2. Fluorine gas exerts a pressure of 1.2 atm. When the
pressure is changed to 1.50 atm, its volume is 250 mL.
What was the original volume?

The final temperature of the mixture is 28.93°C

Data;

The underlying principle of transfer of heat is discussed in heat transfer which can be summarized as heat lost by a warmer body is equal to heat gain by a colder body. The formula of this can be written as

[tex]Q=mc\delta \theta\\[/tex]

Heat Loss = Heat gain

[tex]m_1c_1(T_1-T_3)=m_2c_2(T_2-T_3)\\0.519*2.01*(105-T_3)=5.91*4.18*(16.7-T_3)\\109.53495-1.04319T_3=412.55346-24.7038T_3)\\1.04319T_3+24.7038T_3=412.55346-109.53495\\25.74699T_3=303.01851\\T_3=\frac{303.01851}{25.74699}\\T_3=11.77^0C[/tex]

The final temperature is equal to

[tex]T_f = \delta vap - T_3\\T_f = 40.7 - 11.77\\T_f = 28.93^0C[/tex]

The final temperature of the mixture is 28.93°C

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Answer:

Water vapor, carbon dioxide gas, heat, and light

Explanation:

I think this is right? :)

MY COMPUTER JUST FROZE SO I HAVE NO IDEA IF IM TYPING THE ANSWER

Explanation:

I THINK THE ANSWER WOULD BE OXYGEN AND LIGHT WOULD BE FORMED OFF OF THE CANDLE

Answer:

It is true! Have a great day/night :). & make sure you drink water and eat!

Explanation:

Refer to the attachment

Answer:

groundwater pollution

Explanation:

Hope this solve your answer

This problem is providing us with the reaction whereby tungsten is produced from tungsten (VI) oxide and hydrogen, so the percentage atom economy is required and found to be 64.3 % according to:

In the ambit of green chemistry, atom economy is one of the twelve principles of green chemistry, and tell us how efficient a chemical process is, in terms of the necessary reactants, versus the yielded products. In the ideal case, it is 100 % meaning that all the reactants lead to the desired product.

However, when byproducts are present, this percentage dwindles and the idea is to reason how convenient the process is. In this case, we can calculate the atom economy, by simply dividing the atomic mass of tungsten by the addition of the molar mass of tungsten (VI) oxide and three times that of waters:

[tex]\%A-E=\frac{183.84g/mol}{231.84g/mol+3*18.02g/mol} *100\%\\\\\%A-E=64.3\%[/tex]

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Answer:

7.28 moles Ag°

Explanation:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Given 7.28 moles     7.28 moles

To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...

Limiting reactant determination:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Cu: 7.28 / 1  = 7.28

AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃

Solving Problem depends on AgNO₃; Cu will be in excess.

Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.

Answer:

21.32 L

Explanation:

First, convert grams to moles using molar mass. C has a mass of 12 and O has a mass of 16. CO2 will therefore have a mass of 28 g/mol. Divide 22 by 28 to get about 0.79 moles. Convert C to Kelvin by adding 273; getting 323K. Then use the ideal gas law (PV=nRT) to solve for V (V=nRT/P). This gets you 21.32 L, hope this helps!

Reactivity series:-

[tex]\setlength{\unitlength}{0.8 cm}\begin{picture}(20,15)\thicklines\put(5,9.5){\large {\boxed{ \sf{Reactivity \: series}}}}\put(0.8,8){\large\sf K \qquad\qquad\qquad Potassium\qquad\qquad\qquad \: maximum}\put(0.8,7.2){\large\sf Na \qquad\qquad\qquad Sodium\qquad\qquad\qquad\quad \: reactivity}\put(0.8,6.2){\large\sf Ca\qquad\qquad\qquad \: Calcium}\put(0.8,5.2){\large\sf Mg\qquad\qquad\quad \: Magnesium}\put(0.8,4.2){\large\sf Al\qquad\qquad\qquad \: Aluminium\qquad\qquad\qquad \: decreasing}\put(0.8,3.2){\large\sf Zn\qquad\qquad\quad\qquad \: Zinc\qquad\qquad\qquad\qquad \:reactivity}\put(0.8,2.2){\large\sf Fe\qquad\qquad\quad\qquad Ferrous}\put(0.8,1.2){\large\sf Pb\qquad\qquad\qquad \: \:\: Lead}\put(0.8,0.2){\large\sf H\qquad\qquad\qquad \: \:Hydrogen}\put(0.8, - 0.6){\large\sf Cu\qquad\qquad\qquad \: Copper}\put(0.8, - 1.5){\large\sf Hg\qquad\qquad\qquad \: Mercury}\put(0.8, - 2.5){\large\sf Ag\qquad\qquad\qquad \: \:Silver}\put(0.8, - 3.5){\large\sf Au\qquad\qquad\qquad \: \: Gold\qquad\qquad\qquad\quad \: \: minimum reactivity}\put(9.3,8.2){\vector(0, - 2){12}}\end{picture}[/tex]

#1

Ag is found as too less reactive so

#2

No element in universe can displace potassium (K) from its solution as it's most reactive .

#3

Fe is also a reactive metal.

So

#4

#5

#6

#7

#8

#9

#10

#11

As Ca is third most reactive metal

#12

Answer:

Option B

Explanation:

Use Avogadro constant of 6.02 x 10^23

For Option A,

1.9 moles x (6.02 x 10^23) = 1.1438 x 10^24

For Option B,

5.3 moles x (6.02 x 10^23) = 3.1906 x 10^24

For Option C,

9.5 moles x (6.02 x 10^23) = 5.719 x 10^24

For Option D,

19.2 moles x (6.02 x 10^23) = 1.1558 x 10^25

Therefore, the nearest one to 3.2 x 10^24 is Option B

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

Answer:

A catalyst is a chemical that speeds up a reaction without being used up or chemically changed.

Answer:

I dont know sorry i will try my best htough

Explanation:

Answer:

347.6995462

Phosphorus heptasulfide, free from yellow and white phosphorus appears as light-yellow crystals, light-gray powder, or fused solid. Melting point 310°C.

...

So following this simple ratio, 4 moles of H2O2 will result in 2 moles of O2. For 1 mole of H2O2, it will yield to 0.5 moles of O2. Adding those up, 5 moles of H2O2 will yield to 2.5 moles of O2.

The mole concept is used here to determine the moles of oxygen produced from the decomposition of hydrogen peroxide. The moles of O₂ produced is 2.5.

One mole of a substance is defined as that quantity of it which contains as many entities as there are atoms exactly in 12 g of carbon - 12. The formula used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

The balanced equation for the decomposition of H₂O₂ is given as:

2H₂O₂ → O₂ + 2H₂O

Here the number of 'H' and 'O' atoms are equal on both sides.

The moles of oxygen produced from 5 mol of hydrogen peroxide is:

5 mol H₂O₂  × 1 mol O₂ / 2 mol H₂O₂ = 2.5 moles O₂

Thus the number of moles of O₂ produced from 5 mol of H₂O₂ is 2.5.

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Answer:

Explanation:Hydrogen peroxide

Explanation:

Hydrogen peroxide (

H

2

O

2

) is commonly used as a first aid antiseptic and decomposes naturally. They are usually kept in special containers to retain it's chemical properties, but if you poured some into a bowl you would see little gas bubbles rising up.

2

H

2

O

2

→ 2

H

2

O

+

O

2

Answer:

3,924°F

Explanation:

here is the answer it is a little hard to explain but hopeing it helps you a lot

Answer:

The temperature would be 3,924 degrees Fahrenheit.

Explanation: Hope this helps<3

Answer:

see explanation

Explanation:                      

Answer:

0.682L or 682mL

Use Charles Law of V1/T1 = V2/T2

V1 = 0.6L

T1 = 293K

V2=?

T2= 333K

Explanation:

?

the answer is a because the positive cations are attracted to the negative cathode. when the positive ions get to the cathode they pick up an electron and this produces normal sodium.

Answer:

Answer is B

Explanation:

Answer:

As temperature increases, its solubility increases as well. Notice, however, that it does not increase significantly. In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C .

You can determine how many grams of sodium chloride, commonly known as table salt, can be dissolved in

100 g

of water at

80

∘

C

by taking a look at its solubility graph.

A substance's solubility graph tells you how its solubility changes, let's say starting from room temperature, when temperature is either decreased or increased.

Answer:

3.011 x 10^23 molecules of acetate

Explanation:

Use a conversion factor to figure this out.

[tex]=99.47\ kPa[/tex] × [tex]\frac{1\ atm}{101.325\ kPa}[/tex]

= 0.9816925734 atm (round as you wish)

The answer to your problem is 0.015 liters. I got the answer because to convert cubic centimeters into liters, you need to divide the cubic centimeters by 1000.

Answer:

D

Explanation:

The one above me, and another question resembling this one can attest that is, indeed, the temperature....