Devon’s bike has wheels that are 26 inches in diameter. After the front wheel picks up
a tack, Devon rolls another 100 feet (1200 inches) and stops. How far above the ground in inches is the tack?

Answer:

[tex]\frac{6}{x-5}[/tex]

Step-by-step explanation:

Helping in the name of Jesus.

The discount rate is increased by 12%, the new net present value will be approximately Rs. 5514.29.

To determine the net present value (NPV) when the discount rate is increased by 12%, we need to recalculate the NPV using the new discount rate.

Given:

Current NPV = Rs. 6172

Current discount rate = 9%

Increase in discount rate = 12%

To find the new NPV, we can use the formula:

New NPV = Current NPV / (1 + Increase in discount rate)

Calculating the new NPV:

New NPV = 6172 / (1 + 0.12)

New NPV = 6172 / 1.12

New NPV ≈ Rs. 5514.29

Therefore, if the discount rate is increased by 12%, the new net present value will be approximately Rs. 5514.29.

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Answer:

That's a great point! It's important to continue to encourage others to recycle and to educate people on the benefits of recycling to help achieve that 100% goal.

Answer:

D. 2

Step-by-step explanation:

y=mx+b

m is the slope in this case, and by your equation, we can easily see that the answer should be D, with a slope of 2.

Answer:

d.2

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

y=2x+6

m=2

b=6

slope=2

Answer:

5 + m^3 n^2

----------------------

m^2 n^2

Step-by-step explanation:

To add fractions, we need to get a common denominator:

The common denominator is m^2 n^2.

Multiply the second term by m^2n/ m^2n

m/n * m^2n / m^2 n = m^3n / m^2n^2

Now we can add the two terms

5                               m^3 n^2

------                 + ---------------------------

m^2 n^2                      m^2 n^2

5 + m^3 n^2

----------------------

m^2 n^2

The area of the circle with a radius of 5 cm is approximately 78.53975 square centimeters.

To calculate the area of a circle, we need to use the formula A = πr², where A represents the area and r represents the radius of the circle. In this case, the given radius is 5 cm.

Plugging the value of the radius into the formula, we get:

A = π(5 cm)²

Simplifying the equation further, we have:

A = π(25 cm²)

Using the value of π (pi) as approximately 3.14159, we can calculate the area:

A ≈ 3.14159 × 25 cm²

A ≈ 78.53975 cm²

It's important to note that the area of a circle is always expressed in square units, as it represents the amount of space enclosed by the circle.

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Answer:

when x=-9, y=1

Step-by-step explanation:

the graph shows when the x is at -9, the y is at 1

The area of the triangle is 47.91 units²

When all three sides of the triangle are known we can use Heron's formula. Consider the triangle ABC with sides a, b, and c has shown in the image.

Heron’s formula is:

Area =√s(s−a)(s−b)(s−c)

where,

a, b, c are the side length of the triangle

s is the semi-perimeter. s = (a+b+c)/2

In this case:

Using the knowledge of the radius of a circle. We can say:

a = BC = 3 + 9 = 12 units

b = AC = 5 + 3 = 8 units

c = AB = 5 + 9 = 14 units

s = (a+b+c)/2

s = (12+8+14)/2

s = 34/2

s = 17 units

Area = √s(s−a)(s−b)(s−c)

Area = √17(17−12)(17−8)(17−14)

Area = √17(5)(9)(3)

Area = √2295

Area = 47.91 units²

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Answer:

  (b) When a vertical line intersects the graph of a relation more than once, it indicates that for that input there is more than one output, which means the relation is not a function.

Step-by-step explanation:

You want to know why the vertical line test tells us whether the graph of a relation represents a function.

A relation maps a set of inputs to a set of outputs. A function maps a set of unique inputs to a set of outputs. That is, the elements of the input set of a function are not repeated, but appear only once.

On the graph of a relation, the input values are mapped to the horizontal coordinate(s) of the point(s) on the graph. If the relation has repeated input values, then those points will have the same x-coordinate on a graph, and will lie on a vertical line. So, we can conclude ...

When a vertical line intersects the graph of a relation more than once, it indicates that for that input there is more than one output, which means the relation is not a function.

__

Additional comment

You can narrow the choices by considering their vocabulary. The question asks about the graph of a relation. Choices A and D talk about the graph of a function, so can be rejected immediately.

The subject of the question is a vertical line. As you know, a vertical line is of the form x = constant, where an (x, y) ordered pair is an (input, output) pair of a relation. Thus a vertical line will be referring to one input value that is a constant. Choice C talks about "more than one input", which has no relationship to a vertical line. Hence the only choice that makes any sense in the context of the question is B.

A lot of multiple choice questions can be answered appropriately just by considering the way the question and answers are worded.

<95141404393>

1) 2a - 100

Substituting the value of a here,

[tex] \rm 2(32) - 100 [/tex]

[tex] \rm 64 - 100 [/tex]

[tex] \rm -36 [/tex]

2) b (-12)

Substituting the value of b here,

[tex] \rm 150 (-12) [/tex]

[tex] \rm -1800 [/tex]

3) 4a + b

Substituting the values of a and b here,

[tex] \rm 4(32) + 150 [/tex]

[tex] \rm 128 + 150 [/tex]

[tex] \rm 278 [/tex]

4) 9b - 2a

Substituting the values of a and b here,

[tex] \rm 9(150) - 2 (32) [/tex]

[tex] \rm 1350 - 64 [/tex]

[tex] \rm 1286 [/tex]

The answers are:

below in [tex]\bold{bold}[/tex]

Work/explanation:

Plug in 32 for a

[tex]\sf{2(32)-100}[/tex]

[tex]\sf{64-100}[/tex]

[tex]\bf{-36}[/tex]

____________

[tex]\sf{b(-12)}[/tex]

[tex]\sf{150\cdot(-12)}[/tex]

[tex]\bf{1,800}[/tex]

____________

[tex]\sf{4a+b}[/tex]

[tex]\sf{4(32)+150}[/tex]

[tex]\sf{128+150}[/tex]

[tex]\bf{278}[/tex]

____________

[tex]\sf{9b-2a}[/tex]

[tex]\sf{9(150)-2(32)}[/tex]

[tex]\sf{1,350-64}[/tex]

[tex]\bf{1,286}[/tex]

____________

Answer:

We can simplify the expression under the cube root first:

3∛(125a^6) = 3∛(5^3 * a^6) = 3 * 5 * a^2 = 15a^2

Therefore, the cube root of 3 square root 125 a^6 is equal to 15a^2.

This table shows the frequency of each number obtained after throwing the die 35 times

To prepare a frequency table based on the numbers obtained from throwing a die 35 times, we can list the numbers from 1 to 6 and count the frequency of each number.

Numbers: 1, 2, 3, 4, 5, 6

Frequency: 5, 14, 6, 4, 5, 1

Based on the given numbers, the frequency table would look like this:

Number   | Frequency

1                      5

2                     14

3                      6

4                      4

5                      5

6                       1

This table shows the frequency of each number obtained after throwing the die 35 times.

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the left side of this equation equal the right side through the process of completing the square that establishes the equality between the left side and the right side of the Gaussian integral equation.

using  completing the square method:

Starting with the left side of the equation:

∫[tex]e^(^-^x^2)[/tex] dx

[tex]e^(^-^x^2) = (e^(^-x^2/2))^2[/tex]

∫[tex](e^(^-^x^2/2))^2 dx[/tex]

let  u = √(x²/2) =  x = √(2u²).

dx = √2u du.

∫ [tex](e^(^x^2/2))^2 dx[/tex]

= ∫ [tex](e^(^-2u^2)[/tex]) (√2u du)

The integral of [tex]e^(-2u^2)[/tex]= √(π/2).

∫ [tex](e^(-x^2/2))^2[/tex] dx

= ∫  (√2u du) [tex](e^(-2u^2))\\[/tex]

= √(π/2) ∫ (√2u du)

We substitute back  u = √(x²/2), we obtain:

∫ [tex](e^(-x^2/2))^2[/tex]dx

= √(π/2) (√(x²/2))²

= √(π/2) (x²/2)

= (√π/2) x²

A comparison  with the right side of the equation  shows that they are are equal.

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Answer:

d. creating

Step-by-step explanation:

Random numbers are useful for creating real words situations that involve chance.

A.being

B.selling

C.modeling

D.creating

To determine the probability of having a specific number of phone calls within a given minute, we can use the Poisson distribution, assuming that the calls follow a Poisson process.

The average number of phone calls per minute is 2.5, which indicates that the rate parameter (λ) is also 2.5, as it represents the average number of events occurring in a given interval.

To calculate the probability of having 4 or fewer calls in one minute, we sum the probabilities of having 0, 1, 2, 3, or 4 calls using the Poisson distribution formula. The probability is given by:

P(X ≤ 4) = Σ(k=0 to 4) (e^(-λ) * λ^k / k!)

Similarly, to find the probability of having more than 6 calls, we sum the probabilities of having 7, 8, 9, and so on, up to infinity. The probability is calculated as:

P(X > 6) = 1 - P(X ≤ 6)

By plugging in the values and performing the calculations, we can determine the probabilities for both scenarios.

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The percent profit will be 15.5%.The formula used to calculate the percentage profit is:Percentage Profit = (Profit / Cost Price) x 100%.

Let's assume that the retailer has an item with a wholesale price of $100. After a 54% increase in the wholesale price, the new wholesale price is $154.Now, when the retailer provides a 25% discount off the ticket price, the new price of the item becomes: $154 x 75% = $115.5.

The cost of producing the item is $100, but the retailer sells it for $115.5. Hence, the profit made by the retailer is:$115.5 - $100 = $15.5 or 15.5% profit.The percent profit that the retailer will realize is 15.5%. Therefore, the percent profit will be 15.5%.The formula used to calculate the percentage profit is:Percentage Profit = (Profit / Cost Price) x 100%.

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The distance from Trinidad to Tobago via the ferry is approximately 158 kilometers, but when rounded to the nearest tens, it is approximately 160 kilometers.

The distance from Trinidad to Tobago via the ferry is approximately 158 kilometers. To determine the distance to the nearest tens, we need to round this value to the nearest multiple of 10.

To round a number to the nearest tens, we look at the digit in the ones place. If it is 0 to 4, we round down, and if it is 5 to 9, we round up.

In this case, the digit in the ones place is 8. Since 8 is closer to 10 than to 0, we round up to the nearest tens. Thus, the distance from Trinidad to Tobago can be rounded to 160 kilometers.

Rounding to the nearest tens gives us a value that is easier to work with and provides a rough estimate. It is important to note that this rounded value is not exact and may differ slightly from the actual distance. However, for practical purposes, rounding to the nearest tens is often sufficient.

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[tex](8.2 \times 10^(^-^1^0^))[/tex][tex](5.3\times 10^(^-^9^))[/tex]The sum of [tex](5.3 \times 10^(^-^9^))[/tex] and [tex](8.2 \times 10^(^-^1^0^))[/tex] in scientific notation is 1.35 x 10^−8.

To find the sum of [tex](5.3 \times 10^(^-^9^))[/tex] and [tex](8.2 x 10^(^-^1^0^))[/tex], we can add the coefficients and keep the same base, which is 10. Adding 5.3 and 8.2 gives us 13.5. Since both numbers are expressed in scientific notation, we need to adjust the decimal point to have one digit to the left of it.

The exponent in scientific notation represents the number of decimal places we need to move the decimal point to the left (for negative exponents) or to the right (for positive exponents). In this case, the exponents are -9 and -10.

Since -9 is larger than -10, we need to adjust the decimal point by 1 place to the left. Therefore, the sum of [tex](5.3 x 10^(^-^9^))[/tex] and [tex](8.2 \times 10^(^-^1^0^))[/tex] in scientific notation is [tex]1.35 \times 10^-^8^[/tex].

Note: Scientific notation is a concise way of representing very large or very small numbers by using powers of 10. It consists of a coefficient (a decimal number between 1 and 10) multiplied by 10 raised to an exponent.

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Answer:

3√2/2

Step-by-step explanation:

4 1/2 = 9/2

Now we can express this fraction in radical form by finding the square root of the numerator and denominator separately:

√(9/2) = √9 / √2

Since the square root of 9 is 3, we can simplify further:

√(9/2) = 3 / √2

To rationalize the denominator (i.e., eliminate the radical from the denominator), we can multiply both the numerator and denominator by √2:

3 / √2 * √2 / √2 = 3√2 / 2

Therefore, 4 1/2 in radical form is 3√2/2.

Answer:

A, B, E

Step-by-step explanation:

Notice that A, B, and E all maintain their common ratios, while C and D do not.

Answer:

Step-by-step explanation:

x-6y=4

To solve these equations, we can use the elimination method. We want to eliminate one of the variables, either x or y, by multiplying one of the equations by a constant so that the coefficients of one variable will be the same in both equations but with opposite signs. For example, we can multiply the first equation by 4 to get:

-20x - 24y = -128

Then we can add this equation to the second equation to eliminate y:

-20x - 24y + 4x - 6y = -128 + 4

Simplifying this equation gives:

-16x - 30y = -124

Now we can isolate one variable in terms of the other:

-16x - 30y = -124

-16x = 30y - 124

x = (30/(-16))y + (-124/(-16))

x = (-15/8)y + 31/2

We can substitute this expression for x into either of the original equations to solve for y. For example, substituting into the first equation gives:

-5((-15/8)y + 31/2) - 6y = -32

Multiplying by -8 to clear the fractions gives:

75y - 248 - 48y = 256

Simplifying and solving for y gives:

27y = 504

y = 18.67

Then we can substitute this value of y back into our expression for x to find:

x = (-15/8)(18.67) + 31/2

x = -12.25

Therefore, the solution to the system of equations is:

x = -12.25

y = 18.67

This is the rectangular equation described by the parameter equation x = t1/3 and y = t – 4.

Elimination of the parameter means to rewrite the equations in terms of only x and y. To do this, substitute t from one equation into the other equation. Here, the two equations are:x = t1/3 and y = t – 4Substitute t from the first equation into the second equation:y = (x^3) – 4Now the equation is in terms of x and y only.

This is the rectangular equation described by the parameter equation x = t1/3 and y = t – 4.The rectangular equation, y = (x^3) – 4 can be plotted on a graph. It is a cubic equation. The graph will look like a curve that passes through the point (0, -4) and continues to move towards infinity. The graph will be symmetric to the origin because the equation involves an odd power of x.

If the equation involved an even power of x, the graph would be symmetric to the y-axis. The graph will never touch the x-axis or y-axis, it will only approach them.In conclusion, the rectangular equation y = (x^3) – 4 is derived from the two parameter equations, x = t1/3 and y = t – 4. The graph of this equation is a cubic curve that is symmetric to the origin. The curve passes through (0, -4) and approaches the x and y-axes but never touches them.

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Answer:

a. The cost at 3% is $46.57 b. The cost at 4% is $49.33 c. The cost at 5% is $52.21

Step-by-step explanation:

The function value for f(g(4)) include the following: f(g(4)) = 6.

In Mathematics and Geometry, a function is a mathematical equation which defines and represents the relationship that exists between two or more variables such as an ordered pair in tables or relations.

By critically observing the table of values of the function f and g shown in the image attached above, we can reasonably infer and logically deduce the following function values:

g(4) = 1

f(g(4)) = f(1)

f(1) = 6.

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743 general admission tickets and 304 reserved seat tickets were sold.

Let's solve this problem using a system of equations. Let's assume that x represents the number of general admission tickets sold and y represents the number of reserved seat tickets sold.

According to the given information, we have two equations:

Equation 1: The total number of tickets sold is 1047.

x + y = 1047

Equation 2: The total revenue from ticket sales is $4576.50.

3.50x + 6.50y = 4576.50

Now, we can solve this system of equations.

We can start by multiplying Equation 1 by 3.50 to eliminate x:

[tex]3.50(x + y) = 3.50(1047)\\3.50x + 3.50y = 3664.50[/tex]

Now we have the following system of equations:

[tex]3.50x + 3.50y = 3664.50 (Equation 3)\\3.50x + 6.50y = 4576.50 (Equation 2)[/tex]

By subtracting Equation 3 from Equation 2, we can eliminate x:

[tex](3.50x + 6.50y) - (3.50x + 3.50y) = 4576.50 - 3664.50\\3.00y = 912.00[/tex]

Dividing both sides of the equation by 3.00, we find:

y = 304

Now, substitute the value of y into Equation 1 to find x:

x + 304 = 1047

x = 743

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Given statement solution is :- Mathematical models are extremely valuable tools in various fields, including chemistry, biology, and physics. They offer several advantages: Simplification and abstraction, Prediction and simulation, Cost and time efficiency, Insight and understanding.

Mathematical models are extremely valuable tools in various fields, including chemistry, biology, and physics. They offer several advantages:

Simplification and abstraction: Mathematical models allow complex systems or processes to be represented using simplified mathematical equations or algorithms. This simplification helps in understanding the underlying principles and relationships of the system, making it easier to analyze and predict outcomes.

Prediction and simulation: Models enable scientists to make predictions about the behavior of a system under different conditions. They can simulate scenarios that are difficult or impossible to observe in the real world, allowing researchers to explore various hypotheses and make informed decisions.

Cost and time efficiency: Models can be used to explore different scenarios and test hypotheses in a relatively quick and cost-effective manner compared to conducting real-world experiments. They can help guide experimental design by providing insights into the most relevant variables and parameters.

Insight and understanding: Mathematical models often reveal underlying patterns and relationships that may not be immediately apparent from experimental data alone. They provide a framework for organizing and interpreting data, leading to a deeper understanding of the system being studied.

However, mathematical models also have limitations and potential disadvantages:

Simplifying assumptions: Models are based on assumptions and simplifications, which may not fully capture the complexity of the real-world system. If these assumptions are incorrect or oversimplified, the model's predictions may be inaccurate or misleading.

Uncertainty and error: Models are subject to uncertainties and errors stemming from the inherent variability of the system, limitations in data availability or quality, and simplifying assumptions. It is crucial to assess and communicate the uncertainties associated with model predictions.

Validation and verification: Models need to be validated and verified against experimental data to ensure their accuracy and reliability. This process requires rigorous testing and comparison to real-world observations, which can be challenging and time-consuming.

Mathematical models are closely linked to the fields of chemistry, biology, and physics, providing valuable insights and predictions in these disciplines. Here are some examples:

Chemistry: Mathematical models are used to study chemical reactions, reaction kinetics, and molecular dynamics. One example is the use of rate equations to model the kinetics of a chemical reaction, such as the reaction between reactants A and B to form product C.

Biology: Mathematical models play a crucial role in understanding biological systems, such as population dynamics, gene regulation, and the spread of infectious diseases. For instance, epidemiological models like the SIR (Susceptible-Infectious-Recovered) model are used to simulate and predict the spread of diseases within a population.

Physics: Mathematical models are fundamental in physics to describe physical phenomena and predict outcomes. One well-known example is Newton's laws of motion, which can be mathematically modeled to predict the motion of objects under the influence of forces.

Quantum mechanics: Mathematical models, such as Schrödinger's equation, are used to describe the behavior of particles at the quantum level, providing insights into atomic and molecular structures and the behavior of subatomic particles.

Fluid dynamics: Mathematical models, such as the Navier-Stokes equations, are employed to study the behavior of fluids, including airflow, water flow, and weather patterns.

These examples demonstrate the wide range of applications for mathematical models in understanding, predicting, and simulating various phenomena in the fields of chemistry, biology, and physics.

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Answer:

Step-by-step explanation:

To find the value of an investment compounded continuously, we can use the formula:

A = P * e^(rt)

Where:

A is the final amount

P is the principal amount (initial investment)

e is the mathematical constant approximately equal to 2.71828

r is the annual interest rate (as a decimal)

t is the time period in years

In this case, P = $10,000, r = 0.0315 (3.15% expressed as a decimal), and t = 13.

Plugging in the values into the formula, we get:

A = $10,000 * e^(0.0315 * 13)

Calculating the exponential part:

A = $10,000 * e^(0.4095)

Using a calculator or a math software, we can evaluate e^(0.4095) to get approximately 1.506.

A = $10,000 * 1.506

A ≈ $15,060.

Answer:

[tex]h'(1)=4\sec^2(8)[/tex]

[tex]h''(1)=32\sec^2(8)\tan(8)[/tex]

Step-by-step explanation:

Given the following function.  

[tex]h(x)=\tan(4x+4)[/tex]

Find the following:

[tex]h'(1)= \ ??\\\\h''(1)= \ ??\\\\\\\hrule[/tex]

Taking the first derivative of h(x). We will use the chain rule and the rule for tangent.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{The Chain Rule:}}\\\\\dfrac{d}{dx}[f(g(x))]=f'(g(x)) \cdot g'(x) \end{array}\right}\\\\\\\boxed{\left\begin{array}{ccc}\text{\underline{The Tangent Rule:}}\\\\\dfrac{d}{dx}[\tan(x)]=\sec^2(x) \end{array}\right}[/tex]

[tex]h(x)=\tan(4x+4)\\\\\\\Longrightarrow h'(x)=\sec^2(4x+4) \cdot4\\\\\\\therefore \boxed{h'(x)=4\sec^2(4x+4)}[/tex]

Now plugging in x=1:

[tex]\Longrightarrow h'(1)=4\sec^2(4(1)+4)\\\\\\\Longrightarrow \boxed{\boxed{h'(1)=4\sec^2(8)}}[/tex]

Taking the second derivative of h(x). Using the chain rule again and the secant rule.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{The Secant Rule:}}\\\\\dfrac{d}{dx}[\sec(x)]=\sec(x) \tan(x) \end{array}\right}[/tex]

[tex]h'(x)=4\sec^2(4x+4)\\\\\\\Longrightarrow h''(x)=(4\cdot 2)\sec(4x+4) \cdot \sec(4x+4)\tan(4x+4) \cdot 4\\\\\\\therefore \boxed{h''(x)=32\sec^2(4x+4)\tan(4x+4)}[/tex]

Now plugging in x=1:

[tex]\Longrightarrow h''(1)=32\sec^2(4(1)+4)\tan(4(1)+4)\\\\\\\therefore \boxed{\boxed{ h''(1)=32\sec^2(8)\tan(8)}}[/tex]

Thus, the problem is solved.