Imagine Scott stood at zero on a life-sized number line. His friend flipped a coin 6 times. When the coin
came up heads, he moved one unit to the right. When the coin came up tails, he moved one unit to the left.
After each flip of the coin, Scott's friend recorded his position on the number line. Let f(n) represent Scott's
position on the number line after the nth coin flip.
a. How many different outcomes are there for the sequence of 6 coin tosses?
b. Calculate the probability, before the coin flips have begun, that f(6) = 0, f(6)= 1, and f(6) = 6.
c. Make a bar graph showing the frequency of the different outcomes for this random walk.
d. Which number is Scott most likely to land on after the six coin flips? Why?

Answer:

Step-by-step explanation:

You want the price per ounce and the best deal, given 6-, 10-, and 16-ounce bricks cost $3.59, $4.79, and $7.89.

The unit price is found by dividing the price by the number of units. Here, our unit is 1 ounce, so we divide each price by the number of ounces to find the price per ounce. The calculator display attached shows the result to 4 decimal places. Here, we round to 2 dp.

The lowest price per ounce is obtained with the 10 oz brick.

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Time taken to reach the population size to reach 37,500 is 195 minutes.

Given that, a bacterial culture initially starts with 2,500 bacteria.

The population size of the bacterial culture doubles every 15 minutes, so in x minutes, the population size should double x/15 times. We can write this as an equation:

2,500 × 2^(x/15) = 37,500

[tex]2500\times2^\frac{x}{15} =37500[/tex]

Now, we can take the logarithm of both sides to solve for x:

[tex]log_22500\times2^\frac{x}{15} =log_237500[/tex]

x/15 = 13

So x = 195 minutes.

Therefore, time taken to reach the population size to reach 37,500 is 195 minutes.

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Rounding up to the nearest whole number, you would need to survey approximately 753 randomly selected air passengers to be 90% confident that the sample percentage is within 3.5 percentage points of the true population percentage.

To determine the sample size needed for estimating a population percentage with a specified margin of error and confidence level, we can use the formula for sample size calculation for proportions. The formula is:

n = (Z^2 * p * (1-p)) / E^2

Where:

n is the required sample size,

Z is the Z-score corresponding to the desired confidence level (for a 90% confidence level, Z ≈ 1.645),

p is the estimated population proportion (since we don't have an estimate, we can use 0.5 for maximum sample size),

E is the desired margin of error (in decimal form).

In this case, the desired margin of error is 3.5 percentage points, which is 0.035 in decimal form.

Plugging in the values, we have:

n = (1.645^2 * 0.5 * (1-0.5)) / 0.035^2

Calculating this expression gives us:

n ≈ 752.93

Rounding up to the nearest whole number, you would need to survey approximately 753 randomly selected air passengers to be 90% confident that the sample percentage is within 3.5 percentage points of the true population percentage.

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Answer:

cube A

Step-by-step explanation:

Cube a has the larger coulme because

0.6x0.6x06=0.216

Answer:

700

Step-by-step explanation:

4(175)=700

To prove that H(n) = n!(1/1! + 1/2! + 1/3! + ... + 1/n!) for all n ≥ 1 using induction, we need to follow the steps you've outlined.

Base Case:

For n = 1, we have H(1) = 1·H(0) + 1. Plugging in H(0) = 0 and simplifying, we get H(1) = 1·0 + 1 = 1. On the other hand, f(1) = 1!(1/1!) = 1(1) = 1. The base case holds true.

Inductive Hypothesis:

Assume that for some k > 1, H(k-1) = (1/1! + 1/2! + 1/3! + ... + 1/(k-1)!). This is our inductive hypothesis.

Inductive Step:

Using the recurrence relation, we have H(k) = k·H(k-1) + 1. Plugging in our inductive hypothesis, we get:

H(k) = k(1/1! + 1/2! + 1/3! + ... + 1/(k-1)!) + 1.

To simplify further, we can write k as k!/k!:

H(k) = k!/k! (1/1! + 1/2! + 1/3! + ... + 1/(k-1)!) + 1.

Rearranging the terms, we get:

H(k) = (1/1! + 1/2! + 1/3! + ... + 1/(k-1)!) + k!/k!.

This expression is equal to f(k), which is n!(1/1! + 1/2! + 1/3! + ... + 1/n!). Therefore, we have shown that H(k) = f(k) for the inductive step.

By induction, we have proved that H(n) = n!(1/1! + 1/2! + 1/3! + ... + 1/n!) for all n ≥ 1.

Note: It's important to clarify that H(0) should be explicitly defined as H(0) = 0 in the recurrence relation to ensure that the base case is consistent.

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The slope of the line passing through (4, 4) and (0, -2) is 1.5

An equation is an expression that shows how numbers and variables are related to each other using mathematical operations.

The slope of a straight line is the ratio of its rise to its run. It is given by:

Slope = Rise / Run

Hence, for the line shown passing through (4, 4) and (0, -2):

Slope = (-2 - 4) / (0 - 4) = 1.5

The slope of the line is 1.5

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The work required to move the object from x = 0 to x = 3 meters in the presence of a force f(x) = 2x along the x-axis is 9 joules (J).

The work done by a force in moving an object from one position to another, we need to integrate the force over the displacement.

The force is given by f(x) = 2x and the displacement is from x = 0 to x = 3.

So, the work done W can be calculated as:

W = ∫₀³ f(x) dx

W = ∫₀³ 2x dx

W = [x²]₀³

W = 3² - 0²

W = 9

We must integrate the force over the displacement to determine the work done by a force in moving an item from one location to another.

The displacement ranges from x = 0 to x = 3, and the force is provided by f(x) = 2x.

Thus, the work done W can be determined as follows:

W = sup>0/sup>sub>0/sup>3/sup> f(x) dx W = 0 and 3, respectively. W = [x2]sub>0/sub>sup>3/sup> 2x dx

W = 3² - 0²

W = 9

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Answer: 42,120

Step-by-step explanation:

Area is calculated by multiplying the length of a shape by its width-

Farzana makes 38.3 pounds of egg salad each week for her sandwich shop.

Farzana makes 5 pounds of egg salad each day from Monday to Saturday, totaling 6 days. On Sunday, she makes 8.3 pounds of egg salad. To calculate the total amount of egg salad Farzana makes in a week, we need to add up the amounts from each day.

From Monday to Saturday, she makes a total of 5 pounds * 6 days = 30 pounds of egg salad.

On Sunday, she makes 8.3 pounds of egg salad.

To find the total amount for the week, we add the amounts from Monday to Saturday to the amount from Sunday:

30 pounds + 8.3 pounds = 38.3 pounds

Therefore, Farzana makes 38.3 pounds of egg salad each week for her sandwich shop.

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To solve the given differential equation, we'll separate the variables and integrate with respect to θ and r.

Answer : (r^2 * cos(2θ))/2 - r * sin(θ) - 2r^2 = C

The differential equation is:

(2r^2 * cos(θ) * sin(θ) + r * cos(θ)) * dθ + (4r + sin(θ) - 2r * cos^2(θ)) * dr = 0

Rearranging the terms and dividing by (2r^2 * cos(θ) * sin(θ) + r * cos(θ)) on both sides, we have:

dθ/dr = - (4r + sin(θ) - 2r * cos^2(θ)) / (2r^2 * cos(θ) * sin(θ) + r * cos(θ))

Now, we'll integrate both sides with respect to θ and r separately.

∫ dθ = - ∫ (4r + sin(θ) - 2r * cos^2(θ)) / (2r^2 * cos(θ) * sin(θ) + r * cos(θ)) dr

Integrating the left side gives θ + C₁, where C₁ is the constant of integration.

To solve the integral on the right side, it requires applying suitable trigonometric identities and algebraic manipulations. The exact integration steps may be complex and involve elliptic integrals, but we can express the result in its integral form:

∫ (4r + sin(θ) - 2r * cos^2(θ)) / (2r^2 * cos(θ) * sin(θ) + r * cos(θ)) dr = C₂

Here, C₂ represents the constant of integration for the integral with respect to r.

Combining the results, we have:

θ + C₁ = C₂

Finally, rewriting the equation in terms of r and θ:

(r^2 * cos(2θ))/2 - r * sin(θ) - 2r^2 = C

Here, C represents the combined constant C₂ - C₁.

Therefore, the solution to the given differential equation is given by:

(r^2 * cos(2θ))/2 - r * sin(θ) - 2r^2 = C

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The interquartile range of a data-set is given by the difference between the third quartile and the first quartile.

The interquartile range of a data-set is given by the difference of the third quartile by the first quartile of the data-set.

The quartiles of a data-set are given as follows:

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When x = 3, ŷ equals 4,609. Therefore, the correct answer is (c) 4,609.

The question asks for the value of ŷ when x = 3, given the least squares regression equation. To find ŷ, we simply substitute x = 3 into the equation:

ŷ = 1,204 + 1,135(3)
ŷ = 1,204 + 3,405
ŷ = 4,609

Therefore, the answer is (c) 4,609.

OR

To find the value of ŷ given the least squares regression equation ŷ = 1,204 + 1,135x and x = 3, follow these steps:

1. Plug in the value of x into the equation: ŷ = 1,204 + 1,135(3)
2. Multiply the numbers: ŷ = 1,204 + 3,405
3. Add the numbers: ŷ = 4,609

So when x = 3, ŷ equals 4,609. Therefore, the correct answer is (c) 4,609.

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Answer:

1/9

(1/3)2 = (1/3) × (1/3) = 1/9

The value of y that satisfies the equation is 3.35 or - 5.35.

The value of y that satisfies the equation is calculated as follows;

The given equation;

√ (y + 3) + √ ( y - 2) = 5

Square both sides of the equations as follows;

[√ (y + 3) + √ ( y - 2) ]² = 5²

y + 3 + 2(y + 3)(y - 2) + y - 2 = 25

2y + 1   +   2(y² + y - 6) = 25

2y + 1 + 2y² + 2y - 12 = 25

Collect similar terms and simplify the equation;

2y²  +  4y - 36 = 0

divide through by 2;

y² + 2y - 18 = 0

Solve the quadratic equation using formula method as follows;

a = 1, b = 2, c = -18

y = 3.35 or - 5.35

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a) The value of S4 = -5/8 and S₅ = -19/40

b) The interval estimate for the value of the series has an error of | S₄ - L | = |-5/8 - L|, which measures how close our estimate is to the actual value of L.

Now, let's consider the convergent alternating series ∑ (n = 1 to ∞) (-1)ⁿ/n! = L. Here, n! denotes the factorial function, which means n! = n(n-1)(n-2)...321. This series has a finite sum L, which we want to estimate. To do this, we can look at the nth partial sum of the series, denoted by Sn, which is the sum of the first n terms of the series.

To compute Sn, we simply add up the first n terms of the series. For example, when n = 4, we have:

S4 = (-1)¹/¹! + (-1)²/²! + (-1)³/³! + (-1)⁴/⁴! = -1 + 1/2 - 1/6 + 1/24 = -5/8

Similarly, we can compute the (n+1)th partial sum, denoted by Sₙ₊₁, which is the sum of the first (n+1) terms of the series. For example, when n = 4, we have:

S₅ = (-1)¹/¹! + (-1)²/²! + (-1)³/³! + (-1)⁴/⁴! + (-1)⁵/⁵! = -1 + 1/2 - 1/6 + 1/24 - 1/120 = -19/40

Now, to find bounds on the sum of the series, we can use the fact that the series is alternating and convergent. In particular, we know that the sum of the series is between two consecutive partial sums, i.e.,

Sₙ ≤ L ≤ Sₙ₊₁

This means that if we want to estimate the value of L, we can simply compute Sₙ and Sₙ₊₁ and use them to find an interval that contains L. For example, when n = 4, we have:

S4 = -5/8 and S₅ = -19/40

Therefore, we have:

-19/40 ≤ L ≤ -5/8

This interval estimate for the value of the series has an error of | S₄ - L | = |-5/8 - L|, which measures how close our estimate is to the actual value of L.

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Complete Question:

Consider the convergent alternating series  ∑ (n = 1 to ∞) (-1)ⁿ/n!  = L.

Let Sn be the nth partial sum of this series. Compute Sₙ and Sₙ₊₁ and n=1 use these values to find bounds on the sum of the series.

If n = 4, then Sₙ =----- and Sₙ₊₁ = ---

This interval estimate for the value of the series has error | Sₙ - L|

The Triangle Inequality Theorem, if CE + DE > CD, then Dora is the fastest from the church. Conversely, if CD + DE > CE, then Diego is the fastest.

To determine which student is the fastest between Diego and Dora,  more information about their locations and the distances involved.

The Triangle Inequality Theorem states that in a triangle, the sum of the lengths of any two sides is always greater than or equal to the length of the remaining side.

Assuming that Diego, Dora, and the church form a triangle, compare the distances between each student and the church to determine who is the fastest.

The distances between Diego and the church, Dora and the church, and Diego and Dora are as follows:

Distance between Diego and the church: d1

Distance between Dora and the church: d2

Distance between Diego and Dora: d3

According to the Triangle Inequality Theorem, for any triangle, the sum of the lengths of any two sides is greater than or equal to the length of the remaining side.

d1 + d2 ≥ d3

d1 + d3 ≥ d2

d2 + d3 ≥ d1

The student who is closest to the church is the fastest, the inequalities to determine which student that is.

The first inequality: d1 + d2 ≥ d3. If Diego is closer to the church (d1 < d2), then we can rewrite the inequality as d1 + d2 ≥ d1 + d3, which simplifies to d2 ≥ d3. This means that if Diego is closer to the church, he would be the fastest.

If Dora is closer to the church (d2 < d1), then the inequality becomes d1 + d2 ≥ d2 + d3, simplifying to d1 ≥ d3. if Dora is closer the fastest.

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The system of linear equation that represent this problem is

6x + 10y = 900

10x + 4y = 1220

Let's represent the number of CDs Roberto bought as x and the number of magazines as y

The problem states the following information:

Using the variables;  x and y as given;

1. Roberto bought 6 CDs and 10 magazines for $900.00 pesos. This can be represented as the equation:

  6x + 10y = 900

2. María bought 10 CDs and 4 magazines for $1,220.00 pesos. This can be represented as the equation:

  10x + 4y = 1220

So, the system of equations representing the problem is:

6x + 10y = 900

10x + 4y = 1220

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Translation: Roberto bought 6 cd's and 10 magazines for $900.00 pesos; In the same store, her friend María bought 10 CDs and 4

magazines at $1,220.00 pesos. What is the system of equations with two unknowns that represents the problem?

The derivative of the function at point P₀ in the direction of A is 17√2.

What is derivative?

In calculus, the derivative represents the rate of change of a function with respect to its independent variable. It measures how a function behaves or varies as the input variable changes.

To find the derivative of the function at point P₀ in the direction of vector A, we need to calculate the directional derivative. The directional derivative is given by the dot product of the gradient of the function with the unit vector in the direction of A.

Given:

[tex]f(x, y) = 5xy + 3y^2[/tex]

P₀(-9, 1)

A = -√2i - √2j

First, let's find the gradient of the function:

∇f(x, y) = (∂f/∂x)i + (∂f/∂y)j

Taking the partial derivatives:

∂f/∂x = 5y

∂f/∂y = 5x + 6y

So, the gradient is:

∇f(x, y) = 5y i + (5x + 6y)j

Next, we need to find the unit vector in the direction of A:

[tex]|A| = \sqrt((-\sqrt2)^2 + (-\sqrt2)^2) = \sqrt(2 + 2) = 2[/tex]

u = A/|A| = (-√2i - √2j)/2 = -√2/2 i - √2/2 j

Finally, we can calculate the directional derivative:

Df(P₀, A) = ∇f(P₀) · u

Substituting the values:

Df(P₀, A) = (5(1) i + (5(-9) + 6(1))j) · (-√2/2 i - √2/2 j)

= (5i - 39j) · (-√2/2 i - √2/2 j)

= -5√2/2 - (-39√2/2)

= -5√2/2 + 39√2/2

= (39 - 5)√2/2

= 34√2/2

= 17√2

Therefore, the derivative of the function at point P₀ in the direction of A is 17√2.

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Using the given information, the volume of the rectangular prism is 6,048 cubic units.

A rectangular prism is a three-dimensional geometric shape that has six rectangular faces, each with an identical size and form.

To compute the volume of a rectangular prism, multiply the length (L), width (W), and height (H).  

In this case, we are given:

L = 18

W = 21

H = 16

Volume = L × W × H

= 18 × 21 × 16

= 6,048 cubic units

Therefore, the volume of the rectangular prism is 6,048 cubic units.

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(a) The expected value of Y is :

E(Y) = (n+1)/3

(b) The value of E(Y^2) = (2n^2+5n+1)/6

(c) The variance of Y = (2n^2+5n+1)/6 - [(n+1)/3]^2

(d) P(X+Y=2) = 1/n

a) To find the expected value of Y, we use the law of total probability:

E(Y) = ∑ P(X=k)E(Y|X=k) for k=1 to n

Since Y is uniformly distributed on {1,2,...,X}, we have E(Y|X=k) = (k+1)/2.

Therefore,

E(Y) = ∑ P(X=k)(k+1)/2 for k=1 to n

To find P(X=k), note that X can take on any value from 1 to n with equal probability, so P(X=k) = 1/n for k=1 to n. Thus,

E(Y) = ∑ (k+1)/2n for k=1 to n

E(Y) = [1/2n ∑ k] + [1/2n ∑ 1] for k=1 to n

E(Y) = [1/2n (n(n+1)/2)] + [1/2n n]

E(Y) = (n+1)/3

b) To find E(Y^2), we use the law of total probability again:

E(Y^2) = ∑ P(X=k)E(Y^2|X=k) for k=1 to n

Since Y is uniformly distributed on {1,2,...,X}, we have E(Y^2|X=k) = (k^2+3k+2)/6. Therefore,

E(Y^2) = ∑ P(X=k)(k^2+3k+2)/6 for k=1 to n

Using the same values of P(X=k) as before, we get:

E(Y^2) = ∑ (k^2+3k+2)/6n for k=1 to n

E(Y^2) = [1/6n ∑ k^2] + [1/2n ∑ k] + [1/6n ∑ 1] for k=1 to n

E(Y^2) = [1/6n (n(n+1)(2n+1)/6)] + [1/2n (n(n+1)/2)] + [1/6n n]

E(Y^2) = (2n^2+5n+1)/6

c) The variance of Y is given by Var(Y) = E(Y^2) - [E(Y)]^2. Therefore,

Var(Y) = (2n^2+5n+1)/6 - [(n+1)/3]^2

d) To find P(X+Y=2), we note that X+Y=2 if and only if X=1 and Y=1. Since X is uniformly distributed on {1,2,...,n}, we have P(X=1) = 1/n. Since Y is uniformly distributed on {1,2,...,X}, we have P(Y=1|X=1) = 1. Therefore,

P(X+Y=2) = P(X=1)P(Y=1|X=1) = 1/n

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The equation for a in terms of t, where a direct variation with t and a = 68 when t = 20, is a = 3.4t.

In a direct variation, two variables are related by a constant ratio. In this case, the variable a varies directly with t.

We can write the equation as a = kt, where k represents the constant of variation. To find the value of k, we can use the given information that a = 68 when t = 20.

Plugging these values into the equation, we have 68 = k * 20. Solving for k, we divide both sides by 20, which gives k = 68/20 = 3.4.

The equation for a in terms of t is a = 3.4t. This means that for any given value of t, we can find the corresponding value of a by multiplying t by 3.4.

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Using the formula of probability, the probability of the card either being r or s is 2/3

The probability that the card drawn at random will either be marked r or s can be calculated by dividing the total number of cards by the number of possible outcomes.

Assuming the possible outcomes are r and s;

Number of possible outcomes = 2

Total amount in the event = 3

The probability of selecting either r or s will be;

Probability = Number of favorable outcomes / Total number of possible outcomes;

p = 2/3

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Answer: To estimate the number of people who want the toll road in their city, we can use the percentage range provided and calculate the interval estimate. Here's how you can do it:

Therefore, the interval estimate for the number of people who want the toll road in their city is (123,442, 225,608).

The sampling distribution is normal if the sampled populations are normal, and approximately normal if the populations are nonnormal and the sample sizes n1 and n2 are large: (A) TRUE

The central limit theorem states that as sample sizes increase, the distribution of the sample means approaches a normal distribution regardless of the shape of the population distribution, as long as the samples are randomly selected and independent.

Therefore, if the populations from which the samples are drawn are normal, the sampling distribution of the means will also be normal.

However, even if the populations are nonnormal, the sampling distribution will still be approximately normal if the sample sizes are large enough.

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The line integral ∫e^t dx along the line Segment C is equal to 0.

(a) To evaluate the line integral ∫ds along the line segment C from (0,2) to (0,4), we can use the formula for the arc length of a curve in two dimensions.

The formula for the arc length of a curve defined by a vector-valued function r(t) = (x(t), y(t)) on an interval [a, b] is given by:

L = ∫ √(dx/dt)^2 + (dy/dt)^2 dt

In this case, since the line segment C is a straight line parallel to the y-axis, the x-coordinate remains constant at x = 0. Therefore, dx/dt = 0 for all t.

The y-coordinate varies from y = 2 to y = 4 along C, so dy/dt = 2. Integrating √(dx/dt)^2 + (dy/dt)^2 over the interval [a, b] where a and b are the parameter values corresponding to the endpoints of C, we get:

∫ds = ∫ √(dx/dt)^2 + (dy/dt)^2 dt

= ∫ √0 + 2^2 dt

= ∫ 2 dt

= 2t + C

Evaluating this integral over the interval [a, b] = [0, 1], we get:

∫ds = 2t ∣[0,1]

= 2(1) - 2(0)

= 2

Therefore, the line integral ∫ds along the line segment C is equal to 2.

(b) To evaluate the line integral ∫e^t dx along the line segment C, we can use the fact that dx = 0 since the x-coordinate remains constant at x = 0 Therefore, ∫e^t dx = ∫e^t * 0 dt = 0.

Hence, the line integral ∫e^t dx along the line segment C is equal to 0.

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The type of quadrilateral PQRS is a trapezium. A trapezium is a quadrilateral with one pair of parallel sides. In this case, the parallel sides are PQ and SR.

To find the value of x, we can use the distance formula. The distance formula states that the distance between two points is equal to the square root of the difference of their x-coordinates squared plus the difference of their y-coordinates squared.

In this case, we have the following:

PQ = √((x - 10)² + ((-9) - 3)²

We are given that PS = 15 units, so we can set the above equation equal to 15 and solve for x.

15 = √((x - 10)² + ((-9) - 3)²)

225 = (x - 10)² + 144

225 = x² - 20x + 100 + 144

(x - 15)(x - 5) = 0

Therefore, x = 15 or x = 5.

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In order to construct a right triangle with a given hypotenuse and acute angle, draw a straight line segment that represents the given hypotenuse.

Mark one endpoint of the hypotenuse as point A.

From point A, construct a perpendicular line to the hypotenuse. This perpendicular line will represent one of the legs of the right triangle.

Use a protractor to measure the given acute angle from the perpendicular line you just drew.

From the point where the acute angle intersects the perpendicular line, draw another line segment that extends away from the hypotenuse. This line segment will represent the other leg of the right triangle.

The intersection point of the two legs will be the third vertex of the right triangle.

Make sure to measure and construct accurately to ensure the triangle is a right triangle with the desired properties.

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The first two steps in solving the radical equation √x - 6 + 5 = 12 are:

C. Subtract 5 from both sides and then square both sides.

The first two steps in solving the radical equation √x - 6 + 5 = 12 are:

C. Subtract 5 from both sides and then square both sides.

The correct steps are as follows:

Subtract 5 from both sides:

√x - 6 = 12 - 5

√x - 6 = 7

Square both sides of the equation:

(√x - 6)² = 7²

(x - 6)² = 49

Therefore, the correct choice is option C. Subtract 5 from both sides and then square both sides.

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There are 24 possible ways the four schools can place 1st, 2nd, 3rd, and 4th in the finals.

We have,

To determine the possible ways the four schools can place 1st, 2nd, 3rd, and 4th in the finals, we can use the concept of permutations.

A permutation is an arrangement of objects in a specific order. In this case, we want to find the permutations of the four schools.

The number of permutations can be determined by multiplying the number of choices for each position.

Since there are four schools, there are four choices for the 1st position, three choices for the 2nd position, two choices for the 3rd position, and one choice for the 4th position.

The total number of permutations is given by:

= 4 × 3 × 2 × 1

= 24

Therefore,

There are 24 possible ways the four schools can place 1st, 2nd, 3rd, and 4th in the finals.

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