Answer:
15 cm
Explanation:
Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:
F = Kq₁q₂ / d²
Perbanyak silang
Fd² = Kq₁q₂
Menjaga Kq₁q₂ konstan, kita memiliki:
F₁d₁² = F₂d₂²
Dengan rumus di atas maka diperoleh jarak sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
F₁d₁² = F₂d₂²
225 × 5² = 25 × d₂²
225 × 25 = 25 × d₂²
5625 = 25 × d₂²
Bagilah kedua sisinya dengan 25
d₂² = 5625/25
d₂² = 225
Hitung akar kuadrat dari kedua sisi
d₂ = √225
d₂ = 15 cm
Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N
_____ increase your risk
Answer: All forms of distraction.
Find the force of gravity acting between at 1.7x10^30 kg planet with
5.5x10^20 kg moon that is 2x10^5 m away.
A) 4.0x10^30 N
B) 5.0x10^30 N
C) 4.3x10^30 N
D) 9.8x10^30 N
None of these answers are correct...
Applying the law of universal gravitation, we have
F = G m₁ m₂ / R²
where
G = 6.67 × 10⁻¹¹ N•m²/kg²
m₁ = 1.7 × 10³⁰ kg
m₂ = 5.5 × 10²⁰ kg
R = 2 × 10⁵ m
→ F = (6.67 × 1.7 × 5.5)/2² × 10⁻¹¹⁺³⁰⁺²⁰⁻¹⁰ N
→ F ≈ 15.59 × 10²⁹ N
→ F ≈ 1.6 × 10³⁰ N
An airplane flies at 40 m/s at an altitude of 50 meters. The pilot drops a heavy package which falls to the ground. Where, approximately, does the package land relative to the plane's new position
Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =?
Next, we shall determine the time taken for the package to get to the ground.
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9
t² = 50 / 4.9
t² = 10.2
Take the square root of both side
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =?
s = ut
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane
Photons with the highest energy have the ____
A. strongest positive charge
B. longest period
C. highest amplitude
D. shortest wavelength
Answer:
D. shortest wavelength
Explanation:
Photons with the highest energy have the shortest wavelength. The shorter the wavelength, the higher the energy of a photon.
A photon is a quantity that transmits electromagnetic energy from one place to the other.
Gamma rays have photons that transmits the highest amount of energy. The rays have the shortest wavelength and highest frequency of all electromagnetic radiations.Energy, wavelength and frequency of a photon are connected using the expression:
E = h f = [tex]\frac{hc}{wavelength}[/tex]
E is the energy
h is the Planck's constant
f is the frequency.
a crowbar 2 metres long is used to lift a rock weighing 800 newtons .If the fulcrum is 0.25 metre,from where the bar touches the rock, how much effort must be applied to move the rock
Answer:
??
Explanation:
A communication satellite is in a circular path orbit around Earth. If the speed of the satellite is constant, the net force acting on the satellite ____.
Answer:
is changing in direction, but constant in magnitude
Explanation:
This question is a bit tricky since the velocity of the satellite is changing, but the speed is constant.
Speed is simply a measure of how fast you are going. It doesn't matter where you're going, just how quickly.
Velocity, on the other hand, does care about which direction you're going. For example, it could be then when you travel right, your velocity is positive, and when you travel left, your velocity is negative. This is the similar for a 2D shape like a circular orbit
Since we know velocity is changing, there must be acceleration which changes that velocity (since acceleration is the change in velocity: going from 0 to 60 mph, for example)
Thus, with a non-zero net acceleration, we know that there must be a force that is changing in direction, but constant in magnitude (since the orbit is a circle, and always attracted to the center of the Earth at equal distance).
Radioisotopes often emit one or more types of radiation, including alpha particles, beta particles, and gamma rays. The distance the radiation travels through matter before being absorbed increases in order from alpha to gamma. Which statement describes the best radioisotope that can be used for radioisotope imaging and for radionuclide therapy?
It emits only gamma rays.
It emits only alpha particles.
It emits alpha and beta particles.
It emits beta particles and gamma rays.
Answer:
The most correct option is the last option
Explanation:
During radioisotope/nuclear imaging in diagnosis, the radioisotope must emit gamma rays from within the body. However, in the case of radionuclide therapy, most radionuclides emit beta particles while some others also emit gamma rays.
Answer:
D
Explanation:
The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated
F = m × a
300N = 100kg × a
a = 300 : 100
a = 3ms-²
A bit of explanation :F = Force (N)
m = mass (kg)
a = acceleration (ms-², m/s²)
A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?
Answer:
acceleration = 0.2 m/s/s
Explanation:
initial velocity u = 14
final velocity v = 20
time = 30
acceleration = ?
v = u + at
20 = 14 + 30a
30a = 6
a = 0.2 m/s/s
Answer:
For the aceleration we have:
V = Vi + a * t
Being:
V = 20 m/s
Vi = 14 m/s
a = ?
t = 30 s
Then, lets replace acording the formula:
20 m/s = 14 m/s + a * 30 s
Clear "a":
a = (20 m/s - 14 m/s) / 30 s
a = (6 m/s) / 30 s
a = 0,2 m/s²
The aceleration of the car is 0,2 meters per second squared.
Why is it difficult to use the law of conservation of energy to calculate the
effects of a collision?
Answer:
B
Explanation:
In a collision some of the kinetic energy of the object convert into thermal energy and sound. It's not so easy to measure thermal and sound energy. That's why it's difficult to use law of conservation of energy.
Alert: Energy is always conserved.
A string attached to an airborne balloon was maintained at an angle of 54 degrees with the ground. If 2.3 m of string was reeled in to return the balloon back to the ground, what was the horizontal and vertical displacements
Answer:
dₓ = 1.35 m
dy = 1.86 m
Explanation:
In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:
[tex]d_{x} = d\ Cos\ \theta[/tex]
where,
dₓ = horizontal component of displacement = ?
d = resultant displacement = 2.3 m
θ = angle between displacement and ground = 54°
Therefore,
[tex]d_{x} = (2.3\ m)\ Cos\ 54^0[/tex]
dₓ = 1.35 m
For vertical component of displacement:
[tex]d_{y} = d\ Sin\ \theta\\d_{y} = (2.3\ m)\ Sin\ 54^0[/tex]
dy = 1.86 m
SAT QUESTION // A capacitor is connected to a variable power supply with potential V. Determine the effect on the charge stored on the capacitor if the potential of the power supply is cut in half.
Answer:
decrease by a factor of 2
say something random cuz i already answered my own question
Answer:
The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp is explained below in details.
Explanation:
The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.
So, I think now you got your answer which is absolutely correct and it will help you.
Answer:
hello my good friend
Explanation:
A cyclist accelerates from a velocity of 10 miles/hour east until reaching a velocity of 20 miles/hour east in 5 seconds. What was the cyclist's acceleration?
Answer:
[tex]a = 0.894\ m/s^2[/tex]
Explanation:
Motion with Constant Acceleration
A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is
[tex]v_f=v_o+at[/tex]
Where vo is the initial speed, a is the acceleration, and t is the time.
The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.
Both speeds are given in miles/hour and we must convert it to m/s:
1 mile/hour = 0.44704 m/s
10 mile/hour = 4.47 m/s
20 mile/hour = 8.94 m/s
The acceleration is calculated by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
[tex]\displaystyle a=\frac{8.94-4.47}{5}[/tex]
[tex]a = 0.894\ m/s^2[/tex]
20 n west and 60 n east
BLANK 1: What is the net force acting on the object
BLANK 2: Which direction will the object move
Answer:
a) [tex] F_{T} = 40 N [/tex]
b) The object will move in the east direction
Explanation:
a) The net force is given by the vector sum of the given forces:
[tex] F_{T} = F_{1} + F_{2} [/tex]
Where:
F₁ = the west force = 20 N
F₂ = the est force = 60 N
Taking the east direction as the positive direction we have:
[tex] F_{T} = -20 N + 60 N = 40 N [/tex]
Hence, the net force is 40 N.
b) Since the east force is greater than the west force, the object will move to the east.
I hope it helps you!
A sea turtle must crawl up a beach to lay eggs. Ignoring friction, what work must a 140-kg turtle do in lifting herself 2.5 m above the level of the sea?
Answer:
3500joules of work
Explanation:
Work done = Force×,distance
Given
Focrce= mass ,× acceleration = 140×10 = 1400N
Distance moved = 2.5m
Workdone = 1400×2.5
Work done = 140×25
Workdone = 3500Joules
When riding on a bus, you can tell you are moving by
observing the motion of objects like other moving vehicles
outside the window.
True or False?
Answer:
True
Explanation:
two points A=(+16) and B=(-4) At electric potential respectively find:
a)which points is at higher potential?
b)what is the pontial difference b/w the two points?
c)the work done in moving acharge of 5C from A to B?
Answer:
a. Point A
b. 20 V
c. 100 J
Explanation:
a. Point A is at a higher potential because there is a positive sign in front of its magnitude. Since it is a positive integral value, and has a higher magnitude than point B which is at -4, point A is thus at a higher potential than point B.
b. The potential difference between the two points ΔV = A - B
= +16 V - (-4 V)
= +16 V + 4 V
= + 20 V
c. The work done, W in moving a charge Q across a potential difference ΔV is W = QΔV
So, since Q = 5 C and ΔV = + 20 V
W = QΔV
= 5 C × (+ 20 V)
= 100 J
A thermal cap used in certain apparatus consist of silica rod which fits tightly inside an aluminium tube whose internal diameter is 8mm at 0 degree c … elcius.Calculate what change in temperature to produce channel whose cross section equal to 1 mm
Answer:
change in temperature is a decrease by 268.734 K
Explanation:
We are given;
Temperature: T1 = 0°C = 273 K
Internal diameter; d1 = 8mm
Final diameter; d2 = 1 mm
To solve this, we will use Charles law formula since pressure is constant.
Thus;
V1/T1 = V2/T2
Where T2 is the final temperature.
Now, V1 and V2 are volume
Volume is given by: V = area x height
We are told the cross section is equal except for the diameter.
Thus;
V1 = A1 × h
V2 = A2 × h
Thus;
(A1 × h)/T1 = (A2 × h)/T2
h will cancel out and making T2 the subject, we have;
T2 = (A2 × T1)/A1
A2 = π(d2)²/4
A1 = π(d1)²/4
Thus;
T2 = [(π(d2)²/4) × T1]/(π(d1)²/4)
π and 4 will cancel out to givw;
T2 = ((d2)²× T1)/(d1)²
T2 = (1² × 273)/8²
T2 = 273/64
T2 = 4.266 K
Thus;
Change in temperature = T2 - T1 = 4.266 - 273 = -268.734 K
Thus, change in temperature is a decrease by 268.734 K
The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.10 106 J of work on the car. The car starts from rest at sea level and has a speed of 24.0 m/s at an altitude of 2.20 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.
We know, Work done by all the forces is equal to change in potential energy :
[tex]W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}[/tex]
Here,
[tex]h_i=0\ m\\\\v_i = 0\ m/s[/tex]
Putting all given values, we get :
[tex]W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J[/tex]
Hence, this is the required solution.
Calculate the gravitational force between a 4.0 x 10^8 kg mass and a 2.8 x 10^5 kg mass separated by a distance of 1.0 x 10^4 m.
Answer:
[tex]F_{g}=7.4704\times10^{-5}[/tex]
Explanation:
Givens: d = 1.0 × [tex]10^{4}[/tex] [tex]m_{1} = 4.0 x 10^{8}[/tex] [tex]m_{2} = 2.8[/tex]×[tex]10^{5}[/tex]
Required: [tex]F_{g}=?[/tex]
Formula: [tex]F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}[/tex] (6.67x10^-11 is the gravitational constant)
[tex]F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}[/tex]
[tex]F_{g}=7.4704\times10^{-5}[/tex]
How much force would be needed to
push a 22 kg box across the floor with
an acceleration of 1.9 m/s^2? Assume
that there is a coefficient of friction of.
17 between the box and the floor.
Help me with this!!!!!!!it’s due in 10 minutes
There would be two forces acting on the box parallel to the floor, with a net force of
∑ F = p - f = m a
where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .
There are also only two forces acting on the box perpendicular to the floor, with net force
∑ F = n - w = 0
where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.
w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :
n = w = m g
n = (22 kg) (9.8 m/s²)
n = 215.6 N
The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that
f = µ n
f = 0.17 (215.6 N)
f = 36.652 N
Now solve for the required pushing force:
p - 36.652 N = (22 kg) (1.9 m/s²)
p ≈ 78 N
Answer:
0
Explanation:
What do atoms of elements in a group have that makes their properties similar? A. the same atomic mass
B. the same number of protons
C. the same number of outer level electrons
D. the same total number of electrons
A long-jumper leaves the ground at an angle of 20.0° above the horizontal and at a speed of 11.0 m/s.How far does he jump in the horizontal direction?(Assume his motion is equivalent to that of a particle.).
a. 12m
b. 7.94m
c. 10m
d. 0.384m
Answer:
The correct option is;
b. 7.94 m
Explanation:
The given parameters of the jump of the long jumper are;
The angle above the horizontal with which the long jumper leaves the ground, θ = 20.0°
The speed with which the long jumper leaves the ground, u = 11.0 m/s
The furthest horizontal distance the long jumper jumps, given that the motion is equivalent to that of a particle, is given by the formula for the range, R, of a projectile motion as follows;
[tex]R = \dfrac{u^2 \times sin \left (2 \cdot \theta \right )}{g}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
u = The initial velocity of the long-jumper = 11.0 m/s
θ = The angle of the direction above the horizontal the long-jumper jumps = 20.0°
Plugging in the values, gives;
[tex]R = \dfrac{(11.0 \ m/s)^2 \times sin \left (2 \times 20.0 ^{\circ} \right )}{9.8} = \dfrac{121 \ m^2/s^2 \times sin \left (40.0 ^{\circ} \right )}{9.8 \ m/s^2} \approx 7.94 \ m[/tex]
How far the long-jumper goes = The range, R, of the projectile motion ≈ 7.94 m.
How does a single fixed pulley, like the one seen here, help you do work?
A) Changes the direction of the force.
B) Increases the amount of applied force.
C) Decreases the amount of applied force.
D) Allows you to pull the rope a shorter distance.
Answer:
the answer will be B
Explanation:
because you are pulling the rope, pullimg applies FORCE. the bucket goes up because you applied FORCE
WILL GIVE BRAINLIEST
Lila is a track and field athlete. She has to complete four laps around the track, which is 400 meters. The race took her 6 minutes to complete. What is her average speed to the first decimal point in m/s?
Answer:
4.44m/s
Explanation:
Given parameters:
Number of laps = 4
Length of track = 400m
Time taken = 6min
Unknown:
Average speed = ?
Solution:
The average speed is the total distance covered divided by the time taken.
It is mathematically expressed as;
Average speed = [tex]\frac{total distance}{time taken}[/tex]
Total distance = number of laps x length of track = 4 x 400 = 1600m
Now convert the time to seconds;
60s = 1 min
6 minutes will be 6 x 60 = 360s
So;
Average speed = [tex]\frac{1600}{360}[/tex] = 4.44m/s
Ramas weight is 40 kg. She is carrying a load of 20 kg up to a height of 20 m. What work does she do? What work does she do?
Answer:
The work done by Ramas is 3920 N.
Explanation:
Given;
mass of the load lifted by Ramas, m = 20 kg
height through which the load is lifted, h = 20 m
The work done by Ramas is equal to gravitational potential due to the height in which the load is lifted.
W = PE = mgh
where;
g is acceleration due to gravity = 9.8 m/s²
W = 20 x 9.8 x 20
W = 3920 N.
Therefore, the work done by Ramas is 3920 N.
Please answer ASAP!!
Which of the following is the best reason to read the laboratory procedure before beginning
any type of experiment?
O So you can perform the experiment quickly.
O So you can ask questions about steps you do not understand.
O So you can answer all the questions at the end of the lab.
O So you can decide when is the best time of day to complete the lab.
Answer:
O So you can ask questions about steps you do not understand.
Explanation:
One of the reasons why it is encouraged that the laboratory procedure must be read at the beginning of any type of experiment is familiarize the student with the experimental procedure. Also, questions that can help make the smooth running of the experiment to proceed can be cleared.
It is to this regard that understanding laboratory procedures is very vital. Students must grasp the details of each steps of the experiment before proceeding with their investigation. Other critical information needed to set up the experiment can also be brought into the lime light.HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
How are ribosomes different from other complex animal cell organelles?
Explanation:
Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing
Patriotism and education are traditional American values. Please select the best answer from the choices provided T F
Answer:
True
Explanation:
It is a true statement that "Patriotism and education are traditional American values."
The United States of AmericaThe United States of America are bound together by certain core values that hold the entire country together. These values are reverberated any time the ideals of the country are discussed.
Two of the key values of the American society are;
PatriotismEducationHence, it is a true statement that "Patriotism and education are traditional American values."
Learn more about patriotism: https://brainly.com/question/779632
