.

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