Consider a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year. For simplicity, assume that there is a 50% probability that after the accident the car will need repairs costing $500, a 40% probability that the repairs will cost $5,000, and a 10% probability that the car will need to be replaced, which will cost $15,000. What is the expected loss for the car owner per year

Answers

Answer 1

Answer:

The expected loss for the car owner per year is $750.

Step-by-step explanation:

We are given that a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year.

Let X = Loss for the particular year for a car owner

Now as we know that the loss to the car owner may be of $0, $500, $5,000 or $15,000 because these amount he has to pay as a part of repair cost if his car met with an accident.

So, the probability distribution of X is given by;

           X (Amount of Loss)                               P(X)

                     $0                                                      0.80

                      $500                                            (0.20)(0.50) = 0.10

                      $5,000                                         (0.20)(0.40) = 0.08

                      $15,000                                        (0.20)(0.10) = 0.02

                       Total                                                         1                    

Here, the probability of (0.20)(0.50) means that for the loss of $500, first the car must have to met with an accident and then there is 50% chance that after the accident the car will need repairs costing $500.

Now, the expected loss for the car owner per year is  = [tex]\sum (X \times P(X))[/tex]

   [tex]\sum (X \times P(X))[/tex]  =  [tex](0 \times 0.80) + (500 \times 0.10)+(5,000 \times 0.08)+(15,000 \times 0.02)[/tex]

                           =  50 + 400 + 300 = $750.

So, the expected loss for the car owner per year is $750.


Related Questions

Please answer this correctly

Answers

Answer:

62.5 percent

Step-by-step explanation:

There are a total of 8 choices, 5 of which are less than 6

5/8 is also 62.5percent

Answer:

62.5%

Step-by-step explanation:

There are 5 numbers out of 8 that are less than 6 so there is a 5/8 chance getting them or 62.5% chance.

HELP HELP PLEASEEE RIGHT ANSWER !!!! Flying against the jetstream, a jet travels 5390 miles in 7 hours. Flying with the jetstream, the same jet travels 4760 miles in 4 hous. what is the rate of the jet in still air and what is the rate of the jetstream???

Answers

Answer:

the plane travels 980 mph in still air and the  jet stream is traveling at 210mph

Step-by-step explanation:

100 points!!! Pls help 9 + 10y = 21. What is the value of Y?

Answers

Answer:

1.2

Step-by-step explanation:

9+10y=21

Subtract 9 from both sides:

10y=21-9=12

Divide both sides by 10 to isolate y:

y=1.2

Hope this helps!

Answer:

y = 6/5 = 1 1/5 = 1.2

Step-by-step explanation:

9 + 10y = 21

Subtract 9 from each side

9-9 + 10y = 21-9

10 y = 12

Divide each side by 10

10y/10 = 12/10

y = 6/5

y = 1.2

In Major League Baseball, the American League (AL) allows a designated hitter (DH) to bat in place of the pitcher, but in the National League (NL), the pitcher has to bat. However, when an AL team is the visiting team for a game against an NL team, the AL team must abide by the home team’s rules, and thus, the pitcher must bat. A researcher is curious if an AL team would score more runs for games in which the DH was used. She samples 20 games for an AL team for which the DH was used, and 20 games for which there was no DH. The data are below. The population standard deviation for runs scored is known to be 2.54 for both groups. Assume the populations are normally distributed.
DH no DH
0 3
6 6
8 2
2 4
2 0
4 5
7 7
7 6
6 1
5 8
1 12
1 4
5 6
4 3
4 4
2 0
7 5
11 2
10 1
0 4
Is there evidence to suggest that more runs are scored in games for which the DH is used? Use α=0.10.
Enter the test statistic - round to 4 decimal places.
Enter the P-Value - round to 4 decimal places.
Can it be concluded that more runs are scored in games for which the DH is used?
Yes or No

Answers

Answer:

Step-by-step explanation:

The objective is to compute that more runs are scored in games for which DH is used

Let [tex]\mu_1[/tex] denote the population mean number of runs scored for DH group

Let [tex]\mu_2[/tex] denote the population mean number of runs scored for DH group

Let [tex]n_1[/tex]  and  [tex]n_2[/tex]  denote the sample sizes for DH and no DH

From the available information

[tex]n_1=n_2=20[/tex]

The population standard deviation of runs score is 2.54 for both the groups.

That is [tex]\sigma _1^2=\sigma_2^2=2.54[/tex]

The null hypothesis is [tex]H_0:\mu_1\leq \mu_2[/tex]

The alternative hypothesis is [tex]H_1:\mu_1>\mu_2[/tex]

Let the level of significance [tex]\alpha =0.10[/tex]

Since, the population standard deviation for both the group is known , even though the sample size is less than 30 , use z test

The test statistic is

[tex]z=\frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\mu_1^2}{n_1} +\frac{\mu_2^2}{n_2} } }[/tex]

The sample mean for the DH group is computed as

[tex]\bar x_1=\frac{1}{n_1} \sum_{i=1}^{n_1}\\\\=\frac{1}{20} (0+6+8+2+2+4+7+7+6+5+1+1+5+4+4+5+7+11+10+0)\\\\=\frac{92}{20}\\\\=4.6[/tex]

The sample mean of no DH is computed as

[tex]\bar x_2=\frac{1}{n_2} \sum_{i=1}^{n_1}\\\\=\frac{1}{20} (3+6+2+4+0+5+7+6+1+8+12+4+6+3+4+0+5+2+1+4)\\\\=\frac{83}{20}\\\\=4.15[/tex]

The test statistic is

[tex]z=\frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\mu_1^2}{n_1} +\frac{\mu_2^2}{n_2} } }[/tex]

[tex]=\frac{4.60-4.15}{\sqrt{\frac{2.54^2}{20} +\frac{2.54^2}{20} } } \\\\=\frac{0.45}{\sqrt{0.32258+0.32258} } \\\\=\frac{0.45}{0.803219}\\\\=0.5602[/tex]

P-Value

From the alternative hypothesis, it is clear that the test is one tailed test

P-value = P(Z > z)

[tex]1-P(Z\leq z)\\\\1-P(Z\leq 0.5602)[/tex]

1 - normsdist (0.5602)

(using excel function "normsdist(z)")

= 1 - 0.7123

= 0.2877

Therefore, the P-Value is 0.2877

Decision Rule

Reject the null hypothesis , if the p-value is less than the level of significance . that is p-value is < 0.10

Here, the p-value is 0.2877 which is greater than the level of significance 0.10

so , fail to reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that more runs scored in games for which DH is used.

When using the identity for the sum of two cubes to factor 125q^6-r^6s^3

Answers

Answer:

a = 5q²

b = r²s

Step-by-step explanation:

The given identity is [tex]a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})[/tex]

we have to use this identity to factor of two cubes given as [tex]125q^{6}-r^{6}s^{3}=(5q^{2})^{3}-(r^{2}s)^{3}[/tex]

As this expression is in the form of a³- b³

Here a is 5q² and b is r²s.

Answer:

a=5q2  b=r2s the expression factored is also (5q2-r2s) (25q4+5q2r2s+1r4s2)

Step-by-step explanation:

What is the measure of B (2n + 15) and D (3n - 5)? If ABCD is a parrallelogram

Answers

Answer : The value of angle B and angle D is 25⁰ and 35⁰ respectively.

Step-by-step explanation :

As we know that the opposite angles are equal in parallelogram.

According to the given figure,

∠A = ∠C

and

∠B = ∠D

Given:

∠B = (3n - 5)⁰

∠D = (2n + 15)⁰

From this we conclude that:

∠B = ∠D

(3n - 5)⁰ = (2n + 15)⁰

3n - 5⁰ = 2n + 15⁰

3n - 2n = 15⁰ - 5⁰

1n = 10⁰

n = 10⁰

∠B = (3n - 5)⁰ = (3×10 - 5)⁰ = 25⁰

∠D = (2n + 15)⁰ = (2×10 + 15)⁰ = 35⁰

Therefore, the value of angle B and angle D is 25⁰ and 35⁰ respectively.

If the rectangular menu is 3 feet long by 2 feet wide, what is the area of the menu?

Answers

Answer:

Step-by-step explanation:

Area of rectangular menu

Length × breadth

3×2=6sq feet

Answer:

6 ft^2

Step-by-step explanation:

area of rectangle = length * width

area = 3 ft * 2 ft

area = 6 ft^2

a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues to grow exponentially at a constant rate, what population will it have in 2000

Answers

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

[tex]P(t) = P(0)(1+r)^{t}[/tex]

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that [tex]P(0) = 24000[/tex]

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

[tex]P(t) = P(0)(1+r)^{t}[/tex]

[tex]29000 = 24000(1+r)^{20}[/tex]

[tex](1+r)^{20} = \frac{29000}{24000}[/tex]

[tex]\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}[/tex]

[tex]1 + r = 1.0095[/tex]

So

[tex]P(t) = P(0)(1+r)^{t}[/tex]

[tex]P(t) = 24000(1.0095)^{t}[/tex]

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

[tex]P(t) = 24000(1.0095)^{t}[/tex]

[tex]P(100) = 24000(1.0095)^{100} = 61779[/tex]

It will have a population of 61,779 in 2000.

Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)? Divide 12 by 5. Multiply –6 and 3. Divide 12 by –6. Add 3 and –2.

Answers

Answer:

first you need to multiply -6 and 3

Answer:

-6 and 3

Step-by-step explanation:

sorry it was an late answer I'm just tryna gain points :D

HELP!!!!! 70 points I keep help

Answers

Answer:

The answer is the last one because if the diagonals of a quadrilateral bisect each other then it's a parallelogram.

Answer:

Last answer choice

Step-by-step explanation:

One of the prerequisites for a quadrilateral to be a parallelogram is for the diagonals to bisect each other. Since K is the midpoint, this means that it is halfway between the ends of each of the diagonals, and that they therefore bisect each other. Hope this helps!

A circular swimming pool has a diameter of 20 ft, the sides are 6 ft high, and the depth of the water is 5 ft. How much work (in ft-lb) is required to pump all of the water out over the side

Answers

Answer:

19467649.76 lb-ft^2/s^2

Step-by-step explanation:

diameter of the pool d = 20 ft

radius = d/2 = 20/2 = 10 ft

height of pool side h = 6 ft

depth of water d = 5 ft

the force on the bottom of the pool due to the water in the pool is

F = pgdA

where p = density of water = 62.4 lb/ft^3

g = acceleration due to gravity = 32.17 ft/s^2

Area A = [tex]\pi r^{2}[/tex] = [tex]3.142 * 10^{2}[/tex] = 314.2 ft^2

Force on pool bottom = 64.2 x 32.17 x 5 x 314.2 = 3244608.29 lb-ft/s^2

work done = force times the height the water will be pumped

work = F x h = 3244608.29 x 6 = 19467649.76 lb-ft^2/s^2

The work (in ft-lb) is required to pump all of the water out over the side is :

Given :Diameter of the pool d = 20 ftRadius = d/2 = 20/2 = 10 ftHeight of pool side h = 6 ftDepth of water d = 5 ft

Formula:

F = pgdA

p = density of water = 62.4 lb/ft^3

g = acceleration due to gravity = 32.17 ft/s^2

Area A = [tex]\pi r2\\[/tex] = 314.2 ft^2

Force on pool bottom = 64.2 x 32.17 x 5 x 314.2 = 3244608.29 lb-ft/s^2work done = force times the height the water will be pumpedwork = F x h = 3244608.29 x 6 = 19467649.76 lb-ft^2/s^2

The work (in ft-lb) is required to pump all of the water out over the side is 19467649.76 lb-ft^2/s^2.

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https://brainly.com/question/13102487referrer=searchResults

3 of 8 The following are the ages (years) of 5 people in a room: 14, 14, 18, 18, 22 A person enters the room. The mean age of the 6 people is now 16. What is the age of the person who entered the room?

Answers

Answer:

[tex]\boxed{\sf \ \ age = 10\ \ }[/tex]

Step-by-step explanation:

Hello,

let's write the mean computation, we note x the age of the additional person

[tex]\dfrac{14+14+18+18+22+x}{6}=16[/tex]

[tex]<=> 14+14+18+18+22+x = 6*16=96\\\\<=> x = 96 - ( 14+14+18+18+22)= 10[/tex]

So the age of the person is 10

hope this helps

Answer:

10

Step-by-step explanation:

The mean is the sum of terms divided by number of terms.

Let x be the age of the person who entered the room.

(14+14+18+18+22+x)/6 = 16

(x + 86)/6 = 16

x + 86 = 96

x = 10

The age of the person who entered the room is 10.

Bradley and Kelly are flying out kites at a park one afternoon. And model of Bradley and Kelly skates are shown Below on the coordinate plane as the kites BRAD and KELY, respectively:

Answers

Answer:  b) they ARE similar because BRAD:KELY is 1:2

Step-by-step explanation:

In order for the shapes to be similar they must have congruent angles and proportional sides.

With the options a through d given, we can assume that their sides are proportional.  Since BRAD is smaller than KELY, BRAD would have the smaller number in the ratio.

Answer:

They are similar because Brad and Kelly are 1:2

Step-by-step explanation:

Solve for x
2x
114 im : can someone help me on this question

Answers

Answer:

33 degrees

Step-by-step explanation:

114+2x =180 right?

so 2x = 180-114 = 66

then x = 33

44) The difference of two numbers is 76. The second number is 20% of the first number. What are the numbers?
A) 85, 17
B) 92, 16
C) 95, 19
D) 97,17

Answers

Answer:

C

Step-by-step explanation:

Not A b/c the difference b/w 85 and 17 is not 76

Not D b/c the difference b/w 97 and 17 is not 76

Not B b/c 16 is not 20% of 92

By the process of elimination the answer is C

The owner of a small machine shop has just lost one of his largest customers. The solution to his problem,he says, is to fire three machinists to balance his workforce with his current level of business. The owner says that it is a simple problem with a simple solution. The three machinists disagree. Why

Answers

Answer:

It may look simple to the owner because he is not the one losing a job. For the three machinists it represents a major event with major consequences

Company A is trying to sell its website to Company B. As part of the sale, Company A claims that the average user of their site stays on the site for 10 minutes. Company B is concerned that the mean time is significantly less than 10 minutes. Company B collects the times (in minutes) below for a sample of 19 users. Assume normality.
Time: 1.2, 2.8, 1.5, 19.3, 2.4, 0.7, 2.2, 0.7, 18.8, 6.1, 6, 1.7, 29.1, 2.6, 0.2, 10.2, 5.1, 0.9, 8.2
Conduct the appropriate hypothesis test for Company B using a 0.08 level of significance.
a) What is the critical value for the test? Give your answer to four decimals.
b) What is the appropriate conclusion?
A. Reject the claim that the mean time is 10 minutes because the test statistic is larger than the critical point.
B. Fail to reject the claim that the mean time is 10 minutes because the test statistic is larger than the critical point.
C. Reject the claim that the mean time is 10 minutes because the test statistic is smaller than the critical point.
D. Fail to reject the claim that the mean time is 10 minutes because the test statistic is smaller than the critical point.

Answers

Answer:

a) Critical value = -1.4052

Since we are checking if the mean time is less than 10 minutes, the rejection area would be

z < -1.4052

b) Option C is correct.

Reject the claim that the mean time is 10 minutes because the test statistic is smaller than the critical point.

That is, the mean time is significantly less than 10 minutes.

Step-by-Step Explanation:

a) Using z-distribution, the critical value is obtained from the confidence level at which the test is going to be performed. Since the hypothesis test tests only in one direction (checking if the claim is less than 10 minutes significantly)

P(z < Critical value) = 0.08

From the z-tables, critical value = -1.4052

Since we are checking if the mean time is less than 10 minutes, the rejection area would be

z < -1.4052

b) We first give the null and alternative hypothesis

The null hypothesis is that there isn't significant evidence to suggest that the mean time is less than 10 minutes.

And the alternative hypothesis is is that there is significant evidence to suggest that the mean time is less than 10 minutes.

To now perform this hypothesis test, we need to obtain the test statistic

Test statistic = (x - μ)/σₓ

x = sample mean = (Σx/N)

The data is

1.2, 2.8, 1.5, 19.3, 2.4, 0.7, 2.2, 0.7, 18.8, 6.1, 6, 1.7, 29.1, 2.6, 0.2, 10.2, 5.1, 0.9, 8.2

Σx = 119.7

N = Sample size = 19

x = sample mean = (119.7/19) = 6.3

μ = standard to be compared against = 10 minutes

σₓ = standard error = (σ/√N)

where N = Sample size = 19

σ = √[Σ(x - xbar)²/N]

x = each variable

xbar = mean = 6.3

N = Sample size = 19

Σ(x - xbar)² = 1122.74

σ = (√1122.74/19) = 7.687

σₓ = (7.687/√19) = 1.7635

Test statistic = (x - μ)/σₓ

Test statistic = (6.3 - 10)/1.7635

= -2.098 = -2.10

z = -2.10 and is in the rejection region, (z < -1.4052), hence, we reject the null hypothesis and the claim and say that the mean time is significantly less than 10 minutes.

The test statistic is less than the critical point, hence, we reject the null hypothesis and the claim and conclude that the mean time is less than 10 minutes.

Hope this Helps!!!

The critical value for the test based on the sampling distribution is -1.4052 and one needs to reject the claim.

How to explain the sampling distribution?

From the complete information given, the descriptive statistics from the sample information has been given. The sample mean and variance are given. Therefore, the value of the test statistics from the information is -1.4052.

Also, the conclusion is to reject the claim since the test statistic is smaller than the critical point.

Therefore, the correct option is to reject the claim that the mean time is 10 minutes because the test statistic is smaller than the critical point.

Learn more about sampling on:

https://brainly.com/question/17831271

Assume the distribution of commute times to a major city follows the normal probability distribution, and the standard deviation is 4.2 minutes. A random sample of 13 commute times is given below in minutes. Find the 98% confidence interval for the mean travel time in minutes. Round your answers to two decimal places and use ascending order.

Answers

Answer:

The 98% CI for the mean travel time to the major city is [20.70; 26.14]minutes

Step-by-step explanation:

Hello!

The variable of interest is

X: commute time to a major city.

This variable has a normal distribution

X~N(μ;σ²)

The standard deviation is known to be:

σ= 4.2 minutes

A random sample of n= 13 commute times was taken:

11.5, 13.2, 14.7, 17.1, 18.7, 21.8, 22.4, 25, 26.9, 27.6, 31.1, 35.9, 38.6

You need to estimate the population mean travel time by calculating a 98% CI.

Since the variable has a normal distribution and the population standard deviation is known ,the statistic to use for this interval is the standard normal, then the formula for the interval is:

[X[bar] ± [tex]Z_{1-\alpha /2}[/tex] * [tex]\frac{Sigma}{\sqrt{n} }[/tex]]

The value of the statistic for the 1 - α: 0.98 interval is:

[tex]Z_{1-\alpha /2}= Z_{0.99}= 2.334[/tex]

Next is to calculate the sample mean:

X[bar]= ∑X/n= 304.5/13= 23.42 minutes

[23.42 ± 2.334 * ([tex]\frac{4.2}{\sqrt{13} }[/tex])]

[20.70; 26.14]minutes

With a 98% confidence level you'd expect that the interval [20.70; 26.14]minutes will contain the true mean travel time to the major city.

I hope this helps!

The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less. A member of the hotel's accounting staff noticed that the total charges for guest bills have been increasing in recent months. The accountant will use a sample of future weekend guest bills to test the manager's claim. (a) Which form of the hypotheses should be used to test the manager's claim? H0: - Select your answer - Ha: - Select your answer - The member of the hotel's accounting staff suspects that the total charges for guest bills have Select in recent months. To test the manager’s claim, the staff member will conduct Select test of the population Select . (b) What conclusion is appropriate when H0 cannot be rejected? When H0 cannot be rejected, there Select enough evidence to conclude that the total charges for guest bills have Select in recent months. (c) What conclusion is appropriate when H0 can be rejected? When H0 can be rejected, there Select enough evidence to conclude that the total charges for guest bills have Select in recent m

Answers

Answer:

a) Null hypothesis (H0): the mean guest bill for a weekend is $600.

Alternative hypothesis (Ha): the mean guest bill for a weekend is significantly bigger than $600.

b) When H0 can not be rejected, the conclusion is that there is no enough evidence to claim that the mean guest bill had increased from $600.

c) When the H0 is rejected, they have enough evidence to claim that the mean guest bill is significantly bigger than $600.  

Step-by-step explanation:

a) The accountant, as he wants to see if there is evidence to support the claim that the mean guest bill has increased significanty, should write the hypothesis like that:

Null hypothesis (H0): the mean guest bill for a weekend is $600.

Alternative hypothesis (Ha): the mean guest bill for a weekend is significantly bigger than $600.

A sample of bills of the period in study needs to be taken in order to have a representation of the actual population of bills and then perform a t-test, as the sample mean and standard deviation will be used to perform the test.

b) When H0 can not be rejected, the conclusion is that there is no enough evidence to claim that the mean guest bill had increased from $600. If the P-value was low but not enough, they may take another sample to perform the test again or leave it like that.

c) When the H0 is rejected, they have enough evidence to claim that the mean guest bill is significantly bigger than $600.  

A researcher predicts that listening to music while solving math problems will make a particular brain area more active. To test this, a research participant has her brain scanned while listening to music and solving math problems, and the brain area of interest has a percentage signal change of 58. From many previous studies with this same math problems procedure (but not listening to music), it is known that the signal change in this brain area is normally distributed with a mean of 35 and a standard deviation of 10. (a) Using the .01 level, what should the researcher conclude

Answers

Answer:

As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that listening to music while solving math problems will make a particular brain area more active.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=35\\\\H_a:\mu> 35[/tex]

The significance level is 0.01.

The sample has a size n=1.

The sample mean is M=58.

The standard deviation of the population is known and has a value of σ=10.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{1}}=10[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{58-35}{10}=\dfrac{23}{10}=2.3[/tex]

This test is a right-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z>2.3)=0.0107[/tex]

As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.

Find the equation of the line.
Use exact numbers.
y=

Answers

Answer:

y = 2x+4

Step-by-step explanation:

First we need to find the slope using two points

(-2,0) and (0,4)

m = (y2-y1)/(x2-x1)

m = (4-0)/(0--2)

   = 4/+2

   = 2

we have the y intercept  which is 4

Using the slope intercept form of the line

y = mx+b where m is the slope and b is the y intercept

y = 2x+4

A​ student's course grade is based on one midterm that counts as 20​% of his final​ grade, one class project that counts as 20​% of his final​ grade, a set of homework assignments that counts as 30​% of his final​ grade, and a final exam that counts as 30​% of his final grade. His midterm score is 64​, his project score is 80​, his homework score is 94​, and his final exam score is 77. What is his overall final​ score? What letter grade did he earn​ (A, B,​ C, D, or​ F)? Assume that a mean of 90 or above is an​ A, a mean of at least 80 but less than 90 is a​ B, and so on.

Answers

Answer:

His overall final​ score is 80.1.

His letter grade is a B.

Step-by-step explanation:

To find his grade, we multiply each grade by it's weight.

Grades and weights:

His midterm score is 64​. The midterm counts 20% = 0.2.

His project score is 80​. The project score counts 20% = 0.2.

His homework score is 94. The homework score counts 30%.

His final exam score is 77. It counts 30%.

What is his overall final​ score?

64*0.2 + 80*0.2 + 94*0.3 + 77*0.3 = 80.1

His overall final​ score is 80.1.

What letter grade did he earn​ (A, B,​ C, D, or​ F)?

At least 80 but less than 90 is a​ B. He scored 80.1, so his letter grade is a B.

If tan theta equals -5/2 and theta is a quadrant II angle, what is cos theta ?

Answers

Answer:

cos θ = -2/√29

Step-by-step explanation:

tan θ = -5/2, π/2 < θ < π

One method is to draw a triangle with the hypotenuse in quadrant II.  The height of the triangle is 5, and the base is -2.  The hypotenuse can be found using Pythagorean theorem:

c² = a² + b²

c² = (-2)² + (5)²

c = √29

Therefore, cos θ = -2/√29.

Another method is to use one of the Pythagorean identities.

tan²θ + 1 = sec²θ

(-5/2)² + 1 = sec²θ

25/4 + 1 = sec²θ

29/4 = sec²θ

cos²θ = 4/29

cos θ = -2/√29

Two types of shipping boxes are shown below. What is the difference in the surface areas, in square feet, of the two boxes

Answers

*see attachment showing the 2 boxes

Answer:

3 ft²

Step-by-step explanation:

==>Given:

Box J with the following dimensions:

L = 4.5ft

W = 3ft

H = 2ft

Box F:

L = 3ft

W = 3ft

H = 3ft

==>Required:

Difference between the surface area of box J and box F

==>Solution:

Surface area = 2(WL + HL + HW)

=>S.A of box J = 2(3*4.5 + 2*4.5 + 2*3)

= 2(13.5 + 9 + 6)

= 2(28.5)

S.A of box J = 57 ft²

=>S.A of box F = 2(3*3 + 3*3 + 3*3)

= 2(9 + 9 + 9)

= 2(27)

S.A of box F = 54 ft²

Difference between box J and box F = 57 - 54 = 3 ft²

answer this please ????

Answers

Answer:

a. x = 4

b. x = 17.5

Step-by-step explanation:

a. 5x/2 + 1 = 11

5x/2 = 10

5x = 20

x = 4

b. 2x/7 - 3 = 2

2x/7 = 5

2x = 35

x = 35/2

Answer:

a) x = 4

b) x = 17.5

Step-by-step explanation:

a)

(5x)/2 + 1 = 11

(5x)/2 = 10

5x = 20

x = 4

b)

(2x)/7 - 3 = 2

(2x)/7 = 5

2x = 35

x = 17.5

Harry’s soccer team plays 2 nonconference games for every 3 games that they play against conference opponents. If y represents the number of nonconference games and x represents the number of conference games, which equation best models this proportional relationship?

Answers

Answer:

y=2/3x

Step-by-step explanation:

the ratio is 2:3, so this would graph according to the information given

Answer:

y=2/3x

Step-by-step explanation:

On a coordinate plane, Rectangles A B C D and E F G H are shown. The length of side A B is 6 units and the length of side B C is 3 units. The length of side E F is 8 units and the length of side F G is 4 units. Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin? Why or why not? Yes, because corresponding sides are parallel and have lengths in the ratio Four-thirds Yes, because both figures are rectangles and all rectangles are similar. No, because the center of dilation is not at (0, 0). No, because corresponding sides have different slopes

Answers

Answer:

Yes, because corresponding sides are parallel and have lengths in the ratio Four-thirds.

Step-by-step explanation:

Dilation is a transformation process in which the dimensions of a given figure are resized to produce an image with the same shape. This is done with respect to a scale factor and center of dilation.

In the given question, the center of dilation is at the middle of side DC of rectangle ABCD (i.e on side DC).

Given that the scale factor is  [tex]\frac{4}{3}[/tex],

EF = HG =  [tex]\frac{4}{3}[/tex]  × AB = [tex]\frac{4}{3}[/tex] × 6 = 8 units

FG = EH =  [tex]\frac{4}{3}[/tex]  × BC =  [tex]\frac{4}{3}[/tex]  × 3 = 4 units

Therefore, rectangle EFGH is the result of dilation of ABCD.

Answer:

A. Yes, because corresponding sides are parallel and have lengths in the ratio Four-thirds

Step-by-step explanation:

The life of an electric component has an exponential distribution with a mean of 8.9 years. What is the probability that a randomly selected one such component has a life more than 8 years? Answer: (Round to 4 decimal places.)

Answers

Answer:

[tex] P(X>8)[/tex]

And for this case we can use the cumulative distribution function given by:

[tex] F(x) = 1- e^{-\lambda x}[/tex]

And if we use this formula we got:

[tex] P(X>8)= 1- P(X \leq 8) = 1-F(8) = 1- (1- e^{-\frac{1}{8.9} *8})=e^{-\frac{1}{8.9} *8}= 0.4070[/tex]

Step-by-step explanation:

For this case we can define the random variable of interest as: "The life of an electric component " and we know the distribution for X given by:

[tex]X \sim exp (\lambda =\frac{1}{8.9}) [/tex]

And we want to find the following probability:

[tex] P(X>8)[/tex]

And for this case we can use the cumulative distribution function given by:

[tex] F(x) = 1- e^{-\lambda x}[/tex]

And if we use this formula we got:

[tex] P(X>8)= 1- P(X \leq 8) = 1-F(8) = 1- (1- e^{-\frac{1}{8.9} *8})=e^{-\frac{1}{8.9} *8}= 0.4070[/tex]

Pleassssssseeeeeee heeelllllppppppppp

Answers

Answer: 1. point A

2. 90 degrees

3. 90 degrees clockwise

Step-by-step explanation:

BRAINLIEST??!?!

The profit p in dollars of selling x widgets and y gadgets is given by the function p(x,y)=7x+6y. Which corner point of the shaded region will maximize the profit?

Answers

Options

(0, 35)(10, 30)(15, 25)(20, 15)

Answer:

(C) (15,25)

Step-by-step explanation:

The profit p in dollars of selling x widgets and y gadgets is given by the function p(x,y)=7x+6y.

Option A

When x=0 and y=35

p(x,y)=7(0)+6(35)

p(x,y)=210

Option B

When x=10 and y=30

p(x,y)=7(10)+6(30)

p(x,y)=250

Option C

When x=15 and y=25

p(x,y)=7(15)+6(25)

p(x,y)=$255

Option D

When x=20 and y=15

p(x,y)=7(20)+6(15)

p(x,y)=$230

We observe that the point (15, 25) in Option C yields the highest profit ($255). Therefore, it is the point that maximizes profit.

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