Answer:
17
Step-by-step explanation:
f(x) is the same as y=. "What is f(5)" is the same as saying what is y=3x + 2 when x is 5.
Either way, you are going to replace x with is numerical value, which is 5, and then solve.
y = 3(5) + 2
y = 15 +2
y = 17
f(5) = 17
If 96 out of 200 pet owners own cats, what fraction and what percentage of
pet owners do not own cats?
Check all that apply.
A. 48%
B. 0.52%
C.
104
200
D. 52%
E.
96
200
SUEM
Help me please on this problem
Answer:
-1/2
Step-by-step explanation:
The slope of the line on the graph is 2, determined by counting up from one point and over to another point.
Perpendicular lines have opposite reciprocal slopes.
can someone help me please?
Answer:
(0,4) and (-4,0)
Step-by-step explanation:
Write an equation in standard, point-slope, and slope-intercept form for a line with the given slope and point.
slope = 3 and (1,4)
Answer:
Standard Form: 3x - y = -1
Point-Slope Form: 3x-y+1=0
Slope-Intercept Form: y= 3x + 1
Question Andre bought 8 bagels and ate 2/3 of them. Sandra bought 20 bagels and ate 1/4 of them. Who ate more bagels?
Answer:
Andre
Step-by-step explanation:
Andre ate 2/3 of 8 bagels, so to get the number of bagels-
8 *2/3
8/1*2/3 = 16/3 = 5 1/3
Meanwhile Sandra ate 1/4 of 20, so,
20*1/4 = 20/4 = 5
Can somebody plz answer these word problems correctly thanks! (Middle school math)
Show how u got the answers like steps numbers dividing/multiplying u do!
WILL MARK BRAINLIEST WHEOVER ANSWERS FIRST! :DDD
Answer: is this mathematical question? I will samual
Step-by-step explanation:
PLEASEE answer correctly !!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
4 boys and 5 girls ratio (4:5)
4:5 ratio
hope this helps
Kate's soccer team is selling coupon books and recipe books to raise
money for transportation to their games. Coupen books cost $12 each
and recipe books cost $7.50 each. If Kate sold a total of 42 books and
raised $441, how many coupon books did she sell?
plz help me
Answer:
28 coupon booksStep-by-step explanation:
Let the number of coupon books be c and recipe books be r.
Then we have following equations:
c + r = 4212c + 7.5r = 441Substitute r in the second equation and solve for c:
r = 42 - c12c + 7.5(42 - c) = 44112c - 7.5c + 315 = 4414.5c = 441 - 3154.5c = 126c = 126/4.5c = 28help pleasee look the picture
Answer:
-19
Step-by-step explanation:
3^2= 9
(9-16)(4)= -28
-28+9= -19
Answer:
-19
Step-by-step explanation:
At the equation together then
Multiply 9-7 x 4
Calculate 9-28
That equals -19 so -19 is the answer
Find the equation of the line shown below.
A. y = –0.2x + 2
B. y = –5x + 2
C. y = 0.2x + 5
D. y = 5x + 2
Answer:
y= -0.2x+2
Step-by-step explanation:
I'm may be wrong but if you graph it I used desmos
that's the only one that matches
A line is shown in the graph. What is the equation of the line?
How many posters and picture frames does the store sell on that day?
13 posters and 16 picture frames
Derek swam 5 laps in 1/4
of an hour. Find the laps he swims per hour.
Answer
Derek swims 20 laps per hour.
Explanation
If Derek swims 5 laps in 1/4 of an hour, he swims 4 times of 5 laps in an hour. This is because 4 times 1/4 is one, or an hour. 5 times 4 is 20.
Prove the following integration formula:
[tex]\displaystyle \int e^{au}\sin(bu)\, du=\frac{e^{au}}{a^2+b^2}(a\sin(bu)-b\cos(bu))+C[/tex]
Answer:
See Explanation.
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyEquality PropertiesAlgebra I
Combining Like TermsFactoringCalculus
Derivative 1: [tex]\frac{d}{dx} [e^u]=u'e^u[/tex]Integration Constant CIntegral 1: [tex]\int {e^x} \, dx = e^x + C[/tex]Integral 2: [tex]\int {sin(x)} \, dx = -cos(x) + C[/tex]Integral 3: [tex]\int {cos(x)} \, dx = sin(x) + C[/tex]Integral Rule 1: [tex]\int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]Integration by Parts: [tex]\int {u} \, dv = uv - \int {v} \, du[/tex][IBP] LIPET: Logs, Inverses, Polynomials, Exponents, TrigStep-by-step Explanation:
Step 1: Define Integral
[tex]\int {e^{au}sin(bu)} \, du[/tex]
Step 2: Identify Variables Pt. 1
Using LIPET, we determine the variables for IBP.
Use Int Rules 2 + 3.
[tex]u = e^{au}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = sin(bu)du\\du = ae^{au}du \ \ \ \ \ \ \ \ \ v = \frac{-cos(bu)}{b}[/tex]
Step 3: Integrate Pt. 1
Integrate [IBP]: [tex]\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} - \int ({ae^{au} \cdot \frac{-cos(bu)}{b} }) \, du[/tex]Integrate [Int Rule 1]: [tex]\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{a}{b} \int ({e^{au}cos(bu)}) \, du[/tex]Step 4: Identify Variables Pt. 2
Using LIPET, we determine the variables for the 2nd IBP.
Use Int Rules 2 + 3.
[tex]u = e^{au}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = cos(bu)du\\du = ae^{au}du \ \ \ \ \ \ \ \ \ v = \frac{sin(bu)}{b}[/tex]
Step 5: Integrate Pt. 2
Integrate [IBP]: [tex]\int {e^{au}cos(bu)} \, du = \frac{e^{au}sin(bu)}{b} - \int ({ae^{au} \cdot \frac{sin(bu)}{b} }) \, du[/tex]Integrate [Int Rule 1]: [tex]\int {e^{au}cos(bu)} \, du = \frac{e^{au}sin(bu)}{b} - \frac{a}{b} \int ({e^{au} sin(bu)}) \, du[/tex]Step 6: Integrate Pt. 3
Integrate [Alg - Back substitute]: [tex]\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{a}{b} [\frac{e^{au}sin(bu)}{b} - \frac{a}{b} \int ({e^{au} sin(bu)}) \, du][/tex][Integral - Alg] Distribute Brackets: [tex]\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2} - \frac{a^2}{b^2} \int ({e^{au} sin(bu)}) \, du[/tex][Integral - Alg] Isolate Original Terms: [tex]\int {e^{au}sin(bu)} \, du + \frac{a^2}{b^2} \int ({e^{au} sin(bu)}) \, du= \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}[/tex][Integral - Alg] Rewrite: [tex](\frac{a^2}{b^2} +1)\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}[/tex][Integral - Alg] Isolate Original: [tex]\int {e^{au}sin(bu)} \, du = \frac{\frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}}{\frac{a^2}{b^2} +1}[/tex][Integral - Alg] Rewrite Fraction: [tex]\int {e^{au}sin(bu)} \, du = \frac{\frac{-be^{au}cos(bu)}{b^2} + \frac{ae^{au}sin(bu)}{b^2}}{\frac{a^2}{b^2} +\frac{b^2}{b^2} }[/tex][Integral - Alg] Combine Like Terms: [tex]\int {e^{au}sin(bu)} \, du = \frac{\frac{ae^{au}sin(bu)-be^{au}cos(bu)}{b^2} }{\frac{a^2+b^2}{b^2} }[/tex][Integral - Alg] Divide: [tex]\int {e^{au}sin(bu)} \, du = \frac{ae^{au}sin(bu) - be^{au}cos(bu)}{b^2} \cdot \frac{b^2}{a^2 + b^2}[/tex][Integral - Alg] Multiply: [tex]\int {e^{au}sin(bu)} \, du = \frac{1}{a^2+b^2} [ae^{au}sin(bu) - be^{au}cos(bu)][/tex][Integral - Alg] Factor: [tex]\int {e^{au}sin(bu)} \, du = \frac{e^{au}}{a^2+b^2} [asin(bu) - bcos(bu)][/tex][Integral] Integration Constant: [tex]\int {e^{au}sin(bu)} \, du = \frac{e^{au}}{a^2+b^2} [asin(bu) - bcos(bu)] + C[/tex]And we have proved the integration formula!
Prove: [tex]\displaystyle \int e^a^u sin(bu)\ du = \frac{e^a^u}{a^2+b^2} (a \ sin(bu) - b \ cos(bu)) + C[/tex]
Integration by parts formula: [tex]\displaystyle \int udv = uv - \int vdu[/tex]
Find u, du, v, and dv for this function: [tex]\displaystyle \int e^a^u sin(bu)[/tex]
[tex]\displaystyle u =e^a^u \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = -\frac{cos(bu)}{b} \\ du=ae^a^u \ du \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = sin(bu) \ du[/tex]Plug these values into the IBP formula.
[tex]\displaystyle \int e^a^u sin(bu) \ du = e^a^u \cdot \frac{-cos(bu)}{b} - \int -\frac{cos(bu)}{b} \cdot ae^a^u \ du[/tex]Multiply and simplify the factors. Factor the negative out of the integral.
[tex]\displaystyle \int e^a^u sin(bu) \ du = -\frac{e^a^u cos(bu)}{b} +\int \frac{a \ cos(bu) \ e^a^u}{b} \ du[/tex]Factor out a/b from the integral.
[tex]\displaystyle \int e^a^u sin(bu) \ du = -\frac{e^a^u cos(bu)}{b} + \frac{a}{b} \int cos(bu) \ e^a^u \ du[/tex]Now we are going to apply IBP to the function: [tex]\displaystyle \int cos(bu) \ e^a^u[/tex] . Find u, du, v, and dv for this function.
[tex]\displaystyle u =e^a^u \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = \frac{sin(bu)}{b} \\ du=ae^a^u \ du \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = cos(bu) \ du[/tex]Plug these values into the IBP formula.
[tex]\displaystyle \int e^a^u cos(bu) \ du = e^a^u \cdot \frac{sin(bu)}{b} - \int \frac{sin(bu)}{b} \cdot ae^a^u \ du[/tex]Multiply and simplify the factors.
[tex]\displaystyle \int e^a^u cos(bu) \ du = \frac{e^a^u \ sin(bu)}{b} - \int \frac{a \ sin(bu)\ e^a^u}{b} \ du[/tex]Factor out a/b from the integral.
[tex]\displaystyle \int e^a^u cos(bu) \ du = \frac{e^a^u \ sin(bu)}{b} - \frac{a}{b} \int sin(bu)\ e^a^u} \ du[/tex]Notice that we have the same integral we started with. Let's plug this integral into the original IBP we did.
[tex]\displaystyle \int e^a^u sin(bu) \ du = -\frac{e^a^u cos(bu)}{b} + \frac{a}{b} \big{[ }\frac{e^a^u sin(bu)}{b} - \frac{a}{b} \int sin(bu) \ e^a^u \ du \big{]}}[/tex]Distribute a/b inside the parentheses.
[tex]\displaystyle \int e^a^u sin(bu) \ du = -\frac{e^a^u cos(bu)}{b} + \frac{a \ e^a^u sin(bu)}{b^2} - \frac{a^2}{b^2} \int sin(bu) \ e^a^u \ du[/tex]Factor 1/b out of the right side of the equation.
[tex]\displaystyle \int e^a^u sin(bu) \ du = \frac{1}{b}\big{[} -e^a^u cos(bu)+ a \big{(}\frac{e^a^u sin(bu)}{b} \big{)} - \frac{a^2}{b} \int sin(bu) \ e^a^u \ du \big{]}[/tex]Multiply both sides by b to get rid of 1/b.
[tex]\displaystyle b \int e^a^u sin(bu) \ du = -e^a^u cos(bu)+ a \big{(}\frac{e^a^u sin(bu)}{b} \big{)} - \frac{a^2}{b} \int sin(bu) \ e^a^u \ du[/tex]Add the integral to both sides of the equation.
[tex]\displaystyle b \int e^a^u sin(bu) \ du + \frac{a^2}{b} \int sin(bu) \ e^a^u \ du= -e^a^u cos(bu)+ a \big{(}\frac{e^a^u sin(bu)}{b} \big{)}[/tex]Factor the integral on the left side.
[tex]\displaystyle \int e^a^u sin(bu) \ du \ \big{(} b + \frac{a^2}{b} \big{)}= -e^a^u cos(bu)+ a \big{(}\frac{e^a^u sin(bu)}{b} \big{)}[/tex][tex]\displaystyle \big{(}b+\frac{a^2}{b} \big{)} = \frac{b^2+a^2}{b}[/tex], so we can multiply both sides of the equation by [tex]\displaystyle \frac{b}{a^2+b^2}[/tex].
[tex]\displaystyle \int e^a^u sin(bu) \ du = -e^a^u cos(bu)+ a \big{(}\frac{e^a^u sin(bu)}{b} \big{)} \big{(} \frac{b}{a^2+b^2} \big{)}[/tex]Simplify the equation before multiplying everything by [tex]\displaystyle \frac{b}{a^2+b^2}[/tex].
[tex]\displaystyle \int e^a^u sin(bu) \ du = \big{(}\frac{-e^a^u cos(bu) \ b + a \ e^a^u sin(bu)}{b} \big{)} \big{(} \frac{b}{a^2+b^2} \big{)}[/tex]Multiply the two factors together. Notice that the two b's in the denominator and numerator, respectively, cancel out. We are left with:
[tex]\displaystyle \int e^a^u sin(bu) \ du = \big{(}\frac{-e^a^u cos(bu) \ b + a \ e^a^u sin(bu)}{a^2+b^2} \big{)}[/tex]Factor [tex]\displaystyle e^a^u[/tex] from the numerator.
[tex]\displaystyle \int e^a^u sin(bu) \ du = \big{(}\frac{e^a^u( -b \ cos(bu) \ + a \ sin(bu)}{a^2+b^2} \big{)}[/tex]Split the numerator and denominator to make it appear the same as the original question.
[tex]\displaystyle \int e^a^u sin(bu) \ du = \frac{e^a^u}{a^2+b^2} \big{(} a \ sin(bu) - b \ cos(bu) \big{)}[/tex]Since we are taking the integral of something, we can add a +C at the end to complete the problem.
[tex]\displaystyle \int e^a^u sin(bu) \ du = \frac{e^a^u}{a^2+b^2} \big{(} a \ sin(bu) - b \ cos(bu) \big{)} + C[/tex]This is equivalent to the proof that we are given, therefore, we proved the integral correctly.
a movie starts at 3:30 pm. if the movie is 2 hrs and 10 mins long, what time will it be over ?
Anthony has a goal of saving 96.20. he will save the same amount each week for 13 weeks. How much will Anthony need to save each week in order to meet his hoal
Select the correct answer.
You're given side AB with a length of 6 centimeters and side BC with a length of 5 centimeters. The measure of angle A is 30%. How many
triangles can you construct using these measurements?
А.0
В.1
C.2
D. infinitely many
Answer:
D. infinitely many
Step-by-step explanation:
I assume that percentage sign is a degree symbol.
If there are only two sides given, there can be an infinite amount of triangles
what is the distance between points A(1, 9) and B(4, -2)?
Answer:
Im not certain but it might be (3,11)
Step-by-step explanation:
did you know that Geico can help u save 15 % or more on car insurance??
¯\_(ツ)_/¯
Answer:
I don't have a car T-T
Step-by-step explanation:
Is this graph a function
Answer:
yes
Step-by-step explanation:
becous its aparently equal
V = 4 + 2r solve for r
Answer:
r = V/2 - 2
Step-by-step explanation:
Answer: r=1/2v−2
Step-by-step explanation:
v=4+2r
2r+4=v
2r+4+−4=v+−4
2r=v−4
2r/2=v−4/2
r=1/2v−2
How does the graph change frorm point G to point K?
O The graph increases.
O The graph deceases, then increases.
O The graph rernains constant.
OThe araph increases, then decreases.
Answer:
The graph increases then decreases
Step-by-step explanation:
If you look at point G it is increasing until it gets to the x value of 0. From there on it is decreasing to K.
Answer:
C. The graph increases, then decreases.
Edge 2021
You want to go to a movie and hope to have enough money to get popcorn
and a drink. The cost of the ticket is $12, the popcorn is $10 and the drink is
$7. How much will it cost you to go to the movie with popcorn and a drink?
Answer: $29
Step-by-step explanation: 12+10+7= 29
Answer:
$29 dollars total
Step-by-step explanation:
add 12 + 10 + 7 = 29 or the movie, drink &' popcorn :)
PLSSS HELPPPPPP PLSSSS
Answer:
Morgan, its a straight line and it goes through the origin
Step-by-step explanation:
Your restaurant bill is $74.34. You want leave about a 20% tip. Which is the best estimate of a 20% tip?
Answer:
$15
Step-by-step explanation:
The tip is 14.86
When estimating round to the nearest number so you’ll have 15
please help is this correct
Answer:
yes its correct
Step-by-step explanation:
you dont really need work because its really just substitution.
PLEASE HELP!!! A system of linear equations is shown below.
2x –3y=17 –3x + y = –1 Choose a method (Elimination or Substitution) to solve the system of equations. Solve and explain your process. Academic Language: Elimination, Substitution, Graphing, Intersection, Solution, Coordinate Point, Ordered Pair, Solve, Isolate, Systems, Equations, Additive Inverse, Multiplicative Inverse, Distributive Property, Variable, Combine Like Terms, and Justify.
Answer:
The value of the variable x is -2 and the value of the variable y is -7.
Step-by-step explanation:
The substitution method consists of:
Solve for an unknown in one of the equations, which will be a function of the other unknown .In the other equation that is not used, the same unknown is replaced by the expression obtained in step 1. Solve for the only remaining unknown, obtaining the numerical value of an unknown. Substitute the cleared unknown in step 3 for its numerical value in the equation obtained in step 1. Operate to obtain the numerical value of the other unknown.In this case, you have the system of equations:
[tex]\left \{ {{2*x-3*y=17} \atop {-3*x+y=-1}} \right.[/tex]
Isolating the variable y from the second equation:
y= -1 +3*x
Replacing this expression in the first equation:
2*x-3*( -1 +3*x)= 17
Solving:
2*x -3*(-1)-3*3*x= 17
2*x +3 -9*x= 17
2*x -9*x= 17 -3
(-7)*x= 14
x= 14÷(-7)
x= -2
Now, replacing the value of x in the expression y = -1 + 3 * x you get:
y= -1 +3*(-2)
Solving:
y= -1 -6
y= -7
So, the value of the variable x is -2 and the value of the variable y is -7.
I really need help with this it's super hard for me.
Answer:
c
f
d
a
b
e
Step-by-step explanation:
f(3)=2×3+5= 11
g(0)=-1/3 ×0 +2 =2
f(1)=2×1+5=7 and so on. :)
Tristan sends 91 text messages in 3 days how many Tristan send per a day
Answer:
~30 messages per day.
Step-by-step explanation:
To get the rate at which Tristan sends text mesages per day, divide the 91 text messages sent divided by the three days they sent (3).
91/3 = 30.333 repeating.
Answer:
Like 30.3 and if you round that to the nearest whole number that would be 30
Step-by-step explanation:
What is the percent of change from 5,000 to 9,000?
Answer:
40%
Step-by-step explanation:
10000 = 5000 = 50% + 9000 = 40%
