ECONOMIC Q‼️
Which of these is a common concern of an economist ?

A-The distributions of populations and earths resources
B-How people have organized the rules and laws of their societies
C-The cultural habits and social customs of societies
D-How well resources are used by a society

Explanation:

For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

The cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

The given parameters;

The effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;

[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]

The distance traveled by the cyclist at the give speed and acceleration is calculated as;

[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]

Thus, we can conclude that the cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

Learn more here:https://brainly.com/question/14121363

I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that

1. the initial velocity vector is

[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]

which means the ball is thrown with an initial speed of

√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,

and

2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that

[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]

3. At time t, the ball attains a height y and horizontal range x according to

y = (13 m/s) t - g/2 t²

x = (7.5 m/s) t

where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have

(13 m/s) t - g/2 t² = 0

13 m/s - g/2 t = 0

t = 2 (13 m/s)/g = (26 m/s)/g

Plugging this time into the x equation gives a horizontal range of

x = (7.5 m/s) (26 m/s)/g ≈ 20. m

Answer:

The balloon expands in the number of particles per cubic centimeter decreases. This happens because as it expands there is a decrease in the density of area. The Dead Sea is a solution that is so dense that you easily float on it.