determine the focal length of a lens in a camera if the film is 36.9 mm away from the lens and the object distance is 59.2 cm.

Answers

Answer 1

The focal length of the lens is 39.3 mm. The result is obtained by using the thin lens equation.

What is the Thin Lens Equation?

The Thin Lens Equation is the equation used on a thin positive or negative lens.

[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]

Where

f = focal lengthd₁ = object distanced₂ = image distance

We have a camera with the film 36.9 mm away from the lens and the object distance is 59.2 cm. Determine the focal length!

Let's convert the object distance's unit!

59.2 cm = 592 mm

The distance of the film from the lens is the image distance. So, the focal length is

[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]

[tex]\frac{1}{f} = \frac{1}{592 } + \frac{1}{36.9 }[/tex]

[tex]\frac{1}{f} = \frac{(592-36.9)}{21844.8 }[/tex]

[tex]\frac{1}{f} = \frac{555.1}{21844.8 }[/tex]

[tex]f = \frac{21844.8}{555.1}[/tex]

f = 39.3 mm

Hence, the focal length of a lens in the camera is 39.3 mm.

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Related Questions

________ occurs when one physical device, such as a smartphone, provides the functions that previously required many physical devices, such as gps navigators, flashlights, medical devices, credit cards, texting, and cellular phones.

Answers

Dematerialization occurs when one physical device, such as a smartphone, provides the functions that previously required many physical devices, such as GPS navigators, flashlights, medical devices, credit cards, texting, and cellular phones.

Dematerialization is the process of changing your physical stocks and securities into digital or digital form. The simple timetable is to smoothen the technique of buying, promoting, shifting, and conserving stocks and additionally approximately making it value-powerful and foolproof.

It is the primary requirement to open a Demat account earlier than transacting within the Indian monetary marketplace. The Demat account eliminates all of the dangers that have been related to the keeping of stocks or securities inside the bodily shape.

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everyone at a party is talking equally loudly. if only one person were talking, the sound level would be 72 dB. find the sound level when all 38 people are talking. answer in units of db

Answers

If the sound level one person talks is 72 dB, the sound level when all 38 people are talking will be 87.8 dB.

Sound level difference is given by the expression, [tex]\Delta L=10log n[/tex], where n is the number of people.

Therefore, the difference in sound level in the given case will be

[tex]\Delta L=10log 38[/tex]

[tex]\Delta L=15.8 dB[/tex]

The final loudness will be the resultant of the initial loudness and the difference.

Final loudness = 72 + 15.8

Final loudness = 87.8 dB

Therefore, if the sound level one person talks is 72 dB, the sound level when all 38 people are talking will be 87.8 dB.

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a potato gun having a 0.560 m long barrel fires a 200 g potato by means of expanding gas. as the gas expands, the force on the potato is fx

Answers

If a potato gun having a 0.560 m long barrel fires a 200 g potato by means of expanding gas, the force on the potato is 6552 J

Fx = 14,500 N + (9000 N/m)x − (25,000 N/m²)x²

Since x is in meter, it represents the length of the barrel.

x = 0.56 m

Fx = 14500 + ( 9000 * 0.56 ) - ( 25000 * 0.56 * 0.56 )

Fx = 11700 N

W = F d

W = Work done

F = Force

d = Distance

d = 0.56 m

W = 11700 * 0.56

W = 6552 J

Therefore, the force on the potato is 6552 J

The given question is incomplete. The complete question is:

A potato gun having a 0.560 m long barrel fires a 300 g potato by means of expanding gas. As the gas expands, the force on the potato is Fx = 14,500 N + (9000 N/m)x − (25,000 N/m²)x², where x is in meters the x axis is along the length of the barrel. Determine the work done by the gas on the potato as it travels the length of the barrel.

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two large planets may have high gravitational pull between them because the strength of gravity is partially based upon:

Answers

Two large planets may have high gravitational pull between them because the strength of gravity is partially based upon: mass.

Define the Law of gravitation?

Newton's law of gravitation states that-

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them

It is expressed as-

                                            F = G(m1m2)/R^2

where,

G is the gravitational constant,

m1 and m2 are the masses

R is the distance

More massive objects will pull apart with a stronger gravitational force because the gravitational force is directly proportional to the mass of both interacting objects. Consequently, the gravitational pull between two objects grows as their respective masses do as well. The force of gravity between two things multiplies by 2 if one of their masses doubles. The force of gravity between two objects is tripled if one of their masses is tripled. The force of gravity between two objects is multiplied by two when their masses are equal, and so on.

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Here is a write up of an experiment on heat transfer. The independent variable in this experiment is the _________ of the container. What one word completes the sentence?.

Answers

The independent variable in this experiment is the temperature of the container, while the dependent variable is the heat transfer rate.

What is the dependent experimental variable?

The dependent experimental variable is any variable in an experiment that changes according to the modification of the independent variable that remains unaltered, which is then considered the cause of this change.

Therefore, with this data, we can see that the dependent experimental variable is associated with changes in the independent variable which is unaltered during all experimental procedures and is recognized as the cause of change.

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a weight of 1.0 kn is suspended from the end of a horizontal strut (of negligible mass) 1.5 m long that projects from a wall. a supporting cable 2.5 m long goes from the end of the strut to a point on the wall 2.0 m above the strut. the tension in the cable is

Answers

By observing the tension table we can conclude that the correct answer is Option B ; T = 2 × [tex]10^4[/tex]N

What is tension ?

Any physical object that is in contact with another one can apply forces to that object.

Depending on the types of objects in touch, we label these contact forces differently. We refer to the force as tension if a rope, string, chain, or cable is one of the things applying the force.

The best demonstration of a tension force is when a rope is being pulled. The rope builds up a lot of tension when a pull force is applied to it. However, upon pulling on the rope, the tension is lost and the rope becomes slack.

Given mass = 1 kg

N - mg = ma

F = ma

and mg = ma because the object is static

thus N = 2mg

N = 2 × 1000 × 10

N = 2 × [tex]10^4[/tex] N

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two particles of masses m1 and m2 ( m1

Answers

More than five meters, but less than ten meters, separate two particles with mass m1 and m2 from the atom of mass m1.

Describe mass.

In physics, mass is a quantification of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the use of a force. The change caused by a force applied is smaller the more mass a body has.

Describe the mass formula.

The mass with one mole of a chemical substance or the ratio of a mass of a chemical to its number of chemicals substance is known as the molar mass (M), which is a physical attribute.

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How do I calculate resistance?.

Answers

Resistance can be calculated be using Ohm's law.

What is resistance?

When a substance opposes the flow of electric current, it is said to be resistance. Uppercase letter R is used to symbolize it. The ohm, also written as a word or represented by the Greek letter Ω in uppercase, is the unit of resistance that is typically used.

In a direct-current (DC) electrical circuit, the current is typically inversely proportional to the resistance while the applied voltage is held constant. The current is cut in half when the resistance is doubled; when the resistance is cut in half, the current is increased by double.

By applying Ohm's law which states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant, we can easily calculate resistance of any electrical circuit.

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how many meters does a tossed baseball fall beneath a straight-line path in traveling for 1 ss ? for 2 ss ?

Answers

For t = 1 second, the distance travelled will be 5m

For t = 2 seconds, the distance travelled will be 20m

What is a projectile motion?

Projectile motion is the motion of a body which experiences both vertical and horizontal motions from point of flight up to the point of landing. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

From the question;

For t = 1 second

[tex]H = ut + \frac{1}{2}gt^{2}[/tex]

but u = 0, so;

[tex]H = \frac{1}{2} gt^{2}[/tex]

where g = 10m/s2

H = 1/2 x 10 x 1 x 1

H = 5m

For t = 2 seconds

[tex]H = ut + \frac{1}{2}gt^{2}[/tex]

but u = 0, so;

[tex]H = \frac{1}{2} gt^{2}[/tex]

where g = 10m/s2

H = 1/2 x 10 x 2 x 2

H = 20m

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A 90-watt red light bulb and a 60-watt green light bulb are turned on. Which bulb emits photons with the greater energy?.

Answers

A 90-watt red light bulb and a 60-watt green light bulb are turned on. Which bulb emits photons with the greater energy?. The green bulb

The green bulb, because a green photon has a greater energy than a red photon.

A photon (from historical Greek φῶς, φωτός (phôs, phōtós) 'light') is an fundamental particle that may be a quantum of the electromagnetic discipline, consisting of electromagnetic radiation including light and radio waves, and the force provider for the electromagnetic pressure. Photons are massless,[a] so that they constantly move at the rate of mild in vacuum, 299792458 m/s (or approximately 186,282 mi/s). The photon belongs to the magnificence of bosons.

As with other primary debris, photons are excellent defined via quantum mechanics and exhibit wave–particle duality, their conduct offering residences of both waves and particles. The contemporary photon idea originated in the course of the first two a long time of the twentieth century with the paintings of Albert Einstein, who built upon the research of Max Planck. while looking to explain how depend and electromagnetic radiation can be in thermal equilibrium with each other, Planck proposed that the strength stored inside a fabric item have to be appeared as composed of an integer wide variety of discrete, equal-sized elements. To give an explanation for the photoelectric impact, Einstein added the concept that mild itself is manufactured from discrete devices of strength. In 1926, Gilbert N. Lewis popularized the time period photon for these energy gadgets. eventually, many different experiments confirmed Einstein's method.

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A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as the drawing shows. The centripetal acceleration measured at corner $A$ is $n$ times as great as that measured at corner $B$. What is the ratio $L_{1} / L_{2}$ of the lengths of the sides of the rectangle when $n=2.00 ?$

Answers

12.5 m/s²  is the centripetal acceleration of rotating body.

speed= 5 m/s

radius= 2 m

centripetal acceleration=v²/r

centripetal acceleration=25/2

centripetal acceleration=12.5 m/s²

The speed at which a body rotates around a circle is known as centripetal acceleration. When a body travels in a circle, its direction is constantly changing, which results in a change in velocity, which generates an acceleration because velocity is a vector quantity (i.e., it contains both a magnitude, the speed, and a direction). The acceleration is directed radially toward the center of the circle. The value of the centripetal acceleration, symbolized by the letter ac, is equal to the square of the body's speed along the curve divided by the circle's radius. This is sometimes referred to as the equation ac = v2/r. Meters per second squared are used to measure centripetal acceleration.

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A 120 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.180 m/s. How much work must be done on the hoop to stop it?
___ J

Answers

The work that must be done on the hoop to stop it is calculated to be -3.888 J.

As the mass of the hoop is 120 kg and the hoop's center of mass has a speed of 0.180 m/s, the rotational inertia can be given as follows;

I= mr^2

I=120r^2

The kinetic energy of hoop = Linear kinetic energy + Rotational kinetic energy

K= (1/2mv^2) + (1/2Iw^2)

But; w= (v/r)^2

K= (1/2mv^2) + (1/2×120r^2(v/r)^2)

K = (1/2×120×0.180^2) + (1/2×120×0.180^2)

K = 3.888 J

To stop the hoop, its final kinetic energy must be 0, therefore;

Work done = Kfinal-Kinitial = 0 - 3.888

W= -3.888 J

Hence, -3.888 J of work must be done to stop the hoop.

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ive a basis for each of the given vector spaces over the given field. what is the degree of each field extension?

Answers

A subset of vectors in a vector space that are linearly independent and span the entire space is known as a vector basis.

What is basis vector in vector space?

Make V, for some n, a subspace of Rn. If B is linearly independent and spans V, it is said to be a collection of vectors from V with the formula B = v 1, v 2,..., v r. The collection cannot serve as a foundation for V if either of these requirements is not met. Any vector in V can be written as a linear combination of the vectors in a collection of vectors if it spans V and contains enough vectors to do so. Because there aren't too many vectors in the collection, none of them can start to depend on the others if it is linearly independent. Thus, a basis appears to be the perfect size: It can span the room, but it isn't very large.Example 1: Since the vectors I and j are linearly independent and the collection i, j spans R 2, it serves as a basis for R2. The standard basis for R 2 is what is meant by this. Similar to this, the set i, j, k is referred to as the standard basis for R 3 and is, generally speaking, the standard basis for R n.

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the crank oa rotates in the vertical plane with a constant clockwise angular velocity woof 3.9 rad/s. for the position where oa is horizontal, calculate the force under the light roller b of the 17.0-kg slender bar ab

Answers

The centripetal force under the light roller b of the 17.0-kg slender bar ab is 465.4 N

What is the force under light roller?

The force under light roller b is calculated by applying Newton's second law of motion.

Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

Mathematically, this law is written as;

F = ma

where;

m is the mass of the objecta is the acceleration

in a circular path, we centripetal acceleration, which is given as;

ac = ω²r

where;

ω is the angular speedr is the radius of the path

The radius of the circular path in this case corresponds to length ab = 1.8 m

F = m(ω²r)

F = 17 x (3.9² x 1.8)

F = 465.4 N

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The complete question is below;

the crank oa rotates in the vertical plane with a constant clockwise angular velocity woof 3.9 rad/s. for the position where oa is horizontal, calculate the force under the light roller b of the 17.0-kg slender bar ab which is equal to 1.8 m.

a block of mass 0.4 kg on a horizontal surface is attached to a horizontal spring of negligible mass. the other end of the spring is attached to a wall, and there is negligible friction between the block and the horizontal surface. the center of mass of the block is stretched a horizontal distance x

Answers

Soli energy from the potential energy distance is x = 0.25m. Then plenty of horizontal position graph, we get to that when hor.

Time - period of oscillation, T=21m k Mass = 0.4 +10 = 114 kq = 14 kg 114 320 T = 0.415 second T = 0.42 second us hoolzent.

If you hang a shape from one point you'll find that the center of mass is always directly below that point. So if you hang a shape from two different points and draw a line down from each point the center of mass is where those lines intersect.

The product of the total mass of the system and the position vector of the center of mass equals the sum of the products of the masses of the two particles and their respective position vectors. The center of mass is a position defined relative to an object or system of objects.

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a 1 kg ball is hung at the end of a rod 1 m long. if the system balances at a point on the rod 0.25 m from the end holding the mass, what is the mass of the ro

Answers

The mass of the rod is 1 kg.

Solution:

So 1*25=x*25

1 kg

The product of the total mass of the system and the position vector of the center of mass equals the sum of the products of the masses of the two particles and their respective position vectors. If the mass is unevenly distributed, the centroid is in the area of ​​higher mass.

If the density increases decrease continuously from left to right or right to left the centroid is not at the center of a particular rod. Mass is the amount of matter in the physical body. It is also a measure of body inertia, resistance to acceleration when a net force is applied. An object's mass also determines the strength of gravity on other objects.

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What is the wavelength of a 200 Hz wave?.

Answers

The answer is 150 cm!!!

The researchers calculated a chi-square value of 29.25. If there are three degrees of freedom and the significance level is p=0.05, which of the following statements best completes the chi-square test?
The critical value is 7.82, and the null hypothesis can be rejected because the calculated chi-square value is greater than the critical value.

Answers

The critical value is 7.82. Because the calculated chi-square value is greater than the critical value, the null hypothesis can be rejected.

What is meant by critical value?A crucial value is the test statistic's value that establishes a confidence interval's upper and lower boundaries or the level of statistical significance for a given test.In differential topology, a critical value of a differentiable function is ƒ: M → N between differentiable manifolds, where x is the critical point, and y is the image of x in M in N.A chi-square critical value establishes confidence ranges for specific parameters and serves as a threshold for statistical significance for some hypothesis tests. Chi-square distributions are used to calculate chi-square critical values.The level of significance (typically.05) and degrees of freedom determine the critical value for the chi-square statistic. The formula used to compute the degrees of freedom for the chi-square is: df = (r-1)(c-1) where r is the number of rows and c is the number of columns.

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If the magnitude of the net force acting on the particle is F , how long does it take the particle to acquire its final velocity, 2v in the positive y direction? Express your answer in terms of m, F and v If you use a numerical coefficient, use three significant figures. I found that the answer is (mv/F) but its asking with use three significant figures so how i can find it

Answers

The time taken to reach the velocity 2v is 2fv/m. Acceleration is the term used to describe the change in a moving object's velocity with relation to time.

How to calculate velocity ?

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

It is given that the force acting on the particle is F. So from Newton's law of motion;

F = ma

a =f/m

dv/dt = f/m

[tex]\int\limits^2_0{} \, dv \\[/tex][tex]= \int\limits^l_0 {f/m} \, dt[/tex]

2v = f/m * t

t = 2fv / m

Hence the time taken to reach the velocity 2v is  2fv / m

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when an object is located 38 cm to the left of a lens, the image is formed 22 cm to the right of the lens. what is the focal length of the lens?

Answers

The focal length located 38 cm to the left of a lens, the image is formed 22 cm to the right of the lens is the distance between the lens and the focal point.

All this lenses possesses focal point which is the point where all light incident on the lens converges after reflection. This focal point is closer to the pole of the curved lens. The length between this focal point of the curved mirror and the pole of the lens is therefore the focal length of the lens.

Object distance (u) = 38cm

Image distance(v) = 22cm

Focal length(f) =?

Lens formula:

1/f = 1/u + 1/v

1/f = 1/38 + 1/22

Taking the L. C. M of 22 and 38

1/f = (22 + 38) / 836

1/f = 60/836

Taking the reciprocal

f = 836/60

f = 13.9cm

Therefore, Focal length of the lens is 13.9 cm

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A 22.4 kg block is placed on a ramp that makes an angle of 22 ° to the horizontal. The coefficient of friction between the block and the ramp is 0.11. The block is released from rest and allowed to slide down the ramp. What is the acceleration of the block?

Answers

Answer:  2.67 m/s2

Explanation:

W = mg = (22.4 kg)(9.8 m/s2) = 219.52 N

Wx = (219.52 N)(sin 22) = 82.2 N

Wy = (219.52 N) (cos 22) = 203.5 N

Wy = N (normal force on the block) = 203.5 N

Ff (force of friction) = (coeff. friction)(N) = (0.11)(203.5 N) = 22.4 N

Sum the forces in the x-direction (direction of motion down the ramp):

Fnet = Wx - Ff = 82.2 N - 22.4 N = 59.8 N

a = F/m = 59.8 N / 22.4 kg = 2.7 m/s2

if the maximum force that any member can support is 8 kn in tension and 6 kn in compression, determine the maximum force p that can be supported at joint d.

Answers

According to the given statement The maximum force p that can be supported at joint d is -P / √3 .

What is compression in physics with example?

Pressing two spring ends together is a common visual representation of compression force. The physical shape of the spring gets compacted as compressive pressure is applied to it. The spring immediately extends outward and returns to its original shape when the strain is released.

Briefing:

F[tex]_C_D[/tex] sin 60⁰ = P

F[tex]_C_D[/tex] = 2P / √3.................(Tension)

F[tex]_E_D[/tex] + F[tex]_C_D[/tex] cos 60⁰ = 0

F[tex]_E_D[/tex] = -2P / √3 ×1 / 2 = -P / √3  ..................(Compression)

At joint C

F[tex]_A_B[/tex] = 2P / √3 ..................(Tensile)

F[tex]_B_E[/tex] = -2P / √3 ..................(Compression)

F[tex]_A_E[/tex] + Feb cos 60⁰ = Fec cos 60⁰ + Fed

F[tex]_A_E[/tex] = -2P / √3  × 1/2 + -P / √3 + -2P / √3 × 1/2

F[tex]_A_E[/tex] =  -P / √3

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The zigzag movement of sand grains along a beach is ________.
A. caused by obliquely breaking waves
B. called beach drift
C. very unusual seldom occurs
D. both A and B
both A and B

Answers

The zigzag movement of sand grains along a beach is caused by obliquely breaking waves and called beach drift.

Sediments are moved in a zigzag pattern by the waves down the beach (red arrows). Sediment is mostly transferred in the surf zone. Beach drift refers to the movement of sand along the shore. Sand moves zigzag and is referred to as beach drift when the waves are crashing obliquely.The interaction between coastal waves and sea bottom leads to important coastal phenomena such wave breaking, wave-induced currents, sediment transport, and bed shape change. The mechanism that causes currents to form in the surf zone, where wave energy dissipation occurs after breaking, is wave breaking, which occurs when the wave height and steepness become very great as the water depth shallows.

Thus the correct option is D.

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What evidence have you discovered to explain how kinetic energy and mass are related

Answers

Explanation:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

calculate the period of a satellite orbiting the moon, 99 km above the moon's surface. ignore effects of the earth. the radius of the moon is 1740 km .

Answers

The period of a satellite orbiting the moon, 99 km above the moon's surface is 1.96 hours.

Since the satellite is at a distance of 99 km from the surface and radius of the moon is 1740 km, the effective radius of orbit of the satellite will be

R = 1740+99 = 1839 km

Then taking the mass of the moon:

M = mass of moon = [tex]7.348\times10^{22} kg[/tex] kg

Now the time period can be calculated using the formula:

T = 2π√[R³/(GM)]

Where G is the universal gravitational constant with value [tex]6.67\times10^{-11}[/tex]

Substituting all the values we have, the time period of the given satellite of moon will be

T=7068 s =1.96 hours

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a 9.25 cm -diameter toy top has a moment of inertia of 0.000412 kg m2 about its rotation axis. a string is wrapped around the outside edge of the top. the string is long enough to wrap around the top at least five whole turns. to get the top spinning, its string is pulled with a constant tension of 0.49 n. the tension force is tangent to the circular top.

Answers

The time taken to complete its first five revolutions is 1.07 seconds.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

Torque is also can be calculated by the moment of inertia

τ = I . α

where I is moment of inertia and α is angular acceleration.

From the question above, the parameters given are

F = 0.49 N

I = 0.000412 kgm²

d = 9.25 cm

r = 0.04625 m

N = 5 turns

Find the angular acceleration

τ = τ

I . α = F x r

0.000412 . α = 0.49 . 0.04625

α = 55.01 rad/s²

Find the displacement of total revolution (θ)

θ = N . 2π

θ = 5 . 2π

θ = 10π rad

Find the time taken

θ = 1/2 . α . t²

10π = 1/2 . 55.01 . t²

t² = 1.14

t = 1.07 seconds

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What force does a full moon exert on such a human when it is directly overhead with its center 378,000 km away?.

Answers

The moon pulls a person with a force of 2.4 10 3N. 2.4 × 10 − 3 N . Therefore, the moon's force on the guy is 3.5 x 10-6. 3 5 10 6 times the size of the earth.

Explain about the Force?

The definition of "force" is unambiguous. It is quite acceptable to refer to a force of this level as a push or a pull. It's incorrect to say that an object "has in it" or "contains" a force. A force is experienced by one thing from another. The concept of a force makes no distinction between living creatures and inanimate objects.

A mass-containing object's velocity is altered by a push or pull. An external force is a force that can change a body's resting or moving condition. There is a magnitude and a direction to it.

It is common to utilize Isaac Newton's three principles of motion, which are described in his Principia Mathematica, to demonstrate the idea of force (1687)

= 3.78 x 108 m2 = 6.67 x 10-11N.m2kg27.35 x 1022 kg 70 kg

= 2.40 x 10-3 N

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The amplitude of the voltage across an inductor can be greater than the amplitude of the generator emf in an RLC circuit. Consider an RLC circuit with Epeak = 120 V, R = 15.3 capital omega, L = 1.31 H, and C = 2.09 µ F. Find the amplitude of the voltage across the inductor at resonance.

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The amplitude of the voltage across an inductor can be greater than the amplitude of the generator emf in an RLC circuit. Consider an RLC circuit with Epeak = 120 V, R = 15.3 capital omega, L = 1.31 H, and C = 2.09 µ F. The amplitude of the voltage across the inductor at resonance will be 6223.8624 V.

Peak voltage, Eo = 120 V

Resistance, R = 15.3 Ω

Inductance, L = 1.31 H

Capacitance, C = 2.09 μF = 2.09 × 10^-6 F

At resonance, the angular frequency is given by

ωo = 1/(LC)^1/2

= 1/ [(1.31×2.09 × 10^-6)^1/2]

= 0.606×10^3 rad/s

= 606 rad/s

XL = ωoL

= 606×1.31

= 793.86 ohm

Xc = 1/(ωoC)

= 1/(606×2.09 × 10^-6)

= 0.000789×10^6

=793.86 ohm

If there is resonance at the circuit then impedance will be equal to the resistance of the circuit.

So, Z = R = 15.3 ohm

Io = Eo/Z

= 120/15.3

= 7.84 A

Then ===3 across the inductor will be

VL = Io×XL

= 7.84×793.86

= 6223.8624 V

Hence,  the amplitude of the voltage across the inductor at resonance is 6223.8624 V.

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you are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. which of the following increases the energy density? (select all that apply.)

Answers

On the solenold, increase the number more turns per unit length.

What does an automobile solenoid do?

It functions as an electric and magnetic motor that is attached to your car's battery and is intended to take in low current power and start rotating the appropriately named starter gear before turning again to start a ’s electrical reaction and (in time) your full engine.

What governs a solenoid's operation?

A grommet functions by establishing an electromagnet surrounds an electromagnet, which would be a vibrating nucleus. The electromagnetic field causes that armature to move, and when it does, it opens valves or switches, converting electrical energy to mechanical energy motion and force.

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In the figure, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a=8.50 cm. Each wire carries 15.0 A, and all the currents are out of the page. In unit-vector notation, what is the net magnetic force per meter of wire length on wire 1?

Answers

The net magnetic force per meter of wire length is ( 7.94 ×[tex]10^{-4}[/tex]N/m)i + ( -7.94 × [tex]10^{-4}[/tex]N/m )j.

Here we have to find the net magnetic force per meter.

Using dB= μi sinФ/ 4π r²dx the force on say, wire 1 (the wire at the upper left of the figure) is along the diagonal (pointing toward wire 3, which is at the lower right). Only the forces (or their components) along the diagonal direction contribute. With θ=45°, we find the force per unit meter on wire 1 to be

F1 =∣ F 12 + F 13 + F 14∣=2F 12 cosθ+F 13=2( μi²/ 2p ia)cos45° + μi² / 2√2πa

                                    = 3 / 2√2π (μi²/a)

                                    =3/ 2√2 π ( 4π × [tex]10 ^{-7}[/tex] T.m / A ( 15.0A)² / (8.50 ×[tex]10^{-2}[/tex]m)

                                    = 1.12 × [tex]10^{-3}[/tex] N/m

The direction of  F1 is along r = (î = j) / √2.

In unit-vector notation, we have

F1 = ( 1.12 ×[tex]10^{-3}[/tex]N/m) / √2 (i - j)

   = ( 7.94 × [tex]10^{-4}[/tex]N/m) i + ( -7.94 × [tex]10^{-4}[/tex]N/m) j

Therefore the net force is ( 7.94 ×[tex]10^{-4}[/tex]N/m)i + (-7.94 × [tex]10^{-4}[/tex]N/m)

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