Answer:
C3H8
Explanation:
To determine which compound will produce the largest amount of CO2 when 2.5 moles of each is burned completely in O2, we need to compare the mole ratios of the compounds and the CO2 produced in their balanced chemical equations.
The balanced chemical equations for the combustion of the compounds are:
C3H8 + 5O2 → 3CO2 + 4H2O
C4H10 + 13/2 O2 → 4CO2 + 5H2O
C8H18 + 25/2 O2 → 8CO2 + 9H2O
From these equations, we can see that 1 mole of C3H8 produces 3 moles of CO2, 1 mole of C4H10 produces 4 moles of CO2, and 1 mole of C8H18 produces 8 moles of CO2.
Therefore, when 2.5 moles of each compound are burned completely in O2, the largest amount of CO2 will be produced by C8H18, which produces 8 moles of CO2 per mole of the compound. The amount of CO2 produced by 2.5 moles of C8H18 would be 8 x 2.5 = 20 moles.
In comparison, 2.5 moles of C3H8 would produce 3 x 2.5 = 7.5 moles of CO2, and 2.5 moles of C4H10 would produce 4 x 2.5 = 10 moles of CO2.
what does the ph scale actually measure?
pH scale measures whether the aqueous solution is acidic or basic. It is a measure of concentration of hydronium ion.
The term acidity and alkalinity are measured with a logarithmic scale called pH scale. pH is a measure of how acidic or basic the water is. It is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions are measured to have lower pH values than basic solutions or alkaline solutions. The objects that are not very acidic are called basic objects. The pH scale has values ranging from zero that is the most acidic to 14 that is the most basic. Pure water has a pH value of 7. This value of 7 is considered as neutral that is neither acidic or basic.
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Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this list of thermodynamic properties. Mg(OH)2(s)+2HCl(g)⟶MgCl2(s)+2H2O(g)
ΔH∘rxn =
The standard enthalpy change for the reaction at the 25 °C is the -16.3 kJ.
The chemical reaction is as follows :
Mg(OH)₂(s) + 2HCl(g -----> MgCl₂(s) + 2H₂O(g)
The ΔHf Mg(OH)₂ = - 924.5 kJ/mol
The ΔHf HCl = - 92.30 kJ/mol
The ΔHf MgCl₂ = - 641.8 kJ/mol
The ΔHf H₂O = -241.8 kJ/mol
The standard enthalpy change of the rection is as :
ΔH∘rxn = ∑ ΔHf product - ∑ ΔHf reactant
= ( -641.8 + (2× -241.8 ) - ( - 924.5 + ( 2 × - 92.30 ))
ΔH∘rxn = - 16.3 kJ
The enthalpy change for the reaction is -16.3 kJ.
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