The masses, moles, and number of molecules are as follows:
1. c. 1.4 x 10²⁴
2. b. 4.214 x 10²³ molecules
3. a. 1.2 x 10²²
4. a. 5.9 x 10²³
5. c. 8.0 x 10²³
6. d. 185.3 grams.
7. a. 23.7 grams
8. c. 127.3 grams
9. No answer in the option
10. a. 2.9 grams
What is the number of molecules?To determine the number of molecules in 265 grams of FeF₃:
First, calculate the number of moles of FeF₃:
moles = mass / molar mass
moles = 265 g / 139.839 g/mol
moles = 1.8939 mol
number of molecules = moles * Avogadro's number
number of molecules = 1.8939 mol * 6.022 x 10²³ molecules/mol
number of molecules = 1.138 x 10²⁴ molecules
2. To determine the number of molecules in 98 grams of FeF₃:
moles = 98 g / 139.839 g/mol = 0.7001 mol
number of molecules = 0.7001 mol * 6.022 x 10²³ molecules/mol
number of molecules = 4.214 x 10²³ molecules
3. To determine the number of atoms in 6.2 grams of silver:
moles = 6.2 g / 107.8682 g/mol = 0.0574 mol
number of atoms = 0.0574 mol * 6.022 x 10²³ atoms/mol
number of atoms = 3.457 x 10²² atoms
4. To determine the number of atoms in 54.2 grams of Manganese:
moles = 54.2 g / 54.938045 g/mol = 0.9876 mol
number of atoms = 0.9876 mol * 6.022 x 10²³ atoms/mol
number of atoms = 5.947 x 10²³ atoms
5. To determine the number of molecules in 250 grams of Cu(NO₃)₂:
moles = 250 g / (63.546 g/mol + 2 * 14.007 g/mol + 6 * 16.00 g/mol) = 250 g / 187.56 g/mol = 1.333 mol
number of molecules = 1.333 mol * 6.022 x 10^23 molecules/mol
number of molecules = 8.027 x 10^23 molecules
6. To determine the mass in grams of 6.2 x 10²⁴ molecules of water:
moles = (6.2 x 10²⁴ molecules) / (6.022 x 10²³ molecules/mol)
moles = 10.29 mol
mass = moles * molar mass
mass = 10.29 mol * 18.00 g/mol)
mass = 185.3 grams
7. To determine the mass in grams of 2.3 x 10²³ molecules of NO₃:
moles = (2.3 x 10²³ molecules) / (6.022 x 10²³ molecules/mol)
moles = 0.382 mol
mass = moles * molar mass
mass = 0.382 mol * (14.007 g/mol + 3 * 16.00 g/mol) = 23.7 grams
8. To determine the mass in grams of 9.7 x 10²³ atoms of selenium:
moles = (9.7 x 10²³ atoms) / (6.022 x 10²³ atoms/mol)
moles = 1.61 mol
mass = moles * molar mass
mass = 1.61 mol * 78.9718 g/mol = 127.3 grams
9. To determine the mass in grams of 3.4 x 10²⁴ atoms of osmium:
moles = (3.4 x 10²⁴ atoms) / (6.022 x 10²³ atoms/mol)
moles = 5.64 mol
mass = moles * molar mass
mass = 5.64 mol * 190.23 g/mol
mass = 1074.8 grams
10. To determine the mass in grams of 11 x 10²² molecules of oxygen:
moles = (11 x 10^22 molecules) / (6.022 x 10²³ molecules/mol)
moles = 0.182 mol
mass = moles * molar mass
mass = 0.182 mol * 16.00 g/mol
mass = 2.9 grams
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What is the energy of light with a wavelength of 589 nm? (The speed of light
in a vacuum is 3.00 × 108 m/s, and Planck's constant is 6.626 × 10-34 J.s.)
The energy of light with a wavelength of 589 nm is approximately 3.36 × 10^(-19) Joules.
To calculate the energy of light, we can use the equation E = hc/λ, where E represents the energy, h is Planck's constant (6.626 × 10^(-34) J·s), c is the speed of light in a vacuum (3.00 × 10^8 m/s), and λ is the wavelength of light.
Given that the wavelength is 589 nm (which is equivalent to 589 × 10^(-9) m), we can substitute the values into the equation:
E = (6.626 × 10^(-34) J·s × 3.00 × 10^8 m/s) / (589 × 10^(-9) m)
Simplifying the equation, we get:
E = (1.9778 × 10^(-25) J·m) / (5.89 × 10^(-7) m)
Dividing these values, we find:
E ≈ 3.36 × 10^(-19) J
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What Is the ph of a solution where [h30+]3.5*10-3=
The pH of the solution with a [H₃O⁺] concentration of 3.5 * 10^(-3) mol/L is approximately 2.456.
To determine the pH of a solution based on the concentration of H₃O⁺, you can use the equation:
pH = -log[H₃O⁺]
Given that [H₃O⁺] = 3.5 * 10^(-3) mol/L, we can substitute this value into the equation:
pH = -log(3.5 * 10^(-3))
To evaluate this using a calculator or math software:
pH ≈ -log(3.5 * 10^(-3)) ≈ -(-2.456) ≈ 2.456
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24.1.4 Quiz: Electric Force
Question 5 of 5
What could you do to increase the electric force between two charged
particles by a factor of 16?
A. Reduce one particle's charge by a factor of 4.
B. Increase one particle's charge by a factor of 16.
C. Increase one particle's charge by a factor of 4.
D. Reduce one particle's charge by a factor of 16.
The electric force increases by a factor of 16 when the distance is reduced by a factor of 4, hence option A is correct.
The nucleus and electrons are drawn to one another by the electric force. The void created by a positive or negative charge is referred to as an electric field, since it generates a field there.
The electric force is inversely linked to the square of the separation distance and directly connected to the product of the charges. It would be possible to treble the force by doubling both charges.
Reduce one particle's charge by a factor of 4, to increase the electric force between two charged particles by a factor of 16.
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25g of NH3 is mixed with 4 mole of O2 is the given reaction
a.which is the limiting reaction
b.what mass of no is formed
c.what mass of h2o is formed
Energy
4p
3d
4s
3p
3s
2p
2s
1s
Answer:
Energy
4p ⇵ ⇵ ⇵
3d ⇵ ⇵ ⇵ ⇵ ⇵
4s ⇵
3p ⇵ ⇵ ⇵
3s ⇵
2p ⇵ ⇵ ⇵
2s ⇵
1s ⇵
When the suns radiant energy for the Earth oceans, it causes water to change state by that rating which form of energy does water vapor have
Water vapor has latent heat energy, which is absorbed or released during the process of changing states from liquid to gas or gas to liquid.When the sun's radiant energy hits the Earth's oceans, it causes the water molecules to absorb this energy and become more energized.
This leads to the water molecules breaking apart and transforming into water vapor, which is a gaseous state of water. Water vapor has a specific form of energy known as latent heat. This is the energy required to change the physical state of water from a liquid to a gas or from a gas to a liquid. The process of converting water into water vapor requires energy, and this energy is stored in the water vapor in the form of latent heat.
The amount of latent heat absorbed or released by water vapor is dependent on the temperature and pressure conditions. When the water vapor condenses back into liquid form, this latent heat is released into the atmosphere. This process plays a critical role in weather and climate patterns as it drives the movement of heat and moisture throughout the Earth's atmosphere.
In summary, water vapor has latent heat energy, which is absorbed or released during the process of changing states from liquid to gas or gas to liquid. This energy plays a vital role in the Earth's weather patterns and is a critical component of the Earth's energy balance.
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Question 1
Recall all the models you described in task 1. (Rutherford, Dalton,and Bohr) Think about the results each model would predict for Thomson's experiment. Which atomic models does Thomson's experimental evidence support? Exp why these models are compatible with the experimental results.
Thomson's experimental evidence supports Rutherford's atomic model, as it aligns with the observed behavior of the cathode rays in the cathode ray tube experiment
Thomson's experiment, known as the cathode ray tube experiment, involved passing an electric current through a partially evacuated tube and observing the behavior of the cathode rays. Thomson discovered that the cathode rays were negatively charged particles, which later came to be known as electrons. Based on Thomson's experimental evidence, it is compatible with Rutherford's model, which proposed a dense positively charged nucleus and negatively charged electrons. Thomson's experiment indicated the presence of negatively charged particles (electrons) and their deflection towards the positively charged plate, supporting the idea of a small, dense, positively charged nucleus within the atom. In summary, Thomson's experimental evidence supports Rutherford's atomic model, as it aligns with the observed behavior of the cathode rays in the cathode ray tube experiment. The experiment provided strong evidence for the existence of negatively charged electrons within atoms and the presence of a small, dense, positively charged nucleus.
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I need help solving this problem can anybody help thank you.
The system will react by changing the concentrations to restore equilibrium when the CO and CO2 concentrations in the chemical equation 2CO + O2 2CO2 are raised. The system will try to reduce the rise in CO and CO2 by moving the reaction towards the products side, in accordance with Le Chatelier's concept.
The reaction will go forward as the CO concentration rises, eating part of the extra CO and turning it into CO2. This change lowers the excess CO concentration and aids in reestablishing equilibrium.
However, since CO2 is already a product, its concentration does not have a direct impact on the reaction. However, to keep the stoichiometric balance, it can result in a somewhat greater concentration of CO.
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How many atoms are in 94 g of NaCl
Answer: 9.78 X 10^223 atoms NaCl
Explanation:
Solve using Stoichiometry.
94 g NaCl X (1mole NaCl/58 gNaCl) X (6.02 X 10^23 atoms NaCl/1mole NaCl) = 9.78 X 10^23 atoms NaCl
Draw the orbital Diagram
The orbital diagram of the compound has been shown in the image attached.
What is the orbital diagram of a molecule?
The configuration of the molecular orbitals (MOs) within a molecule is shown in an orbital diagram of the molecule. Atomic orbitals from different molecules' individual atoms overlap to create molecular orbitals. According to the rules of quantum physics, electrons can fill these molecular orbitals.
Each chemical orbital is depicted in an orbital diagram by a line or a box, and the electrons are shown as arrows. The arrow's direction—upward for "spin up" and downward for "spin down"—indicates the spin of the electron.
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Rank the acids from strongest to weakest. To rank items as equivalent, overlap them.
HCl
HI
H2O
H2S
The ranking of the acids from strongest to weakest is: B) HI > A) HCl > D) H2S > C) H2O
To rank the acids from strongest to weakest, we need to consider their acid dissociation constants (Ka) or their respective pKa values. The lower the pKa value, the stronger the acid.
Here are the acids listed from strongest to weakest:
B) HI: Hydroiodic acid has a very low pKa value, indicating that it is a strong acid. It readily dissociates in water to release hydrogen ions (H+). HI is stronger than the other acids in the list.
A) HCl: Hydrochloric acid is also a strong acid with a low pKa value. It dissociates almost completely in water to produce H+ ions.
D) H2S: Hydrogen sulfide is a weak acid compared to HI and HCl. It has a higher pKa value, indicating that it does not dissociate as completely in water as the previous two acids. However, it still donates some hydrogen ions and exhibits acidic properties.
C) H2O: Water is considered a neutral substance with a pKa of 14. It can act as a weak acid or a weak base depending on the reaction it is involved in. In this list, it is the weakest acid. While it can donate a proton to form H+ ions, its tendency to do so is significantly lower compared to the other acids.
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An aqueous solution of ________ will produce a basic solution.
NaClO4
Na2SO3
NaNO3
LiBr
NH4I
Answer:
Explanation:
NH4I NH4 is ammonium thus a base. All other bases end with OH except ammonia which is NH3
Next the students place waxed paper in front of the light instead of the plastic.
Material Waxed Paper
Photograph of Screen Very blurry white image on gray background.
Does the waxed paper affect how the light hits the screen? Explain your response.
Yes, the waxed paper does affect how the light hits the screen. Waxed paper is a translucent material that diffuses light as it passes through.
When light passes through the waxed paper, it scatters in various directions due to the irregularities and texture of the paper's surface. This scattering of light results in a blurry white image on a gray background when the photograph is taken.
Compared to plastic, which is typically more transparent and smooth, waxed paper has a rougher surface and contains wax coatings that further contribute to light scattering. This diffusion of light reduces the sharpness and clarity of the image projected onto the screen.
The scattered light rays create a more diffused and less defined image, leading to a blurry appearance in the photograph.Therefore, the use of waxed paper instead of plastic alters the behavior of light, causing the light to scatter and resulting in a blurry white image on a gray background when projected onto the screen.
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What is the pH of a solution that has a [OH-] concentration equal to 1.36 × 10-10 M?
4.13
O 9.89
7.00
O 5.00
Answer:
Explanation:
pOH = -log1.36 X 10^-10 = 9.87
pH = 14-pOH = 14-8.97 = 5.03
if two magnets are placed on a table, which statement describes a situation with the most attraction between the two magnets
The north pole of one magnet is near the South pole of the other magnet.
The ends of a magnet are called its poles. One end is called the north pole, the other is called the south pole. If you line up two magnets so that the south pole of one faces the north pole of the other, the magnets will pull toward each other.
5. An alcoholic drink containing 216.0 g of H2O and 9.2 g of ethanol (C2H5OH) is bottled by adding CO2. If the mole fraction of water is 0.9 what approximate mass of CO2 is dissolved in it?
The approximate mass of CO2 dissolved in the alcoholic drink is 832.5 grams.
To calculate the approximate mass of CO2 dissolved in the alcoholic drink, we need to consider the mole fraction of water and the composition of the solution.First, let's determine the number of moles of water and ethanol in the solution:
Molar mass of H2O = 18.02 g/mol
Number of moles of H2O = mass of H2O / molar mass of H2O = 216.0 g / 18.02 g/mol = 11.994 mol
Molar mass of C2H5OH = 46.07 g/mol
Number of moles of C2H5OH = mass of C2H5OH / molar mass of C2H5OH = 9.2 g / 46.07 g/mol = 0.1998 mol
Next, we can calculate the mole fraction of ethanol:
Mole fraction of ethanol = (moles of C2H5OH) / (moles of H2O + moles of C2H5OH) = 0.1998 mol / (11.994 mol + 0.1998 mol) = 0.0164
Since the mole fraction of water is given as 0.9, we can calculate the mole fraction of CO2:
Mole fraction of CO2 = 1 - (mole fraction of water + mole fraction of ethanol) = 1 - (0.9 + 0.0164) = 0.0836
Now, we need to determine the mass of CO2 dissolved in the solution. Assuming ideal behavior, we can use Raoult's law to calculate the approximate mass of CO2:
Mass of CO2 = (mole fraction of CO2) * (molar mass of CO2) * (total mass of the solution)
= 0.0836 * 44.01 g/mol * (216.0 g + 9.2 g)
= 0.0836 * 44.01 g/mol * 225.2 g
≈ 832.5 g
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What is the molarity of a solution which contains 58.4 g of CsF dissolved in 500. mL of solution?
Answer:
0.768 mol/L
Explanation:
Given, mass of CsF = 58.4 gm
Molar mass of CsF = Molar mass of Cs + Molar mass of F
= 133 u + 19 u
= 152 u
Number of moles of CsF = Mass of CsF/ Molar mass of CsF
= 58.4/152 mol
Given, volume of solution = 500 mL = 0.5 L
Molarity of solution = moles of solute/volume of solution
= (58.4/152) mol / 0.5 L
= 58.4 * 2/152 mol/L
= 0.768 mol/L
Calculate the pOH if the [OH-] concentration is 5.9 x 10_, M? Is the solution ACIDIC, BASIC, or NEUTRAL?
If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.
To calculate the pOH of a solution, we can use the formula:
pOH = -log[OH-]
Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:
pOH = -log(5.9 x 10^(-M))
Calculating this expression, we find:
pOH = -log(5.9 x 10^(-M))
pOH ≈ -log(5.9) + (-log(10^(-M)))
Since log(10^(-M)) is equal to -M, the equation simplifies to:
pOH ≈ -log(5.9) - M
Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.
If we consider M = 6, for instance, the equation becomes:
pOH ≈ -log(5.9) - 6
Now, we can evaluate the expression:
pOH ≈ 1.23 - 6
pOH ≈ -4.77
Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.
To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.
Since pOH = -4.77, the pH would be:
pH = 14 - pOH
pH ≈ 14 - (-4.77)
pH ≈ 18.77
A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.
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Estimate the pH and Fraction (in terms of percentage) CH3COOH molecules deprotonated in 0.15 M CH3COOH
The pH of the 0.15 M [tex]CH_3COOH[/tex] solution is approximately 2.38. and around 2.9% of the [tex]CH_3COOH[/tex] molecules in the 0.15 M solution are deprotonated.
Acetic acid ([tex]CH_3COOH[/tex]) is a weak acid that only partially dissociates in water to form [tex]H^+[/tex] ions and [tex]CH_3COO^-[/tex] ions. To estimate the pH and fraction of [tex]CH_3COOH[/tex]molecules deprotonated in a 0.15 M [tex]CH_3COOH[/tex]solution, we can use the following equations and approximations:
The dissociation constant for acetic acid (Ka) is 1.8 x 10^-5.
The initial concentration of [tex]CH_3COOH[/tex] is equal to its concentration at equilibrium, since it only partially dissociates.
The concentration of [tex]H^+[/tex] ions is equal to the concentration of [tex]CH_3COO^-[/tex] ions at equilibrium, since the dissociation reaction involves a 1:1 ratio of [tex]H^+[/tex] ions to [tex]CH_3COO^-[/tex] ions.
Using these approximations, we can set up an equilibrium expression for the dissociation of [tex]CH_3COOH[/tex] :
[tex]Ka = [H^+][CH_3COO^-]/[CH_3COOH][/tex]
We also know that the initial concentration of [tex]CH_3COOH[/tex] is 0.15 M. Let x be the concentration of [tex]H^+[/tex] ions and [tex]CH_3COO^-[/tex] ions at equilibrium. Then:
[[tex]H^+[/tex]] = x
[[tex]CH_3COO^-[/tex]] = x
[[tex]CH_3COOH[/tex]] = 0.15 - x
Substituting these values into the equilibrium expression and solving for x, we get:
Ka = x^2 / (0.15 - x)
1.8 x 10^-5 = x^2 / (0.15 - x)
x = 0.0042 M
The pH can be calculated using the formula:
pH = -log[[tex]H^+[/tex]]
pH = -log(0.0042)
pH = 2.38
Therefore, the pH of the 0.15 M [tex]CH_3COOH[/tex] solution is approximately 2.38.
To estimate the fraction of [tex]CH_3COOH[/tex] molecules that are deprotonated, we can use the equation:
Fraction deprotonated = [tex][CH_3COO^-] / [CH_3COOH][/tex] x 100%
At equilibrium, the concentration of [tex]CH_3COO^-[/tex] ions is equal to the concentration of [tex]H^+[/tex] ions, which we calculated to be 0.0042 M. The concentration of [tex]CH_3COOH[/tex] at equilibrium is 0.15 - 0.0042 = 0.1458 M. Substituting these values into the equation, we get:
Fraction deprotonated = 0.0042 / 0.1458 x 100%
Fraction deprotonated = 2.9%
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Which best explains why an Al 3+ ion is smaller than an Al atom?
In forming the Al³+ ion, the Al atom loses the electrons in its outermost energy
level, causing a decrease in the atomic radius.
In forming the Al3+ ion, the Al atom gains three protons and the resulting net
positive charge keeps the electrons more strongly attracted to the nucleus,
reducing the radius.
The Al3+ ion contains more electrons than the Al atom, which results in a greater
attraction for the nucleus and a smaller atomic radius.
In forming the A13+ ion, the Al atom adds electrons into a higher energy level,
causing a decrease in the atomic radius.
There are more protons in an Al3+ ion than there are in an Al atom.
In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius, hence option A is correct.
The number of protons in the nucleus of AlandAl3+ AlandAl3+ is the same, however there are differing numbers of electrons in the final shell. Al³⁺ is smaller than Al because it has fewer electrons.
The Al atom will become an Al³⁺ ion when it loses its third electron and develops a tri-positive charge on it. In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius.
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Urgent help please!!!!
Use the information and graphs to answer the following question.
Trial 1
Trial 2
Energy (kJ)
55 50 35 30 250 15 1050
50
Energy (kJ)
50 5 0 125 30 25 2015 10 50
Time (sec)
Which of the following correctly identifies the reaction that was carried out with a catalyst?
Time (sec)
A Trial 2, because it decreased the rate of the reaction
B Trial 1, because it decreased the activation energy needed for the reaction to occur
C Trial 2, because it decreased the activation energy needed for the reaction to occur
D Trial 1, because it decreased the rate of the reaction
The graph that correctly identifies the reaction that was carried out with a catalyst is Trial 2 because it decreased the activation energy needed for the reaction to occur. The correct option is C.
What are catalysts?Catalysts are substances that increase the rate of a chemical reaction without undergoing any permanent changes themselves.
Catalysts increase the rate of a chemical reaction by lowering the activation energy required for the reaction to occur.
Catalysts have the following features:
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To prepare zinc sulphate eye drops APF (Australian Pharmaceutical Formulary), the following ingredients are provided:
1) chlorobutol aqueous solution (0.67% w/v),
2) zinc sulphate monohydrate,
3) boric acid powder,
4) glycol aqueous solution (50% w/v)
Calculate the amount of each ingredients needed to prepare 70 mL of zinc sulphate eye drops APF. Show your working.
To prepare 70 mL of zinc sulfate eyedrops APF, you would need the following ingredients:
Zinc sulfate monohydrate: 0.07 g
Chlorobutol aqueous solution: 10.45 mL
Boric acid powder: 0.7 g
Glycol aqueous solution: 0.14 mL
To calculate the amount of each ingredient needed to prepare 70 mL of zinc sulfate eye drops APF, we'll follow these steps:
Step 1: Determine the concentration of zinc sulfate needed. Since the recipe doesn't specify the concentration, we'll assume a standard concentration of 0.1% w/v.
Step 2: Calculate the amount of zinc sulfate required. The desired concentration is 0.1% w/v, and we need to prepare 70 mL of the eye drops. Therefore, the amount of zinc sulfate needed can be calculated as follows:
Amount of zinc sulfate (g) = (Desired concentration (g/100 mL) * Volume (mL))/100
= (0.1 * 70)/100
= 0.07 g
Step 3: Determine the amounts of other ingredients based on the provided ratios. The chlorobutol solution is at a concentration of 0.67% w/v, so we need to calculate the volume required using the ratio:
Volume of chlorobutol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of chlorobutol (%)
= (0.07 * 100)/0.67
= 10.45 mL
The boric acid powder doesn't specify the concentration, so we'll assume it to be 1% w/v. Using the same logic, we can calculate the amount of boric acid powder required:
Amount of boric acid powder (g) = (Desired concentration (g/100 mL) * Volume (mL))/100
= (1 * 70)/100
= 0.7 g
Finally, the glycol solution is at a concentration of 50% w/v, so the volume required can be calculated as:
Volume of glycol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of glycol (%)
= (0.07 * 100)/50
= 0.14 mL
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Proton, Neutron and Electron of 23 13 Aluminum
The atomic mass of Aluminum is 23, which means it has a total of 23 particles in its nucleus, including protons and neutrons.
Aluminum has an atomic number of 13, which means it has 13 protons in its nucleus.
To find the number of neutrons, we subtract the atomic number from the atomic mass. So, Aluminum has 23 - 13 = 10 neutrons in its nucleus. Electrons are the negatively charged particles that orbit around the nucleus of an atom.
Aluminum, being a neutral atom, has an equal number of electrons to the number of protons in its nucleus, which is 13. These electrons are distributed in different energy levels or shells around the nucleus.
Aluminum is a widely used metal in different applications due to its unique properties such as low density, high strength, and resistance to corrosion. It is used in the manufacturing of cans, foils, and aircraft parts. The number of protons and electrons determines the atomic number and chemical properties of an element. The number of neutrons affects the stability and isotopes of an element.
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if 3 moes of cl reacts with 3 moles oxygen, then which substance is the limitting reactant and excess reactant
If 3 moles of cl reacts with 3 moles oxygen, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions.
To determine the limiting reactant and excess reactant, we need to compare the stoichiometry of the reaction to the given amounts of each reactant.
The balanced chemical equation for the reaction between chlorine (Cl2) and oxygen (O2) can be represented as follows:
2Cl2 + O2 → 2Cl2O
According to the balanced equation, it requires 2 moles of chlorine (Cl2) to react with 1 mole of oxygen (O2) to produce 2 moles of chlorine oxide (Cl2O).
Given that we have 3 moles of chlorine (Cl2) and 3 moles of oxygen (O2), we can determine the limiting reactant by comparing the ratio of moles between the two reactants.
The ratio of Cl2 to O2 required for complete reaction is 2:1. However, since we have equal amounts of Cl2 and O2 (both 3 moles), neither reactant is present in excess.
Therefore, in this scenario, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions. All of the chlorine and oxygen will be consumed in the reaction, resulting in the complete conversion to chlorine oxide (Cl2O).
It's important to note that if the amounts of Cl2 and O2 were different, the reactant present in lesser quantity would be the limiting reactant, and the reactant in greater quantity would be the excess reactant.
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Name a liquid substance that could be used in the laboratory for dissolving dry mortar on floor tiles
Answer:muriatu acid
Explanation:
SOMEONE PLEASEHELP!!!!!!! Using the graph to the right, answer the following questions:
1. What is the half-life of the radioactive isotope?
2. If someone had 4,000g of the sample remaining, how many half-lives has the sample gone through?
3. How many days would it take to have only 1,000g of the sample remaining?
^^^^show work!!!!!
The half-life of the radioactive isotope is 8 days.
Mass at 8 days = 8000 g
Number of half-lives in 4000 g = 8000 / 4000 = 2 half life
Time needed for 1000g to remain is 32 days.
The half life of a chemical reaction is the time required by the substance to reach half of its concentration. It is a characteristic property of the unstable atomic nuclei and the way in which they decay.
For a given reaction the half life of a reactant is the time required for its concentration to reach a value that is the arithmetic mean of its initial and final value. For a reactant that is entirely consumed it is the time taken for the reactant concentration to fall to one half of its initial value.
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True or False Polyunsaturated fatty acids are precursors of other molecules.
Dietary fats include polyunsaturated fat. Along with monounsaturated fat, it is one of the good fats. Foods like salmon, vegetable oils, and other plant- and animal-based foods include polyunsaturated fat. They act as precursors of other molecules. The given statement is true.
Precursors of eicosanoids with hormone-like properties including prostaglandins, leukotrienes, and thromboxanes are polyunsaturated fatty acids (PUFA).
Dihomo-linolenic acid (DGLA), arachidonic acid (AA), and eicosapentaenoic acid (EPA) are the three precursors that prostaglandins can be formed from. Depending on the precursor, series 1, 2, or 3 prostanoids is produced.
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Please help for brainliest
Curious Carl's chemistry teacher asked him to make a sugar solution. Carl dissolved 400 grams of sucrose (C12H22O11 , molar mass 342.3mol) in 1.00 L of water.
If molarity = moles/liter, what is the molarity of Carl's sugar solution?
Question 31 options:
1.2 M
0.86 M
0.40 M
1.0 M
Answer:
The molarity of Carl's sugar solution can be calculated using the formula:
Molarity = moles of solute / liters of solution
First, we need to determine the number of moles of sucrose in the solution. We can do this using the formula:
moles = mass / molar mass
The mass of sucrose is 400 grams, and the molar mass is 342.3 g/mol:
moles = 400 g / 342.3 g/mol
moles = 1.167 mol
Now we can calculate the molarity by dividing the moles by the liters of solution (which is 1.00 L):
Molarity = 1.167 mol / 1.00 L
Molarity = 1.2 M
Therefore, the molarity of Carl's sugar solution is 1.2 M. Answer: 1.2 M.
Explanation:
I would like a basic rundown, and explanation for the problem.
2 FeCl2 + Cl2 → 2 FeCl3
If 1.8384 moles of FeCl3 are produced, how many moles of Cl2 were reacted?
Answer:
0.9192mol
Explanation:
2 FeCl2 + Cl2 → 2 FeCl3
Cl2 : FeCl3
1 : 2
X : 1.8384
X= 1.8384/2
X= 0.9192
I hope it helps :)
Question 4 of 10
In what way does the shape of a molecule affect how the molecule is
involved with living systems?
OA. It determines what elements are in the molecule.
OB. It determines oxidation states present in the molecule.
OC. It determines how the molecule functions.
OD. It determines the weight of the molecule.
SUBMIT
