At which point is the kinetic energy the greatest?

At Which Point Is The Kinetic Energy The Greatest?

Answers

Answer 1

Answer:

Kinetic energy is energy an object has because of its motion and is equal to one-half multiplied by the mass of an object multiplied by its velocity squared (KE = 1/2 mv2). Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point.

Explanation:

here is an example Where is the apple when it has the most kinetic energy? When the apple is falling and is right before it hits the ground. As an object falls under the influence of gravity, kinetic energy and potential energy are equal everywhere/at the halfway point only. 10. As an object falls under the influence of gravity, potential energy is greater than kinetic energy after halfway point/ before the halfway point

Answer 2

In the roller coaster, the kinetic energy is greatest at point X.

The kinetic energy of a body is given by 1/2mv^2.

Where;

m = mass of the object

v =velocity of the object.

For a roller coaster, the velocity is maximum at the lowest points of the roller coaster. If the velocity is maximum at the lowest point, it also follows that the kinetic energy is also maximum at the lowest point. Hence point X has the highest kinetic energy.

Learn more: https://brainly.com/question/999862


Related Questions

the great pyramid of khufu (giza, egypt) is about 140m tall. How much work would be required to raise an average - sized pyramid black (2.5 tons) to this height?

Answers

Omg I just had this ? But I forgot what I put

your stopped at a red light. You've checked the intersection to see that it is clear of vehicles and pedestrians, unless a tells you not, you may then?

Answers

Answer:

Unless you are at a red light you may not proceedYou pose a threat to other drivers who are following the instructions and ethics.

difference between lower fixed point and upper fixed point​

Answers

Answer:

The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.

Explanation:

A car accelerates at a rate of 2.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 28.0 m/s?

Answers

Answer:

[tex]\huge\boxed{\sf Time = 10 \ seconds}[/tex]

Explanation:

Given:

Initial Velocity = [tex]\sf V_{i}[/tex] = 8.0 m/s

Final Speed = [tex]\sf V_{f}[/tex] = 28.0 m/s

Acceleration = a = ?

Required:

Time = t = ?

Formula:

[tex]\sf a = \frac{V_{f} - V_{i}}{t}[/tex]

Solution:

[tex]\sf 2 = \frac{28-8}{t} \\\\2 = \frac{20}{t} \\\\t = \frac{20}{2} \\\\t = 10 \ seconds\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

what is the correct answer?

Answers

Answer:

i cant explain well but the answer is letter b

x-5

Explanation:

dont report me or i will report you too

Answer:

x-5 is the answer

Explanation:

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What is the kinetic energy of a 0.150 kg
object moving at a velocity of 100m/s?

Answers

Answer:

750J

Explanation:

Given parameters:

Mass of the object   = 0.15kg

Velocity of the object  = 100m/s

Unknown:

Kinetic energy of the body  = ?

Solution:

The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;

        K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass of the body

v is the velocity

 Now insert the parameters and solve;

     K.E  = [tex]\frac{1}{2}[/tex]  x 0.15 x 100²   = 750J

Can someone help me with this question??

Answers

Answer:

3.3

Explanation:

B- 3.3

Merry Christmas! Please mark me brainliest❤️❤️

A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum of the box? (unit = kg*m/s)

Answers

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

HELP ASAP!! WILL TRY TO GIVE BRAINLIEST

Describe chromatin and how it changes.

Answers

Answer:

Chromatin is a mass of genetic material composed of DNA and proteins that condense to form chromosomes during eukaryotic cell division. Chromatin is located in the nucleus of our cells . The primary function of chromatin is to compress the DNA into a compact unit that will be less voluminous and can fit within the nucleus.

I hope this helps

Explanation:

Answer: Me again! Chromatin is a complex of DNA and proteins that forms chromosomes within the nucleus of eukaryotic cells. Nuclear DNA does not appear in free linear strands; it is highly condensed and wrapped around nuclear proteins in order to fit inside the nucleus. Chromatin exists in two forms.

Explanation: Hope this helps! Happy Holidays!

what is the correct answer?

Answers

Answer:

3.2

Explanation:

I remember taking this quiz and I think that one is correct

  URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)

1 point

a) 366,000 J

b) 3,660,000 J

c) 2.73 J

d) 20.73 J​

Answers

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is​

Answers

To Find :

The acceleration of the heavier object.

Solution :

Force of gravitation on lighter object by heavier object is :

[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]

Acceleration of lighter object is given by :

[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex]          .....1)

Now, acceleration of heavier object when separation between them is 25 km :

[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)

Putting value of m in equation 2, we get :

[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]

Therefore, the acceleration of the heavier object is​ 100 m/s².

help!!!! please!!! i’m not sure what the answer is for both questions please

Answers

Answer:

a.) 600N

b.) 2 m/s^2

Explanation:

a.)

In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.

Basically: Force = mass * acceleration ; F = ma

Since both mass and acceleration are already given, just plug them into the formula and solve for force:

Mass = 200kg

Acceleration = 3m/s^2

F = m * a = 200 * 3 = 600kg * m/s^2 = 600N

b.)

In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.

To calculate net force:

Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.

Net Force: 8N - 4N = 4N

Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left

Finally, you find acceleration using newton's 2nd law, F = ma.

Since you already know mass and net force, plug in to solve for acceleration:

4N = 2kg * a

a = 4 N / 2kg = 2m/s^2

Free fall differs from terminal velocity, in that during free fall

A.
only air resistance is acting on an object

B.
only gravity is acting on an object

C.
air resistance and gravity are acting on an object with unequal magnitudes

D.
air resistance and gravity are acting on an object with equal magnitudes

Answers

Answer:

B

Explanation:

A wheelchair ramp is 5.2 m long and 0.8 m high. Calculate the ramp’s mechanical advantage

Answers

Answer:

5

Explanation:

62

Dawn and Timothy are sailboating in Lake Obewon. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.39 m/s/s. How far are they from the shore after 18 seconds? *

Answers

Answer:

The value is [tex]s =63.18 \ m[/tex]  

Explanation:

From the question we are told that

   The uniform  acceleration is   [tex]a = 0.39 \ m/s^2[/tex]

   The time considered is [tex]t = 18 \ seconds[/tex]

Generally the from kinematic equation we have that

          [tex]s = ut + \frac{1}{2} at^2[/tex]

Given that the boat started from rest , the initial velocity is  u =  0  m/s  

So

       [tex]s = 0 * 18 + \frac{1}{2} *0.39 * 18^2[/tex]

=>      [tex]s =63.18 \ m[/tex]

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?

Answers

Answer:

a. t = 2.02 s

b. d = 20.2 m

Explanation:

Horizontal Motion

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

[tex]\displaystyle d=v.t[/tex]

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

b.

The range is:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

n=Q/e formula of this?

Answers

Answer:

Its not just a mere formula . It tells a hell lot about charges .

q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.

This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)

Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as

q=ne.

Hence the formula .

I hope you got what I want to say .

Thanks for reading .

The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed along axes of AB and AC. Set F=500N

Answers

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ [tex]\angle BCA = (90-30)[/tex]

⇒             [tex]=60^{\circ}[/tex]

then,

⇒ [tex]\angle BAC=(180-45-60)[/tex]

⇒             [tex]=75^{\circ}[/tex]

Now,

The corresponding angle will be:

⇒ [tex]\angle FAC=60^{\circ}[/tex]

⇒ [tex]\angle FAB=70+60[/tex]

⇒             [tex]=135^{\circ}[/tex]

Aspect of F across the AC arm will be:

= [tex]F\times cos(60)[/tex]

On putting the values of F, we get

= [tex]500\times (.5)[/tex]

= [tex]200 \ Newton[/tex]

Component F along the AC (in magnitude) will be:

= [tex]F\times cos(135)[/tex]

= [tex]500\times (-.707)[/tex]

= [tex]-353.5 \ N \[/tex]

write any one advantage and disadvantage of eddy current​

Answers

Explanation:

[tex]advantage[/tex]

It is Sensitivity to surface defects. ...

[tex]disadvantage[/tex]

There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated

Please mark as brainliest answer

who is the best soccer player?

Answers

Me I have it the soccer soccer
Lionel Messi. but that’s my opinion.

A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is the force opposing the motion of the car

Answers

Answer:

5000 N

Explanation:

Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.

Since the car is moving with constant velocity, a = 0.

So, F - f = ma

F - f = m(0)

F - f = 0

F = f.

Since F = 5000 N and F = f, f = 5000 N.

So, the opposing force is 5000 N

The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

The opposing force can be calculated by the formula,

F - f = ma

Where,

F = driving force = 5000 N,

f = opposing force = ?

m = mass of car = 11000 N

a = acceleration of car

Since, the car is at constant velocity, a = 0.

So,

F - f = m(0)

F - f = 0

F = f.

Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

To know more about opposing force,

https://brainly.com/question/866413

If a student is sitting in their chair and the leg of the chair breaks the student will __________ toward the floor because the gravity is a greater force.
A.Accelerate
B.Force
C.Balance
D.Speed

Answers

Answer:

theyll accelerate towards the floor :)

C because it gonna balance

A billiard ball bangs against a side bumper, giving the ball a speed of 5 m/s. If the
ball has a mass of 0.15 kg, what is the ball's kinetic energy in joules?

Answers

Answer:

1.875 joules

Explanation:

K.E=1/2 mv²

K.E=1/2 0.15×5²

K.E=1.875 joules

Which of these waves has the greatest wavelength? Group of answer choices Wave shown with 2 wavelengths. Wave shown with 3 wavelengths. Wave shown with 1 wavelength stretch over a short distance. Wavelength shown with 1 wavelength stretched over a long distance.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the figure. However, wavelength can be described as the distance between two crests (identical points) of a wave (as illustrated in the picture attached). Thus, a wave with a large/great wavelength must have a long distance between the two crests and has nothing to do with the number of crests/wavelengths since distance between crests could also be small.

Hence, what appears to be the correct option is the last option (Wavelength shown with 1 wavelength stretched over a long distance).

Answer:

Its B.

Explanation:

Im took the exam.

You’ve been in a car traveling at 80 km/hr. How many hours will it take to travel 640 km?

Answers

I’m pretty sure it’s 8 hours
It’s 8 hours I know I had the question

Determine the velocity of a wave with frequency 10Hz and a wavelength of 10m.

Answers

Answer:

A wave with a frequency of 10 Hz and a wavelength of  10 m should have a velocity of 100 meters per second (m/s)

Explanation:

I WILL MARK BRAINLIEST!
A 2.0 kg bullet is fired into a sandbag sitting on a wagon. The combined mass of the wagon and the sandbag is 4.5 kg. a) If the wagon/sandbag/bullet moved together with a speed of 0.22 m/s immediately after impact with the bullet, with what speed did the bullet enter the sandbag? b) Is this an elastic or inelastic collision? Explain.

Answers

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

the multimeter functions as an ammeter

Answers

Answer: What?

Explanation:

A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.

Answers

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

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