A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate
Ways in which a cyclist can increase the speed of a bicycle
Bicycle riders could accelerate/ increase their speed in various ways
By Changing the gears and by doing so increasing the speedBy Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.By increase the rate at which they are pedalling the bicycle.Learn more about increasing bicycle speed here:
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Convert 37°C to K.
a 310.15 K
b 187.6K
c567.5 K
d 245.7 K
Answer:
A. 310.15K
Explanation:
Celsius Temperature Conversion Formula
[K] = [°C] + 273.15
K = C + 273.15
= 37+273.15
= 310.15
What conditions must be met in order for work to be done?
Check all that apply.
A.The applied force must make the object move.
B.The output force must be greater than the input force.
C.The work must be greater than the momentum.
D.At least part of the applied force must be in the same direction as
the movement of the object.
Answer:
d
Explanation:
A player hits a tennis ball into the air with an initial velocity of 32 m/s straight up. How fast is the ball moving at the highest point in its trajectory if air resistance is negligible?
What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 kilograms?
Answer:
Explanation:
f =ma
F 2500 kg (20m/s-0m/s/15s)
F=2500kg(1.33m/s²)
F =3,325 N
f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
What is Force?A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects.
The force is no longer felt by the two objects when the interaction ends. Only when there is interaction do forces actually exist.
Action-at-a-distance forces are those that happen even when the two interacting objects are not physically touching each other but are nevertheless able to push or pull against each other despite their physical separation. Gravitational forces are an example of action-at-a-distance forces.
Therefore, f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
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what is kinematics?
explain!!~
thankyou ~
Answer:
Kinematics:-
Branch of mechanics concerned Features of motion in an objectCauses and effects of motionsHope it helps!
Answer:
KINEMATICS; kinematics is the study of the motion of mechanicals , bodies ,and system , without ,considerations of their associeted physical properties and the forces acting on themExplanation:
KINEMATICS: Kinematics is the study of objects in emotions there, ( velocity, acceleration, and momentum,)#hope its help#care on learning pa brainlest nalangWhy does he have maximum potential energy at this point?
he is going the fastest speed
he is at the highest point
he has more mass here
What other questions do you have about the effect of gravity on objects?
Answer:
Anything that has mass also has gravity. Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is.
Explanation:
What tool would you use for Volume
Answer:
Volumetric cylinders and volumetric flasks are used to measure volume of liquids contained in them. They are calibrated for volume included in them - this is indicated by the marking "IN". The liquid has accurate volume when it reaches the corresponding marking on the scale. Volume is usually indicated in mL. Mark me brainliest please
The two pendulums shown in the figure below, each consist of a uniform solid ball of mass M supported by a rigid massless rod, but the ball for pendulum A is very tiny while the ball for pendulum B is much larger having a non-negligible radius R = 1.15 m. The length L in the figure is L = 1.6 m. Find the ratio of the ratio TB/TA of the period of pendulum B to the period of pendulum A.
Answer:
P = 2 pi (I0 / M g L)^1/2 for object with inertia of I0
Note that if I0 = M L^2 you have P = 2 pi (L / g)^1/2 the simple pendulum
Radius of sphere = 1.15 = .719 L
I0 = M L^2 + 2/5 M (.719 L)^2 = 1.207 M L^2
P2 = 2 pi (1.207 M L^2 / M g L)^1/2 = 2 pi (1.207 L / g)^1/2
P2 / P1 = (1.207 / 1)^1/2 = 1.10 ratio of periods
Answer:
the ratio is 46:101.
Explanation:
for pendulum 'B', periodic time;
[tex]T_{B} =2\pi \sqrt{\frac{I}{MgL} }[/tex]
inertia of solid sphere[tex]I=\frac{2}{5}MR^{2}[/tex]
I is Moment of Inertia, L is length of rod, and
periodic time for pendulum 'A';
[tex]T_{A}=2\pi \sqrt{\frac{L}{g} }[/tex]
Thus;
[tex]\frac{T_{B} }{T_{A} }=\frac{R}{L}\sqrt{\frac{2}{5} }[/tex]
[tex]\frac{T_{B} }{T_{A} }=\frac{1.15}{1.6}\sqrt{\frac{2}{5} } =\frac{46}{101}[/tex]
What is periodic time?The time taken in one complete oscillation is called time period.
What is moment of inertia?The product of mass of particle(m) and square of the distance from rotational axis (r) is called moment of inertia.
[tex]I=mr^{2}[/tex]
hence, the ratio is 46:101.
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Your motorboat can move at 30 km/h in still water. What is the minimum time it will take you to move 12 km downstream in a river flowing at 6.0 km/h
We have that the Time is mathematically given as
t=0.33h
From the question we are told
Your motorboat can move at 30 km/h in still water. What is the minimum time it will take you to move 12 km downstream in a river flowing at 6.0 km/hTimeGenerally the equation for the Time is mathematically given as
[tex]t=\frac{d}{va+vb}\\\\Therefore\\\\t=\frac{12}{30+6}[/tex]
t=0.33h
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A car starts from rest and accelerates uniformly to a speed of 72km/hr over a distance of 500m. Find the acceleration of the car and time taken to attain this speed
Answer: a = 0.4 m/s^2
t = 50 s
Explanation:
Convert 72 km/hr to m/s by multiplying it by (1000 m / 1 km)(1 hr / 3600s).
Then, plug this into the formula: (v final)^2 = (v original)^2 + 2*a*d; v original = 0, so it becomes 20^2 = 2*a*500. This yields a = .4 m/s^2.
For the time: a = change in speed / t, which becomes .4 = 20 / t, which yields t = 50 s.
In a hydrogen atom, an electron with a charge of (-)1.6E-19 C orbits a proton with the same but positive charge at a distance 61 picometers away (that's trillionths of a meter or 10-12 m). What electric force F, in N, binds the two particles together
This question involves the concept of Colomb's Law and electrostatic force.
The electrostatic force will be "6.2 x 10⁻⁸ N".
COLOMB'S LAW:According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.
[tex]F = \frac{kq_1q_2}{r^}[/tex]
where,
F = electrostatic force = ?k = Colomb's constant = 9 x 10⁹ N.m²/C²q₁ = magnitude of first charge = 1.6 x 10⁻¹⁹ Cq₂ = magnitude of second charge = 1.6 x 10⁻¹⁹ Cr = distance between charges = 61 x 10⁻¹² mTherefore,
[tex]F = \frac{(9\ x\ 10^9\ N.m^2/C^2)(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(61\ x\ 10^{-12}\ m)^2}[/tex]
F = 6.2 x 10⁻⁸ N
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A baton twirler throws a spinning baton directly upward. As it goes up and returns to the twirler’s hand, the baton turns through four revolutions. Ignoring air resistance and assuming that the average angular speed of the baton is 1.90 rev/s, determine the height to which the center of the baton travels above the point of release.
the answer is in the photo.
5. Chipper Jones swings at a 0.15 kg baseball and accelerates it at a rate of
3,000 m/s2. How much force does Sosa exert on the ball?
Answer:
F= ma F(forces) m(mass) a(acceleration) So F= (0.15)(3000)
F= 450 N
Explanation:
ok so we can figure it out
Please help
In this pulley system, the pulleys will
the mechanical force required to lift the block and will change the
(1 point)
O increase, direction of the force
O decrease; weight of the block
O decrease, direction of the force
O increase, weight of the block
Answer:
decrease; direction of the force
Explanation:
4. Peter thinks his friend only became a skilled pianist because he had unconscious experiences with his grandmother, a pianist, when he was a young child. With whose
theory of personality would Peter agree?
O A. Sigmund Freud
O B. Erik Erikson
O C. Carl Jung
O D. Abraham Maslow
Answer:
C.
Explanation:
Ensuring that every contingency is planned for is an aspect of which of the following successful marketing plan requirements?
controllable
timely
fact based
flexible
Answer:
Fact based i think if not timely
Explanation:
Describe one common critique or criticism of Utilitarianism. To what extent do you agree or disagree with this criticism?
please helppppppppppppp
A net force of 15N acts upon a body of mass 3kg for 5s, calculate the change in the speed of the body
As we know –
[tex]\qquad[/tex][tex] \purple{\bf \twoheadrightarrow F = m a } [/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow F = m \dfrac{ v-u}{t} [/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow 15 = 3 \times \dfrac{v-u}{5} [/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow 3 \times \dfrac{v-u}{5} = 15 [/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow \dfrac{3}{5} \times (v-u) = 15 [/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow (v-u)= 15 \times \dfrac{5}{3} [/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow (v-u)= \cancel{15} \times \dfrac{5}{\cancel{3}}[/tex]
[tex]\qquad[/tex][tex] \sf \twoheadrightarrow v-u = 5 \times 5 [/tex]
[tex]\qquad[/tex][tex] \purple{\bf \twoheadrightarrow v-u = 25 } [/tex]
Henceforth, the change in the speed of the body is 25 m/s. A projectile is thrown with an initial speed of 20 m/s at an angle 30 degrees above
the horizontal.
a. What is the maximum height of the projectile?
b. What is the speed of the projectile 2 seconds after being launched?
Part 1
The figure shows a claw hammer as it pulls a
nail out of a horizontal board. If a force of magnitude 133 N is exerted
horizontally as shown, find the force exerted
by the hammer claws on the nail. (Assume
that the force the hammer exerts on the nail
is parallel to the nail).
Answer in units of N
Part 2
Find the force exerted by the surface on the
point of contact with the hammer head. Assume that the force the hammer exerts on the
nail is parallel to the nail.
Answer in units of N.
The force exerted by the hammer claws on the nail is =1578N
How to calculate magnitude of force:The force that is applied, as the effort on the hammer= F1
The force exerted by the hammer claws on the nail= F2
But,
magnitude of force exerted on hammer= F1*d1
While magnitude of force exerted by the hammer claws on the nail = F2( d2sin30°)
And, F1*d1 = F2( d2sin30°)
Where F1 = 133N
d1 = 29cm = 0.29m
F2 = X
d2 = 4.89cm = 0.0489m
After substitution,
133 × 0.29 = X( 0.0489 × sin30°)
38.57 = X ( 0.0489 × 0.5)
38.57 = X(0.02445)
X= 38.57/0.02445
X = 1578N
Therefore, the force exerted by the hammer claws on the nail is =1578N
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Do you think science is objective? Why or why not?
Answer:
Not really it also contains theories and practical aspects of it
Answer:
It is not supposed to be but as humans we may make mistakes and have bias
Explanation:
I need help asap.
why is momentum a vector quantity?
A. It has direction.
B. It has magnitude.
C. It has both direction and magnitude.
D. It has both speed and magnitude.
Answer:
I think it should be ans=A
Please help. I don’t know how to solve this as there is no angle provided.
Answer:
that is weird
Explanation:
i dont know what to say. is there more info?
What can you do to prevent an echo and a reverberation in cinema halls and auditorium?
Answer:
Just make sure the distance between two objects isn't much
What is evidence that magnetic fields exist?
Answer these questions pls ASAP
Answer:
Balloon , vaccum,and thats about it at least all i can think of
Peter does 3,000 joules (J) of work by moving an object 40 meters (m). What is the force that Peter applies to the object? A 75 N B 2,960 N C 3,040 N D 120,000 N
The force that peter applies to the object of distance 40m is 75N.
HOW TO CALCULATE FORCEThe force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;
Force = Work done ÷ distance
According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:
Force = 3000J ÷ 40m
Force = 75N
Therefore, the force that peter applies to the object of distance 40m is 75N.
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A uniform brick of length 18 m is placed
over the edge of a horizontal surface with a
maximum overhang of 9 m attained without
tipping.
Now two identical uniform bricks of length
18 m are stacked over the edge of a horizontal
surface.
What maximum overhang is possible for
the two bricks (without tipping)?
Answer in units of m.
We have that the overhang possible for the two bricks are is mathematically given as
x=13.5m
Length of Overhang
Question Parameters:
A uniform brick of length 18 m
a maximum overhang of 9 m attained
Length 18 m are stacked over the edge of a horizontal
surface.
Generally the equation that balances the moment is mathematically given as
[tex]mg*(x-l/2)=mg(L-x)\\\\2x=3l/l\\\\x=3l/4\\\\x=3/4*18\\\\[/tex]
x=13.5m
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A force of 25N acts on a mass of 5.0kg, initially at rest. Calculate the distance travelled before achieving a velocity of 20m/s
Answer:
40m
Explanation:
let's calculate the acceleration first
force = mass × acceleration
rearranging to find acceleration:
acceleration = force ÷ mass
force = 25N, mass = 5.0kg
acceleration = 25 ÷ 5 = 5ms^-2
we can now use the formula v^2 = u^2 + 2as where v = final velocity, u = initial velocity, a = acceleration and s = distance
rearranging v^2 = u^2 + 2as the distance is
s = (v^2 - u^2) ÷ 2a
v = 20, u = 0, a = 5
s = (20^2 - 0^2) ÷ (2 × 5) = 40m
the distance is 40m
