Answer: true
Explanation:
If the scale model was working as it was predicted to work, then the final product is expected to be flawless. It should be a reasonable product if the scale model is working. Our answer is the option True.
Jonas and his family are moving to another part of the city. As Jonas, his brother, and his Dad were driving one of the trucks filled with furniture to their new home, Jonas noticed that the truck seemed to take longer to stop now that it was heavier with the furniture. Which Newton's Law explains why this happens?
Answer:newtons second law
Explanation:
To get something to accelerate you have to apply a pull force . if the mass increase a grater pull is required
The law that explains the fact that a heavier truck takes a longer time to stop is Newton's law of inertia.
According to Newtons first law of motion also called the law of inertia, a body will continue in a state of rest or uniform motion unless it is acted upon by an external, unbalanced force.
This law explains the reluctance of heavier objects to move or stop. The law that explains the fact that a heavier truck takes a longer time to stop is Newton's law of inertia.
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Bernoulli's principle is responsible for most of the lift produced by an airplane wing.
True
False
Answer:
huiiiiuuu beautiful...
A 5 kg rifle fires a 15 g bullet at a muzzle velocity of 600 m/s. Find the recoil velocity of
the rifle
Answer:
v₂ = 1.8 [m/s]
Explanation:
To be able to solve this problem we must raise the principle of conservation and quantity of movement. It is going to study the momentum before and after the firing of the rifle.
P = m*v
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Now we need to analyze the moment before and after the shot.
[tex](m_{1}+m_{2})*v_{1}=-(m_{1}*v_{2})+(m_{2}*v_{3})[/tex]
where:
m₁ = mass of the rifle = 5 [kg]
v₁ = velocity of the rifle and the bullet before firing = 0 (no movement)
m₂ = mass of the bullet = 15 [g] = 0.015 [kg]
v₂ = velocity of recoil [m/s]
v₃ = velocity of the bullet after firing = 600 [m/s]
Now replacing:
[tex](5+0.015)*0 = -(5*v_{2})+(0.015*600)\\9 = (5*v_{2})\\v_{2}=1.8 [m/s][/tex]
Momentum is the product of mass and velocity. The recoil velocity of the rifle weighing 5 kg is 1.8 m/s.
What is conservation of momentum?According to the law of conservation of momentum if two objects are in contact with each other then for that system of the two objects the momentum of the object before will be equal to the momentum of the object after the collision.
GIven to us
Mass of the rifle, M = 5 kg
Mass of the bullet, m = 15 g = 0.015 kg
Velocity of the bullet afterwards, v₂ = 600 m/s
We know that according to the law of conservation of momentum, the momentum of the bullet and riffle before shooting will be equal to the momentum of the bullet and riffle after shooting.
[tex]Mu_1 + mu_1 = Mv_1 + mv_2[/tex]
Since, before shooting the bullet was in the riffle and the velocity of both was 0,
[tex]M(0) + m(0) = Mv_1 + mv_2\\\\-Mv_1 = mv_2\\\\v_1 = -\dfrac{m \times v_2}{M}[/tex]
Substitute the values,
[tex]v_1 = -\dfrac{0.015 \times 600}{5}\\\\v_1 = -1.8\rm\ m/s[/tex]
Thus, the recoil of the rifle is -1.8 m/s, the negative sign denotes that the velocity of recoil was in opposite direction to the bullet.
Hence, the recoil velocity of the rifle weighing 5 kg is 1.8 m/s.
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say something random cuz i already answered my own question
Answer:
The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp is explained below in details.
Explanation:
The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.
So, I think now you got your answer which is absolutely correct and it will help you.
Answer:
hello my good friend
Explanation:
Patriotism and education are traditional American values. Please select the best answer from the choices provided T F
Answer:
True
Explanation:
It is a true statement that "Patriotism and education are traditional American values."
The United States of AmericaThe United States of America are bound together by certain core values that hold the entire country together. These values are reverberated any time the ideals of the country are discussed.
Two of the key values of the American society are;
PatriotismEducationHence, it is a true statement that "Patriotism and education are traditional American values."
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Ramas weight is 40 kg. She is carrying a load of 20 kg up to a height of 20 m. What work does she do? What work does she do?
Answer:
The work done by Ramas is 3920 N.
Explanation:
Given;
mass of the load lifted by Ramas, m = 20 kg
height through which the load is lifted, h = 20 m
The work done by Ramas is equal to gravitational potential due to the height in which the load is lifted.
W = PE = mgh
where;
g is acceleration due to gravity = 9.8 m/s²
W = 20 x 9.8 x 20
W = 3920 N.
Therefore, the work done by Ramas is 3920 N.
Find the weight of a 4.2 kg backpack,
A) 41.16 N
B) 0.42 kg
C) 41.16 kg
D) 0.42 N
Answer:
Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.
If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.
If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.
A hunter shoots a tranquilizer dart straight at a monkey who is
hanging on a tree branch that is 1.5 meters high. The tree is 16 meters
away from the hunter. The man shot the dart at the monkey with an
initial sideways velocity of 40 m/s, and at the same time, the monkey
let go of the branch. what time will the monkey reach the same height
of the arrow?
t= _S
Answer:
The donkey might be dead
How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?
Answer:
The car will travel 541.67 m
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
The relation between the initial and final speeds is:
[tex]v_f=v_o+a.t[/tex]
Where:
vf = Final speed
vo = Initial speed
a = Acceleration
t = Elapsed time
The acceleration can be calculated by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
And the distance traveled is:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]
The car travels during t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.
Let's convert the speeds to m/s. Recall 1 Km=1000 m and 1 h= 3600 s:
vo=50 Km/h * 1000/3600 = 13.89 m/s
vf=80 Km/h * 1000/3600 = 22.22 m/s
Calculating the acceleration:
[tex]\displaystyle a=\frac{22.22-13.89}{30}[/tex]
[tex]a = 0.28\ m/s^2[/tex]
Now for the distance:
[tex]\displaystyle x=13.89*30+\frac{0.28.30^2}{2}[/tex]
[tex]x=416.67\ m+125\ m[/tex]
[tex]\boxed{x = 541.67\ m}[/tex]
The car will travel 541.67 m
According to the question,
Final speed, [tex]v_f = 80 \ km/h \ ,or \ 22.22 \ m/s[/tex]Initial speed, [tex]v_o = 50 \ km/h, or \ 13.89 \ m/s[/tex]Elapsed time, [tex]t = 30 \ s[/tex]We know the relation,
→ [tex]v_f = v_o +at[/tex]
or,
→ [tex]a = \frac{v_f-v_o}{t}[/tex]
Now,
The acceleration,
→ [tex]x = v_o.t+ \frac{a.t^2}{2}[/tex]
By substituting the values,
[tex]= \frac{22.22-12}{30}[/tex]
[tex]= 0.28 \ m/s^2[/tex]
hence,
The distance traveled be:
→ [tex]x = 13.89\times 30+\frac{0.28.30^2}{2}[/tex]
[tex]= 416.67+125[/tex]
[tex]= 541.67 \ m[/tex]
Thus the above answer is right.
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The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated
F = m × a
300N = 100kg × a
a = 300 : 100
a = 3ms-²
A bit of explanation :F = Force (N)
m = mass (kg)
a = acceleration (ms-², m/s²)
What do atoms of elements in a group have that makes their properties similar? A. the same atomic mass
B. the same number of protons
C. the same number of outer level electrons
D. the same total number of electrons
Land plants are adapted to survive on land through stomata to regulate water regulation, specialized cells, structures that collect sunlight, and water!
Answer:
stomata to regulate water
specialized cells
Explanation:
Land plants are able to successfully adapt to staying on land through the use of stomata to regulate water loss and through the development of specialized cells that give support to grow erect.
Water regulation is important for the survival of plants on land, otherwise, they may face desiccation as a result of the heat from the sun. The stomata is a structure found on the leaves of land plants that open and close to regulate the amount of water lost to the environment through evapotranspiration. When there is adequate water and the plant can afford to lose some water, the stomata open, otherwise, the stomata close.
Support is also important for land plant's survival and the development of specialized cells in the form of sclerenchyma cells take care of this. The fibers and sclerids are two types of sclerenchyma cells that primarily function to support the land plants.
_____ increase your risk
Answer: All forms of distraction.
A cyclist accelerates from a velocity of 10 miles/hour east until reaching a velocity of 20 miles/hour east in 5 seconds. What was the cyclist's acceleration?
Answer:
[tex]a = 0.894\ m/s^2[/tex]
Explanation:
Motion with Constant Acceleration
A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is
[tex]v_f=v_o+at[/tex]
Where vo is the initial speed, a is the acceleration, and t is the time.
The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.
Both speeds are given in miles/hour and we must convert it to m/s:
1 mile/hour = 0.44704 m/s
10 mile/hour = 4.47 m/s
20 mile/hour = 8.94 m/s
The acceleration is calculated by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
[tex]\displaystyle a=\frac{8.94-4.47}{5}[/tex]
[tex]a = 0.894\ m/s^2[/tex]
Uses of lens and mirror in daily life
Answer:
Decorating. Because mirrors reflect light, they create an illusion of open space by doubling whatever is in a room. ...
Safety. People use mirrors and lenses for safety. ...
Vision. Eye doctors use lenses to correct vision. ...
Magnification and Science. ...
Energy and Affirmation Techniques. ...
Photography. ...
How much force would be needed to
push a 22 kg box across the floor with
an acceleration of 1.9 m/s^2? Assume
that there is a coefficient of friction of.
17 between the box and the floor.
Help me with this!!!!!!!it’s due in 10 minutes
There would be two forces acting on the box parallel to the floor, with a net force of
∑ F = p - f = m a
where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .
There are also only two forces acting on the box perpendicular to the floor, with net force
∑ F = n - w = 0
where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.
w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :
n = w = m g
n = (22 kg) (9.8 m/s²)
n = 215.6 N
The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that
f = µ n
f = 0.17 (215.6 N)
f = 36.652 N
Now solve for the required pushing force:
p - 36.652 N = (22 kg) (1.9 m/s²)
p ≈ 78 N
Answer:
0
Explanation:
A string attached to an airborne balloon was maintained at an angle of 54 degrees with the ground. If 2.3 m of string was reeled in to return the balloon back to the ground, what was the horizontal and vertical displacements
Answer:
dₓ = 1.35 m
dy = 1.86 m
Explanation:
In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:
[tex]d_{x} = d\ Cos\ \theta[/tex]
where,
dₓ = horizontal component of displacement = ?
d = resultant displacement = 2.3 m
θ = angle between displacement and ground = 54°
Therefore,
[tex]d_{x} = (2.3\ m)\ Cos\ 54^0[/tex]
dₓ = 1.35 m
For vertical component of displacement:
[tex]d_{y} = d\ Sin\ \theta\\d_{y} = (2.3\ m)\ Sin\ 54^0[/tex]
dy = 1.86 m
A communication satellite is in a circular path orbit around Earth. If the speed of the satellite is constant, the net force acting on the satellite ____.
Answer:
is changing in direction, but constant in magnitude
Explanation:
This question is a bit tricky since the velocity of the satellite is changing, but the speed is constant.
Speed is simply a measure of how fast you are going. It doesn't matter where you're going, just how quickly.
Velocity, on the other hand, does care about which direction you're going. For example, it could be then when you travel right, your velocity is positive, and when you travel left, your velocity is negative. This is the similar for a 2D shape like a circular orbit
Since we know velocity is changing, there must be acceleration which changes that velocity (since acceleration is the change in velocity: going from 0 to 60 mph, for example)
Thus, with a non-zero net acceleration, we know that there must be a force that is changing in direction, but constant in magnitude (since the orbit is a circle, and always attracted to the center of the Earth at equal distance).
An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 320 mV/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. The magnetic field amplitude of the signal at that point, in nT, is closest to:
Answer:
1.07 nT
Explanation:
We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.
So, B = E/c
Substituting E and c into B, we have
B = E/c
= 0.32 V/m ÷ 3 × 10⁸ m/s
= 0.1067 × 10⁻⁸ T
= 1.067 × 10⁻⁹ T
= 1.067 nT
≅ 1.07 nT
The boy a projects a ball downwards with velocity v ,where it reaches the boy b after 0.5 s . So the ball the reaches the ground after time ...... from the moment of projection (g=10 m/s2)
Answer:
the answer i
Explanation:
The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.10 106 J of work on the car. The car starts from rest at sea level and has a speed of 24.0 m/s at an altitude of 2.20 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.
We know, Work done by all the forces is equal to change in potential energy :
[tex]W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}[/tex]
Here,
[tex]h_i=0\ m\\\\v_i = 0\ m/s[/tex]
Putting all given values, we get :
[tex]W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J[/tex]
Hence, this is the required solution.
A murder victim is found slumped over his desk in his office. The bullet that killed him is found lodged in his chair. Investigators find footprints in the carpet and gather traces of silica used to make concrete from the footprints. Their prime suspect is a construction supervisor who recently had an argument with the victim. The suspect's construction firm regularly uses a brand of concrete with high concentrations of silica. On the victim's desk is a threatening letter from the suspect regarding a disagreement between them. The suspect's fingerprints are found on the letter. Which of these pieces of evidence is showing a class characteristic?
A. The fingerprints on the letter belonging to the suspect
B. The silica in the carpet being like the concrete that the suspect's company uses
C. The victim being killed with his own gun
D. The suspect being angry enough with the victim to threaten him
When riding on a bus, you can tell you are moving by
observing the motion of objects like other moving vehicles
outside the window.
True or False?
Answer:
True
Explanation:
Calculate the gravitational force between a 4.0 x 10^8 kg mass and a 2.8 x 10^5 kg mass separated by a distance of 1.0 x 10^4 m.
Answer:
[tex]F_{g}=7.4704\times10^{-5}[/tex]
Explanation:
Givens: d = 1.0 × [tex]10^{4}[/tex] [tex]m_{1} = 4.0 x 10^{8}[/tex] [tex]m_{2} = 2.8[/tex]×[tex]10^{5}[/tex]
Required: [tex]F_{g}=?[/tex]
Formula: [tex]F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}[/tex] (6.67x10^-11 is the gravitational constant)
[tex]F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}[/tex]
[tex]F_{g}=7.4704\times10^{-5}[/tex]
Using the matrices below, determine if the product of AB is defined. If defined, state its dimensions.
a.
not defined
c.
defined, 4 x 2
b.
defined, 2 x 4
d.
defined 3 x 4
Please select the best answer from the choices provided
The answer is, D. defined 3 x 4
Explanation:
But the only problem is, product A is not 3 x 4.
Product A is 2 x 3, so to make this a clear answer: Product B is D. defined 3 x 4 and Product A is A. not defined or alternate answer 2 x 3
Please answer ASAP!!
Which of the following is the best reason to read the laboratory procedure before beginning
any type of experiment?
O So you can perform the experiment quickly.
O So you can ask questions about steps you do not understand.
O So you can answer all the questions at the end of the lab.
O So you can decide when is the best time of day to complete the lab.
Answer:
O So you can ask questions about steps you do not understand.
Explanation:
One of the reasons why it is encouraged that the laboratory procedure must be read at the beginning of any type of experiment is familiarize the student with the experimental procedure. Also, questions that can help make the smooth running of the experiment to proceed can be cleared.
It is to this regard that understanding laboratory procedures is very vital. Students must grasp the details of each steps of the experiment before proceeding with their investigation. Other critical information needed to set up the experiment can also be brought into the lime light.How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?
Answer:
The car will travel 541.67 m
Explanation:
Uniform Acceleration
When an object changes its velocity at the same rate, the acceleration is constant.
The relation between the initial and final speeds is:
[tex]v_f=v_o+a.t[/tex]
Where:
vf = Final speed
vo = Initial speed
a = Constant acceleration
t = Elapsed time
The acceleration can be computed by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
And the distance traveled is calculated as follows:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]
The car travels during a time of t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.
Converting the speeds to m/s:
vo=50 Km/h * 1000/3600 = 13.89 m/s
vf=80 Km/h * 1000/3600 = 22.22 m/s
Both numbers are shown with a 2-decimal precision but they will be used with higher accuracy in further calculations.
Calculating the acceleration:
[tex]\displaystyle a=\frac{22.22-13.89}{30}[/tex]
[tex]a = 0.28\ m/s^2[/tex]
Now for the distance:
[tex]\displaystyle x=13.89*30+\frac{0.28.30^2}{2}[/tex]
[tex]x=416.67\ m+125\ m[/tex]
x = 541.67 m
The car will travel 541.67 m
A long-jumper leaves the ground at an angle of 20.0° above the horizontal and at a speed of 11.0 m/s.How far does he jump in the horizontal direction?(Assume his motion is equivalent to that of a particle.).
a. 12m
b. 7.94m
c. 10m
d. 0.384m
Answer:
The correct option is;
b. 7.94 m
Explanation:
The given parameters of the jump of the long jumper are;
The angle above the horizontal with which the long jumper leaves the ground, θ = 20.0°
The speed with which the long jumper leaves the ground, u = 11.0 m/s
The furthest horizontal distance the long jumper jumps, given that the motion is equivalent to that of a particle, is given by the formula for the range, R, of a projectile motion as follows;
[tex]R = \dfrac{u^2 \times sin \left (2 \cdot \theta \right )}{g}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
u = The initial velocity of the long-jumper = 11.0 m/s
θ = The angle of the direction above the horizontal the long-jumper jumps = 20.0°
Plugging in the values, gives;
[tex]R = \dfrac{(11.0 \ m/s)^2 \times sin \left (2 \times 20.0 ^{\circ} \right )}{9.8} = \dfrac{121 \ m^2/s^2 \times sin \left (40.0 ^{\circ} \right )}{9.8 \ m/s^2} \approx 7.94 \ m[/tex]
How far the long-jumper goes = The range, R, of the projectile motion ≈ 7.94 m.
I’m bored please end my boredom
Answer:
Watch something educational
Explanation:
Like Anime
There are several things you can do to end your boredom time like you can watch movies, you can read books, or can go trekking or something.
What is boredom?According to conventional definitions, boredom is a sentimental and sporadically psychological state that occurs when someone is left without something specific to do when they feel listless and dissatisfied due to a lack of activity or excitement, when they are uninterested in one’s surroundings, or when they think a day or period is tedious.
Scholars also view it as a contemporary phenomenon with a cultural component. There is no agreed-upon definition of boredom.
There are several ways to tackle with boredom:
Call your best friend.Make a dish for yourselfTry out a new hobby.You can join a new clubExercise according to your preferred routine, or start something different, like a dance class.To know more about boredom:
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#SPJ2
Think about a typical school day. In the space provided below, describe how each of the different forms of energy we have learned about (chemical, electrical, heat, kinetic, potential, and solar) are used during a typical school day and how each form of energy is transformed into another.
Answer:
During a typical school day all forms of eneergy is being utilised and also transfer of energy takes place from one form to another.
Explanation:
Chemical energy- A bunsen burner burning a beaker filled with water.
Heat energy- The water in the beaker absorbing the heat from the burner.
Electrical energy- Running Fans and lights in a classroom by switches.
Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.
Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.
Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy
Answer:
Explanation:
Chemical energy- A bunsen burner burning a beaker filled with water.
Heat energy- The water in the beaker absorbing the heat from the burner.
Electrical energy- Running Fans and lights in a classroom by switches.
Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.
Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.
Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy
