The equivalent amount of ammonia in the reaction mixture would be 0.54 relative to the sulfonyl chloride.
Stoichiometric problemThe density of 30% NH4OH solution = 0.90 g/mL
Molarity of NH4OH = 15 M
The mass of the 30% NH4OH solution in 16 ml:
mass = volume x density
mass = 16 mL x 0.90 g/mL
mass = 14.4 g
moles = mass / (molarity x molecular weight)
moles = 14.4 g / (15 M x 35.05 g/mol)
moles = 0.027 mol
The number of equivalents of NH4OH relative to the sulfonyl chloride. One equivalent of NH4OH reacts with one mole of sulfonyl chloride:
equivalents of NH4OH = moles of NH4OH / moles of sulfonyl chloride
equivalents of NH4OH = 0.027 mol / 0.05 mol
equivalents of NH4OH = 0.54 equivalents
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How many grams of hydrogen are present in 10.05 grams of water?
In water (H2O), there are two atoms of hydrogen (H) and one atom of oxygen (O) per molecule. The atomic mass of hydrogen is approximately 1.008 g/mol and the molecular mass of water is approximately 18.015 g/mol.
To calculate the grams of hydrogen in 10.05 grams of water, we need to first determine the number of moles of water present:
moles of water = mass of water / molecular mass of water
moles of water = 10.05 g / 18.015 g/mol
moles of water = 0.5575 mol
Since there are two hydrogen atoms in each molecule of water, the number of moles of hydrogen is twice the number of moles of water:
moles of hydrogen = 2 x moles of water
moles of hydrogen = 2 x 0.5575 mol
moles of hydrogen = 1.115 mol
Finally, we can calculate the grams of hydrogen by multiplying the number of moles of hydrogen by the atomic mass of hydrogen:
grams of hydrogen = moles of hydrogen x atomic mass of hydrogen
grams of hydrogen = 1.115 mol x 1.008 g/mol
grams of hydrogen = 1.12352 g
Therefore, there are approximately 1.12352 grams of hydrogen present in 10.05 grams of water.
What is hydrogen?Hydrogen is a chemical element with the symbol H and atomic number 1. It is the lightest and most abundant element in the universe, constituting roughly 75% of all baryonic mass. Hydrogen is a colorless, odorless, and tasteless gas that is highly flammable.
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Which of the following exhibits the correct orders for both atomic radius and ionization energy, respectively? (smallest to largest) A. F, S, O, and O, S, FB. S, O, F, and F, O, SC. F, O, S, and S, O, FD. S, F, O, and S, F, O E. none of these
The atomic radius of an atom is the distance between the centre of the nucleus and the valence shell of electrons. The correct order of atomic radius and ionization energy is F, O, S, and S, O, F. The correct option is C.
What is ionization energy?The minimum amount of energy required to remove most loosely bound electron from an isolated gaseous atom of that element in the ground state is called ionization energy.
Along a period ionization energy increases and decreases down the group. The atomic radius generally increases down a group and decreases along a period.
Here 'F' has high ionization energy and it has low atomic radius.
Thus the correct option is C.
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the outer most shell of an atom is called the valane shell. the number of electrons in this shell determines ________.
using the rules for naming molecular compounds described in the introduction, what is the name for the compound n2cl4 ?
Answer:
Dinitrogen Tetrachloride
Explanation:
The compound N2Cl4 is made up of two nitrogen atoms and four chlorine atoms, so it is a molecular compound.
To name molecular compounds, we use prefixes to indicate the number of each type of atom in the compound. The prefix for two is "di", and for four is "tetra". Therefore, the name of N2Cl4 would be dinitrogen tetrachloride.
