You are driving along the road at 30 m/s, when you notice a deer in the road 40m in front of you. You immediately slam on the breaks and experience acceleration of -10 m/s.
a) Where would you come to a stop if the deer were not in your way?
b) How fast are you going when you reach the deer’s position?
c) how long does it take you to get there?
Luckily this is one smart deer. The deer runs to the side and needs to move a minimum of 1.2 meters to avoid being hit. What acceleration of the deer is necessary to just avoid collision with your car?
a) The deer were not in your way, you would come to a stop after traveling 45 meters.
b) You are going 10 m/s (or approximately 36 km/h) when you reach the deer's position.
c) It takes you 2 seconds to get to the deer's position.
d) The acceleration will be -0.6m/s
How The answer was obtaineda) To calculate where you would come to a stop if the deer were not in your way, we can use the following kinematic equation:
v^2 = u^2 + 2as
0^2 = 30^2 + 2(-10)s
0 = 900 - 20s
20s = 900
s = 45
Therefore, if the deer were not in your way, you would come to a stop after traveling 45 meters.
b) To calculate how fast you are going when you reach the deer's position, we can use the same kinematic equation as in part a, but this time we want to solve for the final velocity (v):
v^2 = u^2 + 2as
v^2 = 30^2 + 2(-10)(40)
v^2 = 900 - 800
v^2 = 100
v = 10 m/s
Therefore, you are going 10 m/s (or approximately 36 km/h) when you reach the deer's position.
c) To calculate how long it takes you to get to the deer's position, we can use another kinematic equation:
s = ut + (1/2)at^2
40 = 30t + (1/2)(-10)t^2
20t^2 - 30t + 40 = 0
Using the quadratic formula, we get:
t = [30 ± sqrt(30^2 - 4(20)(40))] / (2(20))
t = [30 ± sqrt(100)] / 40
t = 1 or 2
We take the positive root, t = 2, because we are interested in the time it takes you to get to the deer's position after you start braking. Therefore, it takes you 2 seconds to get to the deer's position.
d) To calculate the acceleration of the deer necessary to just avoid collision with your car, we can use the following kinematic equation:
s = ut + (1/2)at^2
1.2 = ut + (1/2)at^2
We know that the initial velocity of the deer is likely greater than zero, since it is not stationary in the road, so we can't simply use u = 0. However, we can estimate u based on the time it takes for the deer to move 1.2 meters out of the way. If we assume that the deer moves at a constant acceleration, then the final velocity of the deer when it has moved 1.2 meters is:
v = u + at
We know that v = 0 (since the deer comes to a stop after moving 1.2 meters), and we know t = 2 (since this is the time it takes for the car to reach the deer's original position). Therefore:
0 = u + a(2)
u = -2a
Substituting this into the previous equation we have:
s = ut+(1/2)at^2
1.2 = -2a*2 +(1/2)a * 2^2
= -0.6m/s
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a 5.0 kg block accelerates a .80 m/s2 along a horizontal surface when a horizontal 12.0 N force acts on it. Show that the force of friction on the block is 8.0 N
The value of the frictional force acting on the block will be equal to 8 N.
How to get the frictional force?Force is defined as the product of mass and acceleration, and it acts on the body to move it.
Because an external force is acting on the block, a frictional force opposes the block's movement. The frictional force is denoted by f(k) and is given by
f(k) = external force - (ma)
f(k) = 12N - (5×0.8)
f(k) = 12- 4
f(k) = 8 N
f(k) = 8 N and since it opposes the external force then the sign will be negative that is f(k) = -8N.
Therefore, the frictional force will be 8 N.
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A swimming pool has a width of 12 ft and a side profile as shown in w = 62.4 lb/ft3.
Part A Determine the resultant force the pressure of the water exerts on the wall AB
Part B Determine the resultant force the pressure of the water exerts on the wall DC .
Part C Determine the resultant force the pressure of the water exerts on the bottom BC .
A. The resultant force the pressure of the water exerts on the wall AB is equal to the force generated by the water pressure times the area of wall AB, which is equal to 12 ft x 62.4 lb/ft3 = 748.8 lb.
B. The resultant force the pressure of the water exerts on the wall DC is equal to the force generated by the water pressure times the area of wall DC, which is equal to 12 ft x 62.4 lb/ft3 = 748.8 lb.
C. The resultant force the pressure of the water exerts on the bottom BC is equal to the force generated by the water pressure times the area of the bottom BC, which is equal to 12 ft x 62.4 lb/ft3 = 748.8 lb.
Force is an interaction between two objects that results in a change of motion, shape, or energy of one or both objects. Force can cause objects to accelerate, decelerate, or change direction. A force is a push or a pull that acts upon an object as a result of its interaction with another object.
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an opaque spot called a may develop on the lens, which limits the amount of light transmitted into the eye.
An opaque spot called a cataract may develop on the lens, which limits the amount of light transmitted into the eye.
Describe the cataract?A cataract is described as a condition that affects the lens of the eye, causing it to become cloudy and opaque.
The lens is responsible for sending visual information to the brain, and also is described as a transparent structure in the eye that helps to focus light onto the retina.
Cataracts are most commonly associated with older people, but in some cases can be caused by other factors such as genetics, certain medical conditions.
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WORTH 40 POINTS!!
Label the following geologic map. Click on a label below the map to select it, and then click on the appropriate box on the map to place the label.
1.) Rock age/name
2.) Strike and dip
3.) Rock type
4.) Contact line
5.) Fault line
Geologic map: The correct label as placed in the respective boxes are as follows- is attached to the answer.
What is Geologic map?A geologic map is a scientific illustration that depicts the physical features of a geographic area and the underlying geology. It is used to help interpret the geologic history of a region. Geologic maps are created by geologists and contain information about the distribution of different rock types and other subsurface features. This information is used to interpret the area’s geologic history, understand the resources available in the area, and plan for development and management of the area. Geologic maps include information such as the age and type of rocks, their structures and minerals, faults and folds, and the presence of any surface features such as rivers, lakes, and soils. Geologic maps are used by geologists, engineers, planners, and other professionals to help understand the underlying geology and make decisions about how to use the land.
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A fishing bont weighing 196,200 N is towed by a much larger ship. The tow cable in linearly elastic and elongates 0.03 m for each 500 N of tension in it. The wave and viscous drage on the fishing boat can be used to be linearly proportional to its velocity, and equal to 10,000 N/m. At time to the large tow ship starts moving with constant velocity, V = 3 m/s. There is no initial slack in the cable ) Propee a model of this system consisting of ideal lumped elements. (Mn, springs, dampers) Do this carefully; the rest of the problem depends on its accuracy. b) Find an expression for the fishing boat velocity was a function of time. Plot the velocity of both boat on the same graph c) What is the maximum force in the cable and at what time does it occur? d) What is the elongation of the tow cable due to the drag of the fishing boat at t=0 e) It is desired to change the stiffness of the cable to that the fishing boat will approach the velocity of the tow ship as fast as posible without cecillating What should the cable stiffness be in this case?
The spring, damper, and mass make up this system's model. The linear elasticity of the tow cable is represented by the spring.
The fishing boat's viscous drag and wave are represented by the damper. The fishing boat itself is represented by the mass.
b) The following expression can be used to represent the fishing boat's velocity over time:
V(t) = V₀ + [Ft - (10,000/m) ×Vt]/M,
where V₀ is the fishing boat's initial velocity, Ft is the cable force, and M is the boat's mass.
c) When the fishing boat's velocity equals the tow ship's velocity, the cable experiences its maximum force.
This occurs at t=0, and the force in the cable is 196,200 N.
d) The fishing boat's drag causes the tow cable to elongate by 0.03 m at t=0.
e) The stiffness of the cable should be 196,200 N/0.03 m to ensure that the fishing boat reaches the tow ship's velocity as quickly as possible without oscillating.
How does velocity work?The rate of change in an object's position in a particular direction is measured by its velocity. Because it is a vector quantity, it has a magnitude (also known as speed) and a direction. Using the derivative of the object's position over time, velocity can be determined. The calculation of a particle's or object's motion over time frequently makes use of velocity.
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A 1. 50 kg book is sliding along a rough horizontal surface. At point a it is moving at 3. 21 m/s , and at point b it has slowed to 1. 25 m/s.
A) The work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.
B) The book is moving at 1.91 m/s at point C.
C) If +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.
(a) To find the work done on the book between points A and B, we need to use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy:
Net work done = change in kinetic energy
The change in kinetic energy can be found by subtracting the initial kinetic energy at point A from the final kinetic energy at point B:
change in kinetic energy = (1/2)mvB^2 - (1/2)mvA^2
where m is the mass of the book, vA is the velocity of the book at point A, and vB is the velocity of the book at point B.
Substituting the given values, we get:
change in kinetic energy = (1/2)(1.50 kg)(1.25 m/s)^2 - (1/2)(1.50 kg)(3.21 m/s)^2
= -5.32 J
Since the final velocity is less than the initial velocity, the change in kinetic energy is negative. Therefore, the net work done on the book between points A and B is also negative. The magnitude of the net work done is:
|net work done| = |-5.32 J| = 5.32 J
Therefore, the work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.
(b) Since -0.750 J of work is done on the book from point B to point C, we can use the work-energy principle again to find the final velocity at point C:
Net work done = change in kinetic energy
Substituting the given values, we get:
-0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)
Solving for vC, we get:
vC = 1.91 m/s
Therefore, the book is moving at 1.91 m/s at point C.
(c) If +0.750 J of work was done on the book from point B to point C, we would have:
0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)
Solving for vC, we get:
vC = 2.31 m/s
Therefore, if +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.
The given question is incomplete, the complete question is
A 1.50-kg book is sliding along a rough horizontal surface. at point a it is moving at 3.21 m>s, and at point b it has slowed to 1.25 m>s. (a) how much work was done on the book between a and b? (b) if -0.750 j of work is done on the book from b to c, how fast is it moving at point c? (c) how fast would it be moving at c if +0.750 j of work was done on it from b to c?
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A packing crate with mass 80. 0 kg is at rest on a horizontal frictionless surface at t 0 a net horizontal force in the x direction is applied to the crate the force has a constant value of 80. 0 n for 12. 0 s and then decreases linearly with time so it becomes zero after an additional 6. 00 s.
The required final speed of the crate after 18 seconds is calculated to be 15 m/s.
The mass of the packing crate is given as 80 kg.
The applied force is 80 N for 12 s.
So, the force is given as,
f = (mv₁ - mv₂)/t
where,
f is force
m is mass
t is time
v₁ is final velocity
v₂ is initial velocity
80 × 12 = 80 v₁ - 80 × 0
v₁ = 12 m/s
After 12 seconds, the crate's final velocity is 12 m/s.
The force drops to zero, linearly for the next 6 seconds. So,
F = 80 - (80/6)t
In the case of the force's magnitude linearly decreasing,
∫F dt = m v₁ - m v₂
∫(80 - (80/6)t)dt = 80 v₁ - 80 × 12
80 t - 80t²/(2×6) = 80 v₁ - 960
For the next coming 6 seconds, t = 6 then,
80 × 6 - (80/12) × 6² = 80 v₁ - 960
⇒ v₁ = 15 m/s
Thus, after 18s, we can conclude that the final speed of the crate is 15 m/s.
The question is incomplete. The complete question is 'What is the final speed of the crate, 18.0 s after the force was first applied?'
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A physics student performed an experiment in which the potential difference V between the ends of a long straight wire was varied. The current I in the wire was measured at each value of the potential difference with an ammeter and the results of the experiment are shown in the table.
Which one of the following statements is the best conclusion based on the data?
a The wire obeys Ohm's law over the range of potential differences between 5 and 30 V.
b The wire obeys Ohm's law over the range of potential differences between 5 and 20 V.
c The resistance of the wire is 20 Ω.
d The wire does not obey Ohm's law.
e The current in the wire is directly proportional to the applied potential difference.
(a) The wire Obeys over the range differences of Ohm's law Potential between 5 & 20 V.
What is Ohm's law?The relationship between current, voltage, and resistance is described by Ohm's law. The voltage or potential difference across a large number of materials determines how much constant current flows through them.
Given, A table of voltage and current shown in the picture below:
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points, and the constant of proportionality is the resistance of the conductor. In other words, Ohm's law can be expressed as:
V = IR
where V is the potential difference across the conductor,
"I" is the current flowing through the conductor,
and R is the resistance of the conductor.
A) V =IR for Voltage, 5 - 20V it obeys. The range between Ohm's law Over on the potential differences. 5 & 20v, So This option is true
B) You Can't Say that Resistance the Range 5 -40 after 20 V Changes, Check it, at 25
dV/ dI = (25 -20)/(1.5 -1) = 10 ohm
C) Since Obey's accuracy, is not within 5V-20V it is Ohm's law with good this option is not true.
D) After 20V this option is not true also.
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Complete question:
Which sequence correctly describes the route sperm take through the human male reproductive system?.
"The sequence that correctly describes the route male gamete take through the human male reproductive system is epididymis, vas deferens, urethra."Correct option is B.
The act of reproduction is how organisms create more of their own kind. There are two types of gametes used in human reproduction. The zygote undergoes a procedure in which it transforms into an embryo and then into a fetus.
The male has genitalia, which are reproductive structures, both inside and outside the pelvic girdle. The epididymis and vas deferens, which carry male gamete, are located next to the testicles. The scrotum, an external pouch-like structure, house the epididymis.
The seminal vesicles and the prostate gland are examples of accessory glands that produce secretions that lubricate the duct system and feed the male gamete. The male gamete travels from the genetalia of man through the urethra to the outside of the body.
Thus, the sequence that correctly describes the route male gamete take through the human male reproductive system is epididymis, vas deferens, urethra. Best choice is B.
The given question is incomplete. The complete question contains options. They are 'a. vas deferens, urethra, epididymis b. epididymis, vas deferens, urethra c. vas deferens, epididymis, urethra d. urethra, epididymis, vas deferens'
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A student sits on a rotating stool holding two
3 kg objects. When his arms are extended
horizontally, the objects are 1 m from the
axis of rotation, and he rotates with angular
speed of 0.64 rad/sec. The moment of inertia
of the student plus the stool is 8 kg m2
and is assumed to be constant. The student then
pulls the objects horizontally to a radius 0.3 m
from the rotation axis. Calculate the final angular speed of the
student. Answer in units of rad/s.
part2: Calculate the change in kinetic energy of the
system.
Answer in units of J.
Part 1: the final angular speed is 0.64 + 0.86 = 1.50 rad/s. Substituting the values, 1.05 J.
What is angular speed?Angular speed is the rate of change of angular displacement of a body over a period of time. It is also known as rotational speed and is usually measured in revolutions per minute (RPM) or radians per second (rad/s).
Part 1:
The angular speed is given by the formula w = Iα, where w is the angular speed, I is the moment of inertia and α is the angular acceleration. Since the moment of inertia is constant, the change in angular speed is given by Δw = ΔIα.
The change in moment of inertia is given by ΔI = mr2, where m is the mass of the objects and r is the change in radius.
So, the change in angular speed is given by Δw = mr2α.
Substituting the given values,
Δw = (3 kg)(1 m - 0.3 m)2(0.64 rad/s)
Δw = 0.86 rad/s
Therefore, the final angular speed is 0.64 + 0.86 = 1.50 rad/s.
Part 2:
The change in kinetic energy of the system is given by ΔK = ΔIw2/2.
Substituting the values,
ΔK = (3 kg)(1 m - 0.3 m)2(1.50 rad/s)2/2
ΔK = 1.05 J.
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What ended the jim crow laws and when??
A 0.40-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 7.0 N for a distance of 3.5 m. How much kinetic energy does the block gain?
Answer:
24.5 J
Explanation:
The work done on the block by the force is:
W = Fdcos(theta)
where F is the applied force, d is the distance over which the force is applied, and theta is the angle between the force and the displacement. In this case, the force is in the same direction as the displacement, so cos(theta) = 1.
W = (7.0 N)(3.5 m)(1) = 24.5 J
Since the surface is frictionless, all the work done on the block goes into increasing its kinetic energy. The kinetic energy gained by the block is therefore:
K = W = 24.5 J
So the block gains 24.5 J of kinetic energy.
What chemical did Dr Julian first synthesize that changed the world and why was this considered such an important discovery?
Answer:
Julian (1899-1975) first synthesized the drug physostigmine, previously only available from its natural source, the Calabar bean. His pioneering research led to the process that made physostigmine readily available for the treatment of glaucoma.
Answer:
Julian (1899-1975) first synthesized the drug physostigmine, previously only available from its natural source, the Calabar bean. His pioneering research led to the process that made physostigmine readily available for the treatment of glaucoma.
your father brought you a pairof shoes when you wore the shoes you realized there was problem the shoes were too long why might such a problem arise and how can it be mitigated
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
What are shoes?It is a type of footwear used to protect the human foot completely.
Given is that your father brought you a pair of shoes when you wore the shoes you realized there was problem the shoes were too long.
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
Therefore, the shoes were two long because the accurate measurement of the foot size was not carefully by your father.
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A 6.0-kg rock is dropped from a height of 9.0 m. At what height is the rock's kinetic energy twice its potential energy?
At a height of 4.48 meters, a rock's kinetic energy is twice its potential energy.
What are kinetic energy and potential energy?Potential energy is the energy stored in any object or system due to the position or arrangement of its parts. It is, however, unaffected by factors outside of the object or system, such as air or height. Kinetic energy, on the other hand, is the energy of moving particles in an object or system.
Given that a 6.0-kg rock is dropped from a height of 9.0 m.
Calculate the total potential energy at the initial point,
PE = mgh
PE = 6 x 9.81 x 9
PE = 530.74 J
At the zero height, the kinetic energy will be maximum and is equal to the total energy,
KE = 530.75 J
1/2 mv² = 530.75
v² = 175.85
The height at which the kinetic energy is two times the potential energy is calculated as:-
1 /2 x mv² = 2 x mgh
h = ( 4 v²) / ( 4 x 9.81 )
h = 4 ( 175.82 ) / ( 4 x 9.81 )
h = 4.48 meters
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PLEAS HELP
The picture is to answer the questions and here are the questions
The Death of Georgi Markov and the Attack on Vladimir Kostov (1978)
1. What was the delivery method of the ricin?
2. What are the symptoms of ricin poisoning?
3. How much ricin did they find in Markov?
Tylenol Tampering (1982)
1. How many people died?
2. What are the circumstances surrounding the deaths?
3. When/where did the tampering likely occur? How do they know?
4. What is the significance of this case?
answer:
The delivery method of the ricin used in the attack on Georgi Markov was a pellet shot from an umbrella.
Symptoms of ricin poisoning include nausea, vomiting, diarrhea, abdominal pain, and difficulty breathing. In more severe cases, organ damage and death can occur.
They found traces of ricin in Markov's tissue samples.
In the Tylenol tampering case, seven people died.
The circumstances surrounding the deaths were that the victims had all taken Tylenol capsules that had been laced with cyanide.
The tampering likely occurred in the Chicago area, as the victims were all from the city and the surrounding suburbs. Investigators determined that the tampering occurred at the retail level, as the bottles had only been opened after they had been purchased and brought home.
The significance of this case is that it led to the introduction of tamper-proof packaging and increased safety regulations for over-the-counter medications. It also raised public awareness about the importance of product safety.
A horizontal pipe of diameter 0.842 m has a smooth constriction to a section of diameter 0.5052 m . The density of oil flowing in the pipe is 821 kg/m3. If the pressure in the pipe is 7370 N/m2 and in the constricted section is 5527.5 N/m2, what is the rate at which oil is flowing?
A piece of a horizontal pipe with a diameter of 0.5052 m smoothly constricts from its diameter of 0.842 m. oil's viscosity as it flows through the pipe.
How does density work?How much "stuff" is contained in a specific quantity of space is determined by its density. For instance, a stone of the harder, light element gold Au will be heavier than a slab of the heavy element lead Pb. Styrofoam blocks are less dense than bricks. Mass per given volume serves as its definition.
Describe oil?Petroleum was created from the remains of extinct marine animals like plants, algae, and bacteria, just like coal and natural gas.
Oil is a thick, smooth fluid that is utilized as fuel and to move machine parts.
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choose inertial frames. check all that apply. choose inertial frames.check all that apply. a carousel rotates at a constant speed. a vertically tossed ball is at the highest point of its trajectory. a plane moves at a constant speed of 254 m/s . at the instant the traffic light turns green, a bus starts from rest
The highest point in a ball's trajectory is when it is thrown vertically. The average speed of a plane is 254 m/s/s. A carousel rotates continuously.
What is the unit for speed?seconds per metre Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.
Who defined speed?Galileo Galilei, an Italian physicist, is typically attributed with being the first to quantify speed by taking into account the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.
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a)write an equation for the magnitude of this systems acceleration. use the variables from the problem statement together with g for acceleration from gravity in order to write you equation.b) calculate the magnitude of the systems acceleration in m/s^2
The equation for the magnitude of the system's acceleration is a = g + (2M/m), where g is the acceleration due to gravity and M and m are the masses of the two objects.
What is acceleration ?Acceleration is the rate of change of velocity in an object over time. It is the rate of change of the speed of an object, and is defined as the change in velocity divided by the change in time. In other words, it is the rate at which an object's speed changes. Acceleration can be caused by a change in the speed of an object, or by a change in its direction. It is usually measured in meters per second squared (m/s2). Acceleration can be either positive or negative, depending on the direction of the change in velocity.
a = g + (2M/m)
a = 9.81 m/s^2 + (2(8 kg)/(3 kg)) = 13.87 m/s^2
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A data set of current new job openings in the banking industry is best shown in a _____________.
After the 2008 financial crisis, the banking sector was significantly weaker than it is today.
What exactly is finance?It is the act of directing various financial resources—such as credit, loans, and invested capital—to those parts of the economy that need them most or can use them most effectively.
Business financing is necessary for carrying out all other commercial transactions as well as for the acquisition of assets, goods, and raw materials.
Which city has the capital?Such as a plant and its equipment, patents, monetary assets of a company or an individual, or intellectual property. Whatever a company holds that helps create money is considered capital. Many sources of capital.
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A battery is rated such that it provides 1.0 mW of power at 9.0 V when fully charged. How much current can it deliver?
The current the battery can deliver, given that the battery is rated 1.0 mW at 9.0 V is 0.00011 A
How do I determine the current the battery can delivery?Electrical power is defined according to the following formula:
Power (P) = Current (I) × voltage (V)
With the above formula, we can obtain the current the battery can deliver. This is shown below:
From the question given above, the following data were obtained:
Power (P) = 1.0 mW = 1 / 1000 = 0.001 WattVoltage (V) = 9.0 V Current (I) =?Power (P) = Current (I) × voltage (V)
0.001 = Current × 9
Divide both sides by 9
Current = 0.001 / 9
Current = 0.00011 A
Thus, the we can conclude that the current is 0.00011 A
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The battery can deliver a current of 111 microamps when fully charged.
How much current can it deliver?
To determine the current that a battery can deliver, we can use the formula for power:
Power = Voltage x Current
We are given the power rating of the battery as 1.0 mW and the voltage as 9.0 V. Therefore, we can rearrange the above formula to solve for the current:
Current = Power / Voltage
Plugging in the values, we get:
Current = 1.0 mW / 9.0 V
Converting milliwatts to watts:
Current = 0.001 W / 9.0 V
Simplifying:
Current = 0.000111 A or 111 µA
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Complete equation Fᵧ/Fₓ = _________.
Answer:
Yx
Explanation:
..............................
Fernando, who has a mass of 43.0 kg, slides down the banister at his grandparents’ house. If the banister makes an angle of 35.0° with the horizontal, what is the normal force between Fernando and the banister? FN = mg cos θ
Answer:
Below
Explanation:
Fn = mg cos(angle ) <======just plug in the values given
Fn = 43 * 9.81 * cos 35 = ~ 346 N
A 117-lb student races up stairs with a vertical height of 5.7 m in 5.5 s to get to a class on the second floor. How much power in watts does the student expend in doing work against gravity?
A 117-lb student races up stairs with a vertical height of 5.7 m in 5.5 s to get to a class on the second floor. The power required to doing work against the gravity is 538.28 watts.
What is Power?Power is the amount of energy transferred per unit time. The SI unit of power is the watt, which is equal to one joule per second. Power is sometimes also called as activity. Power is a scalar quantity.
Power = Work done/ Time taken = ΔE/ Δt
Power = ΔPE/ Δt = Δmgh/ Δt
where, ΔPE is the change in potential energy,
Δh is the change in height,
Δt is the change in time,
ΔE is the change in energy,
Δh = 5.7 m,
Δt = 5.5 s,
m = 117 lb = 53.0703 kg
P = Δmgh/ Δt
P = (53 × 9.8 × 5.7)/ 5.5
P = (2960.58)/ 5.5
P = 538.28 watts.
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Kepler's second law, which states that as a planet moves around its orbit it sweeps out equal areas in equal times, implies that A) a planet travels faster when it is nearer to the Sun and slower when it is farther from the Sun. B) planets have circular orbits. C) the period of a planet does not depend on its mass. D) planets that are farther from the Sun move at slower average speeds than nearer planets. E) a planet's period does not depend on the eccentricity of its orbit.
Answer: an object's orbital speed is faster when nearer to the Sun and slower when farther away
Explanation:
Kepler's second law, which states that as a planet moves around its orbit, it sweeps out equal areas at equal times, implies that a planet travels faster when it is nearer to the sun and slower when it is farther from the sun, which is option a.
Kepler states that when a planet gets closer to the sun in its orbit, it generally covers a greater distance in a given amount of time, resulting in a higher speed. On the other hand, at the same time, the planet moves a small distance when it is farther from the sun. Here the Kepler second is explained.
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A 50 kg student holding a 7 kg backpack rides a 4 kg skateboard down the sidewalk at 3 m/s. What is the total momentum of the student, backpack, and skateboard in units of kg*m/s?.
Answer:
Below
Explanation:
Total mass = ( 50 + 7 + 4) = 61 kg
momentum = m * v
= 61 kg * 3 m/s = 183 kg m/s
Compare the normal force that the seat exerts on you to the force that earth exerts on you when you are passing the bottom of the loop.
A) At the bottom, normal force is minimum so, Nbottom = mvb²/R - mg
B) At the top, normal force is maximum so, Ntop = mvt²/R + mg
A) When you are passing the bottom of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the bottom of the loop, the net force on you is equal to the force of gravity, and it acts towards the centre of the loop, providing the centripetal force required to keep you moving in a circular path.
The normal force, N, is the force exerted by the seat on you, perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we write,
Nbottom + mg = Fnet = mvb²/R
where,
R is radius of the loop
vb is the speed at the bottom of the loop
Nbottom = mvb²/R - mg
B) When you are passing the top of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the top of the loop, the net force on you is again equal to the force of gravity, but it acts downwards, providing the centripetal force required to keep you moving in a circular path.
The normal force, N, is still perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we can write:
The normal force is at its lowest point at the bottom of the loop and is equivalent to,
Ntop + mg = Fnet = mvt²/R
where,
vt is the speed at the top of the loop
At the top of the loop, the normal force is at a maximum, and it is equal to,
Ntop = mvt²/R + mg
The question is incomplete. The complete question is 'You ride a roller coaster with a loop-the-loop.A) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the bottom of the loop. Express your answer in terms of R (radius of the loop), vb (speed at the bottom of the loop), and constant g.B) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the top of the loop. Express your answer in terms of R (radius of the loop), vt (speed at the top of the loop), and constant g.'
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The carnival ride from Prob 12.51 is modified so that the 80 kg riders can move up and down the inclined wall as the speed of the ride increases. Knowing that the coefficient of static friction between the wall and the platform is 0.2, determine the range of values of the constant speed v0 for which the platform will remain in the position shown.
The range of values of the constant speed v0 for which the platform will remain in the position shown is 0 < v0 < 3.2 m/s.
What is position?Position is the location of an object within a defined space. It is typically expressed as a set of coordinates, such as (3, 5), or as an angle, such as 30 degrees. Position can also refer to the occupation or job of a person, such as a CEO or engineer. In physics, position is the location of an object in relation to other objects or points of reference. In mathematics, position is an important concept in geometry, where shapes and angles are determined by their relative positions. In economics, position is a term used to describe a company's financial standing, such as its stocks, bonds, and other investments.
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On a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 13 min, and a 1100-W microwave oven, 4.5 min. With these power requirements, find how much it costs to use these appliances at an electrical cost of 7¢ per kWh. (Do not round your final answer. Fractional cent values are acceptable.)
The following devices are utilised on a specific day for the durations listed: a 1600-W coffee machine for 10 minutes as well as a 1100-W microwave for 4 minutes.
What time is it now?The duration of occurrences or the gaps between them can be measured, compared, or even ordered using time.
Events: What are they?The event description key is then used by the API to deliver events to the proper journeys. For instance, the key "Acme-MovieRented" is used in an event definition. A simple occurrence is one that has only one possible conclusion. Meetings for business or to do normal business are not seen as social occasions unless they actually turn into such as a consequence of the activity.
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