Consider the following system of equations: y = −x + 2 y = 3x + 1 Which description best describes the solution to the system of equations? (4 points) Group of answer choices Line y = −x + 2 intersects line y = 3x + 1. Lines y = −x + 2 and y = 3x + 1 intersect the x-axis. Lines y = −x + 2 and y = 3x + 1 intersect the y-axis. Line y = −x + 2 intersects the origin.

Answer:

9

Step-by-step explanation:

look for scale factor by dividing 12 by 2 to get 6 then dividing 54 by 6 to get 9

Answer:

X^5

Step-by-step explanation:

Note: 1/X^-3 = 1÷X^-3=1÷ (1÷ X^3)= 1×X^3=X^3

When t is equal to 14(π/3) in the function r(t) = sin(t), the corresponding output value is √3/2.

In mathematics, functions play a crucial role in describing relationships between variables. One type of function is the trigonometric function, which deals with the properties and relationships of angles.

In this problem, we are given a trigonometric function r(t) = sin(t) and asked to find the value of r(14)(π/3).

The function r(t) = sin(t) represents a sine function, where t is the input variable (in this case, representing time) and r(t) is the corresponding output. The sine function, denoted by sin(t), calculates the ratio of the length of the side opposite a given angle in a right triangle to the hypotenuse. However, in this context, we are dealing with the unit circle, where the x and y coordinates of a point on the circle correspond to the sine and cosine values of the angle, respectively.

To find r(14)(π/3), we need to substitute 14(π/3) into the function

r(t) = sin(t).

Step 1: Multiply 14 by π/3:

14(π/3) = (14π)/3

Step 2: Substitute the result into the function:

r(14)(π/3) = sin((14π)/3)

At this point, we have the expression sin((14π)/3), which represents the value of the sine function at an angle of (14π)/3.

To evaluate sin((14π)/3), we can use the properties of the sine function and the unit circle. In the unit circle, the x-coordinate of a point on the circle corresponds to the sine value of the angle.

Step 3: Simplify the angle:

(14π)/3 = (12π)/3 + (2π)/3 = 4π + (2π)/3

Step 4: Find an equivalent angle within the unit circle:

To find an equivalent angle within the unit circle, we need to subtract or add full revolutions (2π) until the angle falls within the range [0, 2π].

In this case, 4π is equivalent to 2 full revolutions (2π) since it takes us back to the same point on the unit circle.

Thus, we can simplify the angle to (2π)/3.

Step 5: Evaluate the sine function at (2π)/3:

To find the sine value at (2π)/3, we can refer to the unit circle. At (2π)/3, the x-coordinate of the corresponding point on the unit circle is √3/2.

Therefore, r(14)(π/3) = sin((14π)/3) = sin((2π)/3) = √3/2.

After evaluating the given expression, we find that r(14)(π/3) = √3/2. This means that when t is equal to 14(π/3) in the function r(t) = sin(t), the corresponding output value is √3/2.

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a. The diagonal 3 times 3 matrices: This is a subspace of r3x3 because it is closed under addition and scalar multiplication. The sum of two diagonal matrices is another diagonal matrix, and multiplying a diagonal matrix by a scalar yields another diagonal matrix.

b. The 3 times 3 matrices whose entries are all greater than or equal to 0: This is not a subspace of r3x3 because it is not closed under scalar multiplication. If we multiply a matrix in this set by a negative scalar, the resulting matrix will have entries that are negative, which violates the condition of the set.

c. The 3 times 3 matrices with trace 0: This is a subspace of r3x3 because it is closed under addition and scalar multiplication. The sum of two matrices with trace 0 is another matrix with trace 0, and multiplying a matrix with trace 0 by a scalar yields another matrix with trace 0.

d. The 3 times 3 matrices whose entries are all integers: This is not a subspace of r3x3 because it is not closed under addition. If we add two matrices in this set, the resulting matrix may have entries that are not integers, which violates the condition of the set.

e. The 3 times 3 matrices with all zeros in the second row: This is a subspace of r3x3 because it is closed under addition and scalar multiplication. The sum of two matrices with all zeros in the second row is another matrix with all zeros in the second row, and multiplying a matrix with all zeros in the second row by a scalar yields another matrix with all zeros in the second row.

f. The 3 times 3 matrices in reduced row-echelon form: This is not a subspace of r3x3 because it is not closed under addition. If we add two matrices in reduced row-echelon form, the resulting matrix may not be in reduced row-echelon form, which violates the condition of the set.

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the center of the sphere is (1, 0, -4) and the radius is sqrt(17.5) ≈ 4.183.

To write the equation of the sphere in standard form, we want to express it as

[tex](x - h)^2 + (y - k)^2 + (z - l)^2 = r^2[/tex]

where (h, k, l) is the center of the sphere and r is the radius.

First, we'll complete the square for the x and z terms by moving the constants to the right side:

[tex]2x^2 + 2y^2 + 2z^2 - 4x + 16z = 1[/tex]

Next, we'll factor out the coefficients of the x and z terms:

[tex]2(x^2 - 2x) + 2y^2 + 2(z^2 + 8z) = 1[/tex]

To complete the square for the x and z terms, we'll add and subtract the square of half the coefficient of each term:

[tex]2(x^2 - 2x + 1) - 2 + 2y^2 + 2(z^2 + 8z + 16) - 32 = 1[/tex]

Simplifying, we get:

[tex]2(x - 1)^2 + 2y^2 + 2(z + 4)^2 = 35[/tex]

Dividing by 35 on both sides, we get the standard form of the equation of the sphere:

[tex](x - 1)^2/17.5 + y^2/17.5 + (z + 4)^2/17.5 = 1[/tex]

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Answer:

Step-by-Expressions 1 and 2 are equal and right and 3rd is not correct .

What is expression in math?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

An expression's structure is as follows: Expression: (Math Operator, Number/Variable, Math Operator)

An example of expression is a term or phrase that is regularly used or a means of expressing your thoughts, feelings, or emotions.

The idiom "a penny saved is a penny earned" is a prime example. A smile is an illustration of an expression.

2x(x+3)  = 2x² + 6x is correct Distribution of expressions .

expressions 1 and 2 are equal and right .

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step explanation:

The differences they would have E: The sample sizes would be different.

The difference between the 95% and 98% confidence intervals lies in the level of precision desired. A 98% confidence interval would be wider than a 95% confidence interval because it has to accommodate a larger range of possible values. However, the formula for calculating confidence intervals takes into account both the desired level of precision and the sample size. As the desired level of precision increases (from 95% to 98%), the required sample size also increases.

Therefore, the only difference between the two confidence intervals would be the sample size. The standard errors, t-statistics, z-statistics, and point estimates of the population mean would all be calculated using the same formula and values for both confidence intervals.

Option E is answer.

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The population of the rabbit in Central Park will be approximately 2038 in 2025.

We will use the exponential growth formula to solve this problem:

N(x) = N₀ * (1 + r)ˣ

where N(x) is the population at time x, N₀ is the initial population, r is the growth rate per year and x is the time elapsed (in years).

In this case:

N₀ = 150

r = 11% = 0.11

In 2025,

x = 2025 - 2000 = 25 years

Substituting into the formula:

N(25) = 150 * (1 + 0.11)²⁵

N(25) = 150 * (1.11)²⁵

N(25) ≈ 2038

Therefore, the rabbit population in Central Park is predicted to be approximately 2038 in the year 2025.

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The image of the square S under the given transformation is a parallelogram in the (x, y) plane, defined by the points (0, 0), (1, 0), (0, 1), and (1, 1).

To find the image of the set S under the given transformation, we substitute the coordinates of the points in S into the transformation equations. The set S is a square bounded by the lines u = 0, u = 1, v = 0, and v = 1.

Let's consider the four corners of the square:
Corner 1: (u, v) = (0, 0)
Corner 2: (u, v) = (0, 1)
Corner 3: (u, v) = (1, 0)
Corner 4: (u, v) = (1, 1)

For each corner, we apply the transformation:
Corner 1: (x, y) = (v, u(1 - v^2)) = (0, 0)
Corner 2: (x, y) = (v, u(1 - v^2)) = (1, 0)
Corner 3: (x, y) = (v, u(1 - v^2)) = (0, 1)
Corner 4: (x, y) = (v, u(1 - v^2)) = (1, 1)

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Hence, the probability that a light bulb purchased from this manufacturer will last no more than 14,500 hours is approximately 0.8944.

To solve this problem, we need to standardize the normal distribution and use the standard normal distribution table.

Let X be the random variable representing the life of the manufacturer's compact fluorescent light bulbs. Then, X is normally distributed with mean μ = 12,000 hours and standard deviation σ = 2,000 hours.

We want to find the probability that a light bulb will last no more than 14,500 hours. In other words, we need to find P(X ≤ 14,500).

To standardize X, we use the formula:

Z = (X - μ) / σ

Substituting the values, we get:

Z = (14,500 - 12,000) / 2,000 = 1.25

Now, we look up the probability from the standard normal distribution table. We find that the probability of Z ≤ 1.25 is 0.8944.

Therefore, P(X ≤ 14,500) = P(Z ≤ 1.25) = 0.8944.

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[tex]A=\dfrac{1}{2}bh\\b=42+16=58\text{ ft}\\h=21\text{ ft}\\\\A=\dfrac{1}{2}\cdot 58 \text{ ft}\cdot 21\text{ ft}=609 \text{ ft}^2[/tex]

The given histogram provides information about the heights of trees in a park. However, it is mentioned that the histogram is incomplete, indicating that some data is missing or not represented. Further details are required to provide a complete analysis.

To fully understand the histogram and its implications, we would need additional information such as the specific height ranges and corresponding frequencies or counts of trees within each range. Without this data, it is challenging to interpret the histogram accurately.

The histogram is a graphical representation that displays the distribution of a dataset, typically divided into intervals or bins. It provides insights into the frequency or occurrence of different values or ranges within the dataset. However, without the complete information or a clear representation of the data, it is difficult to draw meaningful conclusions from the histogram alone.

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The correct interpretation is b) There is not a significant difference between the sample value and the population.

In the given statement, z = 1.42 and p > .05. The z-value represents the standardized difference between the sample value and the population mean, while the p-value represents the probability of observing a result as extreme as, or more extreme than, the observed result under the null hypothesis (no difference between the sample value and the population mean). A p-value greater than .05 indicates that the difference between the sample value and the population mean is not statistically significant, meaning we cannot reject the null hypothesis.

Based on the provided information (z = 1.42, p > .05), we can conclude that there is not a significant difference between the sample value and the population.

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Option A is the correct answer as it correctly identifies the roles of the two boldface portions.

The two boldface portions in the argument play different roles. The first boldface portion identifies the conclusion of the argument, while the second boldface portion provides support for that conclusion.

The argument aims to prove that for a given level of output, Delta's operation now causes less fossil fuel to be consumed than it did formerly.

The first boldface portion clearly states the conclusion of the argument, while the second boldface portion provides support for this conclusion by explaining that the new technologies powered by electricity consume less fossil fuel than the older technologies.

Therefore, option A is the correct answer as it correctly identifies the roles of the two boldface portions.

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The value of the derivative, f'(x), is equal to 16x + 7.

To find f'(x), we need to take the derivative of the given function. Using the power rule and the constant multiple rule, we get:
f'(x) = 16x + 7

Now that we have the derivative, we can use the given condition f(0) = 3 to solve for the constant of integration.

We know that:
f(x) = ∫ f'(x) dx

So we can integrate f'(x) to get:
f(x) = 8x² + 7x + C
where C is the constant of integration.

Using f(0) = 3, we get:
f(0) = 8(0)² + 7(0) + C = 0 + 0 + C = C = 3

So the final equation for f(x) is:
f(x) = 8x² + 7x + 3

And the derivative is:
f'(x) = 16x + 7

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Answer: 0.01090566037

Answer: The short answer to this is 0.0109

The 98% "confidence-interval" for which the difference in mean volumes of 10-week recycling for all households with 60 , 75-gallon bins is (-66.886, 0.886).

In order to construct the confidence-interval for the difference in the mean-volumes of 10-week recycling for all households with the 60- and 75-gallon bins, we can use the two-sample t-test with unequal variances.

Let μ₁ and μ₂ be the true mean volumes of recycling for all households with the 60- and 75-gallon bins, respectively.

We want to estimate the difference in the means, μ₁ - μ₂, with a 98% confidence interval.

First, we calculate sample means and standard-deviations;

x'₁ = 382 gallons, s₁ = 52.5 gallons (for 60-gallon bins)

x'₂ = 415 gallons, s₂ = 43.8 gallons (for 75-gallon bins)

Next, we calculate "standard-error" of difference in the means;

SE(μ₁ - μ₂) = √(s₁²/n₁ + s₂²/n²₂);

where n₁ = 25 and n₂ = 22 are the sample sizes.

Substituting the values,

We get,

SE(μ₁ - μ₂) = √((52.5)²/25 + (43.8)²/22) = 14.05 gallons,

The "critical-value" for a 98% confidence interval with (n₁-1) + (n₂-1) = 45 degrees of freedom is : t = 2.412,

The confidence interval can be written as : (x'₁ - x'₂) ± t × SE(μ₁ - μ₂),

Substituting the values,

We get,

= (382 - 415) ± 2.412 × 14.05,

= -33 ± 33.886,

= (-33-33.886, -33+33.886) = (-66.886, 0.886).

Therefore, the required 98% confidence-interval is (-66.886, 0.886).

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The equation graphed is  y = 0.003(x - 50)² - 7.5

The bridge sags the most 7.5 feet from the left bank

A 3-foot will be eve with the river at about 11 feet and 87 feet from the left bank

Standard vertex form, y = a(x - h)² + k    

The vertex from the graph is

v (h, k) = (50, -7.5)

y = a(x - 50)² - 7.5

solving for using (0, 0)

0 = a(0 - 50)² - 7.5

a = 7.8 / 50²

a = 0.00312

hence the equation is y = 0.003(x - 50)² - 7.5

where y = -3 from the graph the point is traced to be  approximately 11 feet and 87 feet from the left bank

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The break-even quantities are:

x = 80 and x = 22.

To find the break-even quantities, we need to set the total costs (C(x)) equal to the total revenues (R(x)):
C(x) = R(x)
1760 + 8x + 0.6x^2 = 100x - 0.4x^2

Now, we will rearrange the equation to form a quadratic equation:
0.6x^2 + 0.4x^2 + 8x - 100x + 1760 = 0

Simplify the equation:
x^2 - 92x + 1760 = 0

Now, to find the break-even quantities (x values), we will solve the quadratic equation. You can use the quadratic formula or factoring. In this case, factoring works:
(x - 80)(x - 22) = 0

So, the break-even quantities are x = 80 and x = 22.

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There are 0.92 ounces in 13 grams.

To convert 13 g to oz, we need to use the conversion factors given:

1 kg = 2.2 lbs

1 lb = 16 oz

First, we need to convert 13 g to lbs:

[tex]13 g * (1 kg / 1000 g) * (2.2 lbs / 1 kg) = 0.02866 lbs[/tex]

Next, we can convert 0.02866 lbs to oz:

[tex]0.02866 lbs * (16 oz / 1 lb) = 0.4586 oz[/tex]

Therefore, there are approximately 0.4586 oz in 13 g.

To understand the conversion process, we use unit analysis, which involves multiplying the given value by conversion factors that cancel out units until we are left with the desired unit. For example, to convert g to lbs, we use the conversion factor 1 kg / 1000 g, which cancels out the g unit and leaves us with kg. Then, we use the conversion factor 2.2 lbs / 1 kg, which cancels out the kg unit and leaves us with lbs. Similarly, to convert lbs to oz, we use the conversion factor 16 oz / 1 lb, which cancels out the lb unit and leaves us with oz.

It's important to keep track of the units throughout the conversion process to ensure that we are multiplying and dividing the correct values. By following the correct steps and using the appropriate conversion factors, we can accurately convert between units and solve problems like this.

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The probability that a person with periodontal disease will have a heart attack is 45.9%.

To find the probability, we need to use Bayes' theorem, which relates the probability of having a heart attack given that the person has periodontal disease (P(A|B)) to the probability of having periodontal disease given that the person had a heart attack (P(B|A)), the probability of having a heart attack (P(A)), and the probability of having periodontal disease (P(B)):

P(A|B) = P(B|A) * P(A) / P(B)

Using the given information, we have:

P(B|A) = 0.77 (77% of heart attack patients have periodontal disease)

P(A) = 0.14 (14% probability of heart attack)

P(B) = 0.3 (30% of healthy people have periodontal disease)

Plugging these values into the formula, we get:

P(A|B) = 0.77 * 0.14 / 0.3 = 0.459 or 45.9%

Therefore, if someone has periodontal disease, the probability that they will have a heart attack is 45.9%.

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The weight of the one potato chips is 14 ounces.

Given that the total weight of the snack bought by Ray is 3.5 pounds,

In which there are two 8-ounce bags of pretzels, two 6-ounce bags of popcorn, and two bags of potato chips.

We need to find the weight of one potato chips bags.

So, first converting the units,

1 pound = 16 ounces

So,

3.5 pounds = 16 × 3.5 = 56 ounces

So, let the weight of potato bags be x,

So,

2 × 8 + 2 × 6 + 2x = 56

16 + 12 + 2x = 56

2x = 56 - 28

2x = 28

x = 14

Hence the weight of the one potato chips is 14 ounces.

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a. The number of ways the bands can be arranged to perform is given by the permutation formula n! / (n-r)! where n is the total number of items and r is the number of items to be selected. In this case, n = 10 and r = 10, so the number of ways the bands can be arranged is:

10! / (10-10)! = 10! / 0! = 10! = 3,628,800

Therefore, there are 3,628,800 different ways the bands can be arranged to perform.

b. If band 9 is performing first and band 3 last, then there are 8 remaining bands that can be scheduled in between. The number of ways to arrange 8 bands is given by the permutation formula 8! / (8-r)! where r is the number of items to be selected, which in this case is 8. Therefore, the number of ways the bands can be scheduled with band 9 first and band 3 last is:

8! / (8-8)! = 8! / 0! = 8! = 40,320

Therefore, there are 40,320 different ways the bands can be scheduled with band 9 first and band 3 last.

c. Since band 9 is performing first and band 3 last, we have fixed two positions in the schedule. Therefore, there are 8 remaining bands that can be arranged in the 8 remaining time slots. The number of ways to arrange 8 bands in 8 time slots is given by the permutation formula 8! / (8-8)! = 8! / 0! = 8! = 40,320. However, since the order of the 8 remaining bands does not matter, we must divide this number by the number of ways to arrange those 8 bands, which is 8! / (8-8)! = 8! / 0! = 8! = 40,320. Therefore, the total number of ways to arrange the bands with band 9 first and band 3 last is:

40,320 / 40,320 = 1

Therefore, there is only one way to arrange the bands with band 9 first and band 3 last.

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Answer:

277.5

Step-by-step explanation:

The area of the region enclosed by one loop of the curve r = 3 cos(5θ) is (9/2) π square units

To find the area of the region enclosed by one loop of the curve given by the polar equation r = 3 cos(5θ), we can integrate over the corresponding range of θ values.

The curve r = 3 cos(5θ) represents a cardioid with five petals.

To determine the range of θ values that corresponds to one loop, we can set the equation inside the cosine function equal to zero:

5θ = 0

This gives us θ = 0.

So, for one complete loop, we need to integrate from θ = 0 to θ = 2π.

The area formula for a polar curve is given by:

A = (1/2) ∫[θ₁,θ₂] r(θ)² dθ

In this case, the area can be calculated as:

A = (1/2) ∫[0, 2π] (3 cos(5θ))² dθ

Simplifying the integral, we have:

A = (9/2) ∫[0, 2π] cos²(5θ) dθ

Using the trigonometric identity cos²(θ) = (1 + cos(2θ))/2, we can rewrite the integral:

A = (9/2) ∫[0, 2π] (1 + cos(10θ))/2 dθ

Expanding the integral, we get:

A = (9/4) ∫[0, 2π] dθ + (9/4) ∫[0, 2π] (cos(10θ))/2 dθ

The first integral ∫ dθ over the interval [0, 2π] gives us 2π:

A = (9/4) (2π) + (9/8) ∫[0, 2π] cos(10θ) dθ

The second integral ∫ cos(10θ) dθ can be evaluated as:

(1/10) sin(10θ)

Evaluating the integral over the interval [0, 2π], we get:

A = (9/4) (2π) + (9/8) [(1/10) sin(10(2π)) - (1/10) sin(10(0))]

Since sin(0) = 0 and sin(20π) = 0, the second term becomes zero:

A = (9/4) (2π) + (9/8) (0)

Simplifying, we have:

A = (9/4) (2π)
A = (9/2) π

Therefore, the area of the region enclosed by one loop of the curve r = 3 cos(5θ) is (9/2) π square units.

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Therefore, the lower quartile is 20.5, which means that the correct option is (c).

To find the lower quartile, we need to first understand what it represents. The lower quartile, or Q1, is a statistical measure that represents the value below which 25% of the data falls.

To calculate Q1, we first need to order the data set from smallest to largest, which gives us:

20, 21, 23, 24

The median of the entire data set is the value that lies at the center when the data is arranged in order. In this case, the median is the average of the middle two numbers, which is (21 + 23) / 2 = 22.

Next, we need to find the median of the lower half of the data set. The lower half of the data set is the first two numbers, which are 20 and 21. To find the median of this lower half, we take the average of these two numbers, which is (20 + 21) / 2 = 20.5.

Therefore, the lower quartile, or Q1, is 20.5. This means that 25% of the data in the set is below 20.5.

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if the length of the pond is 80 meters and the width is 60 meters, the distance across the pond would be the square root of (80^2 + 60^2) = 100 meters.

To find the distance across the pond indirectly, you can use the Pythagorean theorem. The theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides. In this case, the distance across the pond is the hypotenuse of a right triangle formed by the length and width of the pond.

To find the length of the hypotenuse, you can square the length and width and add them together, then take the square root of the sum. This will give you the distance across the pond. For example, if the length of the pond is 80 meters and the width is 60 meters, the distance across the pond would be the square root of (80^2 + 60^2) = 100 meters.

This method is indirect because you are not directly measuring the distance across the pond. Instead, you are using the length and width to calculate it. However, it is a reliable way to find the distance and has been used for centuries to measure distances that are difficult or impossible to measure directly.

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Answer:

parenthesis

exponents

multiply

divide

add

subtract

Step-by-step explanation:

cant help you on the other question sorry

Answer:

Pemdas,

Parenthesis, exponents, multiplication, division, addition, subtraction

-A way to remember the order is to say Please Excuse My Dear Aunt Sally

The triangle height formula would be

h= 2*A/B

(a) A^3 = [1 1]

[−4 −1]

(b) BCT = [−21]

[13]

[0 15]

(c) EC + I3 = [−27 3 0]

[−4 7 0]

[0 24 1]

To perform the indicated computations, we'll multiply and add the matrices according to the given operations.

Given matrices:

A = [−3 1]

[2 −1]

B = [0 3]

[−2 7]

C = [7 0]

[−1 3]

[3 3]

E = [1 3 −7]

[−2 1 −3]

[0 2 6]

I3 = identity matrix of size 3x3

(a) A^3:

To calculate A^3, we need to multiply matrix A by itself three times:

A^2 = A * A

A^3 = A^2 * A

A^2 = [-3 1] [−3 1] [-11 2]

[2 −1] * [2 −1] = [−2 1]

A^3 = [-11 2] [−3 1] [1 1]

[−2 1] * [2 −1] = [−4 −1]

The result is:

A^3 = [1 1]

[−4 −1]

(b) BCT:

To calculate BCT, we need to multiply matrix B by matrix C and then transpose the result:

BCT = (B * C)^T

B * C = [0 3] [7 0] [−21 0]

[−2 7] * [−1 3] = [13 15]

Transposing the result:

(B * C)^T = [−21 0]^T [−21]

[13 15]^T = [13]

[0 15]

The result is:

BCT = [−21]

[13]

[0 15]

(c) EC + I3:

To calculate EC + I3, we need to multiply matrix E by matrix C and then add the identity matrix I3:

EC = E * C

E * C = [1 3 −7] [7 0] [−28 3]

[−2 1 −3] * [−1 3] = [−4 6]

[0 2 6] [3 3] [0 24]

Adding the identity matrix:

EC + I3 = [−28 3] [1 0 0] [−27 3 0]

[−4 6] + [0 1 0] = [−4 7 0]

[0 24] [0 0 1] [0 24 1]

The result is:

EC + I3 = [−27 3 0]

[−4 7 0]

[0 24 1]

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The area bounded by the curves y = x - 2 and y = √x, between x = 0 and x = 4, is -59/6.

To obtain the area bounded by the curves y = x - 2 and y = √x, we need to determine the points of intersection between the two curves.

Setting the two equations equal to each other, we have:

x - 2 = √x

To solve this equation, we can square both sides:

(x - 2)^2 = (√x)^2

x^2 - 4x + 4 = x

Rearranging the terms and simplifying, we get:

x^2 - 5x + 4 = 0

Factoring the quadratic equation, we have:

(x - 1)(x - 4) = 0

This equation yields two solutions: x = 1 ad x = 4.

Now, we can determine the points of intersection by substituting these values back into the equations:

For x = 1:

y = 1 - 2 = -1 (from y = x - 2)

y = √1 = 1 (from y = √x)

For x = 4:

y = 4 - 2 = 2 (from y = x - 2)

y = √4 = 2 (from y = √x)

We have two points of intersection: (1, -1) and (4, 2).

To get the area bounded by the curves, we need to integrate the difference between the two curves with respect to x over the interval [1, 4].

The integral setup for getting the area A is as follows:

A = ∫[1, 4] [(x - 2) - √x] dx

Simplifying the integrand:

A = ∫[1, 4] (x - 2 - √x) dx

To evaluate this integral, we can split it into two parts:

A = ∫[1, 4] (x - 2) dx - ∫[1, 4] √x dx

Integrating each part:

A = [x^2/2 - 2x]∣[1, 4] - [2x^(3/2)/(3/2)]∣[1, 4]

Simplifying further:

A = [(4^2/2 - 2(4)) - (1^2/2 - 2(1))] - [2(4^(3/2))/(3/2) - 2(1^(3/2))/(3/2)]

A = [8 - 8 - (1/2 - 2)] - [(2(8))/(3/2) - (2)/(3/2)]

A = [8 - 8 - (1/2 - 4/2)] - [16/(3/2) - 2/(3/2)]

A = [-1/2] - [32/3 - 4/3]

A = -1/2 - 28/3

A = (-3 - 56)/6

A = -59/6

Therefore, the area bounded by the curves y = x - 2 and y = √x, between x = 0 and x = 4, is -59/6.

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