Note that when the ball is in the air, the only force acting on it is the downward pull of gravity, so the force of the swing is a red herring.
The ball hits the ground at the same height from which it was hit, so its final velocity will have the same magnitude of 49 m/s, but pointing at an angle of 35° below the horizontal.
The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat's average kinetic energy? (1 kJ = 1000 J)
Answer:
69.44kJ
Explanation:
Kinetic energy is expressed as;
KE = 1/2mv^2
m is the mass = 500kg
v is the velocity
Get the velocity;
v = displacement/time
velocity = 2000/120
velcoity = 16.7m/s
Gt the kinetic energy
KE = 1/2 * 500 * 16.7²
KE = 250*277.78
KE = 69,444.4Joules
Since 1000J = 1kJ
69,444.4Joules = 69,444.4/1000
69,444.4Joules = 69.44kJ
Hence the Secretariat's average kinetic energy is 69.44kJ
Answer:C 69.0kJ
Explanation:
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A 2.0 kg bullet is fired into a sandbag sitting on a wagon. The combined mass of the wagon and the sandbag is 4.5 kg. a) If the wagon/sandbag/bullet moved together with a speed of 0.22 m/s immediately after impact with the bullet, with what speed did the bullet enter the sandbag? b) Is this an elastic or inelastic collision? Explain.
Answer:
To answer your question use the code ICE on here to get your answer works every time for me hope this helps
who is the best soccer player?
What is the kinetic energy of a 0.150 kg
object moving at a velocity of 100m/s?
Answer:
750J
Explanation:
Given parameters:
Mass of the object = 0.15kg
Velocity of the object = 100m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass of the body
v is the velocity
Now insert the parameters and solve;
K.E = [tex]\frac{1}{2}[/tex] x 0.15 x 100² = 750J
The vocal cords in your throat _____________.
collapse
vibrate
compress
Answer:
vibrate
Explanation:
Vocal folds vibrate when excited by aerodynamic phenomena; they are not plucked like a guitar string. Air pressure from the lungs controls the open phase. The passing air column creates a trailing “Bernoulli effect,” which controls the close phase.
hope it helps!!
A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum of the box? (unit = kg*m/s)
Answer:
63.8454kgm/s
Explanation:
According to Newton's second law;
Force = mass ×acceleration
Fore = m(v-u)/t
Force = mv-mu/t
MV is the final momentum
mu is the initial momentum = 38kgm/s
Force = 88.3N
Time = 0.338s
Substitute and get mv
88.3 = mv-38/0.338
88.3×0.338 = mv-38
29.8454 = mv-38
MV = 29.8454+34
mv = 63.8454kgm/s
Hence the final momentum is 63.8454kgm/s
Answer:
67.8
Explanation:
im an acellus student, and this is the answer that i got when doing the problem.
URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)
1 point
a) 366,000 J
b) 3,660,000 J
c) 2.73 J
d) 20.73 J
Answer:
(B) the increase in the car's potential energy is 3,660,000 J
Explanation:
Given;
mass of the car, m = 1,000 kg
height through the car was drove, h = 366 m
acceleration due to gravity, g = 10 m/s²
The increase in the car's potential energy is calculated as;
P.E = mgh
P.E = 1000 x 10 x 366
P.E = 3,660,000 J
Therefore, the increase in the car's potential energy is 3,660,000 J
Explain the significance of the thermometer, the electric heater, and the power supply.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete. However, the significance/functions of the "instruments" mentioned (in the completed question) can be predicted since these "instruments" generally have specialized function.
A thermometer is used to determine the temperature of a substance or an object. The electric heater uses electricity to produce heat (which can be utilized for different purposes). The power supply is used to supply electricity for instruments/appliances that may require electricity to function.
A stunt-rider on a motorcycle rides down a ramp and into a vertical loop-the-loop. If the diameter of the loop is 7.50 m, then the slowest speed the motorcycle can have at the top of the loop if it is to remain in contact with the loop is _________ km/h.
Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
[tex]Centripetal Force = Weight \\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v = \sqrt{gr}[/tex]
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
[tex]v = \sqrt{(9.8\ m/s^2)(3.75\ m)}[/tex]
v = 6.06 m/s
the great pyramid of khufu (giza, egypt) is about 140m tall. How much work would be required to raise an average - sized pyramid black (2.5 tons) to this height?
Determine the velocity of a wave with frequency 10Hz and a wavelength of 10m.
Answer:
A wave with a frequency of 10 Hz and a wavelength of 10 m should have a velocity of 100 meters per second (m/s)
Explanation:
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Describe chromatin and how it changes.
Answer:
Chromatin is a mass of genetic material composed of DNA and proteins that condense to form chromosomes during eukaryotic cell division. Chromatin is located in the nucleus of our cells . The primary function of chromatin is to compress the DNA into a compact unit that will be less voluminous and can fit within the nucleus.
I hope this helps
Explanation:
Answer: Me again! Chromatin is a complex of DNA and proteins that forms chromosomes within the nucleus of eukaryotic cells. Nuclear DNA does not appear in free linear strands; it is highly condensed and wrapped around nuclear proteins in order to fit inside the nucleus. Chromatin exists in two forms.
Explanation: Hope this helps! Happy Holidays!
what is the correct answer?
Answer:
i cant explain well but the answer is letter b
x-5
Explanation:
dont report me or i will report you too
Answer:
x-5 is the answer
Explanation:
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The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed along axes of AB and AC. Set F=500N
Answer:
The magnitude will be "353.5 N". A further solution is given below.
Explanation:
The given values is:
F = 500 N
According to the question,
In ΔABC,
⇒ [tex]\angle BCA = (90-30)[/tex]
⇒ [tex]=60^{\circ}[/tex]
then,
⇒ [tex]\angle BAC=(180-45-60)[/tex]
⇒ [tex]=75^{\circ}[/tex]
Now,
The corresponding angle will be:
⇒ [tex]\angle FAC=60^{\circ}[/tex]
⇒ [tex]\angle FAB=70+60[/tex]
⇒ [tex]=135^{\circ}[/tex]
Aspect of F across the AC arm will be:
= [tex]F\times cos(60)[/tex]
On putting the values of F, we get
= [tex]500\times (.5)[/tex]
= [tex]200 \ Newton[/tex]
Component F along the AC (in magnitude) will be:
= [tex]F\times cos(135)[/tex]
= [tex]500\times (-.707)[/tex]
= [tex]-353.5 \ N \[/tex]
write any one advantage and disadvantage of eddy current
Explanation:
[tex]advantage[/tex]
It is Sensitivity to surface defects. ...
[tex]disadvantage[/tex]
There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated
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the multimeter functions as an ammeter
Answer: What?
Explanation:
what is the correct answer?
Answer:
3.2
Explanation:
I remember taking this quiz and I think that one is correct
help!!!! please!!! i’m not sure what the answer is for both questions please
Answer:
a.) 600N
b.) 2 m/s^2
Explanation:
a.)
In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.
Basically: Force = mass * acceleration ; F = ma
Since both mass and acceleration are already given, just plug them into the formula and solve for force:
Mass = 200kg
Acceleration = 3m/s^2
F = m * a = 200 * 3 = 600kg * m/s^2 = 600N
b.)
In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.
To calculate net force:
Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.
Net Force: 8N - 4N = 4N
Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left
Finally, you find acceleration using newton's 2nd law, F = ma.
Since you already know mass and net force, plug in to solve for acceleration:
4N = 2kg * a
a = 4 N / 2kg = 2m/s^2
If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?
Answer:
Its speed will be 280 m/s
Explanation:
Constant Acceleration Motion
It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.
If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:
[tex]v_f=v_o+at[/tex]
The object accelerates from rest (vo=0) at a constant acceleration of [tex]a=8\ m/s^2[/tex]. The final speed at t=35 seconds is:
[tex]v_f=0+8*35[/tex]
[tex]v_f=280\ m/s[/tex]
Its speed will be 280 m/s
Can someone help me with this question??
Answer:
3.3
Explanation:
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?
Answer:
a. t = 2.02 s
b. d = 20.2 m
Explanation:
Horizontal Motion
If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The time the object takes to hit the ground can be calculated as follows:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The time does not depend on the initial speed.
The range or maximum horizontal distance traveled by the object can be calculated by the equation:
[tex]\displaystyle d=v.t[/tex]
The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.
a.
The time taken by the rock to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]
[tex]\displaystyle t=\sqrt{4.0816}[/tex]
t = 2.02 s
b.
The range is:
[tex]\displaystyle d=10\cdot 2.02[/tex]
d = 20.2 m
What is Newton's third law of motion? Give an example.
Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation: hope this helps :)
what is the speed of a 330kg beam dropped from 40m
Answer:
28 m/s
Explanation:
We can use this constant acceleration kinematic equation to find the speed of this beam as it is dropped from 40 m.
Since the object is dropped vertically downwards, we know that the object is in free-fall.
The acceleration of this object is -g, which is -9.8 m/s² since we are making the positive direction upwards and the negative direction downwards.
The initial velocity is 0 m/s since the object is dropped and starts from rest.
The final velocity is what we are trying to solve for.
The displacement in the y-direction is 40 m.
Now we can see which equation contains these 4 variables:
v² = v₀² + 2aΔxPlug in the known variables.
v² = (0)² + 2(-9.8)(-40)Simplify this equation.
v² = 784Take the square root of both sides.
v = 28 m/sThe speed of the 330 kg beam dropped from 40 m is 28 m/s.
Answer:
28 m/sExplanation:
Given information :
mass = 330kg
height =40m
v = √2gh
Where ;
g = acceleration due to gravity = 9.8 or 10 m/s
h = height
how much total energy of the beam just as it hits the ground =
mgh
[tex]330\times 10\times 40\\\\\\=132000[/tex]
Speed at which the beam will hit the ground :
[tex]v = \sqrt{2\times 10\times40} \\\\=\sqrt{800}\\\\=20\sqrt{2}\\\\v=28.28427[/tex]
Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is
To Find :
The acceleration of the heavier object.
Solution :
Force of gravitation on lighter object by heavier object is :
[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]
Acceleration of lighter object is given by :
[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex] .....1)
Now, acceleration of heavier object when separation between them is 25 km :
[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)
Putting value of m in equation 2, we get :
[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]
Therefore, the acceleration of the heavier object is 100 m/s².
a golf ball has a mass 0.046 kkg rests on a tee it is struck by a golf club with an effectiv mass of 0.22 and speed of 44 assuming the collision is elastic, find the speed of the ball when it leaves the tee
Answer:
210 m/s
Explanation:
We will use this equation for an elastic collision:
m₁v₁ + m₂v₂ = m₁v₁ + m₂v₂ The left side of the equation is before the collision; the right side is after the collision.In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).
Left side of equation:v₁ is 0 m/s since the ball is at rest on the tee.
v₂ is 44 m/s, given in the problem.
Right side of equation:v₁ is what we are trying to find.
v₂ is 0 m/s since the ball will be at rest on the ground.
⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯Plug these values into the elastic collision equation:
(0.046 kg)(0 m/s) + (0.22 kg)(44 m/s) = (0.046 kg)(v₁) + (0.22 kg)(0 m/s)Simplify this equation.
(0.22 kg)(44 m/s) = (0.046 kg)(v₁)Get rid of the units.
(0.22)(44) = 0.046v₁Multiply the left side of the equation.
9.68 = 0.046v₁Divide both sides by 0.046.
210.434782609 = v₁ 210 m/s = v₁The speed of the ball when it leaves the tee is about 210 m/s.
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Answer:
[tex]a=2.4\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]
So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].
HELP PLEASE NOW!!!!!!
A car slows down from -27.7m/s to -10.9m/s while undergoing a displacment of -105m. What was its acceleration?
Given :
A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m.
To Find :
The acceleration of the car.
Solution :
We know, by equation of motion :
[tex]2as = v^2 -u^2\\\\a = \dfrac{v^2 -u^2 }{2s}\\\\a = \dfrac{(-10.9)^2 - ( -27.7)^2}{2\times ( -105 )}\\\\a = 3.088\ m/s^2[/tex]
Therefore, acceleration of the car is 3.088 m/s².
A car accelerates at a rate of 2.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 28.0 m/s?
Answer:
[tex]\huge\boxed{\sf Time = 10 \ seconds}[/tex]
Explanation:
Given:
Initial Velocity = [tex]\sf V_{i}[/tex] = 8.0 m/s
Final Speed = [tex]\sf V_{f}[/tex] = 28.0 m/s
Acceleration = a = ?
Required:
Time = t = ?
Formula:
[tex]\sf a = \frac{V_{f} - V_{i}}{t}[/tex]
Solution:
[tex]\sf 2 = \frac{28-8}{t} \\\\2 = \frac{20}{t} \\\\t = \frac{20}{2} \\\\t = 10 \ seconds\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807how is this please help me
Answer:
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A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is the force opposing the motion of the car
Answer:
5000 N
Explanation:
Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.
Since the car is moving with constant velocity, a = 0.
So, F - f = ma
F - f = m(0)
F - f = 0
F = f.
Since F = 5000 N and F = f, f = 5000 N.
So, the opposing force is 5000 N
The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
The opposing force can be calculated by the formula,
F - f = ma
Where,
F = driving force = 5000 N,
f = opposing force = ?
m = mass of car = 11000 N
a = acceleration of car
Since, the car is at constant velocity, a = 0.
So,
F - f = m(0)
F - f = 0
F = f.
Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
To know more about opposing force,
https://brainly.com/question/866413
