Answer:
Leptón
Explanation:
Lepton son partículas elementales de espín de medio entero (espín 1⁄2), y se sabe que no experimentan interacciones fuertes. Los leptones se clasifican en leptones cargados (los leptones similares a los electrones) y leptones neutros (conocidos como neutrinos). Un electrón es un leptón. Los leptones cargados pueden combinarse con otras partículas para formar átomos compuestos de partículas y positronio, mientras que los neutrinos rara vez interactúan con algo, lo que los hace raros de observar.
Dado que la electricidad es el resultado del movimiento o flujo de electrones, la única partícula representativa de esta fuerza es el leptón.
What is the purpose of a buffer?
A. To limit pH changes in solution
B. To force the pH of a solution to change
C. To make a solution form a salt
O D. To neutralize the pH of a solution
Answer:
To limit pJ changes in solution
On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+
Answer:
Acid(BSA) = CH₃COOH
Base (BSB) = H₂O
Conjugate base (CB) = CH₃COO⁻
Conjugate acid (CA) = H₃O⁺
Explanation:
Equation of reaction;
CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺
Hello,
From my understanding of the question, we are required to identify the
1) Acid
2) Base
3) conjugate acid
4) conjugate base in the reaction
Acid (BSA) = CH₃COOH
Base (BSB) = H₂O
CA = conjugate acid = H₃O⁺
CB = conjugate base = CH₃COO⁻
An endothermic reaction will start when the required ΔH energy is received from the environment or solution.
Answer:
true
Explanation:
This sounds like the way an endothermic reaction is going to operate.
It's a very good description of taking on heat which is endothermic.
The statement is true.
A solution of nitrous acid and potassium nitrite acts as a buffer due to reactions that occur within the solution when a strong acid or a strong base is added.
(a) Write the net ionic equation for the reaction that occurs in this buffer to react away any added HCl (aq).
(b) Write the net ionic equation for the reaction that occurs in this buffer to react away any added NaOH (aq).
Answer:
a. NO₂⁻ + H⁺ → HNO₂
b. HNO₂ + OH⁻ → NO₂⁻ + H₂O
Explanation:
A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.
The buffer of the problem is HNO₂/NO₂⁻ where nitrous acid is the weak acid and NO₂⁻ is its conjugate base.
a. When a acid is added to a buffer as the buffer of the problem, the conjugate base will react with the acid, to produce the weak acid, thus:
NO₂⁻ + HCl → HNO₂ + Cl⁻
Ionic equation is:
NO₂⁻ + H⁺ + Cl⁻ → HNO₂ + Cl⁻
In the net ionic equation, you avoid the ions that don't react, that is:
NO₂⁻ + H⁺ → HNO₂b. In the same way, the weak acid will react with the strong acid producing water and the conjugate base, thus:
HNO₂ + NaOH → NO₂⁻ + H₂O + Na⁺
The ionic equation is:
HNO₂ + Na⁺ + OH⁻ → NO₂⁻ + H₂O + Na⁺
And the net ionic equation is:
HNO₂ + OH⁻ → NO₂⁻ + H₂OThe quantum theory of energy levels within atoms was aided by:
study of the sun's light spectrum
emission line spectra of various elements
alpha particles
gamma rays
Answer:
it was based on the studies by emission line spectra of various elements
Explanation:
Answer:
The answer is: emission line spectra of various elements
Explanation:
An oxygen atom has a mass of and a glass of water has a mass of . Use this information to answer the question below. Be sure your answers have the correct number of significant digits. How many moles of oxygen atoms have a mass equal to the mass of a glass of water
Answer:
Number of moles of oxygen atoms having equal mass as glass of water = 3.12 moles
Note: The given question is missing some figures. Here is a complete similar question below.
An oxygen atom has a mass of 2.66*10^-23 g and a glass of water has a mass of 0.050 kg. What is the mass of 1 mole of oxygen atoms? Round your answer to 3 significant digits. How many moles of oxygen atoms have a mass equal to the mass of a glass of water? Round your answer to 2 significant digits.
Explanation:
A mole of a substance contains the Avogadro number of particles = 6.02 * 10²³
Therefore a mole of oxygen atoms contains 6.02*10²³ atoms.
mass of 1 atom of oxygen = 2.66*10⁻²³ g
Mass of 1 mole of oxygen atoms = mass of 1 atom * number of atoms in 1 mole
Mass of 1 mole of oxygen atoms = 2.66*10⁻²³ g * 6.02*10²³ = 16. 01 g
Mass of a glass of water = 0.050 Kg or 50 g
To determine the number of moles of oxygen atoms that have a mass equal to a glass of water i.e. 50 g, the formula below is used;
number of moles = mass/molar mass
mass of oxygen atoms= 50 g, molar mass or mass of one mole of oxygen atoms = 16.01 g
Therefore, number of moles of oxygen atoms = 50 g / 16.01 g = 3.12 moles
If a stronger solution of sodium bicarbonate was used in beaker B, would it require more or less acetic acid to neutralize and why? If a weaker solution of sodium bicarbonate was used i
Answer:
A stronger acid is needed to neutralize the reaction.
Explanation:
Neutral pH solutions are because the acid counteracts the effect of the base, and vice versa.
Both chemical products, both acid and base, reach a pH of 7, which indicates the neutrality of the solution in the reaction, that is, the solution is neither acidic nor basic but NEUTRAL.
The higher the alkalinity of the base, the greater the acidity of the acid will be needed to balance and balance the pH to give neutrality as the final product.
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
Answer:
The total amount of heat needed = 72.2116 kJ
Explanation:
Given that ;
the mass of acetic acid = 120.0 g
The initial temperature [tex]T_1[/tex] = 16.7 °C = (16.7 + 273.15 ) K = 298.85 K
The standard molar mass of acetic acid = 60.052 g/mol
Thus ; we can determine the number of moles of acetic acid;
number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid
number of moles of acetic acid = 120.0 g/ 60.052 g/mol
number of moles of acetic acid = 1.998 moles
For acetic acid:
The standard boiling point [tex]T_2[/tex] = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K
The enthalpy of vaporization of acetic acid [tex]\Delta H_{vap}[/tex] = 23.7 kJ/mol
The heat capacity of acetic acid c = 2.043 J/g.K
The change in temperature Δ T = [tex]T_2 - T_1[/tex]
Δ T = (391.25 - 289.85)K
Δ T = 101.4 K
The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;
q = mcΔT
From our values above;
q = 120 g × 2.043 J/g.K × 101.4 K
q = 24859.2 J
q = 24859 /1000 kJ
q = 24.859 kJ
we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;
Thus;
The needed amount of heat = [tex]\Delta_{vap} *numbers \ of \ moles[/tex]
The needed amount of heat = [tex]23.7 \ kJ/mol * 1.998 \ moles[/tex]
The needed amount of heat = 47.3526 kJ
Hence;
The total amount of heat needed = 24.859 kJ + 47.3526 kJ
The total amount of heat needed = 72.2116 kJ
Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid, HI, and sodium hydrogen carbonate, NaHCO3, are combined. Include physical states.
Answer:
[tex]HI_(_a_q_)~+~NaHCO_3_(_a_q_)~->~NaI_(_a_q_)~+~H_2O_(_l_)~+~CO_2_(_g_)[/tex]
Explanation:
In this case, we will have a neutralization reaction. We have a base ([tex]HI[/tex]) and a base ([tex]NaHCO_3[/tex]). Additionally, we have a strong acid and a strong base, therefore both will be soluble on water, so we will have an aqueous state for these compounds. If we will have a neutralization reaction, we will have as a salt as a product. With this in mind the reaction would be:
[tex]HI_(_a_q_)~+~NaHCO_3_(_a_q_)~->~NaI_(_a_q_)~+~H_2O_(_l_)~+~CO_2_(_g_)[/tex]
All the sodium salts are soluble in water, therefore we will have an aqueous state. Water is a liquid and carbon dioxide is a gas.
I hope it helps!
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 525 mL of a solution that has a concentration of Na ions of 1.10 M
Answer:
31.652g of Na3PO4
Explanation:
We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:
Na3PO4 will dessicate in solution as follow:
Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)
From the balanced equation above,
1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.
Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e
xM Na3PO4 = (1.10 x 1)/3
xM Na3PO4 = 0.367M
Therefore, the molarity of Na3PO4 is 0.367M.
Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:
Molarity of Na3PO4 = 0.367M
Volume = 525mL = 525/1000 = 0.525L
Mole of Na3PO4 =..?
Molarity = mole /Volume
0.367 = mole /0.525
Cross multiply
Mole of Na3PO4 = 0.367 x 0.525
Mole of Na3PO4 = 0.193 mole.
Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:
Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol
Mole of Na3PO4 = 0.193 mole
Mass of Na3PO4 =.?
Mass = mole x molar mass
Mass of Na3PO4 = 0.193 x 164
Mass of Na3PO4 = 31.652g
Therefore, 31.652g of Na3PO4 is needed to prepare the solution.
Before running a titration, you calculate the expected endpoint. However, when performing the experiment, you pass the expected endpoint with no visible color change. What is the most likely problem with the titration set-up
The question is incomplete; the complete question is;
Before running a titration, you calculate the expected endpoint. However, when performing the experiment, you pass the expected endpoint with no visible color change. What is the most likely problem with the titration set- up? Select one
a) There was an air bubble in the burette tip.
b) There is not enough indicator in the analyte.
c) The burette tip is leaking titrant into the analyte.
d) The analyte solution is being stirred too quickly
Answer:
a) There was an air bubble in the burette tip.
Explanation:
Titration involves the determination of the concentration of a solution by measuring the volumes of reactants used in the reaction. The concentration of one of the species must be known while the concentration of the other specie is to be determined by the volumetric analysis.
However, if there are air bubbles at the tip of the burette, this will cause less volume of titrant to be delivered from the burette than expected. Hence, the analyst may think that a certain volume of titrant has been delivered while in reality, a lesser volume was actually delivered due to the air bubbles present. Hence, the analyst may pass the expected endpoint without any colour change because of this problem.
From the available options to the question:
a) There was an air bubble in the burette tip.
b) There is not enough indicator in the analyte.
c) The burette tip is leaking titrant into the analyte.
d) The analyte solution is being stirred too quickly
The most likely problem with the titration setup that could make one to pass the expected endpoint with no visible color change would be if there is not enough indicator in the analyte. The correct option would be B.
A suitable quantity (in drops) of the indicator should be added to the analyte in the conical flask before carrying out a titration. The color of indicators changes quickly near their pKa.
If too few drops of the indicator is used, the color change will be too faint to be obvious and the endpoint will be exceeded. If too many drops of the indicator is used, the final pH of the reaction would be affected and the titer value will be inaccurate.
In this case, the expected endpoint has been exceeded without any color change. The most likely problem would, therefore, be that there is not enough indicator in the analyte.
More on indicators can be found here: https://brainly.com/question/4050911
Enter your answer in the provided box. Before arc welding was developed, a displacement reaction involving aluminum and iron(III) oxide was commonly used to produce molten iron (the thermite process). This reaction was used, for example, to connect sections of iron railroad track. Calculate the mass of molten iron produced when 2.88 kg of aluminum reacts with 24.4 mol of iron(III) oxide.
Answer:
2.7255 kg Fe
Explanation:
Based on the reaction of the thermite process:
2 Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2 Fe(l)
2.88kg of Al (Molar mass: 26.98g/mol) are:
2880g ₓ (1mol / 26.98g) = 106.7 moles Al
For a complete reaction of these moles of Al are necessaries:
106.7 moles Al ₓ ( 1 mol Fe₂O₃ / 2 moles Al) = 53.35 moles Fe₂O₃
As you have just 24.4 moles of Fe₂O₃, Fe₂O₃ is limiting reactant.
1 mole of Fe₂O₃ produce 2 moles of Fe.
Thus, moles of Fe produced are 24.4×2 = 48.8 moles of Fe.
As molar mass of Fe is 55.85g/mol, mass of Fe is:
48.8 moles Fe ×(55.85g / mol) = 2725.5g of Fe =
2.7255 kg FeA protein's secondary structure arises due to interactions between amino acids. Two common secondary structures found in many proteins are alpha helices and beta sheets. Classify the following statements as pertaining to alpha helices or beta sheets.
1. Keep their shape due to hydrogen bonds between adjacent polypeptides chains
2. form long thin structures important for transmembrane proteins
3. flat zig zag like structure
4. a rigid spring like structure around a central axis
Answer:
Alpha helixes:
- form long thin structures important for transmembrane proteins
- have a rigid spring like structure around a central axis
Beta sheets:
- Keep their shape due to hydrogen bonds between adjacent polypeptides chains
- have a flat zig zag like structure
Explanation:
Alpha helices and beta pleated sheets are two types of secondary structure found in proteins.
Alpha helix: In this structure, the polypeptide backbone is tightly wound around an imaginary central axis drawn longitudinally through the center with the R groups of the amino acids protruding outward from the helical backbone. This structure looks like a spring and could either be a left-handed or right-handed helix, though the left-handed helix has not been observed in proteins. Each turn of the helix includes about 3.6 amino acid residues.
The alpha helix is stabilized by a hydrogen bond between the hydrogen atom attached to the electronegative nitrogen atom of a peptide linkage and the electronegative carbonyl oxygen atom of the fourth amino acid on the amino-terminal side of that peptide bond.
Alpha-helices due to their structure, are the most common transmembrane proteins- protein structure element that crosses biological membranes.
Beta sheets: In the beta conformation, the backbone of the polypeptide chain is extended into a zigzag structure. The zigzag polypeptide chain can be arranged side by side to form a structure resembling a series of pleats known as beta sheets. Hydrogen bonds formed between adjacent segments of the polypeptide chain functions to stabilize the structure.
The beta comformation in the form of turns is common in globular proteins.
The Ka for benzoic acid is 6.5 × 10−5. Calculate the pH of a 0.14 M benzoic acid solution.
Answer:
2.52
Explanation:
C6H5COOH + H2O ⇄ C6H5COO- + H30+
0.14M 0 0
-X +X +X
---------------------------------------------------------------
0.14-X X X
Ka= 6.5 × 10^-5 = [tex]\frac{x^{2} }{0.14-x}[/tex]
Since the effect of X in equation (0.14-x) is very small, it can be ignored.
x= 3.02 × 10^-3
-logx = 2.52
Scientists carried out an experiment with flowers from plant X and found out that within three minutes of exposure to the sound of bees, the flowers increased the amount of sugar in their nectar by twenty times.
Explain how the above behaviour of the flowers can benefit plant X
Bees want the nectar from the flowers mostly for the sugar content. Also, the plant needs the bees in order to reproduce. Therefore, making its flowers more appealing to the bees is beneficial for its probability of reproduction.
Draw every stereoisomer for 1,2-difluoro-1,2-dimethylcyclopentane. Use wedge-and-dash bonds for the substituent groups, and be sure that they are drawn on the outside of the ring, adjacent to each other.
Answer:
See figure 1
Explanation:
In this question, we have to find first the chiral carbons on 1,2-difluoro-1,2-dimethylcyclopentane. Carbons 1 and 2. Then, using the Cahn–Ingold–Prelog priority rules. We can draw all the stereoisomers. If we have 2 chiral carbons we will have ([tex]2^n=2^2=4[/tex]) 4 isomers. With this in mind we can have the R,R isomer; the S,S isomer; the S,R isomer, and the R,S isomer. We have to remember that:
Priority 1 = "F"
Priority 2= "C"
Priority 3= "CH2"
Priority 4 = "CH3"
I hope it helps!
A sample of krypton gas occupies a volume of 9.87 L at 51°C and 0.565 atm. If it is desired to decrease the volume of the gas sample to 8.05 L, while increasing its pressure to 0.678 atm, the temperature of the gas sample at the new volume and pressure must be___________ °C.
Answer:
44.1°C
Explanation:
Step 1:
Data obtained from the question include:
Initial volume (V1) = 9.87 L
Initial temperature (T1) = 51°C = 51°C + 273 = 324K
Initial pressure (P1) = 0.565 atm
Final volume (V2) = 8.05 L
Final pressure (P2) = 0.678 atm
Final temperature (T2) =..?
Step 2:
Determination of the new temperature of the gas.
The new temperature of the gas can be obtained by using the general gas equation as shown below:
P1V1 /T1 = P2V2 /T2
0.565 x 9.87/324 = 0.678 x 8.05/T2
Cross multiply
0.565 x 9.87 x T2 = 324 x 0.678 x 8.05
Divide both side by 0.565 x 9.87
T2 = (324 x 0.678 x 8.05)/(0.565 x 9.87)
T2 = 317.1K
Step 3:
Conversion of 317.1K to decree celsius.
This is illustrated below:
T (°C) = T(K) – 273
T (K) = 317.1K
T (°C) = 317.1 – 273
T (°C) = 44.1°C
Therefore, the new temperature of the gas is 44.1°C
g If a sample of 50 mL of ethyl benzene (bp = 136 C) was contaminated with 10 mL of ethyl acetate (bp = 77 C) what effect would this have on the boiling point measurement?
Answer:
melting point will be higher than that of pure ethyl acetate
Explanation:
Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the number of moles of gas as bottle A, what is the ratio of the pressure in B to the pressure in A? Express to 2 sig figs.
Answer:
The ratio of pressure in bottle B to that of bottle A is 1 : 4
Explanation:
We'll be by calculating the pressure in both bottles. This is illustrated below below:
For A:
Temperature (T) = T
Volume (V) = V
Number of mole (n) = n
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =...?
PV = nRT
PV = n x 0.0821 x T
Divide both side by V
P = nT0.0821/V
Therefore, the pressure, in bottle A is
PA = nT0.0821/V
For B:
Temperature (T) = the same as that of A = T
Volume (V) = twice that of A = 2V
Number of mole (n) = half that of A = ½n
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =...?
PV = nRT
P x 2V = ½n x 0.0821 x T
Divide both side by 2V
P = ½n x 0.0821 x T/2V
P = nT0.0821/4V
Therefore, the pressure in bottle B is:
PB = nT0.0821/4V
Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:
Pressure in bottle A (PA) = nT0.0821/V
Pressure in bottle B (PB) = nT0.0821/4V
PB/PA = nT0.0821/4V ÷ nT0.0821/V
PB/PA = nT0.0821/4V x V/nT0.0821
PB/PA = 1/4
Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.
Rate = K[A]
I
Using this equation, what would the reaction rate be for the following set of factors? (4 points)
Rate constant = 1 x 10-3 (L/mol)/s
[A] = 3 M
Answer:
9 × 10⁻³ mol·L⁻¹s⁻¹
Explanation:
Data:
k = 1 × 10⁻³ L·mol⁻¹s⁻¹
[A] = 3 mol·L⁻¹
Calculation:
rate = k[A]² = 1 × 10⁻³ L·mol⁻¹s⁻¹ × (3 mol·L⁻¹)² = 9 × 10⁻³ mol·L⁻¹s⁻¹
Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of micrograms. How many milligrams are in a dose labeled 125 µg? View Available Hint(s) Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of micrograms. How many milligrams are in a dose labeled 125 µg? 1.25 x 105 mg 0.125 mg 1.25 x 10?4 mg 1.25 x 102 mg
Answer:
0.125 mg
Explanation:
The correct answer would be 0.125 mg
According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.
milligram = [tex]10^{-3}[/tex]
microgram = [tex]10^{-6}[/tex]
Hence,
1 milligram = 1000 micrograms or 1 microgram = [tex]10^{-3}[/tex] milligram
Therefore, 125 micrograms will be:
125/1000 = 0.125 milligram
The diagram below shows the different phase transitions that occur in matter. Three bars are shown labeled Solid, Liquid, and Gas. They are connected by arrows labeled 1 to 6. Arrow 1 points from liquid to gas; arrow 2 from solid to liquid, arrow 3 from solid to gas, arrow 4 from gas to liquid, arrow 5 from liquid to solid, and arrow 6 from gas to solid. Which best describes the process that arrow 1 represents? Molecules are speeding up during boiling. Molecules are depositing as ice on a surface. Molecules are slowing down during condensing. Molecules are moving from stationary positions.
Answer:
Molecules are speeding up during boiling
Explanation:
According to the kinetic theory of matter, matter exists in three states; solid, liquid and gas. In the solid state, the molecules of a substance are in fixed positions, the can only vibrate but can not translate. In the liquid state, the molecules acquire a greater degree of freedom and can translate in addition to vibration and rotation. In a gas the molecules are infinitely free and translate at high velocities.
Arrow 1 shows a phase change from liquid to gas. This occurs during boiling. This phase change is possible because the liquid molecules acquire energy in the form of heat supplied during boiling thereby making the molecules of the liquid to speed up their motion and escape the liquid surface as vapour.
Answer:
Molecules are speeding up during boiling.
Explanation:
The bromine test (part d) is often used as an indication of unsaturation(double and triple bonds). Explain why your result for trichloroethylene and toluene were different than for the simple alkene produc
Answer:
Toluene is an aromatic compound not an alkene
Bromine test is used to determine the presence of unsaturation in the given compound. The trichloroethylene does not have any unsaturation while toluene have double bonds of benzene ring. Therefore, the Bromine test can differentiate between trichloroethylene and toluene.
What is degree of unsaturation?The degree of unsaturation of an organic compounds can be categorised two types: saturated and unsaturated. Saturated compounds are those that have only single bonds. An unsaturated compound are those that has a double bond, triple bond, and/or ring(s).
The alkanes with only single bonds are classified as saturated whereas the alkenes and alkynes with double and triple bonds are classified as unsaturated hydrocarbons.
The degree of unsaturation formula helps in finding whether a compound is saturated or unsaturated.
In the Bromine test when the bromine solution will be added into the compound if the brown color of the solution will disappear it means the unsaturation is present in the given compound.
Therefore, the we can distinguish between trichloroethylene and toluene with bromine test.
Learn more about degree of unsaturation, here:
https://brainly.com/question/13404978
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a) What is the common-ion effect?b) Given an example of a salt that can decrease the ionization of HNO2 in solution. List all of the substances (species) that would be present in the solution. (Consider the HNO2, the salt, and the water.)
Answer:
Common ion effect refers to the decrease in the solubility of a substance in a solution with which it shares a common ion.
NaNO2
Explanation:
In order to understand exactly what common ion effect is, let us consider a simple unambiguous example. Assuming I have a solution of an ionic substance that contains a cation A and an anion B, this ionic substance has chemical formula AB. Secondly, I have another ionic distance with cation C and anion B, its chemical formula is CB. Both CB and AB are soluble in water to a certain degree as shown by their respective KSp.
If I dissolve AB in water and form a solution, subsequently, I add solid CB to this solution, the solubility of CB in this solution is found to be lees than the solubility of CB in pure water because of the ion B^- which is common to both substances in solution. We refer to the phenomenon described above as common ion effect.
Common ion effect refers to the decrease in the solubility of a substance in a solution with which it shares a common ion.
If I try to dissolve NaNO2 in a solution of HNO2, the solubility of NaNO2 in the HNO2 solution will be less than its solubility in pure water due to common ion effect. Also, the extent of ionization of HNO2 in a system that already contains NaNO2 will be decreased compared to its extent ionization in pure water. This system described here will contain HNO2, water and NaNO2
In supersonic flights, molecules break apart and react chemically. which safety features protect the plane?
Answer:
Explanation:
The heat Shield are materials (usually made of metals) protect us from heat by absoring lots of heat and gradually releasing heat by surrounding air cirucaltion
Answer:
Heat shield
Explanation: Most heat shields consist of one or more layers of stamped metal that are shaped into a shield that is designed to wrap around the exhaust manifold. The shield acts as a barrier and heat sink, preventing the heat from the manifold from reaching any of the components under the hood and potentially causing damage.
What does the law say about matter
The following can be the answer for your qn. as in your qn., you didn't ask that which law you wanna know abt. You just gave that you wanna know abt laws of matter. So, here they are. Given below. :)
Answer:
Given below are some basic laws of matter.
The Law of conservation of mass, The law of constant proportions. The law of multiple proportions. The law of reciprocal proportions.
......Hope it helps you.....
What are three characteristics of a chemical reaction
Answer:
change in colour , change in temperature , form of bullbes
Explanation:
Answer:
Evolution of gas.
Formation of a precipitate.
Change in color.
Explanation:
calculate the energy in joules and calories required to heat 50.0g silver from 106c to 255c.
Answer:
Explanation:
use this fromula
q = m c ∆t
m is mass of silver =50 g
∆t is difference in temperature= 255-106=149
C= specific heat fo silver ( should be mentioned in your question )
Why does a chemical change occur when copper is heated?
Answer:
When copper is heated, it decomposes to form copper oxide and carbon dioxide. It is an endothermic reaction, which means that it absorbs heat. When heated, copper is easily bent or molded into shapes.
Explanation:
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
Part A Label the anode and cathode, indicate the direction of electron flow.
Drag the appropriate labels to their respective targets.
Part B Write an equation for the half-reaction occurring at each electrode.
Express your answers as chemical equations separated by a comma. Identify all of the phases in your answer.
Part C What minimum voltage is necessary to drive the reaction?
Answer:
-1.05 V
Explanation:
A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.
Oxidation half equation;
Sn(s) ------> Sn^2+(aq) + 2e
Reduction half equation:
Mn^2+(aq) + 2e ----> Mn(s)
Cell voltage= E°cathode - E°anode
E°cathode= -1.19V
E°anode= -0.14 V
Cell voltage= -1.19 V - (-0.14V)
Cell voltage= -1.05 V
Oxidation half equation:
Sn (s) ------> Sn²⁺ (aq) + 2e
Reduction half equation:
Mn²⁺ (aq) + 2e ----> Mn (s)
The minimum voltage necessary to drive the reaction is 1.055 V
The setup of the electrolytic cell consists of a manganese and tin rods dipped in separate containers containing solutions of manganese chloride and tin chloride as electrolytes. A salt bridge is used to connect both half cells and in order to ensure ionic balance.
Since Mn²⁺ is reduced to Mn, the manganese rod serves as the cathode.
As Sn is oxidized to Sn²⁺, the tin rod serves as the anode.
The cathode is connected to the anode (negative terminal) of the battery, while the anode is connected to the cathode of the battery (positive terminal).
Electrons flows from the anode to the cathode.
A battery is connected to the setup to drive the process from being non-spontaneous to spontaneity.
The setup is shown in image attached below.
Oxidation half equation:
Sn (s) ------> Sn²⁺ (aq) + 2e
Reduction half equation:
Mn²⁺ (aq) + 2e ----> Mn (s)
Cell voltage = E°cathode - E°anode
E°cathode= -1.195 V
E°anode= -0.140 V
Cell voltage= -1.195 V - (-0.140V)
Cell voltage= -1.055 V
Therefore, minimum voltage necessary to drive the reaction is 1.055 V
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