Diagram A shows a negatively charged conducting rod placed near a light polystyrene ball that is suspended from the ceiling by an insulating thread .Diagram B shows what happens when the ball touches the rod. Explain why the ball is displaced vertically​

The forces would be:  Force 1 is 1.875 N and Force 2 is 1.5 N.

Since the object is stationary, the net force acting on it must be zero. We can use the principle of moments to find the magnitude of forces 1 and 2.

Taking moments about the left end of the object, we have:

Force 1 x 8 m = Force 2 x 2 m + Force 3 x 4 m

Since Force 3 is given as 3 N, we can substitute that in and solve for Force 1 and Force 2:

Force 1 x 8 m = Force 2 x 2 m + 3 N x 4 m

Force 1 = (Force 2/2) + 12/8 N

Substituting this expression for Force 1 into the equation above:

(Force 2/2 + 12/8 N) x 8 m = Force 2 x 2 m + 3 N x 4 m

Simplifying and solving for Force 2:

4 Force 2 + 3 N x 2 = 8 Force 2 + 12 N

4 Force 2 = 6 N

Force 2 = 1.5 N

Substituting this value of Force 2 back into the equation for Force 1:

Force 1 = (1.5 N / 2) + 12/8 N = 1.875 N

Therefore, Force 1 is 1.875 N and Force 2 is 1.5 N.

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The amount of force needed to lift the sunken treasure chest is  833  N.

The amount of force needed to lift the sunken treasure chest is calculated by applying Newton's second law of motion.

F = mg

where;

The amount of force needed to lift the sunken treasure chest is calculated as;

F = 85 kg x 9.8 m/s²

F = 833  N

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The strength of the electric field (E) at the position indicated by the dot can be obtained with the formula: E = F/q where;

F_ = Force exerted per unit and

q = Positive electric charge at that point.

What is meant by  Electric Field?

Electric field is described as an electric property associated with each point in space when charge is present in any form.

The strength of an electric field, E refers to the force exerted per unit positive charge. It is indicated by the formula: E = F/q. Its SI unit is Newton per Coulomb or Volts per Meter (V/M).

Keep in mind that where the lines are near together, the electric field is highest, and where the lines are far apart, it is weakest.

Although the entire question is not given, the formula above can be applied to determine the solution.

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where F is the force on the wire, I is the current, L is the length of the wire, and B is the magnetic field.

In this case, we have:

Using the right-hand rule, we know that the direction of the force is downward. So, we can write the vector equation for the force as:

Here, the negative sign indicates that the force is directed downward, which is consistent with our use of the right-hand rule. Therefore, the magnitude of the force acting on the wire is 16 N. So, the correct answer is A. 16 N.

The fossil record suggests that multicellular life evolved before complex single-celled life on Earth.

What does the fossil record suggest about the evolution of life on Earth?

The statement that suggests what the fossil record indicates about evolution on Earth is "Multicellular life evolved before complex single-celled life." The fossil record provides evidence that early life forms were single-celled, and over time, some of these organisms evolved into multicellular organisms.

This is supported by the appearance of fossils of multicellular organisms that are older than those of complex single-celled organisms. The other statements are not supported by the fossil record; humans have not existed on Earth for very long, life likely began in the oceans, and early life forms were single-celled.

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The time taken for the displacement is 10 s.

Initial position, X₁ = 2 m

Final position, X₂ = 3m

Therefore, the displacement,

ΔX = X₂ - X₁

ΔX = 1m

The time taken for this displacement,

Δt = 30 - 20

Δt = 10 s

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Your question was incomplete, but most probably your question will be: How long did it take the object to get from the position x = 2.0 m to the position x = 3.0 m? Express your answer(s) using two significant figures. If there is more than one answer enter your answers in ascending order separated by commas.

Option A is correct.

Equivalent Resultant force = 5850 N down acting 4.85 m to the right of p.

Equivalent Resultant Force is a single force that can replace a system of forces acting on a body or structure without altering the motion or equilibrium of the body or structure. The equivalent resultant force has the same effect as the original system of forces in terms of their combined magnitude, direction, and point of application.

In other words, the equivalent resultant force is the net force acting on a body or structure, which has the same effect as the original system of forces.

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According to the information, the new angular velocity is approximately 19.56 rev/min.

The moment of inertia of the merry-go-round with children is given by:

I = MR^2

where M is the total mass of the merry-go-round and children, and R is the radius.

I = (110 kg)(2.23 m)^2

I = 552.83 kg·m^2

The initial angular momentum of the system is given by:

L1 = Iω1

where ω1 is the initial angular velocity.

L1 = (552.83 kg·m^2)(2π(14.8 rev/min)/60)

L1 = 563.9 kg·m^2/s

When the child moves to the center of the merry-go-round, the moment of inertia of the system changes to:

I' = M'R^2

where M' is the new total mass of the merry-go-round and children.

M' = M - m

where m is the mass of the child who moved to the center.

M' = (110 kg) - (26.5 kg)

M' = 83.5 kg

I' = (83.5 kg)(2.23 m)^2

I' = 417.48 kg·m^2

The final angular momentum of the system is given by:

L2 = I'ω2

where ω2 is the new angular velocity.

Since angular momentum is conserved, we can set L1 equal to L2 and solve for ω2:

L1 = L2

Iω1 = I'ω2

(552.83 kg·m^2)(2π(14.8 rev/min)/60) = (417.48 kg·m^2)ω2

ω2 = (552.83/417.48) (2π(14.8 rev/min)/60)

ω2 = 19.56 rev/min

Therefore, the new angular velocity is approximately 19.56 rev/min.

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1. Identify all nodes.

2. Choose a reference node. Identify it with reference (ground) symbol.

3. Assign voltage variables to the other nodes (these are node voltages.)

4. Write a KCL equation for each node (sum the currents leaving the node and set equal to zero).

5. Solve the system of equations from step 4.

The fundamental frequency of the string is 120.4Hz (rounded to 1 decimal place)

The formula for the Fundamental Frequency is given as:

f = 1/2 * L * [tex]\sqrt{T/n}[/tex]

where

  L is length of the string

  T is the tension in the string

  n is the linear density of the string

  f is the fundamental frequency of the string

Given the following,

n = 0.23g/cm = 0.23kg/m

L = 89cm = 0.89m

T = 268N

therefore,

f = 1/2 * 0.89 * [tex]\sqrt{268/0.23}[/tex]

f = 120.4 Hz

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the fundamental frequency of the string is  estimated at 102.7 Hz.

The fundamental frequency, often referred to simply as the fundamental, is described as  as the lowest frequency of a periodic waveform.

The fundamental frequency of a string fixed at both ends is shown as :

f = (1/2L) x  √(T/μ)

where

 L is length of the string

 T is the tension in the string

 n is the linear density of the string

 f is the fundamental frequency of the string

Substituting the given values, we have:

frequency  = (1/2 * 0.89 m)  X √(268 N / (0.023 kg/m))

frequency  = 102.7 Hz

In conclusion, the fundamental frequency of the string is 102.7 Hz.

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The net force on q₁ is zero, which implies  that q₁ is in equilibrium and not moving.

The electric force between two charges is given by Coulomb's law as shown :

F= k * (q₁ * q₂) / r²

where F= force,

k = Coulomb's constant (9.0 x 10^9 N*m²/C²),

q₁ and q₂ a=  the charges of the two particles, a

r = e distance between them.

F₁₂ = (9.0 x 10^9 N*m²/C²) * (-2.35 x 10^-6 C) * (-2.35 x 10^-6 C) / (0.100 m)²

= 9.0 N

the force that q₃ exerts on q₁ is :

F₁₃ = (9.0 x 10^9 N*m²/C²) * (-2.35 x 10^-6 C) * (-2.35 x 10^-6 C) / (0.100 m)²

= 9.0 N (to the left)

We now determine the net force on q₁, we add the forces together:

F_net = F₁₂ + F₁₃

= 9.0 N (to the right) + (-9.0 N) (to the left)

= 0 N

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Answer: 93 Ohm

Explanation: The equivalent resistance of three resistors in series can be found by adding up the individual resistances.

R_total = R1 + R2 + R3

R_total = 32 Ohm + 51 Ohm + 10 Ohm

R_total = 93 Ohm

Therefore, the equivalent resistance of the three resistors in series is 93 Ohm.

The remaining battery capacity would be 76%, which is still above the 25% limit on discharge depth.

If the electric bicycle can go 100 miles on a full charge, and the owner wants to limit the discharge depth to 25%, then they can only use up to 25 miles of the battery's capacity before needing to recharge.

Since the owner's commute is 12 miles round trip, they can make one round trip without depleting the battery more than 25% of its capacity.

Therefore, the owner can make 2 round trips (2 x 12 = 24 miles) before needing to recharge, but they will still have some battery capacity left.

The remaining battery capacity would be (100 - 24)/100 x 100% = 76%, which is still above the 25% limit on discharge depth. So the owner could make a few more round trips before needing to fully recharge the battery.

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Answer: 4.8N

Explanation: Using Force (N) = Mass (Kg) * Acceleration (m/s2)
We know the Mass, but its in grams. convert it into kg.
40g / 1000 = 0.04 KG

Then we need to find the acceleration. We can find it by the given values
acceleration = Delta S / Delta T. Or Change in speed / Change in time
So, 60m\s / 0.5s = 120m\s2

now we can use f=ma
X= 0.04 * 120
X= 4.8N

The Correct answer is C -v

Below is the saturation of each solution as listed on the table;

1. unsaturated

2. supersaturated.

3. supersaturated

4. supersaturated

5. unsaturated

6. supersaturated.

To determine if each solution is saturated, unsaturated, or supersaturated, we need to know the solubility of each substance at 25°C. Here are the approximate solubilities for the substances at 25°C:

Table salt (NaCl): 357 g/L

Sugar (C12H22O11): 2000 g/L (2 g/mL)

Baking soda (NaHCO3): 69 g/L (0.069 g/mL

1. Table salt (NaCl), 38 grams in 200 mL of water:

Solubility at 25°C: 357 g/L * 0.2 L = 71.4 g (maximum amount that can dissolve in 200 mL)

Since 38 g < 71.4 g, this solution is unsaturated.

2. Sugar (C12H22O11), 500 grams in 200 mL of water:

Solubility at 25°C: 2000 g/L * 0.2 L = 400 g (maximum amount that can dissolve in 200 mL)

Since 500 g > 400 g, this solution is supersaturated.

3. Baking soda (NaHCO3), 20 grams in 200 mL of water:

Solubility at 25°C: 69 g/L * 0.2 L = 13.8 g (maximum amount that can dissolve in 200 mL)

Since 20 g > 13.8 g, this solution is supersaturated.

4. Table salt (NaCl), 100 grams in 200 mL of water:

Solubility at 25°C: 357 g/L * 0.2 L = 71.4 g (maximum amount that can dissolve in 200 mL)

Since 100 g > 71.4 g, this solution is supersaturated.

5. Sugar (C12H22O11), 210 grams in 200 mL of water:

Solubility at 25°C: 2000 g/L * 0.2 L = 400 g (maximum amount that can dissolve in 200 mL)

Since 210 g < 400 g, this solution is unsaturated.

6. Baking soda (NaHCO3), 25 grams in 200 mL of water:

Solubility at 25°C: 69 g/L * 0.2 L = 13.8 g (maximum amount that can dissolve in 200 mL)

Since 25 g > 13.8 g, this solution is supersaturated.

The above answers are in reference to the question below;

Substance          Amount of substance in 200 mL of water at 25°C      Saturated, unsaturated, or supersaturated?

Table salt (NaCl)                              38 grams

Sugar (C12H22O11)                        500 grams

Baking soda (NaHCO3)                   20 grams

Table salt (NaCl)                              100 grams

Sugar (C12H22O11)                        210 grams

Baking soda (NaHCO3)                      25 grams

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Cooking is an activity that can easily eliminate toxins produced by pathogens. When food is cooked at a high temperature, it can kill the pathogens that produce toxins and denature the toxins themselves, making them inactive and safe to consume. However, it's important to note that not all toxins produced by pathogens can be eliminated by cooking, and some toxins may remain in the food even after it has been cooked. It's important to practice proper food safety measures, such as washing hands and cooking food thoroughly, to prevent foodborne illness.

Answer:

t = 1.414 seconds

Explanation:

[tex]y_{f} = y_{i} + v_{i}*t +0.5*a*t^2\\y_{f} = y_{i} + 0.5*a*t^2\\(y_{f} - y_{i}) = 0.5*a*t^2\\t = \sqrt{\frac{2*(y_{f}-y_{i})}{a} } \\t = 1.414 seconds[/tex]

a plate with bread, grapes, a hard-boiled egg, cheese, cucumber slices, and carrot slices food groups are represented in this snack

According according to the Demographic Reference Intake report for macronutrients, a sedentary adult should consume 0.36 grammes of animal protein for every pound of weight of their body, or 0.8 grammes of proteins per kilogramme. As a result, the average inactive guy should take around 56 grammes of protein per day, whereas the average sedentary female should consume approximately 46 grammes.

A person can consume too much protein; if it accounts for more than 35% of their daily calories, they may suffer unfavourable repercussions.

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For a standing wave in a tube open at each end, the open ends of the tube are points of maximum displacement and minimum pressure. At these points, the air molecules in the tube are free to move back and forth, causing the pressure to vary periodically between maximum and minimum values. The points of maximum displacement are called antinodes, while the points of minimum displacement are called nodes. In the case of a tube open at each end, the open ends act as antinodes, since the air molecules at these points are free to move.

The mass of the produced isotope 3He is 7.015455244 amu.

Isomeric transitions refer to the nuclear decay processes in which an isomer, which is an excited state of a nucleus, undergoes a transition to a lower-energy state by emitting a gamma ray (γ) photon or undergoing a beta decay (β+) process. In the case of isotopes 4Be and 3Li, let's examine the possibilities of isomeric transitions, specifically β+ decay, between them.

Isotope 4Be has an atomic mass of 7.016929 amu, and it decays by β+ emission to a lower-energy state, resulting in the production of an isotope of boron (B), which is denoted as 4Be* → 5B + β+ + νe, where νe represents an electron neutrino.

The mass of the produced isotope 5B can be calculated as follows:

Mass of 4Be* = 7.016929 amu

Mass of β+ particle = 0.000548756 amu (mass of positron or β+ particle)

Mass of νe = 0.0000000000000000010 amu (mass of electron neutrino)

Mass of 5B = Mass of 4Be* - Mass of β+ particle - Mass of νe

= 7.016929 amu - 0.000548756 amu - 0.0000000000000000010 amu

= 7.016380244 amu

So, the mass of the produced isotope 5B is 7.016380244 amu.

On the other hand, isotope 3Li has an atomic mass of 7.016004 amu, and it can undergo β+ decay to a lower-energy state, resulting in the production of an isotope of helium (He), which is denoted as 3Li → 3He + β+ + νe.

The mass of the produced isotope 3He can be calculated as follows:

Mass of 3Li = 7.016004 amu

Mass of β+ particle = 0.000548756 amu (mass of positron or β+ particle)

Mass of νe = 0.0000000000000000010 amu (mass of electron neutrino)

Mass of 3He = Mass of 3Li - Mass of β+ particle - Mass of νe

= 7.016004 amu - 0.000548756 amu - 0.0000000000000000010 amu

= 7.015455244 amu

So, the mass of the produced isotope 3He is 7.015455244 amu.

Comparing the masses of the produced isotopes, we can see that the isomeric transition from 4Be to 5B results in a change in mass by 7.016380244 - 7.016929 = -0.000548756 amu, while the β+ decay from 3Li to 3He results in a change in mass by 7.015455244 - 7.016004 = -0.000548756 amu.

Thus, the mass change is the same for both isomeric transitions.

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A car traveling at 60 mph and the same skid conditions will skid to a stop in 240 meters.

What is the distance a car traveling at 60 mph and the same skid conditions will skid to a stop?

The distance a car skids to come to a stop is directly proportional to the square of its speed. This means that if the speed is doubled, the distance it will take to stop will be quadrupled.

Let's use this formula to find the distance the car will skid to come to a stop at 60 mph:

(d1 / d2) = (v1^2 / v2^2)

where:

d1 = distance the car skids at 30 mph = 60 meters

v1 = speed of the car at 30 mph = 30 mph

v2 = speed of the car at 60 mph = 60 mph

d2 = distance the car skids at 60 mph (what we want to find)

Plugging in the values, we get:

(d1 / d2) = (v1^2 / v2^2)

60 / d2 = (30^2 / 60^2)

60 / d2 = 1 / 4

d2 = 4 x 60

d2 = 240 meters

Therefore, the car traveling at 60 mph will skid to a stop in 240 meters.

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cardiovascular exercise - the use of the large muscles in the body to perform a continuous activity for at least ten minutes.

ATP - a type of energy required by the body for muscle movement.

oxygen consumption - the amount of oxygen the muscles in the body need in order to produce energy for movement.

steady state - the condition when the muscles of the body are receiving the amount of oxygen they need in order to produce the amount of energy necessary for movement.

oxygen deficit - a state when the muscles are not getting the amount of oxygen they need in order to produce the amount of energy necessary for movement.

EPOC - the extra oxygen a person gets while still breathing hard after stopping exercise.

To summarize, when a person completes physical activity, their body continues consuming high levels of oxygen even after finishing exercising.

The additional amount of required oxygen beyond what is needed in a resting state is termed EPOC (excess post-exercise oxygen consumption).

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Answer:

just calm down an breath your LOVED without stress

Explanation:

Add all of the velocities together....then the rock will be moving in the OPPOSITE direction according to conservation of momentum

(15 + -12 + 1.2) m/s i = -1.8 m/s i

(5 + 8 + -18 ) m/s j = -5 m/s j      These are the resultant force components  on 210 kg of deer meat

-1.8  (210) i   -  5 (210) j    = 200  x  i    +   200 y j  m/s

results in  rock velocities:     1.89 i  m/s      + 5.25  j m/s  

Please tell me if this is incorrect and I will re-evaluate ......

The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/[tex]s^{2}[/tex]), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/[tex]s^{2}[/tex]) x (9 m)

GPE = 15,998.95 J (joules)

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The bullet is in the barrel for 4.5610^-5 s, experiences a force of 16713 N, an impulse of 0.763 Ns, and has a momentum of mv = 34.5 kg*m/s as it leaves the barrel.

What are the time, force, impulse, and momentum of a bullet fired from a gun with given mass, barrel length, and muzzle velocity

(a) The time the bullet spends in the barrel can be found using the equation for distance traveled by an object with constant acceleration, where the initial velocity is zero and the distance is the barrel length:

d = 1/2 at^2

Solving for time t, we get:

t = √(2d/a)

where a is the acceleration of the bullet as it is propelled out of the barrel. To find the acceleration, we can use the equation for force:

F = ma

where F is the force exerted on the bullet, m is the mass of the bullet, and a is its acceleration. Since the bullet is in the barrel, the force is the force of the expanding gases from the gunpowder. We can find this force using the ideal gas law:

PV = nRT

where P is the pressure of the gases, V is the volume of the barrel, n is the number of moles of gas produced by the gunpowder, R is the ideal gas constant, and T is the temperature of the gases. Solving for P, we get:

P = nRT/V

We can assume that the volume of the barrel remains constant during the firing of the bullet, so we can write:

P = k nT

where k is a constant that depends on the volume of the barrel and the gas constant R. Since the bullet is fired in a fraction of a second, we can assume that the temperature of the gases remains constant, so we have:

P = k n

The force exerted on the bullet is then:

F = PA = k nA

where A is the cross-sectional area of the barrel.

a = F/m = k nA/m = k P A/m = (kRT/V)(πr^2)/m

where r is the radius of the barrel. we get:

a = (k)(8.31 J/molK)(293 K)/(0.00066 m^3)(π(0.0033 m)^2)/(0.075 kg) = 2.4110^7 m/s^2

Plugging this into the equation for time, we get:

t = √(2d/a) = √(20.66 m/2.4110^7 m/s^2) = 4.56*10^-5 s

So the bullet is in the barrel for 4.56*10^-5 s.

(b) The force on the bullet while it is in the barrel is the force exerted by the expanding gases from the gunpowder, which we found to be:

F = k nA

Substituting in the given values, we get:

F = (k)(8.31 J/mol*K)(293 K)/(0.00066 m^3)(π(0.0033 m)^2) = 16713 N

So the force on the bullet while it is in the barrel is 16713 N.

(c) The impulse exerted on the bullet while it is in the barrel is the product of the force and the time:

J = FΔt = (16713 N)(4.5610^-5 s) = 0.763 Ns

So the impulse exerted on the bullet while it is in the barrel is 0.763 N*s.

(d) The momentum of the bullet as it leaves the barrel can be found using the equation:

p = mv

where p is the momentum, m is the mass of the bullet, and v is its velocity. We can find the velocity using conservation of energy, since the gun and bullet

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The tension in the cord is approximately 14.6 N.

Tension is a force that is transmitted through a stretched object, such as a rope, string, or cord. In the case of a phone cord, tension refers to the force that is applied to the cord to keep it taut and stretched. When a transverse wave pulse travels along the cord, it creates variations in tension that propagate through the cord. The magnitude of the tension in the cord is directly related to the speed of the wave and the linear density of the cord. A higher tension will result in a faster wave speed, while a lower tension will result in a slower wave speed.

Here in the Question,

The speed of the wave on the cord can be calculated from the distance it travels and the time it takes:

distance = 4 x 3.08 m = 12.32 m

time = 0.903 s

speed = distance / time = 12.32 m / 0.903 s ≈ 13.65 m/s

The speed of the wave is related to the tension in the cord and its linear density (mass per unit length) by the following equation:

v = √(T/μ)

where v is the speed of the wave, T is the tension in the cord, and μ is the linear density of the cord (mass per unit length).

We can rearrange this equation to solve for T:

T = μv^2

The linear density of the cord can be calculated from its mass and length:

μ = m / L = 0.244 kg / 3.08 m ≈ 0.0792 kg/m

Substituting the values we have into the equation for T:

T = μv^2 = (0.0792 kg/m)(13.65 m/s)^2 ≈ 14.6 N

Therefore, the tension in the cord is approximately 14.6 N.

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(a) The longest possible wavelength for the interfering sound waves that can form a standing wave is 2.4 m

b. , the frequency associated with the standing wave in this pipe is 142.9 Hz

a.) The longest possible wavelength for the interfering sound waves that can form a standing wave in a pipe closed at one end and open at the other is four times the length of the pipe, or 4L.

L = 0.6 m, so the longest possible wavelength is:

λ_max = 4L = 4 * 0.6 m = 2.4 m

(b)

the frequency associated with the standing wave in this pipe is calculated as

v = fλ

v = 343 m/s

λ = 2.4 m

f = v/λ = 343 m/s / 2.4 m = 142.9 Hz

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