The magnitude of electrical force on charge [tex]q_{3}[/tex] due to the others is 0.102 newtons.
How to calculate the electrical force experimented on a particle
The vector position of each particle respect to origin are described below:
[tex]\vec r_{1} = (-0.500, 0)\,[m][/tex]
[tex]\vec r_{2} = (+0.500, 0)\,[m][/tex]
[tex]\vec r_{3} = (0, +0.500)\,[m][/tex]
Then, distances of the former two particles particles respect to the latter one are found now:
[tex]\vec r_{13} = (+0.500, +0.500)\,[m][/tex]
[tex]r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}[/tex]
[tex]r_{13} =\frac{\sqrt{2}}{2}\,m[/tex]
[tex]\vec r_{23} = (-0.500, +0.500)\,[m][/tex]
[tex]r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}[/tex]
[tex]r_{23} =\frac{\sqrt{2}}{2}\,m[/tex]
The resultant force is found by Coulomb's law and principle of superposition:
[tex]\vec R = \vec F_{13}+\vec F_{23}[/tex] (1)
Please notice that particles with charges of same sign attract each other and particles with charges of opposite sign repeal each other.
[tex]\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}[/tex] (2)
Where:
[tex]k[/tex] - Electrostatic constant, in newton-square meters per square Coulomb.[tex]q_{1}[/tex], [tex]q_{2}[/tex], [tex]q_{3}[/tex] - Electric charges, in Coulombs.[tex]r_{13}[/tex], [tex]r_{23}[/tex] - Distances between particles, in meters.[tex]\vec u_{13}[/tex], [tex]\vec u_{23}[/tex] - Unit vectors, no unit.If we know that [tex]k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{1} = 2\times 10^{-6}\,C[/tex], [tex]q_{2} = 2\times 10^{-6}\,C[/tex], [tex]q_{3} = 2\times 10^{-6}\,C[/tex], [tex]r_{13} =\frac{\sqrt{2}}{2}\,m[/tex], [tex]r_{23} =\frac{\sqrt{2}}{2}\,m[/tex], [tex]\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)[/tex] and [tex]\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)[/tex], then the vector force on charge [tex]q_{3}[/tex] is:
[tex]\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)[/tex]
[tex]\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N][/tex]
[tex]\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N][/tex]
And the magnitude of the electrical force on charge [tex]q_{3}[/tex] ([tex]R[/tex]), in newtons, due to the others is found by Pythagorean theorem:
[tex]R = 0.102\,N[/tex]
The magnitude of electrical force on charge [tex]q_{3}[/tex] due to the others is 0.102 newtons. [tex]\blacksquare[/tex]
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A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it attains a final velocity of 445 meters/second after 4. 50 seconds. A. 2. 50 × 102 meters B. 1. 00 × 103 meters C. 5. 05 × 102 meters D. 2. 00 × 103 meters E. 1. 00 × 102 meters.
The rocket will cover [tex]1 \times 10^3\rm \ m[/tex] distance in 4. 5 s. Acceleration can be defined as the change in velocity.
What is acceleration?
Acceleration can be defined as the change in speed or the direction of the object.
From kinamatic equation:
[tex]D = v_{t} +\dfrac 12at^2[/tex]
Where,
[tex]D[/tex] - final velocity = 445 m/s
[tex]v_0[/tex] - initial valocity = 0 m/s
[tex]a[/tex] - acceleration = 99. 0 m/s²
[tex]t[/tex] - time = 4. 50 s
Put the values in the formula,
[tex]D = 0\times ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times 10^3\rm \ m[/tex]
Therefore, the rocket will cover [tex]1 \times 10^3\rm \ m[/tex] distance in 4. 5 s.
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anyone help me please
A wave has a wavelength of 2. 30 m and a frequency of 370. 0 Hz. What is the speed of the wave? m/s.
Answer:
154 is the speed i think, correct me if i am wrong
Explanation:
The speed of the given wave is 160.86 m/s. The speed of the wave can be calculated by dividing the frequency by the wavelength of the wave.
How to calculate the speed of the wave?The speed of the wave can be calculated by dividing the frequency by the wavelength of the wave.
[tex]s = \dfrac f \lambda[/tex]
Where,
[tex]f[/tex] - frequency = 370.0 Hz.
[tex]\lambda[/tex] - wavelength = 2.30 m
Put the values in the formula,
[tex]s = \dfrac {370}{2.3}\\\\s =160.86 \rm \ m/s[/tex]
Therefore, the speed of the given wave is 160.86 m/s.
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A person standing at the top of a hemispherical rock of radius R = 13.00 m kicks a ball (initially at rest on the top of the rock) to give it horizontal velocity vi as in Figure P4.62.
Answer:
A ther mody namic system absorbs 300J of heat and at the same time 400J of work is done onit calculate the change
Which answer best describes US national Road
hi the you my live life love
Answer:
it ran from Maryland to Illinois and was made using macadam construction
Weight of a body is 100N, it's weight on the moon is
We know
[tex]\\ \tt\hookrightarrow W_e=6W_m[/tex]
m=moone=earthSo
[tex]\\ \tt\hookrightarrow 100=6W_m[/tex]
[tex]\\ \tt\hookrightarrow W_m=100/6[/tex]
[tex]\\ \tt\hookrightarrow W_m=16.6N[/tex]
A ball is thrown toward the ground. The figure shows the direction of the ball before it reaches the ground and the direction of the ball after it bounces off the ground. After the bounce, the ball leaves the ground with the same speed that it had before the bounce. The angle between the ground and the ball’s direction of travel is θ0 before and after the ball bounces off the ground. The positive directions are indicated in the figure. (a) Each grid below represents a component of the change in momentum of the ball as a result of the bounce. On each grid, draw a vector arrow to indicate the direction and relative magnitude of the change in momentum of the ball as a result of the bounce. If there is no change in momentum for a given component, write "NO CHANGE" under the corresponding grid. (b) A ball of mass M is released from rest at height H1 above the ground. After the ball reaches the ground, it bounces and travels to height H2 (about 1/2 of H1) above the ground, as shown in the figure. In a clear, coherent paragraph-length response that may also contain equations and drawings, explain, using the conservation of momentum and the conservation of energy, why H2
According to the principle of conservation of momentum, the momentum of the bouncing ball changes.
Also, the ball bounces less than its original height because some energy is lost due to heat, friction and air resistance.
How is momentum conserved in the bounce of balls?The principle of conservation of momentum states that for any collision occurring in an isolated system, momentum is conserved.
a. For a body such as a ball dropped from a height, the total momentum is conserved.
However, there is a change in momentum of the ball as some of its momentum is transferred to the earth.
b. When the ball a ball of mass M is released from a height H1, it bounces to a height H2, which is about 1/2 of H1.
The value of H2 is less than that of H1 because some of the energy is converted to heat energy due to friction and air resistance, thereby its energy is less than its original value.
Therefore, the momentum of the bouncing ball is changes. Also, the ball bounces less than its original height because some energy is lost due to heat, friction and air resistance.
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3. What is the acceleration of a car at rest that stays at rest over 10 seconds?
a. 0.0 m/s2
b. 10 mph/s
C.-10 mph/s
d. 10 m/s2
e. Not enough data is given.
Answer:
a.
Explanation:
Use accleration formula,
[tex]a = \frac{v _{f} - v _{i}}{t} [/tex]
The initial velocity and final velocity is at zero. and t=10
So we got
[tex] \frac{0}{10} = 0[/tex]
so
[tex]a = 0[/tex]
a is the answer
PLEASE HELP!!! Predicting the Characteristics of images formed What are the characteristics of the image formed by the object? I F 2F 2F F
Answer:
Real, inverted, equal to body size .
Answer:
Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object.
Explanation:
Edge 2021-2022 :)
Answers are ONLY allowed to be ionic, polar covalent, and nonpolar covalent.
Ionic bonds occur between a metal and a nonmetal.
Covalent bonds occur between only nonmetals.
Polar covalent bonds occur between two nonmetals that are different types of atoms.
Nonpolar covalent bonds occur between the same kinds of nonmetal atoms.
Question:
Oxygen (O) and Oxygen (O)
a.) What type of bond will form between these two elements?
b.) Why?
Calculate the pressure on a man’s foot when a woman of mass 65 kg steps on his foot with her heel which has an area of 0.12m2 with all her weight.
Answer:
Pressure = force/area
= 650N/0.12m^2
= 5416.7 to 1 d.p
I got 650N by taking the gravitational field on earth to be 10N/kg.
Weight = mass x gravitational field
= 65 x 10N/kg
= 650
Answer is 5416.7 pascals (Pa)
Or
5308.3 Pa
if gravitational field was taken to be 9.8N/kg
Hope this helps!
Blank can be considered to be mixtures of minerals
Answer: Igneous Rocks. Like Magma, it's a mixture of many minerals.
Explanation:
If a storm is 7. 5 kilometers away, how much time is expected between observations of lightning and thunder? Round your answer to one decimal place. Seconds.
The expected time period between the observations of lightning and thunder would be 22.5 s.
How to calculate the time of sound waves?
The time taken by sound to reach a certain position can be calculated by the speed formula,
[tex]S = \dfrac dt[/tex]
Where,
[tex]S[/tex] - speed = 0.343 km/s
[tex]d[/tex] - distance = 7.5 km
[tex]t[/tex] - time = ?
Put the values in the formula,
[tex]0.343 = \dfrac {7.5} t\\\\t = \dfrac {0.343}{7.5}\\\\t = 22.5[/tex]
Therefore, the expected time period between the observations of lightning and thunder would be 22.5 s.
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What is the gravitational potential energy of a 1 kilogram ball 100 meters above the floor?
Answer:
gravitational potential energy = 1000 N/kg
Explanation:
Formula used:
gravitational potential energy = mass(kg) * gravity(N) * height(m)
---------------------------------------------------------------------------------------------
Here the mass is 1 kg , gravity is 10N , height is 100 metres
Using the formula: 1 * 10 * 100: 1000 N/kg
The gravitational potential energy of a 1 kilogram ball 100 meters above the floor will be 1000 N/kg.
What is gravitational potential energy ?The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.
The gravitational potential energy is found as;
E=mgh
E=1 ×9.81 ×100
E=981
Hence,the gravitational potential energy will be 981 N/kg.
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#SPJ2
Can someone please help me with this?
Answer:
72 km north
Explanation:
Mark brainliest pl
A _____ provides rapid calculus removal by converting very-high-frequency sound waves into mechanical energy and reduces operator hand fatigue.
Answer:
The Ultrasonic Scaler
Explanation:
How does the amount of energy coming from the energy source (low vs. high) affect the amount of electrical energy created?
Answer:
The environmental problems directly related to energy production and Electricity is a secondary energy source that is generated producedfrom primary energy sources:
hope that helps im new so have a good day (:
As liquid water freezes, what happens to its thermal energy?
A. Thermal Energy remains constant, and kinetic energy decreases.
B. Thermal energy remains constant, and potential energy decreases
C. Thermal energy decreases because kinetic energy is decreasing.
D Thermal energy decreases because potential energy is decreasing.
Answer:
I believe it is C
Explanation:
When the water freezes the kinetic energy decreases because it is staying in place instead of moving around, which also causes thermal energy to decrease.
Answer:
D
Explanation:
The experimentation step of scientific inquiry involves _______. A. Analyzing data b. Drawing a conclusion c. Choosing variables and controls d. Formulating a question Please select the best answer from the choices provided A B C D.
Answer:
C- Choosing variables and controls
Explanation:
Correct on edge.
According to the Law of conservation of energy, potential and kinetic energies should be the same. If they are not, explain in detail why this may be
Answer:
According to the law of conservation of energy, energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant. ... As the car coasts down the hill, it moves faster and so it's kinetic energy increases and it's potential energy decreases.
Explanation:
just simplify this on paraphraser.io you should be good
The total magnification of an image is determined by.
Answer:
Magnification of the objective lens used and the magnification of the ocular lens.
Explanation: I hope you have/had an amazing day today<3
Suppose a car traveled 120 miles in two hours. What can we conclude about the car based on the mean value theorem.
what are the two opposing forces that keep stars between collapsing and inflating?
When a driver injures someone in a DUI crash he can be charged with
a. DUI third party injury
b. DUI personal injury
c. DUI non-victim injury
Though not listed in the options, the correct charge placed on a defendant that caused injury to someone in a DUI crash is that of "DUI with injury" or "DUI serious bodily injury" depending on the gravity of the injury.
What does it mean to be charged with a DUI?Being charged with a DUI means that you were caught "driving while under the influence", meaning that you were under the influence of alcohol or other motor skill impairing substances. A DUI with third party injury is if someone to whom you've lent your vehicle is involved in a DUI with injury.
The DUI charge brought forward in the case of yourself injuring someone in a DUI crash would be DUI with injury or severe bodily injury, depending on the extent to which the victim was injured.
Therefore, we can confirm that the correct charge placed on a defendant that caused injury to someone in a DUI crash is that of "DUI with injury" or "DUI serious bodily injury" depending on the gravity of the injury.
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What disperses seeds?
People, animals, water, and the wind
People, water, cars, and the wind
Animals, water, wind, and the sun
Water, wind, heat, and people
A biker rode up a 20 km hill in 2 hours and down the hill in 0. 5 hours without stopping. What was his average speed:.
Question #1 (a): A book is on a table. A student pushes it for a short time. Initially the book moves, but then it comes to a complete stop. Identify the forces acting on the book before it is pushed. You can use a Force/free-body diagram to help you. (HS-PS2-1) (HS-PS2-2) *
2 points
This is a required question
1 (b) A book is on a table. A student pushes it for a short time. Initially the book moves, but then it comes to a complete stop. Explain why the book moves and then comes to a complete stop. Use the laws of physics in your answer. (HS-PS2-1) (HS-PS2-2) *
3 points
1 (c) A book is on a table. A student pushes it for a short time. Initially the book moves, but then it comes to a complete stop. student wants the book to move at a constant speed in one direction. Describe the forces acting on the book needed for this to occur. (HS-PS2-1) (HS-PS2-2) *
3 points
Answer:
hhjjj
Explanation:
j
The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equals 200 kWh/m2/day. Calculate the average amount of solar energy incident on the PV array each day in kWh/day.
The average amount of solar energy incident on the PV per day is 10000 kWh/day.
Equation
An equation is an expression that shows the relationship between two or more numbers and variables.
Let the PV array has an area equal to 50 square meters. Hence:
Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.
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Describe the change to the stores of energy of the wood, pipe and water as the water
is heated.
[3 marks]
Wood
Pipe
Water
Answer:
Explanation:
If we are free to imagine what wood, pipes and water have with each other, I propose:
A wood stove is used to heat water in the pipe above the stove.
In this case:
Wood: Energy that comes with the wood is stored in the bonds that make up the wood, such as cellulose. The C, H, and O bonds in cellulose all have specific amounts of energy stored in the bonds.
A chemical decomposition of the cellulose (e.g., fire) releases the energy from those bonds. That energy takes the form of light, sound, and heat. A crackling fire will release enough energy to heat any pipes nearby/overhead.
Pipe: The heat capacity of the pipe will determine the amount of energy that is absorbed and transmitted to the water inside the pipe.
Water: The heat capacity of the water will determine how much the temperature will rise Water has a relatively high heat capacity, so it will take a whole for the coffee. Longer for the shower. Heat is stored in the water as molecular vibration on the water molecules. They will vibrate more quickly, which can be measured with a thermometer.
A stationary 25 kg object is located on a table near the surface of the earth. The coefficient of static friction between the surfaces is 0.50 and of kinetic friction is 0.30. A horizontal force of 300 N is applied to the object. Determine the acceleration of the object. *
The net vertical force on the object is
∑ F[vertical] = n - mg = 0
where n is the magnitude of the normal force exerted by the surface, m is the object's mass, and g is the mag. of acceleration due to gravity. It follows that
n = mg = (25 kg) (9.8 m/s²) = 245 N
The net horizontal force is
∑ F[horizontal] = 300 N - f = ma
where f is the mag. of friction and a is the object's acceleration.
We have
f = µn
where µ is the coefficient of friction. Since the object starts at rest, it won't move and accelerate unless the applied force of 300 N is sufficient to overcome the maximum static friction, which is
f = 0.50 n = 0.50 (245 N) = 122.5 N
Since f < 300 N, the box will begin to slide, at which point the coefficient of kinetic friction kicks in and the mag. of friction is
f = 0.30 n = 0.30 (245 N) = 73.5 N
Now solve for a :
300 N - 73.5 N = (25 kg) a
a = (226.5 N) / (25 kg)
a = 9.06 m/s² ≈ 9.1 m/s²
