Answer:
C
Explanation:
don't worry Tama yan base sa pagkakaintindi ko
can someone sent some gravity questions
Answer:
can gravity from waves
Explanation:
yes gravity can froms way
A new tube is used each time a blood sample is tested.Explain why valid results are only obtained if each tube is identical
Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.
Discussion:
During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.
This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.
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The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?
The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The variation of the volume is: ΔV = 7.67 cm³
Pressure is defined by the relationship between force and area.
P = F / A
The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.
PV = nR T
Where P is pressure, V is volume, and T is temperature.
Let's write this equation for two points assuming that the temperature has not changed.
P₀ V₀ = P₁ V₁
V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex] (1)
The subscript "o" is used for the start point and the subscript "1" for the end point.
The pressure in a barometer is:
P = ρ g y
They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.
The volume of the cylinder is
V = π r² y
Let's calculate the initial volume.
V₀ = π 1 9
V₀ = 28.27 cm³
We substitute in equation 1.
V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]
V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]
Let's calculate.
V₁ = [tex]\frac{75}{59} \ 27.27[/tex]
V₁ = 35.94 cm³
The volume to be incremented is
ΔV = V₁ - V₀
ΔV = 35.94 - 28.27
ΔV = 7.67 cm³
Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The change of the volume is: ΔV = 7.67 cm³
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A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?
The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀
The speed of the chord wave is given by the relationship between the tension and the density of the medium.
[tex]v= \sqrt{\frac{T}{\mu } }[/tex]
Where v is the velocity of the wave, T the tension of the string and μ the density
In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.
2L = n λ
Where L is the length of the chord and call the wavelength
Wave speeds are related to wavelength and frequency.
v = λ f
We substitute.
[tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]
For the fundamental frequency n = 1
f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]
They indicate that the tension increases 1.70%
T = T₀ + 0.17 T₀
T = 1.17 T₀
We substitute.
[tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]
f = ra1.17 f₀
f = 1.08 f₀
In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀Learn more about string resonance here: brainly.com/question/16010929
How can you cause a cart moving to the right at a constant speed to move to the left at a constant speed.
Answer:
The answer is below hoped it helped
Explanation:
Forces, when unbalanced, cause objects to accelerate. And the direction of the acceleration is the same as the direction of the extra force. Just because an object is moving to the right does not mean there is more right force than left force. Whether the right or the left force is bigger depends on whether the object is speeding up or slowing down. There must be more right force than left force if an object is moving to the right and speeding up. There must be more left force than right force if an object is moving to the right and slowing down.
4. Analyze: Drag this tile to the green strip. Turn on Show results.
A. What units are given to the right of the equals sign? _ 11,000
B. Why didn't the units cancel in this case? The tile is not fupped
C. What do you think you could do to make them cancel?
Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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Of the Three elements listed, which element is NOT present in the mixture?
Element D
Element A
Element Z
Answer:
element ammmkkkv was a very good
What are the two factors that affect the gravitational pull between two objects?
Answer:
hen dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance.
Explanation:
Guys plz i need those answers as soon as possible
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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A very light rod 40cm long is pivoted at the centre. A weight of 50N is placed at one end. Where is the place to put a weight of 200N in order that the rod is in equilibrium?
Hi there!
We can go about this problem using a summation of torques.
In order to ensure the rod is in equilibrium, we must satisfy the condition:
Στ = 0
Since the rod is "very light", we can disregard its mass.
The equation for torque is:
τ = rFsinθ
In this instance, the torques are the weights of the objects and their distance from the pivot.
As the rod is 40 cm, the pivot is at 20 cm. Also, the torques must sum up to 0, so:
0 = rF1 - rF2
r1F1 = r2F2
0.20(50) = r2(200)
Solve:
10 = r2(200)
r2 = 0.05 m = 5 cm
The 200N weight must be put at a distance of 5 cm from the OTHER SIDE of the pivot in order to balance the rod.
Question 1 of 11
The book has a mass of 2.5 kg.
What net force must act on the book to make it accelerate to the left at a rate
of 7.0 m/s2? (Hint: Use F = ma.)
O A. F = 17.5 N right
OB. F = 2.8 N right
O C. F = 2.8 N left
O D. F = 17.5 N left
Answer:
D. F= 17.5 N left
Explanation:
I just took the quiz and got it correct!
helppp mee pllleasse
Answer:
up swelling moves water horizontally
A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.
While it is being thrown, what is the acceleration experienced by the cheeseburger?
Answer in units of m/s2
Which colour of light is refracted more by a prsim green or blue.explain
Answer:
The light waves are refracted as they enter and leave the prism. The shorter the wavelength of the light, the more it is refracted. As a result, red light is refracted the least and violet light is refracted the most - causing the coloured light to spread out to form a spectrum.
Explanation:
hope this helps
Answer: Neither, its actually violet aka purple. This is because it has the shortest wavelength. This is also why red light is refracted the least because it has the longest wavelength.
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Consider a space shuttle which has a mass of about 1.0 x 105 kg and circles the Earth at an altitude of about 200.0 km. Calculate the force of gravity that the space shuttle experiences. The mass of the earth is?
Answer:
1.6675×10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/r²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²
g = 6.67×10^-6/4×10^10
g = 1.6675×10^{-6-10}
g = 1.6675×10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N
HEEEEEELLLLLLLLPPPPPPPP!!!!!!!!!!
Answer:
True
True
False (Temperature measures the average kinetic energy of the particles in a substance. Thermal energy measures the total kinetic energy of the particles in a substance.)
False (is true only if both object have the same mass)
False (it's 100°)
True
True
True
True
False (Substances with a high specific heat require a lot of heat to have their temperature raised by one degree. On the other hand, substances with a low specific heat require a smaller amount of heat, like most metals)
what is faster?
A. train
B. bus
C. airplane
D. boat
Answer:
airplane
Explanation:
Answer:
a plane would go by far the fastest
Explanation:
it would be airplane ,train, boat, bus
Na + KCL -> K + NaCI reaction type
Explanation:
it is a displacement reaction.
Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:
V = E/Q
Where V is potential difference, E is energy and Q is charge. Given that:
V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.
V = E/Q
15 = 5.25 * 10³ /Q
Q = 350 Coulomb
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
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what is the meaning of physics
Answer:
the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.
Explanation:
What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5. 6 m/s? â€""9. 8 m/s2 0 m/s2 5. 6 m/s2 9. 8 m/s2.
The horizontal acceleration of a ball that is launched horizontally is equal to: B. 0 [tex]m/s^2[/tex]
Given the following data:
Horizontal velocity = 5.6 m/sTo determine the horizontal acceleration of a ball that is launched horizontally:
Acceleration can be defined as the rate of change of velocity with respect to time. In Physics, the acceleration of an object or body is calculated by subtracting its initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]Acceleration = \frac{V\; -\;U}{t}[/tex]
The projectile motion of an object launched horizontally has a constant velocity and as such its horizontal acceleration would be equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).
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Which of the following correctly describes the law of conservation of matter?
Group of answer choices
A.) Matter can only be created, but not destroyed in chemical equations
B.) Matter can neither be created nor destroyed during a chemical reaction
C.) Matter can be destroyed during a chemical reaction as long as it is created again in a different reaction
D.) Matter makes up 98% of stuff in the universe, so it has to be created and destroyed sometimes
Answer:
C
Explanation:
Tama Po yan don't worry
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
Answer:
100 m/s
Explanation:
Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.
Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.
Without:
The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in deathWith safety:
The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happenA box with a weight of 20 newtons rest at a bottom of a ramp and is pushed to the end of the ramp with a force of 40 newtons. This ramp is an incline of 15 meters long. What is the maximum height of the ramp.
To move maximum height the friction force can be assumed to be
negligible.
The height of the ramp is 15 metersReasons:
The component of the weight acting on the incline, w = m·g·sin(θ)
Length of the ramp = 15 m
Potential energy of the box = 15 × sin(θ) ×20 = 300·sin(θ)
F × 15 = 300·sin(θ)
F = 20·sin(θ)
Work done by net force = Potential energy gained by the box
Work done by net force = (40 - 20·sin(θ)) × 15 = 300·sin(θ)
40 = 20·sin(θ) + 20·sin(θ) = 40·sin(θ)
sin(θ) = 1
θ = arcsin(1) = 90°
The ramp is at an inclination of 90°, therefore, the ramp is oriented vertically
The height of the ramp = The length of the ramp = 15 m
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What happens to the sound an object makes when the speed of vibrations decreases (slow down)?.
What happens in a nucleus during beta decay
The numbers of protons increases
The number of neutrons increases
The number of protons decrease
The number of protons plus the number of neutrons decreases
The number of protons plus the number of neutrons decreases
Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other. In beta minus decay, a neutron decays into a proton, an electron, and an antineutrino: n Æ p + e - +.
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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