The force that a surface applies to an object in touch with it when it is perpendicular to the surface is called the normal force. Equal in magnitude; A book lying flat on a table and Not equal in magnitude; inclined plane, elevator.
Is normal force smaller than an object's weight?Normal refers to something that is parallel to a surface. As you will see in the next example, if the object is on an inclination, the normal force may be less than the object's weight.
Is normal force equivalent to horizontal weight?The weight of an object is balanced by the typical response force when it is sitting on a horizontal surface. Yet, not every situation lends itself to this. Yet, when an object is at rest on an inclined plane, its weight is not equal to the usual reaction force.
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why does the mayo clinic staff recommended to drink caffeinated beverages judiciously
Answer:
Explanation:
The Mayo Clinic staff recommends drinking caffeinated beverages judiciously because excessive caffeine consumption can have negative health effects. While moderate caffeine consumption (about 400 mg per day, or the equivalent of four 8-ounce cups of coffee) is generally considered safe for most people, consuming too much caffeine can lead to a variety of negative side effects, including:
1. Insomnia: Caffeine is a stimulant that can interfere with sleep patterns and make it difficult to fall asleep or stay asleep.
2. Anxiety and restlessness: Caffeine can increase feelings of anxiety and restlessness, particularly in people who are sensitive to caffeine.
3. Digestive issues: Caffeine can increase stomach acid production, which can lead to digestive issues such as acid reflux, heartburn, and stomach ulcers.
4. Rapid heartbeat: Consuming too much caffeine can cause an irregular or rapid heartbeat, which can be dangerous for people with underlying heart conditions.
How is energy transferred between objects or systems? Identify an event for which you cite the evidence of energy being transferred.
Answer: Energy can be transferred between objects or systems through various mechanisms such as conduction, convection, radiation, and mechanical work.
In conduction, heat energy is transferred between objects or systems that are in contact with each other through direct molecular collisions. For example, if you heat a metal rod at one end, the heat energy is transferred through the rod to the other end.
In convection, heat energy is transferred between objects or systems through the movement of fluids, such as air or water. For example, when you boil water on a stove, the heat is transferred from the stove to the water through conduction. As the water heats up, it rises to the top of the pot and cooler water flows in to take its place. This process of rising and falling creates a convection current that transfers the heat energy throughout the water.
In radiation, energy is transferred through electromagnetic waves, such as light or infrared radiation. For example, the heat energy from the sun is transferred to the Earth through radiation.
Mechanical work can also transfer energy between objects or systems. For example, when you lift an object off the ground, you are doing work against the force of gravity. The energy you use to do this work is transferred to the object in the form of potential energy.
An example of energy transfer is the use of solar panels to generate electricity. When sunlight hits the solar panels, the energy is transferred through radiation, which creates an electrical current that can be used to power appliances and devices. In this case, the energy is transferred from the sun to the solar panels to the electrical devices.
Explanation: would apreciate a thanks and a brainliest :D
You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 485 N
in the rope. If Sneezy hangs from a similar rope while delivering presents at the earth's equator, what will the tension in it be? (Recall that the earth is rotating about an axis through its north and south poles.)
To solve this problem, we need to consider the effect of the earth's rotation on the tension in the rope. When Sneezy is hanging from a rope at the North Pole, he is not affected by the rotation of the earth because he is located at the axis of rotation. However, when he is hanging from a rope at the equator, he is moving at a tangential velocity of approximately 1670 km/h due to the rotation of the earth.
This tangential velocity creates a centrifugal force that acts on Sneezy and reduces the tension in the rope. The magnitude of this force can be calculated using the formula:
F = m * v^2 / r
where F is the centrifugal force, m is the mass of Sneezy, v is his tangential velocity, and r is the radius of the earth.
Assuming that Sneezy has a mass of 50 kg and the radius of the earth is 6,371 km, we can calculate the centrifugal force as follows:
F = 50 kg * (1670 km/h)^2 / (6371 km)
= 344 N
Therefore, the tension in the rope when Sneezy is hanging from it at the equator will be:
T = 485 N - 344 N
= 141 N
So the tension in the rope will be reduced by 344 N due to the centrifugal force caused by the earth's rotation.
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URGENT HELP PLS
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
The frequency of f3 is approximately 716 Hz.
What is frequency?The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.
a. Given two frequencies, f1 and f2, the frequency ratio is as follows:
frequency ratio= [tex]\frac{f2}{f1}[/tex]
Inputting the values provided yields:
frequency ratio = [tex]\frac{576}{320Hz}[/tex] =1.8.
As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.
b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by [tex]2^{(4/12)}[/tex]. Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:
frequency ratio= [tex]\frac{f}{ (f1 /f2 ) }[/tex]= [tex]\frac{f}{ (f1 / 1.3348) }[/tex]
By dividing the numerator and denominator by 1.3348, we may make this more straightforward:
frequency ratio= (f × 1.33348)/f1
As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.
c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: [tex]2^{(7/12)}[/tex] = 1.49831
Therefore, the frequency of f3 is:
f3 = f1 × ([tex]2^{(7/12)}[/tex]) × ([tex]2^{(7/12)}[/tex]) = 320 Hz × 1.49831 ×1.49831 = 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
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26. A rock is rolled in the sand. It starts at 5.0 m/s, moves in a straight line for a distance of 3.0 m, and then stops. What is the magnitude of the average acceleration? a. 1.8 m/s²
b. 4.2 m/s²
c. 5.4 m/s²
d. 6.2 m/s²
Answer:
b. 4.2 m/s²
Explanation:
The final velocity of the rock is zero. Therefore, the change in velocity is:
Δv = vf - vi = 0 - 5.0 = -5.0 m/s
The distance covered by the rock is 3.0 m. Therefore, the average acceleration is:
a = Δv / Δt
We do not have the value of time, so we can't calculate the acceleration directly. However, we can use the equation of motion that relates the initial velocity, final velocity, acceleration, and distance covered:
d = (vf² - vi²) / (2a)
Substituting the given values:
3.0 = (0² - 5.0²) / (2a)
Solving for acceleration:
a = -25 / (2 x 3.0) = -4.2 m/s²
The magnitude of the average acceleration is 4.2 m/s².
Therefore, the answer is (b) 4.2 m/s².
Object A has uniform velocity VA given by (11i-4j) m s¹. Object B has uniform velocity V, given by (5i+3j) m s¹. a) Find the velocity of B relative to A, giving the answer in i, j form. b) Find the magnitude of the velocity of Brelative to A, giving the answer to 3 significant figures. c) Find the direction of the velocity of B relative to A, giving the answer as an angle from the positive x axis in degrees to 1 decimal place.
(a) The velocity of B relative to A is (-6i + 7j) m/s.
(b) The magnitude of the velocity of B relative to A is 9.22 m/s.
(c) the direction of the velocity of B relative to A is -49.2° from the positive x-axis.
What is the velocity of B?a) The velocity of B relative to A, denoted as V(B/A), can be found by subtracting the velocity of A (VA) from the velocity of B (VB). So, we have:
V(B/A) = VB - VA
Given:
VB = 5i + 3j
VA = 11i - 4j
Substituting the values, we get:
V(B/A) = (5i + 3j) - (11i - 4j)
= -6i + 7j
So, the velocity of B relative to A is (-6i + 7j) m/s.
b) The magnitude of the velocity of B relative to A can be found using the formula for the magnitude of a vector, which is given by:
|V(B/A)| = √(Vx^2 + Vy^2)
Where;
Vx is the x-component of the velocity vector and Vy is the y-component of the velocity vector.Substituting the values, we get:
|V(B/A)| = √((-6)^2 + 7^2)
= √(36 + 49)
= √85
Rounded to 3 significant figures, the magnitude of the velocity of B relative to A is 9.22 m/s.
c) The direction of the velocity of B relative to A can be found using trigonometry. The angle (θ) between the positive x-axis and the velocity vector can be calculated using the inverse tangent (arctan) function:
θ = arctan(Vy / Vx)
Substituting the values, we get:
θ = arctan(7 / -6)
Using a calculator, we find that θ ≈ -49.2°
So, the direction of the velocity of B relative to A is -49.2° from the positive x-axis. Note that the negative sign indicates that the direction is in the clockwise direction.
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Theoretically, in an infinite 100% vacuum, how much of it's kinetic energy does an object flying 100 m/s lose after 5 seconds?
Below is a diagram of a baseball/forearm system at rest. It is acted on by four different forces: the weight of the forearm, the weight of the
baseball, the bicep force, and a force from the upper arm bone (attached at the elbow).
(F is not,
bone
shown)
elbow is
pivot
Tol
F.
bicep
L/2
Use the following values:
length of forearm = L = 20 cm
elbow to bicep distance = d = 3 cm
mass of forearm = M = 4 kg
mass of baseball = m = 1 kg
Mg
L/2
a.) Based on torque considerations, the force of the bicep must be ---Select---
(Make sure you understand the reasoning.)
b.) How large is the force exerted by the bicep?
N
the combined weight of the baseball/forearm.
c.) The upper arm bone exerts a force (not shown above) on the forearm. This force must be:
size:
N, dir: ---Select--- ✪
a.) Based on torque considerations, the force of the bicep must be equal in magnitude to the combined torque of the weight of the forearm, weight of the baseball, and the force from the upper arm bone.
How to solve the problemsMathematically, this can be expressed as:
F_bicep * d = (M + m) * g * (L/2)
where F_bicep is the force exerted by the bicep, d is the distance from the elbow to the point where the force is applied, M and m are the masses of the forearm and baseball, g is the acceleration due to gravity, and L is the length of the forearm.
Simplifying this equation, we get:
F_bicep = (M + m) * g * (L/2) / d
b.) Substituting the given values into the equation above, we get:
F_bicep = (4 kg + 1 kg) * 9.81 m/s^2 * (20 cm/2) / 3 cm
F_bicep = 32.73 N
Therefore, the force exerted by the bicep is 32.73 N.
c.) The force exerted by the upper arm bone must be equal in magnitude and opposite in direction to the combined force of the weight of the forearm, weight of the baseball, and the force from the bicep, in order to maintain static equilibrium.
Mathematically, this can be expressed as:
F_upper arm bone = -Mg - mg - F_bicep
Substituting the given values, we get:
F_upper arm bone = -(4 kg)*9.81 m/s^2 - (1 kg)*9.81 m/s^2 - 32.73 N
F_upper arm bone = -68.65 N
Therefore, the force exerted by the upper arm bone must be 68.65 N in the opposite direction to the combined weight and bicep force.
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50 POINTS ANSWER THIS QUESTION USING GRASP METHOD
GRASP- Given, Required, Analysis, Solution, Paraphrase
(a) The centripetal force required to keep the car traveling on the curved road is 4914.15 N.
(b) The coefficient of friction between the car's wheels and the ground must be approximately 0.334
What is the centripetal force?The centripetal force required to keep a car traveling in a curved path is given by the formula:
Fc = (mv^2) / r
where;
Fc is the centripetal force, m is the mass of the car, v is the velocity of the car, and r is the radius of the curve.Given:
m = 1500 kg (mass of the car)v = 65 km/h = 65 * (1000/3600) = 18.1 m/s)r = 100 m (radius of the curve)Plugging these values into the formula, we get:
Fc = (1500 kg) (18.1)² / 100 m
Fc = 4914.15 N
The friction force between the car's wheels and the ground provides the centripetal force. The friction force can be calculated using the formula:
f = μN
where;
f is the friction force, μ is the coefficient of friction, and N is the normal force.Since the car is not accelerating vertically, the normal force N is equal to the weight of the car, which is given by:
N = mg
where;
g is the acceleration due to gravity, which is approximately 9.8 m/s^2.Plugging in the values for m and g, we get:
N = (1500 kg) * 9.8 m/s^2
N = 14700 N
Now we can use the value of the centripetal force calculated earlier to find the coefficient of friction:
4904.38 N = μ * 14700 N
μ = 4914.15 N / 14700 N
μ ≈ 0.334
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A meteorite enters the Earth's atmosphere and burns up before reaching the Earth itself. The meteorites' kinetic energy stores are transferred to the surroundings as heat, sound and what else?
Answer:
The meteorites' kinetic energy stores are transferred to the surroundings as heat, sound and light energy.
Answer:
The meteorites' kinetic energy stores are transferred to the surroundings as heat, sound and light energy.
Explanation:
When a meteoroid enters Earth's upper atmosphere, it heats up due to friction from the air. The heat causes gases around the meteoroid to glow brightly, and a meteor appears. Meteors are often referred to as shooting stars or falling stars because of the bright tail of light they create as they pass through the sky.
Hope this helps :)
Pls brainliest...
Using the Left Hand Rule, if current points away from you and the field is to the right, which way does the motion point?
A. Left
B. Up
C. Right
D. Down
Explanation:
Using the Left Hand Rule, if current points away from you and the field is to the right, the motion will point upward. Therefore, the correct answer is B. Up.
The Left Hand Rule, also known as the Fleming's Left Hand Rule, is used to determine the direction of the force on a current-carrying conductor in a magnetic field. According to this rule, if the current flows in a direction perpendicular to the magnetic field and you point your left hand in the direction of the magnetic field, and your thumb in the direction of the current, then the direction in which your fingers curl represents the direction of the force acting on the conductor.A 1100 kg safe is 1.8 m above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compresses it 42 cm .
Part A: What is the spring constant of the spring?
Express your answer with the appropriate units.
50 POINTS ANSWER THESE QUESTIONS USING GRASP METHOD
GRASP- Given, Required, Analysis, Solution, Paraphrase
The minimum coefficient of friction required to keep the riders from sliding down is 1.
How to calculate the valueWe can use the equation for centripetal force:
Fc = mv^2 / r
where Fc is the centripetal force, m is the mass of the motorcyclist, v is the minimum speed required, and r is the radius of the circular track.
At the top of the loop, the motorcyclist's weight is given by:
mg = Fc
where g is the acceleration due to gravity.
Substituting the expression for Fc into this equation and solving for v, we get:
v = ✓(gr)
Plugging in the given values, we find:
v = ✓(9.8 m/s^2 * 10.0 m) ≈ 31.3 m/s
Therefore, the motorcyclist must maintain a minimum speed of about 31.3 m/s (or 70 mph) to stay on the track.
b) If the radius of the track is doubled to 20.0 m, the centripetal force required to stay on the track will also double. This is because the force required to keep an object moving in a circle is proportional to the radius of the circle.
Using the same equation as before, we find that the new minimum speed required is:
v_new = ✓(gr_new) = sqrt(9.8 m/s^2 * 20.0 m) ≈ 44.2 m/s
Therefore, the motorcyclist will need to increase their speed by a factor of about 44.2 m/s ÷ 31.3 m/s ≈ 1.41 (or 41%) to loop-the-loop on the new track.
c) To find the minimum coefficient of friction required to keep the riders from sliding down, we need to balance the forces acting on the riders when the floor drops away.
At the top of the ride, the only forces acting on the riders are their weight (mg) and the normal force (N) from the wall pushing them up. The normal force is equal in magnitude to the centripetal force required to keep them moving in a circle, which we found in part (a) to be mg. Therefore, N = mg.
When the floor drops away, the only force keeping the riders from sliding down the wall is the force of friction between the riders' shoes and the wall. This force must be equal to the component of their weight perpendicular to the wall:
F_friction = μN = μmg
where μ is the coefficient of friction.
The component of their weight perpendicular to the wall is given by:
mg cosθ
where θ is the angle between the riders' weight and the normal force. At the top of the ride, θ = 90 degrees, so cosθ = 0.
At the bottom of the ride, the angle between the riders' weight and the normal force is 180 degrees, so cosθ = -1.
Using the equation for the minimum coefficient of friction, we find:
μ_min = |mg cosθ| / N = |mg cos(-1)| / mg = 1
Therefore, the minimum coefficient of friction required to keep the riders from sliding down is 1.
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A light ray strikes the surface of crown glass (n = 1.520), at a 25° angle with respect to the normal from air (n = 1.000293), and leaves the glass, returning to the air. Determine the angle at which the light refracts when it moves from air into the crown glass.
The angle at which the light refracts when it moves from air into the crown glass is 23.3°.
Refraction is the bending of light as it passes through a medium with a different density. It occurs due to a change in the speed of light as it enters a different medium.
We can use Snell's law to solve this problem, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two media:
n1 sin θ1 = n2 sin θ2
where n1 and n2 are the refractive indices of the initial and final media, and θ1 and θ2 are the angles of incidence and refraction, respectively.
From the problem, we have:
n1 = 1.000293 (air)
n2 = 1.520 (crown glass)
θ1 = 25°
We can rearrange Snell's law to solve for θ2:
sin θ2 = (n1/n2) sin θ1
sin θ2 = (1.000293/1.520) sin 25°
sin θ2 = 0.385
Taking the inverse sine of both sides, we get:
θ2 = 23.3°
Therefore, the angle at which the light refracts when it moves from air into the crown glass is 23.3°.
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The distance of object is 10cm from convex mirror of focal length is 15 cm. Find the position of image? pic attached below
The position of the image is 30 cm behind the mirror.
According to the mirror formula,
1/f = 1/u + 1/v
where f is the focal length, u is the distance of the object from the mirror, and v is the distance of the image from the mirror.
Substituting the given values, we get:
1/15 = 1/10 + 1/v
Simplifying, we get:
1/v = 1/15 - 1/10 = (2 - 3)/30 = -1/30
Taking the reciprocal on both sides, we get:
v = -30 cm
The negative sign indicates that the image is virtual and located behind the mirror. Therefore, the position of the image is 30 cm behind the mirror.
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A ball is launched from the surface of a planet. Air resistance and other frictional forces are neglected. The graph shows the position of the ball every 0.20 s.
a. Use this graph to determine:
I. The components of the initial velocity of the ball
II. The angle to the horizontal the ball was launched at
III. The acceleration of free fall on this planet.
b. Make a copy of the graph and draw two arrows to represent the velocity and the acceleration vectors of the ball at t = 1.0 s.
c. The ball is now launched under identical conditions from the surface of a different planet where the acceleration due to gravity is twice as large. Draw the path of the ball on your graph.
The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.
What are the velocities ?Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.
What is time ?Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.
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Hello! How would I go about solving this question? I got the answer wrong.
The coefficient of static friction is (Mg-mgsinθ) / mgcosθ. Hence, the correct option is C.
From the given,
A block of mass m is connected by a string by a frictionless pulley,
A heavier mass M
Inclined angel θ
The coefficient of static friction, μs=?
When the object is at rest, no motion is take place. The net force is zero, Fnet = 0. The normal force Fn = Fgcosθ.
Fn = Fgcosθ
= mgcosθ
Fn = mgcosθ
From Newton's second law:
Fnet = T - Fgcosθ - Ff where T is the tension of the pulley, Fgcosθ is the normal force, Ff is the frictional force.
Fnet = T - Fgcosθ - Ff
T = mgsinθ+μmgcosθ (Frictional force =0)
Fnet = Fg - T = 0
Mg - (mgsinθ+μmgcosθ) = 0
Mg - mgsinθ = μmgcosθ
μ = (Mg - mgsinθ)/ mgcosθ
Hence the coefficient of static friction is μ = (Mg - mgsinθ)/ mgcosθ. Thus the ideal solution is option C.
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Suppose a rocket-propelled motorcycle is fi red from rest horizontally across a canyon 1.00 km wide. (a) What minimum
constant acceleration in the x-direction must be provided by the engines so the cycle crosses safely if the
opposite side is 0.750 km lower than the starting point? (b) At what speed does the motorcycle land if it maintains
this constant horizontal component of acceleration? Neglect air drag, but remember that gravity is still acting in the
negative y-direction.
Explanation:
Vertical distance (note conversion to METERS from km for parameters in Q)
750 m = 1/2 at^2 Where a = 9.81 m/s^2
then t = 12.365 s
Then horizontal distance that must occur in this time frame:
1000 m = do + vot + 1/2 a t^2 ( do and vo = 0 )
where THIS a is the HORIZONTAL accel we are looking for
1000 = 1/2 a t^2
2000 = a ( 12.365)^2
a = ~ 13.1 m/s^2
Answer:
Explanation:
I apologize for any plagiarism in my previous answer. Here is a new answer to the question:
(a) The motorcycle needs to cross the canyon safely by landing on the opposite side. Let's call the starting point of the motorcycle as point A and the landing point as point B. The horizontal distance between A and B is 1.00 km, and the vertical distance between them is 0.750 km.
To find the minimum constant acceleration in the x-direction required to cross the canyon safely, we can use the kinematic equation:
d = (1/2)at^2
where d is the horizontal distance between A and B, a is the constant acceleration in the x-direction, and t is the time it takes to cross the canyon.
We also know that the motorcycle is affected by gravity, which causes it to accelerate downwards with an acceleration of g = 9.81 m/s^2.
To cross the canyon safely, the motorcycle needs to land on the opposite side, so we can use the following inequality:
h <= (1/2)gt^2
where h is the vertical distance between A and B.
Substituting the given values, we have:
d = 1.00 km = 1000 m
h = 0.750 km = 750 m
Using the above equations, we can solve for the minimum acceleration required:
750 m <= (1/2) * 9.81 m/s^2 * t^2
1000 m = (1/2) * a * t^2
Solving for t in the first equation, we get:
t = sqrt((2 * h) / g) = sqrt((2 * 750 m) / 9.81 m/s^2) = 12.19 s
Substituting this value of t into the second equation, we get:
a = (2 * d) / t^2 = (2 * 1000 m) / (12.19 s)^2 = 6.96 m/s^2
Therefore, the minimum constant acceleration in the x-direction required to cross the canyon safely is 6.96 m/s^2.
(b) To find the speed at which the motorcycle lands, we can use the equation:
v_f = at
where v_f is the final velocity in the x-direction.
Substituting the given values, we get:
a = 6.96 m/s^2
t = 12.19 s
Therefore, the final velocity of the motorcycle in the x-direction is:
v_f = 6.96 m/s^2 * 12.19 s = 84.85 m/s
Therefore, the motorcycle lands with a horizontal speed of 84.85 m/s.
A ball is thrown straight up into the air with an initial velocity of 20 m/s. How high does it go? (Assume no air resistance and a gravitational acceleration of 9.8 m/s^2)
A child is sitting on the outer edge of a merry-go-round that is
18 m in diameter. If the merry-go-round makes 8.8 rev/min, what is
the velocity of the child in m/s?
The velocity (in m/s) of the child sitting on the outer edge of the merry-go-round that is 18 m in diameter is
How do i determine the velocity of the child?The following data were obtained from the question:
Angular velocity (ω) = 8.8 rev/minDiameter of merry-go-round = 18 mRadius of merry-go-round (r) = Diameter / 2 = 18 / 2 = 8 mVelocity of child (v) =?The velocity of the child can be obtained as illustrated below:
Velocity (v) = angular velocity (ω) × radius (r)
v = ωr
v = 8.8 × 9
v = 79.2 m/min
Divide by 60 to express in meter per second (m/s)
v = 79.2 / 60
v = 1.32 m/s
Thus, we can conclude from the above calculation that the velocity of the child is 1.32 m/s
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Question 27(Multiple Choice Worth 2 points)
Which of these statements about mixtures is true?
Mixtures are made up of elements bonded together.
Elements and compounds are types of mixtures.
O Pure substances are made up of mixtures combined in specific ratios.
O Mixtures are classified based on the distribution of particles in them.
The correct answer is: Mixtures are classified based on the distribution of particles in them. Is there anything else you would like to know about mixtures?
MARK ME BRAINLEISTWhat is the distance Covered by a Car If its accelerator with 5m/s² for 10 sec at Initial Velocity of 3 m/s.
Answer:
To solve for the distance covered by the car, we need to use the kinematic equation:
distance = initial velocity x time + (1/2) x acceleration x time^2
We know that the initial velocity, u, is 3 m/s, the time, t, is 10 sec, and the acceleration, a, is 5 m/s². Substituting these values gives:
distance = (3 m/s) x (10 sec) + (1/2) x (5 m/s²) x (10 sec)^2
distance = 30 m + (1/2) x 5 m/s² x 100 sec²
distance = 30 m + 250 m
distance = 280 m
Therefore, the car covers a distance of 280 meters if its accelerator with 5m/s² for 10 sec at an initial velocity of 3 m/s.
Explanation:
We have a radioactive source, nuclide X, that has an activity of 1 Curie (Ci) at time zero. It’s decay constant () is 0.00002 s-1. What activity is remaining after 60 hours, expressed as Curies (Ci)?
The activity remaining after 60 hours is approximately 0.423 Curies (Ci).
How to calculate the radioactivityThe decay of a radioactive source follows an exponential decay law, which is given by the formula:
A(t) = A₀ * e^(-λt)
where A₀ is the initial activity of the source, λ is the decay constant, t is the time elapsed since the initial measurement, and A(t) is the activity of the source at time t.
In this case, we are given A₀ = 1 Ci and λ = 0.00002 s^-1. We need to find A(60 hours), which is 606060 seconds = 216000 seconds.
A(216000) = A₀ * e^(-λ216000)
= 1 * e^(-0.00002216000)
≈ 0.423 Ci
Therefore, the activity remaining after 60 hours is approximately 0.423 Curies (Ci).
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How to travel in the speed of light?
Answer:
Explanation:
1. eectromagnetic Fields. Most of the processes that accelerate particles to relativistic speeds work with electromagnetic fields to the same force that keeps magnets on your fridge!
Magnetic Explosions
Wave-Particle Interaction's
How do you solve for acceleration given the velocity equation and a time?
Answer:
You take the derivative of the velocity equation!
Explanation:
The acceleration basically refers to how the velocity changes over time. To find that, you need to take the derivative of the velocity equation. Comment if you would like me to show you what that looks like. Once you find the derivative you can plug your time value into the equation and get the acceleration at that time!
Answer:
find the rate of change of the velocity equation
Please help me in questions 4_5_6
Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.
How to explain the forceAs the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.
The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.
The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.
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If a ball were to be dropped from a 10m tower and it falls 4.9m after 1 second what is the balls average velocity from its starting point to 4.9m. (No air resistance)
The ball is moving upwards at 4.9 m, we know its velocity at that point is 9.3 m/s (upwards). Therefore, the ball's average velocity from its starting point to 4.9 m is 9.3 m/s (upwards).
What is Velocity?
Velocity is a measure of an object's speed in a specific direction. It is a vector quantity, which means it has both magnitude (the numerical value of the speed) and direction. The formula for calculating velocity is v = d/t, where v is velocity, d is the distance traveled, and t is the time it took to travel that distance
Assuming the acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex], we can use the kinematic equation:
d = Vit + (1/2)at^2
where:
d = distance traveled (4.9 m)
Vi = initial velocity (0 m/s since the ball was dropped from rest)
t = time (1 s)
a = acceleration (-9.8 m/[tex]s^{2}[/tex] since it's in the opposite direction to the ball's motion)
Solving for Vi, we get:
Vi = (d - (1/2)[tex]at^{2}[/tex])/t
Vi = (4.9 - (1/2)(-9.8)([tex]1^{2}[/tex])/1
Vi = 9.3 m/s (upwards)
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Explain what you know about the Oxygen atom based on the following element symbol? (Be sure to include information about protons, neutrons, electrons, mass number). 17 8 O 0
Answer:
The element symbol you provided is for Oxygen (O). The bottom number (8) is the atomic number, which represents the number of protons in the nucleus of an atom. So, an Oxygen atom has 8 protons. The top number (17) is the mass number, which is the sum of protons and neutrons in the nucleus. Since there are 8 protons, this means there are 9 neutrons (17-8=9). The charge of the atom is 0, which means the number of electrons is equal to the number of protons (8).
Explanation:
When the inner planets formed, what did their close proximity to the sun cause?
A. It caused the planets to heat up, boiling off any water on their surfaces and leaving them barren.
B. It caused their surfaces to melt so that the inner planets have liquid surfaces.
C. It did nothing, the inner planets formed in the same way as the outer planets.
D. It caused the lighter elements to evaporate, allowing the formation of a thick rocky crust.
To determine the vertical displacement at point B using Castigliano's theorem
Castigliano's theorem is a method used in structural engineering to determine the vertical displacement of a structure under load. It involves using partial derivatives of the strain energy with respect to the applied loads to calculate the displacement.
How can we determine vertical displacement using Castigliano's theorem?Castigliano's theorem is a powerful tool used in structural engineering to analyze and calculate the displacement of a structure under vertical loads. It is based on the principle of virtual work, which states that the work done by external forces on a system is equal to the change in strain energy of that system.
By applying this principle, Castigliano's theorem allows engineers to calculate the displacement of a structure by taking partial derivatives of the strain energy with respect to the applied loads. This method is particularly useful in determining vertical displacement in structures subjected to complex loading conditions, such as bridges, beams, and trusses, and is widely used in structural analysis and design.
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