Answers
Given statement solution is :- m <m<angle TVU <angle VWU this inequality tells us that the sum of angles <V and <m<angle VWU must be less than 90 degrees, the contradiction proof is complete.
To prove that m <m<angle TVU <angle VWU, we can use the given information and the properties of angles formed by intersecting lines.
Given:
TV = UW (1)
TU > VW (2)
To Prove:
m <m<angle TVU <angle VWU
Proof:
Since TV = UW (given), we can conclude that <T and <U are corresponding angles.
Now, consider the triangle TVU. By the Triangle Sum Theorem, the sum of the measures of the interior angles in a triangle is 180 degrees. Therefore, we have:
<T + <V + <U = 180° (3)
Since <T and <U are corresponding angles, we can substitute their measures in terms of <m<angle TVU and <m<angle VWU:
<m<angle TVU + <V + <m<angle VWU = 180° (4)
From equation (4), we can isolate the terms <m<angle TVU and <m<angle VWU:
<m<angle TVU = 180° - (<V + <m<angle VWU) (5)
Now, let's focus on the triangle VWU. By the Triangle Inequality Theorem, the sum of the measures of any two sides of a triangle is always greater than the measure of the third side. Since TU > VW (given), we have:
TV + VW > TU (6)
Substituting TV = UW (from equation (1)), we get:
UW + VW > TU (7)
Now, consider the segment UV. By the Exterior Angle Theorem, the measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles. In this case, we have:
<m<angle TVU = <V + <m<angle VWU (8)
Combining equations (5) and (8), we have:
180° - (<V + <m<angle VWU) = <V + <m<angle VWU
Simplifying this equation, we get:
180° = 2(<V + <m<angle VWU)
Since the sum of two angles cannot exceed 180 degrees, we can conclude that:
180° - 2(<V + <m<angle VWU) > 0
Dividing both sides by 2, we have:
90° - (<V + <m<angle VWU) > 0
Adding (<V + <m<angle VWU) to both sides, we get:
90° > (<V + <m<angle VWU)
This inequality tells us that the sum of angles <V and <m<angle VWU must be less than 90 degrees. Therefore, we can conclude that:
m <m<angle TVU <angle VWU
Hence, the contradiction proof is complete.
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Related Questions
on the following figure,A:E=2:3 and the area of the quadrilateral EDBC is 21 cm² find the of triangle
Answers
Area of quadrilateral BCDE is 20 cm².
From the given figure,
AD/DB=AE/EC=2
AD/AB-AD=AE/AC-AE =2
AB-AD/AD=AC-AE/AE=1/2
AB/AD = AC/AE = 1+1/2
=3/2
Therefore, ratio of areas of triangles ABC and ADE will be
ΔABC/ΔADE = (3/2)² = 9/4
If area of ΔABC =36 cm²,
36/ΔADE = 9/4
Then area of ΔADE =36×4/9 = 16 cm²
Now area of quadrilateral BCED = Area of ΔABC - Area of ΔADE
= 36 - 16
= 20 square cm
Therefore, area of quadrilateral BCDE is 20 cm².
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Mary is 5 yards to the left of the center line on a soccer field. The soccer ball is 10 yards
to the right of the center line. Which expression represents the distance from Mary to the
soccer ball?
A 10 51
B |-5-10|
C -5+10
D |10|-|-51
Answers
Answer: B |-5+10|
Step-by-step explanation:
with simple addition we can find out that the distance from Mary to the soccer ball is 15 yards (5+10).
-5-10 = -15
|-15| = 15
HELP FAST WILL GIVE BRAINLIEST, QUICK 5 MINUTES PLEASE!
So confused will give the right answer that explains it well brainliest yay please help thanks!
Answers
Answer:
2.5
Step-by-step explanation:
The new triangle is the bigger triangle so it is multiplied
The opposite lines between the two triangles is times 2
(O.G triangle side BC is 8 units while side B'C' is 20 units which is 2.5 times more than the O.G side)
hope that helped
3). The ages of ten students randomly chosen from HND Secretryship and Management evening
session class are as follows: 19, 26, 27, 17, 38, 26, 25, 20, 33, 19.
i.
ii.
Compute the average age
The standard deviation of the ages.
Answers
The probability that a student who attends the first session also attends the second session is 1/3
Evaluating the probability
We can approach this problem by using conditional probability.
Let's use the notation "S1" to represent the event that a student attends the first session, and "S2" to represent the event that a student attends the second session.
Then we can use the formula for conditional probability:
P(S2 | S1) = P(S1 and S2) / P(S1)
We know that P(S1) = 0.6, since 60% of students attend the first session. We also know that P(S1 and S2) = 0.2, since 20% of students attend both sessions.
So we can plug in these values and solve for P(S2 | S1):
P(S2 | S1) = 0.2 / 0.6
P(S2 | S1) = 1/3
Therefore, the probability that a student who attends is 1/3 or approximately 0.333.
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complete question:
In a cooking class 20% of
the students attend two
sessions. 60% of students
attend the first session of
cooking class. What is the
probability that a student that
attends the first session also
attends the second session?
Please help me out I am really struggling
Answers
The linear function for the temperature is given as follows:
T(x) = 25 - 3x.
The graph is given by the image presented at the end of the answer.
How to define a linear function?The slope-intercept representation of a linear function is given by the equation shown as follows:
y = mx + b
The coefficients m and b have the meaning presented as follows:
m is the slope of the function, representing the increase/decrease in the output variable y when the input variable x is increased by one.b is the y-intercept of the function, representing the numeric value of the function when the input variable x has a value of 0. On a graph, it is the value of y when the graph of the function crosses or touches the y-axis.The slope and the intercept for the function in this problem are given as follows:
m = -3, as for each km, the temperature decays by 3ºC.b = 25, as at sea level, the temperature is of 25ºC.Hence the function is given as follows:
T(x) = 25 - 3x.
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Which of the following steps is valid in reducing the augmented matrix?
2 1 4 21
3 5 0 25
1 6 2 17
O Square Row 1.
O Divide Row 2 by 2 times Row 1.
OMultiply Row 1 by Column 1.
O Add negative 3 times Row 3 to Row 2.
Answers
Valid step: Subtract 2 times Row 1 from Row 2. (Adding negative 2 times Row 1 to Row 2 would achieve the same result.)
To reduce the augmented matrix:
Square Row 1: This step is not valid in reducing the augmented matrix. Squaring a row would change the values and potentially lead to incorrect results.
Divide Row 2 by 2 times Row 1: This step is valid. Divide each element in Row 2 by 2 times the corresponding element in Row 1. This operation helps in achieving a leading 1 in the second row.
Multiply Row 1 by Column 1: This step is not valid in reducing the augmented matrix. Multiplying a row by a column does not have a defined operation in matrix reduction.
Add negative 3 times Row 3 to Row 2: This step is valid. Multiply Row 3 by -3 and then add it to Row 2. This operation helps in achieving zeros below the leading 1 in the second row.
After performing the valid steps, the reduced augmented matrix would be:
2 1 4 21
0 2 -6 -14
1 6 2 17
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What is the Scale factor=?
Answers
Answer:
k = 1.5--------------------
The scale factor is the ratio of corresponding sides.
Find the scale factor k for the pictured triangles:
k = 6/4 k = 1.5URGENT!!! PLEASE HELP!!! 20 POINTS!!!
A computer software company receives hundreds of support calls each day. There are several common installation problems, call them A, B, C, and D. Several of these problems result in the same symptom, lock up after initiation. Suppose that the probability of a caller reporting the symptom lock up is 0.6
and the probability of a caller having problem A and a lock up is 0.5
.
Step 2 of 2 : What is the probability that the cause of the malfunction is not problem A given that the caller is experiencing a lock up? Round your answer to four decimal places, if necessary.
Answers
The probability that the cause is problem A given that the caller reports a lock-up is 0.25, or 25%.
We have,
We can use Bayes' theorem to solve this problem, which states:
P(A | B) = P(B | A) * P(A) / P(B)
where:
P(A | B) is the probability of event A given that event B has occurred (in this case, the probability that the cause is problem A given that the caller reports a lock up)
P(B | A) is the probability of event B given that event A has occurred (in this case, the probability that the caller reports a lock up given that the cause is problem A)
P(A) is the prior probability of event A (in this case, the probability that the cause is problem A)
P(B) is the prior probability of event B (in this case, the probability that the caller reports a lock up)
We are given that:
P(B) = 0.8 (the probability that the caller reports a lock up)
P(B | A) = 0.5 (the probability that the caller reports a lock up given that the cause is problem A)
We want to find P(A | B) (the probability that the cause is problem A given that the caller reports a lock up)
We don't have the value of P(A), but we can use the fact that the sum of the probabilities of all possible causes (A, B, C, and D) is 1:
P(A) + P(B) + P(C) + P(D) = 1
We also know that the lock up symptom is present in some of the problems, so we can write:
P(B) = P(B | A) * P(A) + P(B | C) * P(C) + P(B | D) * P(D)
Substituting the values we have, we get:
0.8 = 0.5 * P(A) + P(B | C) * P(C) + P(B | D) * P(D)
We don't have the values of P(C) and P(D), but we know that they are not given in the problem statement, so we can assume that they are not relevant for this calculation and that P(C) + P(D) = 0. This allows us to simplify the equation to:
0.8 = 0.5 * P(A) + 0
which gives us:
P(A) = 0.8 / 0.5 = 0.4
Now we can use Bayes' theorem to calculate the probability that the cause is problem A given that the caller reports a lock up:
P(A | B) = P(B | A) * P(A) / P(B) = 0.5 * 0.4 / 0.8 = 0.25
Therefore, the probability that the cause is problem A given that the caller reports a lock up is 0.25, or 25%.
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complete question:
A computer software company receives hundreds of support calls each day. There are several common installation problems, call them A, B, C, and D. Several of these problems result in the same symptom, lock up after initiation. Suppose that the probability of a caller reporting the symptom lock up is 0.80.8 and the probability of a caller having problem A and a lock up is 0.50.5.
Step 1 of 2 :
Given that the caller reports a lock up, what is the probability that the cause is problem A? Round your answer to four decimal places, if necessary.
Because you loved Professor Salaam’s class so much, you go to the market and decide to trade your car for 2 magical doubling beans. After 1 day, you notice that your 2 magical beans have turned into 4 magical beans. After 2 days you look and there are 8 magical beans. On the third day, you notice there are now 16 beans. Since you are a brilliant mathematician, you decide to estimate how many beans you will have after 15 days.
How many beans will you have 65536? If each magical bean is worth $0.50, and your car was worth $65,000, did your trade make sense (after 15 days) YES, NO, MAYBE, Not enough information? Estimate how many days you would need to have doubled your beans for the trade to make sense.
Answers
According to the information, after 15 days we will have 32,768 beans that will be worth $16,384.
How to calculate how many beans will we have after 15 days?The pattern here is that the number of magical beans is doubling each day. Therefore, we can find the number of beans after 15 days by starting with the initial 2 beans and doubling them 15 times:
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 32,768
So after 15 days, you will have 32,768 magical beans.
How to calculate the value of the beans?
If each magical bean is worth $0.50, then the total value of the beans after 15 days would be:
32,768 x $0.50 = $16,384
Comparing this to the value of your car, which was $65,000, it seems like a bad trade.
How many days would I need to have doubled my beans for the trade to make sense?
To estimate how many days you would need to have doubled your beans for the trade to make sense, we can solve for the number of days in the equation:
[tex]2^d[/tex] = 65,000 / ($0.50 x 2)[tex]2^d[/tex] = 65,000 / $1[tex]2^d[/tex] = 65,000d = log2(65,000)d ≈ 15.99According to the above, we would need to have doubled your beans for approximately 16 days to make the trade worth it.
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The life expectancy of a particular brand of lightbulb is normally distributed with a mean of 1,500 hours and a standard deviation of 75 hours.
What is the probability that a lightbulb will last less than 1,410 hours?
A .1151
B .2671
C .3321
D .4218
E .5111
Answers
Step-by-step explanation:
14 10 is 90 less than the mean 1500
z score = - 90 / 75 = - 1.200
from a z-score table this represents .1151
or 11.51 % will last LESS than 1410 hrs
Helppppppppppppppppppppppppppppppppppppppppp
Answers
I NEES HELP STATISTICS
Answers
- This year at least one of their clients will have a starting salary of at least $40,000.
There is not enough information to determine whether this statement is true or false. The mean starting salary from last year does not provide information on this year's salaries.
- Last year some of their clients had a starting salary of exactly $40,000.
This statement is true. Since the mean includes all starting salaries, it is possible for some clients to have had a starting salary of exactly $40,000.
- Last year fewer than half of their clients had a starting salary of $40,000 or less.
This statement is false. Since the mean starting salary is $40,000, it is impossible for fewer than half of the clients to have had a starting salary of $40,000 or less.
- Last year some of their clients had a starting salary of more than $36,000.
This statement is true. Since the mean starting salary is $40,000, it is possible for some clients to have had a starting salary of more than $36,000.
- Last year at least one of their clients had a starting salary of at least $40,000.
This statement is true. Since the mean starting salary is $40,000, it is possible for at least one client to have had a starting salary of at least $40,000.
Therefore, the statements that must be true based on the given information are:
- Last year some of their clients had a starting salary of exactly $40,000.
- Last year some of their clients had a starting salary of more than $36,000.
- Last year at least one of their clients had a starting salary of at least $40,000.
Quadrilateral RUST has a vertex at R (1, 5).
A. (4,4)
B. (4,8)
C. (3,9)
D. (2,8)
What are the coordinates of R'after the translation (x, y) - (x+1, y-1),
followed by a dilation by a scale factor of 2, centered at the origin?
Answers
Answer:
B. (4, 8)
Step-by-step explanation:
You want the coordinates of R(1, 5) after translation by (1, -1) and dilation by a factor of 2.
TranslationApplying the given transformation, you have ...
(x, y) ⇒ (x +1, y -1)
R(1, 5) ⇒ R'(1 +1, 5 -1) = R'(2, 4)
DilationThe dilation multiplies each coordinate value by the dilation factor, 2.
(x, y) ⇒ (2x, 2y)
R'(2, 4) ⇒ R''(2·2, 2·4) = R''(4, 8)
The coordinates after translation and dilation are (4, 8).
#95141404393
Use the Laws of logarithms to rewrite the expression
Answers
The expression log₃(x²∛y²) using the laws of logarithms is 2log₃(x) + 2/3log₃(y)
Rewriting the expression using the laws of logarithmsFrom the question, we have the following parameters that can be used in our computation:
log₃(x²∛y²)
The product law of logarithms states that
log(ab) = log(a) + log(b)
Using the above as a guide, we have the following:
log₃(x²∛y²) = log₃(x²) + log₃(∛y²)
The power law of logarithms states that
log(aᵇ) = blog(a)
Using the above as a guide, we have the following:
log₃(x²∛y²) = 2log₃(x) + 2/3log₃(y)
This means that the values of A and B are A = 2 and B = 2/3
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what equation is the blue line
Answers
Hello!
the equation of the blue line is 3y + 0.5x
Crane Corporation is considering purchasing a new delivery truck. The new truck would cost $55,440. The new truck is expected to generate a cost savings of $7,700. At the end of 8 years, the company will sell the truck for an estimated $27,600.
Traditionally the company has used a rule of thumb that a proposal should not be accepted unless it has a payback period that is less than 50% of the asset's estimated useful life. Larry Newton, a new manager, has suggested that the company should not rely solely on the payback approach, but should also employ the net present value method when evaluating new projects. The company's cost of capital is 8%.
a) Compute the cash payback period and net present value of the proposed investment.
b) Does the project meet the company's cash payback criteria?
c) Does it meet the net present value criteria for acceptance?
Answers
A. The payback period is 7.2 years. The net present value of the proposed investment is 3720.55.
B. No, the project does not meet the company's cash payback criteria.
C. Yes, the project does meet the net present value criteria for acceptance.
How do we solve for the net present value of the proposed investment?A. The truck costs $55,440 and generates annual cost savings of $7,700. So the payback period is the cost of the truck divided the expected amount the truck will generate.
$55,440 / $7,700 = 7.2 years
To solve for the net present value, we say
Net Present Value = ∑ [(Cash inflow in period t) / (1 + [tex]r^{t}[/tex]] - Initial Investment.
NPV = (($7,700 / (1 + 0.08)¹) = 7 129.63
+ ($7,700 / (1 + 0.08)²) = 6601.51
+ .($7,700 / (1 + 0.08)³ = 6112.51
+ ($7,700 / (1 + 0.08)⁴) = 5659.73
+ ($7,700 / (1 + 0.08)⁵) = 5240.49
+ ($7,700 / (1 + 0.08)⁶) = 4 852.31
+ ($7,700 / (1 + 0.08)⁷) = 4492.88
+($7,700 / (1 + 0.08)⁸) = 4160.07
+ ($27,600 / (1 + 0.08)⁸)) = 14911.42
- $55,440
We add all these values together and subtract by $55,440
7 129.63 + 6601.51 + 6112.51 + 5659.73 + 5240.49 +4 852.31 + 4492.88 + 4160.07 + 14911.42 - $55,440
59160.55 - 55,440
NPV = 3720.55
B. The cash payback period of the project is 7.2 years. The company's cash payback criteria state that a project should not be accepted unless it has a payback period that is less than 50% of the asset's estimated useful life, which would be 4 years which is 50% of 8 years. Since 7.2 years is greater than 4 years, the project does not meet the company's cash payback criteria.
C. The positive NPV of $3,720.55 shows that embarking on the prooject will be valuable to the company. This means the project meets the NPV criteria for acceptance.
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if 1 + 1 = 2 then does 2 + 2 = 1 + 1
If 2 + 1 = 21 then does everything else = 21
Solve
x3+y3+z3 = k
Answers
The first statement, "if 1 + 1 = 2, then 2 + 2 = 1 + 1," is true due to the associative property of addition, which allows us to group the numbers in any order we want.
How to find the solutions to the aforementioned questionsThe first statement, "if 1 + 1 = 2, then 2 + 2 = 1 + 1," is true due to the associative property of addition, which allows us to group the numbers in any order we want.
The second statement, "If 2 + 1 = 21, then everything else must equal 21," is false. If we assume that 2 + 1 = 21, we must know the specific mathematical system being used to determine if everything else equals 21.
Without additional information or constraints, the equation "[tex]3 + y^3 + z^3 = k[/tex] cannot be solved. It is a three-variable equation with only one equation, which means there are an infinite number of solutions depending on the values of y, z, and k.
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determine the range of; y = |x|
Answers
The range of the given function y = |x| is [0, ∞).
As per the question, consider that the absolute value of any real number x is always non-negative.
Therefore, the output of the function y = |x| is always non-negative as well.
Furthermore, for any non-negative real number y, there are two possible inputs x that will produce that value of y: x and -x. For example, if y = 2, then x could be either 2 or -2.
Thus, every non-negative real number is in the range of y = |x|, and no negative numbers are in the range.
Therefore, the range of y = |x| is [0, ∞).
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A flower garden is in the shape of a circle. The circumference of the garden is 20 meters. What is the area of the garden? Use 3.14 for pi and round you answer to the nearest whole number.
Answers
The circumference of a circle is also referred to as the distance around that circle.
The circumference of the flower garden which is circular in shape is given as = 20 meters
The formula for the circumference of a circle is given as [tex]\bold{2\pi r}[/tex]
Step 1We have to find the radius of the circular garden
Hence: [tex]\sf 2\pi r = 20 \ m[/tex]
[tex]\sf \pi = 3.14[/tex]
To find the radius, the formula would be given as
[tex]\bold{r = \dfrac{C}{2\pi}}[/tex]
Where C = Circumference of the circle
[tex]\sf r = \dfrac{20}{2\times3.14}[/tex]
[tex]\sf r = \dfrac{20}{6.28}[/tex]
[tex]\sf r = 3.1847133758 \ m[/tex]
Step 2We can find the area of the circle now
The formula for the area of the circle is given as:
[tex]\bold{A = \pi r^2}[/tex]
[tex]\sf A = 3.14 \times 3.1847133758^2[/tex]
[tex]\sf A = 31.847133758 \ m^2[/tex]
[tex]\sf A\thickapprox32 \ m^2[/tex]
Therefore, the area of the flower garden to the nearest whole number is 32m²
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What do the following two equations
represent?
•y-3=2(x − 3)
y + 5 = 2(x + 1)
Choose 1 answer:
A The same line
B
Distinct parallel lines
с Perpendicular lines
D
Intersecting, but not perpendicular lines
Answers
The two equations y - 3 = 2(x − 3) and y + 5 = 2(x + 1) represent (a) the same line
Identifying what the two equations represent?From the question, we have the following parameters that can be used in our computation:
y - 3 = 2(x − 3)
y + 5 = 2(x + 1)
Express the equations in slope intercept form
So, we have
y - 3 = 2x − 6
y + 5 = 2x + 2
These equations give
y = 2x − 3
y = 2x - 3
The above equations are the same
This means that the two equations represent (a) the same line
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A chain saw requires 4 hours of assembly and a wood chipper
5 hours. A maximum of 60 hours of assembly time is available.
The profit is $150 on a chain saw and $220 on a chipper. How
many of each should be assembled for maximum profit?
Answers
The maximum profit that can be obtained is $3160.
Let x be the number of chainsaws to be assembled, and y be the number of wood chippers to be assembled.
We want to maximize the profit, which is given by:
P = 150x + 220y
subject to the following constraints:
4x + 5y ≤ 60 (maximum assembly time available)
x ≥ 0, y ≥ 0 (non-negativity constraints)
We can solve this problem using linear programming.
First, we graph the constraint 4x + 5y ≤ 60 by finding the boundary line:
4x + 5y = 60
y = (-4/5)x + 12
The slope of this line is -4/5, and the y-intercept is 12. We can plot this line on a coordinate plane:
The feasible region is the region that satisfies all the constraints. It is the region below this line, including the non-negativity constraints:
We now evaluate the objective function P at the vertices of the feasible region to find the maximum value of P.
The vertices of the feasible region are (0,0), (0,12), (15,0), and (10,8).
P(0,0) = 0
P(0,12) = 220(12) = 2640
P(15,0) = 150(15) = 2250
P(10,8) = 150(10) + 220(8) = 3160
The maximum value of P is obtained at (10,8), which means that 10 chainsaws and 8 wood chippers should be assembled for maximum profit.
Therefore, the maximum profit that can be obtained is:
P = 150(10) + 220(8) = $3160.
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5/2 pounds to ounces
Answers
5/2 pounds is equal to 40 ounces.
We have to find the 5/2 pounds to ounces
1 pound is equal to 16 ounces.
To convert 5/2 pounds to ounces, we can multiply by 16:
5/2 pounds × 16 ounces/pound = 40 ounces
Therefore, 5/2 pounds is equal to 40 ounces.
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What is the surface area
Answers
1296 unit square will be the total surface area of the given figure.
To find the surface area of the given figure. first, we need to separate this graph into two cuboids such that,
the upper one with the dimension of 9*6*6.lower one with the dimension of 27*6*12.The surface area of a cuboid is given by the formula:
A = 2lw + 2hw + 2lh
thus, for the upper cuboid,
A = 2*9*6+2*6*6+2*9*6
A=288
thus, for the lower cuboid,
A = 2*27*6+2*27*12+2*12*6
A=1116
So the total surface area = sum of the surface area of both cuboids - 2* area of the touching side
Total surface area = 1116+288-2*9*6
Therefore total surface area will be 1296.
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Calculate the following: 1 7/8 ÷ 2 4/9 =
Answers
Answer:
135/176=0.767045
Step-by-step explanation:
1 7/8÷2 4/9
15/8÷22/9
15/8×9/22
135/176
Inequalities 7th grade Bai had a cell plan…
Answers
The solution is, the solution is x > −1.
This means that any value of x greater than −1 satisfies x + 3 > 2.
Inequalities can be represented on a number line such as that shown in the image attached below. The solid line shows the range of values that x can take. We put an open circle at −1 to show that although the solid line goes from −1, x cannot actually equal −1.
Inequalities are mathematical expressions involving the symbols >, <, ≥ and ≤.
To ‘solve’ an inequality means to find a range, or ranges, of values that an unknown x can take and still satisfy the inequality.
Suppose we want to solve the inequality x + 3 > 2.
We can solve this by subtracting 3 from both sides:
x + 3 > 2
x > −1
So the solution is x > −1.
This means that any value of x greater than −1 satisfies x + 3 > 2.
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30. Which of these sentences uses active voice?
The winning homerun was hit by the worst player on the baseball
team.
My friend invited his whole class to Saturday's soccer championship.
The children were taken to the circus by their doting grandfather.
At noon, some cookies were going to be baked by the baker.
Answers
The sentence that uses active voice is: "My friend invited his whole class to Saturday's soccer championship."
How to get the active voiceNow, let's examine the sentences you provided:
"The winning homerun was hit by the worst player on the baseball team."Passive voice: The subject ("the winning homerun") is being acted upon by the action (hit by the worst player).
"My friend invited his whole class to Saturday's soccer championship."Active voice: The subject ("my friend") is performing the action (inviting his whole class).
"The children were taken to the circus by their doting grandfather."Passive voice: The subject ("the children") is being acted upon by the action (taken to the circus by their doting grandfather).
"At noon, some cookies were going to be baked by the baker."Passive voice: The subject ("some cookies") is being acted upon by the action (baked by the baker).
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Complete the expressions and select the missing properties.
Write each answer as a number, a variable, or the product of a number and a variable.
Answers
p + 12 is the resulting expression using commutative law of addition.
Solving linear expressionLinear expression are expression that has a leading degree of 1.
Given the expression below
4 + (8 + p)
Using the commutative law of addition A + B = B + A, we will have:
4 + (8 + p) = (8 + p) + 4
= (4 + 8) + p
= 12 + p
Applying the commutative law, we will have
12 + p = p + 12
Hence the resulting expression using the commutative law of addition is p + 12
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Forecast the stock price on Monday 4/24/2023 by calculating 5-day weighted moving average of the previous week (4/17--4/21) as shown below.
Date Price Weight
4/17/2023 $ 157.01 1
4/18/2023 $ 159.37 3
4/19/2023 $ 159.36 5
4/20/2023 $ 161.78 7
4/21/2023 $ 164.08 9
Answers
The weighted average for the previous week is given as follows:
$161.64.
How to calculate the mean of a data-set?The mean of a data-set is given by the sum of all observations in the data-set divided by the cardinality of the data-set, which represents the number of observations in the data-set.
Considering the weights, the sum of the observations is given as follows:
1 x 157.01 + 3 x 159.37 + 5 x 159.36 + 7 x 161.78 + 9 x 164.08 = 4041.1.
The sum of the weights is given as follows:
1 + 3 + 5 + 7 + 9 = 25.
Hence the weighted average is given as follows:
4041.1/25 = $161.64.
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Thinking about the geoboard shown, Klay says it is impossible to make a triangle with an area of 5. Kevin says he can make a triangle with an area of 5
If you agree with Kevin, make a triangle with an area of 5 and explain below how you know it is an area of 5.
If you agree with Klay, make a triangle with an area as close as possible to 5 and convince us below that 5 is not possible.
Answers
Kevin make a triangle with an area of 5 is Correct.
To construct a triangle with an area of 5, we need to consider the formula for the area of a triangle: Area = (1/2) x base x height.
Let's choose a base of 4 units and a height of 2.5 units.
Plugging these values into the area formula, we have:
Area = (1/2) x 4 x 2.5
Area = 5
Therefore, we have constructed a triangle with a base of 4 units and a height of 2.5 units, resulting in an area of 5.
This confirms that it is indeed possible to make a triangle with an area of 5 units.
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Kaylin and CJ are in a dating relationship. Kaylin is trying to study for a test but keeps being interrupted with texts from CJ. The constant texting from CJ is not new behavior, but
recently it has started to annoy Kaylin as it has become more frequent and time consuming. CJ gets annoyed if Kaylin does not text right back. What would be the most effective way
for Kaylin to address the texting issue?
Through text, tell CJ that she is feels frustrated with the constant testing and C's need for immediate response. When she is freshed studying, she would like to find a time to talk more about this issue
O
O Through text, tell CJ that she is tuming her phone on silent to study and that she w
O Tum off her phone in order to focus on studying
O Continue to text CJ back
text him when she is finished studying
Answers
Expressing her frustration and finding a time to have a conversation, is the most effective way for Kaylin to address the texting issue with CJ. Option A
What would be the most effective way for Kaylin to address the texting issueBy clearly communicating her feelings of frustration and the impact that constant texting has on her ability to study effectively, Kaylin can open up a dialogue with CJ. This approach allows both parties to discuss their expectations, needs, and find a mutually beneficial solution. It also demonstrates Kaylin's willingness to address the issue directly and find a resolution.
Option B, turning her phone on silent to study, may help Kaylin focus on her studies, but it doesn't address the underlying issue of CJ's constant texting or Kaylin's frustration with it. It may lead to miscommunication or further misunderstandings between them.
Option C, continuing to text CJ back or texting him when she is finished studying, doesn't address the issue of constant interruptions and the impact it has on Kaylin's ability to concentrate. It may perpetuate the behavior and not effectively communicate her needs and boundaries.
Therefore, option A, expressing her frustration and finding a time to have a conversation, is the most effective way for Kaylin to address the texting issue with CJ.
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