Answer:
The value is [tex]\alpha = 3.84 \ rad/s^2[/tex]
Explanation:
From the question we are told that
The constant angular speed is [tex]w = 11.9 \ rad/s[/tex]
The time taken is [tex]t = 3.10 \ s[/tex]
Generally the magnitude of the angular acceleration is mathematically represented as
[tex]\alpha = \frac{w}{t}[/tex]
=> [tex]\alpha = \frac{11.9}{ 3.10 }[/tex]
=> [tex]\alpha = 3.84 \ rad/s^2[/tex]
A space probe is sent to an alien planet and conducts an experiment in order to determine the acceleration due to gravity on the planet. It produces the following table
Object Rock Grain of sand Metal bolt
Mass 20 grams 0.8 grams 79 grams
Recorded force of gravity :0.1224 N 0.00501 N 0.4871 N
Given this data, which of the following the closest approximation of the acceleration due to gravity on this planet
a
3.8 m/s^2
b
4.0 m/s^2
c
9.9 m/s^2
d
6.1 m/s^2
Answer: D. 6.1 m/s^2
Explanation:
Use the rules for significant figures to find the answer to the following addition problem: "21.4+15+17.17+4.003"
Answer:
57.6
Explanation:
"Significant figures" refer to figures that have an actual contribution to a number's value.
They refer to all digits except those with "leading zero," which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are 234.
The rule for adding and subtracting significant figures is to round off the answer to the least number of decimal places. However, when it comes to multiplying and dividing significant figures, you have round off the answer to the least number of significant digits.
Let's solve.
21.4
+15
17.17
4.003
57.573
Let's now round off to the least number of decimal places, which is the tenths. Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6
Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10
How would taping a coin to the balloon affect the overall motion of the balloon?
Answer:
the motion of the coin taping the balloon is the balloon squshing down
Help me please I’ll give brainliest
Answer:
zoom in
Explanation:
sodium is a metal why
Explanation:
Sodium is a chemical element with the symbol Na (from Latin "natrium") and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table. ... The free metal does not occur in nature, and must be prepared from compounds.
Explanation:
Sodium is an alkali metal, being in group 1 of the periodic table.
Does anyone know the answer to this page and the next one that it has?
A pendulum clock uses a simple pendulum as its timing device. The clock is correct at noon. The next day, when the clock reads noon, the actual time is 11:50 a.m. What is the fractional change in pendulum length that must be made so the clock runs at the correct rate
Answer: the length of the pendulum should be 1.4% longer
Explanation:
Given that;
when its noon, the clock reads 11:50 am,
i.e we have 10 minutes delay ⇒ 10min × 60 = 600secs
we know that in simple pendulum
T = 2π√(l/g)
d means delay and c means correct;
24hrs = 86400 secs
Now
Td/Tc = (86400-600) / 86400 = 0.993 = [2π√(ld/gc)] / [2π√(ld/gc)] = √(ld/lc)
so ld/lc = 0.98616
lc = 1.014 ld
lc/l.d = -1 + 1.014 = 0.014 × 100 = 1.4% longer
therefore the length of the pendulum should be 1.4% longer
You want to move a spacecraft that is in 300 km circular orbit around Venus into another circular orbit around Venus of 600 km. Explain how you would accomplish this. Solve for the velocities that need to be applied.
Answer:
The final velocity will be half of the initial velocity of the spacecraft.
Explanation:
Angular momentum is conserved for the circular force motion and central force motion.
Considering
L = MVR = Constant
Where
M = Mass of the object
V = Velocity of the object
r = radius of circle
We know that
V = [tex]\frac{1}{R}[/tex]
So,
[tex]\frac{V_{2} }{V_{1} }[/tex] = [tex]\frac{R_{1} }{R_{2} }[/tex]
As per the given data
[tex]R_{1}[/tex] = Initial Radius = 300 km
[tex]R_{2}[/tex] = Final Radius = 600 km
[tex]V_{1}[/tex] = Initial Velocity =
[tex]V_{2}[/tex] = Final Velocity =
Placing values in the formula
[tex]\frac{V_{2} }{V_{1} }[/tex] = [tex]\frac{300 km}{600 km }[/tex]
[tex]\frac{V_{2} }{V_{1} }[/tex] = [tex]\frac{1}{2}[/tex]
[tex]{V_{2}[/tex] = [tex]\frac{1}{2} V_{1}[/tex]
Hence, The final velocity will half of the initial velocity of the spacecraft.
Lisa made the electromagnet shown. (Image above) What can Lisa do to increase the strength of the electromagnet?
O She can use a nail with weaker magnetic properties.
O She can change the direction of the nail.
O She can increase the number of wire loops.
O She can reduce the current in the wire.
If correct first gets Brainliest Please hurry this is a timed test( this is second time just in case I didn't go through)
Answer:
I think C
Explanation:
if im wrong then what is it im taking the exam too
Answer: C. She can increase the number of wire loops.
Explanation:
If you exert a force of 10.0 N to lift a box a distance of 0.75m, how much work do you do?
(4 Points)
0.075 J
7.5 J
10.75 J
75 J
Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m).
Work = Force × Distance.
W = 10 N × 0.75 m
W = 7.5 JThe spiral spring showed are identical. Each spring has a spring constant K =100N/m determine the total extension caused by the 150N weight
1 spring k=100
2 springs k =200
f=kx
then k=f/x
200=150/x
x=200/150
x=4/3
Explanation:
need thanks ..................
The total extension caused by the 150N weight is 1.5 m
Data obtained from the question Spring constant (K) = 100 N/mForce (F) = 150 NExtention (e) =? How to determine the extensionFrom Hooke's law,
Force (F) = spring constant (K) × extention (e)
F = Ke
150 = 100 × e
Divide both side by 100
e = 150 / 100
e = 1.5 m
Therefore, the total extention caused by the weight is 1.5 m
Learn more about spring constant:
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An earth satellite travels in a circular orbit at 20,000 mph if the radius of the orbit is 4,300 mi what angular velocity is generated?
Answer:
0.00129rad/s
Explanation:
The angular velocity is expressed as;
v = wr
w is the angular velocity
r is the radius
Given
v = 20,000 mph
r = 4300mi
Get w;
w = v/r
w = 20000* 0.44704/4300*1609.34
w = 8940.8/6,920,162
w = 0.00129rad/s
Hence the angular velocity generated is 0.00129rad/s
What is true of the bottom layer of the ocean
Answer:
well i tough it was infinte but its not an the layer is a d i c k
Explanation:
Two workers are sliding 500 kg crate across the floor. One worker pushes forward on the crate with a force of 440 N while the other pulls in the same direction with a force of 340 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor
Answer:
0.159
Explanation:
Given that
F1 = 440 N
F2 = 340 N
m = 500 kg
acceleration, a = 0 m/s²
Remember that F = m.a
If F - f(f) = 0, then F = f(f)
N = mg
f(f) = μN, substituting for N, we have
f(f) = μmg
The total force, F = F1 + F2
F = 440 + 340
F = 780 N
Recall that we'd already proven that
F = f(f), so F = 780 N = f(f)
And again, f(f) = μmg, if we substitute for all the values, we have
780 = μ * 500 * 9.81
780 = μ * 4905
μ = 780 / 4905
μ = 0.159
Therefore, the coefficient of static friction of the crate on the floor is 0.159
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2.09 s. What minimum coefficient of static friction between her feet and the floor of the merry-go-round is required to keep her in the circular path
Answer:
2.01
Explanation:
First, we need to find the centripetal acceleration.
We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute
Now this speed gotten in rpm will be converted to m/s, to ease the calculation
30 rpm = πdN/60 m/s
30 rpm = (3.142 * 4 * 30)/60
30 rpm = 377.04/60
30 rpm = 6.284 m/s
a(c) = v²/r
a(c) = 6.284²/2
a(c) = 39.49 / 2
a(c) = 19.74 m/s²
F = ma
F = 50 * 19.74
F = 987 N
Also, Normal Force, F(n) =
F(n) = mg
F(n) = 50 * 9.81
F(n) = 490.5
We then use this to find the coefficient of static friction, μ
μ = F/F(n)
μ = 987 / 490.5
μ = 2.01
A car accelerates at 2 m/s2. Assuming the car starts from rest, how much time does it need to accelerate to a speed of 16 m/s?
Answer:
8 seconds
Explanation:
as per 1st equation of motion
v=u+at,
u= initial velocity, v= final velocity , t=time, a=acceleration
since it starts from rest , u=0
v=16m/s
a=2m/s^2
16=0+2t
16=2t
t=8
A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms⁻¹ , the magnitude of the induced emf in the wire of aerial is:
Answer: Induced emf is given by:
ε= Bvl
On putting the values we get
=5×10
−5
×1.50×2
=0.15mV
Explanation:
Hope these helped have a wonderful Christmas break ❄️
A constant force of magnitude 23 N acts on an object for 3.1 s. What is the magnitude of the impulse
Answer:
71.3 NsExplanation:
The impulse of an object can be found by using the formula
impulse = force × time
From the question we have
impulse= 23 × 3.1
We have the final answer as
71.3 NsHope this helps you
A person pushes a box filled with books with a force of 120 newtons a distance of 30 meters within 3 minutes Calculate the work the person did and the amount of power required
120/30-4
I will give brainliest
when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answer:
c ) potential your welcome heheSuppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will jump straight upward.Will the shrimp do any work in this case?
Answer:
yes
Explanation:
I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction
HELP ME NOW PLZ
What is the speed of a boy moving around a circular park of
radius 6 m if he goes once around the park in 20 s?
A-1.88m/s
B-3.76m/s
C-5.65m/s
D-None of the above
Answer: 1.88 m/s
Explanation:
The speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.
What is speed?Speed is a measurement of how quickly an object's distance traveled changes. Speed is a scalar, which implies it has magnitude but no direction as a unit of measurement.
A thing that moves quickly and with great speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time.
Given information:
The radius of the circular park, r = 6 m,
The time is taken to cover one round, t = 20s,
The total distance covered by the boy is equal to the circumference of the park, so
d = 2[tex]\pi[/tex]r,
[tex]d = 2*3.14*6\\d = 37.68 m[/tex]
Now,
the speed of the boy, s = [tex]37.68/20[/tex] ,
s = 1.88 m/s
Therefore, the speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.
To know more about speed:
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A 0.7 kg block attached to a spring with force constant 160 Nm is free to move on a frictionless, horizontal surface. The block is released from rest when the
spring is stretched + 0.15 m as shown in figure below. At the instant the block is released the force vector on the block is.
(Consider Right direction is positive direction and Left direction is negative direction)
- 34.29 N
+ 34.29 N
+ 24 N
Оe
h Oa-241
Answer:
+ 24 N
Explanation:
the computation is shown below:
Given that
Mass of the block = m = 0.7 kg
Sprint constant = k = 160 N / m
x = 0.15m
Now the force on the block is
F = kx
= (160) (0.15)
= 24 N
As the instant block is released so the acting of the force on the block is positive and it would be in a positive direction i.e. right direction
Therefore the third option is correct
9. Who was the FIRST person to propose that the continents might fit together
Answer:
Alfred Wegener
Explanation:
Two forces with magnitudes of 6 pounds and 18 pounds are applied to an object. The magnitude of the resultant is 13 pounds. Find the measurement of the angle between the resultant vector and the vector of the 18 pound force to the nearest whole degree.
Answer: the angle between the resultant vector and the vector of the 18 pound is 28°
Explanation:
given that data in the question; as its interpreted in the diagram below;
from the cosine rule, we know that;
a² = b² + c² - 2bc
so
(13)² = (6)² + (18)² - (2 × 6 × 18 ) cos∅
169 = 36 + 324 - 216cos∅
169 = 360 - 216cos∅
216cos∅ = 360 - 169
216cos∅ = 191
cos∅ = 0.8842
∅ = cos⁻¹ ( 0.8842 )
∅ = 27.8° ≈ 28° {nearest whole number}
Therefore the angle between the resultant vector and the vector of the 18 pound is 28°
The total yearly world consumption of energy is approximately 4.0 × 1020 J. How much mass would have to be completely converted into energy to provide this amount of energy?
Answer:
m = 4.4 × 10³ kg
Explanation:
Given that:
The total yearly energy is 4.0 × 10²⁰ J
The amount of mass that provides this energy can be determined by using the formula:
E = mc²
where;
c = speed of light in free space = (3 × 10⁸)
4.0 × 10²⁰ = m × (3 × 10⁸)²
[tex]m = \dfrac{4.0 \times 10^{20} }{(3\times 10^8)^2}[/tex]
m = 4.4 × 10³ kg
PLease help i will give brainliest
Answer:
1. False
2. Fats
3. False
Explanation:
MyPlate is an initiative from the United States Department of Agriculture that is designed to help Americans improve their eating habits throughout their lifetimes. Every meal matters. The five food groups represented in My Plate include vegetables, grain, dairy, protein foods, and fruits.
Calories are a source of energy for the human body. So, the more active a person is, the more energy he would need to be supplied to him in form of calories. The less active a person is, the fewer calories he would need.
A large pendulum with a 200-lb gold-plated bob 12 inches in diameter is on display in the lobby of the United Nations building. The pendulum has a length of 75 ft. It is used to show the rotation of the Earth-for this reason it is referred to as a Foucault pendulum. What is the least amount of time it takes for the bob to swing from a position of maximum displacement to the equilibrium position of the pendulum?
Answer:
2.4s
Explanation:
The length of the pendulum = 75ft
Diameter d = 12 inches
The time period of the pendulum is given as
T = 2pi(L/g)^1/2
Then the time it takes to move from displacement to equilibrium is given as:
t = T/4
= (Pi/2)*(L/g)^1/2
= pi/2 x [(75x0.3048)/9.81]^0.5
= 1.57x[22.86/9.81)^0.5
= 2.4s
2.4 seconds is the least amount of time that it would take.
A nuclear power plant is being built to generate electricity for a large
metropolitan area. Which process will it use?
O A. Nuclear decay of uranium-238
B. Chemical decay of wood
C. Nuclear fission of uranium-235
O D. Combustion of fossil fuels
Answer:
C. Nuclear fission of uranium-235
Answer:
C. Nuclear fission of uranium-235
Explanation:
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