If 84 J of work are exerted to pull a wagon, how much force does it take to pull the wagon 7. 0 m? Round your answer to the nearest whole number. It takes N of force to pull the wagon.

Susan has connected her drive to a USB 2.0 port, which does not support the maximum bandwidth required. The correct option is D.

Thus, The issue is probably related to the USB port's bandwidth because the disc works perfectly on her coworker's PC and the right drivers are loaded.

The drive requires a minimum bandwidth of 400 Mbps, and USB 2.0 ports often have less bandwidth than USB 3.0 ones.

As a result, using a USB 2.0 connector to connect the drive might not give it enough bandwidth to operate as intended.

Thus, Susan has connected her drive to a USB 2.0 port, which does not support the maximum bandwidth required. The correct option is D.

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Known :

m1 = m

m2 = 3m1 = 3m

a1 = 30.0 m/s²

Solution :

Net force of the object is constant, so :

F1 = F2

m1 • a1 = m2 • a2

(m)(30.0 m/s²) = (3m)(a2)

a2 = 10 m/s²

Explanation:

R = A + B. Vectors in the opposite direction are subtracted from each other to obtain the resultant vector. Here the vector B is opposite in direction to the vector A, and R is the resultant vector.

Answer:

A study looking at how alcohol consumption impacts the brain. A study to discover the components making up human DNA. A study accessing whether stress levels 

Explanation:

For example, a scientist that tries to figure out how the body makes cholesterol, or what causes a particular disease, is performing basic scienc

Answer:

i think a month

Explanation:

He lifted the box as high as 1.2 m (B).

Hi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

[tex] \boxed{\sf{\bold{W = F \times s}}} [/tex]

With the following condition :

Now, because in this question, the "s" is a displacement that proportion to the change of altitude of the objects. So, the "s" can be written as "∆h* (altitude change). The formula can also be changed to:

[tex] \boxed{\sf{\bold{W = F \times \Delta h}}} [/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{W = F \times \Delta h} [/tex]

[tex] \sf{120 = 100 \times \Delta h} [/tex]

[tex] \sf{h = \frac{120}{100}} [/tex]

[tex] \boxed{\sf{h = 1.2 \: m}} [/tex]

He lifted the box as high as 1.2 m (B).

The height to which the box will be lift up by a force of 100N and work done of 120 Joules is 1.2 meters. Thus, the correct option is B.

The work done by a force of a particular magnitude is defined as the product of the force in the direction of the displacement of the object and the magnitude of this displacement. Work done can be calculated by multiplying Force and Distance in the direction of force as follows.

W = F × d

W = work (J),

F = force (N),

d = shift or displacement (m).

Here, d is a displacement that is proportional to the change of altitude of the objects. So, the d can be written as ∆h (altitude change or height change). The formula can also be written as:

W = f × Δh

where, W = work (J)

F = force (N)

Δh = change of altitude (m)

As given,

W = work = 120 J

F = force = 100 N

Δh = change of altitude

W = f × Δh

120 = 100 × Δh

Δh = 120/100

h = 1.2m

Therefore, the correct option is B.

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Answer:

Direction is N 51.3° E

Explanation:

» From trigonometric ratios:

[tex]{ \tt{ \red{ \tan( \theta) = \frac{opposite \: { \blue{(south)}}}{adjacent \: { \blue{(west)}}} }}} \\ \\ { \tt{ \tan( \theta) = \frac{50}{40} = \frac{5}{4} }} \\ \\ { \tt{ \theta = { \tan }^{ - 1} ( \frac{5}{4}) }} \\ \\ { \tt{ \theta = 51.3 \degree}} \\ \\ { \boxed{ \tt{ \: direction : \:{ \green{N }}\: 51.3 \degree \: { \green{ E }}}}}[/tex]

Both objects will have the same temperature, which is larger than T but smaller than 2*T

A system in equilibrium if it is not able to experience spontaneous changes.

Here, we assume that our system is just the two objects with the given temperatures, and nothing else.

Thus, when we put them together, the only thing that will happen is a heat transfer (from the hotter object to the other one), until both of them have the same temperature (when both objects have the same temperature the heat flux stops).

Also, the object with temperature 2*T loses temperature, while the object with temperature T increases its temperature, then we can conclude that the final temperature of both objects will be in between these:

T < Tₓ < 2*T

To get the exact final temperature, we would need more information.

So what will be true after some time has passed?

The only thing that we know will happen is:

Both objects will have the same temperature, which is larger than T but smaller than 2*T

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Answer: Thermodynamics Unit Test

1. Heat will flow from Object B to Object A.

2. Heat flows due to a temperature difference between two objects.

3. 100 J/g

4. 9,887.5 J

5. Some heat is always lost to the environment.

6. Short Answer Question

Explanation:

100% correct

The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

The given parameters:

The resultant force on the box is calculated as follows;

[tex]F_{net} = F_1 - F_2\\\\F_{net} = 8.3 \ N - \ 6.6 \ N\\\\F_{net} = 1.7 \ N[/tex]

The resultant acceleration of the box is calculated as follows;

[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{1.7}{31} \\\\a = 0.055 \ m/s^2[/tex]

Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

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Answer:

. Carpet has a rougher surface than the bare floor, so there are more areas for the object to have friction with the rougher surface and slow down.

Explanation:

An object that is sliding across carpet slow down because of friction acting between its rougher surface and the surface of the object.

When two bodies come in touch with each other, friction, a sort of relative force, acts as a resistance. In other words, friction force opposes the relative motion of two bodies when they come into touch with one another.

When an object is sliding across carpet, it has to pass through a surface which is more rough compare to plane surface. So, frictional force will be greater in this case compare to plane surface. This frictional force resists the sliding of the object and the object slows down gradually.

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Because r is given, we can use the second expression in the equation ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 to calculate the centripetal acceleration. Solution.

Answer:

increase

Please Give Brainliest!

By knowing how intensity relates to distance, we will see that at 4 meters of the engine the intensity is 80.

The sound spreads in a solid angle like all waves, so the intensity of the sound will decrease with the distance squared, this means that:

[tex]I = \frac{P}{4*pi*r^2}[/tex]

Where P is the sound power, we know that when the student is at 8m from the engine, the intensity measured is 20 (it does not tell the units) so we have:

[tex]20 = \frac{P}{4*3.14*(8m)^2} \\\\P = 20*4*3.14*(8m)^2 = 16,078.8 m^2[/tex]

Now, if you move 4 meters closer to the engine, your new position will be:

r = 4m

Then we have:

[tex]I = \frac{16,078.8 m^2}{4*3.14*(4m)^2} = 80[/tex]

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Answer:

80 is the answer! 100% CORRECT!

Explanation:

~Hope this helps! :)

Answer:

Yes

Explanation:

When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.

Answer: Unequal sharing of electrons makes water a polar molecule. ... This means that electrons spend a bit more time at the oxygen end of the molecule. This makes the oxygen end of the molecule slightly negative. Since the electrons are not near the hydrogen end as much, that end is slightly positive.

Explanation:

Answer:

Explanation: You need to do this problem in respect to component velocities. Just use a vector and grab the magnitude using distance formula.

The components are Y=600, X=100

So the velocity vector is V> = sqrt(600^2+100^2) = 608.276253 in the direction (100, 600)

The force exerted on Alice’s foot as she kicks the ball is 1.25 N.Force can be defined as the influence that can accelerate the object.

Force can be defined as the influence that can accelerate the object. From Newton's Second Law of motion,

[tex]F = ma[/tex]

Where,

[tex]F[/tex] - force

[tex]m[/tex] - mass = 0. 25 kg

[tex]a[/tex] - acceleration = 5 N

Put the values in the formula,

[tex]F = 0.25 \times 5\\\\F = 1.25 \rm \ N[/tex]

Therefore, the force exerted on Alice’s foot as she kicks the ball is 1.25 N.

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Answer:

It is estimated that the light sources used as transmitters in the light-wave com munication system in Chicago have the ability to transmit more than 650 voice signals simultaneously.  

Explanation:

Answer:

Z -- SOUND WAVES

Answer:

Newtons second law of motion known as the law of acceleration

Explanation:

The second law explains that a greater mass requires a greater force

Answer:

Inertia.

Explanation:

Goodluck!!

Answer:

the mass is 6 kilos grams

Atmospheric pressure, also known as barometric pressure, is the pressure within the atmosphere of Earth. The standard atmosphere is a unit of pressure defined as 101,325 Pa, which is equivalent to 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

Surface pressure is the atmospheric pressure at a location of the Earth's surface (terrain and oceans).

Answer:

Edison

Explanation:

Among other notable inventions, Edison and his assistants developed the first practical incandescent lightbulb in 1879 and a forerunner of the movie camera and projector in the late 1880s.

Answer:

The answer is choice (3)

Explanation: Land materials do require more energy than water to raise their temperature by one degree, hence why water gets heated a lot easier than something like wood.

Hi there!

We can use the equation for gravitational force:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Fg = force due to gravity (N)

m1, m2 = masses of objects (kg)

r = distance between the center of mass of the objects (m)

G = gravitational constant

1.

Using the equation:
[tex]F'_g = \frac{G(3m_1)(3m_2)}{r^2} = 9F_g[/tex]

The force would be 9 times larger.

2. (Repeat?)

3.

The square of distance is inversely related, so:
[tex]F'g= \frac{Gm_1m_2}{(\frac{2}{3}r)^2} = \frac{Gm_1m_2}{\frac{4}{9}r^2} = \frac{9}{4}F_g[/tex]

The force is 9/4ths times larger.

4.

Combining:
[tex]F'_g = \frac{G(2m_1)(2m_2)}{(3r)^2} = \frac{4Gm_1m_2}{9r^2} = \frac{4}{9}F_g[/tex]

The force is 9/4ths times larger.

5.

[tex]F'g = \frac{G(2m_1)m_2}{(4r)^2} = \frac{2Gm_1m_2}{16r^2} = \frac{1}{8}F_g[/tex]

The force is 1/8th the original.

6.

Equation for gravitational field:
[tex]g = \frac{Gm_e}{r_e^2}[/tex]

g = acceleration due to gravity (m/s²)

G = gravitational constant

me = mass of earth (kg)
re = radius of earth (m)

With the following transformations:
[tex]g' = \frac{G(2m_e)}{(\frac{1}{3}r)^2} = \frac{2Gm_e}{\frac{1}{9}r^2} = 18g[/tex]

The acceleration due to gravity is 18 times as large.

answer is down hera