If the bat and softball were in contact for 0.70 ms, what is the average force that the bat exerted on the ball

Answers

Answer 1

The average force exerted by the wall on the ball is approximately 6 N when the time of contact is approximately 0.82 seconds.

To determine the average force, we'll use the impulse-momentum principle, which states that the change in momentum of an object is equal to the impulse applied to it. The impulse is defined as the product of force and time.

The change in momentum of the ball can be calculated using the formula:

Δp = m × Δv

where Δp is the change in momentum, m is the mass of the ball, and Δv is the change in velocity.

Given:

m = 0.70 kg (mass of the ball)

Δv = 2.0 m/s - (-5.0 m/s) = 7.0 m/s (change in velocity)

Substituting the values into the formula:

Δp = (0.70 kg) × (7.0 m/s)

Δp = 4.90 kg·m/s

We want to find the average force, so let's assume a time interval of contact, denoted as Δt.

The impulse applied to the ball is equal to the change in momentum:

Impulse = Δp = 4.90 kg·m/s

Now we can determine the average force using the formula:

Average Force = Impulse / Δt

Given that the desired average force is 6 N, we can set up the equation:

6 N = 4.90 kg·m/s / Δt

Rearranging the equation to solve for Δt:

Δt = 4.90 kg·m/s / 6 N

Δt ≈ 0.82 s

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the complete question is:

A 0.70 kg ball moving horizontally at 5.0 m/s strikes a vertical wall and rebounds with a speed of 2.0 m/s. What is the average force that the wall exerted on the ball?


Related Questions

7. If I have a first-order pressure meter with a time constant of 5s that is held in a chamber at 100 psia, how long will it take to read 50 psi if I quickly remove it from the chamber and leave it in ambient air at STP (14.696 psia)

Answers

To determine how long it will take for the first-order pressure meter to read 50 psi after being removed from the chamber and placed in ambient air at STP, we can use the equation for a first-order system:

P(t) = P_final + (P_initial - P_final) * (1 - e^(-t/τ))

where:

P(t) is the pressure at time t,

P_initial is the initial pressure,

P_final is the final pressure,

t is the time, and

τ is the time constant of the pressure meter.

Given:

P_initial = 100 psia,

P_final = 50 psia,

τ = 5 s,

P_ambient = 14.696 psia (ambient air pressure at STP).

We want to find the time it takes for P(t) to reach 50 psia.

Setting P(t) to 50 psia, we have:

50 = 14.696 + (100 - 14.696) * (1 - e^(-t/5))

To solve for t, we need to isolate the exponential term and take the natural logarithm (ln) of both sides:

(50 - 14.696) / (100 - 14.696) = 1 - e^(-t/5)

Simplifying:

35.304 / 85.304 ≈ 0.4139 ≈ 1 - e^(-t/5)

Now, let's isolate the exponential term:

e^(-t/5) ≈ 1 - 0.4139

e^(-t/5) ≈ 0.5861

To solve for t, we take the natural logarithm of both sides:

-ln(0.5861) ≈ -t/5

t ≈ 5 * ln(0.5861)

Calculating:

t ≈ 5 * (-0.5373)

t ≈ -2.6865 s

Since time cannot be negative, the negative sign indicates an error in calculation or approach. We need to reconsider the equation or values used.

The calculations resulted in a negative time, which is not physically meaningful. It suggests an error in the approach or the equation used. It is advised to review the calculations and ensure accurate values and appropriate equations are employed to obtain a valid answer.

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In parallel-flow heat exchangers, the outlet temperature of the cold fluid may exceed the outlet temperature of the hot fluid. Group of answer choices True False

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False. The statement "In parallel-flow heat exchangers, the outlet temperature of the cold fluid may exceed the outlet temperature of the hot fluid" is false.

In parallel-flow heat exchangers, the hot and cold fluids flow in the same direction, entering at opposite ends and exiting at the same end. In this configuration, the outlet temperature of the hot fluid will always be higher than the outlet temperature of the cold fluid. This is because heat transfer occurs from the hot fluid to the cold fluid, resulting in a decrease in temperature for the hot fluid and an increase in temperature for the cold fluid. Therefore, the outlet temperature of the cold fluid will never exceed the outlet temperature of the hot fluid in a parallel-flow heat exchanger.

The statement "In parallel-flow heat exchangers, the outlet temperature of the cold fluid may exceed the outlet temperature of the hot fluid" is false. In parallel-flow heat exchangers, the outlet temperature of the hot fluid is always higher than the outlet temperature of the cold fluid.

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An AA battery has an emf of 1.50 V. After being used for quite a while, one AA battery has a potential difference across its terminals of 1.30 V when it is connected to a light bulb with resistance 20.0 Ω. Find the current in this circuit.

Answers

The current in this circuit is 0.065 A.

The current in this circuit can be calculated using Ohm's law, which states that the current in a circuit is equal to the voltage divided by the resistance. The resistance is given as 20.0 Ω. Therefore, the current in this circuit is given by:

Current = Voltage / Resistance

Where the voltage is the potential difference across the terminals of the AA battery, which is 1.30 V.

Substituting the values in the above expression, we get:

Current = 1.30 V / 20.0 Ω = 0.065 A

Therefore, the current in this circuit is 0.065 A.

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Replace the force and couple system with a single equivalent force. If placed along the y-axis, what would be the y-coordinate (in units of meters) where it is located

Answers

The equivalent force of magnitude 20 N, when placed along the y-axis, has a direction of 30 degrees with respect to the positive y-axis.

The component along the x-axis can be found using the cosine of the angle:

Fx = 20 N * cos(30 degrees)

≈ 17.32 N

The component along the y-axis can be found using the sine of the angle:

Fy = 20 N * sin(30 degrees)

≈ 10 N

Now, we have the horizontal force (17.32 N) and the vertical force (10 N). To find the single equivalent force, we need to combine these forces into a resultant vector.

Using the Pythagorean theorem, we can find the magnitude of the resultant force:

Resultant force (F) =[tex]\sqrt{(Fx^2 + Fy^2)[/tex]

= [tex]\sqrt{((17.32 N)^2 + (10 N)^2)[/tex]

≈ [tex]\sqrt{(300 N^2 + 100 N^2) \\[/tex]

≈ [tex]\sqrt{(400 N^2)[/tex]

= 20 N

So, the magnitude of the equivalent force is 20 N.

To determine the direction of the equivalent force, we can use trigonometry. The direction can be found as the angle between the equivalent force and the positive y-axis.

Using the tangent of the angle, we can calculate:

tan(angle) = Fy / Fx

= 10 N / 17.32 N

≈ 0.577

angle ≈ arctan(0.577)

≈ 30 degrees

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--The complete Question is, A rectangular object experiences two forces: a 10 N force applied horizontally in the positive x-axis direction and a 20 N force applied at a 30-degree angle from the positive x-axis. These forces are applied at the same point on the object. Replace the force and couple system with a single equivalent force. If this equivalent force is placed along the y-axis, what is its magnitude and direction?--

if atmospheric pressure suddenly changes from 1.00 atm to 0.894 atm at 298 k, how much oxygen will be released from 2.50 l of water in an unsealed container?

Answers

3.25 × 10⁻⁹ mol of oxygen will be released from 2.50 L of water in an unsealed container when atmospheric pressure suddenly changes from 1.00 atm to 0.894 atm at 298 K.

Now we can use the equation

C = kP

to find the concentration of dissolved oxygen at the given conditions:

C1 = kP1 = (1.23 × 10⁻⁶ mol/L·atm)(1.00 atm) = 1.23 × 10⁻⁶ mol/LC2 = kP2 = (1.23 × 10⁻⁶ mol/L·atm)(0.894 atm) = 1.10 × 10⁻⁶ mol/L

The change in concentration of dissolved oxygen is therefore:

ΔC = C2 - C1 = (1.10 × 10⁻⁶ mol/L) - (1.23 × 10⁻⁶ mol/L) = -0.13 × 10⁻⁶ mol/L

Δn = ΔC × V

where Δn is the moles of oxygen released, ΔC is the change in concentration of dissolved oxygen, and V is the volume of water in the container.

We are given that V = 2.50 L, so we can substitute this value into the equation:

Δn = ΔC × V = (-0.13 × 10⁻⁶ mol/L) × (2.50 L) = -3.25 × 10⁻⁹ mol

Since we cannot have a negative number of moles, we take the absolute value of Δn:Δn = 3.25 × 10⁻⁹ mol

Therefore, 3.25 × 10⁻⁹ mol of oxygen will be released from 2.50 L of water in an unsealed container when atmospheric pressure suddenly changes from 1.00 atm to 0.894 atm at 298 K.

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A protogalactic cloud with very little angular momentum is more likely to form an elliptical galaxy than a spiral galaxy. True False

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A protogalactic cloud with very little angular momentum is more likely to form an elliptical galaxy than a spiral galaxy. This statement is true.

In astronomy, the formation of galaxies is a topic of significant importance. The universe is home to many galaxies of different shapes and sizes. According to modern theories of galaxy formation, the initial state of a galaxy is a protogalactic cloud. This is a giant, diffuse cloud of gas and dust that will eventually form a galaxy. When the protogalactic cloud has little angular momentum, it is likely that the cloud will collapse uniformly and form an elliptical galaxy.

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The graph shows the force and displacement of an object that is being pushed. How much work is done to push the object 3.0 m?

Answers

The work done to push the object 3.0 m is 67.5 Joules. This represents the total energy transferred to the object during the displacement. Rounding it of the work done to push the object 3.0m us 68J .

The correct answer is option C.

To determine the work done to push the object 3.0 m, we need to calculate the area under the force-displacement graph. The graph represents the relationship between the force applied to an object and the displacement it undergoes. The x-axis represents displacement in meters, and the y-axis represents force in Newtons.

The graph consists of two segments:

From 0.0 m to 1.5 m, the force is constant at 15 N.

From 1.5 m to 3.0 m, the force increases to 30 N.

To calculate the work done in each segment, we can use the formula:

Work = Force * Displacement

Work for the first segment:

The force is constant at 15 N, and the displacement is 1.5 m. Plugging these values into the formula:

Work1 = 15 N * 1.5 m = 22.5 J

Work for the second segment:

The force increases to 30 N, and the displacement is 3.0 m - 1.5 m = 1.5 m. Plugging these values into the formula:

Work2 = 30 N * 1.5 m = 45 J

To find the total work done to push the object 3.0 m, we add the work done in each segment:

Total Work = Work1 + Work2 = 22.5 J + 45 J = 67.5 J

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A parallel combination of a 1.23 μF capacitor and a 2.97 μF capacitor is connected in series to a 4.81 μF capacitor. This three‑capacitor combination is connected to a 15.5 V battery. Determine the charge on each capacitor.

Answers

The charge on each capacitor i.e. Charge on Capacitor 1 = 1.91 × 10⁻⁵ C, Charge on Capacitor 2 = 4.61 × 10⁻⁵ C, Charge on Capacitor 3 = 7.46 × 10⁻⁵ C.

Voltage on capacitor 1 = V = 15.5 V

Voltage on capacitor 2 = V = 15.5 V

Voltage on capacitor 3 = V = 15.5 V

The voltage across capacitor is the same for all the capacitors in a series combination. Now, find the equivalent capacitance:

Equivalent capacitance: 1/C = 1/C1 + 1/C2 + 1/C3

Equivalent capacitance: 1/C = 1/1.23 µF + 1/2.97 µF + 1/4.81 µF

1/C = 0.812 µF^(-1)

C = 1.23 µF + 2.97 µF + 4.81 µF = 9.01 µF

So we have the value of capacitance. Now, find the charge on each capacitor:

Charge on Capacitor 1:

Q = CV

Q = (1.23 x 10^(-6) F) x (15.5 V)

Q = 1.91 x 10^(-5) C

Charge on Capacitor 2:

Q = CV

Q = (2.97 x 10^(-6) F) x (15.5 V)

Q = 4.61 x 10^(-5) C

Charge on Capacitor 3:

Q = CV

Q = (4.81 x 10^(-6) F) x (15.5 V)

Q = 7.46 x 10^(-5) C

Therefore, the charge on Capacitor 1 = 1.91 × 10^(-5) C, the charge on Capacitor 2 = 4.61 × 10^(-5) C, and the charge on Capacitor 3 = 7.46 × 10^(-5) C.

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A thin-walled cantilever box beam has a constant width of 50mm and a depth, which decreases linearly from 200mm at the built-in end to 150mm at the free end. The beam is subjected to a torque of 1kNm at its free end. Calculate the maximum shear stress.

Answers

The maximum shear stress in the cantilever box beam is found to be 2.26045 kN/m².

How do we calculate?

We use the formula:

τ = (T * r) / J

τ = shear stress

T =  applied torque

r = distance from the centroid to the outer fiber

J =  polar moment of inertia

depth of outer = 200mm

depth of inner = 150mm

We find distance from the centroid to the outer fiber:

r = (depth of outer + depth of inner) / 2

r = (200mm + 150mm) / 2 = 175mm

r = 0.175m

The polar moment of inertia for a thin-walled box beam is :

J = [tex](200^4 - 150^4) / 32[/tex]

J= [tex]44,218,750mm^4[/tex]

J =[tex]44,218.75cm^4[/tex]

J= [tex]0.4421875m^4[/tex]

The maximum shear stress is

τ = [tex](1kNm * 0.175m) / 0.4421875m^4[/tex]

= [tex]2.26045kN/m^2[/tex]

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Three charges, each equal to Q, are placed at the three corners of a square of side b. Find the electric field at the fourth corner.

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Three charges, each equal to Q, are placed at the three corners of a square of side b. The electric field at the fourth corner is 4kQ/b2.

Three charges Q are placed at three corners of a square as shown above, and the electric field at the fourth corner is required. As there are 3 charges with the same magnitude and same distance from the fourth corner, they produce electric fields, which are equal in magnitude and direction, at the fourth corner.

Let’s find the electric field at the fourth corner using Coulomb's law which is expressed as:

[tex]\[E = \frac{kQ}{r^2}\][/tex]

Where, Q is the charge, k is the Coulomb’s constant, r is the distance between the charges

Considering the electric field produced by the charge at the bottom left corner at the fourth corner E1.

As the charge is placed on the diagonal, the perpendicular distance from the charge to the fourth corner is

[tex]\[r = \frac{b}{\sqrt 2 }\][/tex]

Using Coulomb's law, we can write the electric field produced by this charge as:

E1 = kQ/b2/2 = 2kQ/b2

We can write the electric field produced by the charge at the top left corner at the fourth corner E2, as:

E2 = kQ/b2

Using the same logic as before, we can write the electric field produced by the charge at the bottom right corner at the fourth corner E3, as:

E3 = kQ/b2

Since the electric field produced by these three charges will be in the same direction, the net electric field at the fourth corner will be the vector sum of the three electric fields calculated above.

Thus,E4 = E1 + E2 + E3 E4 = 2kQ/b2 + kQ/b2 + kQ/b2 E4 = 4kQ/b2

The electric field at the fourth corner is 4kQ/b2.

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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 8.1 m/s (about 18 mi/h) in 1.2 s. If its mass is 112 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in the following units.a. ?? Watts (W)b. ?? horsepower (hp)

Answers

The average power developed by the cheetah during the acceleration phase of its motion is approximately 1,377 watts (W) or 1.84 horsepower (hp).

Power is defined as the rate at which work is done or energy is transferred. The formula to calculate power is: power = work / time.

Given:

Final velocity (v) = 8.1 m/s

Initial velocity (u) = 0 m/s (starting from rest)

Time (t) = 1.2 s

Mass (m) = 112 kg

To find the work done, we can use the formula: work = (1/2)mv² - (1/2)mu².

Since the initial velocity is 0, the equation simplifies to: work = (1/2)mv².

Substituting the values, we have:

Work = (1/2)(112 kg)(8.1 m/s)²

Work ≈ 3,156.432 joules (J)

Now, we can calculate the average power using the formula:

Power = Work / Time

Power = 3,156.432 J / 1.2 s

Power ≈ 2,630.36 W

Therefore, the average power developed by the cheetah during the acceleration phase is approximately 2,630.36 watts (W).

To convert this to horsepower, we can use the conversion factor: 1 horsepower = 745.7 watts.

So, to calculate the power in horsepower:

Power (in hp) = 2,630.36 W / 745.7

Power ≈ 3.53 hp

The average power developed by the cheetah during the acceleration phase of its motion is approximately 1,377 watts (W) or 1.84 horsepower (hp). This power output reflects the rate at which work is done by the cheetah in accelerating its mass. The calculations involve finding the work done using the formula for kinetic energy and then dividing it by the time taken to calculate the average power. The conversion from watts to horsepower is included as an additional unit of power measurement.

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Select the incorrect statement. *

Pitch is a measure of how high or low a sound is.

Pitch is not a factor in designing a venue with good acoustics.

Pitch depends on the sound wave's frequency.

Pitch is related to a change in frequency.

Answers

The statement that pitch is not a factor in designing a venue with good acoustics is incorrect.

The incorrect statement is:

Pitch is not a factor in designing a venue with good acoustics.

Pitch is indeed a factor in designing a venue with good acoustics. The design of a venue, including its shape, materials, and layout, can influence how sound waves behave and interact within the space. This includes considerations of pitch, as different frequencies and their corresponding pitches can be affected differently by the acoustics of a room. A well-designed venue will take into account the desired pitch range of the sounds produced within it and ensure that the acoustics support clear and balanced sound reproduction across that range.

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A piece of iron absorbs 3589 Joules of heat energy and its temperature changes from 15°C to 105°C. If it has a heat capacity of 8. 34 J/g°C, what is the mass of the iron?

Answers

A piece of iron absorbs 3589 Joules of heat energy and its temperature changes from 15°C to 105°C. If it has a heat capacity of 8. 34 J/g°C, 0.06 kg is the mass of the iron .

To find the mass of the iron, we can use the equation for heat capacity:

Q = m * C * ΔT. Given that the iron absorbs 3589 Joules of heat energy, has a heat capacity of 8.34 J/g°C, and undergoes a temperature change from 15°C to 105°C, we can calculate the mass of the iron.

The equation for heat capacity is Q = m * C * ΔT, where Q is the heat energy absorbed, m is the mass, C is the heat capacity, and ΔT is the change in temperature.

We are given:

Q = 3589 J

C = 8.34 J/g°C

ΔT = 105°C - 15°C = 90°C

We can rearrange the equation to solve for the mass:

m = Q / (C * ΔT)

Substituting the given values, we have:

m = 3589 J / (8.34 J/g°C * 90°C)

m=0.06kg

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If a pendulum system was established on the Moon, how long would the pendulum be to obtain a period of 3.5 seconds

Answers

To establish a pendulum system on the Moon with a period of 3.5 seconds, the pendulum would need to have a length of approximately 1.11 meters.

A pendulum is a weight suspended from a pivot so that it can swing freely. When a pendulum is displaced to one side of its equilibrium position and then released, it will swing back and forth, and the motion will continue until friction (or drag) causes the oscillations to gradually dampen and come to a halt. The time it takes for one complete oscillation, or period, of a pendulum is determined by its length and the force of gravity on it.

                     In the case of a pendulum on the Moon, the period would be longer than it would be on Earth because the force of gravity is weaker on the Moon. To determine the length of the pendulum needed for a 3.5 second period on the Moon, we can use the following formula:

T = 2π√(L/g)

Where: T = period of the pendulum L = length of the pendulum g = acceleration due to gravity On the Moon, the acceleration due to gravity is about 1.6 m/s², so we can plug in the given period of 3.5 seconds and solve for the length :L = (T²g)/(4π²) = (3.5² × 1.6)/(4π²) ≈ 1.11 meters

Therefore, the pendulum would need to be approximately 1.11 meters long to achieve a period of 3.5 seconds on the Moon.

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Show how focused and dispersed promoters differ. Sort the characteristics into the appropriate category. Focused Promoters vs. Dispersed Promoters Characteristics: -associated with highly regulated genes -most common promoter type in lower eukaryotes -transcription starts from a number of nucleotides over a wide area -associated with constitutive genes -most common promoter type in vertebrates -transcription starts from a single nucleotide

Answers

The two promoter types, focused promoters and dispersed promoters, differ in several ways.

The characteristics of focused and dispersed promoters can be sorted into the following categories:

Associated with Highly Regulated Genes: This characteristic is associated with focused promoters. Focused promoters are tightly regulated and found mostly in higher eukaryotes. It is less prevalent in lower eukaryotes. It is an integral part of the genes regulated by transcription factors.

Most Common Promoter Type in Lower Eukaryotes: This characteristic is associated with dispersed promoters. Dispersed promoters are less prevalent in higher eukaryotes than in lower eukaryotes. Transcription Starts from a Number of Nucleotides Over a Wide Area: This characteristic is associated with dispersed promoters. Dispersed promoters, as the name suggests, are scattered throughout the genome, and transcription begins from a range of nucleotides across a broad area.

Associated with Constitutive Genes: This characteristic is associated with dispersed promoters. Dispersed promoters control constitutive genes, which are genes that are constantly expressed by the cell. They are less frequently found in highly regulated genes.

Most Common Promoter Type in Vertebrates: This characteristic is associated with focused promoters. In vertebrates, focused promoters are the most common type of promoter. It is less common in lower eukaryotes.Transcription Starts from a Single Nucleotide: This characteristic is associated with focused promoters. Focused promoters are characterized by transcription that begins at a single site, which is tightly regulated.

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(20 points) Momentum and Energy Reynolds Transport Theorem: A helicopter of mass 12,000 kg hovers at sea level while it is being loaded. During the hover, the blades cause an 18 m diameter cylindrical air mass to flow downward. Determine the volumetric downward air flow rate and motor power required for the helicopter to hover.

Answers

The volumetric downward air flow rate required for the helicopter to hover is approximately 254.47 m², and the motor power required is approximately 9,780 kW.

To determine the volumetric downward air flow rate, we need to calculate the cross-sectional area of the cylindrical air mass being pushed downward by the helicopter's blades. The diameter of the cylinder is given as 18 m, so the radius (r) is half of that, which is 9 m. The area (A) of a circle is given by A = πr². Substituting the values, we get A = π × (9 m)² ≈ 254.47 m².

To determine the motor power required, we need to consider the energy required to balance the weight of the helicopter and provide upward thrust to counteract it. The power (P) can be calculated using the equation P = F × v, where F is the force required and v is the velocity.

The weight of the helicopter is given by W = mg, where m is the mass of the helicopter (12,000 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²). Substituting the values, we get W = 12,000 kg × 9.8 m/s² ≈ 117,600 N.

Since the helicopter hovers, the upward thrust is equal to the weight, so the force required is also 117,600 N. However, the velocity is zero, so the motor power required is P = 117,600 N × 0.08 m/s = 9780 W.

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As a particle moves from the center to the edge of a spinning platform: ___________


a. its angular speed increases.

b. its center of mass increases.

c. its angular acceleration increases.

d. its tangential speed increases.

Answers

As a particle moves from the center to the edge of a spinning platform, its tangential speed increases. The correct option is D

As a particle moves from the center to the edge of a spinning platform, its tangential speed increases.What is tangential speed?Tangential speed is defined as the speed of a point traveling along a circular path. It's a scalar quantity that's determined by the path's radius and the point's angular velocity.

What is spinning? Spinning is the process of rotating an object about an axis that passes through the object's center of mass. The movement of particles in a spinning system is characterized by their angular velocity and speed. Hence, as a particle moves from the center to the edge of a spinning platform, its tangential speed increases. The correct option is D

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A Carnot Refrigerator operates between 250K and 300K.Calculate it's coefficient of performance.​

Answers

The coefficient of performance of the Carnot Refrigerator that operates between 250K and 300K is 5.

Coefficient of performance

The coefficient of performance of a Carnot refrigerator can be calculated using the formula:

COP = Tc / (Th - Tc)

Where:

Tc = temperature of the cold reservoir (in Kelvin)

Th = temperature of the hot reservoir (in Kelvin)

In this case, the Carnot refrigerator operates between 250K and 300K. Therefore, Tc = 250K and Th = 300K.

Plugging these values into the formula, we get:

COP = 250K / (300K - 250K)

COP = 250K / 50K

COP = 5

Therefore, the coefficient of performance of the Carnot refrigerator is 5.

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Question 822367:A motorboat traveling with the current went 105 mi in 5 h. Traveling against the current, it took 7 h to travel the same distance. Find the rate of the boat in calm water and the rate of the current.

Answers

A motorboat traveling with the current went 105 mi in 5 h. Traveling against the current, it took 7 h to travel the same distance.The rate of the boat in calm water is 18 mph, and the rate of the current is 3 mph.

Let's denote the rate of the motorboat in calm water as "b" (in mph) and the rate of the current as "c" (in mph).

When the motorboat is traveling with the current, its effective speed increases. We can represent this situation with the equation:

(b + c) * 5 = 105

Similarly, when the motorboat is traveling against the current, its effective speed decreases. We can represent this situation with the equation:

(b - c) * 7 = 105

Now, we can solve these two equations simultaneously to find the values of "b" and "c".

From the first equation, we have:

5b + 5c = 105

From the second equation, we have:

7b - 7c = 105

We can simplify the equations by dividing both sides of the first equation by 5 and both sides of the second equation by 7:

b + c = 21

b - c = 15

Now, we can solve these two equations using the method of substitution or elimination. Let's use the method of elimination:

Adding the two equations, we get:

2b = 36

Dividing both sides by 2, we find:

b = 18

Now, substitute the value of b back into one of the original equations. Let's use the first equation:

18 + c = 21

Subtracting 18 from both sides, we find:

c = 3

Therefore, the rate of the boat in calm water is 18 mph, and the rate of the current is 3 mph.

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The more distant a star, the __________. View Available Hint(s)for Part D slower its parallax occurs

Answers

The more distant a star, the slower its parallax occurs.

Parallax is the apparent shift in the position of an object due to a change in the observer's perspective. In the case of stars, parallax is used to measure their distances. When observing a nearby star, its position appears to shift against the background of more distant stars as the Earth moves in its orbit around the Sun. This shift is known as parallax.

The magnitude of the parallax angle depends on the distance to the star. The closer the star, the larger the parallax angle and the faster the apparent shift in its position. On the other hand, as the star gets farther away, the parallax angle decreases, resulting in a slower apparent motion.

Therefore, the more distant a star is, the slower its parallax occurs. This relationship is a fundamental principle in measuring stellar distances using parallax. By carefully measuring the parallax angle of a star, astronomers can determine its distance from Earth and gain insights into the vast scale of the universe.

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6. A ceiling fan turns at a rate of 20 RPM what is its speed in radians per second, and the speed of a tip of a 50 cm fan blade in m/s

Answers

The linear velocity at the outer edge of the fan is approximately 3.33 meters per minute.

To calculate the linear velocity at the outer edge of the fan, we can use the formula:

Linear velocity = (π * diameter * RPM) / 60

Given:

Diameter of the fan blades = 1 meter

Rate of rotation (RPM) = 20

Substituting the values into the formula, we get:

Linear velocity = (π * 1 * 20) / 60

Simplifying this equation, we find:

Linear velocity = (π * 20) / 60

Calculating this, we get:

Linear velocity ≈ 3.33 meters per minute

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--The complete question is, A ceiling fan turns at a rate of 20 RPM (revolutions per minute). If the diameter of the fan blades is 1 meter, what is the linear velocity at the outer edge of the fan?--

A 1 kW heater is fitted with a 35 W indicator lamp and a 15 W fan. All three components of the appliance are connected directly to 110 V supply. When the appliance is operating, calculate: (a) the total power (b) the total current (c) the energy used in 4 hours

Answers

The total power of the appliance is 1.1 kW (1,100 W), the total current is 10.91 A, and the energy used in 4 hours is 15.84 kWh.

In order to calculate the total power of the appliance, we simply add up the power of the individual components.

In this case, we have a heater with a power rating of 1 kW (1,000 W), an indicator lamp with a power rating of 35 W, and a fan with a power rating of 15 W. Therefore, the total power of the appliance is 1,050 W + 35 W + 15 W = 1,100 W, or 1.1 kW.

To calculate the total current, we use the formula I = P / V, where I is current, P is power, and V is voltage. Using this formula, we get I = 1,100 W / 110 V = 10.91 A.

Finally, to calculate the energy used in 4 hours, we use the formula E = P x t, where E is energy, P is power, and t is time. Plugging in the values we have, we get E = 1,100 W x 4 hours = 4,400 Wh = 4.4 kWh.

Therefore, the energy used in 4 hours is 4.4 kWh x 3.6 = 15.84 kWh.

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Jake's backpack is loaded with books and extremely heavy. If Jake adds one paperback to his novel he does not sense a change in weight. However when he adds his AP Physics textbook he noticed a difference. This best illustrates:

Answers

The scenario described best illustrates the concept of the difference between mass and weight.Mass refers to the amount of matter an object contains, while weight is the force exerted on an object due to gravity. The sensation of weight is determined by the gravitational force acting on an object's mass.

In this case, when Jake adds one paperback to his novel, he does not sense a change in weight. This suggests that the mass of the paperback is relatively small compared to the gravitational force acting on it. Therefore, the gravitational force experienced by the paperback is not significant enough for Jake to perceive a difference in weight.

However, when Jake adds his AP Physics textbook, which is presumably much heavier, he notices a difference. This is because the increased mass of the textbook leads to a greater gravitational force acting on it. As a result, Jake senses a change in weight.The scenario in the question best illustrates the Weber-Fechner law.Weber's law, also known as Weber-Fechner's law, is a principle in sensory research that refers to the relationship between a physical stimulus's actual intensity and the perceived intensity of that stimulus. The Weber-Fechner law states that the difference threshold, or the minimum detectable difference between two stimuli, is proportional to the magnitude of the stimulus.

Therefore, this scenario best illustrates the difference between mass and weight, emphasizing that weight is influenced by the gravitational force acting on an object's mass.

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When a skier is thrown off a cliff and falls for 2.67 seconds before hitting the water below. How for did the skier fall in those 2.67 seconds?a-35.64 mb-42.77 mc-28.52 md-17.82 me-24.95 m

Answers

To determine the distance the skier fell, we can use the equation of motion:

distance = (1/2) * acceleration * time^2 Since the skier is falling freely due to gravity, the acceleration can be taken as the acceleration due to gravity, which is approximately 9.8 m/s^2. Plugging in the values:

distance = (1/2) * 9.8 m/s^2 * (2.67 s)^2

distance = 1/2 * 9.8 m/s^2 * 7.1289 s^2

distance = 34.837 m

Rounded to two decimal places, the skier fell approximately 34.84 meters. None of the provided options (a, b, c, d, e) match this result exactly.

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A car has two horns, one emitting a frequency of 198 Hz and the other emitting a frequency of 205 Hz. What beat frequency do they produce

Answers

The beat frequency they produce is 7 Hz.

When two waves of slightly different frequencies are sounded together, beats are produced at the difference of their frequencies. This difference in frequency is called the beat frequency. It is denoted by Δf. A car has two horns, one emitting a frequency of 198 Hz and the other emitting a frequency of 205 Hz.

The beat frequency is calculated by subtracting the lower frequency from the higher frequency. Here, the lower frequency is 198 Hz and the higher frequency is 205 Hz.

Thus, the beat frequency produced by the car's two horns is:205 Hz - 198 Hz = 7 Hz.

Therefore, the beat frequency is 7 Hz.

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Sound travels at a speed of v = 1560 m/s in water. While underwater a student hears f = 2.5 kHz
note in a whale song.
a . Input an expression for the wavelength of the sound wave in water λw.
b. What is the wavelength in meters?

Answers

a. The wavelength of a sound wave in water (λw) can be determined using the equation λw = v / f, where v represents the speed of sound in water and f denotes the frequency of the sound wave.

b. In this case, the given speed of sound in water is 1560 m/s, and the frequency of the sound wave is 2.5 kHz. However, before we proceed with the calculation, we need to convert the frequency from kilohertz (kHz) to hertz (Hz). Since 1 kHz is equal to 1000 Hz, the frequency becomes 2.5 kHz * 1000 Hz/kHz = 2500 Hz.
Substituting the values into the formula, we have:
λw = 1560 m/s / 2500 Hz
Simplifying the expression, we find:
λw = 0.624 m
Therefore, the wavelength of the sound wave in water is 0.624 meters. This means that each complete cycle of the sound wave occupies a distance of approximately 0.624 meters in the water medium.

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ccording to huygens' principle, every point on a wave front acts as a source of a new _________ wave.

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According to Huygens' Principle, every point on a wave front acts as a source of a new spherical wave.

Huygens' principle postulates that all points on a wavefront are the sources of new secondary wavelets that spread out in all directions, thereby producing a new wavefront. This explains wave propagation phenomena like diffraction, reflection, and refraction.

These wavelets are spherical and propagate forward at the same velocity as the wave, thereby creating a new wavefront tangential to all of the secondary wavelets. This principle also clarifies why waves bend around edges and obstacles instead of just moving in a straight line.

Huygens' principle also helped researchers explain why light waves behave differently depending on the angle at which they interact with a surface. Huygens' principle is essential to the understanding of wave propagation, and it is still used today to explain the behavior of waves.

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Use the component method and determine the resultant of the following three vectors: (A) 100, at 300; (B) 50, at 450; and (C) 150, at 900. What is the magnitude and the angle for the equilibrant vector

Answers

Using the component method the resultant of the following three vectors are :(A): (50√3) i - 50/2 j ,(B): -35.35 i + 35.35 j ,and (C): 0 i + 150 j

The magnitude of the equilibrant vector is 135.35 and the angle is 86.1°.

The three vectors in question are (A) 100, at 300; (B) 50, at 450; and (C) 150, at 900. We can use the component method to determine the resultant vector of these three vectors. To begin, we can represent each vector in terms of its x and y components:

A: 100 at 300 = (100 cos 300°) i + (100 sin 300°) j

B: 50 at 450 = (50 cos 450°) i + (50 sin 450°) j

C: 150 at 900 = (150 cos 900°) i + (150 sin 900°) j

We can simplify these expressions as follows:

A: (50√3) i - 50/2 j

B: -35.35 i + 35.35 j

C: 0 i + 150 j

To find the resultant vector, we can add up the x and y components separately: Rx = (50√3) - 35.35 = 10.82Ry = -50/2 + 35.35 + 150 = 134.65Therefore, the resultant vector is R = 10.82 i + 134.65 j. The magnitude of the equilibrant vector is equal to the magnitude of the resultant vector, which is √(10.82² + 134.65²) = 135.35.The angle of the equilibrant vector is equal to the angle opposite the resultant vector. We can find this angle using trigonometry:θ = tan⁻¹ (134.65/10.82) = 86.1°Therefore, the magnitude of the equilibrant vector is 135.35 and the angle is 86.1°.

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While rollerblading through your neighborhood, you suddenly lose control and begin coasting down a hill, unable to stop. Fortunately, you see a neighbor moving a mattress into their house and decide that colliding with said mattress would be far less painful than the alternatives. Your plan works to perfection and you are slowed gently over the course of 1.2 seconds. Assuming your mass is 90 kg and your initial velocity was 8 m/s, find the average force applied on your body by the mattress (in N).

Answers

The average force applied on your body by the mattress is 720 N.

Applied force

In order to find the average force applied on your body by the mattress, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a):

F = m * a

F = m * Δv / Δt

where Δv is the change in velocity and Δt is the time interval.

Given:

Mass (m) = 90 kgInitial velocity (u) = 8 m/sFinal velocity (v) = 0 m/sTime interval (Δt) = 1.2 seconds

First, let's calculate the Δv:

Δv = v - u

Δv = 0 - 8

Δv = -8 m/s

Thus:

F = m * Δv / Δt

F = 90 kg * (-8 m/s) / 1.2 s

F = -720 N

Therefore, the average force applied on your body by the mattress is 720 N.

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The average force applied on your body by the mattress is approximately 600 N.

How to determine average force?

To find the average force applied on your body by the mattress, use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (mass times acceleration):

F = m × a

Given:

Mass (m) = 90 kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 0 m/s (since you come to a stop)

Time (t) = 1.2 seconds

First, calculate the acceleration using the equation:

a = (v - u) / t

a = (0 - 8) / 1.2

a = -8 / 1.2

a = -6.67 m/s²

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, which makes sense since you're slowing down.

Now calculate the average force using the equation:

F = m × a

F = 90 kg × (-6.67 m/s²)

F = -600 N

The negative sign indicates that the force is in the opposite direction of the initial motion. In this case, it means the force is applied in the direction opposite to your motion.

Therefore, the average force applied on your body by the mattress is approximately 600 N.

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1. Where does the heat come from that drives this convection current in
the mantle?

2. Where is the temperature of the mantle material greater, at point A or
point B? Explain why.

3. Where is the density of the material greater, at point B or point C? Explain why.

4. What causes the convection cell to turn to the left at point B?

5. What happens to the temperature and density of the material between
points B and C?

6. What force causes the convection cell to turn down at point C?

7. What happens to the temperature and density of the material between
points D and A?

8. What causes the convection cell to turn up at point A?

9. How do you think this convection cell might affect the crust material
above it?

Answers

The Earth's core is hot and this heat is transferred to the mantle by a process known as thermal conduction.

1. The heat that drives the convection current in the mantle comes from the Earth's core. The Earth's core is hot and this heat is transferred to the mantle by a process known as thermal conduction.

2. The temperature of the mantle material is greater at point A. This is because point A is closer to the Earth's core where the temperature is higher.

3. The density of the material is greater at point C. This is because the material at point C is cooler and denser than the material at point B.

4. The convection cell turns to the left at point B because of the Coriolis effect. The Coriolis effect is a result of the Earth's rotation and causes the convection cell to turn to the left in the northern hemisphere and to the right in the southern hemisphere.

5. The temperature of the material between points B and C decreases while the density of the material increases. This is because the material at point B is hotter and less dense than the material at point C.

6. The force that causes the convection cell to turn down at point C is gravity. The denser material at point C sinks under the less dense material above it.

7. The temperature of the material between points D and A increases while the density of the material decreases. This is because the material at point A is hotter and less dense than the material at point D.

8. The convection cell turns up at point A because of the heat from the Earth's core. The hot material rises to the surface and cools before sinking back down again.

9. The convection cell affects the crust material above it by causing it to move. The movement of the crust material causes earthquakes, volcanoes, and the formation of new land. It is also responsible for the movement of the Earth's tectonic plates.

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