In a particular redox reaction, MnO2 is oxidized to MnO4– and Fe3 is reduced to Fe2 . Complete and balance the equation for this reaction in acidic solution. Phases are optional.

The pair of isostructural compounds more likely to undergo thermal decomposition at lower temperatures is MgCO₃ and CaCO₃ (Option A).

MgCO₃ and CaCO₃ are both isostructural, meaning they have the same crystal structure. However, MgCO₃ has a smaller cation (Mg₂⁺) compared to CaCO₃ (Ca₂⁺). This means that the bond between the cation and anion in MgCO₃ is stronger, making it more difficult to break and therefore requiring higher temperatures for decomposition. Therefore, CaCO₃ is likely to undergo thermal decomposition at a lower temperature compared to MgCO₃.

CsI₃ and N(CH₃)₄I₃ are both isostructural and contain the same [I₃]⁻ anion. However, CsI₃ has a larger cation (Cs⁺) compared to N(CH₃)₄I₃ (N(CH₃)₄⁺). This means that the bond between the cation and anion in CsI₃ is weaker, making it easier to break and therefore requiring lower temperatures for decomposition. Therefore, CsI₃ is likely to undergo thermal decomposition at a lower temperature compared to N(CH₃)₄I₃.

Learn more about isostructural: https://brainly.com/question/1626090

#SPJ11

The specific measurement that will be affected is the volume of gas collected in the graduated cylinder. Since not all the gas was caught, the volume measured will be less than the actual volume of gas released. This will not change the molar mass calculation.

The molar mass is calculated by using the mass of the gas and the volume of the gas collected. Even though the volume measured was less than the actual volume, the mass of the gas collected should still be accurate. Therefore, the molar mass calculation should not be affected.
Hi! I'm happy to help with your question.

a. The specific measurement that will be affected is the volume of gas collected in the graduated cylinder.

b. This mistake will likely result in a decrease in the calculated molar mass. Since the volume of gas collected is lower than it should be, the molar mass calculation will be based on a smaller amount of gas, leading to a lower value than the actual molar mass.

To know more about molar mass calculation.  click here:

brainly.in/question/15629812

#SPJ11

The production of metallic aluminum by electrolytic reduction involves the use of the Hall-Héroult cell. This process involves the extraction of aluminum from bauxite, a mineral rich in aluminum oxide, through the use of electrolysis. First, the bauxite is purified and then transformed into alumina, which is then mixed with a molten electrolyte consisting of cryolite and fluorspar.

The Hall-Héroult cell is then used to electrolyze the mixture at high temperatures (around 960°C), which results in the separation of aluminum from the oxygen in the alumina. This process requires a large amount of electrical energy, as well as constant monitoring and maintenance of the cell. The metallic aluminum produced by this process can be further processed and refined for use in various industries.

To know more about electrolytic reduction refer here:

https://brainly.com/question/24139367#

#SPJ11

The reactions are as follows: Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V

Mg2+(aq) + 2e- → Mg(s) E° = -2.37 V

Fe2+(aq) + 2e- → Fe(s) E° = -0.44 V

we have determined the half-cell reduction potentials of the following reactions:

Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V

Mg2+(aq) + 2e- → Mg(s) E° = -2.37 V

Fe2+(aq) + 2e- → Fe(s) E° = -0.44 V

To use zinc as the reference electrode, we need to determine the potential of the Zn/Zn2+ half-cell under standard conditions. The standard reduction potential for this reaction is 0 volts by definition.

Next, we can compare the half-cell potentials of the other reactions to the Zn/Zn2+ half-cell by subtracting their potentials from the potential of the Zn/Zn2+ half-cell:

Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V

Zn2+(aq) + 2e- → Zn(s) E° = 0.00 V

Mg2+(aq) + 2e- → Mg(s) E° = -2.37 V

Fe2+(aq) + 2e- → Fe(s) E° = -0.44 V

Therefore, we can fill in the relative half-cell reduction potentials with zinc as the reference electrode as follows:

Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V

Mg2+(aq) + 2e- → Mg(s) E° = -2.37 V

Fe2+(aq) + 2e- → Fe(s) E° = -0.44 V

Zn2+(aq) + 2e- → Zn(s) E° = 0.00 V

Note that we have switched the order of the Mg and Fe half-cell potentials to reflect their correct order in terms of increasing reduction potential.

Click the below link, to learn more about Electric potential:

https://brainly.com/question/9383604

#SPJ11

The volume decreased by 1.3 L (from 8.5 L to 7.2 L) to cause the pressure change from 14.6 psi to 103.8 kPa at constant temperature.  To determine the change in volume that caused the pressure change, we can use the ideal gas law:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.

First, we need to convert the initial pressure and volume to SI units:

P1 = 14.6 psi = 100.68 kPa

V1 = 8.5 L

Next, we can use the ideal gas law to calculate the number of moles of gas in the initial state:

n1 = (P1 V1) / (RT1)

where R is the ideal gas constant (0.0821 L·atm/K·mol) and T1 is the temperature in Kelvin (27.0 + 273 = 300 K).

Similarly, we can use the ideal gas law to calculate the number of moles of gas in the final state:

n2 = (P2 V2) / (RT2)

where P2 is the final pressure (103.8 kPa), T2 is the temperature (also 27.0 °C + 273 = 300 K), and we want to solve for V2, the final volume.

Equating the number of moles of gas in the two states (since the amount of gas remains constant):

n1 = n2

(P1 V1) / (RT1) = (P2 V2) / (RT2)

Solving for V2, we get:

V2 = (P1 V1 RT2) / (P2 RT1)

Substituting the given values, we get:

V2 = (100.68 kPa x 8.5 L x 300 K) / (103.8 kPa x 0.0821 L·atm/K·mol x 300 K)

V2 = 7.2 L

Therefore, the volume decreased by 1.3 L (from 8.5 L to 7.2 L) to cause the pressure change from 14.6 psi to 103.8 kPa at constant temperature.

To know more about ideal gas law, visit:

https://brainly.com/question/28257995

#SPJ1

Kw at 15°C of pure water at a pH of 7.17 is 2.78 x 10^-15.

To calculate Kw at 15°C, we can use the equation:
Kw = [H+][OH-]

At 15°C, the pH of pure water is 7.17, which means:

[H+] = 10^-pH
[H+] = 10^-7.17
[H+] = 5.27 x 10^-8

Since pure water is neutral, [H+] = [OH-]. Therefore:

[OH-] = 5.27 x 10^-8

Now we can plug these values into the Kw equation:

Kw = [H+][OH-]
Kw = (5.27 x 10^-8)(5.27 x 10^-8)
Kw = 2.78 x 10^-15

Therefore, the answer is: 2.78 x 10^-15.

To know more about pH refer here:

https://brainly.com/question/15289741#

SPJ11#

Based on the given information, it can be concluded that ethanol is a polar molecule while carbon tetrachloride is a nonpolar molecule. Polar molecules like ethanol can dissolve in polar solvents like water, while nonpolar molecules like carbon tetrachloride cannot dissolve in polar solvents.

Based on the information provided, we can conclude that ethanol is polar and miscible with water, while carbon tetrachloride is nonpolar and immiscible with water. This difference in polarity is what leads to ethanol's ability to dissolve in water and carbon tetrachloride's inability to do so.

To know more about polar molecule visit:-

https://brainly.com/question/31023968

#SPJ11

An excitatory postsynaptic potential (EPSP) occurs when neurotransmitters bind to their receptors and open chemically-gated ion channels, typically cation channels, such as Na+ or Ca2+.

What is Ion?

An ion is an atom or molecule that has gained or lost one or more electrons, giving it a net positive or negative electrical charge. When an atom gains an electron, it becomes negatively charged and is called an anion. When an atom loses an electron, it becomes positively charged and is called a cation. Ions play important roles in many chemical and biological processes, such as nerve impulses, muscle contractions, and the formation of chemical bonds. They can also be involved in the movement of fluids and nutrients across cell membranes.

This influx of positive ions depolarizes the postsynaptic membrane, making it more likely to generate an action potential.

Learn more about Ion from the given link

https://brainly.com/question/13692734

#SPJ1

According to the question the calculation for the second reaction is 2487.2 J.

Reaction is a response to a stimulus, either internal or external. It is an action taken in response to a certain situation or event. When a person faces a certain situation or event, they may react in a certain way. This could be a physical response such as running away or an emotional response such as feeling scared.

The amount of heat energy produced in each reaction can be calculated using the equation q=mcΔT,
where m is the mass of the solution,
c is the specific heat, and ΔT is the change in temperature.
For example, in the first reaction,
the mass of the solution is 10 mL x 1.03 g/mL = 10.3 g and the change in temperature is 20°C. Thus, q= (10.3 g) (4.18 J/(g•°C)) (20°C) = 829.4 J.
The calculation for the second reaction is the same: q= (20 mL x 1.03 g/mL) (4.18 J/(g•°C)) (30°C) = 2487.2 J.

To learn more about reaction
https://brainly.com/question/25769000
#SPJ1

Your question is: An aqueous solution is made with the salt obtained from combining the weak acid hydrofluoric acid (HF) and the weak base methylamine (CH3NH2). Is the solution acidic, basic, or neutral?

The solution is basic.
When a weak acid (hydrofluoric acid) reacts with a weak base (methylamine), the resulting salt will be an ionic compound consisting of the conjugate base of the acid (F-) and the conjugate acid of the base (CH3NH3+). In an aqueous solution, these ions can react with water to form their respective parent compounds.
F- + H2O ⇌ HF + OH-
CH3NH3+ + H2O ⇌ CH3NH2 + H3O+
Since both the acid and the base are weak, their conjugate base and conjugate acid will be relatively strong. However, in this case, the basic nature of F- is weaker than the acidic nature of CH3NH3+. This is due to the higher stability of the conjugate acid CH3NH3+ as compared to the conjugate base F-.
When the salt is dissolved in water, the reaction that occurs to a greater extent is the hydrolysis of CH3NH3+ ion, producing a higher concentration of hydroxide ions (OH-) than hydronium ions (H3O+). As a result, the pH of the solution will be greater than 7, indicating that the solution is basic.

For more information on hydrolysis see:

https://brainly.com/question/29439050

#SPJ11

As the number of lone pairs on the central atom of a molecule increases, the size of the bond angle(s) decreases. This is because the lone pairs exert a stronger repulsive force on the bonded pairs of electrons, causing them to move closer together and therefore decreasing the angle between them.

The lone pairs are held closer to the central atom than the bonded pairs, which results in a greater repulsion between the lone pairs and the bonded pairs. This repulsion causes the angle between the bonded pairs to decrease, resulting in a smaller bond angle overall. The effect of lone pairs on bond angles is known as the VSEPR (Valence Shell Electron Pair Repulsion) theory, which explains the geometry of molecules based on the repulsion between pairs of electrons in the valence shell of atoms.

Learn more about lone pairs: https://brainly.com/question/25192438

#SPJ11

The correct answer is option a. HBr > [tex]CH_{2}ClCOOH[/tex] > [tex]CH_{2}FCH_{2}COOH[/tex] > [tex]I_{3}COOH[/tex] > [tex]CH_{3}CH_{2}COOH[/tex].

The strength of an acid depends on its ability to donate a proton (H+). HBr is a strong acid, whereas the others are organic acids with varying degrees of acidity due to the presence of electronegative atoms or groups. The stronger electron-withdrawing groups (Cl, F) make the acids more acidic, as they stabilize the negative charge on the conjugate base.

[tex]CH_{2}ClCOOH[/tex] is also a strong acid due to the electron-withdrawing effect of the chlorine atom.  [tex]CH_{2}FCH_{2}COOH[/tex] is weaker than the previous two due to the electron-donating effect of the fluorine atom.  [tex]I_{3}COOH[/tex]  is weaker than the previous three due to the electron-withdrawing effect of the iodine atoms. [tex]CH_{3}CH_{2}COOH[/tex] is the weakest acid due to the absence of any electron-withdrawing or donating groups.

To know more about Acid strength:

https://brainly.com/question/30323941

#SPJ11

The atomic radius as you move from the left to the right hand side of the periodic table.

We have to note that the periodic table is the kind of arrangement that shows the elements that we have in the order in which the elements can be able to undergo reaction.

The atomic radius typically increases as you walk down a group (vertical column) and decreases as you move across a period (horizontal row) from left to right, according to trends shown in the periodic table.

Learn more about periodic table:https://brainly.com/question/29617735

#SPJ1

The three terms - mass, volume, and density - all have a mathematical relationship between each other.

The Density Formula

[tex]d = \frac{m}{v} [/tex]

In the formula, d is the variable for density, m is the variable for mass, and v is the variable for volume. Basically, when you divide the mass of an object by it's volume, you get the density of that object.

Because of this, we can assume that there are two other formulas to show us how we can find the mass and volume of an object, all which using the three terms stated in the question.

[tex]m = d \times v[/tex]

[tex]v = \frac{m}{d} [/tex]

Therefore, there is a mathematical relationship between mass, volume, and density.

The interpolated value of the activity coefficient of Rb⁺ at an ionic strength of 0.040 M is 0.902.

To interpolate the value of the activity coefficient of Rb⁺ at a given ionic strength of 0.040 M, we can use a linear interpolation formula:

y = y1 + (x - x1) * ((y2 - y1) / (x2 - x1))

where:

x = 0.040 M (the given ionic strength)

x1 = 0.01 M (the ionic strength in the table closest to the given value)

x2 = 0.05 M (the next ionic strength in the table)

y1 = 0.907 (the activity coefficient corresponding to x1)

y2 = 0.835 (the activity coefficient corresponding to x2)

Substituting these values into the formula, we get:

y = 0.907 + (0.040 - 0.010) * ((0.835 - 0.907) / (0.050 - 0.010))

y = 0.907 + 0.030 * (-0.144)

y = 0.902

For more question on activity coefficient click on

https://brainly.com/question/31504767

#SPJ11

The correct sequence of reactions hat can be used to convert 1-pentene to 1-pentyne is  (b) - treatment with Br2, followed by treatment with NaNH2.

First, 1-pentene reacts with bromine (Br2) in a halogenation reaction, which adds two bromine atoms across the double bond. This results in the formation of 1,2-dibromopentane. Next, the compound undergoes dehydrohalogenation when treated with sodium amide (NaNH2), a strong base. This reaction removes a hydrogen atom and a bromine atom from the 1,2-dibromopentane molecule, generating an alkyne with a triple bond between the first and second carbons. This final product is 1-pentyne.

The other options do not lead to the desired product due to differences in the reactions or reagents used, such as creating different functional groups, not removing the halogen atoms, or not producing an alkyne. Overall,The correct sequence of reactions hat can be used to convert 1-pentene to 1-pentyne is  (b) - treatment with Br2, followed by treatment with NaNH2.

Learn more about halogenation at:

https://brainly.com/question/28717295

#SPJ11

The correct answer is D) Two bromine atoms. The presence of two peaks of equal intensity at 160 and 162 in the mass spectrum suggests the presence of two isotopes, which could correspond to the two bromine isotopes (79Br and 81Br) in the compound. None of the other answer choices correspond to isotopes with atomic masses of 160 and 162.

The mass spectrum of a compound provides information about the molecular weight of the compound and the relative abundance of its different isotopes. The presence of two peaks of equal intensity separated by a mass of 2 suggests that the compound contains two isotopes of the same element that differ by a mass of 2, such as chlorine-35 and chlorine-37 or bromine-79 and bromine-81. The difference in mass between the two peaks is not large enough to be attributed to the presence of iodine, which has a much higher atomic mass. Therefore, option B can be ruled out. The fact that there are two peaks of equal intensity suggests that the compound contains an even number of the same element. Therefore, option A can be ruled out because it suggests the presence of an odd number of chlorine atoms. Option C suggests the presence of a single bromine atom, which is not consistent with the observation of two peaks in the mass spectrum. Therefore, option C can also be ruled out. Thus, the correct answer is option D, which suggests the presence of two bromine atoms. The two peaks of equal intensity could be attributed to the presence of two isotopes of bromine-79 and bromine-81.

Learn more about mass spectrum here:

https://brainly.com/question/31040502

#SPJ11

The concentration of NO at equilibrium is [tex]4.4 * 10^{-4} M[/tex].

The given equilibrium reaction is:

[tex]2 NOCl(g)[/tex] ⇌ [tex]2 NO(g) + Cl_2(g)[/tex]

The equilibrium constant (Kc) for this reaction is [tex]1.6 * 10^{-5}[/tex] at 35°C.

At equilibrium, the concentration of [tex]Cl_2[/tex] is 0.012 M, and the concentration of NOCl is 0.28 M. We need to calculate the concentration of NO at equilibrium.

Let's assume that the initial concentration of NO is x M. Then, at equilibrium, the concentration of NO will be (2x) M (because the stoichiometric coefficient of NO is 2 in the balanced equation).

The equilibrium concentration of NOCl will be (0.28 - 2x) M (because 2 moles of NOCl will react to form 2 moles of NO and 1 mole of [tex]Cl_2[/tex], so the concentration of NOCl will decrease by 2x, and the concentration of [tex]Cl_2[/tex] will increase by x).

The equilibrium concentration of [tex]Cl_2[/tex] will be (0.012 + x) M (because 2 moles of NOCl will react to form 2 moles of NO and 1 mole of [tex]Cl_2[/tex], so the concentration of [tex]Cl_2[/tex] will increase by x).

Substituting these values into the equilibrium expression for Kc:

[tex]Kc = [NO]^2[Cl_2]/[NOCl]^2[/tex]

[tex]1.6 * 10^{-5} = (2x)^2(0.012 + x)/((0.28 - 2x)^2)[/tex]

Solving this equation for x using the quadratic formula gives:

[tex]x = 2.2 * 10^{-4} M[/tex]

The concentration of NO at equilibrium is

[tex]2(2.2 * 10^{-4}) = 4.4 * 10^{-4} M[/tex].

For more question on equilibrium click on

https://brainly.com/question/19340344

#SPJ11

a. While the electrode you will use is sensitive to nitrate, in practice, it is somewhat "insensitive" to the total concentration of other ions in the solution.

b. To minimize this error, a large excess of "chloride" ions was added to all samples. Adding "sodium chloride" to all samples ensures that they have the same total ion concentration, due to the dominant "sodium" and "chloride" concentrations.

The sensitivity of an ion-selective electrode to a specific ion can be influenced by the total concentration of other ions in the sample. To reduce this error, a large excess of another ion, typically chloride ions, is added to all samples to achieve the same total ion concentration.

This process is called "ionic strength adjustment" and ensures that the electrode response is only dependent on the specific ion of interest and not influenced by other ions in the sample.

The added ions are typically chosen based on their low reactivity and non-interference with the ion of interest. Ionic strength adjustment is an essential step in accurately measuring ion concentration using ion-selective electrodes.

Learn more about concentration at

https://brainly.com/question/10725862

#SPJ4

1.  Addition of CO(g) will shift the equilibrium system to the right.

2. The net effect of decreasing the temperature on the following exothermic reaction is it will shift the equilibrium toward the side of the reactants

3. If CaO(s) is added, The system remains unchanged.
4. The equilibrium system will shift to the right with Addition of CO(g)

1. According to Le Chatelier's principle, adding CO(g) to the equilibrium system will cause the reaction to shift in the direction that reduces the concentration of the added substance. In this case, the reaction will shift to the right, favoring the formation of COCl2(g).

2. For an exothermic reaction, decreasing the temperature will shift the equilibrium toward the side that produces heat (the reactants). This is because the system will try to counteract the temperature change by generating heat.

3. If CaO(s) is added to an equilibrium system, and it is not a reactant or product in the balanced chemical equation, there will be no effect on the equilibrium position. The system remains unchanged.

4. Similar to answer 1, the addition of CO(g) will cause the equilibrium to shift to the right, favoring the formation of COCl2(g) as the system tries to minimize the change in CO(g) concentration according to Le Chatelier's principle.

For more such questions on equilibrium system, click on:

https://brainly.com/question/14405126

#SPJ11

We can convert the pressure to mmHg using the conversion factor of 1 atm = 760 mmHg, giving us a final answer of 2382 mmHg. Therefore, the pressure in the 12.2 L vessel is 2382 mmHg.

First, we need to calculate the total number of moles of gas in the vessel. Using the molar masses of [tex]CO_{2}[/tex], [tex]SO_{2}[/tex], and Ar, we get 0.054 mol of [tex]CO_{2}[/tex], 0.027 mol of [tex]SO_{2}[/tex], and 0.147 mol of Ar.

Next, we can calculate the total pressure of the gas mixture using the ideal gas law. Converting the volume to liters and the temperature to Kelvin, we get P = (0.054 + 0.027 + 0.147) mol x 0.0821 L atm [tex]mol^{-1}K^{-1}[/tex] x 315 K / 12.2 L = 3.14 atm.

Finally, we can convert the pressure to mmHg using the conversion factor of 1 atm = 760 mmHg, giving us a final answer of 2382 mmHg. Therefore, the pressure in the 12.2 L vessel is 2382 mmHg.

To know more about conversion factor, refer here:

https://brainly.com/question/23510660#

#SPJ11

The pH of the benzoic acid solution before any base is added is 2.90.

Benzoic acid is a weak acid that partially dissociates in water. The dissociation reaction is as follows:

[tex]\text{C}_6\text{H}_5\text{COO}^- + \text{H}_2\text{O} - > \text{C}_6\text{H}_5\text{COOH} - \text{H}_3\text{O}^+[/tex]

The equilibrium constant expression for this reaction is given by:

[tex]K_\text{a} = \frac{[\text{C}_6\text{H}_5\text{COO}^-][\text{H}_3\text{O}^+]}{[\text{C}_6\text{H}_5\text{COOH}]}[/tex]

where [tex]\text{C}_6\text{H}_5\text{COO}^-[/tex] and [tex]\text{C}_6\text{H}_5\text{COOH}[/tex] are the concentrations of the benzoate ion and benzoic acid, respectively, and [tex]\text{H}_3\text{O}^+[/tex] is the concentration of the hydronium ion.

To determine the pH of the benzoic acid solution before any base is added, we first need to calculate the concentration of hydronium ions present in the solution.

At equilibrium, the concentration of the benzoate ion is equal to the concentration of hydronium ions produced by the dissociation of benzoic acid. Therefore,

[tex]\text{C}_6\text{H}_5\text{COO}^-[/tex] = [tex]\text{H}_3\text{O}^+[/tex]

Substituting this expression into the Ka expression and rearranging, we get:

[tex]\text{H}3\text{O}^+ &= \sqrt{K\text{a}[\text{C}_6\text{H}_5\text{COOH}]}[/tex]

[tex]= \sqrt{6.3 \times 10^{-5} \times 0.150} \[/tex]

[tex]= 1.27 \times 10^{-3} \ \text{M}[/tex]

Therefore, the pH of the benzoic acid solution before any base is added is:

[tex]\text{pH} &= -\log[\text{H}_3\text{O}^+][/tex]

[tex]= -\log(1.27 \times 10^{-3})[/tex]

pH = 2.90

To learn more about benzoic acid

https://brainly.com/question/24052816

#SPJ4

The reaction of 3.8 mol of Al with 6.2 mol HBr will produce 3 mol of H₂.

The reaction's chemically balanced equation,

3H₂ + 2AlBr₃ → 2Al + 6HBr

As per the equation, 2 moles of hydrogen gas makes 2 moles of Al and correspondingly 6 moles of HBr.

Therefore, if 6.2 moles of hydrogen bromide and 3.8 moles of aluminium react.

3 mol HBr per 1 mol Al

Therefore, 3.8 mol Al (3 mol HBr/1 mol Al) = 11.4 mol HBr is needed for a complete reaction.

Since we only have 6.2 mol of HBr, HBr is limited and Al is abundant.

3 mol H2 / 6 mol HBr = 3 mol H₂ from 6 mol HBr

As a result, 3 mol of H₂ will be produced when 3.8 mol of Al and 6.2 mol of HBr react.

To know more about moles, visit,

https://brainly.com/question/29367909

#SPJ4

The steps that can be used as a rationale for the absence of Ag in an unknown solution (but with Pb²⁺ present) in a chemical analysis experiment are: a, b, d, e, and h.

Steps (a), (b), (d), (e), (f), and (g) can be used as a rationale for the absence of Ag in an unknown solution with Pb²⁺ present in a chemical analysis experiment. The lack of yellow precipitate with KyCrO, no blackening of the white solid with NaOH and SnCl₂, and the absence of a white precipitate with 6M HCl suggest the absence of Ag.

The presence of a light blue decantate in step 1-A and the lack of dark blue solution after the addition of 15M NH₃ further support this conclusion. Additionally, the absence of a white precipitate in step 2-B and the lack of reddish-brown precipitate after adding KFe(CN)₆⁻ also indicate the absence of Ag in the unknown solution.

To know more about precipitate, here

brainly.com/question/31046678

#SPJ4

--The complete question is, Which step(s) can be used as a rationale for the absence of Ag in an unknown solution (but with Pb²⁺ present) in a chemical analysis experiment? Select all that apply:

a. A yellow precipitate did not form when KyCrO was added in step 1-C.

b. The white solid did not turn black upon addition of NaOH and SnCl2.

c. The presence of a light blue decantate in step 1-A.

d. All of the white precipitate from step 1-A dissolved in hot water.

e. A lack of dark blue colored solution after addition of 15 M NH3.

f. A white precipitate did not form in step 2-B.

g. A reddish brown precipitate did not form after adding K Fe(CN)6-

h. The white precipitate from step 1-B dissolved in 6 M NH3 and then reformed when 6 M HNO3 was added.

Note: The question is referring to a specific chemical analysis experiment, where the absence of Ag needs to be justified in an unknown solution with the presence of Pb²⁺.--

If a fatty acid has 20 carbons, ATP will it produce after it completely breaks down into co2 and water would be approximately 129 ATP

During beta-oxidation in the mitochondria, the fatty acid is broken down into two-carbon units called acetyl-CoA, which enters the citric acid cycle to produce ATP. Each round of the citric acid cycle produces 1 ATP, 3 NADH, and 1 FADH2, which enter the electron transport chain to produce more ATP.

Since one fatty acid with 20 carbons produces 10 acetyl-CoA units, it goes through the citric acid cycle 10 times, therefore, it produces 10 ATP, 30 NADH, and 10 FADH2. The NADH and FADH2 produced from beta-oxidation produce more ATP through oxidative phosphorylation in the electron transport chain, producing approximately 2.5 ATP per NADH and 1.5 ATP per FADH2. So, the total ATP produced from the complete breakdown of a fatty acid with 20 carbons would be approximately 129 ATP (10 from the citric acid cycle and 119 from the electron transport chain).

Learn more about beta-oxidation at:

https://brainly.com/question/29458295

#SPJ11

The most part of Chalk is Calcium Carbonate (CaCO3). When this reacts with Hydrochloric acid, we have production of Carbon dioxide, Calcium Chloride and Water.

CaCO3 + 2HCl → CO2 + CaCl2 + H2O

The ka for the monoprotic acid is 1.38 x 10^(-4).

To find the ka for the monoprotic acid, we can use the equation:

ka = 10^(-pH) * [H+] / [HA]

where pH is the given pH of the solution, [H+] is the concentration of hydrogen ions (which can be found using the pH), [HA] is the initial concentration of the acid (which we need to solve for), and ka is the acid dissociation constant. We know that the solution is 1.77 m, which means there are 1.77 moles of the acid in 1 liter of solution.

We can use this information to calculate the initial concentration:

[HA] = 1.77 mol / 1 L = 1.77 M

Next, we need to find the concentration of hydrogen ions using the pH:

pH = -log[H+] 2.51 = -log[H+] [H+] = 10^(-2.51) = 2.23 x 10^(-3) M

Now we can substitute these values into the equation for ka:

ka = 10^(-pH) * [H+] / [HA]

ka = 10^(-2.51) * (2.23 x 10^(-3)) / (1.77)

ka = 1.38 x 10^(-4)

Learn more about monoprotic acid at

https://brainly.com/question/22497931

#SPJ11

The addition of HCl to the reaction mixture would alter the chemical equilibrium and shift the reaction towards the formation of aluminum hydroxide.

If HCl (hydrochloric acid) is added to the reaction mixture from the previous question, it would react with the NaAl(OH)4 (sodium tetrahydroxoaluminate) present in the mixture. The balanced chemical equation for this reaction would be:

HCl(aq) + NaAl(OH)4(aq) → Al(OH)3(s) + NaCl(aq) + H2O(l)

Here, the HCl would donate a proton to the NaAl(OH)4, resulting in the formation of Al(OH)3 (aluminum hydroxide), NaCl (sodium chloride), and H2O (water). This would be an acid-base reaction where HCl acts as an acid and NaAl(OH)4 acts as a base.

Since aluminum hydroxide is an insoluble solid, it would precipitate out of the solution as a white solid. This would be observed as a white cloudy appearance in the reaction mixture. Additionally, the solution would become more acidic due to the addition of HCl.

The presence of excess HCl in the solution could also lead to the dissolution of some of the aluminum hydroxide precipitate, resulting in a clearer solution.

To know more about aluminum hydroxide refer here:

https://brainly.com/question/29422382#

#SPJ11

The pH for the solution is approximately 3.05.

The pH of a Ba(OH)2 solution can be found by calculating the concentration of hydroxide ions (OH-) and then taking the negative logarithm of that concentration.

Ba(OH)2 dissociates in water to produce two moles of OH- ions for every mole of Ba(OH)2 dissolved. Therefore, the concentration of OH- ions in a [tex]4.5* 10^-4[/tex]M Ba(OH)2 solution is:

[tex][OH-] = 2 * (4.5 * 10^-4) = 9 * 10^-4 M[/tex]

Taking the negative logarithm of this concentration gives us the pH:

[tex]pH = -log[OH-] = -log(9 * 10^-4) = 3.05[/tex]

Rounding to three significant figures gives us a pH of 3.05.

Therefore, the pH of a [tex]4.5 * 10^-4[/tex] M Ba(OH)2 solution is approximately 3.05.

Learn more about pH

brainly.com/question/491373

#SPJ11

Water has a higher surface tension than most liquids because of hydrogen  bonds its molecules form.

Water has a higher surface tension than other liquids due to the relatively high molecular or strong cohesive interactions that occur between its molecules. Hydrogen bonds also make it possible for water molecules to strongly adhere to one another and resist stretching.

The formed links are known as hydrogen bonds, and they cause the water molecules to stick together tightly and have a high surface tension.

A robust and flexible lattice of water molecules is created when several water molecules form hydrogen bonds with one another. High surface tension results from this. Water striders may move across the water's surface thanks to surface tension.

To know more about surface tension, visit,

https://brainly.com/question/138724

#SPJ4