Given the following information about the commodity market and the money market C = 0.5Y + 200, 1 = -50r + 1800.MS= 3500, L1 = 0.25Y, L2= -25r + 3000. The LM equation is
a. y=2000+ 100r
b. y=2000-50r
c. r=1000+2007
d. r=2000+100y

Answer:

To find the intervals on which the function g(x) = x^2 - 2x - 8 is increasing or decreasing, we need to take the derivative of g(x) with respect to x and find where it is positive (increasing) or negative (decreasing).

g(x) = x^2 - 2x - 8

g'(x) = 2x - 2

Now we need to find where g'(x) > 0 (increasing) and where g'(x) < 0 (decreasing).

g'(x) > 0

2x - 2 > 0

2x > 2

x > 1

g'(x) < 0

2x - 2 < 0

2x < 2

x < 1

Therefore, g(x) is increasing on the interval (1, infinity) and decreasing on the interval (-infinity, 1).

the expected value of the total sales projection is $9,840.

To calculate the expected value of the total sales projection, we need to multiply the number of units sold by the price and the probability of each scenario, and then add up the results. Let's use the following table as a reference:

| Scenario | Probability | Units Sold | Price per Unit |
 |----------|-------------|------------|----------------|
 | 1        | 0.3         | 500        | $10           |
 | 2        | 0.4         | 800        | $12          |
 | 3        | 0.3         | 1000       | $15           |

To calculate the expected value of scenario 1, we multiply 500 units by $10 per unit and by the probability of 0.3, which gives us a result of $1,500. We can do the same for scenarios 2 and 3, and then add up the results:

Scenario 1: 500 x $10 x 0.3 = $1,500
Scenario 2: 800 x $12 x 0.4 = $3,840
Scenario 3: 1000 x $15 x 0.3 = $4,500

Total expected value = $1,500 + $3,840 + $4,500 = $9,840

Therefore, the expected value of the total sales projection is $9,840.

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The value of second order differentiation, that is d²y/dx² at x = 1 is 132 for function y= f(x) such that f(1) = 2 and dy/dx=y³+3 .

Hence option c is the correct answer.

The given function of x is, y = f(x)

y = f(x) is twice differentiable.

dy/dx = f'(x) = y³ + 3

Differentiation dy/ dx with respect to x, that is differentiating y = f(x) second time with respect to x, we get,

f''(x) = d²y / dx² = [d(dy/dx)] / dx

= d (y³ + 3) / dx

Thus by chain rule of differentiation we get,

f''(x) = d²y / dx² = 3y² (dy/dx)

= 3y² ( y³ +3)

= 3[tex]y^{5}[/tex] + 9y²

Since, f(1) = 2, it implies when x=1 , then y = 2 as y = f(x)

Therefore, d²y/dx² at x = 1  or f''(1) is,

f''(1) = 3[[tex](2)^{5}[/tex]] + [9(2²)]

= 96 + 36 = 132

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The probability that the scooter came from Plant2 given that it is of standard quality is approximately 0.3861 or 38.61%

To find the probability that the scooter came from Plant2 given that it is of standard quality, we can use Bayes' theorem.

Let A be the event that the scooter comes from Plant2, and B be the event that the scooter is of standard quality. We want to find P(A|B), the probability that the scooter came from Plant2 given that it is of standard quality.

Using the formula for Bayes' theorem, we have:

P(A|B) = P(B|A) * P(A) / P(B)

where P(B|A) is the probability that a scooter from Plant2 is of standard quality, P(A) is the probability that a randomly chosen scooter came from Plant2, and P(B) is the probability that a randomly chosen scooter is of standard quality.

From the given information, we have:

P(B|A) = 0.96 (the probability that a scooter from Plant2 is of standard quality)
P(A) = 0.38 (the proportion of scooters manufactured by Plant2)
P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)
    = 0.96 * 0.38 + 0.92 * 0.62 (using the law of total probability)
    = 0.9416

Substituting these values into Bayes' theorem, we get:

P(A|B) = 0.96 * 0.38 / 0.9416
      = 0.3861

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.

The proportion of the population between 24 and 32 is approximately 0.159, or 15.9%.

To find the proportion of a normal population between 24 and 32 with a mean (μ) of 40 and a standard deviation (σ) of 11, follow these steps:

1. Calculate the z-scores for 24 and 32 using the z-score formula: z = (X - μ) / σ
  For 24: z1 = (24 - 40) / 11 = -16 / 11 ≈ -1.45
  For 32: z2 = (32 - 40) / 11 = -8 / 11 ≈ -0.73

2. Use a z-table or calculator to find the proportion of the population corresponding to these z-scores.
  For z1 = -1.45:

p(z1) ≈ 0.074
  For z2 = -0.73:

p(z2) ≈ 0.233

3. Find the proportion of the population between z1 and z2 by subtracting p(z1) from p(z2).
  p(z2 - z1) = p(z2) - p(z1) = 0.233 - 0.074 = 0.159

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The rewritten expression of 8x + 20 using the distributive property is 4(2x + 5)

From the question, we have the following parameters that can be used in our computation:

8x+ 20 distributive property

This means that

8x + 20

Factor out 4 from the equation

So, we have

8x + 20 = 4(2x + 5)

The above equation has been rewritten using the distributive property.

Hence, the rewritten expression using the distributive property is 4(2x + 5)

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The 95% confidence interval for the population mean annual earnings will be constructed as (2909.69, 3330.31)

To construct the confidence interval for the population mean, we can use the formula:

Confidence interval = sample mean +/- (critical value) x (standard error)

where the critical value is based on the desired confidence level (95% in this case), and the standard error is calculated as the population standard deviation divided by the square root of the sample size.

Plugging in the given values, we get:

Confidence interval = 3120 +/- (1.96) x (677/√(40))
Confidence interval = 3120 +/- 210.31

Therefore, the 95% confidence interval for the population mean annual earnings is (2909.69, 3330.31). This means we can be 95% confident that the true population mean falls within this range.

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If Bill took 2 hours to bike around a lake, then it would take Bill 5 hours to walk-around the lake at a speed of 4 miles per hour.

The "Speed" is defined as a "scalar-quantity" that refers to the rate at which an object changes its position with respect to time.

Let the distance around lake be = "d" miles.

We know that,

⇒ Time-taken to bike around lake is = 2 hours,

⇒ Speed while biking = 10 mph,

We use formula ⇒ Distance = (Speed) × (Time),

Substituting the values,

We get,

⇒ d = 10 × 2,

⇒ d = 20 miles,

Now, Speed while walking = 4 miles per hour,

So, Time taken to walk around the lake = (Distance)/(Speed),

⇒ Time taken to walk around lake = 20/4,

⇒ Time taken to walk around lake = 5 hours,

Therefore, the required time is 5 hours.

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integrated I(y) with respect to y, you'll get a numerical value for the double integral ∬(R) SR dA.

The specific function SR, it's not possible to provide a numerical answer.

Step-by-step explanation should help you evaluate the double integral for any given SR.

To evaluating a double integral over a region R.

Let's break it down step-by-step.
Identify the region R: R is given by the bounds [0, 3] for the x-axis and [1, 2] for the y-axis.

This defines a rectangular region in the xy-plane.
Set up the double integral:

Since the region R is a rectangle, you can write the double integral as:
∬(R) SR dA = ∫(x=0 to x=3) ∫(y=1 to y=2) SR dx dy
Here, SR represents the integrand that you need to integrate with respect to x and y.
Integrate with respect to x:

To evaluate the inner integral, integrate SR with respect to x, while keeping y constant.

Let's denote the result as I(y).
I(y) = ∫(x=0 to x=3) SR dx
Integrate with respect to y:

Now, evaluate the outer integral by integrating I(y) with respect to y over the given range [1, 2]:
∬(R) SR dA = ∫(y=1 to y=2) I(y) dy
Evaluate the integral:

Once you've integrated I(y) with respect to y, you'll get a numerical value for the double integral ∬(R) SR dA.

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The area is 25 square meters, the length of the square is s = 5 meters,

and the rate at which the length is increasing is:

ds/dt = 1 / (2 × 5) = 0.1 m/s

To find the slope of the line tangent to the curve [tex]zsin(y) = x^2[/tex] at the point (2, 7/3):

We need to use implicit differentiation, which involves differentiating both sides of the equation with respect to x, treating y and z as functions of x.

Differentiating both sides with respect to x, we get:

z × cos(y) × dy/dx + sin(y) × dz/dx = 2x

At the point (2, 7/3), we have x = 2 and y = 7/3. To find dz/dx, we need to solve for it in terms of known quantities:

z × cos(7/3) × dy/dx + sin(7/3) × dz/dx = 4

Now, we need to find dy/dx, which represents the slope of the tangent line at the given point. To do this, we need to find the value of dy/dx at the point (2, 7/3).

To find dy/dx, we can differentiate the original equation with respect to x, treating z as a constant:

z × cos(y) × dy/dx = 2x

Plugging in x = 2 and y = 7/3, we get:

z × cos(7/3) × dy/dx = 4

dy/dx = 4 / (z × cos(7/3))

Now, substituting this expression for dy/dx into the equation we found earlier, we get:

zcos(7/3)(4 / (z × cos(7/3))) + sin(7/3) × dz/dx = 4

Simplifying, we get:

dz/dx = (4 - 4 × cos(7/3)) / sin(7/3)

So the slope of the tangent line at the point (2, 7/3) is

dz/dx = (4 - 4 × cos(7/3)) / sin(7/3).

To find the rate at which the length of a square is increasing when its area is 25 square meters, we need to use the chain rule and the formula for the area of a square:

[tex]A = s^2[/tex]

where A is the area and s is the length of a side of the square.

Taking the derivative of both sides with respect to time t, we get:

dA/dt = 2s  × ds/dt

where ds/dt is the rate at which the length of the square is increasing.

We are given that dA/dt = 1 m^2/s when [tex]A = 25 m^2[/tex], so we can substitute these values into the equation:

1 = 2s × ds/dt

solving for ds/dt, we get:

ds/dt = 1 / (2s)

Substituting A = 25, we get:

[tex]s =\sqrt{25} = 5 m[/tex]

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The radius is that goes from the chord to the center point is r= 8.2 units

The chord of a circle is a line segment that joins any two points on the circumference of the circle. The diameter is the longest chord that passes through the center of the circle

A line from the center of a circle intersecting a chord makes an angle of 90 degrees at the point of intersection

Using Pythagoras theorem

r² = c² + h²

r² = 8² + 2²

r²= 64 + 4

r² = 68

Making r the subject of the relation we have that

r = √68

r= 8.2 units

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The only functions g such that the first difference of g is the zero function are constant functions.

The first part of the problem asks us to consider a constant function f. A constant function is a function that takes the same value for every input. For example, f(x) = 3 is a constant function, since it takes the value 3 for every input value of x. We are asked to show that the first difference of a constant function is the zero function. To see why this is the case, consider the formula for the first difference:

Of(x) = f(x+1) - f(x)

For a constant function, we have f(x+1) = f(x), since the function takes the same value for every input. Substituting this into the formula above, we get:

Of(x) = f(x+1) - f(x) = f(x) - f(x) = 0

This shows that the first difference of a constant function is indeed the zero function.

The second part of the problem asks whether there are any other functions g such that the first difference of g is also the zero function. In other words, we are looking for functions g such that g(x+1) - g(x) = 0 for all positive integer values of x.

To answer this question, we can use the fact that if the first difference of a function is the zero function, then the function must be a constant function.

To see why this is the case, suppose g(x+1) - g(x) = 0 for all x. Then we have g(x+1) = g(x) for all x, which means that the value of the function at any input value x+1 is the same as the value of the function at the input value x. In other words, the function takes the same value for every input value, which means that it is a constant function.

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Answer:

  36

Step-by-step explanation:

You want a number c so that x² -12x +c is a perfect square trinomial.

It is helpful to understand the form of the square of a binomial:

  (x -a)² = x² -2ax +a²

In this problem, you are given the coefficient of x is 12, and you are asked for the constant corresponding to a².

When we match coefficients, we find the coefficients of x to be ...

  -12 = -2a

Dividing by -2 gives ...

  6 = a

Then the square we're looking for (a²) is ...

  a² = 6² = 36

The trinomial ...

  x² -12x +36 = (x -6)²

is a perfect square trinomial.

The constant we want to add is 36.

__

Additional comment

We chose to expand the square (x -a)² = x² -2ax +a² so the sign of the x-term would match what you are given. For the purpose of completing the square, that is not important. The added constant is the square of half the x-coefficient. The sign is irrelevant, as the square is always positive.

You will note that when we write the expression as the square of a binomial, the constant in the binomial is half the x-coefficient (and has the same sign).

  x² -12x +36   ⇔   (x -6)²

The maximum height of the object thrown on the moon is approximately 12.739 meters.

The maximum height of the object thrown on the moon can be found by first finding the time when the velocity is zero, and then using that time to calculate the height using the position function.

Step 1: Differentiate the position function s(t) = 6.5t - 0.831t² to get the velocity function v(t).
v(t) = 6.5 - 1.662t

Step 2: Set the velocity function equal to zero and solve for t.
0 = 6.5 - 1.662t
t ≈ 3.911 seconds

Step 3: Plug the value of t into the position function to find the maximum height.
s(3.911) = 6.5(3.911) - 0.831(3.911)²
s(3.911) ≈ 12.739 meters

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Anthony worked for approximately 7.35 hours. This can be answered by the concept of Standard deviation.

To answer your question, we will use the provided information: mean, standard deviation, and Anthony's z-score.

Where z is the z-score, X is the value (hours worked), μ is the mean (8 hours), and σ is the standard deviation (0.5 hours). We know Anthony's z-score is -1.3, so we can solve for X:

-1.3 = (X - 8) / 0.5

Now, multiply both sides by 0.5:

-0.65 = X - 8

Next, add 8 to both sides:

7.35 = X

So, Anthony worked for approximately 7.35 hours.

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The first derivative of f(x) is [tex]f'(x) = (x^2 - 6x + 7) / (x - 3)^2[/tex], and the second

derivative is[tex]f''(x) = 4 / (x - 3)^3[/tex].

To find the first derivative of the given function, we will use the quotient rule:

[tex]f(x) = (x^2 - 3x + 2) / (x - 3)\\f'(x) = [ (x - 3)(2x - 3) - (x^2 - 3x + 2)(1) ] / (x - 3)^2\\f'(x) = [ 2x^2 - 9x + 9 - x^2 + 3x - 2 ] / (x - 3)^2\\f'(x) = [ x^2 - 6x + 7 ] / (x - 3)^2[/tex]

To find the second derivative, we will use the quotient rule again:

[tex]f''(x) = [ (x - 3)^2(2x - 6) - (x^2 - 6x + 7)(2(x - 3)) ] / (x - 3)^4\\f''(x) = [ 2x^2 - 12x + 18 - 2x^2 + 12x - 14 ] / (x - 3)^3\\f''(x) = [ 4 ] / (x - 3)^3[/tex]

Now let's find the asymptotes. The function has a vertical asymptote at x = 3, since the denominator becomes zero at that point. To find the horizontal asymptote, we will divide the numerator by the denominator using long division:

   x + 1

___________

[tex]x - 3 | x^2 - 3x + 2\\x^2 - 3x[/tex]

-------

2x + 2

2x - 6

------

8

The quotient is x + 1 with a remainder of 8/(x - 3). As x approaches infinity or negative infinity, the remainder term becomes negligible, and the function approaches the line y = x + 1. Therefore, the horizontal asymptote is y = x + 1.

To find the y-intercept, we set x = 0:

[tex]f(0) = (0^2 - 3(0) + 2) / (0 - 3) = -2/3[/tex]

So the y-intercept is (0, -2/3).

To find the x-intercept, we set y = 0 and solve for x:

[tex]0 = (x^2 - 3x + 2) / (x - 3)\\0 = x^2 - 3x + 2[/tex]

Using the quadratic formula, we get:

x = (3 ± sqrt(9 - 8)) / 2

x = (3 ± 1) / 2

x = 2 or x = 1

So the x-intercepts are (2, 0) and (1, 0).

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[tex]\cos(40^o )=\cfrac{\stackrel{adjacent}{x}}{\underset{hypotenuse}{6}}\implies 6\cos(40^o )=x\implies 4.596\approx x[/tex]

Make sure your calculator is in Degree mode.

The solution of Differential Equation is y' + py = a cos(px) - b sin(px) - 1

To begin, we can take the derivative of both sides of the given equation with respect to x:

y' = a cos(px) - b sin(px) - 1

Notice that the derivative of sin(px) is cos(px), and the derivative of cos(px) is -sin(px). Using these trigonometric identities, we can express the derivative of y in terms of y itself:

y' = -py + a cos(px) - b sin(px) - 1

Now we have an equation that relates y and its derivative, without involving the constants a and b. This is a first-order linear differential equation, which can be written in the standard form:

y' + py = a cos(px) - b sin(px) - 1

where p is the constant coefficient of y. This is our final answer, the differential equation that represents the relationship between y, its derivative, and the given equation involving sine, cosine, and x.

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To hold all 96 books, we need 11 shelves.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

To find the number of shelves required to hold 96 books, we divide the total number of books by the number of books that can be held on one shelf. In this case, each shelf can hold 9 books. Therefore, the number of shelves required is calculated as:

Number of shelves = Total number of books / Number of books per shelf

Number of shelves = 96 / 9

Number of shelves = 10.6667

Since we cannot have a fractional number of shelves, we round up the answer to the nearest whole number, which gives us 11 shelves.

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The probability that at least one out of three bulbs lasts 1000 hours or more is 0.973 or approximately 97.3%.

To solve this problem, we need to use the concept of complementary probability. Complementary probability states that the probability of an event occurring plus the probability of its complement (the event not occurring) equals 1. Therefore, we can find the probability of at least one bulb lasting 1000 hours or more by finding the complement of the probability that all three bulbs fail before 1000 hours.

The probability that a single bulb fails before 1000 hours is 0.3. Therefore, the probability that it lasts 1000 hours or more is 0.7. Using this probability, we can find the probability that all three bulbs fail before 1000 hours as follows:

Probability of all three bulbs failing = 0.3 x 0.3 x 0.3 = 0.027

This means that the probability of at least one bulb lasting 1000 hours or more is the complement of 0.027, which is:

Probability of at least one bulb lasting 1000 hours or more = 1 - 0.027 = 0.973 or 97.3%

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The 3rd kitten weighs 4.5 ounces

An expression in math is a sentence with a minimum of two numbers/variables and at least one math operation in it. Let us understand how to write expressions. A number is 6 more than half the other number, and the other number is x. This statement is written as x/2 + 6 in a mathematical expression. Mathematical expressions are used to solve complicated puzzles.

Total weight=14 ounces

1st kitten= 1/4pound = 4 ounces

2nd kitten= 5.5 ounces

3rd kitten = x ounces

Let the expression for the total weight be

4+5.5+x=14

To find the value of x:

9.5 + x=14

x= 14 - 9.5

x=4.5 ounces

Hence the 3rd kitten weighs 4.5 ounces.

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The given question is incomplete, complete question is:

The total weight of three kittens is 14 ounces kitten one weighs 1/4 pound kit in two weighs 5.5 ounces how many ounces does kitten three weigh?

Using the concept of similar triangles, we can say that the length GU is 16

Similar triangles are defined as triangles that have the same shape, but we can say that their sizes may differ. Thus, if two triangles are similar, then it means that their corresponding angles are congruent and corresponding sides are in equal proportion.

Using the concept of similar triangles, we can say that:

GU/NA = BU/BA

BA = 8 + 4 = 12

Thus:

GU/24 = 8/12

GU = (24 * 8)/12

GU = 16

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The probability that X has a value less than 2.1 is 0.2 or 20%.

The probability that the random variable X has a value less than 2.1 can be found by calculating the area under the probability density function (PDF) of X from 0.1 to 2.1. Since X is a uniform random variable over the interval [0.1, 5], its PDF is a straight line with a slope of 1/(5-0.1) = 0.2 and a height of 1/(5-0.1) = 0.2 over the interval [0.1, 5].

Therefore, the probability that X has a value less than 2.1 is the area of the triangle formed by the points (0.1, 0), (2.1, 0), and (2.1, 0.2), which is given by:

(1/2) × base × height = (1/2) × (2.1 - 0.1) × 0.2 = 0.2

So the probability that X has a value less than 2.1 is 0.2 or 20%.

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The probability that sheer guesswork yields 4 correct answers for 5 of the 20 problems about which the student has no knowledge is 15/16384.

1. Calculate the probability of guessing one question correctly:

Since there is only 1 correct answer out of 4 possible answers, the probability is 1/4.

2. Calculate the probability of guessing one question incorrectly:

Since there are 3 incorrect answers out of 4 possible answers, the probability is 3/4.

3. Calculate the probability of guessing 4 questions correctly and 1 question incorrectly:

This is (1/4)^4 * (3/4) = 3/16384.

4. Determine the number of ways to arrange 4 correct answers and 1 incorrect answer among 5 questions. This can be calculated using the binomial coefficient formula:

C(n, k) = n! / (k!(n-k)!)

where n = 5 (total questions) and k = 4 (correct answers). So,

C(5, 4) = 5! / (4!(5-4)!) = 5.

5. Multiply the probability of guessing 4 questions correctly and 1 question incorrectly by the number of ways to arrange the answers: 3/16384 * 5 = 15/16384.

So, the probability that sheer guesswork yields 4 correct answers for 5 of the 20 problems is 15/16384.

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The limit of the function is infinity.

The limit of a function is the value that the function approaches as the input values get closer and closer to a particular point. In this problem, the input value is approaching infinity, and we need to find the limit of the given function as x approaches infinity.

To find the limit, we need to examine the behavior of the function as x gets larger and larger. We can do this by looking at the dominant terms in the function, which are the terms with the highest powers of x. In this case, the dominant terms are 5x³ and 20x³.

As x gets larger and larger, the term 4/20x³ becomes insignificant compared to the dominant terms, so we can ignore it. Similarly, the term -9x^2 becomes smaller compared to the dominant terms, and we can also ignore it. Therefore, the function approaches the value of 5x³ as x approaches infinity.

Now, as x gets larger and larger, the value of 5x³ also gets larger and larger without bound.

Therefore, we can say that the limit of the function as x approaches infinity does not exist. In other words, the function does not approach a particular value as x gets larger and larger.

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If width of a rectangle is 4 meters less than its length which have an area of 140 square meters, then the length of rectangle is 14 meter.

The "Area" is defined as a mathematical measure of the amount of space enclosed by a two-dimensional shape, such as a rectangle, triangle, circle, or any other polygon.

Let the length of rectangle be "L" meters and

Let width be "W" meters.

We know that, width is 4 meter shorter than length,

So, Width = Length - 4 meters

Area = 140 square meters

The formula to find area of rectangle is : Area = (Length)×(Width),

Substituting the length and breadth,

We get,

⇒ 140 = L×(L - 4),

⇒ 140 = L² - 4L,

⇒ L² - 4L - 140 = 0,

⇒ (L + 10)(L - 14) = 0,

⇒ L + 10 = 0 or L - 14 = 0,

⇒ L = -10 or L = 14,

Since length cannot be negative, we discard the solution L = -10.

Therefore, the length is 14 meters.

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To construct a confidence interval for the population standard deviation, we can use the chi-square distribution.

The formula for the chi-square distribution is: (X - n*σ^2)/σ^2 ~ χ^2(n-1)

where X is the sample variance, n is the sample size, σ is the population standard deviation, and χ^2(n-1) is the chi-square distribution with n-1 degrees of freedom.

(X/χ^2(a/2, n-1), X/χ^2(1-a/2, n-1))

where X is the sample variance, n is the sample size, a is the level of significance (1 - confidence level), and χ^2(a/2, n-1) and χ^2(1-a/2, n-1) are the chi-square values with n-1 degrees of freedom that correspond to the lower and upper bounds of the confidence interval, respectively.

s^2 = (1/n) * Σ(xi - x)^2

where s is the sample standard deviation, n is the sample size, xi is the value of the i-th observation, and x is the sample mean.

s = $1.50

n = 10

x = $8.75

s^2 = (1/10) * Σ(xi - x)^2

s^2 = (1/10) * [(xi - x)^2 + ... + (xi - x)^2]

s^2 = (1/10) * [(xi - 8.75)^2 + ... + (xi - 8.75)^2]

s^2 = (1/10) * [(54.76) + ... + (0.06)]

s^2 = 5.47

a = 0.05

χ^2(0.025, 9) = 2.700

χ^2(0.975, 9) = 19.023

(X/χ^2(0.975, 9), X/χ^2(0.025, 9))

(5.47/19.023, 5.47/2.700)

($0.32, $2.02)

Therefore, we can say with 95% confidence that the population standard deviation is between $0.32 and $2.02.

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Answer:

Step-by-step explanation:

If Angelique is n years old, then Jamila's age can be expressed as:

Jamila's age = 2(Angelique's age + 1)

Substituting n for Angelique's age, we get:

Jamila's age = 2(n + 1)

Therefore, an expression in terms of n for Jamila's age is 2(n + 1)

Answer:

24

Step-by-step explanation:

4 x 8 = 32

4 + 4 + 8 + 8 = 24

Area = 32

Perimeter = 24

The probability that 2 containers will contain less than 2 defects is approximately 0.005184 or 0.5184%.%

We can solve this problem using the Poisson distribution. Let X be the number of defects on a product container, which is Poisson distributed with a mean of λ = 4.3.

To find the probability that a container has less than 2 defects, we can use the Poisson probability mass function:

P(X < 2) = P(X = 0) + P(X = 1)

The probability of X = 0 is:

[tex]P(X = 0) = e^(-λ) * λ^0 / 0! = e^(-4.3) ≈ 0.013[/tex]

The probability of X = 1 is:

[tex]P(X = 1) = e^(-λ) * λ^1 / 1! = e^(-4.3) * 4.3 / 1 ≈ 0.059[/tex]

Therefore, the probability that a randomly chosen container will have less than 2 defects is:

P(X < 2) = P(X = 0) + P(X = 1) ≈ 0.013 + 0.059 = 0.072

So, the probability that 2 containers will contain less than 2 defects is:

[tex]P(X_1 < 2 and X_2 < 2) = P(X < 2)^2 ≈ 0.072^2 = 0.005184[/tex]

Therefore, the probability that 2 containers will contain less than 2 defects is approximately 0.005184 or 0.5184%.

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