balance the following equation in acidic solution using the lowest possible integers and give the coefficient of h . mno4-(aq) h2c2o4(aq) → mn2 (aq) co2(g)

Answers

Answer 1

The balanced equation for the oxidation of oxalic acid by permanganate ion in acidic solution is

8H⁺ + MnO₄⁻ + 5H₂C2₂O₄ → Mn²⁺ + 10CO₂ + 8H₂O

Since the coefficient of H2C2O4 is 1, the coefficient of H is 2. Therefore, the answer is 2.

The balanced equation for the oxidation of oxalic acid by permanganate ion in acidic solution is as follows: Step-by-step solution:

In acidic medium:

First, determine the oxidation states of the atoms:In MnO₄⁻, Mn has an oxidation state of +7.In H₂C2₂O₄, the oxidation state of C is +3, while that of H is +1In Mn²⁺, the oxidation state of Mn is +2, while in CO₂, C has an oxidation state of +4.In the redox reaction, the oxidation number of Mn decreases from +7 to +2, while that of C increases from +3 to +4.

Balance the equation by adding water molecules, hydrogen ions (H⁺) and electrons (e-) to both half-reactions so that they have an equal number of electrons on both sides. This is called the half-reaction method.

Therefore, the balanced equation is as follows:

MnO₄⁻ + 8H⁺ + 5e- → Mn²⁺ + 4H₂O (reduction half reaction)

H₂C2₂O₄ → 2CO₂ + 2H⁺ + 2e- (oxidation half reaction)

The ionic equation is: MnO₄⁻ + 8H⁺ + 5e- + 5H₂C2₂O₄ → Mn²⁺ + 10CO₂ + 8H₂O

Add the two half-reactions, and then cancel out the common species.

8H⁺ + MnO₄⁻ + H₂C2₂O₄ → Mn²⁺ + 10CO₂ + 8H₂O

The coefficients of the balanced equation are 5, 8, 1, 1, 10, and 8 for MnO₄⁻, H⁺, H₂C2₂O₄, Mn²⁺, CO₂, and H₂O, respectively.

Since the coefficient of H₂C2₂O₄ is 1, the coefficient of H is 2. Therefore, the answer is 2.

Learn more about balanced equation at: https://brainly.com/question/26694427

#SPJ11


Related Questions

Balance the following equation in acidic conditions. Phases are optional. C2O4^2- + MnO2 --> Mn^2+ + CO2

Answers

The balanced equation in acidic conditions for the reaction is:

C2O4^2- + 2 MnO2 + 4 H+ → 2 Mn^2+ + 4 CO2 + 2 H2O

To balance the equation, we start by balancing the atoms that appear in multiple species. In this case, there are two Mn atoms on the right side, so we place a coefficient of 2 in front of MnO2 on the left side.

Next, we balance the oxygen atoms by adding water molecules (H2O) to the appropriate side. Here, we add 2 water molecules on the right side.

Then, we balance the hydrogen atoms by adding protons (H+) to the opposite side. In this case, we add 4 H+ ions on the left side.

Finally, we balance the charge by adding electrons (e-) to the side that has a higher negative charge. In this case, we add 8 electrons to the left side. By following these steps, we obtain the balanced equation as shown above.

To know more about acidic conditions, refer to the link:

https://brainly.com/question/2497404#

#SPJ11

write the cell notation for an electrochemical cell consisting of an anode where al(s) is oxidized to al3 (aq) and a cathode where fe3 (aq) is reduced to fe2 (aq) at a platinum electrode. assume all aqueous solutions have a concentration of 1 mol/l and gases have a pressure of 1 bar. subscriptsuperscript help

Answers

The electrochemical cell consisting of an anode where Al(s) is oxidized to Al3+(aq) and a cathode where Fe3+(aq) is reduced to Fe2+(aq) at a platinum electrode can be represented by the following cell notation: Al(s) | Al3+(aq) || Fe3+(aq) | Fe2+(aq) | Pt(s)

Explanation: The cell notation for an electrochemical cell typically includes the symbols of the reactants and products involved in the redox reaction, along with their corresponding phases and charges, separated by vertical lines. The anode is placed on the left side of the vertical lines, and the cathode is placed on the right side. A double vertical line represents the salt bridge, or the porous membrane that separates the two half-cells and allows the migration of ions without mixing the solutions.

In the given question, the half-reactions can be written as follows:

Anode: Al(s) → Al³⁺(aq) + 3e⁻Cathode: Fe³⁺(aq) + e⁻ → Fe²⁺(aq)By convention, the more negative electrode is placed on the left side, and the more positive electrode is placed on the right side. In this case, Al(s) is more negative than Fe2+ (aq), so it should be placed on the left side, and Fe3+ (aq) should be placed on the right side. The Pt(s) indicates that platinum is used as an inert electrode.

Therefore, the cell notation can be written as: Al(s) | Al³⁺(aq) || Fe³⁺(aq) | Fe²⁺(aq) | Pt(s)Note that the vertical line in the middle represents the salt bridge, which could be represented by two vertical lines (||) or by a single horizontal line with two vertical lines at its ends (↔).

To know more about Anode refer to:

https://brainly.com/question/17109743

#SPJ11

the reaction of acid chlorides and anhydrides with amines both require two equivalents of the amine, but for different reasons. which of the following statements is true?

Answers

The acid chlorides and anhydrides require two equivalents of amine, but for different reasons.

Acid chlorides react with amines to form amides through a nucleophilic substitution reaction. This reaction requires two equivalents of the amine because one equivalent acts as a nucleophile, attacking the carbonyl carbon of the acid chloride, while the other equivalent serves as a base, neutralizing the resulting HCl byproduct.

On the other hand, anhydrides react with amines to form amides through an acyl substitution reaction. In this case, two equivalents of the amine are required to ensure complete conversion, as one equivalent reacts with each carbonyl group of the anhydride. Understanding these distinct mechanisms is crucial for proper reaction design and achieving desired products.

Learn more about Anhydrides

brainly.com/question/30655084

#SPJ11

draw a structural formula for the major organic product of the reaction shown hbr.

Answers

To draw a structural formula for the major organic product of the reaction shown hbr, we need to know what the reactants are.

Let the reaction be between an alkene and hydrogen bromide (HBr) in the presence of a peroxide catalyst.

The reaction mechanism for this reaction is called a free radical addition.

The first step is the initiation step, where the peroxide catalyst (ROOR) breaks down into two free radical species:

ROOR → 2 RO•

The next step is the propagation step, which occurs in two stages.

In the first stage, the hydrogen bromide (HBr) reacts with the free radical to form a new radical:

HBr → H• + Br•

In the second stage, the alkene reacts with the new radical to form a new free radical:

CH2=CH2 + H• → CH3CH2• + H•

The final step is the termination step, where two free radicals react to form a stable product:

RO• + RO• → ROR

CH3CH2• + Br• → CH3CH2Br

The major organic product of this reaction is 1-bromopropane which has the structural formula CH3CH2Br .

Learn more about the structural formula:

brainly.com/question/31115811

#SPJ11

which of these is an example of a base?group of answer
a)HCl
b)Ca(OH)2
c)CH3COOH
D)H2SO4

Answers

The correct answer is b) Ca(OH)2. It is an example of base.

A base is a substance that can accept protons (H+) or donate hydroxide ions (OH-) in a chemical reaction. Let's analyze the given options:

a) HCl: HCl is an acid, not a base. It donates protons (H+) and is classified as a strong acid.

b) Ca(OH)2: Ca(OH)2 is an example of a base. It contains the hydroxide ion (OH-) and can donate these ions in a reaction. It is known as calcium hydroxide or hydrated lime.

c) CH3COOH: CH3COOH is an acid, commonly known as acetic acid or vinegar. It donates protons (H+) and is classified as a weak acid.

d) H2SO4: H2SO4 is an acid, known as sulfuric acid. It donates protons (H+) and is classified as a strong acid.

Therefore, among the given options, b) Ca(OH)2 is the example of a base.

for more questions on base
https://brainly.com/question/13773045
#SPJ8

what element is being oxidized in the following redox reaction? h2o2(l) clo2(aq) → clo2-(aq) o2(g)

Answers

The element that is being oxidized in the given redox reaction is hydrogen (H).Redox reaction:A redox reaction is a type of chemical reaction that involves both oxidation and reduction, which occur simultaneously.

During this reaction, the oxidation state of atoms changes. In the given redox reaction:2H2O2(l) + 2ClO2(aq) → 2ClO2-(aq) + O2(g) + 2H2O(l)The hydrogen (H) in H2O2(l) is being oxidized because its oxidation state changes from -1 to 0 as it forms H2O(l).Oxidation is the process of losing electrons or increasing oxidation state.

The oxidation state of an atom or molecule is the charge that an atom would have if all its bonds were ionic. In the given reaction, the oxidation state of hydrogen changes from -1 to 0.In the reaction, the oxidation state of Cl changes from +3 to +5 as ClO2 is converted to ClO2-. Thus, chlorine (Cl) is being reduced.

To know more about oxidation visit :

https://brainly.com/question/13182308

#SPJ11

find the percent dissociation of a 0.100 mm solution of a weak monoprotic acid having ka=1.8×10−3ka=1.8×10−3 .

Answers

The percent dissociation of a 0.100 M solution of a weak monoprotic acid having Ka = 1.8 × 10-3 can be calculated using the following steps.

Calculate the concentration of H+ ions produced in the solution by dissociation of the acid. Let the concentration of H+ ions be [H+].[H+] = √(Ka[C])where Ka is the acid dissociation constant and C is the concentration of the weak acid. Given that Ka = 1.8 × 10-3 and C = 0.100 M, we have:[H+] = √(1.8 × 10-3 × 0.100)= 0.012

Calculate the percent dissociation using the equation:% dissociation = [H+] / C × 100%=[0.012 / 0.100] × 100%= 12%Therefore, the percent dissociation of a 0.100 M solution of a weak monoprotic acid having Ka = 1.8 × 10-3 is 12%.

To know more about monoprotic  visit :

https://brainly.com/question/32092334

#SPJ11

Determine the velocity of a marble (m = 8.66 g) with a wavelength of 3.46 × 10-33m.
a.45.2 m/s
b.11.3 m/s
c.22.1 m/s
d.38.8 m/s
e.52.9 m/s

Answers

The velocity of the marble with a wavelength of 3.46 × 10^-33 m is approximately 22.1 m/s.

So, the correct answer is C.

The velocity of a marble with a wavelength of 3.46 × 10^-33 m can be calculated using the de Broglie equation.

The equation states that the wavelength (λ) of a particle is inversely proportional to its momentum (p).

Therefore, p = h/λ

where h is the Planck's constant. The velocity (v) of the particle is then given by v = p/m

where m is the mass of the particle.Using the given values:

Mass of marble, m = 8.66 g = 0.00866 kg

Wavelength of marble, λ = 3.46 × 10^-33 m

Planck's constant, h = 6.626 × 10^-34 J·s

Momentum of marble, p = h/λ = (6.626 × 10^-34 J·s)/(3.46 × 10^-33 m) = 0.191 kg·m/s

Velocity of marble, v = p/m = (0.191 kg·m/s)/(0.00866 kg) ≈ 22.1 m/s

Option (c) is the correct answer.

Learn more about wavelength at:

https://brainly.com/question/22984946

#SPJ11

Converting the velocity from m/s to the required unit of m/s, we get

:v = 2.642 × 10^-29 m/s × (1 m/1.0 × 10^0 nm) = 2.642 × 10^-20 m/s

Finally, rounding off to 3 significant figures, we get:v = 38.8 m/sHence, the velocity of the marble is 38.8 m/s.

The correct answer is d. 38.8 m/s. Here is the explanation:We are given:mass of the marble, m = 8.66 g Wavelength of the marble, λ = 3.46 × 10^-33mWe are to determine the velocity of the marble, v, using the de Broglie wavelength equation:λ = h/mv whereh is the Planck's constant = 6.626 × 10^-34 J.s Substituting the given values,

we get:3.46 × 10^-33 = (6.626 × 10^-34)/(8.66 × 10^-3)v

Solving for v, we get:

v = (3.46 × 6.626)/(8.66) = 2.642 × 10^-32 m/s

Dividing by

10^-3, we get:v = 2.642 × 10^-29 m/s

Now, converting the velocity from m/s to the required unit of m/s, we get

:v = 2.642 × 10^-29 m/s × (1 m/1.0 × 10^0 nm) = 2.642 × 10^-20 m/s

Finally, rounding off to 3 significant figures, we get:v = 38.8 m/sHence, the velocity of the marble is 38.8 m/s.

To know more about velocity visit:

https://brainly.com/question/30559316

#SPJ11

in the process of water treatment, is the step in which water is sprayed into a fine mist allowing volatile compounds to evaporate.

Answers

The water treatment process you're referring to, in which water is sprayed into a fine mist to allow volatile substances to evaporate, is known as "air stripping" or "stripping."

In order to help remove volatile impurities like volatile organic compounds (VOCs) or specific gases like chlorine or ammonia, water is exposed to air during this step. Due to the increased surface area that the mist or small droplets give, the volatile chemicals move from the aqueous phase to the gas phase. The evaporating air and these volatile substances are subsequently eliminated from the system.

Given that some volatile pollutants have a propensity to partition into the gas phase rather than the liquid phase, air stripping is an efficient way to remove them from water. It is frequently utilised in the process of treating water, especially when handling contaminated groundwater or industrial effluent.

Hence, the step you are referring to in water treatment, where water is sprayed into a fine mist to allow volatile compounds to evaporate, is known as "air stripping" or "stripping."

To learn more about stripping, visit:

https://brainly.com/question/31261170

#SPJ11

what is the molarity of an unknown solution of cu2 whose absorbance is 0.6?

Answers

The molarity of an unknown solution of Cu2+ whose absorbance is 0.6 can be calculated using the Beer-Lambert law. The formula for calculating the molarity of a solution is as follows:Molarity of solution = Absorbance / (molar absorptivity x path length)

The Beer-Lambert law can be defined as the relationship between the concentration of a solution and the amount of light absorbed by that solution. It is mathematically expressed as follows: A = εlcwhere,A is the absorbance of the solution.ε is the molar absorptivity of the substance. l is the path length of the light through the solution. c is the concentration of the substance in the solution.

Rearranging the equation above, we have: c = A / (εl)Now, we can substitute the given values into the equation to obtain the molarity of the unknown solution of Cu2+.c = 0.6 / (19500 x 1) = 3.08 x 10^-5 M Therefore, the molarity of the unknown solution of Cu2+ is 3.08 x 10^-5 M.

To know more about molarity visit:

https://brainly.com/question/31545539

#SPJ11

balance each equation by inserting coefficients as needed.
equation1: C3H8+O2 ----> CO2+H2O
equation2: N2H4------> NH3+N2

Answers

In chemistry, balancing a chemical equation is the process of ensuring that the number of atoms of each element is the same on both sides of the equation. This is done by adding coefficients to the reactants and products. Balanced equations are as follows :

Equation 1: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Equation 2: N₂H₄ → 2NH₃ + N₂

To balance the given chemical equations, we need to make sure that the number of atoms of each element is the same on both sides of the equation.

Equation 1: C₃H₈ + O₂ → CO₂ + H₂O

To balance the equation, we can start by balancing the carbon atoms:

C₃H₈ + O₂ → 3CO₂ + H₂O

Next, let's balance the hydrogen atoms:

C₃H₈ + O₂ → 3CO₂ + 4H₂O

Finally, let's balance the oxygen atoms:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The balanced equation is: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

Equation 2: N₂H₄ → NH₃ + N₂

To balance this equation, we start by balancing the nitrogen atoms:

N₂H₄ → 2NH₃ + N₂

Next, let's balance the hydrogen atoms:

N₂H₄ → 2NH₃ + N₂

The equation is already balanced. N₂H₄ → 2NH₃ + N₂.

To know more about the balance the equation refer here :

https://brainly.com/question/31242898#

#SPJ11

what masses of dimethylamine and dimethylammonium chloride do you need to prepare 2.00 l of ph = 12.00 buffer if the total concentration of the two components is 0.500 m?

Answers

The equation for the formation of the dimethylamine and dimethylammonium chloride buffer is,CH3NH2(aq) + HCl(aq) ⇌ CH3NH3+(aq) + Cl−(aq)The equilibrium constant expression for this reaction is,Kc = [CH3NH3+][Cl−]/[CH3NH2][HCl]pH = pKa + log[base]/[acid].

Volume of solution (V) = 2.00 LTotal concentration of the two components = 0.500 mFrom the balanced equation of the buffer formation, 1 mole of acid reacts with 1 mole of base to form 1 mole of salt. Thus, moles of acid (HCl) = moles of salt (CH3NH3+) = 0.500 mol/L × 2.00 L = 1.00 moleNext, let x be the number of moles of base (CH3NH2) added, which will also be the number of moles of conjugate acid (CH3NH3+) formed.

Molar concentrations: [CH3NH2] = x/2.00 L[CH3NH3+] = x/2.00 L[HCl] = (1.00 – x)/2.00 L[Cl–] = (1.00 – x)/2.00 LUsing the equilibrium constant expression,Kc = [CH3NH3+][Cl−]/[CH3NH2][HCl]We can substitute molar concentrations of all species to getKc = [(x/2.00) × (1.00 – x)/2.00] / [(1.00 – x)/2.00 × x/2.00]Kc = (x/2.00)2 / (1.00 – x)From the pH of the buffer pH = pKa + log[base]/[acid]12.00 = pKa + log [x/2.00] / [(1.00 – x)/2.00]12.00 = 4.20 + log [x/2.00] / [(1.00 – x)/2.00]log [x/2.00] / [(1.00 – x)/2.00] = 12.00 – 4.20 = 7.80[x/2.00] / [(1.00 – x)/2.00] = 6.89x = 6.89 (1.00 – x)6.89x = 6.89 – 6.89x7.89x = 6.89x = 0.875 mol/LTherefore, mass of dimethylamine = Molar mass × number of moles = 45.05 g/mol × 0.875 mol/L × 2.00 L = 78.6 g .

To know more about equilibrium visit :

https://brainly.com/question/30694482

#SPJ11

A drug tagged with 9943Tc (half-life = 6.05 h) is prepared for a
patient. The original activity of the sample was 1.10 Bq. (a)
Calculate the time constant for this isotope. (b) Calculate the
activity A drug tagged with 99 43 Tc (half-life = 6.05 h) is prepared for a patient. The original activity of the sample was 1.10 Bq. (a) Calculate the time constant for this isotope. Note that your value shou

Answers

The time constant for the isotope is approximately 8.73 h. The activity of the sample after it has sat on the shelf for 2.00 h is approximately 0.98 Bq.

Here is the explanation :

(a) To calculate the time constant (τ) for the isotope, we can use the formula:

[tex]\tau = \frac{\ln(2)}{\lambda}[/tex]

Where:

ln(2) is the natural logarithm of 2, approximately 0.693

λ is the decay constant, which is equal to [tex]\frac{\ln(2)}{\text{half-life}}[/tex]

Given:

Half-life = 6.05 h

Calculating the decay constant:

[tex]$\lambda = \frac{\ln(2)}{6.05 h}$[/tex]

Substituting the values:

[tex]\[\tau = \frac{0.693}{\frac{\ln(2)}{6.05\,\text{h}}}\][/tex]

Simplifying:

τ ≈ 8.73 h

Therefore, the time constant for this isotope is approximately 8.73 h.

(b) To calculate the activity of the sample after it has sat on the shelf for 2.00 h, we can use the decay equation:

[tex]A(t) = A_0 * e^{-\lambda t}[/tex]

Where:

A(t) is the activity at time t

A₀ is the initial activity

λ is the decay constant

t is the time

Given:

Initial activity (A₀) = 1.10 Bq

Time (t) = 2.00 h

[tex]\lambda \approx \frac{\ln(2)}{6.05\,\mathrm{h}}[/tex]

Substituting the values:

[tex]A(t) = 1.10,\mathrm{Bq} \times e^{-\left(\frac{\ln(2)}{6.05,\mathrm{h}}\right) \times 2.00,\mathrm{h}}[/tex]

Calculating:

[tex]A(t) \approx 1.10\,\mathrm{Bq} \times e^{-0.1147}[/tex]

Therefore, the activity of the sample after it has sat on the shelf for 2.00 h is approximately X Bq (where X is the calculated value).

To know more about the isotope refer here :

https://brainly.com/question/27475737#

#SPJ11

Complete question :

A drug tagged with 9943Tc (half-life = 6.05 h) is prepared for a patient. The original activity of the sample was 1.10 Bq. (a) Calculate the time constant for this isotope. Note that your value should be in the same units that you will select below. 8.73 Unit : Oh % O 1/h OBq (b) Calculate the activity of the sample after it has sat on the shelf for 2.00 h. Note that your value should be in the same units that you will select below. X Unit : h O Bq O 1/h %

A sample of solid ammonium chloride was placed in an evacuated container and heated so that it decomposed to ammonia gas and hydrogen chloride gas. After heating the total pressure in the container was 4.4atm. Calculate the Kp at this temperature for the decomposition reaction NH4CL(s) <--> NH3(g) + HCl(g)
using the ICE table I have it as I 0 0
C x x
E x x
is this correct and if not how do I go about solving this problem correctly?

Answers

Therefore, the concentration of NH4Cl is considered to be constant and so it is not included in the expression for Kp. Hence, it is not possible to calculate Kp at this temperature for the given reaction.

The given balanced chemical equation is

NH4Cl(s) ⇌ NH3(g) + HCl(g)

The initial pressure of the system is 0 atm since ammonium chloride is in solid form.

When it is heated, it decomposes to NH3(g) and HCl(g).Let the partial pressure of NH3 be x atm and that of HCl be x atm.

Total pressure of the system = 4.4 atm

Now, according to the ideal gas law,

PV = nRT ……

(1)Here, P is the partial pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant and T is the temperature of the gas. The number of moles of NH3 and HCl are equal since the reaction is 1:1. Let the number of moles of NH3 and HCl be n. From the balanced chemical equation, 1 mole of NH4Cl decomposes to form 1 mole of NH3 and 1 mole of HCl. So, the initial number of moles of NH4Cl is n. Let the change in the number of moles of NH4Cl be x. So, the number of moles of NH4Cl left at equilibrium = n - x. At equilibrium, the number of moles of NH3 and HCl = n (from the balanced chemical equation).Volume of the system is constant. So, the volume occupied by NH3 and HCl together is equal to the volume occupied by NH4Cl initially. The pressure exerted by NH4Cl is negligible compared to the pressure exerted by NH3 and HCl. So, we can consider the pressure of NH4Cl to be zero.

Partial pressure of NH3 = x

Partial pressure of HCl = x

Total pressure of the system = 4.4 atm

Partial pressure of NH3 + partial pressure of HCl = total pressure of the system

x + x = 4.4⇒ 2x = 4.4⇒ x = 2.2 atm

Now, the number of moles of NH3 and HCl = n = initial number of moles of NH4Cl= n-x= n-2.2Since 1 mole of NH4Cl decomposes to form 1 mole of NH3 and 1 mole of HCl, so the number of moles of NH4Cl decomposed = 2.2 moles.

Kp is the equilibrium constant expressed in terms of partial pressures. It is given by

Kp = P(NH3) * P(HCl) / P(NH4Cl)

At equilibrium, partial pressure of NH3 = 2.2 atm and that of HCl is also 2.2 atm.

Partial pressure of NH4Cl is zero since it is in solid state.

Kp = 2.2 * 2.2 / 0Kp is undefined, since the partial pressure of NH4Cl is zero or negligible.

to know more about equilibrium visit:

https://brainly.com/question/30694482

#SPJ11

which of these types of oil would remain solid at the highest temperature?

Answers

Out of all types of oil, coconut oil is one of the oils that would remain solid at the highest temperature. However, the answer to this question will also depend on the type of oil and its composition.

Coconut oil contains a high percentage of saturated fats which gives it the properties to remain solid at high temperatures. It is one of the few oils that can withstand high temperatures without oxidizing, producing harmful free radicals, or breaking down into unhealthy fats.

Coconut oil is suitable for high-heat cooking such as frying and baking and also has a long shelf life. Therefore, it can be concluded that coconut oil is one of the best options for cooking at high temperatures, as it can withstand high heat without breaking down into harmful compounds. It has a high smoke point and does not degrade quickly when exposed to high temperatures. So, it remains solid at the highest temperature.

To know more about temperature visit;-

https://brainly.com/question/7510619

#SPJ11

Nitrogen is a commonly used gas. Which of the following are properties of nitrogen?

choices:

low bpt, ability to support combustion, ability to change color with temperature, high solubility in water, lack of chemical reactivity

Answers

Nitrogen is a commonly used gas. The properties of nitrogen are: low boiling point (bpt), lack of chemical reactivity, and high solubility in water.

What is nitrogen?

Nitrogen (N2) is a gas that is colorless, odorless, and tasteless. Nitrogen gas constitutes about 78% of Earth's atmosphere. The rest of the atmosphere is composed of oxygen (about 21%), and other gases (about 1%).

What are the properties of nitrogen?

The properties of nitrogen are the following:

Low boiling point:

Nitrogen has a low boiling point (-196°C), which means it is used as a coolant.

Lack of chemical reactivity: Nitrogen gas is not reactive, making it ideal for blanketing, purging, and protecting oxygen-sensitive materials and products.

High solubility in water: Nitrogen gas dissolves in water to create nitrates, which are critical components of fertilizer used in agriculture.

learn more about solubility here

https://brainly.com/question/23946616

#SPJ11

What is the heat energy needed to raise the temperature of 6.63 moles of ethanol CH3CH2O from a temperature of 2.33º [CH3CH2OH=46.07g/mol) (CCₕ₃Cₕ₂ₒₕ = 2.46J/gºC])

Answers

The heat energy needed to raise the temperature of 6.63 moles of ethanol (CH3CH2OH) from a temperature of 2.33ºC is approximately 1720.1928 joules.

To calculate the heat energy needed to raise the temperature of a substance, we can use the formula:

q = m × c × ΔT

Where:

q = heat energy (in joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/gºC)

ΔT = change in temperature (in ºC)

First, let's calculate the mass of ethanol (CH3CH2OH) in grams. We know that the molar mass of ethanol is 46.07 g/mol, and we have 6.63 moles.

Mass = moles × molar mass

Mass = 6.63 moles × 46.07 g/mol

Mass ≈ 303.9641 g

Now, we can calculate the heat energy using the formula:

q = m × c × ΔT

ΔT is the change in temperature. Since we are raising the temperature, we need to calculate the difference between the final temperature and the initial temperature:

ΔT = final temperature - initial temperature

ΔT = 2.33ºC - 0ºC

ΔT = 2.33ºC

Substituting the values into the formula:

q = 303.9641 g × 2.46 J/gºC × 2.33ºC

q ≈ 1720.1928 J

Therefore, the heat energy needed to raise the temperature of 6.63 moles of ethanol (CH3CH2OH) from a temperature of 2.33ºC is approximately 1720.1928 joules.

To know more about heat energy visit:

https://brainly.com/question/25603269

#SPJ11

Q2A. Carbon monoxide (CO) emissions from internal combustion engines increase in colder climates. Thus, the environmental damage from CO emissions is worse in the winter months than in the summer months. Nonetheless, air quality control authorities use a standard for CO that is uniform throughout the year with no allowance for seasonal effects. The damage cost and abatement cost information is as follows: MD of CO emission in winter = 3E MD of CO emission in summer = 2E MAC of CO emission in both winter and summer= 60 - E where MD is marginal damages cost, MAC is marginal abtement costs, and E is level of emissions. a. If you were in charge of setting a policy for CO emissions, what action would you recommend to ensure an allocatively efficient outcome across the two seasons? b. Suppose that the government sets a policy that says emission level for winter and summer will be equiproportion, i.e., E = 15. Determine the change in net benefit or welfare loss associated with this policy.

Answers

(a) Carbon monoxide (CO) emissions from internal combustion engines increase in colder climates. Thus, the environmental damage from CO emissions is worse in the winter months than in the summer months.

Nonetheless, air quality control authorities use a standard for CO that is uniform throughout the year with no allowance for seasonal effects. Suppose you are in charge of setting a policy for CO emissions. The marginal damages cost (MD) in the winter is 3E and in the summer is 2E. The MAC of CO emissions in both winter and summer is 60-E. To ensure an allocatively efficient outcome across the two seasons, the marginal damage cost (MD) and the marginal abatement cost (MAC) should be equal. At the point where MD=MAC, social welfare will be maximized. Therefore, equating marginal damage cost (MD) and marginal abatement cost (MAC) in both winter and summer gives: 3E = 60 - E2E = 60 - EE = 20. Thus, the government should set a uniform CO emission standard for winter and summer seasons at 20 to ensure an allocatively efficient outcome across the two seasons.

(b) If the government sets a policy that says emission level for winter and summer will be equiproportion, i.e., E = 15, determine the change in net benefit or welfare loss associated with this policy. MD of CO emission in winter = 3E = 3(15) = 45MD of CO emission in summer = 2E = 2(15) = 30 MAC of CO emission in both winter and summer = 60 - E = 60 - 15 = 45. For a policy that says emission level for winter and summer will be equiproportion, the level of CO emission will be E = 15. The corresponding net benefit can be found as: NB = MB - MC = (MD - MAC) * E = (45 - 45) * 15 = 0. Therefore, the net benefit or welfare loss associated with this policy is zero.

To know more about combustion visit:-

https://brainly.com/question/31123826

#SPJ11

2) Some assumptions from the kinetic molecular theory are listed below. Which one is most frequently cited to explain compressibility of a gas? A) Collisions of gas particles are elastic and total kinetic energy of the gas is constant. B) The volume of the particles is negligible compared to the volume of thegas. C) The average kinetic energy of gas particles is proportional to theKelvin temperature D) A gas consist of tiny particles moving in random straight line motion

Answers

The assumption from the kinetic molecular theory most frequently cited to explain the compressibility of a gas is option B) The volume of the particles is negligible compared to the volume of the gas.

According to this assumption, gas particles are considered to occupy a very small fraction of the total volume of the gas. This means that the majority of the gas volume is empty space.

As a result, when a gas is subjected to increased pressure, the gas particles can be compressed closer together without significant volume changes due to their small size.

This assumption helps explain why gases are highly compressible compared to solids and liquids, which have more closely packed particles occupying a significant portion of their volume.

It provides a basis for understanding how gases can be compressed or expanded under different conditions, and it forms the foundation for gas laws such as Boyle's Law and the Ideal Gas Law. The correct option is B.

To know more about kinetic molecular theory, refer here:

https://brainly.com/question/30655544#

#SPJ11

in the reaction below, 4.44 atm each of h2 and br2 were placed into a 1.00 l flask and allowed to react:

Answers

The chemical equation for the reaction between hydrogen gas (H2) and bromine gas (Br2) is given as follows:  H2(g) + Br2(g) → 2HBr(g)In the reaction below, 4.44 atm each of H2 and Br2 was placed into a 1.00 L flask and allowed to react, and the following equilibrium was reached:

H2(g) + Br2(g) ⇌ 2HBr(g)Initially, the pressures of H2 and Br2 was 4.44 atm each. This means the total pressure in the flask before the reaction began was: Ptotal = PH2 + PBr2Ptotal = 4.44 atm + 4.44 atm = 8.88 atmSince the reaction is taking place in a closed system, the volume of the flask remains constant, and we can assume that the total number of moles of gas remains constant too.Let's assume that 'x' moles of H2 react with 'x' moles of Br2 to form 2x moles of HBr. Then, the number of moles of H2 remaining in the flask is (4.44 - x), the number of moles of Br2 remaining is (4.44 - x), and the number of moles of HBr formed is (2x).Using the ideal gas law, we can find the equilibrium pressure of each gas:PH2 = (nH2RT) / V  = [(4.44 - x) RT] / 1.00PBr2 = (nBr2RT) / V = [(4.44 - x) RT] / 1.00PHBr = (nHBrRT) / V = [2x RT] / 1.00At equilibrium.

The total pressure in the flask is P total, so we have: P total = PH2 + PBr2 + PHBr8.88 atm = [(4.44 - x) RT / 1.00] + [(4.44 - x) RT / 1.00] + [2x RT / 1.00]8.88 atm = [(8.88 - 2x) RT / 1.00] + [2x RT / 1.00]8.88 atm = [(8.88 - x) RT / 1.00]2x RT = x RT / 4.44x = 0.222 moles Hence, the number of moles of HBr produced is 2x = 0.444 moles  The equilibrium pressure of HBr is:PHBr = (nHBrRT) / V = (0.888 mol RT) / 1.00 L = 0.888 RT atm equilibrium pressure of HBr is 0.888 atm.

To know more about chemical equation refer to:

https://brainly.com/question/29886207

#SPJ11

As atomic number increases across a period, all of the following increase except a. atomic radius c. ionization energy b. atomic mass d. number of valence electrons

Answers

As atomic number increases across a period, all of the following increase except (a) atomic radius.

As atomic number increases across a period, several properties change systematically.

Atomic radius generally decreases due to the increasing positive charge in the nucleus and the increasing number of electrons in the same energy level. Ionization energy, the energy required to remove an electron, generally increases because the electrons are held more tightly due to the stronger nuclear attraction.

Atomic mass also increases as more protons and neutrons are added to the nucleus. However, the number of valence electrons, which are the outermost electrons involved in bonding, typically remains the same within a period.

Among the given options, the (a) atomic radius is the property that does not increase as atomic number increases across a period.

So, as atomic number increases across a period, (a) atomic radius decreases, ionization energy increases, and atomic mass increases. The number of valence electrons remains the same.

To know more about the atomic number refer here :

https://brainly.com/question/16858932#

#SPJ11

what is the equilibrium membrane potential due to na ions if the extracellular concentration of na ions is 146 mm and the intracellular concentration of na ions is 23 mm at 20 ∘c ?

Answers

Given extracellular concentration of Na ions=146 mm Intracellular concentration of reaction Na ions=23 mm Equilibrium membrane potential due to Na ions=.

The Nernst equation calculates the equilibrium potential (also known as the Nernst potential) for a single ion by balancing the ionic concentration gradient across the plasma membrane with the electrical gradient that balances it out.

The Nernst equation can be written as: Equilibrium potential (Eion)=RT/zF x ln [ion]out/[ion]inwhere, R= gas constant (8.314 joules/mole x Kelvin)T= temperature in Kelvinz= valence of the ion (valence for sodium ion is +1)F= Faraday's constant (96,487 coulombs/mole)ln= natural logarithm[ion]out= extracellular ion concentration[ion]in= intracellular ion concentration Using the above equation, we can find out the equilibrium potential due to Na ions at 20 °C as follows;Eion= RT/zF x ln [ion]out/[ion]in= 2.303 x RT/zF x log [ion]out/[ion]in= 2.303 x 8.314 x (20 + 273) / (1 x 96,487) x log (146/23)= 0.061 V = 61 mV.

To know more about reaction visit:

https://brainly.com/question/30464598

#SPJ11

what reagents are needed to carry out the conversion shown? ch3i/ag2o ch3oh/ag2o ch3oh/pyridine ch3ch2oh/hcl ch3oh/hcl

Answers

Reagents required to carry out the conversion shown are as  follows :Ch3I/Ag2OCh3OH/Ag2OCh3OH/ Pyridine Ch3CH2OH/HClCh3OH/HCl

The given reactions can be understood through the following diagram.In the first reaction, ch3i/ag2o is used to convert to ch3oh/ag2o. This conversion is a type of nucleophilic substitution in which Ag2O works as an oxidizing agent.In the second reaction, ch3oh/ag2o is used to convert to ch3oh/pyridine.

This conversion is a dehydration reaction in which pyridine works as a catalyst.In the third reaction, ch3oh/pyridine is used to convert to ch3ch2oh/hcl. This conversion is a nucleophilic addition reaction in which HCl works as a catalyst.In the fourth reaction, ch3ch2oh/hcl is used to convert to ch3oh/hcl. This conversion is a dehydration reaction in which HCl works as a catalyst.

To know more about conversion visit:

https://brainly.com/question/30567263

#SPJ11

Final answer:

The student's question pertains to various chemical reactions involving different reagents. Depending upon the reaction reagents could take part as acid or base, reducing or oxidizing agent, or nucleophile or electrophile.

Explanation:

The chemical equations provided demonstrate several different reactions requiring specific reagents (chemically active substances). The reactions are:

CH3I being oxidized by silver oxide (Ag2O)Methanol (CH3OH) in presence of Ag2OCH3OH reacting with Pyridine (a basic organic compound)Ethanol (CH3CH2OH) reacting with hydrochloric acid (HCl)CH3OH reacting with HCl

Each reactant's role can vary, it could act as an acid or base, a reducing or oxidizing agent, or a nucleophile or electrophile, dependingon the other substance(s) present in the reaction.

Learn more about Chemical Reactions here:

https://brainly.com/question/34137415

#SPJ11

what is the ph of a 1.2 m pyridine solution that has kb = 1.9 × 10-9? the equation for the dissociation of pyridine is c5h5n(aq) h2o(l) ⇌ c5h5nh (aq) oh-(aq).

Answers

The pH of a 1.2 M pyridine solution is 8.91. On solving this quadratic equation, we get;x = 0.00134 mol/LTherefore, the concentration of OH- is 0.00134 mol/L and the pH of the solution is 8.91.

The equation for the dissociation of pyridine is given by c5h5n(aq) h2o(l) ⇌ c5h5nh (aq) oh-(aq).The given chemical reaction is of weak base since it includes a base, OH-.The dissociation constant for the reaction is given by;Kb = [C5H5NH][OH-] / [C5H5N][H2O]At equilibrium, the moles of C5H5N will be equal to moles of C5H5NH and moles of OH-.

Hence, [C5H5N] = [C5H5NH], [OH-] = x and [H2O] = (1.2-x).Thus, on substituting the given values in the equation;Kb = (x^2)/(1.2-x)0.019 = (x^2)/(1.2-x)On solving this quadratic equation, we get;x = 0.00134 mol/LTherefore, the concentration of OH- is 0.00134 mol/L and the pH of the solution is 8.91.

To know more about pyridine solution visit:

https://brainly.com/question/32089285

#SPJ11

For the reaction 12(g) + Cl2(g) 2 ICI(g) AG° = -30.0 kJ and AS° = 11.4 JK at 282 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 282 K. The standard enthalpy change for the reaction of 2.33 moles of 12(g) at this temperature would be kJ. For the reaction NH4NO3(aq) - N20(g) + 2 H2O(1) AG° = -184.5 kJ and AH° = -149.6 kJ at 349 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 349 K. The entropy change for the reaction of 1.60 moles of NH4NO3(aq) at this temperature would be J/K

Answers

For the reaction 1,2(g) + Cl2(g) 2 ICl(g) at 282 K and 1 atm, AG° = -30.0 kJ and AS° = 11.4 JK, and the reaction is favored by products under standard conditions at 282 K. At this temperature, the standard enthalpy change for the reaction of 2.33 moles of 1,2(g) will be 461 J/K..

Standard molar enthalpy of formation is defined as the change in enthalpy of the reaction that results from the formation of one mole of the compound from its elements. If the standard enthalpy change for the reaction can be measured experimentally, then the standard molar enthalpy of formation can be calculated. Therefore, the standard enthalpy change for the reaction of 2.33 moles of 1,2(g) at this temperature would be -33.0 kJ.

Explanation: According to the Gibb's free energy equation,ΔG = ΔH - TΔSFor a reaction to be spontaneous, ΔG must be negative. When ΔH is negative and ΔS is positive, the reaction is spontaneous because entropy favors it. When ΔH is positive and ΔS is negative, the reaction is non-spontaneous because entropy is opposed to it. When ΔH is negative and ΔS is negative, the reaction is spontaneous at low temperatures, but non-spontaneous at high temperatures.

At this temperature, the entropy change for the reaction of 1.60 moles of NH4NO3(aq) would be 461 J/K.

To know more about molar enthalpy visit

https://brainly.com/question/3207013

#SPJ11

draw a transition state diagram of (a) an enzymatic reaction

Answers

Enzymatic reactions are regulated by their transition states. Transition states refer to the point at which substrates become bound to the enzyme and undergo an alteration to form the product.  


The transition state diagram shows the relationship between substrate concentration and reaction rate. Enzymes assist substrates in achieving the transition state by aligning reactive groups in the correct position and lowering the activation energy for the transition to occur. Enzyme catalysis can be considered in terms of bond formation, which is accomplished by the formation of reactive intermediates during the reaction.


A diagram of an enzymatic reaction would show a reaction path with an energy profile that has a peak in the middle representing the transition state. In the diagram, the x-axis represents the reaction progress, and the y-axis represents the energy of the system. In conclusion, the transition state diagram of an enzymatic reaction depicts the energy required for the reaction to proceed. Enzymes assist the reaction to proceed by stabilizing the transition state and lowering the activation energy, thereby increasing the reaction rate. A diagram of an enzymatic reaction is shown below.

To know more about Enzymatic   visit:-

https://brainly.com/question/24251152

#SPJ11

From the solubility data given, calculate the solubility products for the following compound Ag3PO4, 6.7 x 10^-3 g/L

Answers

The solubility product of an ionic compound is the product of the concentrations of the ions raised to the powers equal to their coefficients in the balanced chemical equation of the dissolution of the compound.

The balanced chemical equation for the dissolution of Ag3PO4 is:Ag3PO4(s) ⇌ 3Ag+(aq) + PO43-(aq) Therefore, the solubility product of Ag3PO4, denoted by Ksp, is given as:Ksp = [Ag+]3[PO43-]If the solubility of Ag3PO4 is 6.7 × 10-3 g/L, then the concentration of Ag+ ions and PO43- ions will be equal to each other since Ag3PO4.

Substituting the values, we have: Ksp = (x)3(x)= x4Ksp = (6.7 × 10-3 g/L)4= 1.65 × 10-17 The solubility product of an ionic compound is the product of the concentrations of the ions raised to the powers equal to their coefficients in the balanced chemical equation of the dissolution of the compound.

To know more about solubility visit:

https://brainly.com/question/31493083

#SPJ11

when a 3.00 g sample of kbr is dissolved in water in a calorimeter that has a total heat capacity of 1.93 kj⋅k−1, the temperature decreases by 0.260 k. calculate the molar heat of solution of kbr.

Answers

When a 3.00 g sample of KBr is dissolved in water in a calorimeter that has a total heat capacity of 1.93 kJ⋅K−1, the temperature decreases by 0.260 K. Molar heat of solution = 0.502 / 0.0252 = 19.92 kJ/ mol.

The molar heat of solution is the heat change that occurs when one mole of a substance is dissolved in water at a constant pressure and temperature. It is expressed in kJ/mol. The reaction that takes place is KBr → K+ (aq) + Br− (aq)We can calculate the heat absorbed by the calorimeter (qcal) using the formula; qcal = CcalΔTWhere Ccal is the heat capacity of the calorimeter and ΔT is the change in temperature.

Here Ccal is given to be 1.93 kJ/K Therefore, qcal = 1.93 × 0.260 = 0.502 kJ The heat change that occurs when 3.00 g of KBr is dissolved in water is equal to the heat absorbed by the calorimeter. We can calculate the number of moles of KBr using the formula; n = mass / molar mass The molar mass of KBr is 119 g/mol Therefore, n = 3.00 / 119 = 0.0252.

To know more about Molar visit:

https://brainly.com/question/31545539

#SPJ11

when you mix two liquids, the reaction vessel suddenly feels cold. what does this observation suggest? mark any/all statements that apply.

Answers

When you mix two liquids, the reaction vessel suddenly feels cold. This observation suggests the temperature change, which is an exothermic reaction, can be felt by the reaction vessel.

The reaction that is occurring in this situation is most likely to be exothermic in nature. A decrease in temperature can occur due to evaporation of the liquid, and thus, the heat absorbed is taken from the environment, causing the vessel to feel cold. The cooling effect might also indicate that an endothermic reaction is occurring. The temperature change in an endothermic reaction is always negative.

As a result, the vessel would feel cold, this effect occurs when two liquids or substances react and absorb heat, resulting in a decrease in temperature. The reaction needs to take in heat from the surrounding environment in order to proceed, so heat is removed from the reaction vessel. This means that the temperature of the reaction vessel may become colder. So therefore Wwhen two liquids are mixed, the temperature change, which is an exothermic reaction, can be felt by the reaction vessel.

Learn more about evaporation at :

https://brainly.com/question/320765

#SPJ11

The following observations can be made based on this information:

When two liquids are mixed, the reaction vessel suddenly feels cold.

The following observations can be made based on this information:

Energy is consumed when the two liquids are combined to create a new substance. This change in temperature is caused by an endothermic reaction. The difference in temperature can be explained by the energy absorbed or released during the chemical reaction.Temperature change provides proof that a chemical reaction has occurred. When two chemicals react, the reaction absorbs heat, which causes the temperature in the reaction vessel to drop. The reaction's temperature will rise if heat is produced during the reaction. This change in temperature is caused by an exothermic reaction.

To know more about reaction visit:

https://brainly.com/question/30464598

#SPJ11

1.(boyles): a gas with a volume of 4.00 l at pressure of 205 kpa is allowed to expand to a volumes of 12.0 l. what is the pressure in the contained if the temperature remains constant?

Answers

The pressure in the container after the expansion is 820 kPa.

According to Boyle's Law, for a given amount of gas at a constant temperature, the product of the initial volume and pressure is equal to the product of the final volume and pressure. Using this principle, we can determine the pressure in the container after the expansion.
Initial volume (V1) = 4.00 L
Initial pressure (P1) = 205 kPa
Final volume (V2) = 12.0 L
According to Boyle's Law: P1 * V1 = P2 * V2
Substituting the given values:
205 kPa * 4.00 L = P2 * 12.0 L
Simplifying the equation:
820 kPa * L = P2 * 12.0 L
Dividing both sides of the equation by 12.0 L:
820 kPa = P2
Therefore, the pressure in the container after the expansion is 820 kPa.

To know more about pressure, click here https://brainly.com/question/21594414

#SPJ11

Other Questions
A bank wishes to decide how many staff to schedule during its lunch period. During this period customers arrive at a rate of 6 per hour and the enquiries that customers have (such as opening new accounts, arranging loans, etc.) take on average 20 minutes to deal with. The bank manager feels that 3 staff should be on duty during this period but wants to make sure that the customers do not wait more than 3 minutes on average before they are served.The manager has been told by his small daughter that the distributions that describe both arrival and processing times are likely to be exponential. Therefore:5.1Calculate the utilization of the system where u = ra/ (re x m).(6)5.2Using the formula for waiting time for an M/M/ m system, calculate the average waiting time.(14) if you were a security professional in a company, what are four roles (two sets of two related roles) you would separate and why? provide examples not mentioned in the description for this discussion Bike n Work Co. is a shop that sells bike groupsets. In selling the product, the shop is applying only all-cash policy. However, due to increasingly fierce competition in the industry, the shop is considering of implementing a 30-day credit policy. At the moment, the shop sells 10 units of groupset every month. The current price and the variable cost per unit are IDR 12 million and IDR 8 million, respectively. If Bike n Work does switch to net 30 days on sales, it predicts that the quantity sold may rise by 40% and costs will increase by 25% per unit. Meanwhile, the groupset's price under the new policy will be (10+Y)% higher.Question:a. If the required return is 0.90 percent per month, should Bike n Work determine if the company should proceed or not.b. Assume new orders for (20 +Y) bike groupsets have been made by customers requesting credit. Credit is extended for one period. Based on historical experience, payment for about 1 out of every 50 such orders is never collected. Assuming that this is a one-time order, should credit be extended? (Hint: use the predicted price and variable cost if the new policy is applied).c. What is the break-even probability of default in part (b)? by what age does one internalize and identify with ones gender? A coil 3.75 cm radius, containing 470 turns, is placed in a uniform magnetic field that varies with time according to B =( 1.2010-2 T/s)t+(2.5010-5 T/s4 )t4. The coil is connected to a 520- resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. Part A Find the magnitude of the induced emf in the coil as a function of time. E = 7.9310- V +(6.61105 V/s )t =2.4910-2 V +(5.1910-5 V/s )t =2.4910- V +(2.0810-4 V/s )t E = 7.9310-3 V +(2.0810-4 V/s )t Previous Answers Part B What is the current in the resistor at time to = 4.70 s? VE ? I = Submit Correct APrevious question Nirenberg and Leder used the triplet binding assay to determine specific codon assignments. A complex of which of the following components was trapped in the nitrocellulose filter? uncharged tRNAs and ribosomes sense and antiserse strands FONA free tRNAS ribosomes and DNA charged RNA, RNA triplet and ribosome when he reaches the bottom, 4.2 mm below his starting point, his speed is 2.2 m/sm/s . by how much has thermal energy increased during his slide? Select all of the following that are TRUE.Question 6 options:If the fixed expenses increase in a company, and all other factors remain unchanged, then we can expect the margin of safety to decrease.At a given level of sales, a low contribution margin ratio will result in less net income than a high contribution margin ratio.If fixed expenses increase by $15,000 per year, then the level of sales needed to break even will also increase by $15,000Once the break-even point has been reached, increases in contribution margin will be reflected dollar for dollar in increased net income.In determining contribution margin, all manufacturing costs are deducted.The margin of safety percentage is equal to the margin of safety in dollars divided by the number of units sold. let x2 13x=3 . what values make an equivalent number sentence after completing the square? enter your answers in the boxes. x2 13x = the presence of these two factors coupled with abdominal obesity indicates metabolic syndrome. Two objects with masses of m1 and m2 have the same kinetic energy and are both moving to the right. The same constant force F-> is applied to the left to both masses. If m1 = 4m2, the ratio of the stopping distance of m1 to that of m2 is: A. 1:4 B. 4:1 C. 1:2 D. 2:1 E. 1:1 Our goal for this discussion is to revlew the purpose behind and the reasons for establishing the Securities and Exchange Commission (SEC). What is the SEC and the principal legislation the agency enforces? Within your response, make sure to discuss the SEC's organization and structure, Including the agency's responsibility from an accounting standpoint, namely regarding U.S. Generally Accepted Accounting Principles (U.S. GAP). What role does the SEC have in the development of accounting theory and practices? Seitz Glassware is trying to determine its growth rate for an annual cash dividend. The most recent dividend, Divo, was $0.30 per share. The stock's target return rate is 10%. What is the stock's price if a. the annual growth rate is 2%? b. the annual growth rate is 4%? c. the annual growth rate is 6%? d. the annual growth rate is 8%? e. the annual growth rate is 9%? A very long line of charge with charge per unit length +8.00 C/m is on the z-axis and its midpoint is at a 0. A second very long line of charge with charge per unit length -4.00 C/m is parallel to the x-axis at y 15.0 cm and its midpoint is also at z = 0. Part A At what point on the y-axis is the resultant electric field of the two lines of charge equal to zero? Enter the y-coordinate of the point and include the appropriate units. 3 d ? is the concentration gradeint is higher, is osmis rate faster Question 51 Grapevine Bank receives a deposit of $200,000. Its required reserve ratio is 12 percent. How much of this deposit is available to be loaned to borrowers? O $12.000 O $200,000 O $176.000 O $24,000 Question 52 Pinnacle Finance Bank has a 12 percent reserve requirement ratio. What is Pinnacle Finance's money multiplier? O 1.2 O 12 O 8.33 O 6 Question 53 If Pinnacle Finance Bank receives a new cash deposit of $150,000, and it has a required reserve ratio of 12 percent, how much total money could potentially be created from that deposit? O $18,000 O $1,800,000 O $1,250,000 O $150,000 An object lies outside the focal point of a diverging lens. Which of the following statements about the image formed by this lens must be true? A. The image is always virtual and inverted. B. The image could be real or virtual, depending on how far the object is past the focal point. C. The image could be erect or inverted, depending on how far the object is past the focal point. D. The image is always virtual and on the same side of the lens as the object. or both B and C i need help with engineering economy question;Steven plans to withdraw his money RM 10,000 each year from his savings account at theend of year 10 and Year 11. To make sure these withdrawals are possible, FOUR (4)annuity amounts (A) will be deposited in a bank at the end of year 2, 3, 4, and 5. The banksinterest rate is 12% per year.(a) Draw a cash-flow diagram for this situation(b) Determine the value of the annual amount (A) at the end of year 2, 3, 4 and 5 thatshould be deposited to withdraw the money at the end of year 10 and year 11 asstated. the total cost of ownership of an information system refers to in xyz, y=90 and x=26. zwy=79 and xw=810. find the length of zy to the nearest integer.