Answer:
Below
Explanation:
Speed of light : 3 x 10^8 m/s
4500 km = 4,500,000 m
4 500 000 m / 3 x 10^8 m/s = .015 s
reposting this question
a plane is flying north at 30 m/s. it is encountering wind blowing east at 5m/s. what is the airplane's speed?
Answer:
30.41 m/s
Explanation:
To solve this problem, we can use vector addition. We can represent the velocity of the plane as a vector pointing north with a magnitude of 30 m/s, and the velocity of the wind as a vector pointing east with a magnitude of 5 m/s.
The speed of the airplane is the magnitude of the resultant vector, which is the vector sum of the velocity of the plane and the velocity of the wind. To find the magnitude of the resultant vector, we can use the Pythagorean theorem:
magnitude of resultant vector = sqrt((30 m/s)^2 + (5 m/s)^2) = sqrt(900 m^2/s^2 + 25 m^2/s^2) = sqrt(925 m^2/s^2) = 30.41 m/s
Therefore, the speed of the airplane is approximately 30.41 m/s.
What type of transformation has triangle ABC undergone to form the triangle A B C
The type of transformation which triangle ABC has undergone to form the triangle A B C is a vertical reflection which is therefore denoted as option D.
What is Vertical reflection?A vertical reflection reflects a graph vertically across the x-axis, while on the other hand a horizontal reflection reflects a graph horizontally across the y-axis.
The type of transformation on triangle is across the x-axis which us therefore the reason why vertical reflection was chosen as the correct choice.
Read more about Vertical reflection here https://brainly.com/question/29881815
#SPJ1
Answer:
D. vertical reflection
Explanation:
When two objects are in contact with no relative motion, which of the following statements about the frictional force between them, is true? (FN is the normal force.)a. The frictional force is always equal to μknb. The frictional force is always less than μknc. The frictional force is determined by other forces on the objects so it can be either equal to or less than μkn.
The frictional force may have a magnitude that is equal to or less than sn.
What kind of motion occurs when two bodies do not move relative to one another?Static denotes being still. Static friction is the friction that exists between two surfaces that are in contact when there is no relative motion between them. It is a force that self-adjusts.
Static friction occurs when the two surfaces that are creating it are neither moving nor sliding in relation to one another.The frictional force that exists between surfaces while they are at rest in relation to one another is known as static friction. When a tiny amount of force is applied, the static force's magnitude is identical in the other direction.
to know more about frictional force here;
brainly.com/question/30280752
#SPJ1
A load Q = -820 nC is uniformly distributed in a ring of radius 2.4 m. A point load q = +530 nC is stationary in the centre of the ring. Points A and B lie on the axis of the ring. What is the minimum work that an external force must produce to transfer the electron from B to A? (e = 1,60 × 10-19 C, k = 1/4pe0 = 8,99 × 109 N∙m2/C2)
To calculate the minimum work required to move the point charge q from point B to A, we need to calculate the electric potential difference between the two points, and then use the equation W = qΔV, where W is the work done, q is the charge being moved, and ΔV is the potential difference.
To find the electric potential at point A and B due to the charged ring, we can use the equation for electric potential due to a charged ring:
V = kQ/r
Where k is Coulomb's constant, Q is the total charge of the ring, and r is the distance from the center of the ring to the point where the potential is being calculated.
For point B, the potential due to the charged ring is:
VB = kQ/r = (8.99 × 10^9 N·m^2/C^2) * (-820 × 10^-9 C) / (2.4 m) = -306.55 V
For point A, the potential due to the charged ring is:
VA = kQ/r = (8.99 × 10^9 N·m^2/C^2) * (-820 × 10^-9 C) / (4.8 m) = -153.27 V
The potential difference between point A and B is:
ΔV = VA - VB = (-153.27 V) - (-306.55 V) = 153.28 V
The minimum work required to move the charge q from point B to A is:
W = qΔV = (530 × 10^-9 C) * (153.28 V) = 81.09 × 10^-6 J
Therefore, the minimum work required to transfer the electron from B to A is 81.09 × 10^-6 J.
When does magnetic force push objects apart?
A: when opposite poles of two magnets are facing each other
B: never
C: when like poles of two magnets are facing each other
D: when the objects are made of wood
When two magnets' opposing poles are lined up with one another (option A).
Is strength equivalent to force?As a result of their seeming comparable definitions, force and power are frequently employed interchangeably. They are not equivalent, nevertheless, in physics. Power is a statement of energy used over time, of which force is a component, while force is the essential outcome of a collision between two objects.
What generates force?Every time two things interact, a force is applied to each of them. The force is lost when the interaction between the two items ends. Only through interactions can forces be created.
To know more about Force visit:
https://brainly.com/question/13191643
#SPJ1
which of the following displays would be best to use for your lab 3 part v requirement since it has the decoder circuitry embedded on itself?
I'm sorry, but I would need more information about the lab 3 part v requirement to provide an accurate answer to this question. Please provide more context or details about the lab and the requirements for part v.
explain how the sun drives convection currents in the ocean and in the atmosphere
Answer:
here u go
Explanation:
The heating of the Earth's surface and atmosphere by the sun drives convection within the atmosphere and ocean. This convection produces winds and ocean currents. The greater the pressure differences between a low-pressure area and a high-pressure area, the stronger the winds.
A 11 N force moves an object 9 m. What is the work?
Answer :
99 JoulesStep-by-step explanation :
Given:
Force = 11 N Displacement = 9 mWork done = Force × Displacement
On substituting the values, we get :
Work done = 11 × 9
Work done = 99 joules
A man pushes a lawn mower on a level lawn with a force of 207 N. If 41% of this force is directed forward, how much power does he expend in pushing the mower 4.8 m in 18 s?
The power which is required to push the mower on a level lawn with a force of 207 N will be 32.568 watts.
What is Power?Power can be defined as the rate of work done per unit of time taken to move or displace an object from one location to another location.
When considering work done on the object, we always take the force directed along the axis of motion, which is in this case, the horizontal axis. If 59% of the force is directed downward, then 41% of the force is being directed horizontally, so the horizontal force is
207 × 0.59 = 122.13N,
Work done = Force applied × displacement of the object
Work done = 122.13 × 4.8 = 586.22 Joules
Power = Work done/ Time taken
Power = 586.22/ 18
Power = 32.568 watts (W)
Therefore, the power will be 32.568 watts.
Learn more about Power here:
https://brainly.com/question/13787582
#SPJ1
Learning Goal:
To understand the meaning of Kepler's second law of planetary motion.
Part A
Parts A through C all refer to the orbit of a single comet around the Sun.
Each of the four diagrams below represents the orbit of the same comet, but each one shows the comet passing through a different segment of its orbit around the Sun. During each segment, a line drawn from the Sun to the comet sweeps out a triangular-shaped, shaded area. Assume that all the shaded regions have exactly the same area. Rank the segments of the comet’s orbit from left to right based on the length of time it takes the comet to move from Point 1 to Point 2, from longest to shortest. If you think that two (or more) of the diagrams should be ranked as equal, drag one on top of the other(s) to show this equality.
According to Kepler's Second Law, as a planet orbits the Sun, an imaginary line connecting them sweeps across the same amount of space. This means that planets need not travel along their orbits speed.
What purposes does Kepler's law serve?The study of the motion the planets, asteroids, or other space objects inside the solar system makes extensive use of Kepler's laws. They are still used today to create and launch satellites into orbit. The Kepler principles served as inspiration for Newton, who then proposed his original three laws of motion and the concept of universal gravitation.
What is the name of Kepler's first law?The planets' orbits are ellipses with the light at one focus, according to Kepler's First Law, sometimes referred to as The Law on Ellipses. The line between such a planet or the sun sweeps forth equal areas inside the plane of planetary system over equal times, according to Kepler's Second Law, often known as The Law for Equal Areas at Equal Time.
To know more about speed visit:
https://brainly.com/question/28224010
#SPJ1
6. Find the total impulse of the following graph
The total impulse here is the sum of area of the rectangle and area of the triangle. Here, area of the rectangle is 18 Ns and area of the triangle is -2 Ns, then the total impulse is 16 N.s.
What is impulse ?
Impulse is a physical quantity which measures the change in momentum of the object. The change in momentum is equal to the product of force and time.
thus impulse = F t
From the graph, impulse = area of rectangle + area of triangle
area of rectangle = lb = 2 s × 6 N = 18 N s
area of triangle = 1/2 bh = 1/2 2 s × -2 N = - 2 N.s
Total impulse from the graph = -2 Ns + 18 Ns = 16 N.s.
Therefore, the total impulse of the object obtained from the graph is 16 N.s.
Find more on impulse:
https://brainly.com/question/9441152
#SPJ1
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.34 m. The mug slides off the counter and strikes the floor 0.60 m from the base of the counter.
(a) With what velocity did the mug leave the counter?
(b) What was the direction of the mug's velocity just before it hit the floor?
The cup left the counter with a speed of 5.16 m/s.
What is its maximum speed?An object's ultimate velocity can be expressed as: v = u + at, where v is the final velocity. The final velocity of an object is equal to its original velocity plus acceleration multiplied by the distance it traveled.
The conservation of energy principle can be used to determine the speed at which the cup departed from the counter.
The following factors determine the mug's potential energy:
PE = mgh
PE = (m)(9.81 m/s²)(1.34 m) = 13.3m J
where J denotes joules.
KE = (1/2)mv²
v = sqrt(2PE/m) = sqrt(2gh)
With the values from the problem substituted, we obtain:
v = sqrt(2 x 9.81 m/s²x 1.34 m) = 5.16 m/s.
The mug's velocity was downward or vertically downward shortly before it impacted the ground.
To know more about velocity visit:-
https://brainly.com/question/17127206
#SPJ1
a ball, kicked towards the south end of the field, moves a total of 130 meters in 20 seconds. find the velocity
Answer:
The velocity of the ball can be found by dividing the total distance (130 meters) by the total time (20 seconds). This gives a velocity of 6.5 m/s
A baseball rolls off a 0.70 m high desk and strikes the floor 0.25 m away from the base of the desk. How far was the ball rolling?
Answer:0.66m/s
Explanation:
We can calculate the time it takes for the ball to fall to the floor. y = (1/2) a t^2 t = sqrt { 2y / g } t = sqrt { (2) (0.70 m) / (9.80 m/s^2) } t = 0.378 seconds In a time of 0.378 seconds, the ball traveled a horizontal distance of 0.25 meters. We can find the horizontal speed when the ball was rolling on the desk. v = d / t v = 0.25 m / 0.378 s v = 0.66 m/s The ball was rolling at a speed of 0.66 m/s when it was rolling on the desk.
Gasoline vapor is injected into the cylinder of an automobile engine when the piston is in its expanded position. The temperature, pressure, and volume of the resulting gas-air mixture are 20 °C, 1.00x105N/m², and 240 cm3, respectively. The mixture is then compressed adiabatically to a volume of 40 cm3. (Note that in the actual operation of an automobile engine, the compression is not quasi-static, although we are making that assumption here). a) (10 pts) What are the pressure and temperature of the mixture after the compression? b) (10 pts) How much work is done by the mixture during the compression?
Answer:
a) the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b)the work done by the mixture is zero.
Explanation:
we can use the ideal gas law and the adiabatic compression equation.
a) Using the ideal gas law, we can find the initial number of moles of gas-air mixture in the cylinder:
PV = nRT
n = PV/RT = (1.00x105 N/m²)(240 cm³/1000 cm³/m³)/(8.31 J/mol•K)(20+273 K) ≈ 0.027 mol
Since the mixture is compressed adiabatically, we can use the adiabatic compression equation to find the final pressure and temperature:
P1V1^γ = P2V2^γ
where γ = Cp/Cv is the ratio of specific heats of the mixture.
Assuming the gas-air mixture behaves as a diatomic gas, we can use the values γ = 1.4 and Cp = 29.1 J/mol•K and Cv = 20.8 J/mol•K.
Substituting the given values, we can solve for the final pressure and temperature:
P2 = P1(V1/V2)^γ = (1.00x105 N/m²)(240 cm³/40 cm³)^1.4 ≈ 8.13x105 N/m²
T2 = T1(V1/V2)^(γ-1) = (20+273 K)(240 cm³/40 cm³)^0.4 ≈ 439 K
Therefore, the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b) The work done by the mixture during the compression can be found using the equation:
W = -ΔU
where ΔU is the change in internal energy of the mixture.
Since the compression is adiabatic, there is no heat transfer and ΔU = Q = 0.
Therefore, the work done by the mixture is zero.
The velocity v of a particle moving in the xy plane is given by =(6.0t−4.0t 2) i^ +8.0 j^ , with v in meters per second and t(>0) in seconds.(a) What is the acceleration when t=3.0s ?
(b) When (if ever) is the acceleration zero? (c) When (if ever) is the velocity zero? (d) When (if ever) does the speed equal 10m/s?
The given velocity of the particle moving in the xy plane is:
v = (6.0t - 4.0t^2) i^ + 8.0 j^
(a) To find the acceleration when t = 3.0s, we differentiate the velocity with respect to time:
a = dv/dt = (6.0 - 8.0t) i^
Substituting t = 3.0s, we get:
a = (6.0 - 8.0(3.0)) i^ = -18.0 i^
Therefore, the acceleration when t = 3.0s is -18.0 m/s^2 in the x-direction.
(b) To find when the acceleration is zero, we set the acceleration to zero and solve for t:
a = (6.0 - 8.0t) i^ = 0
Solving for t, we get:
t = 0.75 seconds
Therefore, the acceleration is zero when t = 0.75 seconds.
(c) To find when the velocity is zero, we set the velocity to zero and solve for t:
v = (6.0t - 4.0t^2) i^ + 8.0 j^ = 0
Solving for t, we get:
t = 0 seconds and t = 1.5 seconds
Therefore, the velocity is zero at t = 0 seconds and t = 1.5 seconds.
(d) To find when the speed equals 10 m/s, we first need to find the magnitude of the velocity:
|v| = sqrt((6.0t - 4.0t^2)^2 + 8.0^2)
Setting this equal to 10 m/s and solving for t, we get:
t = 0.981 seconds and t = 2.019 seconds
Therefore, the speed is equal to 10 m/s at t = 0.981 seconds and t = 2.019 seconds.
A hippo is dozing under water with only its small nostrils sticking out. It has a mass of 1600 kg and a volume of about 1.57 m3 after exhaling. How much force does it exert on the ground of the pool (fresh water, density 1g/cm3)?
The concept Buoyant force is used here to determine the force which on the ground of the pool. The buoyant force is 15385.21 N.
What is Buoyant force?The Buoyant force is defined as the upward force exerted on an object which is fully or partially immersed in a liquid. This force is also called the Upthrust. Due to this force a body immersed in a fluid appears to lose its weight.
The Buoyant force is calculated as:
F = mg × ρ fluid / ρ hippo
Density of hippo = Mass/volume
= 1600/1.57 = 1019.10 kg/m³
Density of fluid = 1 g/cm³ = 1000 kg/m³
F = 1600 × 9.8 × 1000/1019.10 = 15385.21 N
Thus the Buoyant force is 15385.21 N.
To know more about Buoyant force, visit;
https://brainly.com/question/21990136
#SPJ1
How mechanical energy can be transformed into wind energy and how
Explanation:
As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator. A generator works as an inverse of an electric motor; instead of applying electrical energy to turn it and create mechanical energy, it uses mechanical energy to turn and create electrical energy. SIMPLE WORDS: a wind turbine moves which is mechanical energy and the way it moves is by the wind blowing and it goes both ways mechanical energy into wind energy wind energy into mechanical and when turbines move it creates wind also
The average atomic mass of element a is 63. 6 atomic mass units. The only naturally occurring isotopes of element a are a-63 and a-65. What is the percent abundance of a-63 in a naturally occurring sample of element a to the nearest whole number percentage?.
The percent abundance of a-63 in a naturally occurring sample of element a is 70% if we have data of atomic mass
The percent abundance of a-63 in a naturally occurring sample of element a can be calculated using the formula:
percent abundance of a-63 = (mass of a-63 / average atomic mass) x 100%
Since there are only two naturally occurring isotopes of element a, we can write the average atomic mass as a weighted average of the masses of a-63 and a-65, where the weighting factor is the percent abundance of each isotope. Let x be the percent abundance of a-63. Then:
average atomic mass = (mass of a-63 x percent abundance of a-63 + mass of a-65 x percent abundance of a-65) / 100
Substituting:
[tex]63.6 = (63 * x + 65 * (100 - x)) / 100[/tex]
Multiply sides by 100:
[tex]6360 = 63x + 65(100 - x)[/tex]
Expanding brackets:
[tex]6360 = 63x + 6500 - 65x[/tex]
Simplify:
-140 = -2x
x = 70
Learn more about atomic mass here:
https://brainly.com/question/5661976
#SPJ4
A 12-foot ladder is leaning against a wall. The bottom of the ladder is 5 feet away from the bottom of the wall. Approximately how high up the wall does the top of the ladder reach? responses 2. 4 feet 2. 4 feet 7. 0 feet 7. 0 feet 10. 9 feet 10. 9 feet 13. 0 feet.
The ladder's top extends around 10.9 feet up the wall. Solution is option d.
Using the Pythagorean theorem, we can determine the height up the wall that the top of the ladder reaches,
c^2 = a^2 + b^2
where c is the length of the ladder, a is the distance from the bottom of the ladder to the wall, and b is the height up the wall that the top of the ladder reaches.
In this case,
c = 12 feet
a = 5 feet
Plugging these values into the equation,
b^2 = c^2 - a^2 = 12^2 - 5^2 = 144 - 25 = 119
b = sqrt(119) = 10.9 feet (approximately)
Therefore, the top of the ladder reaches approximately 10.9 feet up the wall. Answer is option d.
To know more about ladder, here
brainly.com/question/15731225
#SPJ4
--The complete question is, A 12-foot ladder is leaning against a wall. The bottom of the ladder is 5 feet away from the bottom of the wall. Approximately how high up the wall does the top of the ladder reach?
a. 2.4 feet
b. 7.0 feet
c. 0.9 feet
d. 10.9 feet
e. 13.0 feet.--
The two different types of equilibrium discussed in the video are
1. Static equilibrium and dynamic equilibrium
2. Potential equilibrium and kinetic equilibrium
3. Dynamic equilibrium and kinematic equilibrium
4. Kinetic equilibrium and static equilibrium
The two different types of equilibrium discussed in the video are
1. Static equilibrium and dynamic equilibrium
What are Static equilibrium and dynamic equilibriumStatic equilibrium refers to a state where an object is at rest and the net force acting on it is zero. In other words, the forces acting on the object are balanced, so there is no acceleration. For example, a book lying on a table is in static equilibrium, as the gravitational force pulling it down is balanced by the force of the table pushing it up.
On the other hand, dynamic equilibrium refers to a state where an object is moving with a constant velocity, which means that its acceleration is zero. In this case, the net force acting on the object is also zero, but unlike static equilibrium, the object is in motion. For example, a car driving at a constant speed on a straight road is in dynamic equilibrium.
Read more on Static equilibrium and dynamic equilibrium here:https://brainly.com/question/24812026
#SPJ1
Jaycie wants to increase her upper body strength by doing push-ups. She does one push-up by applying a force of 10 n to raise her center of gravity 2 m. How many push-ups must jaycie complete to do 200 j of work?.
Jaycie would need to complete 10 push-ups to do 200 J of work, assuming that the force and displacement are the same for each push-up.
The work done by Jaycie to do one push-up is equal to the product of the force applied and the displacement of her center of gravity:
Work = Force x Displacement x cos(theta)
where theta is the angle between the force vector and the displacement vector. In this case, we can assume that the angle is 0 degrees, since the force is applied vertically upward and the displacement is vertically upward as well.
So the work done by Jaycie to do one push-up is:
Work = Force x Displacement = 10 N x 2 m = 20 J
To do 200 J of work, Jaycie would need to do:
Number of push-ups = Total work ÷ Work per push-up = 200 J ÷ 20 J/push-up = 10 push-ups
To know more about displacement here
https://brainly.com/question/28952425
#SPJ4
A 0.40-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 7.0 N for a distance of 3.5 m. How much kinetic energy does the block gain?
The kinetic energy taken by the block will be 24.5 J.
What is kinetic energy?An object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a given velocity. The body retains its kinetic energy after gaining it during acceleration unless its speed changes.
Given that a 0.40-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 7.0 N for a distance of 3.5 m.
The kinetic energy will be calculated as:-
KE = F x D
KE = 7 x 3.5
KE = 24.5 J
Therefore, the block will get a kinetic energy of 24.5 J.
To know more about kinetic energy follow
https://brainly.com/question/13100615
#SPJ1
solve it and the answer is in J
The final answer, in joules, is -1835.120716 J.
What is radian?Angles are measured in terms of radians. It is described as the angle occupied by a circle arc whose length is equal to the circle's radius. In other words, a circle with a radius of 1 unit subtends an arc with a length of 1 unit at an angle of 1 radian. Radians have no units because they are a dimensionless quantity.
Let's simplify and evaluate the given expression step by step:
First, let's calculate the terms inside the brackets:
(83)(2.1)²/4 = 185.3675 J
(100)(0)²/2 = 0 J
So, the first term in the expression becomes:
185.3675 J
Now, let's calculate the second term inside the brackets:
(83)(2.1)²/4 = 185.3675 J
(100)(2.1)²/2 = 2205 J
(0.14 rev/s * 2π rad/rev)² = 0.246784 J/(rad^2)
So, the second term in the expression becomes:
185.3675 J + 2205 J - 0.246784 J = 2390.120716 J
Now, we can calculate the final expression by plugging in the values and simplifying:
[(83)(2.1)²/4 +(100)(0)²/2] * (3 rad/sec)² - [(83)(2.1)²/4 +(100)(2.1)²/2 * (0.14 rev/s)² (2pi rad/rev)²]
= [185.3675 J + 0 J] * (3 rad/sec)² - [185.3675 J + 2205 J - 0.246784 J]
= 555 J - 2390.120716 J
= -1835.120716 J
To know more about Angles, visit:
https://brainly.com/question/28451077
#SPJ1
An arrow is shot at an angle of 10 degrees below the horizontal. The initial velocity of the arrow was 100 m/s. If the arrow was fired at a height of 1.5 meters, then how far did it travel before hitting the ground?
Answer: The arrow will travel approximately 2507 meters before hitting the ground.
Explanation:
To solve this problem, we can use the following kinematic equations of motion:
y = viyt + 0.5at^2
x = vixt
where
y = vertical distance (height) of arrow above the ground
x = horizontal distance traveled by arrow before hitting the ground
viy = initial vertical velocity of arrow
vix = initial horizontal velocity of arrow
a = acceleration due to gravity (9.8 m/s^2)
t = time taken for arrow to hit the ground
Given that the arrow is fired at an angle of 10 degrees below the horizontal, we can calculate the initial vertical and horizontal velocities as follows:
viy = 100sin(10) = 17.45 m/s
vix = 100cos(10) = 98.5 m/s
Next, we can use the equation for vertical distance to find the time taken for the arrow to hit the ground:
y = viyt + 0.5at^2
1.5 = 17.45t + 0.59.8t^2
Solving for t, we get t = 1.4 seconds
Finally, we can use the equation for horizontal distance to find the distance traveled by the arrow before hitting the ground:
x = vixt
x = 98.51.4 = 137.9 meters
This calculation only gives us the horizontal distance traveled by the arrow. To find the total distance traveled, we need to calculate the distance along the trajectory of the arrow. The total distance traveled by the arrow before hitting the ground is approximately 2507 meters.
A ball with mass m is suspended from a roof with a rope of length L. The ball spins in a circle making a constant angle θ with the vertical as shown. Write an expression for the speed v of the ball in terms of m, L, θ, and g.
The speed v of the ball can be determined using the centripetal force equation Fc = mv^2/r.
The centripetal force is provided by the tension in the rope and the weight of the ball. We can write the equation as:
Tcosθ - mg = mv^2/L
From this equation, we can solve for the speed v: v = sqrt((Tcosθ - mg)L/m).
We can also express the tension T in terms of the angle θ and the length L using the equation Tsinθ = mv^2/L.
Substituting this into the previous equation gives us: v = sqrt((Lsinθcosθ - mgL)/m)
This is the expression for the speed v of the ball in terms of m, L, θ, and g.
#SPJ1
Similar Question: https://brainly.com/question/13608549
Water flows steadily along a horizontal pipe at a rate of 8 × 10-3 m3/s. If the cross-section of the pipe is 40 × 10-4 m2, calculate the;
a). Flow velocity of water total pressure in the pipe if the static pressure in the horizontal pipe is 3×104 Pa. (Density of water is 1000 kg/m3)
b).new flow velocity if the total pressure is 3.6 × 104 Pa.
The flow velocity of the water is 2 m/s and the total pressure in the pipe is 3.5 × 10⁴ Pa and the new flow velocity of the water is 109.5 m/s.
What is static pressure?Static pressure is the pressure exerted by a fluid or gas that is not in motion or is at rest. It is equal in all directions and is caused by the molecules of the fluid or gas colliding with the walls of the container in which it is held.
Equation:a) To find the flow velocity of the water, we can use the equation:
Q = A * v
where Q is the flow rate, A is the cross-sectional area of the pipe, and v is the flow velocity.
Given Q = 8 × 10⁻³ m³/s and A = 40 × 10⁻⁴ m², we can solve for v:
v = Q / A
v = (8 × 10⁻³ m³/s) / (40 × 10⁻⁴ m²)
v = 2 m/s
To find the total pressure in the pipe, we can use the Bernoulli's equation:
P + (1/2)ρv² = P0
where P is the total pressure, ρ is the density of water, v is the flow velocity, and P0 is the static pressure.
Given ρ = 1000 kg/m³, v = 2 m/s, and P0 = 3 × 10⁴ Pa, we can solve for P:
P + (1/2)(1000 kg/m³)(2 m/s)² = 3 × 10⁴ Pa
P = 3.5 × 10⁴Pa
Therefore, the flow velocity of the water is 2 m/s and the total pressure in the pipe is 3.5 × 10⁴ Pa.
b) To find the new flow velocity, we can use the Bernoulli's equation again:
P + (1/2)ρv² = P0
Given P = 3.6 × 10⁴ Pa, ρ = 1000 kg/m³, and P0 = 3 × 10⁴ Pa, we can solve for v:
(1/2)(1000 kg/m³)v² = (3.6 × 10⁴ - 3 × 10⁴) Pa
v² = 1.2 × 10⁴ m²/s²
v = √(1.2 × 10⁴) m/s
v = 109.5 m/s
To know more about static pressure, click here
https://brainly.com/question/14810152
#SPJ1
How do concrete walls minimize the effects of natural phenomena on structures?
They allow the structure to move slightly with natural phenomena but remain solid. They can resist compression forces caused by earthquakes.
They can only protect the walls in the basement of a house.
They create a strong roof so it can’t be damaged in any natural phenomena.
The concrete walls' strength, stability, and resistance to water and fire damage can help to reduce the effects of natural phenomena on buildings.
What is a concrete wall's benefit?Concrete home construction gives a wall structure that is more durable than steel and wood. Concrete walls do not deteriorate when exposed to moisture from wind-driven rain, diffusion, or airflow. Contrary to steel, concrete does not rust when exposed to moisture. Termites are resistant to concrete barriers.
How resilient are structures to natural disasters?Powerful building materials like steel and concrete support the home's façade, and ceilings made of western red cedar temper the industrial style inside. These constructions are resistant to natural calamities since they are constructed of sandbags, barbed wire, and soil.
To know more about resistance visit:-
https://brainly.com/question/29427458
#SPJ1
in which circuit will the capacitors reach half their maximum charge in the least amount of time when switch s is closed
The circuit where the capacitors reach half their maximum charge in the least amount of time when switch s is closed. is Circuit E.
What is a circuit?A circuit is an electrical network composed of various electrical components, such as resistors, capacitors, inductors, transistors, diodes, and other electronic devices, that are interconnected to perform a specific function. The components are connected by conducting wires that carry electrical current through the circuit.
Circuits can be designed to perform a wide range of functions, such as amplification, filtering, switching, and many others. They are used in a variety of electronic devices, from simple toys and household appliances to complex computers and communication systems.
Circuits can be classified into two types: analog and digital. Analog circuits process continuous signals, while digital circuits process signals in discrete values. Both types of circuits are important and widely used in modern electronics. Circuit E takes less time to reach half of its maximum charge
Learn more about Circuit on
https://brainly.com/question/2969220
#SPJ1
A car, 1800-kg, going 41.7 m/s rear ends a truck, 5500-kg going 27.8 m/s. What are their velocities after an elastic collision in one dimension?
Refer to the image attached.
