if you had the same amount of ammonium nitrate and water, what would happen to the temperature?

Answer with Explanation:

To determine the amount of water needed to dilute a 2.5 M KCl solution to a 1.0 M solution, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, we know that:

M1 = 2.5 M

V1 = 550 mL

M2 = 1.0 M

We want to find V2, the final volume of the solution, which will be greater than 550 mL due to the addition of water.

Using the dilution formula, we can solve for V2:

M1V1 = M2V2

2.5 M x 550 mL = 1.0 M x V2

V2 = (2.5 M x 550 mL) / 1.0 M

V2 = 1375 mL

Therefore, we would need to add 1375 mL - 550 mL = 825 mL of water to 550 mL of a 2.5 M KCl solution to make a 1.0 M solution.

The three common states of matter are solid, liquid and gas. The intermolecular forces present between the particles in each state will be different. It is in gaseous state H₂O particles are fathers apart.

The gaseous state is the state of matter in which the intermolecular force of attraction is low than the liquid. The particles have a larger distance between the particles. The gaseous state of water is known as water vapor.

In gaseous state, the molecules have high kinetic energy and small intermolecular forces. Here the molecules can move randomly and the gas particles are highly compressible. They have lower density than solids and liquids.

The gaseous particles possess the property called diffusion. They have high volume and expand in the container they are placed. Here the particles move at higher speeds in all directions and hit each other.

Thus in gaseous form water has more freedom.

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The chart with characteristics of mineral resources has been attached below.

Luster, also spelled as "lustre", is the visual appearance of a mineral surface when it reflects light. It is a physical property that describes how shiny or dull the surface of a mineral appears. Luster is determined by the way in which light is reflected from the surface of the mineral, and can be described as metallic (like the shine of a metal), vitreous (like the shine of glass), pearly (like the shine of pearls), greasy, dull, or earthy. The luster of a mineral can provide clues about its identity, as different minerals have characteristic lusters that can help distinguish them from one another.

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Volume (in ml) of a 15. 0 m of stock solution is required to prepare 250. 0 ml of a 2. 35 m of solution is 39.17ml.

We may get the following solution to the above issue by using the A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, as well as several imperial or US-standard units. Volume and the notion of length are connected.

connection of molarity and volume.

[tex]M_1V_1 = M_2V_2[/tex],

where [tex]M_1[/tex] and [tex]M_2[/tex] are the molar concentrations and [tex]V_1[/tex] and [tex]V_2[/tex] are the volumes of the solutions.

The conversion from 15.0M (L of stock solution) to 2.35M (0.25L) took place.

[tex]V_2[/tex] =[tex]\frac{(2.35\times0.25)}{15}[/tex] L of stock solution

Hence, 39.17 ml or 0.0392 L of stock solution are required.

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The compound contains approximately 0.1486.02210^23 carbon atoms, or about 8.9*10^22 carbon atoms. Thus, the number of carbon atoms in the compound is approximately 15.

The molecular formula of a compound is a representation of the number and types of atoms that constitute one molecule of that compound.

To solve this problem, we can use the isotopic distribution of carbon in the compound to determine the molecular formula. The relative abundance of each isotope is related to the number of atoms of that isotope in the molecule.

Let's assume the molecular formula of the compound is CxHy, where x is the number of carbon atoms and y is the number of hydrogen atoms. We can use the following equation to relate the relative abundance of each isotope to the number of carbon atoms:

(0.9893)x(0.4475) + (0.0107)x(0.02904) = 0.02904

Simplifying this equation, we get:

0.443x + 0.00031268x = 0.02904

0.44331268x = 0.02904

x = 0.06556/0.44331268

x = 0.148

Therefore, the compound contains approximately 0.1486.02210^23 carbon atoms, or about 8.9*10^22 carbon atoms. Thus, the number of carbon atoms in the compound is approximately 15.

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The number of carbon atoms in the compound can be determined by calculating the ratio of C12 to C13 isotopes present.

Carbon atoms are the building blocks of life. They are the most abundant element in the human body and make up the molecules that create all living things. Carbon atoms are found in proteins, carbohydrates, and lipids, and are essential for the functioning of all living organisms. Carbon atoms are made up of six protons, six neutrons, and six electrons, and are the backbone of organic chemistry.

Since the relative abundances of C12 and C13 are 44.75% and 2.904% respectively, the ratio of C12 to C13 can be calculated as follows:

C12/C13 = (44.75/2.904) = 15.39

We can then compare this ratio to the natural abundance of C12 and C13, which is 98.93% and 1.07%, respectively.

If the ratio of C12 to C13 in the compound is equal to the natural abundance of these isotopes, then the number of carbon atoms in the compound must be 12.

C12/C13 = (98.93/1.07) = 92.52

Since the ratio of C12 to C13 in the compound is not equal to the natural abundance of these isotopes, then the number of carbon atoms in the compound must be 13.

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The mass (in grams) of aluminum chloride that has the same number of aluminum atoms as 3.19 g of aluminum oxide is 8.36 g

First, we shall determine the mass of aluminum, Al present in 3.19 g of aluminum oxide, Al₂O₃. Details below:

102 g of Al₂O₃ contains 54 g of Al

Therefore,

3.19 g of Al₂O₃ will contain = (3.19 × 54) / 102 = 1.69 g of Al

Next, we shall determine the number of atoms in 1.69 g of Al. Details below:

From Avogadro's hypothesis,

1 mole of Al = 6.02×10²³ atoms

But

1 mole of Al = 27 g

Thus,

27 g of Al = 6.02×10²³ atoms

Therefore,

1.69 g of Al = (1.69 × 6.02×10²³) / 27

1.69 g of Al = 3.772×10²² atoms

Finally, we shall determine the mass of aluminum chloride, AlCl₃. Details below:

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of AlCl₃

But

1 mole of AlCl₃ = 133.5 g

Thus,

6.02×10²³ atoms = 133.5 g of AlCl₃

Therefore,

3.772×10²² atoms = (3.772×10²² × 133.5) / 6.02×10²³

3.772×10²² atoms = 8.36 g

Thus, the mass of aluminum chloride, AlCl₃, is 8.36 g

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10.7 x 1024 atoms of lithium reacts with nickel (II) bromide to produce 1.04 x 10-1 g of nickel.

Lithium is a chemical element with symbol Li and atomic number 3. It is a soft, silvery-white alkali metal and is the lightest of all metals. It is the least dense solid element and is the only alkali metal that does not react with air at room temperature. Lithium is highly reactive and flammable, and is used in many applications such as batteries, lubricants, pharmaceuticals, glass, ceramics, and nuclear weapons. It is used in the treatment of bipolar disorder, and its compounds are used in specialized glass and ceramics.

The mass of nickel produced in the reaction can be determined by using the atomic mass of each element. The atomic mass of lithium is 6.94 g/mol and the atomic mass of nickel is 58.69 g/mol. Using Avogadro's number, which is 6.022 x 1023 atoms/mol, we can calculate the mass of nickel produced in the reaction.

10.7 x 1024 atoms of lithium = 10.7 x 1024 / 6.022 x 1023 moles of lithium = 1.78 x 10-1 moles of lithium

1.78 x 10-1 moles of lithium x 58.69 g/mol of nickel = 1.04 x 10-1 g of nickel

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It is accurate what is said about membranes below: an enzyme-mediated mechanism is mostly responsible for lateral diffusion.

A substance can be either hydrophobic or hydrophilic. Given that the word "hydr" is derived from the Greek word "hydor," which means "water," hydrophobic materials are "water-fearing" and do not blend with water, whereas hydrodynamic materials are "water-loving" and have a propensity to become wetted by water.

Non-polar substances with a low affinity for water are referred to as hydrophobic substances and are water-repellent. As opposed to a hydrophobic interaction, which is indicated by a contact angle larger than 90°, a hydrophilic interaction is indicated by a contact angle less than 90°.

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Answer:

≈16.67 grams

Explanation:

To solve this problem, we need to use the atomic mass of titanium to convert the number of atoms to grams. The atomic mass of titanium is 47.867 g/mol, which means that one mole of titanium atoms has a mass of 47.867 grams.

We are given the number of atoms of titanium, which is 2.1 x 10^23. We can use Avogadro's number to convert this to the number of moles of titanium:

2.1 x 10^23 atoms / (6.022 x 10^23 atoms/mol) = 0.349 moles

Now we can use the molar mass of titanium to convert moles to grams:

0.349 moles x 47.867 g/mol = 16.67 grams

Therefore, 2.1 x 10^23 atoms of titanium have a mass of approximately 16.67 grams.

8.5 g is the mass of something like the ammonia (in g) 3.01 x 1023 sodium atoms.

The most common alkali metal & sixth most abundant element on the world, sodium compensates 2.8 percent of a crust of the Earth. As opposed to sodium alone, sodium salts are much more beneficial. The most often used sodium component in common salt is sodium chloride. In the winter, it is used to de-ice roads and flavour food.

Ammonia produced from industry is used as fertiliser in agriculture to the tune of 80%.Ammonia is also used to create polymers, explosives, textiles, pesticides, dyes, and other compounds in addition to its various applications. Moreover, it is utilised to clean water sources.

No. of molecules of the Ammonia =3.01×10

23

Molar Mass of the Ammonia =17g/mole.

Using the Formula,

No. of Molecules =Mass/Molar Mass×Avogadro

s Number.

⇒3.01×10

23

=Mass/17×6.022×10

23

Mass=

2

17

∴Mass=8.5 g.

Hence, the Mass of the Ammonia is 8.5 g.

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A Class A burette is a type of laboratory glassware used for precise volumetric measurements of liquids.

This burette is a graded glass tube with a glass tip at one end. It is utilized to dispense liquids in predetermined quantities. Most experiments requiring titration use a burette.

It is typically made of borosilicate glass and has a long, narrow, cylindrical shape with a stopcock at the bottom for dispensing the liquid. The burette is usually graduated in milliliters (mL) with the smallest graduation being 0.1 mL.

Class A burettes are manufactured and tested according to strict standards set by organizations such as the National Institute of Standards and Technology (NIST) in the United States, and the International Organization for Standardization (ISO) globally.

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According to Le Chatelier's Principle,  a system that is in equilibrium will adapt to partially offset the effects of fluctuations.

According to Le Chatelier's Principle,  a system that is in equilibrium will adapt to partially offset the effects of fluctuations in temperature, volume, concentration, as well as pressure, leading to a new equilibrium.

In the equation for equilibrium,  4HCl(gas) + O₂(gas) → 2Cl₂(gas) + 2H₂O(gas) + energy. If the system's pressure rises, the equilibrium will move to the right. If the system's pressure drops, the equilibrium will move to the left. Oxygen concentration will drop, and equilibrium will move to the left. If the system's temperature rises, equilibrium will move to the right.

Therefore, according to Le Chatelier's Principle,  a system that is in equilibrium will adapt to partially offset the effects of fluctuations.

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Carbon monoxide ( CO ) is toxic because binds more strongly to the iron in the hemoglobin ( Hb ) than  oxygen ( O₂ ). The equilibrium constant K at 298 K is 56.59.

The chemical equation is as :

Hb   +   O₂     ⟶  HbO₂     ΔG∘ 1 = +70 kJ/mol

Hb   +   CO  ⟶  HbCO      ΔG∘ 2 = −80 kJ/mol

HbO₂  + CO  ---> HbCO  +  O₂      ΔG∘ 3 = ?

ΔG∘ 3 = (+ 70 - 80  ) kJ/mol

ΔG∘ 3 = - 10 kJ/mol

ΔG∘ 3 = - RT ln K

ΔG∘ = standard Gibbs free energy  = -10kJ/mol = -10000 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 298 K

k = equilibrium constant  = ?

- 10000 J/mol = - (8.314 J/kmol ) × 298 × ln eq

K = 56.59

Thus, the equilibrium constant Ka is  56.59.

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This question is incomplete, the complete question is :

Carbon monoxide (CO) is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does oxygen (O2), as indicated by these approximate standard free-energy changes in blood:

reaction A:reaction B:Hb+O2Hb+CO⟶⟶HbO2,HbCO, ΔG∘=−70 kJ/mol ΔG∘=−80 kJ/mol

Estimate the equilibrium constant K at 298 K for the equilibrium

HbO2  + CO⇌HbCO+O2

142.20 is the boiling point of a solution made of 75.4g of urea (CH,N₂O) dissolved in 800. g of X.

Boiling point is the temperature at which a liquid boils and turns into a vapor. At the boiling point, the vapor pressure of the liquid is equal to the atmospheric pressure. The boiling point of a liquid is usually higher than its melting point, and the two points have different values for different substances.

The boiling point elevation of the solution can be calculated using the following equation:

ΔT = K*m

where K is the boiling point elevation constant and m is the molality of the solution.

To calculate the molality of the solution, we first need to calculate the moles of urea present in 75.4g.

75.4g of urea has a molar mass of 60.06 g/mol, so 75.4g of urea contains 1.25 moles.

Now, we can calculate the molality of the solution.

800 g of liquid X weighs 800 g/mol, so 800 g of liquid X contains 800 moles.

Therefore, the molality of the solution is 1.25 moles/800 moles, or 0.00156 moles/mol.

Now, we can calculate the boiling point elevation of the solution:

ΔT = K*m

ΔT = -2.43°C-kg-mol * 0.00156 moles/mol

ΔT = -0.038 °C

Therefore, the boiling point of the solution is 142.20.

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The statement is true that a molecule is composed of several functional groups.

A molecule is a group of two or more atoms held together by chemical bonds. Atoms can form chemical bonds by sharing electrons with other atoms, leading to the formation of stable molecules with unique chemical and physical properties. Molecules can be made up of atoms of the same element or different elements, and they can vary widely in size and complexity. In biology, many important molecules are made up of carbon, hydrogen, oxygen, nitrogen, and other elements, and they play critical roles in biological processes such as metabolism, cellular signaling, and genetic information storage and transmission. Examples of important biological molecules include DNA, RNA, proteins, carbohydrates, lipids, and many others. These molecules are responsible for carrying out the various functions of cells and organisms and are critical for life as we know it.

Here,

Many molecules in biology are composed of several functional groups, which are specific atoms or groups of atoms within the molecule that give it its chemical properties and reactivity. Examples of common functional groups in biological molecules include amino (-NH2), carboxyl (-COOH), hydroxyl (-OH), phosphate (-PO4), and methyl (-CH3) groups, among others. The presence of these functional groups can determine how a molecule interacts with other molecules in the cell and can influence its function and activity.

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Henry’s law states that the amount of a gas that dissolves in a solution is proportional to the pressure of the gas.

Henry's law is a gas law that states that the amount of a given gas that will dissolve in a given type and volume of liquid is directly proportional to the partial pressure of that gas above the liquid. The law was named after chemist William Henry, who first proposed it in 1803. Henry's law is expressed mathematically as: P = kH x c, where P is the partial pressure of the gas, kH is the Henry's law constant, and c is the concentration of the gas in the liquid. This law is applicable to gases that are relatively insoluble in liquids, such as nitrogen, oxygen, and carbon dioxide.

As the diver ascends to the surface, the pressure on the nitrogen gas decreases rapidly which results in an increased amount of gas being released from the solution. This release of nitrogen gas forms bubbles in the diver’s bloodstream, leading to decompression sickness.

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The production of the ester CH3COOCH2CH3 typically involves the reaction between acetic acid (CH3COOH) and ethanol (CH3CH2OH) in the presence of a catalyst, typically sulfuric acid (H2SO4) or a strong acid ion exchange resin. The reaction can be represented, by the help of following equation:

CH3COOH + CH3CH2OH → CH3COOCH2CH3 + H2O

In this reaction, the -OH group from the carboxylic acid (acetic acid) and the -OH group from the alcohol (ethanol) combine to form a molecule of water (H2O) while the remaining groups (CH3COO and CH3CH2) combine to form the ester CH3COOCH2CH3.

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Answer:

if u are talking Abt H2O then the shape is vent shaped and angle between both oxygen atoms is 104.5°

Explanation:

I hope the image helps

5.20 mol of calcium carbide (CaC2) will produce 2.60 moles of acetylene (C2H2).

Acetylene (C2H2) is a colorless, flammable gas primarily composed of two carbon atoms and two hydrogen atoms. It is one of the simplest and most useful of all the organic compounds. Acetylene is used in a variety of industrial applications, from welding and cutting metals to producing polyethylene plastics. Acetylene is also used as an industrial fuel and a chemical feedstock for many other compounds. As a fuel, acetylene is used for heating, lighting, and powering engines, as well as in torches for welding and cutting metals.

Based on the chemical equation for the reaction, calcium carbide (CaC2) reacts with water (H2O) to produce acetylene (C2H2) and calcium hydroxide (Ca(OH)2).

CaC2 + 2H2O → C2H2 + Ca(OH)2

Since 5.20 mol of CaC2 is given and water is in excess, we can assume that the amount of water is enough to completely react with the calcium carbide.

Using the mole ratio of the equation, we can calculate the amount of acetylene produced. Since 1 mole of CaC2 reacts with 2 moles of H2O to produce 1 mole of C2H2, 5.20 moles of CaC2 will produce 2.60 moles of C2H2.

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Answer:

The balanced chemical equation for the reaction between H3AsO4 and NaOH is:

H3AsO4 + 3NaOH -> Na3AsO4 + 3H2O

The stoichiometry of the reaction shows that one mole of H3AsO4 reacts with three moles of NaOH. Therefore, to determine the volume of NaOH required to reach the half-equivalence and equivalence points, we need to calculate the number of moles of H3AsO4 in the solution.

Assuming a 1 L solution of H3AsO4, the number of moles of H3AsO4 is given by:

n(H3AsO4) = mass(H3AsO4) / molar mass(H3AsO4)

where the mass of H3AsO4 is not provided, so we cannot calculate it directly. However, we can use the information about the pKa values of H3AsO4 to estimate the number of moles of H3AsO4 at the half-equivalence and equivalence points.

At the half-equivalence point, [H3AsO4] = [H2AsO4-]. Therefore, we can assume that half of the H3AsO4 has been converted to H2AsO4-. At this point, the pKa1 of H3AsO4 is used up, and the pKa2 becomes relevant. The pKa2 of H3AsO4 is 6, which means that the pH of the solution will be close to 6. At this pH, approximately half of the H2AsO4- will be deprotonated to form HAsO42-. Therefore, we can assume that the number of moles of H3AsO4 at the half-equivalence point is equal to the number of moles of H2AsO4-.

At the equivalence point, all the H3AsO4 has been neutralized by NaOH, and the solution contains only Na3AsO4 and water.

To calculate the volume of NaOH required to reach each point, we need to use the molarity of the NaOH solution. The molarity of the 12 M NaOH solution is:

M(NaOH) = moles(NaOH) / volume(NaOH in liters)

where the moles of NaOH are equal to the moles of H3AsO4 at the half-equivalence or equivalence point, and the volume of NaOH is what we need to calculate.

At the half-equivalence point:

Moles of H3AsO4 = Moles of H2AsO4-

Moles of H2AsO4- = Moles of H3AsO4 / 2

Moles of NaOH = 3 x Moles of H3AsO4

Molarity of NaOH = 12 M

Volume of NaOH = Moles of NaOH / Molarity of NaOH

Substituting the values, we get:

Moles of H3AsO4 = 0.5 x mass(H3AsO4) / molar mass(H3AsO4)

Moles of H2AsO4- = 0.25 x mass(H3AsO4) / molar mass(H3AsO4)

Moles of NaOH = 1.5 x mass(H3AsO4) / molar mass(H3AsO4)

Molarity of NaOH = 12 M

Volume of NaOH = 1.5 x mass(H3AsO4) / (12 M x molar mass(H3AsO4))

Similarly, at the equivalence point, all the H3AsO4 has been neutralized, so the number of moles of NaOH is equal to the number of moles of H3AsO4 in the solution. Thus, we can use the same formula as for the half-equivalence point, but with the moles of NaOH equal to the moles of H3AsO4 at the equivalence point.

In summary, to calculate the volume of NaOH required to reach the half-equivalence and equivalence points, we can use the following formulas:

Volume of NaOH at the half-equivalence point = 1.5 x mass(H3AsO4) / (12 M x molar mass(H3AsO4))

Volume of NaOH at the equivalence point = mass(H3AsO4) / (12 M x molar mass(H3AsO4))

These formulas will give the volume of NaOH in milliliters (mL) required to reach each point. Note that the mass of H3AsO4 is not provided, so we cannot calculate the actual volume required, but we can use these formulas to estimate the relative volumes at each point.

As the wind slows, silt is deposited because the wind has less energy.

Deposition in rivers and streams. A stream or river begins to deposit silt when it begins to slow down. In steep terrain, larger sediments fall, but smaller sediments can still be carried. As the slope gets less steep, smaller sediments are dropped.

Sediment that has been eroded is deposited in a new location when the speed of the wind or water slows. Fertile land is produced as a result of the sedimentation process.

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In comparison to cyclohexane, those following will be much more soluble in water.

The majority of cyclohexane is used to make thermoplastic intermediates and other typical uses for nylon, including garments, tents, and carpets. In recent years, benzene has been replaced by cyclohexane in many applications and is still utilized as a solvent in industrial and chemical operations.

Consuming cyclohexane could upset your stomach. At cyclohexane concentrations typically present in the environment, these effects are unlikely to manifest. The skin may become irritated if cyclohexane is spilled on it. Skin dryness and cracking may result from prolonged or repetitive skin contact.

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Answer:

✿´`·.·´`✿What are the 7 steps in a scientific method and its definition?

Image result for Match each scientific method term to its definition.

The six steps of the scientific method include: 1) asking a question about something you observe, 2) doing background research to learn what is already known about the topic, 3) constructing a hypothesis, 4) experimenting to test the hypothesis, 5) analyzing the data from the experiment and drawing conclusions, and 6)

Answer:

2.94 g/cm3

Explanation:

To find the bulk density of the rock, we need to consider the weighted average of the densities of each mineral component, taking into account their respective proportions:

Bulk density = (0.3 x 2.65 g/cm3) + (0.25 x 3.50 g/cm3) + (0.35 x 2.70 g/cm3) + (0.1 x 3.28 g/cm3)

Bulk density = 0.795 + 0.875 + 0.945 + 0.328

Bulk density = 2.943 g/cm3

Therefore, the bulk density of the rock is 2.94 g/cm3 (rounded to two decimal places).

Answer:

The energy value of the vegetable oil is 12.8 kcal/g.

Explanation:

We can use the following formula to calculate the energy value of the vegetable oil:

Energy value = energy released / mass of sample

We are given that the mass of the sample is 0.35 g and the energy released is 17.9 kJ. We need to convert the energy to calories and the mass to grams to get the answer in kcal/g.

1 kJ = 1000 J

1 cal = 4.184 J

So,

17.9 kJ = 17.9 x 1000 J = 17900 J

17900 J = 17900 / 4.184 cal = 4274.5 cal

Now we can calculate the energy value:

Energy value = 4274.5 cal / 0.35 g = 12212.9 cal/g

Finally, we can convert the answer to kcal/g by dividing by 1000:

Energy value = 12212.9 cal/g / 1000 = 12.8 kcal/g (rounded to one decimal place)

Keeping the car well tuned with regular servicing helps to reduce the emission of oxides of nitrogen gas to the atmosphere. Hence, option B is correct.

NOₓ is a representation of oxides of nitrogen gas. Nitrogen gas reacts with atmospheric oxygen produces NO, NO₂ etc. all are causing atmospheric  pollution and other serious issues such as acid rain, global warming, ozone layer depletion etc.

Thus, it is very important to reduce the emission of oxides of nitrogen. Vehicles and industries are the main sources of NOₓ emission. Evolving these gas directly to air caused serious consequences.

Keeping the vehicles maintained regularly with ensuring that no gas leakage or over expulsion is there. Hence, option C is helpful to reduce the emission of this gas.

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If 5.00cm³ of 0.20mol/L Na[tex]_2[/tex]CO[tex]_3[/tex] was diluted with distilled water to obtain 250cm³ solution. 0.64 mol/L is the concentration of the resulting solution.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute in the solution to the solvent or whole solution is another way to define concentration.

In order to indicate concentration, mass every unit volume is typically used. The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.

Concentration₁×volume₁=concentration₂×volume₂

0.20×5.00=concentration₂×250

concentration₂= 0.64 mol/L

Therefore, 0.64 mol/L is the concentration of the resulting solution.

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The 125 moles of NaCl or sodium chloride solution in 4 l solution will have molarity 31.25 M.

The molarity of any solution is given by the formula - Molarity = number of moles ÷ volume of solution in litres.

In this question, we have the required values which are number of moles and volume of solution in litre. Therefore, keeping the values in formula to find the molarity of solution.

Molarity = 125/4

Now perform the division of values stated on Right Hand Side of the above mentioned equation

Molarity = 31.25 M

Thus, the molarity of solution is 31.25 M.

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Answer:

3.613*10^24 atoms

Explanation:

The starting mixture contained approximately 23.62% SiO2.

Silicon dioxide (SiO2) has many important uses in various fields:

Glassmaking: SiO2 is a primary component of most types of glass. It is added to glass to improve its hardness, clarity, and resistance to heat and chemicals.

Ceramics: SiO2 is used in the production of ceramics and pottery as it gives the material added strength and durability.

Electronics: SiO2 is used as a dielectric material in electronic devices like transistors, integrated circuits, and microchips. It is an important component of the insulation layers that protect the electrical components and prevent them from overheating.

Construction: SiO2 is used as an important component in construction materials like concrete, bricks, and roofing tiles. Its hardness and durability make it ideal for building materials.

Cosmetics: SiO2 is used in many cosmetic products like face powders, sunscreens, and lotions. It is used as an absorbent or bulking agent that helps to give products a silky texture.

To determine the percentage of SiO2 in the starting mixture, we need to calculate the total mass of the starting mixture and the mass of SiO2 in it.

The total mass of the starting mixture is the sum of the masses of NaCl, SiO2, and CaCO3:

total mass = 1.3012 g + 0.5410 g + 0.4503 g = 2.2925 g

The mass of SiO2 in the starting mixture is given as 0.5410 g.

To calculate the percentage of SiO2 in the starting mixture, we divide the mass of SiO2 by the total mass of the mixture and multiply by 100:

% SiO2 = (mass of SiO2 / total mass) x 100

% SiO2 = (0.5410 g / 2.2925 g) x 100

% SiO2 = 23.62%

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