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Answer: the bag 33.33 ect and the selecting of a red ball is 90%

Step-by-step explanation:

if a bag had three red balls, one blue ball and there are four ball intotal you would most likely get a red ball out of blue the other 10% is the blue ball and for the bags answer is just 100 divided by 3

Answer:

Step-by-step explanation:

Basically what you are doing is using the numbers from the first table to fill in the second table. To solve for the volume multiply the length, width, and height together of each size of the tank and fill in the volume box on the table. To solve for the capacity you're going to simply convert the volume which will be in cm^3 into Liters. If you can use a calculator for that thats great! If not just take what you have for the volume and divide it by 1000. To solve for the surface area you need three parts to add together. Width times the height, length times the height, and width times the length. Take those three components and then at them all together, and once you have that multiply that all by two.

Hope this helps!

Answer:

1st question answer in screeshoot

2nd answer

a. height of rectangular container = 6.6 cm

b. 4.25 L of more water is required to fill the container.

c. 37.03%  percentage of the tank is filled when it contains 2.5 L of water

Step-by-step explanation:

1st QUESTION

i) Volume of small tank = l x b x h

                                             = 24 ×18×15

  Volume of small tank = 6480 cm³            

Capacity of 1L small tank = 1000 cm³

Capacity of 6480 cm³ small tank = 6480 ÷ 1000 = 6.48 L

Total Surface Area of small tank = 2 (lb+bh+hl)

                                                         = 2 ([24×18] + [18×15] + [15×24])

                                                         = 2 (432+270+360)

                                                         = 2 (1062)

Total Surface Area of small tank = 2124 cm³

Curved Surface Area of small tank = 2(l+b) ×h

                                                            = 2 (24+18) ×15

                                                            = 2×42×15

Curved Surface Area of small tank = 1260 cm³

ii) Volume of medium tank = l x b x h

                                             = 30 ×21×20

  Volume of medium tank = 12600 cm³            

Capacity of 1L medium tank = 1000 cm³

Capacity of 12600 cm³ medium tank = 12600 ÷ 1000 = 12.6 L

Total Surface Area of medium tank = 2 (lb+bh+hl)

                                                         = 2 ([30×21] + [21×20] + [20×30])

                                                         = 2 (630+420+600)

                                                         = 2 (1650)

Total Surface Area of medium tank = 3300 cm³

Curved Surface Area of medium tank = 2(l+b) ×h

                                                            = 2 (30+21) ×20

                                                            = 2×51×20

Curved Surface Area of medium tank = 2040 cm³

iii) Volume of large tank = l x b x h

                                             = 36 ×24×25

  Volume of large tank = 21600 cm³            

Capacity of 1L large tank = 1000 cm³

Capacity of 21600 cm³ large tank = 12600 ÷ 1000 = 21.6 L

Total Surface Area of large tank = 2 (lb+bh+hl)

                                                         = 2 ([36×24] + [24×25] + [25×36])

                                                         = 2 (864+600+900)

                                                         = 2 (2364)

Total Surface Area of large tank = 4728 cm³

Curved Surface Area of large tank = 2(l+b) ×h

                                                            = 2 (36+24) ×25

                                                            = 2×60×25

Curved Surface Area of large tank = 3000 cm³

iv) Volume of extra large tank = l x b x h

                                             = 40 ×27×30

  Volume of extra large tank = 32400 cm³            

Capacity of 1L  extra large tank = 1000 cm³

Capacity of 32400 cm³ extra large tank = 32400 ÷ 1000 = 32.4 L

Total Surface Area of extra large tank = 2 (lb+bh+hl)

                                                         = 2 ([40×27] + [27×30] + [30×40])

                                                         = 2 (1080+810+1200)

                                                         = 2 (3090)

Total Surface Area of extra large tank = 6180 cm³

Curved Surface Area of extra large tank = 2(l+b) ×h

                                                            = 2 (40+27) ×30

                                                            = 2×67×30

Curved Surface Area of extra large tank = 4020 cm³

2. QUESTION

   a. Volume of rectangular container = l x b x h

       height of rectangular container    = [tex]\frac{Volume 0f rectangular container}{ l X b }[/tex]--------(i)

as we know 1L = 1000 cm³

      Volume of 2.5 L rectangular container = 2500 cm³

       length of container (l)= 15 cm

       width/breadth of container(b)=25cm

putting values in equation (i)                                                    

height of rectangular container = [tex]\frac{2500}{15X25}[/tex]

height of rectangular container =[tex]\frac{2500}{375}[/tex]

height of rectangular container = 6.6 cm    

b. Volume of new rectangular container = l x b x h-----------(ii)

length of container (l)= 15 cm

width/breadth of container(b)=25cm

height of container (h) = 18 cm

now putting values in equation (ii)

Volume of rectangular container = 15×25×18

Volume of new rectangular container = 6750 cm³

Volume of old rectangular container = 2500 cm³

difference = Volume of new rectangular container- Volume of old       rectangular container

difference = 6750 - 2500

difference = 4250 cm³

as we know 1L = 1000 cm³

difference =  4.25 L

c. Percentage filled = (Volume of water / Total capacity of tank) × 100--(iii)

we know  1 L = 1000 cm³

Volume of water = 2.5 liters = 2500 cm³  

Total capacity of tank = 6.75 liters = 6750 cm³

Now putting values in equation (iii)

Percentage filled = (2500 cm³ / 6750 cm³) × 100

Percentage filled = 37.03%        

Mean of team A  < Mean of team B

MAD of team A < MAD of team B

Now, We can simplify as,

The double dot plot shows the runs scored per game by two baseball teams during a 10 game seasons.

Now, We can find the value of mean as,

For team A,

Mean = (2 x 1 + 3 x 1 + 4 x 4 + 5x 2 + 6 x 1 + 7 x 1) / 10

Mean = (2 + 3 + 16 + 10 + 6 + 7) / 10

Mean = 44 / 10

Mean = 4.4

For team B;

Mean = (2 x 1 + 5 x 2 + 6 x 4 + 7 x 2 + 9 x 1) / 10

Mean = 59/10

Mean = 5.9

MAD for both team are,

For team A;

MAD = |4.4 - 2| + |4.4 - 3| + 4 |4.4 - 4| + 2 |4.4 - 5| + |4.4 - 6| + |4.4 - 7| / 10

MAD = 2.4 + 1.4 + 1.6 + 1.2 + 1.6 + 2.6 / 10

MAD = 1.08

For team B;

MAD = |5.9 - 2| + 2|5.9 - 5| + 4 |5.9 - 6| + 2 |5.9 - 7| + |5.9 - 9| / 10

MAD = 3.9 + 1.8 + 0.4 + 2.2 + 3.1 / 10

MAD = 1.14

Hence,

Mean of team A  < Mean of team B

MAD of team A < MAD of team B

To learn more about Scatter Plot visit:

brainly.com/question/6592115

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Answer:

Step-by-step explanation:

First, you need to know all the numbers. 4 occurs twice, 5 occurs once, 6 occurs twice, 7 doesn't occur, 8 occurs twice, and 9 occurs once. So, if you laid it out, it would look like this: 4,4,5,6,6,8,8,9.

So to find the sum, you add all of those together which will give you 50.

To find the mean, you will need to find the sum (50) and divide that by the number of values which can be shown as : 50/8 or 6 1/4.

So, the sum would be 50 and the mean would be 6 1/4.

Answer:

1st one 8/20

Step-by-step explanation:

Answer:

Sum = 4(2) + 5(1) + 6(2) + 7(0) + 8(2) + 9(1)

= 8 + 5 + 12 + 0 + 16 + 9

= 50

Mean = Sum/Frequency

= 50/8

= 6.25 rings

Answer:

Step-by-step explanation:

You want the Sum and Mean of the number of rings as listed in the given table.

The "frequency" line tells you the number of times the value above is included in the list. The expanded list of number of rings, taking frequency into account, is ...

  {4, 4, 5, 6, 6, 8, 8, 9}

The sum of these numbers is 50.

The average of these 8 numbers is 50/8 = 6.25.

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Answer: [tex]y = \frac{1}{4} x - 1[/tex]

Step-by-step explanation: In general, know that the equation for a linear graph is [tex]y = mx + b[/tex], where

In our case,

Answer:

Area of five squares = 1289.09 square units

Perimeter =  194.6 units

Step-by-step explanation:

Area of square and perimeter:

   First find the length of each square, then find the area of each square.

To find the area of five squares, add all the area of each square.

Side of square1 = 27 units

[tex]\sf Side \ of \ square2 = \dfrac{2}{3}*27=2*9 = 18 \ units\\\\Side \ of\ square3= \dfrac{2}{3}*18=2*6=12 \ units\\\\Side \ of \ square4=\dfrac{2}{3}*12=2*4=8 \ units\\\\Side \ of \ square5=\dfrac{2}{3}*8=\dfrac{16}{3}=5.3 \ units[/tex]

Area of square1 = 27*27 = 729 square units

Area of square2 = 18*18 = 324 square units

Area of square3 = 12*12 = 144 square units

Area of square4 = 8*8 = 64 square units

Area of square5 = 5.3*5.3 = 28.09 square units

Area of five squares = 729 + 324 + 144 + 64 +28.09

                                  = 1289.09 square units

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Perimeter of the composite figure = (27 + 27+27+9) + (18+18+6) +(12+12+4) + (8+8+2.7)+ (5.3+5.3+5.3)

                                                         = 90 + 42 + 28 + 18.7 + 15.9

                                                          = 194.6 units

Answer:

List: 4,4,5,6,6,8,8,9

Sum: 50

Mean: 6.25

Step-by-step explanation:

List: 4,4,5,6,6,8,8,9

(Frequency means number of times that the heading above occurs)

Sum: 50 (add them up)

Mean: 50/8=6.25 (Divide the sum by number of terms)

Answer: List: 4,4,5,6,6,8,8,9

Sum: 50

Mean: 6.25

Step-by-step explanation: just trying to make it simple:)

This theorem states that [tex]a^2+b^2=c^2[/tex], where c is the hypotenuse of a triangle and a and b are the legs (the other two sides).

As we can see from the image, we are given the lengths of the hypotenuse and one of the legs. Now, we must find x, the length of the other leg.

[tex]a^2+b^2=c^2[/tex]

Plug in the given lengths:

[tex]5^2+b^2=13^2[/tex]

Solve for b:

[tex]b=-12,12[/tex]

Since length cannot be negative, we know that b must be equal to 12.

x = 12 ft

The Pythagorean Theorem

This theorem states that , where c is the hypotenuse of a triangle and a and b are the legs (the other two sides).

Solution

As we can see from the image, we are given the lengths of the hypotenuse and one of the legs. Now, we must find x, the length of the other leg.

Plug in the given lengths:

Solve for b:

Since length cannot be negative, we know that b must be equal to 12.

Answer

x = 12 ft