Calculate the size of angle 'i' in the triangle illustrated below.​

Calculate The Size Of Angle 'i' In The Triangle Illustrated Below.

Answers

Answer 1

Answer:

B. 75°

Step-by-step explanation:

The 2 lines are parallel, so corresponding angles theorem should prove that i is equal to 75°

Answer 2

Answer:

75 degrees

Step-by-step explanation:


Related Questions

For a specific location in a particularly rainy city, the time a new thunderstorm begins to produce rain (first drop time) is uniformly distributed throughout the day and independent of this first drop time for the surrounding days. Given that it will rain at some point both of the next two days, what is the probability that the first drop of rain will be felt between 8: 40 AM and 2: 35 PM on both days? a) 0.2479 Web) 0.0608 om c) 0.2465 d) 0.9385 e) 0.0615 f) None of the above.

Answers

Answer:

b) 0.0608

Step-by-step explanation:

As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed

Therefore the rain probability is

[tex]= \frac{T}{24}[/tex]

where,

T = Length of the time interval

Plus, as we know that rain is independent

So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes

i.e

= 5.91666 hours long.

So, P1 should be

[tex]= \frac{5.91666}{24}[/tex]

= 0.2465

Now we assume the probability of rain on day 2 is P2

So it would be same  i.e 0.2465

Since these events are independent

So, the total probability is

[tex]= 0.2465 \times 0.2465[/tex]

= 0.0608

Hence, the b option is correct

Five-thirds divided by one-third =

Answers

Answer:

Step-by-step explanation: [tex]\frac{5}{3}[/tex]÷[tex]\frac{1}{3}[/tex] =

(Decimal: 0.555556)

6. Factor the expression.
9b2 + 48b + 64
A (3b + 8)2
B (-3b + 8)2
C (-3b - 82
D (3b - 8)2
70%​

Answers

Answer:

A. [tex](3b+8)^2[/tex]

Step-by-step explanation:

[tex]9b^2+48b +64\\=(3b)^2 + 2\times 3b\times 8 +(8)^2\\=(3b+8)^2[/tex]

What is the algebraic expression for "the sum of three times a number and seven"? A. 3 x + 7 B. 3 x + 11 x C. 3 + 7 x

Answers

Answer:

3x+7

Step-by-step explanation:

Three times a number, let x be the number and 7 so plus 7

The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.

The given phrase is "the sum of three times a number and seven".

Variables and constants are combined to generate algebraic expressions using a variety of techniques. Terms comprise expressions. A term is the sum of several elements. Both numerical and algebraic (literal) factors are acceptable.

Let the unknown number be x.

Three times of a number = 3x

The number 7 is added to the  obtained sum.

That is, 3x+7

So, the expression is 3x+7

The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.

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The graph below shows the solution to which system of inequalities?

Answers

Answer:

B

Step-by-step explanation:

The solid red line is y = x + 8 and the dashed line is y = -1/2x. Since the solution is shaded on the left side of y = x + 8 we know that the first part is y ≥ x + 8. We use ≥ and not > because the line is solid, meaning that all points on the line are also solutions to the inequality. The solution is shaded on the right side of y = -1/2x so the second part is y > -1/2x. We use > and not ≥ because the line is dashed, meaning that the points on the line are not solutions to the inequality. Therefore, the answer is y ≥ x + 8 and y > -1/2x.

The graph of Fx), shown below, resembles the graph of G(x) = x2, but it has
been changed somewhat. Which of the following could be the equation of
F(x)?

Answers

Answer:

Correct answer is:

C. [tex]F(x) =-x^{2} -3[/tex]

Step-by-step explanation:

We are given a function:

[tex]G(x) = x^{2}[/tex]

The graph of [tex]G(x)[/tex] is also shown in the given question figure.

It is a parabola with vertex at (0,0).

Sign of [tex]x^{2}[/tex] is positive, that is why the parabola opens up.

General equation of parabola is given as:

[tex]y = a(x-h)^2+k[/tex]

Here, in G(x), a = 1

Vertex (h,k) is (0,0).

As seen from the question figure,

The graph of F(x) opens down that is why it will have:

Sign of [tex]x^{2}[/tex] as negative. i.e. [tex]a = -1[/tex]

And vertex is at (0,-3)

Putting the values of a and vertex coordinates,

Hence, the equation of parabola will become:

[tex]y = -1(x-0)^2+(-3)\\y = -x^2-3[/tex]

The correct answer is:

C. [tex]F(x) =-x^{2} -3[/tex]

The required equation of graph f(x) is [tex]y = -x^{2} -3[/tex]

Given that,

The graph of f(x), resembles the graph of G(x) = [tex]x^{2}[/tex].

We have to find,

Which of the following could be the equation of  f(x).

According to the question,

Function, [tex]G(x) = x^{2}[/tex],

The graph in the given question figure. It is a parabola with vertex at (0,0).

By the graph predict that Sign of [tex]x^{2}[/tex]  is positive, that is why the parabola opens up.

General equation of parabola is given by,

[tex]y = a(x-h)^{2} +k[/tex]

Where, a = 1, and vertex (h, k) is (0,0).

The graph of F(x) unknown function opens down ,

Sign of [tex]x^{2}[/tex] as negative. and the vertex is at (0,-3)

To find the equation of function f(x),

Putting the values of a and vertex coordinates,

[tex]y = a(x-h)^{2} +k[/tex]

The equation of parabola become:

[tex]y = -1(x-0)^{2} +(-3)\\\\y = -x^{2} -3[/tex]

Hence, The required equation of f(x) is [tex]y = -x^{2} -3[/tex].

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Find the interquartile range (IQR) of the data in the dot plot below. luis lacrosse scoring each season pls helpppppppppppppppp

Answers

Answer:

3.5

Step-by-step Explanation:

To find the IQR of the given data in the dot plot shown in the attachment below, follow the steps below:

==>Step 1: write out each data point represented on the dot plot in an ordered manner. A dot represents each value of number of goals scored by Luis each season.

Thus, we would have:

43 (1 dot)

44, 44, 44 (3 dots)

45, 45(2 dots)

47 (1 dot)

48, 48 (2 dots)

Our data set from the least to the highest is: 43, 44, 44, 44, 45, 45, 47, 48, 48

==>Step 2: Find the median

Our median value is the middle value of our data set. Thus:

43, 44, 44, 44, | 45, | 45, 47, 48, 48

Our median would be 45.

==>Step 3: Find the upper and lower median (Q3 & Q1):

Our upper median (Q3) would be the middle value of the upper portion of our data set, while our lower median would be the middle value portion of our data set.

Upper portion of our data set are the values we have from our median point upwards towards our right, while the lower portion are values downwards to our left. Thus, our upper and lower median values are shown below which would be the mean of the 2 middle values shown in the brackets below:

43, (44, 44,) 44, | 45, | 45, (47, 48,) 48

Upper median (Q3) = (47+48) ÷ 2 = 47.5

Lower median (Q1) = (44+44) ÷ 2 = 44

==>Step 4: Subtract the lower median from the upper median to get the IQR.

IQR = Upper median (Q3) - Lower median (Q1)

IQR = 47.5 - 44

IQR = 3.5

Answer:

3.5

Step-by-step Explanation:

To find the IQR of the given data in the dot plot shown in the attachment below, follow the steps below:

==>Step 1: write out each data point represented on the dot plot in an ordered manner. A dot represents each value of number of goals scored by Luis each season.

Thus, we would have:

43 (1 dot)

44, 44, 44 (3 dots)

45, 45(2 dots)

47 (1 dot)

48, 48 (2 dots)

Our data set from the least to the highest is: 43, 44, 44, 44, 45, 45, 47, 48, 48

==>Step 2: Find the median

Our median value is the middle value of our data set. Thus:

43, 44, 44, 44, | 45, | 45, 47, 48, 48

Our median would be 45.

==>Step 3: Find the upper and lower median (Q3 & Q1):

Our upper median (Q3) would be the middle value of the upper portion of our data set, while our lower median would be the middle value portion of our data set.

Upper portion of our data set are the values we have from our median point upwards towards our right, while the lower portion are values downwards to our left. Thus, our upper and lower median values are shown below which would be the mean of the 2 middle values shown in the brackets below:

43, (44, 44,) 44, | 45, | 45, (47, 48,) 48

Upper median (Q3) = (47+48) ÷ 2 = 47.5

Lower median (Q1) = (44+44) ÷ 2 = 44

==>Step 4: Subtract the lower median from the upper median to get the IQR.

IQR = Upper median (Q3) - Lower median (Q1)

IQR = 47.5 - 44

IQR = 3.5

Farhan has three pieces of rope with lengths of 140cm, 168cm and 210cm. He wishes to cut all the three pieces of ropes into smaller pieces of equal length and that there is no leftover rope. (i) What is the greatest possible length of each of the smaller pieces of rope? How many smaller pieces of rope can he get altogether?
give correct answer

Answers

Answer:

The greatest possible length is 14 cm.

The total number of smaller pieces is 37.

Step-by-step explanation:

The greatest common factor of these three numbers is 14.

Total number of smaller pieces = 10+12+15 = 37

Best Regards!

What is the value of x?
57°
(3x + 6)°

Answers

Answer:

x = 9

Step-by-step explanation:

Answer:

x = 9

Step-by-step explanation:

a right angle is 90 degrees, so

90 - 57 = 33

33 - 6 = 27

3 * 9 = 27 :)

Question from quadratic equation .
solve.
(x-3)(x+7)=0

Answers

Answer:

x = 3, -7

Step-by-step explanation:

Since you already have the factored form, all you need to do is set the equations equal to zero to find you roots:

x - 3 = 0

x + 7 = 0

x = 3, -7

Answer:

3 or -7

Step-by-step explanation:

For it to equal 0, x must be 3 or -7 because anything multiplied by 0 is 0. So you take each part, x-3 and see how you can make that a 0. x-3=0, therefore x must be 3. Other part x+7=0, x must be -7.

According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year, and approximately 3% of all births in the United States result in birth defects each year. Consider two babies being born independently of one another. 1. The probability that both babies have birth defects is;______ a. 0.0009. b. 0.0400.c. 0.0606. d. 0.2000. 2. The probability that neither baby catches the flu in a given year is:_____ a. 0.024. b. 0.040. c. 0.230 d. 0.640. 3. Event A occurs with probability 0.1. Event B occurs with probability 0.6. If A and B are independent, then:______ a. P(A and B) = 0.06. b. P(A or B) = 0.70. c. P(A and B) = 0.70. d. P(A or B) = 0.06. 4. Event A occurs with probability 0.2. Event B occurs with probability 0.9. Event A and B:______ are disjoint cannot be independent. cannot be disjoint. are reciprocating. The center for Disease Control and Prevention reports that the rate of Chlamydia infections among American women ages 20 to 24 is 2791.5 per 100,000. Take a random sample of three American women in this age group. 5. The probability that all of them have a Chlamydia infection is:_____ a. nearly 0. b. 0.028. c. 0.084. d. 0.837 6. The probability that none of them have a Chlamydia infection is:_______ a. 0.084. b. 0.919. c. 0.972. d. nearly 1.

Answers

Answer:

(1) a. 0.0009

(2) d. 0.640

(3)

a. P(A and B) = 0.06. b. P(A or B) = 0.70.

(4)Not disjoint

(5) a. nearly 0.

(6)b. 0.919

Step-by-Step Explanation:

(1)Probability of a baby being born with a birth defect =3%=0.03

The probability that both babies have birth defects=0.03 X 0.03= 0.0009.

(2)The probability of contracting the influenza virus each year = 20%=0.2

Therefore, the probability of not contracting the influenza virus =1-0.2=0.8

The probability that neither baby catches the flu in a given year:

=0.8 X  0.8

=0.64

(3)

P(A)=0.1

P(B)=0.6

P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7

P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06

(4)

P(A)=0.2

P(B)=0.9

Event A and B cannot be disjoint.

(5)

The probability of an American woman aged 20 to 24 having Chlamydia infection  [tex]=\dfrac{2791.5}{100000}[/tex]

The probability that three randomly selected women in this age group have the infection

[tex]=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0[/tex]

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection  [tex]=1-\dfrac{2791.5}{100000}[/tex]

The probability that three randomly selected women in this age group do not have the infection

[tex]=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919[/tex]

Sal bought 2 shirts and a hat. Sal remembers each shirt was $10, and the total was $50. Which equation helps answer the question: How much were the hat? A: 10 + x = 50 B: 10 + 10 + x = 50 C: x = 50 + 10 D: 10 + 10 = 50 + x 1

Answers

Answer:

The answer is B.

Step-by-step explanation:

There are two shirts, both cost 10.

10 + 10.

The variable is the cost of the hat, which we add on.

10 + 10 + x.

Finally, 50 is the total price so that is going to be what it equals.

10 + 10 + x = 50

plzzzzzzzzzzz help asap plz

Answers

Answer:

Area: 96

Perimeter: 44

Step-by-step explanation:

The area of a parallelogram is the height multiplied by the base, which in this case is 8 and 12, respectively. This means that the area is 96 square centimeters. The perimeter is the sum of all the side lengths, or 10+12+10+12=44 cm. Hope this helps!

A newsletter publisher believes that less than 29% of their readers own a Rolls Royce. Is there sufficient evidence at the 0.02 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.

Answers

Answer:

For this case they want to proof if the proportion of readers own a Rolls royce is less than 0.29 and that wuld be the alternative hypothesis. The complement would represent the null hypothesis. Then the system of hypothesis for this case are:

Null hypothesis: [tex] p \geq 0.29[/tex]

Alternative hypothesis: [tex]p< 0.29[/tex]

Step-by-step explanation:

For this case they want to proof if the proportion of readers own a Rolls royce is less than 0.29 and that wuld be the alternative hypothesis. The complement would represent the null hypothesis. Then the system of hypothesis for this case are:

Null hypothesis: [tex] p \geq 0.29[/tex]

Alternative hypothesis: [tex]p< 0.29[/tex]

What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Superscript 9 Baseline EndRoot

Answers

Answer:

[tex] 4x^5\sqrt[3]{3x} [/tex]

Step-by-step explanation:

I'm not sure I understand the problem, but I think it's this:

[tex] \sqrt[3]{16x^7} \times \sqrt[3]{12x^9} = [/tex]

[tex]= \sqrt[3]{16 \times 12 \times x^{16}}[/tex]

[tex]= \sqrt[3]{192 \times x^{15} \times x}[/tex]

[tex] = \sqrt[3]{64 \times 3 \times (x^5)^3 \times x} [/tex]

[tex] = \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x} [/tex]

[tex] = 4x^5\sqrt[3]{3x} [/tex]

The product of the given expression [tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9}[/tex] will be [tex]4x ^5\sqrt[3]{3x}[/tex].

[tex]4x ^5\sqrt[3]{3x}[/tex].

What are some basic properties of exponentiation?

If we have a^b then 'a' is called the base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

[tex]a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\[/tex]

The given expression is follows as

[tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} \\\\\sqrt[3]{16\times 12 \times x^{16}} \\\\\sqrt[3]{192\times x \times x^{15}} \\\\\sqrt[3]{64\times 3\times x \times (x^{5})^3} \\\\\sqrt[3]{4^3 \times 3\times x \times (x^{5})^3}[/tex]

[tex]4x ^5\sqrt[3]{3x}[/tex]

Therefore, the product of the given expression [tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9}[/tex] will be [tex]4x ^5\sqrt[3]{3x}[/tex].

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An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:
420 425 427 427 432 433 434 437 439 446 447 448 453 454 465 469
Suppose the sample is from a normal population.
(a) Calculate a 95% confidence interval for the population mean, and interpret it.
(b) Calculate a 95% upper confidence bound for the population mean, and interpret it.

Answers

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex] = 441

            s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]  = 14.34

            n = sample size = 16

            [tex]\mu[/tex] = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.131 < [tex]t_1_5[/tex] < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.131) = 0.95

P( [tex]-2.131 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.131 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.131 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.131 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X -2.131 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X +2.131 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                      = [ [tex]441-2.131 \times {\frac{14.34}{\sqrt{16} } }[/tex] , [tex]441+2.131 \times {\frac{14.34}{\sqrt{16} } }[/tex] ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

the value of √-2,√-3 is​

Answers

[tex]\sqrt{-2}[/tex]

[tex]=\sqrt{-1}\sqrt{2}[/tex]

[tex]=\sqrt{2}i[/tex]

[tex]\sqrt{-3}[/tex]

[tex]=\sqrt{-1}\sqrt{3}[/tex]

[tex]=\sqrt{3}i[/tex]

Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the estimated product?

Answers

Answer: first box is 20 (1/2)

Second box is 10

Answer:

Answer: first box is 20 (1/2)

Second box is 10

Step-by-step explanation:

HELP ASAP!!!The first picture is what each variables equal too

Answers

Answer:

Just replace the variables with the number

d5

c4 (uh oh)

a2

b-3

f-7

d-c = 5 - 4 = 1

1/3 - 4(ab+f)

2 x -3 = -6

-6 + -7 = -13

-13 x 4 = -52

1/3 - -52 = 1/3 + 52 =

52 1/3

Hope this helps

Step-by-step explanation:

(
[tex] \sqrt{2 - 1( \sqrt{2 + 3} } [/tex]

(​

Answers

This would be the exact value

Will give BRAINLIEST! Find the set of x values that satisfy this inequality. 2 | 5x − 4 | > 6 Select one:a. x ≤ 7 / 5 and x ≥ 1 / 5b. x > 7 / 5c. x > 7 / 5 or x < 1 / 5d. 1 / 5 ≤ x ≤ 7 / 5

Answers

Answer:

c. x > 7 / 5 or x < 1 / 5

Step-by-step explanation:

2 | 5x − 4 | > 6

| 5x - 4 | > 3

5x -4 > 3 ⇒ 5x > 7 ⇒ x > 7/55x -4 < -3 ⇒ 5x < 1 ⇒ x < 1/5

So combining the 2 above we get:

x > 7/5 or x < 1/5

Correct choice is c.

Answer:

x>7/5                 or            x <1/5

Step-by-step explanation:

2 | 5x − 4 | > 6

Divide by 2

2/2 | 5x − 4 | > 6/2

 | 5x − 4 | > 3

There are two solutions one positive and one negative ( the negative flips the inequality)

5x-4 >3      or         5x-4 < -3

Add 4 to each side

5x-4 +4>3+4   or              5x-4+4 < -3+4

5x >7                  or            5x <1

Divide by 5

x>7/5                 or            x <1/5

P(5,12)
find cosec theta?

Answers

Answer:

[tex] \frac{13}{12}[/tex]

Step-by-step explanation:

[tex]p(5, \: \: 12) = (x, \: \: y) \\ \implies \: x = 5, \: \: y = 12 \\ \because \: {r}^{2} = {x}^{2} + {y}^{2} \\ \therefore \: {r}^{2} = {5}^{2} + {12}^{2} = 25 + 144 = 169 \\ \therefore \: {r} = \sqrt{169} \\ \therefore \: {r} = 13 \\ \because \cosec \theta = \frac{r}{y} \\ \therefore \cosec \theta = \frac{13}{12} \\ [/tex]

How many solutions does 6-3x=4-x-3-2x have?

Answers

Answer:

no solutions

Step-by-step explanation:

6-3x=4-x-3-2x

Combine like terms

6-3x =1 -3x

Add 3x to each side

6 -3x+3x = 1-3x+3x

6 =1

This is not true so there are no solutions

Answer:

No solutions.

Step-by-step explanation:

6 - 3x = 4 - x - 3 - 2x

Add or subtract like terms if possible.

6 - 3x = -3x + 1

Add -1 and 3x on both sides.

6 - 1 = -3x + 3x

5 = 0

There are no solutions.

Make a situation where 8=D

Answers

Answer:

Some situation can be where D equals

8800/1001600/50

Step-by-step explanation:

8 is also known as 8 wholes so,

800/100 and 1600/50 are both equal to 8.

Please mark Brainliest

Let's write an equation.

[tex]\frac{3}{2}d = 12[/tex]

If d is being multiplied by a fraction, simply multiply both sides of the equation by the reciprocal of that fraction to get d by itself.

So in this problem, since d is being multiplied by 3/2,

we multiply both sides of the equation by 2/3.

On the left, (2/3)(3/2) cancels out and on the right, if you multiply 12 by 2/3, the 12 and 3 reduce to 4 and 1 so we have (4)(2) which is 8.

Find the derivative of g(t)=3t^2+2t at t=-1 algebraically

Answers

Answer:

8.

Step-by-step explanation:

If y = ax^n then the derivative y' = anx^(n-1)

g(t) = 3t^2 + 2t so  the derivative g'(t)

2*3 t^(2-1) + 2t(1-1)

= 6t + 2

At t =1 its value is  6 + 2 = 8.

the mean of the prime factors of 24 is

Answers

Answer:

bad words

Step-by-step explanation:

it is your shet

Answer:

2.25

Step-by-step explanation:

Prime Factors of 24 is 2 x 2 x 2 x 3

2 + 2 + 2 + 3 = 9

9/4 = 2.25

I need help for the solution​

Answers

Answer:

[tex]\boxed{ \ dY_t=(2\theta+2\psi Y_t+\phi^2)dt+2\phi \sqrt{Y_t}dW_t\ }[/tex]

Step-by-step explanation:

it is a long time I have not applied Ito's lemma

I would say the following

for [tex]f(x)=x^2[/tex]

f'(x)=2x

f''(x)=2

so using Ito's lemma we can write that

[tex]dY_t=2V_tdV_t+\phi^2dt[/tex]

[tex]dY_t=2(\theta+\psi V_t^2)dt+2\phi V_tdW_t+\phi^2dt[/tex]

[tex]dY_t=(2\theta+2\psi V_t^2+\phi^2)dt+2\phi V_tdW_t[/tex]

so it comes

[tex]dY_t=(2\theta+2\psi Y_t+\phi^2)dt+2\phi \sqrt{Y_t}dW_t[/tex]

What number should be in the blank in the sequence? 7; 17; 37; 77; ___ ; 317

Answers

Answer:

157

Step-by-step explanation:

Given the sequence

7; 17; 37; 77; ___ ; 317

17-7=1037-17=2077-37=40

Let the blank space=x

We notice that the difference is always multiplied by 2.

Therefore:

x-77=80

x=80+77

x=157

The number that should be in the blank space of the sequence is 157.

Now, observe the pattern in full:

17-7=1037-17=2077-37=40157-77=80317-157=160

The sequence concept to solve the problem. Then the missing number of the sequence is 157.

What is a sequence?

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

Given

The sequence is [tex]7, 17, 37, 77, \_\_\_\_ , 317[/tex]

We can observe that the difference is getting double That can be given as

[tex]1 7\ \ - 7 = 10\\\\37 - 17 = 20 \\\\77 - 37 = 40[/tex] and so on.

Then the fourth number will be

[tex]77 + 80 = 157[/tex]

Then the fifth number will be

[tex]157+160 = 317[/tex]

Thus, the missing number of the sequence is 157.

More about the sequence link is given below.

https://brainly.com/question/21961097

Sample data for the arrival delay times (in minutes) of airlines flights is given below. Determine whether they appear to be from a population with a normal distribution. Assume that this requirement is loose in the sense that the population distribution need not be exactly normal, but it must be a distribution that is roughly bell-shaped Click the icon to view the data set. Is the requirement of a normal distribution satisfied? A. No, because the histogram of the data is not bell shaped, there is more than one outlier, and B. Yes, because the histogram of the data is bell shaped, there are less than two outliers, and the C. Yes, because the histogram of the data is not bell shaped, there is more than one outlier, and D. No, because the histogram of the data is bell shaped, there are less than two outliers, and the the points in the normal quantile plot do not lie reasonably close to a straight line points in the normal quantile plot lie reasonably close to a straight line the points in the normal quantile plot do not lie reasonably close to a straight line points in the normal quantile plot lie reasonably close to a straight line Arrival delay times (minutes) 9 40 - 36 36 105 15- 45 45 27 32 24 5-30 38 2 16 -31 -21-45-30 9837 14 29 50 -44-37 41 - 4-2510 3 -27 6 -38 -26 -25

Answers

Answer:

sdvsdsdfdff

Step-by-step explanation:

Moises read a book that is more than 200 pages long. It took him 10 days, and he read the same number of pages each day. The inequality 10 p greater-than 200 represents the possible values of p, the number of pages he read each day.

Which is a possible value of p?.
10
15
20
25

Answers

Answer:

25

Step-by-step explanation:

10p > 200

10 * 10 < 200

10 * 15 < 200

10 * 20 = 200

10 * 25 > 200

Answer:

The answer is D

Step-by-step explanation:

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