g(t) = 2t+4
h(t)=4t-2
Find (goh)(t)

Answer:

true

Step-by-step explanation:

cause I’ve done this before

The correct  equation is D. x2 + y2 + 6x − 24y + 148 = 0.

Equation is a physical and mathematical statement that describing physical phenomena and the relationship between different physical quantity typically consist of variable simple presenting physical quantity and then it personal variable may be pointed such as your energy.


This equation is the general form of a circle with center A and radius 5. The equation can be derived from the coordinates of the center A and the radius of the circle. The center of the circle is located at (-3, 12). To get the equation, first calculate the distance between the center A and a point on the circumference of the circle, which is the radius of the circle, 5. Then, use the Pythagorean theorem to calculate the equation of the circle: x2 + y2 + 6x – 24y + 148 = 0.
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f(x) is discontinuous.

Since LHS ≠ RHS ≠ f(x).

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

here, we have,

We have,

f(x) = x + 1, for x ≤ 2

f(x) = 2x - 1, for 1 < x < 2

f(x) = x - 1, for x < 1

Now,

A x = 1

LHS of f(x) = lim f((h - 1)) =  (h - 1 - 1) = 0 -2 = -2

RHS of f(x) = lim  f(h + 1) =  (2(h + 1) - 1) = 2h + 2 - 1 = 0 + 1

f(1) = x + 1 = 1 + 1 = 2

We see that,

LHS ≠ RHS ≠ f(x)

So,

f(x) is not continuous, it is discontinuous.

Thus,

f(x) is discontinuous.

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The complete question.

Show that the following functions are continuous or discontinuous at x = 1.

f(x) = x + 1, for x ≤ 2

f(x) = 2x - 1, for 1 < x < 2

f(x) = x - 1, for x < 1

The fraction of May's property that is left is 7/15.

A fraction is a value derived in such a way that it is a part of a given initial value. An example is one third of 12 is 4. In this case, 4 is a fraction of 12.

Considering the given question, we have;

let the total property of May be represented by 1, so that

fraction left after giving 1/5 to her son = 1 - 1/5

                             = (5 - 1)/ 5

                             = 4/ 5

The fraction left after giving 1/5 of her property to her son is 4/ 5.

So that;

the fraction left after she gave 1/3 to her daughter = 4/ 5 - 1/ 3

                                               = (12 - 5)/ 15

                                               = 7/ 15

Therefore, the fraction of her property left is 7/ 15.

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Graph appears to intersect the X axis in between 20 and 22 and algebraically the estimate of zero is 21.

Linear equations are equation involving one or more expressions including variables and constants and the variables are having no exponents or the exponent of the variable is 1.

Given a linear function which represents the profit of Bethany, y after x hours of dog walking.

(a) From the graph, we have to estimate the zero.

The graph seems to intersect the X axis in between 20 and 22, approximately 21.

(b) To solve this algebraically, we have the profit function,

y = 23x - 480

When y = 0,

23x - 480 = 0

23x = 480

x = 20.87 ≈ 21

Hence the graphical method gives the same estimate as the algebraic method.

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The longer side of the rectangle is the side that connects the points (-4,2) and (3,2), which have the same y-coordinate, so it is a horizontal line.

The length of this side is the distance between the x-coordinates of these two points, which is:

3 - (-4) = 7

Therefore, the length of the longer side of the rectangle is 7 units.

Answer:

C

Step-by-step explanation:

x + y + 10 = 0 ( subtract x + 10 from both sides )

y = - x - 10 → (1)

x² + y - 2 = 0 → (2)

substitute y = - x - 10 into (2)

x² - x - 10 - 2 = 0

x² - x - 12 = 0 ← in standard form

(x - 4)(x + 3) = 0 ← in factored form

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 4 = 0 ⇒ x = 4

Using the vertical line test we conclude that y is not a function of x.

When we have the graph of a relation, the vertical line test says that if we draw a vertical line over the graph and it intercepts the graph in more than one point, then the graph does not represent a function.

Here we have the graph of a circle, and there are multiple lines that intercept the graph twice (for example the line x = 0)

So we can conclude that this is not a function, thus, the correct option is A.

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The set of data that is skewed-right, there is at least 99.7% of the data within 3 standard deviations.

A statistical principle known as the empirical rule, also known as the three-sigma rule or 68-95-99.7 rule, holds that with a normal distribution, almost all observed data will lie within three standard deviations (denoted by ) of the mean or average (denoted by ).

Some points about standard deviation using Empirical Formula:

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The rate at which Mandy used up her bags of dog food is 2/3 bags per day

What is unit rate?

A unit rate is the cost for only one of anything. This is expressed as a ratio with a denominator of 1. For instance, if you covered 70 yards in 10 seconds, you did so at an average speed of 7 yards per second. Although both of the ratios—70 yards in 10 seconds and 7 yards in one second—are rates, only the latter is a unit rate.

Slope = change in y /change in x

Here,   Slope = change in bags of food/ /change in days

form the graph = 4/6  = 4  bags per 6 days

4/6 simplifies to 2/3

=>  2/3 bags per day

The rate at which Mandy used up her bags of dog food is 2/3 bags per day

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Answer:

(0.0301, 0.1733)

Step-by-step explanation:

[tex]\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\\\CI_{98\%}=\biggr(\frac{287}{522}-\frac{233}{520}\biggr)\pm 2.326\sqrt{\frac{\frac{287}{522}(1-\frac{287}{522})}{522}+\frac{\frac{233}{520}(1-\frac{233}{520})}{520}}\\\\\\CI_{98\%}\approx\{0.0300,0.1734\}[/tex]

Hence, the best choice is (0.0301, 0.1733) which tells us that we are 98% confident that the difference between the two proportions of men and women who successfully found Egypt on the map when highlighted is between 0.0301 and 0.1733

The accrued amounts are $32,796.58 and $706,396.44.

Compound interest is computed as interest on the principle of an account plus any accrued interest.

Compound interest can be calculated using the following formula:

x = P (1+r/n[tex])^{rt}[/tex]

,where x = compound interest

P = principal (the initial deposit or loan amount)

r = annual interest rate

n = the number of compounding periods per unit of time

t = the number of time units the money is invested or borrowed for

(a) If you invest $9,500 per period for 13 years at 10 percent.

First, convert R as a percent to r as a decimal

r = R/100

r = 10/100

r = 0.1 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 9,500.00(1 + 0.1/1[tex])^{13}[/tex]

A = 9,500.00(1 + 0.1[tex])^{13}[/tex]

A = $32,796.58

(b). If you invest $9,500 per period for 50 years at 9 percent,

First, convert R as a percent to r as a decimal

r = R/100

r = 9/100

r = 0.09 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 9,500.00(1 + 0.09/1[tex])^{50}[/tex]

A = $706,396.44

Therefore, the amounts are$32,796.58 and $706,396.44.

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Answer:

x = 54

Step-by-step explanation:

See picture below :)

The cost of the burger and the cost of an order of fries to Lynn would be :

From the problem, we know that Lynn spent $20.00 and purchased 4 hamburgers and 5 orders of fries. Similarly, we know that Ricardo spent $41.20 and purchased 10 hamburgers and 7 orders of fries, which gives us the equations:

4h + 5f = 20

10h + 7f = 41.20

Using substitution, we can express h in form of f to be :

4h + 5f = 20

4 [ ( 3 f + 1. 20 ) / 2] + 5 f = 20

6 f + 2 . 40 + 5 f = 20

11 f = 17. 60

f = $ 1. 60

We can then find the cost of hamburgers using the first equation :

4h + 5f = 20

4h + 5 ( 1. 60 ) = 20

4h + 8 = 20

4h = 12

h = $ 3

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The difference quotient expression for the given function is

[tex]\frac{f(x+h)-f(x)}{h} =\frac{\sqrt{(x+h+1)(x+h-1)}-\sqrt{(x+1)(x-1)} }{h}[/tex]

The expression in single-variable calculus is usually referred to as the difference quotient.

[tex]\frac{f(x+h)-f(x)}{h}[/tex]

When taken to the limit as h gets closer to zero, h frac f(x+h)-f(x)h, which gives the derivative of the function f.

The slope of a secant line passing through the curve of f(x) is measured by the difference quotient.

Consider the difference quotient formula,

[tex]\frac{f(x+h)-f(x)}{h}[/tex]

Evaluate the function at x = x + h

replace the variable x with (x + h) in the given expression

[tex]f(x+h)=\sqrt{(x+h)^2-1}[/tex]

simplify the result ,

[tex]f(x+h)=\sqrt{(x+h+1)(x+h-1)}[/tex]

find the components of the definition,

[tex]f(x+h)=\sqrt{(x+h+1)(x+h-1)}[/tex]

[tex]f(x)=\sqrt{(x+1)(x-1)}[/tex]

plug in the components,

[tex]\frac{f(x+h)-f(x)}{h} =\frac{\sqrt{(x+h+1)(x+h-1)}-\sqrt{(x+1)(x-1)} }{h}[/tex]

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The transformation from ABCD onto A'B'C'D' is a rigid transformation.

From the question, we have the following parameters that can be used in our computation:

A transformation maps ABCD onto A'B'C'D'

In order for a transformation to map square ABCD onto square A'B'C'D', certain congruence statements must be true.

The corresponding sides of ABCD and A'B'C'D' must have the same length i.e. AB = A'B', BC = B'C', CD = C'D', and DA = D'A'.

The corresponding angles of ABCD and A'B'C'D' must have the same measure i.e angle A = angle A', angle B = angle B', angle C = angle C', and angle D = angle D'.

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Financial plan - The cost of a jug of squeezed orange is $2.00 and the cost of pop is $1.00. These information propose that Sharon is augmenting her utility from the given fixed spending plan

A written financial program offers you a quantifiable objective to strive for. By monitoring your progress, you can eliminate doubt or uncertainty regarding your choices and make necessary adjustments to help you get past potential roadblocks.

Budgeting is the most crucial first step in financial planning. Making a budget is fairly simple; keeping one is more challenging! What matters is having the self-control to take the time as well as care to track and reconcile your spending in some way.

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The question you have indicated appears incomplete. However, here is a very similar example that uses the same logic and principles of probability and proportion. In this case, the proof is given below.

a.

Given: f(x) = 2(x+2)/5 , 0 <x< 1

Calculating P(0 <X< 1)

P(0 <X< 1) = ∫ f(x) dx {0.1}

Substitute 2(x+2)/5 for f(x)

P(0 <X< 1) = ∫ 2(x+2)/5 dx {0.1}

P(0 <X< 1) = 2/5 ∫(x+2) dx {0.1}

Integrate with respect to x

P(0 <X< 1) = 2/5 (x²/2+2x) {0.1}

P(0 <X< 1) = 2/5 (1²/2+2(1))

P(0 <X< 1) = 2/5 (½+2)

P(0 <X< 1) = 2/5 * 5/2

P(0 <X< 1) = 1 ----- Proved

b.

Here we're to solve for P(¼<X< ½)

P(¼<X< ½) = ∫ f(x) dx {¼,½}

Substitute 2(x+2)/5 for f(x)

P(¼<X< ½) = ∫ 2(x+2)/5 dx {¼,½}

P(¼<X< ½) = 2/5 ∫(x+2) dx {¼,½}

P(¼<X< ½) = 2/5 (x²/2+2x) {¼,½}

P(¼<X< ½) = 2/5 [ (½²/2+2(½)) - (¼²/2+2(¼))]

P(¼<X< ½) = 2/5 [(⅛+1)-(1/32 + ½)]

P(¼<X< ½) = 0.2375

The probability that more than ¼ but fewer than ½ of the people contacted will respond to this type of solicitation is 0.2375

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Full Question:

The proportion of people who respond to a certain mail-order solicitation is a continuous random variable X that has the density function f(x) = 2(x+2)/5 , 0 <x< 1, 0, elsewhere.

(a) Show that P(0 <X< 1) = 1.

(b) Find the probability that more than ¼ but fewer than ½ of the people contacted will respond to this type of solicitation.

The probability that $xo$ is shorter than $xp,$ $xq,$ and $xr.$ is,

⇒ 1/3

The term probability refers to the likelihood of an event occurring. Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.

Given that;

Let $pqr$ be an equilateral triangle, centered at $o$ a point $x$ is chosen at random inside the triangle.

Hence, The probability that $xo$ is shorter than $xp,$ $xq,$ and $xr.$ is,

⇒ 1/3

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Answer:

The value of l is 48. The formula to calculate volume (V) is V = l * w * h, so we can rearrange the equation to solve for l, or l = V/(w * h). In this case, l = 120/(5 * 4) = 48.

Answer:

125

Step-by-step explanation:

w

Answer:

43% * 258 = 110.94 (£110.94 is 43% of £258) 258 + 110.94 = 368.94

Step-by-step explanation:

The probability that now the card is indeed a diamond or a face card is [tex]\frac{11}{26}[/tex].

The probability that any random event will occur is referred to as probability. This expression is used to calculate the likelihood that a given event will occur. When we fling a coin into the air, as an illustration. Probability: P(A) = f / N calculates the probability that an event will take place. Ratios and probability are related, but the former determines the latter. When calculating the likelihood of an event, it is necessary to know the probability of that event.

When we find the probability, we obtain:

A typical deck of cards contains 52 cards. There are 12 face cards, known as the Kings, Queens, and Jacks, because there are four suits. There are a total of 13 diamonds, of which 3 are previously counted face cards. Hence, there are 10 diamonds that are faceless.

So, total Diamond & face card =22

Probability =[tex]\frac{22}{52}[/tex]=[tex]\frac{11}{26}[/tex].

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If Precision Engineering Factory consumes 12,500 units of a component in every three- month period.  the total cost of material is TZS 6,060 per year.

The annual demand for the material can be calculated as follows:

Annual demand = (12,500 units/3 months) x (4 quarters/year) = 50,000 units/year

Ordering cost = TZS 3 per order

Number of orders = (50,000 units/year) / (12,500 units/order) = 4 orders/year

Ordering cost per year = (4 orders/year) x (TZS 3/order) = TZS 12/year

Trucking cost = TZS 12 per order

Trucking cost per year = (4 orders/year) x (TZS 12/order) = TZS 48/year

Deterioration and obsolescence cost = TZS 0.04 per unit per year

Deterioration and obsolescence cost per year = (50,000 units/year) x (TZS 0.04/unit/year) = TZS 2,000/year

Interest cost = TZS 0.06 per unit per year

Interest cost per year = (50,000 units/year) x (TZS 0.06/unit/year) = TZS 3,000/year

Storage cost = TZS 1,000 per year for 50,000 units

Storage cost per unit per year = (TZS 1,000/year) / (50,000 units) = TZS 0.02/unit/year

Storage cost per year = (50,000 units/year) x (TZS 0.02/unit/year) = TZS 1,000/year

Total cost of material = Ordering cost + Trucking cost + Deterioration and obsolescence cost + Interest cost + Storage cost

Total cost of material = TZS 12/year + TZS 48/year + TZS 2,000/year + TZS 3,000/year + TZS 1,000/year

Total cost of material = TZS 6,060/year

Therefore, the total cost of material is TZS 6,060 per year.

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Answer:

Step-by-step explanation:

To solve for b, we can use the law of sines, which states that in any triangle ABC:

a/sin(A) = b/sin(B) = c/sin(C)

Here, we are given B = 150°, C = 20°, and c = 21 inches. We can solve for the remaining angle A by using the fact that the angles of a triangle add up to 180°:

A + B + C = 180°

A = 180° - B - C

A = 180° - 150° - 20°

A = 10°

Now we can use the law of sines to solve for b:

a/sin(A) = b/sin(B)

a = c * sin(A)/sin(C) = 21 * sin(10°)/sin(20°)

b = a * sin(B)/sin(A) = 21 * sin(10°)/sin(20°) * sin(150°)/sin(10°)

b = 21 * sin(150°)/sin(20°)

Using a calculator, we get:

b ≈ 41 inches (rounded to the nearest whole number)

Therefore, the length of side b is approximately 41 inches.

The percentage error of the student's estimated mass is 2.15%.

The percentage or percent error is the difference between the estimated value and the actual value divided by the actual value, multiplied by 100.

The estimated mass of the student = 82.0 kg

The actual mass of the student = 83.8 kg

Absolute error = Actual Value - Estimated Value

= 1.8 kg (83.8 - 82.0)

Percentage error = Actual Value - Estimated Value /Actual Value x 100

= 2.15% (1.8/83.8 x 100)

Thus, we can conclude that the student's estimate contains a 2.15% error.

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Answer:

54.2 cakes

Step-by-step explanation:

divide 380 by 7 and you'll get 54.2 as your answer

True. bar graphs (aka. column charts) with error bars are used to show the comparison between two variables, not the relationship.

A confidence intervals bar chart (shown as red lines)

In graphs, error bars are used to graphically show data variability and to denote error or uncertainty in reported measurements. They provide a basic indication of a measurement's accuracy or, alternatively, how far the true (error-free) value may deviate from the reported value. The standard deviation of uncertainty, the standard error, or a specific confidence range (such a 95% interval) are frequently represented as error bars. Due to the fact that these values are not the same, the measure chosen needs to be specified clearly in the graph or supporting text.

According to the definition the statement is true.

True. bar graphs (aka. column charts) with error bars are used to show the comparison between two variables, not the relationship.

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The Volume of Solid is 2,773.66 inch³ and Surface Area is

2,552.82 inch².

Surface area is the amount of space covering the outside of a three-dimensional shape.

Given:

Cylinder: Height = 30 inch, Radius = 5 inch

Semi sphere: radius = 5 inch

Cone: Height = 6 inch, radius = 5 inch, l= √r² + h² = 7.81 inch

Now, The Volume solid

= Volume of Semi sphere  + Volume of Cylinder + Vol. of Cone

= 2/3 πr³ + πr²H + 1/3 πr²h

= πr² (2/3 r + H + 1/3 h)

= 3.14 x 5 x 5 (2/3(5) + 30 + 1/3 (6))

= 78.5 x ( 10/ 3 + 30 + 2)

= 2,773.66 inch³

Now, the Surface Area of Solid

= SA (Cylinder+ S. Sphere + Cone)

= πr²H + 2πr² + 1/3 πrl

= πr (rH + 2r + 1/3l)

= 3.14 x 5 (150 + 10 + 2.60)

= 2,552.82 inch²

Now, the model is increased by 8 times then the dimensions are:

Cylinder: Height = 240 inch, Radius = 40 inch

Semi sphere: radius = 40 inch

Cone: Height = 48 inch, radius = 40 inch, l= √r² + h² = 62.48 inch

and, Now, The Volume solid after dilation

= Volume of Semi sphere  + Volume of Cylinder + Vol. of Cone

= 2/3 πr³ + πr²H + 1/3 πr²h

= πr² (2/3 r + H + 1/3 h)

= 3.14 x 40 x 40 (2/3(40) + 240 + 1/3 (48))

= 78.5 x ( 10/ 3 + 30 + 2)

= 1,420,117.33 inch³

Now, the Surface Area of Solid

= SA (Cylinder+ S. Sphere + Cone)

= πr²H + 2πr² + 1/3 πrl

= πr (rH + 2r + 1/3l)

= 3.14 x 5 (1200 + 80 + 20.82)

= 163, 382. 992 inch²

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Answer: $3,700 or $90,650

Step-by-step explanation:

Answer:

3,700

Step-by-step explanation:

i thibk thisisthay answer