Answer:
E = - 2*E₀*sinθ*i
V = V = 2*E₀*sinθ /r
Explanation:
First situation: a quarter-circle rod produces at the origin
E₀ and V₀
We know that E = K * Q/r and
E = E₀ Q = L*λ Q = 1/4 * 2*π*r*λ Q = (1/2)*π*r*λ
where:
r is the radius of the circle which at the same time is the distance between the rod quarter of the circle and the origin.
λ is the longitudinal density of charge, and
k = 1/4*π*ε₀
Then E₀ = (1/2)* k*π*λ and V₀ = - E₀/Q V₀ = - E₀/r
E₀ = E₀ₓ + E₀y E₀ₓ = E₀*cosθ E₀y = - E₀*sinθ
θ the angle between E₀ and the x-axis
Second situation half of a circle ( first quarter +Q and fourth -Q )
In that configuration, the components in the x-axis cancel each other ( by symmetry) and the y-axis components of +Q and -Q are to be added then
E = Eₓ + Ey but by inspection we find Eₓ = 0 ( the components of the
the electric field produced of the two quarters canceled each other)
and we have to add the two identical y-axis components of the two quarters therefore
E = 2*E₀y
each component of E₀y = - E₀*sinθ
Then the new electric field becomes
E = - 2*E₀*sinθ*i
The new V = - (- 2*E₀*sinθ /r)
V = 2*E₀*sinθ /r
(Note remember that V is a scalar )
Can someone please help?
Answer:
Gold = 19.3g/cm³
Explanation:
Given the following data;
Mass = 38.6g
Volume = 2cm³
To find the density;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Substituting into the equation, we have;
[tex]Density = \frac{38.6}{2}[/tex]
Density = 19.3g/cm³
Therefore, from the table the material is Gold.
Gold is a chemical element and it is the element 79 on the periodic table. Thus, it has an atomic number of 79. The chemical symbol for Gold is Au, it is chemically classified as a transition metal and as a solid at room temperature.
Generally, the chemical element Gold is known to have the following physical properties;
I. Malleable.
II. Ductile.
III. A good conductor of electricity and heat.
Also, it is a non-toxic chemical element with a beautiful lustrous sheen.
A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answer: 67 how much candy does nick have
Explanation:
A brick is moving at a speed of 3 m/s and a pebble is moving at a speed of 5 m/s. If both objects have the same kinetic energy, what is the ratio of the brick's mass to the rock's mass
Answer:
let M be the mass of brick
let m be the mass of the pebble
.5M(3)^2 =KE
.5m(5)^2= KE
.5M9 = .5m25
9M = 25m
(9/25)M = m
Answer:
A
Explanation:
e=1/2M[tex]V^{2}[/tex]
1/2[tex]M_{1}[/tex]9=1/2[tex]M_{2}[/tex]25
[tex]\frac{M_{1} }{M_{2} }[/tex] =[tex]\frac{25}{9}[/tex]
We now have two tappers that are tapping the surface of the water together. They are tapping in sync (both are hitting the surface at the same time). A small cork is sitting in the tank at the position of the small brown circle. As the stars continue to tap and the ripples from each star continue to move outward, what will happen to the cork
Answer:
The cork moves up and down.
Explanation:
The cork moves up and down because of the waves produce due to tapping the surface of water. The cork experience movement due to placed on the water surface so when the wave passes through the medium by tapping of water, movement of cork also occur. Cork has high volume and lower mass so it floats on the water surface and experience movement due to waves.
g A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 N of lift per square meter of wing. (The fact that a wing has a top and bottom surface does not double its area.) a)At takeoff the aircraft travels at 61.1 m/s, so that the air speed relative to the bottom of the wing is 61.1 m/s. Given the sea level density of air to be 1.29 kg/m3, how fast (in m/s) must it move over the upper surface to create the ideal lift
Answer:
The value is [tex]u = 72.69 \ m/s[/tex]
Explanation:
From the question we are told that
The amount of force a square meter of an aircraft wing should produce is [tex]F = 1000 \ N[/tex]
The air speed relative to the bottom of the wing is [tex]v = 61.1 \ m/s[/tex]
The air level density of air is [tex]\rho_s = 1.29\ kg/m^3[/tex]
Gnerally this force per square meter of an aircraft wing is mathematically represented as
[tex]F = \frac{1}{2} * \rho_s * A * [ u^2 - v^2 ][/tex]
Here u is the speed air need to go over the top surface to create the ideal lift
A is the area of a square meter i.e [tex]A = 1 \ m^2[/tex]
So
[tex]1000 = \frac{1}{2} * 1.29 * 1 * [ u^2 - 61.1 ^2 ][/tex]
=> [tex]u = 72.69 \ m/s[/tex]
NASA's Ames Research Center has a large centrifuge used for astronaut training. The centrifuge consists of a 3880-kg, 18.0-m-long tubular structure, which rotates about its center. Find the centrifuge's rotational inertia when two 105-kg seats are mounted at either end of the tube, 7.92 m from the rotation axis, and both are occupied by 72.6-kg astronauts. Treat the tube as a thin rod and the astronauts and seats as point masses.
Answer:
I = 1.27×105 kg⋅m2
Explanation:
The weight of an astronaut plus his space suit on the Moon is only 319 N. How much (in N) do they weigh on Earth?
Answer:
The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.
Explanation:
Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it. This law indicates that the net force applied on a body is proportional to the acceleration that the body acquires. The constant of proportionality is the mass of the body, so Newton's second law is expressed in the following formula:
F = m*a
Where:
F is the net force. It is expressed in Newton (N) m is the mass of the body. It is expressed in kilograms (Kg). a is the acceleration that the body acquires. It is expressed in meters over second squared (m/s²).The weight of an astronaut plus his space suit on the Moon is only 319 N. Then, being:
F= weight= 319 Nm= ?a = acceleration of the Moon's gravity, whose value is 1.62 m/s²you get:
319 N= m* 1.62 m/s²
Solving:
[tex]m=\frac{319 N}{1.62 \frac{m}{s^{2} } }[/tex]
m=196.91 kg
The mass is an invariable quantity, regardless of the planet in which the astronaut plus his space suit on the Moon is, then you have:
F= weight= ?m= 196.91 kga = acceleration of the Earth's gravity, whose value is 9.81 m/s²replacing in the definition of force:
Weight= 196.91 kg* 9.81 m/s²
Weight= 1,931.69 N
The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.
8
9
TIME REMAINING 10:34
Which statement describes an atomic nucleſus?
An atomic nucleus is negatively charged.
An atomic nucleus has no electrical charge.
An atomic nucleus consists of mostly empty space.
An atomic nucleus contains most of the atom's mass,
An atomic nucleus . . .
-- contains all of the atom's positive charge
-- contains almost all of the atom's mass
-- contains none of the atom's negative charge.
Answer:
An atomic nucleus . . .
-- contains all of the atom's positive charge
-- contains almost all of the atom's mass
-- contains none of the atom's negative charge.
Explanation:
yaaaaaa what the person on top said
A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Approximately what pitch does he hear after the truck passes and is moving away?
Answer:
The pitch that he hears after the truck passes and is moving away is 819.6 Hz.
Explanation:
The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:
[tex] f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}} [/tex]
Where:
[tex]f[/tex]: is the perceived frequency
[tex]f_{0}[/tex]: is the emitted frequency
[tex]v_{s}[/tex]: is the speed of sound = 340 m/s
[tex]v_{o}[/tex]: is the speed of the observer = 0 (he is not moving)
[tex]v_{f}[/tex]: is the speed of the fire truck
First, we need to find the speed of the fire truck. When it approaches the observer we have:
[tex] f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}} [/tex]
[tex] 950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}} [/tex]
[tex] v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz} [/tex]
[tex] v_{f} = 25.05 m/s [/tex]
Hence, the speed of the fire truck is 25.05 m/s.
Now, we can calculate the pitch that the observer hears after the truck passes:
[tex] f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}} [/tex]
[tex] f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s} [/tex]
[tex] f = 819.6 Hz [/tex]
Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.
I hope it helps you!
A student travels 4.0m East, 8.0m South, 4.0m west, and finally 8.0m north. What is her displacement? What distance did she travel?
no cap bro bro i thinks its poop Explanation:
Draw the Free- Body diagram of the 37 kilogram glass falling to the floor in a vacuum.
Then, use Newton’s Second Law to calculate how much force the glass hits the floor with.
Answer:
362.6 N
Explanation:
[tex]F_{g}=mg[/tex]
[tex]F_{g}=37\cdot9.8[/tex]
[tex]F_{g}=362.6\ N[/tex]
Therefore, the force that the glass hits the floor with is 362.6 N
A 3 kg exercise ball is held 2m above the ground. What is the gravitational potential energy?
Answer:
58.56 J
Explanation:
Since the formula for gravitational potential energy is:
GE = m x g x h - where m = mass (kg), g = acceleration due to gravity (9.81 m/s²), h = height (m)
GE= 3 x 9.81 x 2
GE = 58.86 J
Hope this helps
In compressed state, a spring 3.00 meters long hanging from the ceiling has a potential energy of 2.0 joules. If the entire potential energy is used to release a ball of mass
Answer:
0.068kg
Explanation:
In compressed state, a spring 3.00 meters long hanging from the ceiling has a potential energy of 2.0 joules. If the entire potential energy is used to release a ball of mass
Potential energy is expressed using the formula
PE = mgh
m is the mass
g is the acceleration due to gravity = 9.8m/s²
h is the height = 3.0m
PE = 2.0Joules
Required
Mass of the ball
Substitute the given values into the formula as shown;
2.0 = m(9.8)(3)
2 = 29.4m
m = 2/29.4
m = 0.068kg
Hence the mass of the ball is 0.068kg
Light of intensity So and polarized horizontally passes through three polarizes. The first and third are horizontal, but the second is oriented 0.3927 rad to the horizontal. In terms of So , what is the intensity of the light that passes through the set of polarizers
Answer: the intensity of the light that passes through the set of polarizers is 0.7285 S₀
Explanation:
based on the data in the question;
As the first polarizer lets all the light through because its plane of polarization is not different from light.
The second polarizer has 2 effects;
firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355
Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.
Hence;
after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.
Therefore
the Overall reduction is by a factor of 0.85355 × 0.85355 S₀
= 0.7285 S₀
Therefore the intensity of the light that passes through the set of polarizers is 0.7285 S₀
calculate the number of molecules of hydrogen and carbon present in 4 g of methane?
Answer: 6.022×10²³ molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.
A small hole P is made in a piece of cardboard. The hole is illuminated by a torch as shown in Fig. 16.3. The pencil of light coming out of the hole falls on a mirror.
5th question
Answer:
According to law of reflection i know in case of plane mirror the angle of reflection is equal to the angle of incidence. So,if you placed the eye on point A the hole can be seen.
Explanation:
A solid sphere made of plastic density of 1350 kg/m3 has a radius of 35.0 cm. It is suspended by a massless cord. 75% of its volume is in water and 25% of it is in oil. The density of water is 1000 kg/m3 and the density of the oil is 850 kg/m3. What is the total buoyant foce on the sphere
Answer:
B_total = 1694 N , T = - 937.7 N
Explanation:
This is an exercise of the Archimedes principle that establishes that the thrust of a liquid is equal to the weight of the dislodged volume
B = ρ g V_body
For this case we will assume that the weight of the body is in equilibrium with the thrust of the liquids and the tension of the rope
B₁ + B₂ - W + T = 0
suppose liquid 1 is water and liquid 2 is oil
ρ₁ g V₁ + ρ₂ g V₂ = W
for body weight let's use the definition of density
ρ = m / V
m = ρ V
we substitute
T = ρ g V - (ρ₁ g V₁ + ρ₂ g V₂)
In the problem we are told that the volume in the water is 75% and the volume in the oil is 25% of the body's volume.
T = ρ g V - g (ρ₁ 0.75 V + ρ₂ 0.25 V)
let's calculate the volumes
Body
V = 4/3 π r³
liquid 1 (water)
V₁ = 0.75 V = ¾ V
liquid 2 (oil)
V₂ = 0.25 V = ¼ V
we substitute
T = ρ g [tex]\frac{4}{3}[/tex] π r³ - g (ρ₁ [tex]\frac{3}{4}[/tex] [tex]\frac{4}{3}[/tex] π r³ + ρ₂ [tex]\frac{1}{4}[/tex] [tex]\frac{4}{3}[/tex] π r³)
T = [tex]\frac{4}{3}[/tex] ρ g r³ - g π r³ (ρ₁ + [tex]\frac{1}{3}[/tex] ρ₂)
The term of the floating force is
B_total = g π r³ (ρ₁ + [tex]\frac{1}{3}[/tex] ρ₂)
let's calculate its value
B_total = 9.8 π 0.35³ (1000 + ⅓ 850)
B_total = 1694 N
therefore the tension in the string is
T = [tex]\frac{4}{3}[/tex] 1350 9.8 0.35³ - 1694
T = 756.3 - 1694
T = - 937.7 N
The negative sign indicates that the system tends to come out of the liquid, for which a downward force must be applied to keep it in position.
A rod is made of three segments of equal length with different masses. The total mass of the rod is 6m. Will the moment of inertia of the rod be (i) greater about the left end, (ii) greater about the right end, or (iii) the same about both ends
Answer: (iii) the same about both ends
Explanation:
The moment of inertia is the sum of the square of the distance from the axis of massage and rotation of each length of the rod. The moment of inertia can be expressed as I = imiri2. The connection of the rod is the product of the moment length and distance (square), so it is the same at both ends.
The moment of inertia depends on the distribution of mass and the square of the distance from the axis.
The moment of inertia of the rod is the same about both ends. Hence, option (iii) is correct.
What is the moment of inertia?The degree measure of the resistance of an object towards an angular acceleration about the given axis is known as the moment of inertia of an object.
Given data -
The total mass of rod is, M = 6m.
The moment of inertia is the sum of the square of the distance from the axis of massage and rotation of each length of the rod. The mathematical expression is given as,
[tex]I = M \times r^{2}[/tex]
Since the connection of the rod is the product of the moment length and distance (square), so it is the same at both ends.
Thus, we can conclude that the moment of inertia of the rod is the same about both the ends.
Learn more about the moment of inertia here:
https://brainly.com/question/6953943
stopping potential becomes more and more negative why
Answer:
stopping potential is the negative potential applied to the circuit to stop the moving electrons so as to stop the flow of current
for high current high negative potential is applied
A rotating space station simulates artificial gravity by means of centripetal acceleration at the rim. The radius of the station is 1156 m and the apparent acceleration of gravity at the rim is 6.13 m/s2. What is the rotation rate of the station in rpm (revolutions per minute).
a= 1156× 6.13= 7086.28
Explanation:
a = m× m/ s^2
Roughly speaking, the radius of an atom is about 10,000 times greater than that of its nucleus. If an atom were magnified so that the radius of its nucleus became 2.0 cm, about the size of a marble, what would be the radius of the atom in miles
Answer:
0.124 miles
Explanation:
Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,
R = 10000r
= 10000 × 0.02 m
= 200 m
We know that 1 mile = 1609 m.
So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles
So, the radius of the atom in miles is 0.124 miles
A
B
с
4 teaspoons sugar
2 cups water
6 teaspoons sugar
2 cups water
4 teaspoons sugar
3 cups water
Which of these lemonade glasses is the most concentrated for sugar?
Ос
Oь
Oa
A horizontal force F is used to pull a 5 kg block across a floor at constant speed of 3 m/s. The frictional force between the block and the floor is 10 N. The net work done on the block in 1 minutes is most nearly:
Answer:
5× 3 over 10 = 1.5
Explanation:
F = 1m/s × kg over n
The net work done on the block in 1 minutes is most nearly 1800 Joule.
What is work?
A force must be applied in order for work to be completed, and there must also be motion or displacement in the force's direction. The amount of force multiplied by the distance moved in the force's direction is known as the work done by a force acting on an item.
Work has no direction and only magnitude. Work is a scalar quantity as a result.
Given that: A horizontal force F is used to pull a 5 kg block across a floor at constant speed of 3 m/s.
As the block is moving with uniform velocity; this force is equal to the frictional force in magnitude.
So, The net work done on the block in 1 minutes is =
force× displacement
= force × velocity × time
= 10 × 3 × 60 Joule
= 1800 Joule.
Learn more about work here:
https://brainly.com/question/18094932
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An l-c cirucit with a 70 mh inductor and a ,54 F capacitor oscillates. The maximum charge on the capacitor is 11.5 C. What are the oscillation frequency and the maximum current in this circuit
This question is incomplete, the complete question is;
An l-c cirucit with a 70 mh inductor and a 0.54 μF capacitor oscillates. The maximum charge on the capacitor is 11.5 μC. What are the oscillation frequency and the maximum current in this circuit ;
Options
a) 1.07 kHz, 63.4 mA
b) 4.38 kHz, 101.3 mA
c) 6.74 kHz, 55.7 mA
d) 2.31 kHz, 93.5 mA
e) 0.82 kHz, 59.1 mA
Answer:
the oscillation frequency and the maximum current in this circuit are; 0.82 kHz and 59.1 mA respectively.
so Option e) 0.82 kHz, 59.1 mA is the correct answer
Explanation:
Given that;
inductor L = 70 mH = 70 × 10⁻³ H
Capacitor C = 0.54 μf = 0.54 × 10⁻⁶ f
Qmax on capacitor = 11.5 μf = 11.5 × 10⁻⁶ c
oscillation frequency in L-C circuit;
f = 1/2π√(LC)
we substitute our values;
f = 1/2π√(70 × 10⁻³ × 0.54 × 10⁻⁶ )
f = 0.0818 × 10⁴ Hz
f = 0.082 × 10³ Hz ≈ 0.82 kHz
Maximum circuit in L-C circuit is given by
I_max = Qmax/√(LC)
we substitute
I_max = 11.5 × 10⁻⁶ / √(70 × 10⁻³ × 0.54 × 10⁻⁶ )
= 59.1 × 10³ A ≈ 59.1 mA
Therefore the oscillation frequency and the maximum current in this circuit are; 0.82 kHz and 59.1 mA respectively.
so Option e) 0.82 kHz, 59.1 mA is the correct answer
How does radiation transfer thermal energy from the Sun to Earth?
Answer:
The thermal energy is carried by electromagnetic waves
Explanation:
There are three types of transfer of heat (thermal energy):
- Conduction: conduction occurs when two objects/two substances are in contact with each other. The heat is transferred from the hotter object to the colder object by the collisions between the molecules of the two mediums.
- Convection: convection occurs when a fluid is heated by an external source of heat. The part of the fluid closer to the heat source gets warmer, therefore it becomes less dense and it rises, and it is replaced by the colder part of the fluid, which is colder. Then, this part of fluid is heated as well, so it gets warmer, it rises, etc.. in a cycle.
- Radiation: radiation occurs when thermal energy is carried by electromagnetic waves. Since electromagnetic waves do not need a medium to propagate, this is the only method of heat transfer that can occur through a vacuum (so, in space as well).
Indeed, the Sun emits a lot of electromagnetic radiation, which travels through space and eventually reaches the Earth, heating it.
Explanation:
Pls Help physics 8th class question
Answer:
angle of reflection and angle of incident is always equal
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is
its average speed during the time from t 5 seconds to t - 10 seconds?
A. 2 meters/second
В. 3 meters/second
С. 4 meters/second
D. 5 meters/second
E. 6 meters/second
write the characteristic of aluminum
Answer:
see below
Explanation:
alluminium is,
1.lustrous
2.highly malleable
3.reactive metal
4.some times acts as non metal
5.good conductor
6.obtained from bauxite
7.Atomic number 13 so electrons and protons are 13
8.neurons are 14
9.ductile
10.melting point is very high approximately 660 degree celsius.
Answer:
It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.
Explanation:
Which one of the following is insoluble in water?
Food coloring
Lemon slices
Rock salt
White vinegar
Answer:
Lemon slices is the correct answer
Answer:
food coloring
Explanation:
i think food coloring is because it's just water with food coloring and that's it
A man stands on top of a cliff and shouts.
He hears the echo on the third clap when
he claps his hand at the rate of two claps
per second. What is the distance between
man & the obstruction, if the velocity of
sound is 320 m/s
[tex] \small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x[/tex]
[tex] \small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1[/tex]
[tex] \bf \to \: x = \frac{320}{2} m = 160m[/tex]
[tex] \small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m[/tex]
